PHP - How Do I Submit A Single Form From Multiple Forms On The Same Page.
I am creating a user inbox system. I am retrieving all the unread messages. Each message row contains a "reply" form. So say I have 10 messages showing on a single page. That's 10 forms. What I would like to know is how can I submit any one of the 10 forms and not have it affect the remaining 9 forms? Here is the basic code. if(isset($_POST['submit'])) { $post_message = trim($_POST['message']); $errors = array(); $db->beginTransaction(); if(empty($post_message)) { $errors[] = 'The message field can not be empty!'; } if(empty($errors)) { $db->commit(); echo 'success'; } else { $db->rollBack(); } } <form action="" method="post"> <fieldset> <textarea name="message" maxlength="10000" placeholder="What would you like to say?"></textarea> </fieldset> <fieldset> <input type="submit" name="submit" value="Submit" /> </fieldset> </form>
Similar TutorialsSay I have an "Entries" table. I want to submit same multiple entries using a form submission. And If I have other queries submitted in the same form, I want those quarries to be submitted only once. Is that possible to do? Here's my code. if(isset($_POST['submit'])) { $entries = 10; $id = 55; $name = 'Smith'; $insert = $db->prepare("INSERT INTO entries(id, name) VALUES(:id, :name)"); $insert->bindParam(':id', $id); $insert->bindParam(':name', $name); $result_insert = $insert->execute(); if($result_insert == false) { echo 'Fail'; } else { echo 'Success'; } } ?> <form action="" method="post"> <input type="submit" name="submit" value="SUBMIT" /> </form> Edited January 13, 2019 by imgrooot hi i need help on posting multiple inputs in a single button...while using mysql_fetch_array here is my codes: <? $re6 = mysql_query('select username from users where course = "BSIT" and yearlevel = "FOURTH"'); ?> <br /> <h1>Post Grade</h1> <h1>IT, Fourth Year</h1> <br />Please fill the following form to send The Grade<br /> <? $n = 0; while($row = mysql_fetch_row($re6)) { echo'<form action="grade_post.php" method="post">'; echo'Recipient<span class="small">(Username)</span><input type="text" value="'.$row['username'].'" readonly="readonly" id="recip" name="recip[' . $n . ']" />'; echo'Subject<input type="text" value="'.htmlentities($otitle, ENT_QUOTES, 'UTF-8').'" id="title" name="title[' . $n . ']" />'; echo'<input type="hidden" value="FOURTH" id="year" name="year[' . $n . ']" />'; echo'<input type="hidden" value="FIRST" id="sem" name="sem[' . $n . ']" />'; echo'Grade<input type="text" id="message" name="message[' . $n . ']" ><br />'; ++$n; } ?> i get all my recipients in every input type, but when i tried to post it in my database not all of them are posted rather only one of them are posted in my database ...what i want to happen is that all of my recipients in every input type will be posted in my database with different ids'...help pls... Which one is better for standards practices in PHP. 1. Using the same form for everything. (Add and edit). Meaning setting up one form to handle adding new records, as well as editing existing records. Or 2. Using two different forms for both actions. Use one form/area to handle Adding, and one form/area to handle editing. Which one of these are better from a standards/practice point of a view. Which one better fits into the MVC platform (a framework like Codeignitor, or Cake). Should their be separate controller functions/views for add and edit or should they all be in the same controller function/form. Thanks for the feedback. Hey guys, I'll be the first to say that I'm a real php n00b, and only understand the basics. I have a website already in place that someone else coded and I just need to add something to. There's a form that posts to another page and then back to a sql database. What I want to do is have the form also email me the contents of the form when it is submitted. Is there a way to have a form do multiple actions? I'm not sure the best way to go about this, so if someone has some pointers, I'd really appreciate it. Thanks! You would think the answer would be all over the Internet and easy to find, but it’s not. I have searched many times, and in all the multitude of search results I have still never found an adequate usable answer. The MOST you ever find is someone saying how easy it is with PHP, but they don’t tell you how, even when the person they are answering asks them (odd). You can be that one in a billion person who finally answers it for real and helps someone out. I have a simple HTML form with data fields first_name, last_name, email, phone, country, a few hidden inputs, and a single submit button, like so: (Please note: the method is GET, not Post.) <form