PHP - Set Time To Variable
Hi, how to set current time to variable then use it to add new record to DB? $loginDate = date("Y-m-d"); $loginTime = ??? Thanks Similar TutorialsProbably something simple but I have searched high and low and can't figure this one out. I have a variable that is of the datetime format. I have another variable that is of the time format. I need to add them together. Example: $var1 = 2012-02-24 06:38:22 $var2 = 02:00:00 $var3 = $var1 + $var2 = 2012-02-24 08:38:22 Thanks for the help! PHP date and time function is not showing correct time on my local system I have the following php code date_default_timezone_set("Africa/Lagos"); $date = date('d-m-y h:i:s'); echo "Server Time ".$date ."<br>"; echo "The time is " . date("h:i:sa")."<br>"; $current_datetime = date("Y-m-d") . ' ' . date("H:i:s", STRTOTIME(date('h:i:sa'))); echo "Current time1: ".$current_datetime . "<br>";
Output
Server Time 21-05-21 09:55:39
Expected Output
Server Time 21-05-21 10:55:39
Any help would be appreciated. Edited May 21 by Ponel I am trying to simulate an ad expiration and carry out an action if the ad is expired. And I cannot get the if/else to work properly... I've tried many variations and I cannot see what I am doing wrong here. Any tips please 3 hours and counting of no solution! $ad_start = time()-14 . "<br />"; // 14 days from today in the past (negative) echo $ad_start; $current_time = time() . "<br />"; // current epoch time echo $current_time; $days_past = $ad_start - $current_time; // days past echo "<br />$days_past days have past since the ad started!<br />"; if($days_past <= 14) { echo "<br />Ad is less than 14 days. Not expired."; } else { echo "<br />Ad is over 14 days. Expired."; } Basically I have recently been playing around with parsing a csv file. What I am looking to do at this point is simply take the date/timestamp (part of the csv file), which is in the following format:DD/MM HH:MM:SS.100th/s For the sake of argument, lets say I have this in an array string called $csv[0] and the file has several lines that span the course of a couple hours. I wouldn't mind having to use explode() to breakup/remove the date or 100th/s IF that would make things a lot simpler. So where would I start in trying to achieve this?. The result I am looking for will simply return "X Seconds". Storing this in a string variable would be a bonus, as I plan to use this to divide a separate piece of information. Any examples or ideas would be great. Thank you. ps: Here is an example time from the csv file itself: Code: [Select] 11/19 22:23:18.143 OK So I've got a datepicker that sends a date in d/m/y format. My DB stores the data in Unix Timestamp Which I can convert the date to with strtotime however this does the exact date & time. All I want is the actual day. I've spent hours trying to convert this with just the day with mixed results... Thanks. PHP 5.2.6 We rent PHP server space on a server in California. Several of my pages generated by PHP show the current date and time, so when the page is printed, the user knows when the data was printed. Our users could be anywhere in the US, I am in Michigan. How do I convert the server time (PDT) into local time, regardless of where the user is? Thanks. Hello, I tried to implement some PHP code to enable a web page to show "Dinner" specials versus "Lunch" specials based on the time. The business is located in the Eastern Time Zone, so I only need to routine to work based on Eastern Time (New York). What I am noticing is that the server is processing the lines of code so fast that the command to establish the correct time for the remaining code is not always being acknowledged. This line of code appears to be processing too fast for the remaining lines of code: date_default_timezone_set ( "America/New_York" ); Is there some additional code I can put in place to make sure the correct time is always ascertained? I need the $hourmin variable to always return a combination of hour + minute based on 24-hour time and Eastern Time zone. My code is as follows: <?php $name8 = file_get_contents("test/special8name.txt"); date_default_timezone_set ( "America/New_York" ); $gethour = date("H"); $getminutes = $gettimedate["minutes"]; $gettimedate = date(); $hourmin = $gethour . $getminutes; $currentday = date("l", time()); $currentdate = date("M j, Y"); if ($hourmin < 1500 && $currentday <> "Saturday" && $currentday <> "Sunday") { echo "<span class=\"namesred\">$name8 </span>"; } else if ( $hourmin > 1500 && $hourmin < 2300 && $currentday <> "Saturday" && $currentday <> "Sunday") { echo "<span class=\"namesblue\">$name8 </span>"; } else if ( $currentday == "Saturday" or $currentday == "Sunday") { echo "<span class=\"namesblue\">$name8 </span>"; } ?>
