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PHP - Mysqli_num_rows() Expects Parameter 1 To Be Mysqli_result, Bool Given
I have searched the internet about this and found hundreds have asked the question and not once was it answered in a meaningful way--or maybe I'm just dense. Would somebody please tell me what is the problem he Simple, simple form:
<html>
<form action="send_post.php" method="post">
</body> =========== Simple, simple PHP script:
<?php
if (mysqli_num_rows($result) > 0) { But most importantly, how should it be written so that it returns the desired results? I have checked the query from the CMD line, it returns multiple entries. Really, I have reached FRUSTRATION OVERLOAD! Edited April 12, 2020 by eljaydeeSimilar TutorialsHi all, I have received a warning message, which it still puzzles me. I suspect it might be my inner join command, which I have coded it wrongly? Line 37 refers to this line - if (mysqli_num_rows($data) == 1) { Do you guys have any idea? Thanks Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in D:\inetpub\vhosts\123.com\http\viewprofile.php on line 37 Code: [Select] <?php // Connect to the database $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); $query = "SELECT tp.name, tp.nric, tp.gender, tp.race_id, r.race_name AS race" . "FROM tutor_profile AS tp " . "INNER JOIN race AS r USING (race_id) " . "WHERE tutor_id = '" . $_GET['tutor_id'] . "'"; $data = mysqli_query($dbc, $query); if (mysqli_num_rows($data) == 1) { // The user row was found so display the user data $row = mysqli_fetch_array($data); echo '<table>'; if (!empty($row['name'])) { echo '<tr><td class="label">Name:</td><td>' . $row['name'] . '</td></tr>'; } if (!empty($row['nric'])) { echo '<tr><td class="label">NRIC:</td><td>' . $row['nric'] . '</td></tr>'; } if (!empty($row['last_name'])) { echo '<tr><td class="label">Last name:</td><td>' . $row['last_name'] . '</td></tr>'; } if (!empty($row['gender'])) { echo '<tr><td class="label">Gender:</td><td>'; if ($row['gender'] == 'M') { echo 'Male'; } if ($row['gender'] == 'F') { echo 'Female'; } echo '</td></tr>'; } if (!empty($row['race'])) { echo '<tr><td class="label">Race:</td><td>' . $row['race'] . '</td></tr>'; } echo '</table>'; //End of Table echo '<p>Would you like to <a href="editprofile.php?tutor_id=' . $_GET['tutor_id'] . '">edit your } // End of check for a single row of user results else { echo '<p class="error">There was a problem accessing your profile.</p>'; } mysqli_close($dbc); ?> Hi Guys.
Doing an assignment for uni, and stuck on an error. Ill attach some files to show the problem and any help very much appreciated.
Error and the screen it comes on
Code
<?php $select = mysqli_query($con, "SELECT * FROM categories");
while ($row = mysqli_fetch_assoc($select)) { }
function dispsubcategories($parent_id) {
}
function getnumtopics($cat_id, $subcat_id) {
and the structure of the database
Edited March 28, 2020 by Ben555 Hi guys, I received an error, could anyone explain this current error? Thanks Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in D:\inetpub\vhosts\championtutor.com\httpdocs\questionnaire.php on line 32 update.php
<?php
// Include config file
require_once "config.php";
// Define variables and initialize with empty values
$head = $content = $date = $time = "";
$head_err = $content_err = $date_err = $time_err = "";
// Processing form data when form is submitted
if(isset($_POST["id"]) && !empty($_POST["id"])){
// Get hidden input value
$id = $_POST["id"];
// Validate head
$input_head = trim($_POST["head"]);
if( strlen($input_head) > 200){
$head_err = "Max character length is 200.";
} elseif(!filter_var($input_head, FILTER_VALIDATE_REGEXP, array("options"=>array("regexp"=>"/^[a-zA-Z\s]+$/")))){
$head_err = "Please enter a valid head.";
} else{
$head = $input_head;
}
// Validate content
$input_content = trim($_POST["content"]);
if(empty($input_content)){
