PHP - How To Create A Set Of Data From String To Insert In Mysql
Hi to everybody I need ur help because I’m trying to make a script in php to write the same data but with different date in MySQL depending on the splitting ($data06).... like a schedule...
For example if $data06 = annual and $data03 = “2019/01/01” programm must create in MySQL : 2019/01/01 2020/01/01 2021/01/01 2022/01/01 2023/01/01
if $data06=“half year” will create 10 date , increasing 6 moths ...
But I have a problem at finish of code switch ($data06) { case 'annual': $numrate = 5; $aumdata = "+12 months"; break; case 'half year': $numrate = 10; $aumdata = "+6 month"; break;
default: echo "error"; $sql = "INSERT into $nometb ( name, scadenza ) values ( '$data01', '$data03' )"; if ($conna->query($sql) === TRUE) {} else {die('ERROR'. $conna->error); }
//IMPORT NEXT AND NEW DATE $newDate = date_create($data03); for ($mul = 2; $mul <= $numrate; ++$mul) {
$datanuova = date_create($data03); $datanuova->modify($aumdata); $datanuova->format('yy/m/d'); $newDate = $datanuova->format('yy/m/d');
$sql = "INSERT into $nometb ( name, scadenza ) values ( '$data01', '$newDate' )"; if ($conna->query($sql) === TRUE) {} else {die('ERROR'. $conna->error); }
//HERE THERE IS ERROR $data03 = $newDate;
if ($conna->query($sql) === TRUE) {} else {die('ERRORE NELL\'IMPORTAZIONE'. $conna->error); } }
} }
}
How I can resolve ?
many thanks Francesco Similar TutorialsI have a variable and it contains a lot of strong data would I want to convert the string data into an array. What's the best way of doing because I know older versions of php will be slightly different?
Hey yall! I'm working on a new site idea and I've run across a problem that I know is simple enough but I'm stumped. It's in the signup form What I want to do is insert the new user into the 'Login' table and get the user id that was just created and use that to create a table with the user id in the name. Here is what I have: // now we insert user into 'Login' table mysql_real_escape_string($insert = "INSERT INTO `Login` (`UID`, `pass`, `HR`, `mail`, `FullName`) VALUES ('{$_POST['username']}', '{$_POST['pass']}', '{$_POST['pass2']}', '{$_POST['e-mail']}', '{$_POST['FullName']}')"); mysql_query($insert) or die( 'Query string: ' . $insert . '<br />Produced an error: ' . mysql_error() . '<br />' ); $error="Thank you, you have been registered."; setcookie('Errors', $error, time()+20); // Get user ID mysql_real_escape_string($checkID = "SELECT * FROM Login WHERE `mail` = '{$_POST['e-mail']}'"); while ($checkIDdata = mysql_fetch_assoc($checkID)) { $userID = $checkIDdata; // now we create table 'Transactions" for the user mysql_real_escape_string($create = "CREATE TABLE `financewatsonn`.`Transactions_{$userID}` ( `ID` INT( 20 ) NOT NULL AUTO_INCREMENT COMMENT 'Transaction ID', `name` VARCHAR( 50 ) NOT NULL COMMENT 'Name/Location', `amount` VARCHAR( 50 ) NOT NULL COMMENT 'Amount', `date` VARCHAR( 50 ) NOT NULL COMMENT 'Date', `category` VARCHAR( 50 ) DEFAULT NULL COMMENT 'Category', `delete` INT( 1 ) NOT NULL DEFAULT '0', UNIQUE KEY `ID` ( `ID` ) ) ENGINE = MYISAM DEFAULT CHARSET = utf8 COMMENT = 'User ID {$userID}'"); mysql_query($create) or die( 'Query string: ' . $create . '<br />Produced an error: ' . mysql_error() . '<br />' ); } I know in 'Get user ID' that I need to get the ID but I'm not sure how to get that information. i get the error Quote Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource at 166 which is the while line under Get user ID I am trying to add a value, input into a form, to a MySQL database. However, something must be wrong with the casting, because if there is a space in the form value, then I get an error, as in: //$_POST['string'] == '1blah 2blah'; sql = "INSERT INTO table (some_string) VALUES ($_POST[string])"; $sql_result = mysql_query($sql) or die ('The error is as follows: ' . mysql_error() . '<br /><br />Value could not be added.'); Then I get the following error: The error is as follows: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '2blah' at line 1 I've entered paragraphs into a database before, so this error is now to me. The column 'some_value' is a type: varchar(50). Hi guys, I have a very simple add.php to add data to a mySQL db. I have a menu/list drop down as one of my fields on my form and this shows an array of results from another table (ranks of the RAF) within my db. When I click the save button I have it process a INSERT INTO command but all i get inputted into my staff table is the first word... eg if I chose "Pilot Officer" from the list menu and then click save all that would appear in my db is "Pilot". Any clues? I will paste the php below... Code: [Select] <?php include('config.php'); ?