action="https://MyDomainOnMyServer.com/MyPHPScript.php”> <input type="text" name="first_name" value="" /> <input type="text" name="last_name" value="" /> <input type="text" name="email" value="" /> <input type="text" name="phone" value="" /> <input type="hidden" name="type" value="type123"> <input type="hidden" name="project" value="new123"> <select required name="country"> <option value="">Choose your country</option> <option value="US">United States</option> <option value="CA">Canada</option> <option value="GB">United Kingdom</option> <option value="Many More">Many More Countries</option> </select> <input type="submit" value="Submit Form" /> </form> NOTE: Originally, the form action would have been: action="https://TheirExampleDomainOnTheirRemoteServer.com/TheirRemotePHPScript.php" name="form1234" Upon clicking the single submit button only, what I need to have happen is this: 1. Send me an email to whatever@whatever.tld containing all the form submission data 2. Place the form submission data into a MySQL database having the corresponding data fields 3. Send the form submission contents including the hidden input values to "https://TheirExampleDomainOnTheirRemoteServer.com/TheirRemotePHPScript.php" name="form1234" AS IF that had remained set as the original form action to begin with So basically what I’m trying to obtain is the cleanest possible PHP script that will do those three things, which is essentially what others have asked for over the years in search results I have found, but no one has ever provided it in a clear instance that works. If I can just see such a script, I should be able to see how it works and then do what I need. Thanks. Reply Hey all, I am building a simple cms. I have a posts table and I have an images table. A post has many images and images has a foreign key to the posts table. So when a user edits, updates, creates, and deletes a post, they affect the images related to the post. Sometimes a post can have more than one image, like three images. Hence I rendered this in the view (note that I am using a datamapper that converts tables to objects and fields to key/value pairs): Code: [Select] foreach($records as $post){ echo form_open_multipart("homes/update/$post->id"); //File uploads require a multipart form. Default form handling uses the application/x-www-form-urlencoded content type. Multipart forms use the multipart/form-data encoding. //this is critical to pass the id as part of the action attribute of the form, so we can use our params hash to target the id to update the specific record echo label('Update Title'); echo form_input('title',$post->title); echo label('Update Body'); echo form_textarea('body',$post->body); $images = $post->images->include_join_fields()->get(); if(!is_null($images->image_file_name)){ echo label('Update Images'); foreach($images as $image){ echo form_upload('image_file_name',$image->image_file_name); } } } echo form_submit('submit','Update'); The above line of code will render a few input file types. The problem occurs during posting to my update method. It is looking for one parameter from the input file field and so if I upload three different images, it will only look for one and write only one to database: Code: [Select] $field_name = 'image_file_name'; if ( ! $this->upload->do_upload($field_name)){ $error = array('error' => $this->upload->display_errors()); echo $error['error']; // redirect('homes/edit'); } else { $data = array('upload_data' => $this->upload->data()); $image_file_name = $data['upload_data']['file_name']; Is it possible to do wht I am trying to do? Should I only have on input file type per form submission or is that I need to fix the code to accomodate for multiple submissions by creating an array of sorts? Thanks for response. Hi, I've tried to follow a couple tuts on multi-page forms using php. The reason I'm doing it is that I'd like to create a mock-job application form for my students at school. This would be too long to have on one page. Anyway, I've created the most simple form I could think of and was hoping someone could help me out and show me how to get the info from page 1 to 2, then the info from pages 1 and 2 to 3, and then submit the info from pages 1, 2 and 3 to the database. Page 1 asks for firstname, page 2 asks for lastname, and page 3 asks for email address. The fourth page is the one that processes the form. Page 1: (app_form_1.php) Code: [Select] <form id="form1" name="form1" method="post" action="app_form_2"> Firstname: <label> <input type="text" name="firstname" id="firstname" /> </label> </form> <p> <label> <input type="submit" name="Continue" id="Continue" value="Continue" /> </label> Page 2 (app_form_2.php) Code: [Select] <form