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PHP - Php Mysqli Update
Dear Sir/Madame I am making a website where user can insert data and wait for the admin to approve/reject the form. Now i am stuck with the update status where an admin can submit with a click pending to approval or reject with comments. I am new to PHP programming. Can somebody help me with the issue. Part 1 is inserting the data and part two is fetching the data but i am unable to solve the status approve/reject and comment at the same time on the view.php? page. Kindly help. Thank you.
<?php
$host="localhost";
$username="root";
$pass="";
$db="ems1";
$conn=mysqli_connect($host,$username,$pass,$db);
if(!$conn){
die("Database connection error");
}
// insert query for register page
if(isset($_REQUEST['proposal']))
{
$details=$_POST['details'];
$location=$_POST['location'];
$date=$_POST['date'];
$time=$_POST['time'];
$status="Pending";
$comment=$_POST['comment'];
$query="INSERT INTO `proposal` (`details`,`location`,`date`,`time`,`status`,`comment`) VALUES ('$details','$location','$date','$time','$status','$comment')";
$res=mysqli_query($conn,$query);
if($res){
$_SESSION['success']="Not Inserted successfully!";
header('Location:');
}else{
echo "Leave not Applied, please try again!";
}
}
?>
<div class="col-xs-6 col-xs-push-3 well">
<form class="form-horizontal" method="post" action="" >
<input type="hidden" name="proposal" value="">
<fieldset>
<legend>New Proposals </legend>
<!----left box----------->
<!----right box----------->
<div class="col-xs-9">
<div class="form-group">
<label for="inputEmail" class="col-lg-3"><b>Details:</b></label>
<div class="col-lg-9">
<input type="text" name="details" class="form-control">
</div>
</div>
<div class="form-group">
<label for="inputEmail" class="col-lg-3"><b>Location:</b></label>
<div class="col-lg-9">
<input type="text" name="location" class="form-control" >
</div>
</div>
<div class="form-group">
<label for="inputEmail" class="col-lg-3"><b>Date:</b></label>
<div class="col-lg-9">
<input type="date" name="date" class="form-control">
</div>
</div>
<div class="form-group">
<label for="inputEmail" class="col-lg-3"><b>Time:</b></label>
<div class="col-lg-9">
<input type="time" name="time" class="form-control" >
</div>
</div>
<div class="col-lg-9">
<input type="hidden" name="status" class="form-control" >
</div>
</div>
<div class="form-group">
<label for="inputEmail" class="col-lg-3"><b></b></label>
<div class="col-lg-9">
<input type="hidden" name="comment" class="form-control">
</div>
</div>
</div>
<div class="form-group">
<div class="col-lg-12">
<button type="reset" class="btn btn-default">Cancel</button>
<button type="submit" class="btn btn-primary">Submit</button>
</div>
</div>
</fieldset>
</form>
</div>
</div>
<body>
<h2 style="text-align:center; color:orangered;">
DASHBOARD
</h2>
<table>
<h3>
<tr style="background-color:#E4EBC5; color:orangered;">
<th>ID</th>
<th>Details</th>
<th>Location</th>
<th>Status</th>
<th>Comment</th>
</tr>
</h3>
</table>
<?Php
////////////////////////////////////////////
require "dbconfig.php"; // MySQL connection string
$count="SELECT id,details,location,time,status,comment FROM proposal";
if($stmt = $connection->query($count)){
while ($nt = $stmt->fetch_assoc()) {
echo "
<body>
<table>
<tr>
<td><a href=view.php?id=$nt[id]>$nt[id]</a></td>
<td>$nt[details]</td>
<td>$nt[location]</td>
<td>$nt[status]</td>
<td>$nt[comment]</td>
</tr>
</table>
</body>
";
}
}else{
echo $connection->error;
}
?>
Similar TutorialsHi, I am having trouble coding for mysqli update. Please, somebody tell me the correct way. I'm trying to update the "lastused" (current date) field in "emailtbl". Somebody please tell the best way to code this. Below is the message and following, the current code: Fatal error: Call to undefined function curdate() in C:\xampp\htdocs\home\lastused.php on line 14
$db = new mysqli('localhost', 'root', 'pass', 'mydb');
if($db->connect_errno > 0)
{die('Unable to connect to database [' . $db->connect_error . ']');}
$sql = <<<SQL
SELECT *
FROM `emailtbl`
WHERE `id` = '$id'
SQL;
if(!$result = $db->query($sql))
{die('There was an error running the query [' . $db->error . ']');}
$lastused = $_POST['lastused'];
$lastused = curdate();
echo "last date accessed is ".$data['lastused'];
$result->free();
$db->escape_string('This is an unescape "string"');
$db->close();
?>
$update
= mysqli_query($dbconnect, "UPDATE emailtbl SETlastused = curdate() WHERE id ='$id'"); if($update == false) { die("UPDATE FAILED: ".mysqli_error($dbconnect)); } echo "$lastused is the last date this account was accessed"; Hi, i have a user update function in my code so I can easily change user fields int he database public function updateUser ($username, $value, $what) { $q = "UPDATE `users` SET ? = ? WHERE username = ?"; if ($stmt = $this->db_connection->prepare($q)) { $stmt->bind_param("sis", $what, $value, $username); $stmt->execute(); } } The database is connected successfully, but say i run a updateUser('blaine0002', 'blah', 'password'); nothing would get updated and no errors are thrown. Am i doing something wrong? Thank you! I have several registration systems that were designed some time ago running mysql. How long do I have until I have to competely move to mysqli? I am working on recoding them, but it is taking some time. Does anyone know when it will become an issue?