> <form action='' method='POST' enctype='multipart/form-data'> <p><b>Rank:</b><br /> <select name="rank" id="rank"> <option selected>Please Select</option> <?php $query = "SELECT * FROM ranks ORDER BY rank ASC"; $result = mysql_query($query); while($row = mysql_fetch_array($result)) { echo "<option value=". $row["rank"] .">". $row["rank"] ."</option>"; } ?> </select> <p><b>Forename:</b><br /> <input name="forename" type="text" id="forename" value="" size="40"> <p><b>Surname:</b><br /><input name='surname' type='text' id="surname" value='' size="40" /> <p><b>Category:</b><br /> <select name="category" id="category"> <option selected>Please Select</option> <?php $query = "SELECT * FROM categories"; $result = mysql_query($query); while($row = mysql_fetch_array($result)) { echo "<option value=". $row["category"] .">". $row["category"] ."</option>"; } ?> </select> <p><b>Email:</b><br /><input name='email' type='text' id="email" value='' size="50" /> <p><b>Mobile:</b><br /> <input name='mobile' type='text' id="mobile" value='' size="40" /> </p> <input type='submit' value='Save' /> <input type='hidden' value='1' name='submitted' /> </form> <?php if (isset($_POST['submitted'])) { $rank = mysql_real_escape_string($_POST['rank']); $forename = mysql_real_escape_string($_POST['forename']); $surname = mysql_real_escape_string($_POST['surname']); $category = mysql_real_escape_string($_POST['category']); $email = mysql_real_escape_string($_POST['email']); $mobile = mysql_real_escape_string($_POST['mobile']); $sql = "INSERT INTO `staff` (`rank` , `forename` , `surname` , `category` , `email` , `mobile` ) VALUES ( '$rank' , '$forename' , '$surname' , '$category' , '$email' , '$mobile')"; mysql_query($sql) or die(mysql_error()); echo (mysql_affected_rows()) ? "Staff Added":"Nothing Added"; } ?>
Array ( [data] => Array ( [0] => Array ( [latitude] => 22.934566 [longitude] => 79.08728 [type] => county [distance] => 44.328 [name] => Narsinghpur [number] => [postal_code] => [street] => [confidence] => 0.5 [region] => Madhya Pradesh [region_code] => MP [county] => Narsinghpur [locality] => [administrative_area] => [neighbourhood] => [country] => India [country_code] => IND [continent] => Asia [label] => Narsinghpur, India ) ) ) Hi guys, I have an array: array ( [apple]=> red, [orange] => orange, [banana] => yellow ) That I want to insert into the apidata table, the PDO connection is good so I guess my code is wrong: $mykeys = implode(', ', array_keys($newarr)); $myplaceholders[] = '(' . implode (", ", array_fill(0, count($newarr), '?')) . ')'; $values = array_values($newarr); $res = $db->prepare("INSERT INTO apidata (item, value) VALUES $myplaceholders") ; $res->execute([$mykeys, $values]); The apidata table has three fields id (auto_increment) item and value, where am I going wrong? Thanks I am trying to display data from mysql. Each row from the mysql database shows up under rows. I want the rows of data from mysql to appear in colums of 4. can some one help please. <?php $sql = 'SELECT * FROM dbtable ORDER BY id'; $result = $db->query($sql); $output[] = '<ul>'; while ($row = $result->fetch()) { $output[] = '<table>'; $output[] = '<tr>'; $output[] = '<td class="style10"><strong>'.$row['item'].'</strong></td>'; $output[] = '</tr>'; $output[] = '<tr>'; $output[] = '<td><img src="images/'.$row['pic'].'" width="100" height="150" /></td>'; $output[] = '</tr>'; $output[] = '<tr>'; $output[] = '<td>'.$row['description'].'</td>'; $output[] = '</tr>'; $output[] = '</table>'; } echo join('',$output); ?