What are the differences and implications of UTC time and Zulu time? <?php function getArr(string $time):array { $dateTime = new \DateTime($time); return [ 'time'=>$time, 'timestamp'=> $dateTime->getTimestamp(), 'dateTime' => $dateTime ]; } $arr = getArr('2020-08-05'); $arr_z = getArr('2020-08-05T00:00:00Z'); print_r($arr); print_r($arr_z); echo('equal timestamps: '.($arr['timestamp'] === $arr['timestamp']?'true':'false'));
Array ( [time] => 2020-08-05 [timestamp] => 1596585600 [dateTime] => DateTime Object ( [date] => 2020-08-05 00:00:00.000000 [timezone_type] => 3 [timezone] => UTC ) ) Array ( [time] => 2020-08-05T00:00:00Z [timestamp] => 1596585600 [dateTime] => DateTime Object ( [date] => 2020-08-05 00:00:00.000000 [timezone_type] => 2 [timezone] => Z ) ) equal timestamps: true
This topic has been moved to Application Design. http://www.phpfreaks.com/forums/index.php?topic=316461.0 I am having a problem with PHP displaying the correct date and time. It updates as it should, but is fast by 4min and is always displaying a date in 2004. I ran a basic php script to make sure the application im using itself is not wrong. go to lunenburgledger.com/time.php Anybody had any ideas on where to check? The system time on the Windows Server 2003 is correct. The only thing I can think of is that it was converted to a virtual machine on vmware esxi, but the system time stayed right. Any ideas? Thanks! Hi, The hosting provider for my domain confirm me that the server time is in EST (UTC-5). They also sent me a grab supporting that Code: [Select] server time is now: ---------------------- Sun Nov 7 02:20:01 EST 2010 ------------------- But when I use the following code, the output I get is has 1 hr difference (UTC-6) echo date("d M, Y h:i:s A",time()); Output==> 07 Nov, 2010 01:20:01 AM But it suppose to give the same time as the server, ryt? Can anybody please explain? Thanks, Let's say I am buying a share for $10. If I sell the share on the same day BEFORE 3:30PM, it will be sold for $10, but if I keep the share past 3:30PM, I want the code to automatically add $1 (Taxes and such) once in the the price of the share in database, after that no matter how many days pass by, the price will remain the same.
I've thought about CRON jobs, but I have no idea how to make/use them or set them up.
Any direction or help is appreciated.
I am making a time clock, and I was wondering what is the best way to calculate the number of hours an employee worked? I have a table called "statuses" it holds names of punch types: - id = the auto_inc - status = "in/out/break/lunch" text statuses - paid = whether or not the punch is paid or not (true/false) I have another table called "logging" This table holds the information about the punch type: - id = the auto_inc - owner = the member id - ip = members ip - inout = the punch type from the statuses table - location = the city/state of where the punch took place - date = the time the member punched Maybe I am over thinking this, but what is the best way to calculate the hours a person has worked? Right now I am getting all the punches for for a particular member between a date range. then loop through the data to display it and passing it to a method in a class called Calc. I want to then add the times from punch in to punch out, then the next punch in to punch out. Any suggestions? I have this: $sql = mysqli_query($conn, "SELECT ip , page , CASE WHEN referrer = '' THEN 'N/A' ELSE referrer END as referrer , DATE_FORMAT(date, '%m/%d/%y') as date , TIME_FORMAT(time, '%T') as time FROM tblTraffic ORDER BY date DESC, time DESC"); most of my traffic report contains the correct times, my time, which is CST in the USA. but some records are off by a lot. Does the time() function capture the time of the actual location from which the visitor is coming from? if so, what could I do to return my timezone for any visitor? w3 schools and php.net don't mention this. Hey Guys! I have the following doubt. When echoing from Server like this: Code: [Select] echo "time=" . time(); I get the time in the following raw format: 1299272294 I would really like to echo it with this format: Tue Mar 1 23:50:00 GMT-0300 2011 Is there a way I could do that? Really looking forward for some help on this one, Thanks a lot in advance! Cheers! Hey guys, How would I go about subtracting Today from a previous day to find the