Hi folks, This has been wrecking my brain. I did do a google a few times to see if I can find a solution but nothing unfortunately. I want to be able to update the details on a page without having to reupload a new image each time. But if I don't open a new image for upload, I cannot update any of the other details. Below is the code and form etc for this particular thing... Please note this is just a project and will not be going live. I know there are vulnerabilities and I will work on those at a later stage. Thanks for any help with this current issue.
<?php
include_once('includes/header.php');
if(isset($_POST['new']) && $_POST['new']==1){
if (isset($_POST['submit'])) {
if(!empty($_FILES['image']['name'])) {
// Get image name
$image = $_FILES['image']['name'];
$image = mysqli_real_escape_string($con, $_FILES['image']['name']);
$slide_text = mysqli_real_escape_string($con, $_POST['slide_text']);
$youtube = mysqli_real_escape_string($con, $_POST['youtube']);
$vid_text = mysqli_real_escape_string($con, $_POST['vid_text']);
// image file directory
$target = "uploads/".basename($image);
if($_POST['image'] = ""){
$sql = "UPDATE slide SET slide_text='".$slide_text."', image='".$image."', youtube='".$youtube."', vid_text='".$vid_text."'";
}
else{
$sql = "UPDATE slide SET slide_text='".$slide_text."', youtube='".$youtube."', vid_text='".$vid_text."'";
}
$result = mysqli_query($con, $sql);
if (move_uploaded_file($_FILES['image']['tmp_name'], $target)) {
$msg = "Image uploaded successfully";
}else{
$msg = "Failed to upload image";
}
if(!$result){
die('Error: ' . mysqli_error($con));
} else{
$message = ' - <i class="fa fa-check success"> Record Updated!</i>';
}
}
}
}
$sql = "SELECT * FROM slide";
$result = $con->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
?>
<!-- Header-->
<div class="breadcrumbs">
<div class="col-sm-4">
<div class="page-header float-left">
<div class="page-title">
<h1>Slide Show</h1>
</div>
</div>
</div> <div class="col-sm-8">
</div>
</div>
<div class="content mt-3">
<div class="animated fadeIn">
<div class="row">
<div class="col-lg-12">
<div class="card">
<div class="card-header"><strong>Image </strong><small>Slide</small></div>
<div class="card-body card-block">
<form role="form" method="post" action"" enctype="multipart/form-data">
<input type="hidden" name="new" value="1" />
<div class="modal-body">
<div class="row form-group">
<div class="col-6">
<div class="form-group"><label for="image" class=" form-control-label">Image</label>
<input type="file" id="image" name="image" value="<?php echo $row['image']; ?>" class="form-control">
</div>
</div>
<div class="col-6">
<div class="form-group"><label for="name" class=" form-control-label">Uploaded Image</label>
<img src="uploads/<?php echo $row['image']; ?>" width="150" height="150" class="img-fluid hover-shadow" />
</div>
</div>
</div>
<div class="row form-group">
<div class="col-6">
<div class="form-group"><label for="youtube" class=" form-control-label">Video</label>
<input type="text" id="youtube" name="youtube" value="<?php echo $row['youtube']; ?>" placeholder="Enter Video URL" class="form-control">
</div>
</div>
<div class="col-6">
<div class="form-group"><label for="vid_text" class=" form-control-label">Video Text</label>
<input type="text" id="vid_text" name="vid_text" value="<?php echo $row['vid_text']; ?>" placeholder="Video Text" class="form-control">
</div>
</div>
</div>
<div class="form-group"><label for="slide_text" class=" form-control-label">Text Overlay</label>
<textarea is="slide_text" name="slide_text" class="form-control"><?php echo $row['slide_text']; ?></textarea>
</div>
<div class="modal-footer">
<button type="submit" name="submit" id="submit" class="btn btn-primary">Confirm</button>
</div>
</form>
</div>
</div>
</div><!-- .animated -->
</div><!-- .content -->
<?php
}
}
?>
</div><!-- /#right-panel -->
<!-- Right Panel -->
<script src="assets/js/vendor/jquery-2.1.4.min.js"></script>
<script src="assets/js/popper.min.js"></script>
<script src="assets/js/plugins.js"></script>
<script src="assets/js/main.js"></script>
<script src="assets/js/lib/data-table/datatables.min.js"></script>
<script src="assets/js/lib/data-table/dataTables.bootstrap.min.js"></script>
<script src="assets/js/lib/data-table/dataTables.buttons.min.js"></script>
<script src="assets/js/lib/data-table/buttons.bootstrap.min.js"></script>
<script src="assets/js/lib/data-table/jszip.min.js"></script>
<script src="assets/js/lib/data-table/pdfmake.min.js"></script>
<script src="assets/js/lib/data-table/vfs_fonts.js"></script>
<script src="assets/js/lib/data-table/buttons.html5.min.js"></script>
<script src="assets/js/lib/data-table/buttons.print.min.js"></script>
<script src="assets/js/lib/data-table/buttons.colVis.min.js"></script>
<script src="assets/js/lib/data-table/datatables-init.js"></script>
<script src="https://cdn.tiny.cloud/1/sw6bkvhzd3ev4xl3u9yx3tzrux4nthssiwgsog74altv1o65/tinymce/5/tinymce.min.js" referrerpolicy="origin"></script>
<script>
tinymce.init({
selector: 'textarea',
plugins: 'advlist autolink lists link image charmap print preview hr anchor pagebreak',
toolbar_mode: 'floating',
});
</script>
<script type="text/javascript">
$(document).ready(function() {
$('#customer-table').DataTable();
} );
</script>
</body>
</html>
As you can see I am trying to use an If clause if the image field in the form is empty then I just want to update the other details. Else, if I fill the image field with a file, then update the lot.