id="form1" name="form1" method="post" action="app_form_3"> Lastname: <label> <input type="text" name="firstname" id="firstname" /> </label> </form> <p> <label> <input type="submit" name="Continue" id="Continue" value="Continue" /> </label> Page3 ( app_form_3.php ) Code: [Select] <form id="form1" name="form1" method="post" action="app_form_process"> Email address: <label> <input type="text" name="emailaddress" id="emailaddress" /> </label> </form> <p> <label> <input type="submit" name="submit" id="Submit" value="Submit" /> </label> Page 4 (app_form_process.php ) Code: [Select] <?php global $_POST; $firstname = $_POST["firstname"] ; $lastname = $_POST["lastname"]; $emailaddress = $_POST["emailaddress"]; //**********************SEND TO DATABASE**************************** //MySQL Database Connect include 'mysql_connect.php'; $query = "INSERT INTO application_form (firstname, lastname, emailaddress)" . "VALUES ('$firstname', '$lastname', '$emailaddress')"; //if($query){echo 'data has been placed'} mysql_query($query) or die(mysql_error()); ?> Any help is much appreciated. Thanks, Dave Hi I have put together a options page for the script that I have been working on. I have 1 options page where there options are divided into 4 jQuery tabs with there own save button. The options in each tab are posted using Ajax to their own separate file like process.php, process1.php etc. My question is there a way to place all the processing code in one file and if so would this affect the load on the server? Would each form be better off having their own page for processing? For example: Code: [Select] <form id="options_1" action="process1.php" method="post" > <!-- this is form 1 that is processed with process1.php --> </form> <form id="options_2" action="process2.php" method="post" > <!-- this is form 2 Can this form be processed using process1.php instead of process2.php --> </form> <form id="options_3" action="process3.php" method="post" > <!-- this is form 3 Can this form be processed using process1.php instead of process3.php --> </form> Hey guys, im new to php and have become stuck with having more than one html form/submit that will relays to another piece of code to view something At the moment my first form works but once i submit my second form it relays back to the first form how can i prevent this so i can have many submit forms on one php page? Thanks Code: [Select] <?php $dbname = $_POST['dbname']; $tblname = $_POST['tblname']; checksubmit( $dbname); function checksubmit( $dbname){ if(isset($_POST['enter'])) { checkform( $dbname); } else { page1( $dbname); } } function checkform ($dbname){ if(empty($_POST['dbname'])){ echo 'fill out database name'; } else page2( $dbname ); } function page1( $dbname){ echo " <form method='post' action=''> <table> <tr> <td>Database name:</td><td><input type='text' name='dbname' /></td> </tr><tr> <td colspan='2' align='right'><input type='submit' name='enter' value='enter' /></td> </tr> </table> </form> "; } function page2( $dbname ){ echo " <form method='post' action=''> <table> <tr> <td>Table Name:</td><td><input type='text' name='tblname' /></td> </tr><tr> <td colspan='2' align='right'><input type='submit' name='return' value='return' /></td> </tr> </table> </form> "; if(isset($_POST['return'])) { page3( $dbname ); } } function page3( $dbname ) { echo 'I want to make it here'; } ?> Hey all, This question is coming forth of another topic, but since that topic is not really about this issue, I posted this new topic. Okay, so I made a table, and each row is generated with a WHILE loop. In this while loop, there's also a form generated for each row/record, for updating them seperately. I'm having trouble with naming those forms to process them seperately. I could name them like name="form20110001", with the number being the record's id. But since there can be gaps between id's, how can I retreive them efficiently? And I want them to process all on a single process page, obviously. How can I do this easily? Can someone give me a concise example? Would appreciate it a lot. Thanks Hi Guys, I am attempting to create a program for a local auction house. I arrived at a stand still on a certain issue which is creating a sticky form. On the "enter auction details page" the user will be entering data as the auction is in session. 