$content_err = "Please enter an content.";
} else{
$content = $input_content;
}
// Validate date
$input_date = trim($_POST["date"]);
if(empty($input_date)){
$date_err = "Please enter an date.";
} else{
$date = $input_date;
}
// Validate time
$input_time = trim($_POST["time"]);
if(empty($input_time)){
$time_err = "Please enter an time.";
} else{
$time = $input_time;
}
// Check input errors before inserting in database
if(empty($head_err) && empty($content_err) && empty($date_err) && empty($time_err)){
// Prepare an update statement
$sql = "UPDATE list SET head=?, content=?, date=?, time=?, WHERE id=?";
if($stmt = mysqli_prepare($link, $sql)){
// Bind variables to the prepared statement as parameters
mysqli_stmt_bind_param($stmt, "ssssi", $param_head, $param_content, $param_date, $param_time, $param_id);
// Set parameters
$param_head = $head;
$param_content = $content;
$param_date = $date;
$param_time = $time;
$param_id = $id;
// Attempt to execute the prepared statement
if(mysqli_stmt_execute($stmt)){
// Records updated successfully. Redirect to landing page
header("location: index.php");
exit();
} else{
echo "Something went wrong. Please try again later.";
}
}
// Close statement
mysqli_stmt_close($stmt);
}
// Close connection
mysqli_close($link);
} else{
// Check existence of id parameter before processing further
if(isset($_GET["id"]) && !empty(trim($_GET["id"]))){
// Get URL parameter
$id = trim($_GET["id"]);
// Prepare a select statement
$sql = "SELECT * FROM list WHERE id = ?";
if($stmt = mysqli_prepare($link, $sql)){
// Bind variables to the prepared statement as parameters
mysqli_stmt_bind_param($stmt, "i", $param_id);
// Set parameters
$param_id = $id;
// Attempt to execute the prepared statement
if(mysqli_stmt_execute($stmt)){
$result = mysqli_stmt_get_result($stmt);
if(mysqli_num_rows($result) == 1){
/* Fetch result row as an associative array. Since the result set
contains only one row, we don't need to use while loop */
$row = mysqli_fetch_array($result, MYSQLI_ASSOC);
// Retrieve individual field value
$head = $row["head"];
$content = $row["content"];
$date = $row["date"];
$time = $row["time"];
} else{
// URL doesn't contain valid id. Redirect to error page
header("location: error.php");
exit();
}
} else{
echo "Oops! Something went wrong. Please try again later.";
}
}
// Close statement
mysqli_stmt_close($stmt);
// Close connection
mysqli_close($link);
} else{
// URL doesn't contain id parameter. Redirect to error page
header("location: error.php");
exit();
}
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Update Record</title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.css">
<link rel="icon" type="image/png" href="https://www.htmlhints.com/image/fav-icon.png">
<meta name="msvalidate.01" content="B7807734CA7AACC0779B341BBB766A4E" />
<meta name="p:domain_verify" content="78ad0b4e41a4f27490d91585cb10df4a"/>
<script async src="https://pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"></script>
<!-- Global site tag (gtag.js) - Google Analytics -->
<script async src="https://www.googletagmanager.com/gtag/js?id=UA-145078782-1"></script>
<script>
window.dataLayer = window.dataLayer || [];
function gtag(){dataLayer.push(arguments);}
gtag('js', new Date());
gtag('config', 'UA-145078782-1');
</script>
<style>
.wrapper{
width: 500px;
margin: 0 auto;
}
.hh_button {
display: inline-block;
text-decoration: none;
background: linear-gradient(to right,#ff8a00,#da1b60);
border: none;
color: white;
padding: 10px 25px;
font-size: 1rem;
border-radius: 3px;
cursor: pointer;
font-family: 'Roboto', sans-serif;
position: relative;
margin-top: 30px;
margin: 0px;
position: absolute;
right: 20px;
top: 1.5%;
}
header {
color: white;
padding: 20px;
margin-bottom: 20px;
}
header a, header a:hover {
text-decoration: none;
color: white;
}
</style>
</head>
<body>
<header>