if($_POST['image'] = ""){
$sql = "UPDATE slide SET slide_text='".$slide_text."', image='".$image."', youtube='".$youtube."', vid_text='".$vid_text."'";
}
else{
$sql = "UPDATE slide SET slide_text='".$slide_text."', youtube='".$youtube."', vid_text='".$vid_text."'";
}
This doesn't work. Any ideas, besides give up?
<?php
//COOKIE CHECKER
if (isset($_COOKIE["person"])){
if (filter_var($_COOKIE["person"], FILTER_VALIDATE_INT)){
$user_id = $_COOKIE["person"];
//DATABASE CONNECTION VARIABLES
$myserver ="localhost";
$myname = "username";
$mypassword = "password";
$mydb ="dbname";
/*SQL CONNECTION*/
// Create connection
$conn = new mysqli($myserver, $myname, $mypassword, $mydb);
// Check connection
if ($conn->connect_error) {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>
<H1>Decline of the Han - Three Kingdoms</H1>';
die("Connection failed: " . $conn->connect_error);
echo '</BODY>
</HTML>';
}
else {
//COUNT USER
$cquery = "SELECT COUNT(*) AS usercheck FROM Players WHERE ID = ?";
$cid = $conn->prepare($cquery);
$cid->bind_param('i', $user_id);
$cid->execute();
$cid->bind_result($usercheck);
$cid->fetch();
if ($usercheck ==1){
if (isset($_POST["profile"])){
if(!filter_var($_POST["profile"], FILTER_SANITIZE_STRING)){
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">Unable to filter bio <a href="biography.php">return</a></P>';
echo '</BODY>
</HTML>';
}
else {
$profile = $_POST["profile"];
$sql = "UPDATE Player_Data SET Bio =? WHERE ID=?";
$q = $conn->prepare($sql);
$q->bind_param("si", $profile, $user_id);
$q->execute();
echo '<P>Biography altered <a href="biography.php">return</a></P>';
//close connection
$conn->close();
}
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">'.$usercheck.' '.$user_id.'</P>';
echo '<P class="error">No such user found!</P>';
//close connection
$conn->close();
//foot
echo '</BODY>
</HTML>';
}
//end connection check
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">ERROR invalid cookie!</P>';
echo '</BODY>
</HTML>';
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">No cookie detected!<br><a href="login.php">login</a></P>';
echo '</BODY>
</HTML>';
}
?>
I have an error in the update, but I am not seeing where I made it. Its annoying because the update won't execute and anything beyond the update isn't visible in the html source code in the browser, so it is likely to be a syntax error, but where?
<?php
//COOKIE CHECKER
if (isset($_COOKIE["person"])){
if (filter_var($_COOKIE["person"], FILTER_VALIDATE_INT)){
$user_id = $_COOKIE["person"];
//DATABASE CONNECTION VARIABLES
$myserver ="localhost";
$myname = "username";
$mypassword = "password";
$mydb ="dbname";
/*SQL CONNECTION*/
// Create connection
$conn = new mysqli($myserver, $myname, $mypassword, $mydb);
// Check connection
if ($conn->connect_error) {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>
<H1>Decline of the Han - Three Kingdoms</H1>';
die("Connection failed: " . $conn->connect_error);
echo '</BODY>
</HTML>';
}
else {
//COUNT USER
$cquery = "SELECT COUNT(*) AS usercheck FROM Players WHERE ID = ?";
$cid = $conn->prepare($cquery);
$cid->bind_param('i', $user_id);
$cid->execute();
$cid->bind_result($usercheck);
$cid->fetch();
if ($usercheck ==1){
if (isset($_POST["profile"])){
if(!filter_var($_POST["profile"], FILTER_SANITIZE_STRING)){
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">Unable to filter bio <a href="biography.php">return</a></P>';
echo '</BODY>
</HTML>';
}
else {
$profile = $_POST["profile"];
$sql = "UPDATE Player_Data SET Bio =? WHERE ID=?";
$q = $conn->prepare($sql);
$q->bind_param("si", $profile, $user_id);
$q->execute();
echo '<P>Biography altered <a href="biography.php">return</a></P>';
//close connection
$conn->close();
}
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">'.$usercheck.' '.$user_id.'</P>';
echo '<P class="error">No such user found!</P>';
//close connection
$conn->close();
//foot
echo '</BODY>
</HTML>';
}
//end connection check
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">ERROR invalid cookie!</P>';
echo '</BODY>
</HTML>';
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">No cookie detected!<br><a href="login.php">login</a></P>';
echo '</BODY>
</HTML>';
}
?>
I have an error in the update, but I am not seeing where I made it. Its annoying because the update won't execute and anything beyond the update isn't visible in the html source code in the browser, so it is likely to be a syntax error, but where?