1. item Description 2. Item Price 3. Bidders Id 4. Qty Of course it would be repetitive to require the user to keep entering the same data for every bidder, so I want to stick the obvious fields which are "item description" & "Item Price" as these don't change until a new item comes up for sale. As of know I am processing the input on a separate page which records all input to the database with a redirect back to the "enter auction details page". I have tried many times to get the item description and item price fields to stick. These would need to change as the user moves onto the next item in which the description and price would change as well. Here is my current code for this part: Code: [Select] <?php session_start(); $field_itemDescription = ""; //iyem description, default as blank if (isset($_SESSION['itemDescription'])) $itemDescription = $_SESSION['itemDescription']; ?> <form action="record_trans.php" method="post"> <font face= "calibri" size= "4"> <table> <tr> <td><b>Item Description:</b></td> <td><input type= "text" name= "itemDescription" size= "30" value="<?php echo $itemDescription;?>"></td> </tr> <tr> <td><b>Item Price:</b></td> <td><input type= "text" name= "itemPrice" size= "5" value="<?php echo $itemPrice;?>"> </td> </tr> </tr> <td><b>Winning Bidders:</b></td> <td><input type="text" name= "bidderId" size= "5" /> </td> </tr> <tr> <td><b>How many deals?:</b></td> <td><input type="text" name= "itemQty" size= "3" value= "1" /></td> </tr> </table> <center><input type="submit" name="submit" value= "Save & Cont." " /></center> </form></font> This seems to be a bit of a challenge but I am creating a multiple page form and on one of the pages I have a select field. I would like the user to have the ability to select multiple options but I am using some functions to move the data in hidden fields from page to page. I don't think my functions are jiving with my my foreach loop cause I keep getting an invalid argument error. Thanks in advance for any help. Here is my function: function setSelected($fieldName, $fieldValue) { if(isset($_POST[$fieldName]) && $_POST[$fieldName] == $fieldValue) { echo 'selected="selected"'; } } And here is my loop: $selections = ""; if(isset($_POST["selections"])) { foreach ($_POST["selections"] as $selection) { $selections .= $selection . ", "; } } hi i hv a form to submit on this url http://localhost/site/index.php?action=search and in my html <form method="GET" action="<?php echo $_SERVER['PHP_SELF'];?>" name="searchForm"> // my code </form> // i also tried //http://localhost/site/index.php?action=search& // but did not helped now problem is i wants to go that URL so after submit it should look a like this as i am loading search page with action. http://localhost/site/index.php?action=search&searchstring=word but it keeps me redirecting to http://localhost/site/index.php?searchstring=word how can i make it work so it will goto this URL http://localhost/site/index.php?action=search&searchstring=word Thanks for help. I have the website he http://bossexclusive.com/babyauction/index.php , and http://bossexclusive.com/babyauction/thanks.php . When you press submit on the index.php, it takes you to thanks.php. then, after 5s, it takes you back to index.php. My question is: How could I make it so when I press submit, the box submits the form, but instead of redirecting to thanks.php, it displays the same thank you message on the side, but stays on index.php? If that didn't make sense, let me know. My html and php are below (HTML) Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Baby Auction | Discounted Premium Brand Baby Products</title> <link rel="stylesheet" type="text/css" href="styles.css"/> </head> <body> <div id="main"> <div id="contact"> <h1>Sign up to recieve Auction notifications</h1> <form action="emailer.php" method="post"> <input type="text" name="email" id="email" placeholder="yourname@email.com" /> <input type="image" name="submit" src="images/submit.jpg" width="146px" height="20px" value="Submit"> </form> </div> </div> <div class="copyright"> <?php include 'footer.php'; ?> </div> </body> </html> and emailer.php: Code: [Select] <?php $email = trim(strip_tags($_POST['email'])); $subject = "Contact form submitted!"; $to = 'BlankingOutMyEmail@gmail.com'; $body = <<<HTML $message HTML; $headers = "From: $email\r\n"; $headers .= "Content-type: text/html\r\n"; mail($to, $subject, $body, $headers); header('Location: thanks.php'); ?> I have two pages. one is insert_events.php and the other is veiw_events. In insert_events i have a form which have a submit button. I want when i click on the submit button, it redirects me to the view_events.php page showing the events. Any idea about this problem will be appreciated. Thanks Hi All, Is there any way that PHP can detect if a page has been refreshed? Basically I have a form that when submitted, inserts a row in to a database, but I am finding that when I refresh the page, it repeats the insert statement. Any ideas? Thanks Matt Hi everyone, as the title stated, I would like to know how I could submit a form in one page(cart) and unset a session variable on other page.
