PHP - Easy Question (i Hope): Php Include File With Links

While going through an instructional book, I ran across some code that I didn't immediately understand.  I've stripped it down to the relevant bits:


function example($object_a, $object_b) {

  $compare = $object_a->id == $object_b->id;

  return another_function('argument 1') && $compare || another_function('argument 2');

}



My first confusion was this line:
$compare = $object_a->id == $object_b->id;
Does this set $compare to TRUE if the ids match and FALSE if they do not?

And the second confusion:
return another_function('argument 1') && $compare || another_function('argument 2');
What is returned if the ids match?  What is returned if they are different? 

When I try testing this out on my machine, it returns both functions whether or not the ids match, but I know that's not what's supposed to happen.  Can anyone break this down for me?

Thanks.

hello. i want to know what is *$ or +$ because i see it in many contact forms. also, what is the difference between these:
/^[A-Z]+[a-z]*$/
/^[A-Z]+[a-z]+$/
/^[A-Z]+[a-z]$/
/^[A-Z]+[a-z]/

also, which is the shortest and efficient method of checking somebodys name to be exactly "Name Surname" - "Green Trancer" ? in my form, i use
var filter = /^[A-Z]+[a-z]*$/;
var filter2 = /^[A-Z]+[a-z]+\s+[A-Z]+[a-z]+$/;
and then i check the name to be like filter or filter2.

how can i check that between the words to be exactly one space character ?

thank you very much.

So I am extending the DateTime class and would like to completely disable the modify() function that is built in so i have this:
Code: [Select]
<?php
class NewDateTime extends DateTime
{

public function modify()
{
throw new Exception('modify() has been disabled.');
}
}

thats not the entire class description, just the pertinent part of course

now any time I create a new object from NewDateTime I get this message at the top of the screen:

Quote

Strict Standards: Declaration of NewDateTime::modify() should be compatible with that of DateTime::modify() in C:\xampp\htdocs\.....my file path here.....\NewDateTime.php on line 62


what gives? how do I get rid of this and still disable modify()? I'm betting its a setting that i have wonky but I am really rusty in php so dont know where to look in php.ini

Hey people!

I've been setting a coding script for experience and this is my situation:

To buy a virtual flower, one needs to have 50 virtual coins.
So I first extract the number of coins the person has from the DB.
If the user doesn't have the sufficient number of coins, the BUY button will not be available and vice versa.

When the BUY button is clicked, I update the database, adding the flower to the user's inventory and subtracting 50 from the total number of coins the user has. This I do in that page itself using
if(isset($_POST['submit'])) 

Now, I need to know how I could check whether the user has at least 50 coins even if the button is available.
I hope that you could understand this.
I want to do it for validation purposes. Its to prevent the user spending the coins he has in another browser window and then returning to the visible button to click it.

I hope that I make sense. Thanks in advance!

Regards,
Thauwa

Hello Everybody   I usually work with C#, but I'm doing a website right now and have a question: I want a picture in my header and when I change the window size the image may not move.   My code so far:

#a1 { 
position: relative;
top:-175px; left:0px; width:50px; height:50px;
background-image:url(http://domain.png);
      background-repeat:no-repeat;}
</style>

Hope someone can answer this question easy

I'm trying to search the 'ad' column where 'ad' = 1 or 3

I'm having problems doing this.

Here is what I currently have, but it is not bringing back 'ad' where ='1' (for obvious reasons)
Quote

    $query = "SELECT * FROM users WHERE ad='3' AND state='$state1'";



Here is what I thought would work, but it displays every listing in my database when I do it this way.

Quote

    $query = "SELECT * FROM users WHERE ad='3' OR ad='1' AND state='$state1'";




Thank you in advance for your answers, google is not being so kind to me right now.

I have a php file that generates a string that I need to use in a .js (javascript)file. Being that php developers sometimes using javascript with php, Im hoping someone can help me with this, cause i dont know any javascript.
Code: [Select]
//This is the varible inside the .js file
var suggestionText = "I need to be able to include my string generated by the php file here...";

Wow, am I glad I found this forum!  I spent the past few hours trying to modify a PHP/mySQL script in order to test it. What this script does is basically look up a mySQL database (based on ip2nation) to find out what country and currency the IP address belongs to. This is the code sample:

Code: [Select]
$sql = 'SELECT  c.country, c.curr_code FROM  ip2nationcountries c, ip2nation i WHERE  i.ip < INET_ATON("24.24.24.24") AND c.code = i.country ORDER BY  i.ip DESC LIMIT 0,1';

        $countryName = $db->get_sql_row($sql);

I tested the code in PHPmyAdmin and it returns 2 rows:

country ------- curr_code (row names)
United States ------- USD (actual values)

So basically 2 variables, United States and USD. Now comes the problem, in order to test the script for several countries, I need to be able to "override" the result in the PHP script

I tried to do that by commenting out the part that returns the result from the mySQL query and modifying it with the following style, but I think I'm doing something wrong:

Code: [Select]
### $countryName = $db->get_sql_row($sql); ###

$countryName = "United States USD";

Is there any way that I can temporarily override the result returned by mySQL and "fake it" so to say? I understand the mySQL query returns 2 rows, so how would I go about overriding 2 rows?