> Hi, I'm having trouble adding data to the database (test) that i created. I just can't see where I'm going wrong. need some other peoples opinions. I have tried taking the id out of the SQL statement completely as it is an auto increment, but that doesn't seem to work either. Thanks in advance... <?php $fname = $_POST['fname']; $sname = $_POST['sname']; $email = $_POST['email']; $pword = $_POST['password']; $gender = $_POST['gender']; $user_name = "root"; $password = ""; $database = "test"; $server = "127.0.0.1"; $db_handle = mysql_connect($server, $user_name, $password); $db_found = mysql_select_db($database, $db_handle); if ($db_found) { $SQL = "INSERT INTO members (id, fname, sname, email, password, gender) VALUES (NULL, $fname, $sname, $email, $pword, $gender);"; $result = mysql_query($SQL); mysql_close($db_handle); print "Thanks for joining us ".$fname."."; print "<br /><br />"; print $fname . "<br />"; print $sname . "<br />"; print $email . "<br />"; print $pword . "<br />"; print $gender . "<br />"; } else { print "Database NOT Found"; mysql_close($db_handle); } ?> Hi. I'm making a private webpage for my self where i can post news, games, music titles and movies. I'm made it so that i can post and delete them from my page. Also i wanted to have the option to edit them. So i made a action that shows me a list og the posts in each category. And then i want the option to hit UPDATE, and then it should open the form with the info's from MySQL. I've made those two options as the following: Code: [Select] elseif ( $action == "EditNews" ) { // EDIT NEWS START if ( !$_GET['id'] ) { ?> <div id="content"> <?php $sql = mysql_query("SELECT * FROM news") or die(mysql_error()); while ( $row = mysql_fetch_assoc($sql) ) { echo "<a href=\"?page=Admin&action=UpdateNews&id=" . $row['news_id'] . "\">Update</a> | " . $row['subject'] . "<br>"; } echo "</div>"; } else { $type = $_GET['type']; $id = $_GET['id']; } // EDIT NEWS END } elseif ( $action == "UpdateNews" ) { // UPDATE NEWS START if ( !$_POST['submit'] ) { $id = $_GET['id']; $sql = mysql_query("SELECT * FROM news WHERE news_id='$id'") or die(mysql_error()); $user_id = $_SESSION['uid']; $subject = $_row['subject']; $body = nl2br($_row['body']); ?> <div id="content"> <form action="?page=Admin&action=EditNews" method="post"> <div id="">Subject</div> <div id=""><input id="input" type="text" name="subject"></div> <div id="">Message</div> <div id=""><textarea id="input" name='body' cols='15' rows='4'></textarea></div> <div id=""><input id="submit" class="input" type="submit" name="submit" value="Post News"></div> </form> </div> <?php } else { ?> <div id="content">Not Working!</div> <?php } // UPDATE NEWS END } - I know i miss something, but i've tried to get to the point, where i only have the form as blank, and need some help from there. I hope someone can help me with my problem. MOD EDIT: [code] . . . [/code] tags added. I have a mysql table with the structure of Code: [Select] ID Menu_Name Parent_ID 1 Finance NULL 2 Business NULL 3 Investment 1 4 Trading 2 How can I create a html <ul><li> list based on the parent? Hi all. Here is the code:(thanks to jcbones) Code: [Select] if (($handle = fopen($source_file, "r")) !== FALSE) { $columns = fgetcsv($handle, $max_line_length, ","); foreach ($columns as &$column) { $column = str_replace(".","",$column); } while (($data = fgetcsv($handle, $max_line_length, ",")) !== FALSE) { while(count($data) < count($columns)) { array_push($data, NULL); } $c = count($data); for($i = 0; $i < $c; $i++) { $data[$i] = "'{$data[$i]}'"; } $sql[] = '(' . implode(',',$data) . ','.$_POST[group].')'; } $sql = implode(',',$sql); $query = "INSERT INTO mytable (".mysql_real_escape_string(implode(",",$columns)).",Custgroup,user_id) VALUES " . $sql . "\n"; mysql_query($query) or trigger_error(mysql_error()); fclose($handle); } } If my csv file is: lastname,firstname,gender bob,ah,male So now the query will be : INSERT INTO mytable (lastname,firstname,gender) VALUES ('bob',ah','male'). But how if I want to insert extra data into mysql together with the data in csv file? Such as I have a value $_POST['group'] = 'family', so I tried: Code: [Select] $sql[] = '(' . implode(',',$data) . ','.$_POST[group].')'; $query = "INSERT INTO $target_table (".mysql_real_escape_string(implode(",",$columns)).",custgroup) VALUES " . implode(',',$sql) . "\n"; But in the query it will become : INSERT INTO mytable (lastname,firstname,gender,custgroup) VALUES ('bob',ah','male',family). It didn't have single quote , so I have error to insert the record.Can I know how to solve this problem? Thanks. how i can make a insert using this fuctions I m learning php, as using this functions (mysqli abstract) but after update wont work any more.