Hi i have this simple update form and scrip but somehow it doesnt seem to be update the field on the database can someone help out please. The html form is the second form bellow where the action send to status_update.php HTML FORM Code: [Select] <?php include("../header.html"); ?> <?php include("header_news.html"); extract($_REQUEST,EXTR_SKIP); ?><?php /* print("sfilm_refnum = $sfilm_refnum<BR>"); print("sfilm_addr01 = $sfilm_addr01<BR>"); print("sfilm_postcode = $sfilm_postcode<BR>"); print("Film Client = $fclient<BR>"); */ ?> <form id="search" action="list.php" method="post" name="search"> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#eeeeee"> <tr> <td align="right" width="140"></td> <td width="320"><span class="hofblack10"> </span> </td> <td align="center" width="100"><input type="hidden" name="lstart" value="<?php print("$lstart"); ?>" /><input type="hidden" name="lend" value="<?php print("$lend"); ?>" /><input type="hidden" name="lamount" value="<?php print("$lamount"); ?>" /></td> <td align="center" width="100"></td> <td align="right"></td> </tr> </table> </form> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#4050c4"> <tr> <td width="60" class="hofwhite10">action</td> <td width="140"><span class="hofwhite14">DATE</span></td> <td width="80"><span class="hofwhite14">ID</span></td> <td><span class="hofwhite14">News Titile</span></td> <td width="100"><span class="hofwhite14">Status</span></td> </tr> <tr height="0"> <td bgcolor="white" width="60"></td> <td bgcolor="white" width="140" height="0"></td> <td bgcolor="white" width="80" height="0"></td> <td bgcolor="white" height="0"></td> <td bgcolor="white" width="100" height="0"></td> </tr> </table><table width="780" border="0" cellspacing="0" cellpadding="4"><tr> <td width="60"></td> <td width="80"></td> <td><a class="blueullrg" href="add.php">Add News</a></td> <td align="right" width="120"></td> </tr> <tr height="0"> <td width="60" height="0"></td> <td width="80" height="0"></td> <td height="0"></td> <td align="right" width="120" height="0"></td> </tr> </table> <?php //get the DB connection variables include("../../../includes/config.php"); //connect to DB $connection = @mysql_connect($db_address,$db_username,$db_password) or die("Couldn't CONNECT."); $db = @mysql_select_db($db_name, $connection) or die("Couldn't select DATABASE."); $query2="SELECT * FROM news WHERE !(news_status='deleted')"; $result2 = mysql_query($query2) or die("Couldn't execute QUERY - Select NEWS Qty"); $fqty = mysql_num_rows($result2); //SELECT or FIND the same USERNAME $query3="SELECT * FROM news WHERE !(news_status='deleted') ORDER BY news_id DESC"; $result3 = mysql_query($query3) or die("Couldn't execute QUERY - Select NEWS"); while ($row = mysql_fetch_array($result3)) { $news_id = $row['news_id']; $news_title = $row['news_title']; $news_story = $row['news_story']; $news_image = $row['news_image']; $news_image_caption = $row['news_image_caption']; $news_image_link = $row['news_image_link']; $news_date_day = $row['news_date_day']; $news_date_month = $row['news_date_month']; $news_date_year = $row['news_date_year']; $news_status = $row['news_status']; $news_website = $row['news_website']; $news_date_created = $row['news_date_created']; $news_date_modified = $row['news_date_modified']; ?> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#eeeeee"> <tr> <td width="60"><span class="hofblack10"> <?php if($news_status=="deleted"){ print("<a class='hifblack10'>deleted</span>"); }ELSE{ print("<a class='blueul' href='edit.php?id=$news_id'>edit</a>"); } ?> </span></td> <td width="140"><span class="titlegrey12"> <?php if(!$news_date_day) { echo "00"; } else{ echo $news_date_day; } echo "/"; if(!$news_date_month) { echo "00"; }else{ echo $news_date_month; } echo "/"; if(!$news_date_year) { echo "0000"; }else{ echo $news_date_year; } ?> </span></td> <td width="80"><span class="titlegrey12"><?php print("$news_id"); ?></span> </td> <td><?php if($news_status=="deleted") { print("<class='hofblack10'>$news_title</span>"); }ELSE{ print("<a class='blueul' href='edit.php?id=$news_id'>$news_title</a>"); } ?></td> <td width="100"> <form id="list_update" action="status_update.php" method="post" name="list_update"> <select name="newnstatus" size="1"> <option <?php if($row['news_status'] == "") { print("selected"); } ?> selected="selected" value="">Status...</option> <option <?php if($row['news_status'] == "on") { print("selected"); } ?> value="on">On</option> <option <?php if($row['news_status'] == "off") { print("selected"); } ?> value="off">Off</option> <option <?php if($row['news_status'] == "deleted") { print("selected"); } ?> value="deleted">Delete</option> </select> <input type="hidden" name="nstatus" value="<?php echo $row[news_status]; ?>" /> <input type="hidden" name="id" value="<?php echo $row[news_id]; ?>" /> <input type="submit" name="update" value="update" /> </form> </td> </tr> <tr height="0"> <td bgcolor="white" width="60"></td> <td bgcolor="white" width="140" height="0"></td> <td bgcolor="white" width="80" height="0"></td> <td bgcolor="white" height="0"></td> <td bgcolor="white" width="100" height="0"></td> </tr> </table> <?php } mysql_close($connection);//}?