PHP - <? Include("include/session.php"); ?>
When I put this above all else in my document and test it offline, all I see is code in the browser. But when I test it on my web server, I can view the markup and whatnot.
Does anyone know why this is? Similar TutorialsI am come across a very odd situation when I include a connnet.php file. For some reason it messes up the layout of the page. However when I enter the connect code onto the page it looks fine. Code: [Select] include("connect.php"); What is also strange is that when I include the header and footer it works fine. For some reason it is just when I include the connect.php file. Is this because it is above the CSS file? Code: [Select] include("header.php"); Code: [Select] include("footer.php"); I am having some real problems with the code in red below which sits in my "index.php" file, and would be very grateful for any help! <?php include("header.php"); include $_GET["view"] . ".php"; include("footer.php"); ?> The links for my "views" (e.g. <a href="?view=page_news">News</a> ) are in my "header.php" file. The whole website works absolutely fine, except when you first arrive on the homepage you get: Notice: Undefined index: view Warning: include(.php) [function.include]: failed to open stream: No such file or directory This is presumably because a link hasn't been clicked yet, thus a "view" hasn't been defined yet, but I have no idea how to get around this! I hope I haven't been too vague with my explanation... Thanks, James This include does not work. I presume due to the ? in it. <?php include("signin-redirect.php?page=my-account.php");?> It works as just signin-redirect.php but I want to include the ?page=my-account.php on the end of it. Thanks This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=342600.0 I really new to php and this has me baffled, I have seen it done before and just cant figure it out. I have a box in my left column that looks like this I have two includes to go in that div one is named todo.php and the other is change.php how do I go about switching only the includes within that dive tag when the ToDo and Change buttons are pressed? Thanx Rab I have a file called "inc_records.php" which outputs data from a mysql query. It has the following code in it. $content = "<p>" . $record_array['first_name'] . "</p>"; $content .= "<p>" . $record_array['last_name . "</p>"; I am going to use this code everytime I need to display that data. I want to save the $content variable as another variable. For example. $_SESSION['content'] = include("includes/inc_records.php"); However this isn't working so what is the best way to do it? Thanks for any help. in the hard code this text is not anywhere to be seen. HOWEVER. the final result prints this text before every php include.. the site is www.matt-cardle.co.uk ive noticed it only does it on pages after the landing page.. so www.matt-cardle.co.uk DOESNT SHOW but www.matt-cardle.co.uk/Home [and any other page] DOES SHOW the unclude i am using is like this for all page: "<?php include '../includes/ads2.php'; ?>" and text before and after this for example is..: <table style="width: 55%; height: 84px;" cellspacing="0" cellpadding="0" align="right"> <tr> <td style="height: 23px" class="style9"><?php include '../includes/ads2.php'; ?></td> </tr> </table> Hello person who reads this now I work a lot with <?php include("..."); ?> and I never thought beyond the html I put in there. In 1 of the include files I have the set-up of a simple vertical html/css menu and on the right next to it I have an image. However, not every page on my website needs the same image and I probably will change a lot of them frequently. Now I was wondering if (and how) I could include a piece of PHP code which does the following: If the web-url is "page1.php" show "image1.png" If the web-url is "page2.php" show "image2.png" If the web-url is "page3.php" show "image3.png" etc. This way I only have to change the "imageX.png" in 1 file. I hope you can help me. Best regards and thanks in advance! Ferdri3 Hello everyone. I'm having a problem with what should be a fairly simple login system that is included on the index page of my site. Basically, it is set up to display a short form so that the user can enter his/her email address and password to log in. If there is a mistake with the email/password, it displays the same form with a notification that there was an incorrect email or password. The problem that I'm having is that when the wrong email/password is entered, the page goes to the next step of notifying the user of the incorrect information but it does not