<strong><i class="fas fa-chevron-left"></i> <a href="https://www.htmlhints.com/"></a> <i class="fas fa-chevron-right"></i></strong>
</header>
<div class="wrapper">
<div class="container-fluid">
<div class="row">
<div class="col-md-12">
<div class="page-header">
<h2>Update Record</h2>
</div>
<p>Please edit the input values and submit to update the record.</p>
<form action="<?php echo htmlspecialchars(basename($_SERVER['REQUEST_URI'])); ?>" method="post">
<div class="form-group <?php echo (!empty($head_err)) ? 'has-error' : ''; ?>">
<label>head</label>
<input type="text" name="head" class="form-control" value="<?php echo $head; ?>">
<span class="help-block"><?php echo $head_err;?></span>
</div>
<div class="form-group <?php echo (!empty($content_err)) ? 'has-error' : ''; ?>">
<label>content</label>
<textarea name="content" class="form-control"><?php echo $content; ?></textarea>
<span class="help-block"><?php echo $content_err;?></span>
</div>
<div class="form-group <?php echo (!empty($date_err)) ? 'has-error' : ''; ?>">
<label>date</label>
<input type="date" name="date" class="form-control" value="<?php echo $date; ?>">
<span class="help-block"><?php echo $date_err;?></span>
</div>
<div class="form-group <?php echo (!empty($time_err)) ? 'has-error' : ''; ?>">
<label>time</label>
<input type="time" name="time" class="form-control" value="<?php echo $time; ?>">
<span class="help-block"><?php echo $time_err;?></span>
</div>
</div>
<input type="hidden" name="id" value="<?php echo $id; ?>"/>
<input type="submit" class="btn btn-primary" value="Submit">
<a href="index.php" class="btn btn-default">Cancel</a>
</form>
</div>
</div>
</div>
</div>
<ins class="adsbygoogle my-3"
style="display:block"
data-ad-format="fluid"
data-ad-layout-key="-fb+5w+4e-db+86"
data-ad-client="ca-pub-1506739985879215"
data-ad-slot="5016195832"></ins>
<script>
(adsbygoogle = window.adsbygoogle || []).push({});
</script>
</body>
</html>
database.sql -- phpMyAdmin SQL Dump -- version 5.0.3 -- https://www.phpmyadmin.net/ -- -- Host: 127.0.0.1 -- Generation Time: Nov 19, 2020 at 09:41 PM -- Server version: 10.4.14-MariaDB -- PHP Version: 7.4.11 SET SQL_MODE = "NO_AUTO_VALUE_ON_ZERO"; START TRANSACTION; SET time_zone = "+00:00"; /*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */; /*!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS */; /*!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION */; /*!40101 SET NAMES utf8mb4 */; -- -- Database: `tododb` -- -- -------------------------------------------------------- -- -- Table structure for table `list` -- CREATE TABLE `list` ( `id` int(20) NOT NULL, `head` varchar(200) NOT NULL, `content` text NOT NULL, `date` date NOT NULL, `time` time NOT NULL ) ENGINE=InnoDB DEFAULT CHARSET=latin1; -- -- Dumping data for table `list` -- INSERT INTO `list` (`id`, `head`, `content`, `date`, `time`) VALUES (69, 'task', 'test123', '2222-12-13', '22:22:00'); -- -- Indexes for dumped tables -- -- -- Indexes for table `list` -- ALTER TABLE `list` ADD PRIMARY KEY (`id`); -- -- AUTO_INCREMENT for dumped tables -- -- -- AUTO_INCREMENT for table `list` -- ALTER TABLE `list` MODIFY `id` int(20) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=70; COMMIT; /*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */; /*!40101 SET CHARACTER_SET_RESULTS=@OLD_CHARACTER_SET_RESULTS */; /*!40101 SET COLLATION_CONNECTION=@OLD_COLLATION_CONNECTION */;
Warning: mysqli_stmt_close() expects parameter 1 to be mysqli_stmt, bool given in C:\xampp\htdocs\todolist\update.php on line 75 Hi
I am a student who is fairly new to PHP and MySQL. I have been working on creating a registration page for a website and I'm getting the following warnings when I've tested the page:
Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in /home/ed12e2w/public_html/COMM2735/dynamic_website/registration.php on line 74 Warning: mysqli_free_result() expects parameter 1 to be mysqli_result, boolean given in /home/ed12e2w/public_html/COMM2735/dynamic_website/registration.php on line 80 I think that my query has failed but I'm not completely sure on what to change in order to solve this. Here is the section of code I'm having problems with: Attached Files register.php 733bytes 4 downloads Someone help me in this problem please?? Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in line 8 $rec= mysqli_query ($db, "SELECT FROM joborder WHERE id=$id"); $record = mysqli_fetch_array ($rec); // line 8 $fnames= $record ['fnames'] ; Edited March 8 by keiWarning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in /home/myritebook/public_html/footer.php on line 13 I am trying to fix the above error. Please Help. code is given below:
<?php
if ($conn) {
try{
catch(Exception $e){
<!DOCTYPE html>
{ trying to figure this problem out. sucks being a newbie maybe i will gain enough knowledge to be able to help out others in the near future. Code: [Select] <?php session_start(); $DBConnect = @mysqli_connect("localhost", "**********", "**********") Or die("<p>Unable to connect to the database server.</p>" . "<p>Error code " . mysqli_connect_errno() . ": " . mysqli_connect_error()) . "</p>"; $DBName = "skyward_aviation"; @mysqli_select_db($DBConnect, $DBName) Or die("<p>Unable to select the database.</p>" . "<p>Error code " . mysqli_errno($DBConnect) . ": " . mysqli_error($DBConnect)) . "</p>"; $CustomerName = ""; if (isset($_COOKIE['customerName'])) $CustomerName = $_COOKIE['customerName']; $TableName = "mileage"; $Mileage = 0; $SQLstring = "SELECT SUM(mileage) FROM $TableName WHERE flyerID='{$_SESSION['flyerID']}"; $QueryResult = @mysqli_query($DBConnect, $SQLstring); if (mysqli_num_rows($QueryResult) > 0) { $Row = mysqli_fetch_row($QueryResult); $Mileage = number_format($Row[0], 0) ; mysqli_free_result($QueryResult); } mysqli_close($DBConnect); ?> i know its a simple stupid error but cant remember nor figure it out. HERES THE ERROR Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in C:\xampp\htdocs\PHP_Projects\Chapter.10\FrequentFlyerClub.php on line 23 I have a table with a list of users and an edit button and delete button. When the edit button is pressed on a site it passes the user_id as p_id to the page that catches it and displays the data. The problem is when I click on the "update user" button, I get the following error:
Warning: Undefined variable $the_user_id in C:\xampp\htdocs\3-19-21(2) - SafetySite\admin\edit_user.php on line 10 The weird thing is I had another update user page with a table I created that ran the query to update the table in the database just fine. But as I created it, it didn't look all that great so I recreated the page and used a bootstrap table because of the much cleaner look. Both pages have the exact same PHP code, the only difference is the bootstrap table I added in. So I'm really at a loss with this. Other than the table and PHP code, there is a script at the bottom of the page for the table itself to allow for searching within the table, i'll include that as well. The PHP code is as follows:
<?php //THE "p_id" IS BROUGHT OVER FROM THE EDIT BUTTON ON VIEW_ALL_USERS if (isset($_GET['p_id'])) { $the_user_id = $_GET['p_id']; } // QUERY TO PULL THE SITE INFORMATION FROM THE p_id THAT WAS PULLED OVER $query = "SELECT * FROM users WHERE user_id = $the_user_id "; $select_user = mysqli_query($connection,$query); //SET VALUES FROM ARRAY TO VARIABLES while($row = mysqli_fetch_assoc($select_user)) { $user_id = $row['user_id']; $user_firstname = $row['user_firstname']; $user_lastname = $row['user_lastname']; $username = $row['username']; $user_email = $row['user_email']; $user_phone = $row['user_phone']; //$user_image = $row['user_image']; $user_title_id = $row['user_title_id']; $user_role_id = $row['user_role_id']; } THE UPDATE QUERY CODE....................................................................................................................