I hope this makes sense ...you're all my last hope.

 

Just a quick question about including php files on a page...

Let's say I have my index page that is a fully functioning page with all the <html>, <body>, and <head> tags where they should be.  Now I want to include another file, which also has <html>, <body>, and <head> tags.  Would this cause any problems or is it ok to include the second file as is?

Alright, so I just started picking up PHP again and I have a pretty simple question. I have a html form that takes a string then writes it on another page. My problem is when I use quotations I'll get slashes in them on the page it writes the string on.

Is there a way to clean that stuff up?

I want to include a php file after an succesfully login.
Let's suposed that I have a login form on index.php. If the login was ok I want to include a php file with some content instead of the login form.
Something like:
Code: [Select]
<?
if($_POST['ok']){
     require('content.php');
} else {
//login form
}
?>

It's ok to include in the code the name of the file that you have on server ? From security point of view.

Thanks

Can I include a class file in the same page that I use an instance of the same class with my action attribute with my form.


Here's the code

Code: [Select]
<?php include 'Resources/User.php';?>
<html>
    <head>
        <title></title>
        <link href="stylesheets/styles.css" rel="stylesheet" type="text/css"/>
    </head>


    <body>
       
        <form action = "Resources/testClass.php" method="post" enctype="multipart/form-data">
            <label>First Name: </label>
            <input type="text" name="fname" id="fname" size="25" maxlength="25"/>
            <label>Last Name: </label>
            <input type="text" name="lname" id="lname" size="25" maxlength="25"/>
            <label>Email: </label>
            <input type="text" name="email" id="email" size="25" maxlength="40"/>
            <label>Username: </label>
            <input type="text" name="username" id="username" size="25" maxlength="32"/>
            <label>Password: </label>
            <input type="password" name="password" id="password" size="25" maxlength="32"/>
            <label>Re-enter Password: </label>
            <input type="password" name="conf_pass" id="conf_pass" size="25" maxlength="32"/>
            <br /><br />
            <input type="submit" name="submit" id="submit" value="Register"/>
            <input type="reset" name="reset" id="reset" value="Reset"/>
        </form>

    </body>
</html>

www.desmond-otoole.co.uk/secure/securefunctions.php

/bank/admin/index.php

what should I do in the index.php file to access securefunctions.php

require("../secure/SecureFunctions.php");
require("../../secure/SecureFunctions.php");
require("www.desmond-otoole.co.uk/secure/SecureFunctions.php");

Nothing seems to work

I just get a stupid google chrome page saying
This page isn’t working

Hello, Im trying to pass a variable to a newly created page using GET.
Code: [Select]
$query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Restaurant' ORDER BY name");
echo mysql_error();
while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0];
$i = -1;
foreach($nt as $value)
{$i++;
echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title'>"  . $nt[$i] . "</a>" . "<br/>";
$FileName = str_replace(' ','_',$nt[$i]) . ".php";
$FileHandle = fopen($FileName, 'w') or die("cant open file");
$pageContents = file_get_contents("header.php");
fwrite($FileHandle,"$pageContents");}
fclose($FileHandle);
header.php

Code: [Select]
<head>
<?php $title = $_GET['Title']; ?>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<p>HEADER UPDATED!</p>
<p>TESTING - the heading below should read (title goes here in capital letters)</p>
<?php <h1>$title</h1> ?> //This is line 12
</body>
</html>

Im getting the error; 
Parse error: syntax error, unexpected '<' in D:\Hosting\3753557\html\1pw\mexican.php on line 12
I suspect that I have my syntax muddled in header.php?

Is there a better way to pass variables to a newly created page? (fopen).

Many thanks for any ideas.

Hello person who reads this now

I work a lot with <?php include("..."); ?> and I never thought beyond the html I put in there.

In 1 of the include files I have the set-up of a simple vertical html/css menu and on the right next to it
I have an image. However, not every page on my website needs the same image and I probably will change
a lot of them frequently.

Now I was wondering if (and how) I could include a piece of PHP code which does the following:

If the web-url is "page1.php" show "image1.png"
If the web-url is "page2.php" show "image2.png"
If the web-url is "page3.php" show "image3.png"
etc.

This way I only have to change the "imageX.png" in 1 file.

I hope you can help me.

Best regards and thanks in advance!
Ferdri3