Right now my form is setting a variable within the page back to 0, however I would like the form to unset the session variable from other page as well.
The issue with my code is that every time I attempt to clear out all items, my code can empty out the cart. But whenever I close and reopen the cart, the same content will show up again. So I need to unset the session variable.
Please let me know what should I do in order to solve the problem and I greatly appreciate your help.
My code is currently looking like this:
cart.php
if(!empty($_GET['aID'])) { $aID = $_GET['aID']; echo $aID; if(isset($_POST['removeAll'])) { $aID = "0"; } $cartSQL = "SELECT * from article where aID in ($aID)"; echo "cart sql :$cartSQL"; $cartQuery = mysqli_query($dbc, $cartSQL) or die (mysqli_error($dbc)); while($row = mysqli_fetch_array($cartQuery, MYSQLI_BOTH)) { $aTitle[] = $row[ 'name' ]; } } <form action = "" method = "POST"> <td style = "width = 200px"><input type="submit" value="Empty cart" name="removeAll"></td> </form>And this is the session variable from other page where I would like it to be unset upon submitting the form. if(!empty($cartSubmit)) $_SESSION["cartSubmit"] = $cartSubmit; else $cart = $_SESSION["cartSubmit"]; <a href="javascript:popup('cart.php?aID=<?php if(empty($cartSubmit)) echo "$cart"; else echo "$cartSubmit";?>')">Cart</a> Alright, so I play a browser game called Politics and War. I run an alliance that has 74 members. In that alliance we offer a bank service for all our members, but I - being the leader - am the only one who can access the bank. I have been building a site that works with the game API to gather data for members and create a dashboard. One of the features I am trying to build is allowing them to withdraw from their account instantly.
So, what I need: To be able to submit a POST request to login to the site (specifically on this page --> https://politicsandwar.com/login) with my username and password, but then I need to keep the session active and navigate to a different page (the alliance bank page). On that page I first need to scrape a value from a hidden input (token) and then I need to submit a POST request to this same page while still being logged in.
I am not asking someone to do it for me, but rather someone to help me know how to go about this. I have never submitted post requests with PHP, but I have used PHP cURL in the past. I also have made POST requests with JS, but never PHP.
Thank you so much for anyone that is able to help! I have two pages one is db.php and another is form.php. In form.php i have created a form which contains different fields and a submit button. But i want to write the queries in db.php. And when i click on the submit button the insert query in db.php should be executed and insert data in database but the focus remains on form.php. How can i do this??? Any Idea? Hi Guys, I am fairly new to PHP, and I recently changed my whole site to use PHP sessions, which worked fine. Then I added PHP parts in my pages that display different menu choices depending on if a PHP session exists. This also works fine, until I found that any HTML/PHP pages that have form/submits no longer work, and I get kicked back to the index.php After slow backtracking, I removed new parts, and found the forms started working again if I removed the PHP part that chooses which JavaScript file to reference, as follows from contact.php <?php if (isset($_SESSION['SESS_MEMBER_ID'])){ echo "<script language=\"JavaScript\" type=\"text/javascript\" src=\"menu_horz.js\"></script>"; } else {echo "<script language=\"JavaScript\" type=\"text/javascript\" src=\"log_menu_horz.js\"></script>"; } ?> I tried changing the echo ".." to use single quotes ' ' instead, but then it doesn't work at all then with a form or no form on the page. I assume I am doing something wrong, but I can't find any resources that give me a definitive way of referencing Javascript files. What freaked me out was only the ones with forms were an issue. I am using <?php session_start(); ?> at the beginning of every page (before any output). Other PHP code on the page is working fine. Only the above part seems to be the problem, and works too, as long as I don't submit a form. - Could it be more weirder :-) - I tried also to find a workaround, but it would mean having PHP inside my JavaScript file, but I am not sure it would work, since JS is client side, and PHP server... Essentially, I just want to run certain JS menus depending if the person is logged in or not. - Example contact.php attached Any ideas of what the problem might be with the code above? Will be grateful for any help you can give. Regards D |