difference? For example, I want to subtract TODAY from a previous date in my database, to determine if the difference is greater than 1 day. Any ideas? I tried doing the subraction in TIMESTAMPS, but when I convert the date back to Y-m-d H:i:s, I got some weird year and time. Hello all. I am very new to PHP, and I am not sure where to look or what I'm looking for in my current assignment. My task is to take in two numbers between 0-100. Once I take in that number, it should state beside it "The __ was accepted." The program should not accept any numbers greater than 100 or any characters. Once I do this, I must take a second number and do a similar thing. Finally, I must have a statement show up at the bottom stating which number is greater. Essentially, I need help in determining what I should use to place parameters, and how I can keep the program from echo ing any statement until input has been taken and tested for parameters. Any help you can provide will be greatly appreciated! I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here. It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere. <?PHP require('connect.php'); ?> <form action ='' method='post'> <select name="id"> <?php $extract = mysql_query("SELECT * FROM cars"); while($row=mysql_fetch_assoc($extract)){ $id = $row['id']; $make= $row['make']; $model= $row['model']; $year= $row['year']; $color= $row['color']; echo "<option value=$id>$color $year $make $model</option> ";}?> </select> Which attribute would you like to change?<br /> <input type="radio" name="getchanged" value="make"/>Make<br /> <input type="radio" name="getchanged" value="model"/>Model<br /> <input type="radio" name="getchanged" value="year" />Year<br /> <input type="radio" name="getchanged" value="color" />Color<br /><br /> <br /><input type='text' value='' name='tochange'> <input type='submit' value='Change' name='submit'> </form> //This is where I need help... <?PHP if(isset($_POST['submit'])&&($_POST['tochange'])){ mysql_query(" UPDATE cars SET '$_POST[getchanged]'='$_POST[tochange]' where id = '$_POST[id]' ");}?> I have just re-installed Xampp and suddenly my sites are now displaying lots of: Notice: Use of undefined constant name - assumed 'name' in ... Notice: Use of undefined constant price - assumed 'price' in ... this is an example of the line its refering too: $defineProducts[1001] = array(name=>'This is a product', price=>123); My login script stores the user's login name as $_SESSION[ 'name'] on login. For some unapparent reason, i'm getting errors stating that $user and $priv are undefined variables, though I've attempted to define $user as being equal to $_SESSION['name'], using $user to look up the the user's privilege level (stored as the su column ) in the SQL table, and then where the result of the sql query is $priv which is then evaluated in an if statement. I can't seem to figure out why this might not be working. The code I'm using: <?php session_start(); function verify() { //verify that the user is logged in via the login page. Session_start has already been called. if (!isset($_SESSION['loggedin'])) { header('Location: /index.html'); exit; } //if user is logged in, we then lookup necessary privleges. $_SESSION['name'] was written with the login name upon login. Privleges // are written in db as a single-digit integer of of 0 for users, 1 for administrators, and 2 for special users. $user === $_SESSION['name']; //Connect to Databse $link = mysqli_connect("127.0.0.1", "database user", "password", "database"); if (!$link) { echo "Error: Unable to connect to MySQL." . PHP_EOL; echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL; echo "Debugging error: " . mysqli_connect_error() . PHP_EOL; exit; } //SQL Statement to lookup privlege information. if ($result = mysqli_query($link, "SELECT su FROM accounts WHERE username = $user", MYSQLI_STORE_RESULT)) { //LOOP TO CYCLE THROUGH SQL RESULTS AND STORE Privlege information as vairable $priv. while ($row = $result->fetch_assoc()) { $priv === $row["su"]; } } // close SQL connection. mysqli_close($link); // Verify privleges and take action. Only a privlege of "1" is allowed to view this page. A privlege of "2" indicates special //accounts used in other scripts that have certain indermediate additional functions, but are not trusted administrators. if ($priv !== 1) { echo $_SESSION['name']; echo "you have privlege level of $priv"; echo "<br>"; echo 'Your account does not have the privleges necessary to view this page'; exit; } } verify(); ?>
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