> <table width="780" border="0" cellspacing="0" cellpadding="4"> <tr> <td width="60"></td> <td width="80"></td> <td><a class="blueullrg" href="add.php">Add News</a></td> <td align="right" width="120"></td> </tr> </table><?php // include("list_navigation.html"); ?> <?php include("../footer.html"); ?> </div></body></html> The action script php Code: [Select] <?php /* echo "fstatus: ".$fstatus."<BR>"; echo "id: ".$id."<BR>"; echo "fclient: ".$fclient."<BR>"; echo "newfstatus: ".$newfstatus."<BR>";*/ //set the date of agreement $timestamp = date('l jS \of F Y h:i:s A'); //get the DB connection variables include("../../../includes/config.php"); //connect to DB $connection = @mysql_connect($db_address,$db_username,$db_password) or die("Couldn't CONNECT."); $db = @mysql_select_db($db_name, $connection) or die("Couldn't select FILMS DATABASE."); // All appears well, so enter into database $query= "UPDATE news SET news_status = '$newnstatus' WHERE news_id='$id'"; $result = mysql_query($query) or die("could not execute query - Update FILMS Record to DB"); //setup an email to the Admin @ hof, w/o attachment $emailto="xx@xxx.co.uk"; $emailfrom="no-reply@xxxx.co.uk"; $emailsubject="xx Record Updated"; $emailmessage="Hello Registrar\n\n"; $emailmessage.="News ID: ".$id."\n"; $emailmessage.="Updated on: ".$timestamp."\n\n"; $emailmessage.="Status was: ".$nstatus."\n"; $emailmessage.="Status now: ".$newfnstatus."\n"; $emailmessage.="Thank you,\n\n"; $emailmessage.="Web Site ROBOT\n"; $emailmessage.="(Administrator)\n"; $emailmessage.="xxx.co.uk | xxx.biz\n"; $emailmessage.="----------------------------------------------\n"; $emailmessage.="e. http://www.xxx.co.uk/contact.php\n"; $emailmessage.="w. http://www.xxx.co.uk\n"; $emailheader="From: xxx.co.uk<$emailfrom>"; $emailheader .= 'Cc: xxx@xxx.co.uk'."\r\n"; $emailheader .= 'Bcc: xxx@xxxxx.co.uk'."\r\n"; $ok=mail($emailto,$emailsubject,$emailmessage,$emailheader); mysql_close($connection); if ($ok) { header("Location: list.php"); /* Redirect browser */ exit; } else { $errmsg="There was a problem, please try later or telephone us direct."; $errsta="1"; include("edit_error.html"); //echo "<p>Mail could not be sent. Sorry!</p>"; exit; } ?> Thanks in advance Can anyone post a generic update function to update mysql table. The manual approach: update $tablename set $column1='a', $column2='b' where $id=$value; what Im basically trying to do is just like a phpmyadmin function... you select rows you want to update with a checkbox and then it takes you to a page where the rows that are clicked are shown in forms so that you can view and edit info in them... and then have 1 submit button to update them all at once. I created this code to upload a member's main picture on his member page on website. I'll only include the query part of the code since that's what is relevant to my problem. The idea is basically to upload a new picture onto the database if no picture already exists for that member and display the picture on the page. If a picture already exists, then the script replaces the old picture with the new one upon upload. But for whatever reason I don't understand, when I try to replace the old pic, it gets inserted in a new row on the database instead of replacing the old row, and the new pic gets displayed on the web page alongside the old. Code: [Select] $query = "SELECT username FROM images WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'"; $result = @mysql_query($query); $num = @mysql_num_rows($result); if ($num> 0) { //Update the image $update = mysql_query("UPDATE images SET image = '" . $image['name'] . "' WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'"); $_SESSION['error'] = "File updated successfully."; //really should be session success message. header("Location: member.php"); exit; } else { // NOTE: This is where a lot of people make mistakes. // We are *not* putting the image into the database; we are putting a reference to the file's location on the server $sql = "insert into images (member_id, image_cartegory, image_date, image) values ('{$_SESSION['id']}', 'main', NOW(), '" . $image['name'] . "')"; $result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error()); $_SESSION['error'] = "File uploaded succussfully."; //really should be session success message. header("Location: member.php"); } So can anyone tell me what the problem is? Could the fact that my insert script actually uploads the image onto a folder on my server and only stores the path name in the database have anything to contribute to the mixup? Appreciate your responses in advance. As the title says I need help with multiple update system.. Can't really get it to work at all >.< Here's some code: $selectt = mysql_query("SELECT * FROM exercises WHERE user='" . $_SESSION["user"] . "' AND exname='" . $_GET["edit"] . "'"); echo '<form method="POST" action="exercises.php?edited">'; echo '<div id="newexx">'; while($raw = mysql_fetch_array($selectt)) { echo '<input type="text" name="up[' . $raw["id"] . ']" value="' . $raw["swe"] . '">'; echo '<input type="text" name="up1[' . $raw["id"] . ']" value="' . $raw["eng"] . '"><br>'; echo '<input type="hidden" name="id[' . $raw["id"] . ']">'; } echo '</div>'; echo '<input type="submit" value="Update Exercise">'; echo '</form>'; if(isset($_GET["edited"])) { $swe = $_POST["up"]; $eng = $_POST["up1"]; $id = $_POST["id"]; foreach($id as $value => $index) { $update = "UPDATE exercises SET swe='".