PHP - Database Entries To C# Question:

For some reason my for loop only seems to be storing some data in my fields, most of the time the data is not true but simply duplicating one of the entries. So instead of having a string of 1,2,3,4 for instance it would store all of them as 4. The entires are selected using fields in a multiple select box, in theory of someone choses 10 unique entries from the "Systems" category all 10 should be made into rows in the MySQL table.

Any idea why this is happening?

The form,

if ($type == "games") {

echo "<tr><td>".$name."</td><td><select name='".$name."_".$i."'[] multiple='multiple'><option value='' selected>--------</option>";

$sqla = mysql_query("SELECT * FROM ".$pre."games ORDER BY `name` ASC") or die(mysql_error());

while($row2a = mysql_fetch_array($sqla)) {
$system = mysql_fetch_array(mysql_query("SELECT * FROM ".$pre."systems WHERE id = '".$row2a[system]."'"));
echo "<option value='".$row2a[id]."'>".$row2a[name]." - ".$system[name]."</option>";
}
echo "</select></td></tr>";
}

if ($type == "system") {
echo "<tr><td>".$name."</td><td><select name='".$name."_".$i."'[] multiple='multiple'><option value='' selected>--------</option>";

$sqlb = mysql_query("SELECT * FROM ".$pre."systems ORDER BY `name` ASC") or die(mysql_error());
while($row2b = mysql_fetch_array($sqlb)) {
echo "<option value='".$row2b[id]."'>".$row2b[name]."</option>";
}
echo "</select></td></tr>";
}

The PHP code,

while($row = mysql_fetch_array($query)) {
$name = "$row[name]";

for ($i = 0; $i < count($_POST["systems_$i"]); $i++) {
   mysql_query("INSERT INTO ".$pre."fielddata VALUES (null, 'systems', '".$_POST["systems_$i"]."', '".$fetch[0]."', 'content')");
}

for ($i = 0; $i < count($_POST["games_$i"]); $i++) {
   mysql_query("INSERT INTO ".$pre."fielddata VALUES (null, 'games', '".$_POST["games_$i"]."', '".$fetch[0]."', 'content')");
}

Hi,
I want to be able to generate visitor statistics for a blog I'm creating. I'm going to be collecting numerous pieces of data when a post is viewed, including a time stamp of the visit.

I need to be able to select timestamps that were within the current day, the previous day, the day before that ect.. So that I can generate the statistics.
Show it for the current week (current day and 6 previous days).

So it would be the entries where the timestamp was made on the days: 11/1, 10/1, 9/1, 8/1, 7/1, 6/1, 5/1. For example.

Not quite sure how I could do this.

Thanks.

Hello,

I am using the following code to display images managed by a MySQL database.  Basically another program manages a bunch of images, but this script displays certain ones (ones with INCLUDE = 1 in the database) on my main page.  My question is, is there an easy way to limit the number of images it displays, say to 5?  I'm not too concerned which images actually display (ascending or descending)... or better yet, random!  Most importantly, I only want five to display.  Each image will be linked to the full page, which displays all the images.

Any ideas?

Thanks!


Code: [Select]
<?php
$username="XXXXXXX";
$password="XXXXXXX";
$database="XXXXXXX";

mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
$query="SELECT * FROM ft_form_12 WHERE col_24='1'";
// $query="SELECT * FROM ft_form_12";
// SELECT * FROM ft_form_12 WHERE col_24='1'
$result=mysql_query($query);

$num=mysql_numrows($result);

mysql_close();
?>

<?php
$i=0;
while ($i < $num) {

$f20=mysql_result($result,$i,"col_23"); //Photo file name
$f21=mysql_result($result,$i,"col_24"); //INCLUDE
?>

<a href="http://www.domain.com/display_whole_page.shtml"><img src="http://www.domain.com/the_file/pictures/<?php echo $f20; ?>" height="50" border="0"></a>&nbsp;&nbsp;&nbsp;
               
<?php
$i++;
}
?>

Hello. Many thanks for your help.