/** insert data array */ public function insert(array $arr) { if ($arr) { $q = $this->make_insert_query($arr); $return = $this->modifying_query($q); $this->autoreset(); return $return; } else { $this->autoreset(); return false; } }complement /** insert query constructor */ protected function make_insert_query($data) { $this->get_table_info(); $this->set_field_types(); if (!is_array(reset($data))) { $data = array($data); } $keys = array(); $values = array(); $keys_set = false; foreach ($data as $data_key => $data_item) { $values[$data_key] = array(); $fdata = $this->parse_field_names($data); foreach ($fdata as $key => $val) { if (!$keys_set) { if (isset($this->field_type[$key])) { $keys[] = '`' . $val['table'] . '`.`' . $val['field'] . '`'; } else { $keys[] = '`' . $val['field'] . '`'; } } $values[$data_key][] = $this->escape($val['value'], $this->is_noquotes($key), $this->field_type($key), $this->is_null($key), $this->is_bit($key)); } $keys_set = true; $values[$data_key] = '(' . implode(',', $values[$data_key]) . ')'; } $ignore = $this->ignore ? ' IGNORE' : ''; $delayed = $this->delayed ? ' DELAYED' : ''; $query = 'INSERT' . $ignore . $delayed . ' INTO `' . $this->table . '` (' . implode(',', $keys) . ') VALUES ' . implode(',', $values); return $query; }before update this class i used to insert data like this $db = Sdba::table('users'); $data = array('name'=>'adam'); $db->insert($data);this method of insert dont works on new class. if i try like this i got empty columns and empty values. thanks for any help complete class download http://goo.gl/GK3s4E Hi I have been trying to grab some data from an XML feed parse it and then insert it into a database. I will only need to do this on one occasion so no update or deletes. Sample of xml structu Code: [Select] <property> <id>34935</id> <date>2009-11-03 06:52:45</date> <ref>SVS0108</ref> <price>450000</price> <currency>EUR</currency> <price_freq>sale</price_freq> </property> Using xml2array class to parse the feed: <?php /** * xml2array Class * Uses PHP 5 DOM Functions * * This class converts XML data to array representation. * */ class Xml2Array { /** * XML Dom instance * * @var XML DOM Instance */ private $xml_dom; /** * Array representing xml * * @var array */ private $xml_array; /** * XML data * * @var String */ private $xml; public function __construct($xml = '') { $this->xml = $xml; } public function setXml($xml) { if(!empty($xml)) { $this->xml = $xml; } } /** * Change xml data-to-array * * @return Array */ public function get_array() { if($this->get_dom() === false) { return false; } $this->xml_array = array(); $root_element = $this->xml_dom->firstChild; $this->xml_array[$root_element->tagName] = $this->node_2_array($root_element); return $this->xml_array; } private function node_2_array($dom_element) { if($dom_element->nodeType != XML_ELEMENT_NODE) { return false; } $children = $dom_element->childNodes; foreach($children as $child) { if($child->nodeType != XML_ELEMENT_NODE) { continue; } $prefix = ($child->prefix) ? $child->prefix.':' : ''; if(!is_array($result[$prefix.$child->nodeName])) { $subnode = false; foreach($children as $test_node) { if($child->nodeName == $test_node->nodeName && !$child->isSameNode($test_node)) { $subnode = true; break; } } } else { $subnode = true; } if ($subnode) { $result[$prefix.$child->nodeName][] = $this->node_2_array($child); } else { $result[$prefix.$child->nodeName] = $this->node_2_array($child); } } if (!is_array($result)) { $result['#text'] = html_entity_decode(htmlentities($dom_element->nodeValue, ENT_COMPAT, 'UTF-8'), ENT_COMPAT,'ISO-8859-15'); } if ($dom_element->hasAttributes()) { foreach ($dom_element->attributes as $attrib) { $prefix = ($attrib->prefix) ? $attrib->prefix.':' : ''; $result["@".$prefix.