display the rest of the page that it is included on. What is happening is when the user arrives at the site it displays the index.php page, which is currently a blank page with some simple text, and the included page mentioned above. When an incorrect email/password is entered, instead of staying on the index page and displaying the included page with the login form, the user is redirected away from the index page to the included page only. Here's my code for "head.inc.php": Code: [Select] <?php include("conf.inc.php"); // Includes the db and form info. session_start(); // Starts the session. if ($_SESSION['logged'] == 1) { // User is already logged in. $_SESSION['email'] = $email; header("Location: main.php"); // Goes to main page. exit(); // Stops the rest of the script. } else { if (!isset($_POST['submit'])) { // If the form HAS NOT been submitted. echo "<form name=\"form\" action=\"head1.inc.php\" method=\"POST\" style=\"margin-bottom:0;\">"; echo "<a href=\"signup.php\" class=\"bluelink\">Sign Me Up!</a> "; echo "<a href=\"pwordhelp.php\" class=\"bluelink\" onClick=\"return popup(this, 'notes')\">Forgot Password</a> <br>"; echo "<input type=\"text\" name=\"email\" size=\"17\" value=\"Email...\" style=\"color: #999999\" onfocus=\"if (this.value == 'Email...') {this.value=''; this.style.color='#000000'}\"> "; echo "<input type=\"text\" name=\"pword\" size=\"17\" value=\"Password...\" style=\"color: #999999\" onfocus=\"if (this.value == 'Password...') {this.value=''; this.style.color='#000000'; this.type='password'}\"> "; echo "<input type=\"submit\" name=\"submit\" value=\"Submit\"> "; echo "</form>"; } else { // If the form HAS been submitted $email = form($_POST['email']); $pword = md5($_POST['pword']); // Lightly encrypts the password. $q = mysql_query("SELECT * FROM `signin` WHERE email = '$email' AND pword = '$pword'") or die (mysql_error()); // mySQL query $r = mysql_num_rows($q); // Checks to see if anything is in the db. if (!$r) { // There is something in the db. The username/password match up. echo "<form name=\"form\" action=\"head1.inc.php\" method=\"POST\" style=\"margin-bottom:0;\">"; echo "<a href=\"signup.php\" class=\"bluelink\">Sign Me Up!</a> "; echo "<a href=\"pwordhelp.php\" class=\"bluelink\" onClick=\"return popup(this, 'notes')\">Forgot Password</a> <br>"; echo "<font color=\"#FF0000\"><strong>Incorrect Email or Password.</strong></font> "; echo "<input type=\"text\" name=\"email\" size=\"17\" value=\"Email...\" style=\"color: #999999\" onfocus=\"if (this.value == 'Email...') {this.value=''; this.style.color='#000000'}\"> "; echo "<input type=\"text\" name=\"pword\" size=\"17\" value=\"Password...\" style=\"color: #999999\" onfocus=\"if (this.value == 'Password...') {this.value=''; this.style.color='#000000'; this.type='password'}\"> "; echo "<input type=\"submit\" name=\"submit\" value=\"Submit\"> "; echo "</form>"; } else { // If the username/password is invalid $_SESSION['logged'] = 1; // Sets the session. $_SESSION['email'] = $email; header("Location: main.php"); // Goes to main page. exit(); // Stops the rest of the script. } } } ?> Here's the code for "index.php": Code: [Select] <?php include("head.inc.php"); echo "This is the index page"; ?> Any ideas on how to stop the redirection from the index page when the incorrect info is entered? Can someone please help me with an array problem i can not figure out. I need the array to be numbered from 1 to how ever many fields that are needed in the form and have a mysql field name and the title of the field also in the array. 1, "mysql_field_name", "Title of form field" 2, "", "" and so on then the form will be shown based on the array. I have the following draft code which I am working with. any suggestions on how i may do this array ? Code: [Select] <?php $options = array( '1'=> array('fieldtext'=>'option1', 'mysqlfield'=>'option1'), '2'=> array('fieldtext'=>'option2', 'mysqlfield'=>'option2'), '3'=> array('fieldtext'=>'option3', 'mysqlfield'=>'option3'), '4'=> array('fieldtext'=>'option4', 'mysqlfield'=>'option4'), ); // $options = array(1 => "option1", "option2", "option3", "option4"); // the line above works but i want to include the name of the mysql field as well. $userid = 1; ?> <div style="align: center; margin: 12px; font-family:Tahoma;"> <br><br><?php if ($_POST['Update'] != "Update") { // check if form submitted yet, if not get data from mysql. $res = db_query("SELECT * FROM `users` WHERE `userid` = '" . $userid . "'"); foreach($options as $key => $value) { $_POST[$key] = mysql_result($res, 0, $value); } $ok_to_update = "no"; } elseif ($_POST['Update'] == "Update") { // check if form submitted yet, if so get POST data. // error checking // foreach($options as $key => $value) { // $_POST[$i] = ""; // } $ok_to_update = "yes"; } if ($_POST['Update'] == "Update" && $ok_to_update == "yes") { // $res = db_query("INSERT INTO `users` () VALUES ()"); // add user details to database. ?