I am writing a PHP/MySQL dating-site and have hit a programming impass.

I have a database full of members and a search form consisting of checkboxes.

So to search, a member ticks say...gender: female; age: 21,22,23,24,25,26; height: 5'4",5'5",5'6",5'7"; county: cornwall,devon,somerset

How can a run a check on the database selecting all entries that fall into the selected criteria. For example a 23 year old female of 5'5" living in Cornwall and a 26 year old female of 5'4" living in Somerset?

The key index of my database is 'id' and the fields a age,height,county
The names of the form checkboxes a
Gender: male, female; Age: 21,22,23,24 etc; Height: 5_4,5_5,5_6 etc; county: cornwall,devon etc

I coded the following but some parts are not working (the "curveball" mentioned at the end).
How would YOU do this?

I have a page (A) displaying a form with a textarea field using a WYSIWYG interface.
The user will enter a list of unordered items and upon submit the string will look something like this:

This is my list of food items:
 <ul>
  <li> Lettuce </li>
  <li> Tomatoes </li>
  <li> Eggs </li>
 <ul>




Upon submit, I need to give each list item an unique id and store this id along with the text next to it in a separate table:

List_item_id   List_item_text  List_item_state
food_1             Lettuce
food_2             Tomatoes
food_3             Eggs





The user will then land in another page with a form displaying the list. The text is now in the page itself and not in a textarea.
Instead of the bullets a dropdown list appears, and the user can select "buy" or "sell" for each list item. 
This page (B) looks something like this:

<form>
This is my list of food items:
  <br><select name="food_1">
   <option value="buy">Buy</option>
   <option value="sell">Sell</option>
  </select>
  Lettuce

  <br><select name="food_2">
   <option value="buy">Buy</option>
   <option value="sell">Sell</option>
  </select>
  Tomatoes

  <br><select name="food_2">
   <option value="buy">Buy</option>
   <option value="sell">Sell</option>
  </select>
  Eggs

<input type=submit value="submit">
</form>




When the user hits "submit" the table with the list items will be updated with the values selected in the dropdown list:

List_item_id   List_item_text  List_item_state
food_1             Lettuce        Buy
food_2             Tomatoes       Buy
food_3             Eggs           Sell



The next time the user goes to Page B the list will remember the states.


Here's the curveball: At any point the user may click on "EDIT LIST" on Page B so they may add more items (at the begining, middle or end of the string). On edit mode the list items should appear as bullets again inside the WYSIWYG interface.

Keep in mind that some of the text in the string may not be a list item (ie, "this is my list of food...")

Im trying to create a website where users login, and then when they add a new entry to the database there name is put as the author. This is how my tables are set up. One table is named job and has the columns id, jobtext, jobdate, and authorid. Another table is called author. This table contains the columns id, username, password, and name. Authorid from the job table matches with id from the author table. When a user logins in this code is used to register the name...session_start();
$_SESSION['myusername'] = $_POST['myusername'];
$_SESSION['mypassword'] = $_POST['mypassword'];
header("location: index.php");
}
else {
echo "Wrong Username or Password";
}

This is the form users use to add a new entry...
if (isset($_GET['add']))
{
$pagetitle = 'New Job';
$action = 'addform';
$text = '';
$authorid = '';
$id = '';
$button = 'Add job';

include $_SERVER['DOCUMENT_ROOT'] . '/jobs/includes/db.inc.php';

// Build the list of authors
$sql = "SELECT id, name FROM author";
$result = mysqli_query($link, $sql);
if (!$result)
{
$error = 'Error fetching list of authors.';
include 'error.html.php';
exit();
}

while ($row = mysqli_fetch_array($result))
{
$authors[] = array('id' => $row['id'], 'name' => $row['name']);
}