$attrib->nodeName] = $attrib->nodeValue; } } return $result; } /** * Generated XML Dom * */ private function get_dom() { if(empty($this->xml)) { echo 'No XML found. Please set XML data using setXML($xml)'; return false; } $this->xml_dom = @DOMDocument::loadXML($this->xml); if($this->xml_dom) { return $this->xml_dom; } echo 'Invalid XML data'; exit; } } ?> My results page: <?php require_once('classes/xml2array.php'); require_once('conn.php'); function curlURL($url) { $ch= curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.2) Gecko/20070219 Firefox/2.0.0.2'); $output = curl_exec($ch); return $output; } $curlResults = curlURL("http://localhost/alphashare_dump/property.xml"); $xml = $curlResults; $converter = new Xml2Array(); $converter->setXml($xml); $xml_array = $converter->get_array(); $array = ($xml_array['root']['property']); echo "<pre>"; print_r($array); echo "</pre>"; ////////////// INSERT DATA INTO DB //////////////////////////////////////////////////// ?> My array structure looks like this: Code: [Select] Array ( [0] => Array ( [id] => Array ( [#text] => 34935 ) [date] => Array ( [#text] => 2009-11-03 06:52:45 ) [ref] => Array ( [#text] => SVS0108 ) [price] => Array ( [#text] => 450000 ) [currency] => Array ( [#text] => EUR ) [price_freq] => Array ( [#text] => sale ) [part_ownership] => Array ( [#text] => 0 ) Can somebody help with actually getting this into some format that will enable me to insert this into my database please GT Hi there, hope u guys able to help. I'm have created a enquiry form where I want these actions to run when a button is submitted: 1. Insert data from form fields into my database 2. When data is inserted into database, then send an e-mail (multiple email user) to the address with the form fields. The e-mail is carrying the form fields. so ...what I need now is how to send the form field to email. Insert the data into my table in my database,then send en e-mail. Code: [Select] <? // Connects to your Database mysql_connect("xxxxxx","xxxxxx","xxxxxx") or die(mysql_error()); mysql_select_db("xxxxxx") or die(mysql_error()); // now we insert it into the database $insert = "INSERT INTO enquiry (name, email, cont_number, subject, msg) VALUES ('".$_POST['name']."', '".$_POST['email']."', '".$_POST['cont_number']."', '".$_POST['subject']."','".$_POST['msg']."')"; $add_member = mysql_query($insert); ?> <?php function error_bool($error, $field) { if($error[$field]) { print("<td style=color:red>"); } else { print("<td>"); } } function show_form() { global $HTTP_POST_VARS, $print_again, $error; ?> <h2 align="center"> Enquiry Form</h2> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <table align="center" cellpadding="3"> <tr> <?php error_bool($error, "name"); ?> Name </td> <td>:<input name="name" type="text" id="name" SIZE="33" value="<? echo $_POST["name"]; ?>"></td> </tr> <tr> <?php error_bool($error, "email"); ?> Email </td> <td>:<input name="email" type="text" id="email" SIZE="33" value="<? echo $_POST["email"]; ?>"></td> </tr> <tr><td>Contact No. </td><td> :<input type="text" name="cont_number" SIZE="33" maxlength="10"> </td></tr> <tr><td>Subject </td><td> :<input type="text" name="subject" SIZE="33" maxlength="25"> </td></tr> <tr><td>Your Message :</td><td> <textarea name="msg" cols="27" rows="5" wrap="virtual"></textarea> </td></tr> <tr> <td><th colspan=4 align="right"> <input type="reset" value="CLEAR"><input type="submit" name="Submit" value="Submit"></td> </th><td> </td> </tr> </table> </form> <? } if(isset($_POST["Submit"])) { check_form(); } else { show_form(); } function check_email_address($email) { // First, we check that there's one @ symbol, and that the lengths are right if (!ereg("^[^@]{1,64}@[^@]{1,255}$", $email)) { // Email invalid because wrong number of characters in one section, or wrong number of @ symbols. return false; } // Split it into sections to make life easier $email_array = explode("@", $email); $local_array = explode(".", $email_array[0]); for ($i = 0; $i < sizeof($local_array); $i++) { if (!ereg("^(([A-Za-z0-9!#$%&'*+/=?^_`{|}~-][A-Za-z0-9!#$%&'*+/=?^_`{|}~\.