><p><br><br><br>Thank you for updating</p><?php } else { ?><form name="form1" method="post" action=""> <?php foreach($options as $key => $value) { ?><p><?php echo($value); ?>: <input type="text" name="<?php echo($key); ?>" value="<?php echo($_POST[$key]);?>"></p> <?php } ?> <input name="Update" type="submit" value="Update"> </form> <?php } ?> </div> basically i want to be able to include a file.. in other files within folders. i have a universal include which holds my template etc and i have a include in there which mess's up when being called by a file inside a folder... now i know usually you can just use. include("../file.php"); or you can define the entire url of the included file.. but i was wondering if there was another way? Hi, bit stuck on how to find and replace "<" and ">" with "<" and ">". I basically have a database record that outputs to screen and I need the code in the <code> tags to be rendered to the screen. I therefore need it to go through the whole array variable from the db and change the symbols just inside the code tags. Please be aware that the code tags might happen more than once here's an example below Code: [Select] <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> the desired output would be: <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> help on this would be great Cheers Rob Hi guys I am a newbie with PHP and I have been trying to solve this problem for 3 days.. Ive set up a booking form on my website to be sent directly to my email once the client clicked on the send button.. The problem I am having while checking these pages on wamp is that the booking form is ok but when I click on the send button the following message error appears "Warning: mail() [function.mail]: Failed to connect to mailserver at "localhost" port 25, verify your "SMTP" and "smtp_port" setting in php.ini or use ini_set() in C:\wamp\www\fluffy_paws\booking_form2.php on line 27" When I check online I have this message "500 - Internal server error. There is a problem with the resource you are looking for, and it cannot be displayed." Are my codes wrong??? My webhosting is Blacknight.com , Im on Windows Vista, my internet is a dongle with O2 ireland Thanks for your help! Hi guys I'm struggling a bit, I need to replace a word that occurs multiple times in text with an array("up","down","forward","backwards") of words. $find = "left"; $replace = array("up","down","forward","backwards"); $text = "left left left left"; echo str_replace($find,$replace,$text); The Output is: array array array array Did try this with a foreach statement as well, but no luck. Is there a better way of doing this? Thanks Hi All, first of all. Sorry for signing up to the site and then immediately asking for help. I hate doing it but always seems to be the way people get involved with forums these days and it seems I am no different... So thank you in advance if you are kind enough to answer! Among many personal flaws, my issue is a technical one regarding the ability to retain session variables. Unfortunately whilst the website itself is not complicated, the problem is not as simple as just running session_start(); and letting it get on and do its own thing. So the problem exists around a relatively simple contact form and the basic Turing test that it uses to prove the user is human. The script adds a value to the $_SESSION variable and then on the next page load, tests to see if the variable is still there. As per this little function: function cookiesEnabled() { if ($_SESSION['cookiesEnabledTest']) $_SESSION['cookiesEnabled'] = true; else $_SESSION['cookiesEnabledTest'] = true; } Now for what must be 95% of all users, the variable is still there, proving the the session is being maintained as the user navigates the site. Unfortunately a small group of computers appear to be having difficulties with this for a not too clear reason. The computers have varying browser user agents indicating that they are all (so far) using one of the following: MSIE 8 MSIE 7 MSIE 7 in what appears to be MSIE 6 compatibility mode Now in testing, I can't get MSIE 8 or MSIE 7 to produce the same effect, with exception to MSIE 8 in "InPrivate" browsing mode. In this mode it is easy to see that there is no cookie txt file being created and thus no way of the browser to pass back the session id on the next page load. I can't think of any detail that I have missed out, but if there is anything I have left unclear, please let me know! Thanks again! Felix cant work out this mysql syntax error "operation":"medupdate","medid":"","name":"ibo","medyear":"5","medmonth":"21","medday":"1","recuser":1,"SuccFail":"fail","SuccFailMessage":"error occured You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '''WHERE med_id=' at line 2","ResultData":""} Code: [Select] $sql="update metodology set med_description='".