// Build the list of categories
$sql = "SELECT id, name FROM category";
$result = mysqli_query($link, $sql);
if (!$result)
{
$error = 'Error fetching list of categories.';
include 'error.html.php';
exit();
}

while ($row = mysqli_fetch_array($result))
{
$categories[] = array(
'id' => $row['id'],
'name' => $row['name'],
'selected' => FALSE);
}

include 'form.html.php';
exit();
}

if (isset($_GET['addform']))
{
include $_SERVER['DOCUMENT_ROOT'] . '/includes/db.inc.php';

$text = mysqli_real_escape_string($link, $_POST['text']);
$author = mysqli_real_escape_string($link, $_POST['author']);

if ($author == '')
{
$error = 'You must choose an author for this job.
Click &lsquo;back&rsquo; and try again.';
include 'error.html.php';
exit();
}

$sql = "INSERT INTO job SET
jobtext='$text',
jobdate=CURDATE(),
authorid='$author'";
if (!mysqli_query($link, $sql))
{
$error = 'Error adding submitted job.';
include 'error.html.php';
exit();
}

$jobid = mysqli_insert_id($link);

if (isset($_POST['categories']))
{
foreach ($_POST['categories'] as $category)
{
$categoryid = mysqli_real_escape_string($link, $category);
$sql = "INSERT INTO jobcategory SET
jobid='$jobid',
categoryid='$categoryid'";
if (!mysqli_query($link, $sql))
{
$error = 'Error inserting job into selected category.';
include 'error.html.php';
exit();
}
}
}

header('Location: .');
exit();
}


Form.html.php =
<?php include_once $_SERVER['DOCUMENT_ROOT'] .
'/includes/helpers.inc.php'; ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<title><?php htmlout($pagetitle); ?></title>
<meta http-equiv="content-type"
content="text/html; charset=utf-8"/>
<style type="text/css">
textarea {
display: block;
width: 100%;
}
</style>
</head>
<body>
<?php session_start(); ?>

<h1><?php htmlout($pagetitle); ?></h1>
<form action="?<?php htmlout($action); ?>" method="post">
<div>
<label for="text">Type your job he </label>
<textarea id="text" name="text" rows="3" cols="40"><?php
htmlout($text); ?></textarea>
</div>
<div>
<label for="author">Author:</label>
<select name="author" id="author">
<option value="">Select one</option>
<?php foreach ($authors as $author):?>
<option value="<?php htmlout($author['id']); ?>"<?php
if ($author['id'] == $authorid)
echo ' selected="selected"';
?>><?php htmlout($author['name']); ?></option>
<?php endforeach; ?>
</select>
</div>
<fieldset>
<legend>Categories:</legend>
<?php foreach ($categories as $category): ?>
<div><label for="category<?php htmlout($category['id']);
?>"><input type="checkbox" name="categories[]"
id="category<?php htmlout($category['id']); ?>"
value="<?php htmlout($category['id']); ?>"<?php
if ($category['selected'])
{
echo ' checked="checked"';
}
?>/><?php htmlout($category['name']); ?></label></div>
<?php endforeach; ?>
</fieldset>
<div>
<input type="hidden" name="id" value="<?php
htmlout($id); ?>"/>
<input type="submit" value="<?php htmlout($button); ?>"/>
</div>
</form>
</body>
</html>


Right now, under authors, it displays all the authors in the database. I want it to just show/submit the authorid of the logged in user.

I posted this on stackoverflow, but no one wanted to touch it.   http://stackoverflow...rse-new-entries   I've tried array_push, but the results remain as SimpleXML, and not a plain array, which I wasn't able to use.  I tried some other things that I can't remember.

$feed_url = 'http://feeds.feedburner.com/SlickdealsnetFP?format=xml';
$contents = file_get_contents($feed_url);
$x = new SimpleXMLElement($contents);

$arrayFPTitle=array();

foreach($x->channel->item as $temp){
	array_push($arrayFPTitle, $temp->title);
}

Have any suggestions?... I've been on this problem for a few hours, now. I even tried regex, but you can imagine I quickly realized I wasn't going to figure that out.
Edited by icor1031, 18 September 2014 - 01:35 AM.