-]{0,63})|(\"[^(\\|\")]{0,62}\"))$", $local_array[$i])) { return false; } } if (!ereg("^\[?[0-9\.]+\]?$", $email_array[1])) { // Check if domain is IP. If not, it should be valid domain name $domain_array = explode(".", $email_array[1]); if (sizeof($domain_array) < 2) { return false; // Not enough parts to domain } for ($i = 0; $i < sizeof($domain_array); $i++) { if (!ereg("^(([A-Za-z0-9][A-Za-z0-9-]{0,61}[A-Za-z0-9])|([A-Za-z0-9]+))$", $domain_array[$i])) { return false; } } } return true; } function check_form() { global $HTTP_POST_VARS, $error, $print_again; $error['name'] = false; if($_POST["name"]=="") { $error['name'] = true; $print_again = true; $message="The name field is empty<br>"; } if(!check_email_address($_POST['email'])) { $error['email'] = true; $print_again = true; $message.="Either Field Empty or Invalid Email ID <br>"; } if($print_again) { show_form(); } else { show_form(); $message="Thank You !! <br> Form has been submitted"; } echo "$message"; } ?> </body> </html> How do i do this? Thank you in advanced and sorry for bad English. Best regards, Desmond Hello guys, im using this code atm and it's working, but the new rows created are put in the end of the table. I want them to stack up from the beginning pushing older rows down. What should i do to make that work? <?php $con = mysql_connect("localhost","*****","*******"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("ananaz_se", $con); $sql="INSERT INTO stuff (adult, namn, url) VALUES ('$_POST[adult]','$_POST[namn]','$_POST[url]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "1 row added"; mysql_close($con) ?> Hi all . In my scripts , there is a textarea that allow user to enter multiple phone number , message and date . If there are 3 phone numbers in textarea , how can I insert 3 of them into sql with the same data of message and date? Such as : phone number : 0102255888,0235544777,0896655444 message:hello all date:10/10/2011 and when it's insert into table , it will become: 1. 0102255888 | hello all | 10/10/2011 2. 0235544777 | hello all | 10/10/2011 3. 0896655444 | hello all | 10/10/2011 Here is the code I tried , but it will just save the last phone number . Code: [Select] $cellphonenumber = explode(',', $_POST['cellphonenumber']); $message = $_POST['inputtext']; $date = $_POST['datetime']; foreach($cellphonenumber as $value) { $sql="INSERT INTO esp( Recipient , Message , Date) VALUES ('$value','$message','$date')"; } mysql_query($sql) or die ("Error: ".mysql_error()); echo "Database updated."; Any hints or advices ? Thanks for every reply . I'm Trying to INSERT Data into mysql which is generated from biomatric attendance device. what i wanted to do is to save these data into mysql database. <?php include 'db.php'; ?> <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <script src="//ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script> <script src="//ajax.googleapis.com/ajax/libs/jqueryui/1.11.2/jquery-ui.min.js"></script> <!-- <script type="text/javascript" src="load.js"></script> --> <link rel="stylesheet" href="style.css"> <title>Live Attendance</title> </head> <?php include("zklib/zklib.php"); $zk = new ZKLib("192.168.1.3", 4370); $ret = $zk->connect(); sleep(1); if ( $ret ): $zk->disableDevice(); sleep(1); ?> <body> <table border="1" cellpadding="5" cellspacing="2" style="float: left; margin-right: 10px;"> <tr> <th colspan="5">Data User</th> </tr> <tr> <th>UID</th> <th>ID</th> <th>Name</th> <th>Role</th> <th>Password</th> </tr> <?php try { //$zk->setUser(1, '1', 'Admin', '', LEVEL_ADMIN); $user = $zk->getUser(); sleep(1); while(list($uid, $userdata) = each($user)): if ($userdata[2] == LEVEL_ADMIN) $role = 'ADMIN'; elseif ($userdata[2] == LEVEL_USER) $role = 'USER'; else $role = 'Unknown'; ?> <tr> <td><?php echo $uid ?></td> <td><?php echo $userdata[0] ?></td> <td><?php echo $userdata[1] ?></td> <td><?php echo $role ?></td> <td><?php echo $userdata[3] ?