<?php if(isset($_POST['update_user'])) { $user_id = $_POST['user_id']; $user_firstname = $_POST['user_firstname']; $user_lastname = $_POST['user_lastname']; $username = $_POST['username']; $user_email = $_POST['user_email']; $user_phone = $_POST['user_phone']; //$user_image = $_POST['user_image']; $user_title_id = $_POST['user_title_id']; $user_role_id = $_POST['user_role_id'];
$query = "UPDATE users SET "; $query .= "user_id = '{$user_id}', "; $query .= "user_firstname = '{$user_firstname}', "; $query .= "user_lastname = '{$user_lastname}', "; $query .= "username = '{$username}', "; $query .= "user_email = '{$user_email}', "; $query .= "user_phone = '{$user_phone}', "; //$query .= "user_image = '{$user_image}', "; $query .= "user_title_id = '{$user_title_id}', "; $query .= "user_role_id = '{$user_role_id}' "; $query .= "WHERE user_id = '{$the_user_id}' "; $update_user = mysqli_query($connection,$query); if(! $update_user) { die("QUERY FAILED" . mysqli_error($connection)); } } ?> THE "UPDATE USER" BUTTON THE USER CLICKS ON TO UPDATE....................................................................................................................
<div class="col-1"> <button class="btn btn-primary" type="submit" name="update_user">Update User</button> </div>
Any Help is Greatly Appreciated! Edited March 23 by ZsereneI am trying to create a simple voting form. Everything goes well until I submit and then I get a Warning: mysqli_error() expects exactly 1 parameter, 0 given on line 79 error. I am assuming it is not pulling the ID correctly but as I am new to php and mysqli I cannot exactly say if it the way the code is written or if I am calling the parameter incorrectly in the query. Again I am new to to this so please be gentle. Below is my code. It pulls the drop down list correctly and echo's correctly but I believe my post query to be a little out of wack. Could someone point me in the correct direction? It would be very appreciated.
<form action="businesstype_update.php" method="post">
<?php
if(isset($_POST['voteall'])){
$vote_lg = "update membertest where id={$row_lg['id']} set vote=vote+1";
$run_lg = mysqli_query($con, $vote_lg) or die(mysqli_error());
}
$result_lg = mysqli_query($con, "SELECT id, business FROM membertest WHERE businesstype='large'");
echo "Vote for large business of the year! <SELECT name='business'>\n";
echo "<option>Select a large business</option>";
while($row_lg = $result_lg->fetch_assoc()) {
echo "<option value='{$row_lg['id']}'>{$row_lg['business']}</option>\n";
}
echo "</select></br></br>\n";
echo "<input type='submit' name='voteall' value='voteall'>";
$result_lg->close();
$con->close();
i get this error Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\website\viewvideos.php on line 25 Code: [Select] $addviews = $views + 1; $query = mysql_query("UPDATE headlines SET views='$addviews' WHERE id=$viewid"); $rows = mysql_fetch_assoc($query); i dont get whats wrong Hi all, I have received this error, and I could clearly recall I did not actually change any content in the file. May I know how should I debug it? Thanks Warning: mysqli_error() expects exactly 1 parameter, 0 given in D:\inetpub\vhosts\abc.com\httpdocs\inc\php\tutor\t_reg_post1.php on line 163 May I know what does this mean, this is the code which they are referring to. I have tried troubleshooting, still could not find the cause, appreciate if anyone can help? Thanks Warning: mysqli_error() expects exactly 1 parameter, 0 given in D:\inetpub\vhosts\championtutor.com\httpdocs\inc\elements\t_reg_post1.php on line 204 /**INSERT into tutor_musical_background table**/ foreach($musics as $music) { $query6 = "INSERT INTO tutor_musical_background (tutor_id, musical_instrument_id) VALUES ('$tutor_id', '$music')"; $results6 = mysqli_query($dbc, $query6) or die(mysqli_error()); Hi I'm having a bit of bother with my login. I created a login using this tutorial http://www.phpeasystep.com/phptu/6.html and it works perfectly. So i have attempted to change it to meet my own database. So basically i've changed the database, table names etc to meet my own. I haven't