Maybe some of the great coders here can help this noob out.
So here is what I have so far:

Code: [Select]
//set age criteria for deletion
$age = 60;

//get current date
$datenow  = date("Y-m-d");

//set the range we want to delete
$delete_range = $datenow - $age;

//get old user_id from users table
$oldusers_users = mysql_query ("SELECT user_id FROM users WHERE lastvisit < $delete_range ");

//get user_id from images table that correspond to users table
$oldusers_images = mysql_query ("SELECT user_id FROM images WHERE $oldusers_users=user_id.images ");

//find folders that correspond to the usernames and delete
$oldusers_files = mysql_query ("SELECT username FROM users WHERE lastvisit < $delete_range ");
//print out username
//$result = mysql_($oldusers_files);
$foldername = mysql_result($oldusers_files, 0);

$sigspath = "sigs/";
unlink($sigspath . $foldername . ".gif/index.php");
rmdir($sigspath . $foldername . ".gif");
//now delete user_id's from database
mysql_query("DELETE * FROM users WHERE user_id=$oldusers_users");
mysql_query("DELETE * FROM images WHERE user_id=$oldusers_images");
unset($oldusers_users, $oldusers_images, $oldusers_files, $foldername, $sigspath );
mysql_close($link);
Right now it is only returning the first entry, not the entire list that meets the criteria.  It does delete that one file though but does not remover the rows from the database.

I am sure the database stuff is jacked up I am really new to that part.  What am I doing wrong here or is there a better way to do this perhaps

I have a standard form that displays users current data from a mysql database once logged in(code obtained from the internet). Users can then edit their data then submit it to page called editform.php that does the update. All works well except that the page does not display the updated info. Users have to first logout and login again to see the updated info. even refreshing the page does not show the new info. Please tell me where the problem is as i am new to php.   my form page test.php

<?PHP
require_once("./include/membersite_config.php");

if(!$fgmembersite->CheckLogin())
{
    $fgmembersite->RedirectToURL("login.php");
    exit;
}

?>
<form action="editform.php?id_user=<?= $fgmembersite->UserId() ?>" method="POST">
<input type="hidden" name="id_user" value="<?= $fgmembersite->UserId() ?>"><br>
Name:<br> <input type="text" name="name" size="40" value="<?= $fgmembersite->UserFullName() ?>"><br><br>
Email:<br> <input type="text" name="email" size="40" value="<?= $fgmembersite->UserEmail() ?>  "><br><br>
Address:<br> <input type="text" name="address" size="40" value="<?= $fgmembersite->UserAddress() ?>  "><br><br>

<button>Submit</button>

my editform.php

<?php

$con = mysqli_connect("localhost","root","user","pass");

if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

mysqli_query($con,"UPDATE fgusers3 SET name = '".$_POST['name']."', email= '".$_POST['email']."', address= '".$_POST['address']."' WHERE id_user='".$_POST['id_user']."'");



header("Location: test.php");

?>

Hey guys.. I've been setting up a database for a contact page and I have everything working for it except the following error on my update contact page.. can anyone help me figure it out?? The error lines are the ones where I have my mysql_result's.

Errors:

No Records Found

Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 3 in /home/jonnyp22/public_html/a5/update_contact.php on line 103

Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 3 in /home/jonnyp22/public_html/a5/update_contact.php on line 104

Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 3 in /home/jonnyp22/public_html/a5/update_contact.php on line 105

Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 3 in /home/jonnyp22/public_html/a5/update_contact.php on line 106

Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 3 in /home/jonnyp22/public_html/a5/update_contact.php on line 107

Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 3 in /home/jonnyp22/public_html/a5/update_contact.php on line 108

Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 3 in /home/jonnyp22/public_html/a5/update_contact.php on line 109

Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 3 in /home/jonnyp22/public_html/a5/update_contact.php on line 110

Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 3 in /home/jonnyp22/public_html/a5/update_contact.php on line 111