> </td> </tr> <?php endwhile; } catch (Exception $e) { header("HTTP/1.0 404 Not Found"); header('HTTP', true, 500); // 500 internal server error } //$zk->clearAdmin(); if (isset($_POST['create_post'])) { $query = "INSERT INTO attendance(idx)"; $query .= "VALUES ($id)"; $submittodbquery = mysqli_query($con,$query); if (!$submittodbquery) { die("Failed up upload " . mysqli_error($con)); }else { echo "updated"; } } ?> </table> <button id="submit" type="submit" name="create_post" class="btn btn-danger">Submit New Post</button> <?php $name = $userdata[1]; $attendance = $zk->getAttendance(); sleep(1); while(list($idx, $attendancedata ) = each($attendance)): if ( $attendancedata[2] == 1 ) $status = 'Check Out'; else $status = 'Check In'; ?> <?php $idx ?> <?php $attendancedata[0] ?> <?php $attendancedata[1] ?> <?php $status ?> <?php date( "d-m-Y", strtotime( $attendancedata[3] ) ) ?> <?php date( "H:i:s", strtotime( $attendancedata[3] ) ) ?> <?php // custom code if (isset($_POST['submit'])) { $query = "INSERT INTO attendance(idx)"; $query .= "VALUES ($idx)"; $submittodbquery = mysqli_query($con,$query); if (!$submittodbquery) { die("Failed up upload " . mysqli_error($con)); }else { echo "updated"; } } ?> <?php endwhile ?> </table> <input type="submit" name="submit" value="Update Database"> <?php $zk->enableDevice(); sleep(1); $zk->disconnect(); endif ?> </body> </html> Thanks for reading my question ..
hi there..im new to php mysql and im having trouble inserting a string data to mysql from a php date() function. here's my code: Code: [Select] $year = date('Y'); echo $year; $insertSQL = sprintf("INSERT INTO tbl_elections (election_id=$year)"); mysql_select_db($database_organizazone_db, $organizazone_db); $Result1 = mysql_query($insertSQL, $organizazone_db) or die(mysql_error()); when i try to output the $year variable on a webpage, it returns "2012" but when i try to insert this data into my database table, it returns an error like this: check the manual that corresponds to your MySQL server version for the right syntax to use near '=2012)' is there a way to convert "2012" into a normal string data type? Not sure exactly what my problem is here, but i have looked at this at least a hundred times and I just can't figure out what is going on. Everything works great except for the sending the email part. It displays the error "There was a problem sending the mail". The form field checking works fine, the insert into mysql works fine - - but it won't send the email. I have tried using double quotes and single quotes for the email information ($to, $subject, etc...) I have even eliminated the form data from the email information and it still doesn't send. I am hopelessly stuck at this point Any ideas?? Code below: <html> <body bgcolor = 'blue'> <div align = 'center'> <h1>test FORM</h1> </div> <p> <?php If ($_POST['submit']) //if the Submit button pressed { //collect form data $fname = $_POST['FName']; $lname = $_POST['LName']; $email = $_POST['Email']; $tel = $_POST['Tel']; $mess = $_POST['Mess']; $errorstring = ""; if (!$fname) $errorstring = $errorstring."First Name<br>"; if (!$lname) $errorstring = $errorstring."Last Name<br>"; if (!$email) $errorstring = $errorstring."Email<br>"; if ($errorstring !="") echo "<div align = 'center'><b>Please fill out the following fields:</b><br><font color = 'red'><b>$errorstring</b></font></div>"; else { $fname = mysql_real_escape_string($fname); $lname = mysql_real_escape_string($lname); $email = mysql_real_escape_string($email); $tel = mysql_real_escape_string($tel); $mess = mysql_real_escape_string($mess); $con = mysql_connect("localhost","user","password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("mec", $con); $sql="INSERT INTO formtest (FName, LName, Title, Tel, Email, Mess) VALUES ('$fname','$lname','$title','$tel','$email','$mess')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } $to = 'myemailaddress'; $subject = 'test form'; $message = 'Hello'; $headers = 'From Me'; $sent = mail($to, $subject, $message, $headers); if($sent) {print "Email successfully sent";} else {print "There was an error sending the mail";} mysql_close($con); } } ?