$swe."', eng='".$eng."' WHERE id='".$index."'"; mysql_query($update); } Would be thankful for reply! Good morning. I am looking fo some help with an update script to update all rows in a table. This is what I have for a form and all looks well. form.php <?php // run the query and put the results in an array variable called $result $result = mysql_query("SELECT * FROM table ORDER BY 'id', 'title', 'text', 'number'"); print "<form method='post' action='update.php'> <table width='100%' border='0' cellspacing='1' cellpadding='1'><tr> <td align='center'><strong>ID</strong></td> <td align='center'><strong>Title</strong></td> <td align='center'><strong>text</strong></td> <td align='center'><strong>Number</strong></td> </tr>\n"; // start a loop to print all of the courses with their book information // the mysql_fetch_array function puts each record into an array. each time it is called, it moves the array counter up until there are no more records left while ($Update = mysql_fetch_array($result)) { // start displaying the info; the most important part is to make the name an array (notice bookinfo[$i]) print "<td align='center'><p>{$Update['id']}</p></td>\n"; print "<td align='center'><input type='text' name='title' value='{$Update['title']}' /></td>"; print "<td align='center'><input type='text' size='40' name='text' value='{$Update['text']}' /></td>\n"; print "<td align='center'><input type='text' size='40' name='number' value='{$Update['number']}' /></td>\n"; print "</tr>\n"; // add 1 to the count, close the loop, close the form, and the mysql connection } print "<tr> <td colspan='4' align='center'><input type='submit' value='submit' />"; print "</td> </tr> </table> </td> </tr> </form> </table>"; print "</tr>\n"; ?><br /><br /> My question is. How do I update this info into the database with the proper info. ie. Update.php? I'm new to PHP and I was able to figure out how to populate data from my database into my text fields. I am trying to add the update information to the same php file; however, I am now receiving errors within the data I was able to populate,
Notice: Undefined variable: stmt in C:\xampp\htdocs\Cust_App\update.php on line 47 and errors with the Update statement
Notice: Undefined variable: stmtupdate in C:\xampp\htdocs\Cust_App\update.php on line 96 I had defined the customerID variable above in the code, but it isn't being captured from here. I tried setting up this query like the one which gathered the data, but I'm off by a little bit. I would like the option to be able to update all fields. Any help is appreciated. I'm trying to learn as I may get asked to update other forms in the future. (new boss asks a lot)
<?php
require_once('database.php');
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<!-- the head section -->
<head>
<title>My Guitar Shop</title>
<link rel="stylesheet" type="text/css" href="main.css" />
</head>
<!-- the body section -->
<body>
<div id="page">
<div id="header">
<h1>SportsPro Technical Support</h1>
<p>Sports management software for the sports enthusiast.</p></h1>
</div>
<div id="main">
<h1>View/Update Customer</h1>
<form action="update.php" method="get" >
<?php
if(isset($_GET['customerID'])) {
$customerID = filter_input(INPUT_GET, 'customerID', FILTER_SANITIZE_NUMBER_INT);
$sql = "SELECT * FROM customers WHERE customerID =$customerID ";
$stmt = $db->query($sql);
}
?>
<div id="content">
<!-- display a table of products -->
<h2>Customers</h2>
<form method = "edit">
<?php foreach ($stmt as $cust) { ?>
<div>
<label>First Name</label>
<input type="text" name="name" class ="form-control" value ="<?php echo $cust['firstName']; ?>">
</div><br>
<div>
<label>Last Name</label>
<input type="text" name="name" class ="form-control" value ="<?php echo $cust['lastName']; ?>">
</div><br>
<div>
<label>Address</label>
<input type="text" name="address" class ="form-control" value ="<?php echo $cust['address']; ?>">
</div><br>
<div>
<label>City</label>
<input type="text" name="city" class ="form-control" value ="<?php echo $cust['city']; ?>">
</div><br>
<div>
<label>State</label>
<input type="text" name="state" class ="form-control" value ="<?php echo $cust['state']; ?>">
</div><br>
<div>
<label>Country</label>
<input type="text" name="countryCode" class ="form-control" value ="<?php echo $cust['countryCode']; ?>">
</div><br>
<div>
<label>Zip Code</label>
<input type="text" name="postalCode" class ="form-control" value ="<?php echo $cust['postalCode']; ?>">
</div><br>
<div>
<label>Email </label>
<input type="text" name="email" class ="form-control" value ="<?php echo $cust['email']; ?>">
</div><br>
<div>
<label>Phone Number </label>
<input type="text" name="phone" class ="form-control" value ="<?php echo $cust['phone']; ?>">
</div><br>
<div>
<label>Password </label>
<input type="text" name="password" class ="form-control" value ="<?php echo $cust['password']; ?>">
</div><br>
<div>
<?php }
?>
<input type="Submit" name="Update_Data" value="Update Data"></input>
<?php
$sql2 = "UPDATE customers SET firstName = ". $stmtupdate['firstName']." WHERE customerID =$customerID ";
$stmtupdate = $db->query($sql2);
?>
</div>
</div>
<div id="footer">
<p>
© <?php echo date("Y"); ?> SportsPro, Inc.