Code: [Select]
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">

<head>
<meta content="text/html; charset=utf-8" http-equiv="Content-Type" />
<title>Update Contact</title>
<script  type="text/javascript">
function Validateform(){
var email=document.form1.email;
var firstname=document.form1.firstname;
var lastname=document.form1.lastname;
var state=document.form1.state;

var reEmail = /^(?:\w+\.?)*\w+@(?:\w+\.)*\w+$/;

if ((email.value==null)||(email.value=="")){
alert("Please enter email address");
email.focus();
return false;
}
if (reEmail.test(email.value)==false){
  alert ("Please enter valid email address");
    email.focus();
    return false;
    }
if ((firstname.value=="")||(firstname.value==null)) {
alert("Please enter first name");
firstname.focus();
return false;
}

if ((lastname.value=="")||(lastname.value==null)) {
alert("Please enter last name");
lastname.focus();
return false;
}
if (state.selectedIndex==0) {
alert("Select state");
state.focus();
return false;
}
return true;
 }

</script>

<style type="text/css">
.style1 {
text-align: center;
color: #F8B57E;
font-size: x-large;
}
.style2 {
text-align: center;
}
.style3 {
text-align: right;
color: #F8B57E;
}
.style4 {
text-align: left;
}
.style6 {
text-align: center;
color: #F8B57E;
font-size: medium;
}
.style7 {
color: #FFFFFF;
}
</style>
</head>

<body style="color: #FFFFFF; background-color: #102541">

<div class="style2">

<p class="style1"><strong>Update Contact</strong></p>
<p class="style6">* Indicates a Required Field</p>

<?php

include("dl.php");

// If the form has not been submitted then show it

if(!$_POST['Submit'])
{

$email=$_GET['email'];

$query="SELECT * FROM person WHERE Email = '$email'";
$result=mysql_query($query) or die('Error: ' . mysql_error());

$num=mysql_numrows($result);

mysql_close();

if ($num == 0) {
echo "<b><center>No Records Found</center></b>";
}

$lastname=mysql_result($result,0,"Last_Name");
$email=mysql_result($result,0,"Email");
$firstname=mysql_result($result,0,"First_Name");
$address1=mysql_result($result,0,"address1");
$address2=mysql_result($result,0,"address2");
$city=mysql_result($result,0,"city");
$state=mysql_result($result,0,"state");
$zip=mysql_result($result,0,"zip");
$phone=mysql_result($result,0,"phone");

?>

<form action="<?=$_SERVER['PHP_SELF']?>" method="post">
<table style="width: 100%">
<tr>
<td style="width: 219px; height: 26px" valign="top" class="style3">E-mail Address:</td>
<td style="height: 26px" class="style4">
<input name="email" style="width: 363px" type="text" value="<? echo $email; ?>" readonly="readonly" />
</td>
</tr>
<tr><td class="style3">First Name:</td><td class="style4"><input type="text" name="firstname" id="firstname" size="30" width="250px" value="<? echo $firstname; ?>"/></td></tr>
    <tr>
<td class="style3" >Last Name:</td><td class="style4" ><input name="lastname" id="lastname" type="text"  size="30" width="250px" value="<? echo $lastname; ?>"/></td>
</tr>
    <tr><td class="style3">Phone:</td><td class="style4"><input type="text" name="phone" id="phone" size="15" width="250px" value="<? echo $phone; ?>"/></td></tr>
    <tr>
      <td class="style3">Address Line 1:</td><td class="style4"><input type="text" name="address1" id="address1" size="50" width="250px" value="<? echo $address1; ?>" /></td></tr>
    <tr>
      <td class="style3">Address Line 2:</td><td class="style4"><input type="text" name="address2" id="address2" size="50" width="250px" value="<? echo $address2; ?>"/></td></tr>
    <tr><td class="style3">City:</td><td class="style4"><input type="text" name="city" id="city" size="50"  width="250px" value="<? echo $city; ?>"/></td></tr>
    <tr><td class="style3">State:</td><td class="style4"><select name="state" id="state">
   