$req['name']."', med_year='".$req['medyear']."', med_month='".$req['medmonth']."', med_day='".$req['medday']."', med_recorddate= now(), med_recorduserid= 1'"; $sql.= " WHERE med_id=".$req['medid']; Code: [Select] <?php session_start(); $index="1"; $_SESSION[$index]=2; echo "$_SESSION[$index]"; ?> Hi good day check how to have a variable "$index" inside session.. I'm trying to post to a (SMF) simplemachines 2.0 forum using curl. I have logged in and I have tried sending all the fields, but when I try to post, I receive this message: "The following error or errors occurred while posting this message: Your session timed out while posting. Please try to re-submit your message." Do any of you know why this happens? Is the problem that when I visit the posting url, they give me a cookie that expires if I leave the posting url? I don't think the form is invalid, it looks like it has to do with the session. People at the simplemachines forum can have this problem when they try to post the ordinary way, but that is because of an inactivity period. Can my problem be because of a cookie? What I'm trying to accomplish is your average session login w/ a cookie-based "remember me" feature. I can log in fine, I can set cookies, I can access those cookies, and I can use that data to log in just as if the user had logged in manually. The problem is logging out. But the bigger problem is figuring out why. You see, it works perfect. It logs in and it log out, so long as I am outputting data to the page. I was outputting a session variable and the cookies I set to make sure they were all working right; and they were. But then as soon as I disable those echoes, all of a sudden it won't log out anymore. So then I turn them on to see what the data says and BAM, I'm logged out. I log back in fine, I log back out fine, so I turn em off again. I log in fine. I can't log out. I try multiple times. I close my browser and open a new one. Still logged in. I try a few more times, still logged in. I turn the output back on, load the page again and I'm logged out. So... WTF? (my code to follow) I am getting the following error when using composer: "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? Just started. I am pretty sure composer.json wasn't changed. journalctl doesn't show anything. Maybe Doctrine related, however, nothing seems to help.
Any ideas? [michael@devserver www]$ php -v PHP 7.3.4 (cli) (built: Apr 2 2019 13:48:50) ( NTS ) Copyright (c) 1997-2018 The PHP Group Zend Engine v3.3.4, Copyright (c) 1998-2018 Zend Technologies with DBG v9.1.9, (C) 2000,2018, by Dmitri Dmitrienko [michael@devserver www]$ composer -V Composer version 1.4.2 2017-05-17 08:17:52 [michael@devserver www]$ yum info composer Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * base: mirror.us.oneandone.net * epel: mirror.rnet.missouri.edu * extras: mirror.us.oneandone.net * remi-php73: mirror.bebout.net * remi-safe: mirror.bebout.net * updates: mirror.us.oneandone.net Installed Packages Name : composer Arch : noarch Version : 1.8.4 Release : 1.el7 Size : 1.8 M Repo : installed From repo : epel Summary : Dependency Manager for PHP URL : https://getcomposer.org/ License : MIT Description : Composer helps you declare, manage and install dependencies of PHP projects, : ensuring you have the right stack everywhere. : : Documentation: https://getcomposer.org/doc/ [michael@devserver www]$ composer update Loading composer repositories with package information Updating dependencies (including require-dev) [ErrorException] "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? update [--prefer-source] [--prefer-dist] [--dry-run] [--dev] [--no-dev] [--lock] [--no-custom-installers] [--no-autoloader] [--no-scripts] [--no-progress] [--no-suggest] [--with-dependencies] [-v|vv|vvv|--verbose] [-o|--optimize-autoloader] [-a|--classmap-authoritative] [--apcu-autoloader] [--ignore-platform-reqs] [--prefer-stable] [--prefer-lowest] [-i|--interactive] [--root-reqs] [--] [<packages>]... [michael@devserver www]$
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