</p>
</div>
</div><!-- end page -->
</body>
</html>
Hi Guys, I want my UPDATE function from the code below to only update those fields that are NOT empty - if they are empty on submit then do not update or change any values from that field. I know that sounds odd, but with my file fields, when I submit to change something else at a later date it will overwrite the photo, download1,2 & 3 values and as a result I loose my files from the mysql table. Cheers, S <?php include('config.php'); if (isset($_GET['Ter']) ) { $ter = (int) $_GET['Ter']; if (isset($_POST['submitted'])) { //Photo & Document Upload Upload $timestamp_photo = time(); $timestamp_download1 = time(); $timestamp_download2 = time(); $timestamp_download3 = time(); //This is the directory where the files will be saved //Photos $photo_target = "images/"; $photo_target = $photo_target .$timestamp_photo. basename( $_FILES['photo']['name']); //Documents $download_target = "documents/"; $download_target1 = $download_target .$timestamp_download1. basename( $_FILES['download1']['name']); $download_target2 = $download_target .$timestamp_download2. basename( $_FILES['download2']['name']); $download_target3 = $download_target .$timestamp_download3. basename( $_FILES['download3']['name']); //This gets all the other information from the form $photo = ($_FILES['photo']['name']); $download1 = ($_FILES['download1']['name']); $download2 = ($_FILES['download2']['name']); $download3 = ($_FILES['download3']['name']); //Pause Photo/Document Upload foreach($_POST AS $key => $value) { $_POST[$key] = mysql_real_escape_string($value); } $sql= "UPDATE `ter` SET `Ter` = '{$_POST['Ter']}' , `BranchName` = '{$_POST['BranchName']}' , `BranchAddress` = '{$_POST['BranchAddress']}' , `BranchTel` = '{$_POST['BranchTel']}' , `BranchEmail` = '{$_POST['BranchEmail']}' , `BranchLink` = '{$_POST['BranchLink']}' , `Theme` = '{$_POST['Theme']}' , `LocalInfo` = '{$_POST['LocalInfo']}' , `BranchInfo` = '{$_POST['BranchInfo']}' , `photo` = '$timestamp_photo{$_FILES['photo']['name']}' , `download1` = '$timestamp_download1{$_FILES['download1']['name']}' , `download1name` = '{$_POST['download1name']}' , `download2` = '$timestamp_download2{$_FILES['download2']['name']}' , `download2name` = '{$_POST['download2name']}' , `download3` = '$timestamp_download3{$_FILES['download3']['name']}' , `download3name` = '{$_POST['download3name']}' WHERE `Ter` = '$ter' "; mysql_query($sql) or die(mysql_error()); //Unpause Photo/Document Upload //Writes the photo to the server if(move_uploaded_file($_FILES['photo']['tmp_name'], $photo_target)) { echo "<br />The file ".$timestamp_photo. basename( $_FILES['photo']['name']). " has been uploaded. <br />"; } else { echo ""; } //End of Photo/Document Upload //Writes the photo to the server if(move_uploaded_file($_FILES['download1']['tmp_name'], $download_target1)) { echo "<br />The file ".$timestamp_download1. basename( $_FILES['download1']['name']). " has been uploaded. <br />"; } else { echo ""; } //End of Photo/Document Upload //Writes the photo to the server if(move_uploaded_file($_FILES['download2']['tmp_name'], $download_target2)) { echo "<br />The file ".$timestamp_download2. basename( $_FILES['download2']['name']). " has been uploaded. <br />"; } else { echo ""; } //End of Photo/Document Upload //Writes the photo to the server if(move_uploaded_file($_FILES['download3']['tmp_name'], $download_target3)) { echo "<br />The file ".$timestamp_download3. basename( $_FILES['download3']['name']). " has been uploaded. <br />"; } else { echo ""; } //End of Photo/Document Upload echo (mysql_affected_rows()) ? "<br />Edited Branch.<br />" : "<br />Nothing changed. <br />"; } $row = mysql_fetch_array ( mysql_query("SELECT * FROM `ter` WHERE `Ter` = '$ter' ")); ?> Hi, The following code is what I want in that it creates a menu and I can select and display a table row.
I still need to use that selection to update the "lastused". I really appreciate your help. <!DOCTYPE><html><head><title>email menu</title></head> <body><center> <form name="form" method="post" action=""> <?php $con=mysqli_connect("localhost","root","cookie","homedb"); //============== check connection if(mysqli_errno($con)) {echo "Can't Connect to mySQL:".mysqli_connect_error();} else {echo "Connected to mySQL</br>";} //This creates the drop down box echo "<select name= 'target'>"; echo '<option value="">'.'--- Select email account ---'.'</option>'; $query = mysqli_query($con,"SELECT target FROM emailtbl"); $query_display = mysqli_query($con,"SELECT * FROM emailtbl"); while($row=mysqli_fetch_array($query)) {echo "<option value='". $row['target']."'>".$row['target'] .'</option>';} echo '</select>'; ?> <input type="submit" name="submit" value="Submit"/><!-- update "lastused" using selected "target"--> </form></body></html> <!DOCTYPE><html><head><title>email menu</title></head> <body><center> <?php $con=mysqli_connect("localhost","root","cookie","homedb"); if(mysqli_errno($con)) {echo "Can't Connect to mySQL:".mysqli_connect_error();} if(isset($_POST['target'])) { $name = $_POST['target']; $fetch="SELECT target,username,password,emailused,lastused, purpose, saved FROM emailtbl WHERE target = '".