<option <? if ($state=="NJ") echo selected ;?> >NJ</option>
<option <? if ($state=="NY") echo selected ;?> >NY</option>

</select></td></tr>
    <tr><td class="style3">Zip:</td><td class="style4"><input type="text" name="zip" id="zip" size="5" value="<? echo $zip; ?>"/></td></tr>
</table>
<p class="style2"><input name="Submit" type="submit" value="Update" />&nbsp;<a href="show_contacts.php"><span class="style7">Show Contacts</span></a>
<br />
</p>
</form>

<?php

}
else
{

// The form has been submitted so process it

$email=$_POST['email'];
$lastname=$_POST['lastname'];
$firstname=$_POST['firstname'];
$phone=$_POST['phone'];
$address1=$_POST['address1'];
$address2=$_POST['address2'];
$city=$_POST['city'];
$state=$_POST['state'];
$zip=$_POST['zip'];

$query="UPDATE person SET Last_Name='$lastname',FIRST_Name='$firstname',Phone='$phone', Address1='$address1', Address2='$address2', city='$city', state='$state',zip='$zip' WHERE Email='$email'";

if (!mysql_query($query,$con))
  {
   die('Error: ' . mysql_error());
  }
else {
echo "<center><b> Contact info $lastname updated successfully </b><a href='show_contacts.php'>show contacts</a></center>";
}

mysql_close();

}
?>
</div>
</body>

</html>

Hi

Just want some advice on how to do the below:

I already have one table called 'venopt' which has two fields one is 'id' and 'venues'

I also already have a table for members details called 'ptdata' and has 'id' 'firstname' and 'surname' etc

Both ids in each table are primary keys and autoincremented.

The user will be selecting options from the 'venues' table and submitting them via POST.

How should i then handle the data, is it best to setup another table which will store the selections and if so how would i go about that?

Or is it best to store the details in an array say in the 'ptdata' table.

Either way I would also want to retrieve the contents of the array and display it in another drop down list?

Any ideas

quick question... I have a column in my table called views. I want to reset the column to 0 for each row in the table. What's the easiest way to do this?

I created a database class to connect to a database.  The code is below.  I'm not sure how to call this connection in other classes.  Do I use:

$db->pdo = $conn->prepare($sql);

or what?  Note that the db object is instantiated at the end of the class file.  Here is the class:

 

class DB {
	
	public $pdo = '';
	//public $message = 'A message from db'; // Debug

function __construct() {
	
	// Database info located elsewhere
	$servername = "localhost";
	$username = "root";
	$password = "";
	$dbname = "dbname";
	
	try {
		
	  $this->pdo = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
	  // set the PDO error mode to exception
	  $this->pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

	}  // End Try
	
	catch(PDOException $e) {
		  echo "Error: " . $e->getMessage();
		}
		
		//echo '<h3>Everything wnet OK.</h3>';  // Debug

	} // End __construct
	
} // End class definition DB.php

$db = new DB;

Thanks,

 

--Kenoli

hello.

i have a question for you.

say i have a group of tick boxes and i select a couple.

would i put them in to the database as varchar ?
like this:

id   varchar
1    1, 2, 3

or

id   varchar
1    '1', '2', '3'


then my next question is how would i use them.
i guess i would explode them or something.

the thing is, i have some code that currently pull 1 item from the database (using varchar) and echos it fine but when i add more i get nothing back.

thanks
rick

I have code for displaying result from database:

foreach ($_SESSION["products"] as $cart_itm)
        {
           $product_code = $cart_itm["code"];
		   $results = $mysqli->query("SELECT * FROM products WHERE product_code='$product_code' LIMIT 1");
		   $obj = $results->fetch_object(); 

Now, I display data with: $obj->product_name     When I get the list, how to put inline numbers (1 2 3 4 ...)?   1       products1 2       products1 3       products1 4       products1..