changed any other lines. When i run it i get an error message: Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\checklogin.php on line 26 The code is below: Code: [Select] <?php $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="final year project"; // Database name $tbl_name="tbl_user"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // username and password sent from form $mem_username=$_POST['mem_username']; $mem_password=$_POST['mem_password']; // To protect MySQL injection (more detail about MySQL injection) $mem_username = stripslashes($mem_username); $mem_password = stripslashes($mem_password); $mem_username = mysql_real_escape_string($mem_username); $mem_password = mysql_real_escape_string($mem_password); $sql="SELECT * FROM $tbl_name WHERE username='$mem_username' and password='$mem_password'"; $result=mysql_query($sql); // Mysql_num_row is counting table row $count=mysql_num_rows($result); // If result matched $mem_username and $mem_password, table row must be 1 row if($count==1){ // Register $mem_username, $mem_password and redirect to file "login_success.php" session_register("mem_username"); session_register("mem_password"); header("location:login_success.php"); } else { echo "Wrong Username or Password"; } ?> Line 26 is $count=mysql_num_rows($result); I'm baffled as to why the test database worked. I tried another test database but got the same error. baffled.com Hope someone can help MOD EDIT: [code] . . . [/code] tags added. After overcoming this-> error "Deprecated: mysql_connect(): The mysql extension is deprecated and will be removed in the futu use mysqli or PDO instead in this-> $myconnection = mysql_connect($server, $user, $pass);" by changing mysql_query to mysqli_query($con, $query), I started getting this specific error on line 106= $result = mysqli_query($myconnection, $query) or $this->debugAndDie($query);
Warning: mysqli_query() expects parameter 1 to be mysqli, null given on line 106=="$result = mysqli_query($myconnection, $query) or $this->debugAndDie($query);"
This header wont go, I tried $myconnection = mysql_connect($query); and it says expecting 2 parameters.
Please I'm open to ideas to solve this,
<snip - code is posted in next post>
Edited by mac_gyver, 05 June 2014 - 03:28 PM. removed code not in code tags as the op posted it later My brain isn't working... I am trying to get this Prepared Statement to pull Events from my database and display them, but get this error... Quote Warning: mysqli_stmt_bind_param() expects parameter 1 to be mysqli_stmt, boolean given in /Users/user1/Documents/DEV/++htdocs/01_MyProject/events_9.php on line 30 Here is my code... Code: [Select] <?php // Initialize a session. session_start(); // Access Constants. require_once('config/config.inc.php'); // Initialize variables. $eventExists = FALSE; // Connect to the database. require_once(ROOT . 'private/mysqli_connect.php'); // ******************** // Build Event Query * // ******************** $id=1; // Build query. $q = 'SELECT id, name, location, date FROM show WHERE id=?'; // Prepare statement. $stmt = mysqli_prepare($dbc, $q); // Bind variable. mysqli_stmt_bind_param($stmt, 'i', $id); (The last line above is Line 30.) Debbie I've just started to learn PHP and I'm having a little trouble. I'm trying to stick with OOP but I'm having trouble with it. I've coded a database connection and I'm trying to take data from a form and insert it into a database. I've managed to do it without OOP but I can't get it to work with. The code is below. Any help would be great. I have a file for the form, which should take the data and the php should insert it into the table - <?php // Get the PHP file containing the dbConnect class require('../../configuration.php'); // Get the PHP file containing the dbConnect class require('../../lib/db.class.php'); // Checks whether a form has been submitted. If so, carry on if ($_POST) { // Creates an instance of dbConnect $link = new dbConnect(); // Creates a SQL query $insertQuery = 'INSERT INTO content SET title = "' . $_POST['title'] . '", alias = "' . $_POST['alias'] . '", category = "' . $_POST['category'] . '", summary = "' . $_POST['summary'] . '", content = "' . $_POST['content'] . '"'; $result = $link->query($insertQuery, $link); } ?