$name."'"; $result = mysqli_query($con,$fetch); if(!$result) {echo "Error:".(mysqli_error($con));} $lastused = "CURDATE()"; // update "lastused" using selected "target" //display the table echo '<table border="1">'.'<tr>'.'<td bgcolor="#ccffff align="center">'. 'Email menu'. '</td>'.'</tr>'; echo '<tr>'.'<td>'.'<table border="1">'.'<tr>'.'<td bgcolor="#ccffff align="center">'.'target'.'</td>'.'<td bgcolor="#ccffff align="center">'.'username'.'</td>'.'<td bgcolor="#ccffff align="center">'.'password'.'</td>'.'<td bgcolor="#ccffff align="center">'.'emailused'.'</td>'.'<td bgcolor="#ccffff align="center">'.'lastused'.'</td>'.'<td bgcolor="#ccffff align="center">'.'purpose'. '</td>'.'<td bgcolor="#ccffff align="center">'. 'saved' .'</td>'.'</tr>'; while($data=mysqli_fetch_row($result)) {echo ("<tr><td>$data[0]</td><td>$data[1]</td><td>$data[2]</td><td>$data[3]</td><td>$data[4]</td><td>$data[5]</td><td>$data[6]</td></tr>");} echo '</table>'.'</td>'.'</tr>'.'</table>'; } ?> </body></html> Hello everyone, For two weeks now, I'm trying to get this database connection in my query. Can someone give me a solution and tell me what I've done wrong? Am I overlooking something? <?php class Mysql{ public function connect(){ $mysqli = new mysqli('localhost','root','','login'); } } class Query extends Mysql{ public function runQuery(){ $this->result = parent::connect()->query("select bla bla from bla bla"); } } $query = new Query; $query->runQuery(); ?> I have just started using MySQLi and am clueless it is giving me the follow errors in which i do not understand
Warning: mysqli_select_db() expects exactly 2 parameters, 1 given in C:\xampp\htdocs\Login\connect.php on line 23 Notice: Trying to get property of non-object in C:\xampp\htdocs\Login\connect.php on line 25 Notice: Use of undefined constant mysqli - assumed 'mysqli' in C:\xampp\htdocs\Login\connect.php on line 32 Warning: mysqli_query() expects parameter 1 to be mysqli, string given in C:\xampp\htdocs\Login\connect.php on line 32 Warning: mysql_fetch_assoc() expects parameter 1 to be resource, null given in C:\xampp\htdocs\Login\connect.php on line 33 can someone please explain to me why i am getting these? and my code is
$mysqli_db = mysqli_select_db("$db_name");
if($mysqli_db->connect_errno) {
printf("Database not found: %s\n", $mysql->connect_error);
exit();
}
$sql = "SELECT * FROM $tbl_name WHERE username='$username' AND password='$password'";
$result = mysqli_query($sql);
$row = mysqli_fetch_assoc($result);
I just got rid off most the errors the only ones left are
Warning: mysqli_query() expects at least 2 parameters, 1 given in C:\xampp\htdocs\Login\connect.php on line 32Fatal error: Call to undefined function mysqli_result() in C:\xampp\htdocs\Login\connect.php on line 33 Code Updated:
$mysqli_db = mysqli_select_db($mysqli_connect, $db_name);
if(!$mysqli_db) {
printf("Database not found: %s\n", $mysqli->connect_error);
exit();
}
$sql = "SELECT * FROM $tbl_name WHERE username='$username' AND password='$password'";
$query = mysqli_query($sql);
$result = mysqli_result($query);
$row = mysqli_fetch_assoc($result);
Edited by Tom8001, 30 November 2014 - 12:43 PM. I dont know whether the statement is correct.....i just tried it.....and it didn't work. $stmt->bind_param('ssiiiss',$_POST['name'],$_POST['email'],$_POST['d'],$_POST['m'],$_POST['y'],$_POST['add'],$_POST['phone']); here my first two values are strings and next 2 tiny int's next is int and last 2 again strings. Ok I am trying to use mysqli instead of the usual mysql. Mysql would be outdated. With mysqli, sgl-injection is impossible if you use the "?" in those codes. I would normally use a function but I've made a simple script to find the error. I use $parameters and $sql because these are the data I need to give as parameters to the function, so I used it here too but without the function actually. Code: [Select] ini_set('display_errors',1); // 1 == aan , 0 == uit error_reporting(E_ALL | E_STRICT); # sql debug define('DEBUG_MODE',true); // true == aan, false == uit $userid = 11; $lang = 1; $newLink = "testing123"; $db_host = "localhost"; $db_gebruiker = "root"; $db_wachtwoord = ''; $db_naam = "projecteasywebsite"; $sql= "INSERT tbl_link(userid,linkcat,linksubid,linklang,linkactive,linktitle) VALUES(?, ?, ?, ?, ?, ?)"; $parameters = '"iiisis", $userid, 1, 0, $lang, 1, $newLink'; echo $parameters; $mysqli = new mysqli($db_host, $db_gebruiker, $db_wachtwoord, $db_naam); $stmt = $mysqli->prepare($sql); $stmt->bind_param($parameters); $stmt->execute(); echo "<br><br>". mysqli_connect_errno(); echo "<br><br>". mysqli_report(MYSQLI_REPORT_ERROR); $stmt->close(); $mysqli->close(); I got Wrong parameter count for mysqli_stmt::bind_param() So naturally a problem when we execute : Warning: mysqli_stmt::execute() [mysqli-stmt.execute]: (HY000/2031): No data supplied for parameters in prepared statement ($stmt->execute() Is someone using mysqli too ? hello , I'm starting to use mysqli and i have few questions. is there a guide for mysqli? and how do i use this functions at mysqli ? mysql_num_rows mysql_query mysql_fetch_assoc mysql_fetch_array thanks , Mor. |
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