> <p> <form action= 'testmecform.php' method= 'POST'> <table width = '640' border = '0' align = 'center'> <tr> <td align = 'right'><b>First Name</b></td> <td><input type = 'text' name = 'FName' value = '<?php echo $fname; ?>' size = '25'></td> <td><div align = 'right'><b>Telephone</b></div></td> <td><input type = 'text' name = 'Tel' value = '<?php echo $tel; ?>' size = '25'></td> </tr> <tr> <td align = 'right'><b>Last Name</b></td> <td><input type = 'text' name = 'LName' value = '<?php echo $lname; ?>' size = '25'></td> <td> </td> <td> </td> </tr> <tr> <td align = 'right'><b>Email</b></td> <td><input type = 'text' name = 'Email' value = '<?php echo $email; ?>' size = '25'></td> <td> </td> <td> </td> </tr> <tr> <th colspan = '4'><b>Please enter any additional information he </b></th> </tr> <tr> <th colspan = '4'><textarea name = 'Mess' cols = '50' rows = '10'><?php echo $mess; ?></textarea></th> </tr> <tr> <th colspan = '4'><b>Please make sure all information is correct before submitting</b></th> </tr> <tr> <th colspan = '4'><input type = 'submit' name = 'submit' value = 'Submit Form'></th> </tr> </table> </form> </body> </html> I am not sure if the title is correct; I tried my best.
I'm a PHP/MySQL beginner and I really need some help.
I have a small script that I am using for sending SMS. I recently added a phonebook. The problem with the phonebook right now is that it's available to all users, i.e. they can all update and delete all rows. What I would like to do is make it so that each user can update and delete only their own contacts.
I have a table call contacts. Inside that table there is first name, last name, company and phonenumber.
How can I accomplish this with PHP & MySQL?
CREATE TABLE IF NOT EXISTS `contacts` ( `contact_id` int(10) NOT NULL AUTO_INCREMENT, `firstname` varchar(255) NOT NULL, `lastname` varchar(255) NOT NULL, `company` varchar(255) NOT NULL, `cell_no` text NOT NULL, PRIMARY KEY (`contact_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; CREATE TABLE IF NOT EXISTS `users` ( `user_id` int(11) NOT NULL AUTO_INCREMENT, `users_name` varchar(30) NOT NULL, `uname` varchar(30) NOT NULL, `u_pass` varchar(60) NOT NULL, `utype` varchar(30) NOT NULL, `timezone` varchar(30) NOT NULL, `uapi_user` varchar(30) NOT NULL, `uapi_pass` varchar(60) NOT NULL, PRIMARY KEY (`user_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ; <?php if (isset($_POST['submit'])){ //form has been submitted1 $firstname = trim($_POST['firstname']); $lastname = trim($_POST['lastname']); $company = trim($_POST['company']); $cellno = trim($_POST['cell_no']); if($firstname == ''){ echo '<div class="alert alert-danger">First Name is not Valid!</div>'; exit; }elseif($lastname == ''){ echo '<div class="alert alert-danger">Last Name is not Valid!</div>'; exit; }elseif($company == ''){ echo '<div class="alert alert-danger">Company is not Valid!</div>'; exit; }elseif($cellno == ''){ echo '<div class="alert alert-danger">Cellphone Number is not Valid!</div>'; exit; }else{ $query = "Select cell_no from contacts where cell_no = '".$cellno."' "; $result = mysql_query($query); if (!mysql_num_rows($result)) { $sql = "INSERT INTO contacts(firstname, lastname, company, cell_no) values('{$firstname}','{$lastname}', '{$company}', '{$cellno}')"; $result = mysql_query($sql); confirm_query($result); //echo '<div class="alert alert-success">Successfully added.</div>'; //exit; ?> <script type="text/javascript"> window.location = "contact_list.php"; </script> <?php } else{ echo '<div class="alert alert-danger">Username. already exist!.</div>'; echo '<p><a href="new_contact.php" class="btn btn-success"> Back </a></p>'; exit; }} }else{ $firstname = ""; $lastname = ""; $company = ""; $cellno = ""; } ?> |