> <body> <form action="" method="post"> <div> <label for="title">Title:</label> <textarea id="title" name="title" rows="1" cols="30"> </textarea> </div> <div> <label for="alias">Alias:</label> <textarea id="alias" name="alias" rows="1" cols="30"> </textarea> <div> <label for="category">Category:</label> <textarea id="category" name="category" rows="1" cols="30"> </textarea> </div> <div> <label for="summary">Summary:</label> <textarea id="summary" name="summary" rows="6" cols="40"> </textarea> </div> <div> <label for="content">Content:</label> <textarea id="content" name="content" rows="12" cols="40"> </textarea> </div> <div> <input type="submit" value="Add Article" /> </div> </form> This is my class to connect to the db - class dbConnect extends siteConfig { var $theQuery; var $link; // Function to connect to the database public function dbConnect() { // Load configuration from parent class $config = siteConfig::getConfig(); // Get main config settings from the array that we just loaded $host = $config['hostname']; $user = $config['username']; $pass = $config['password']; $db = $config['database']; // Connect to the DB $link = mysql_connect('localhost', 'user', 'pass'); if (!$link) { $error = 'Unable to connect to the database server.'; echo $error; exit(); } } // Function to execute a database query public function query($link, $query) { $this->theQuery = $query; mysql_query($this->link, $query); } // Function to get array of query results public function getArray($result) { return mysql_fetch_array($result); } // Function to close the connection public function closeConnection() { mysql_close($this->link); } } I also have a config file. I'm not using it atm but I thought I'd show it anyway as it may help - class siteConfig { var $config; function getConfig() { $config['site_url'] = 'localhost/edencms'; $config['hostname'] = 'localhost'; $config['username'] = 'user'; $config['password'] = 'pass'; $config['database'] = 'edencms'; } } After filling out the form and sending it, I get the following error: Quote Warning: mysql_query() expects parameter 2 to be resource, object given in C:\xampp\htdocs\EdenCMS\lib\db.class.php on line 39 It seems like $link isn't staying as a resource once the dbConnect is called. If I print it in the dbConnect function, it shows it's a resource but if I try to print it after, it shows as an object. I'm not sure why. As I said, I'm new, so go easy I'm an extreme newbie and have this current error on my site. The error states: Warning: mktime() expects parameter 4 to be long, string given in featured_product.php on line 75 <?php for ($i = 0; $i < $num_rows; $i++) { $id = mysql_result($result,$i,"id"); $title = mysql_result($result,$i,"title"); $featured = mysql_result($result,$i,"featured"); $feature_date = mysql_result($result,$i,"feature_date"); $feature_date_arr = explode("-",$feature_date); $feat_date = mktime(0,0,0,$feature_date_arr[0],$feature_date_arr[1],2000+$feature_date_arr[2]); if ( ($feat_date+($featured*24*60*60))<time() ) { $db2->query("UPDATE product_catalog SET featured = 0 WHERE id='$id'"); $featured = 0; } else { $featured = 1; $db2->query("UPDATE product_catalog SET featured = 1 WHERE id='$id'"); } ?> Any ideas on how to correct this? Thanks! I have tired to search this up but get nothing back.. :@ This error is on line 18 on line 18 is Code: [Select] if (mysql_num_rows($result) == 1) { Quote Notice: Undefined variable: result in C:\xampp\htdocs\Exam_Online\Staff_login\Staff_login_process.php on line 18 Warning: mysql_num_rows() expects parameter 1 to be resource, null given in C:\xampp\htdocs\Exam_Online\Staff_login\Staff_login_process.php on line 18 Wrong Username or Password This is the error message. Code: [Select] if (mysql_num_rows($result) == 1) { // Set username session variable $_SESSION['ID'] = $_POST['ID']; header("location:Staff_Menu.php"); } else { echo"Wrong Username or Password"; } |
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