PHP - Php And Html In Same Script

Hi guys, sorry for such a newbish question.  Any help would be greatly appreciated.

HTML FORM:
Code: [Select]
<form action="form.php" method="post" onsubmit="return validateForm()" name="form">
<b>First Name:*</b>
<input type="text" name="first_name" size="50" />
<b>Last Name:*</b>
<input type="text" name="last_name" size="50" />
<b>Phone:*</b>
<input type="text" name="phone" size="50" />
<b>Email:*</b>
<input type="text" name="email" size="50" />
<p><b>What is your favorite color?*</b></p>
<p align="left">
<select name="se">
<option value="W">White</option>
<option value="G">Green</option>
<option value="Y">Yellow</option>
</select>
<input type="submit" value="Submit"/>
</form>


FORM.PHP script
Code: [Select]
<?php
$se = $_POST['se'];
$seURL = '';
switch ($se) {
  case 'W':
    $seURL = "http://url1.com";
    break;
  case 'G':
    $seURL = "http://url2.com";
    break;
  case 'O':
    $seURL = "http://url3.com";
    break;
  default:
    $seURL = "";
}
if ($seURL != "") {
/* Redirect browser */
/* make sure nothing is output to the page before this statement */
header("Location: " . $seURL);
}

// get posted data into local variables
$EmailFrom = "noreply@domain.com";                           
$EmailTo = "email@domain.com";                       
$Subject = "Form";                                         
$first_name = Trim(stripslashes($_POST['first_name'])); 
$last_name = Trim(stripslashes($_POST['last_name'])); 
$phone = Trim(stripslashes($_POST['phone'])); 
$email = Trim(stripslashes($_POST['email'])); 

// validation
$validationOK=true;
if (!$validationOK) {
  print "<meta http-equiv=\"refresh\" content=\"0;URL=error.htm\">";
  exit;
}

// prepare email body text
$Body = "";
$Body .= "first_name: ";
$Body .= $first_name;
$Body .= "\n";
$Body .= "last_name: ";
$Body .= $last_name;
$Body .= "\n";
$Body .= "phone: ";
$Body .= $phone;
$Body .= "\n";
$Body .= "email: ";
$Body .= $email;
$Body .= "\n";
$Body .= "color: ";
$Body .= $se;
$Body .= "\n";

// send email 
$success = mail($EmailTo, $Subject, $Body, "From: <$EmailFrom>");

// send email to user
if ($se=="W")
$EmailFrom = "noreply@domain.com";
$to = $email;
$subject = "form email";
$body = "thank you for filling out our form";
if (mail($to, $subject, $body, "From: <$EmailFrom>")) {
  echo("<p>Message successfully sent!</p>");
} else {
  echo("<p>Message delivery failed...</p>");
}

?>
[code]


MOD EDIT: [nobbc][code] . . . [/code][/nobbc] tags added . . .

Here is the code that i am using to accept data and display the data.

To accept and add it in database i am using :

$comment = $_POST['txtcomment'];
$comment = @mysql_real_escape_string($comment);


To display the data from DB i am using :

$comment = $rowscomment['comment'];
<?php echo nl2br($comment); ?>


Please help me correct it....... I am still learning PHP.

Hello all, I'm new to PHP and to these forums and i'm having trouble with a little script I'm working on.

I have to point out at the start that the script actually works, other than for the error I'm reporting.

What it does, is lets the user upload an image to the server and creates a thumbnail imageof it in another folder. This works as intended. (I.e. the images gets uploaded and the thumbnail is created) The issue i'm having is when the work is completed successfully...

If there's an error, I update a variable $msg with an error mesage. (File too large, or invalid filetype) If this is the case, the script will render the html code correctly, display the error, then redirect you using javascript after 4 seconds to the original page.

No worries here, everything works so far.

However, if there is no errors to report and the script is successfull, I update $msg to say "it worked"(or whatever) but instead of displaying the formatted webpage displaying the message, then redirecting after 4 seconds, all that happens is the html code is displayed instead.

(If I cut and paste this code into a new htmlfile, it renders correctly.)

Attached below is the php code which does all the work. (But not the main php file which calls it)

Can someone please point me in the right direction as to what I'm doing wrong! lol

(Again, I'm new here so a big hello from me!!!)

Code: [Select]
<?php
   print( "<html>\n");
   print( "   <head>\n");
   print( "      <title>Random banner and file upload</title>\n");
   print( "      <link rel=StyleSheet href=\"styles.css\" type=\"text/css\">\n");
   print( "   </head>\n");
   print( "   <body>\n" );
   
   $file_upload = "true";
   $filetype = $_FILES[ "file_up" ][ "type" ];
   $file_name = $_FILES[ "file_up" ][ "name" ];
   $startimage = $_FILES[ "file_up" ][ "tmp_name" ];
   $largeimage = "images/uploads/$file_name";
   $thumbimage = "images/uploadthumbs/thumb-$file_name";
   $msg = "      ";
   $invalidfilesize = "<p class='centeralign'>Your uploaded file size is more than 250KB so please reduce the file size and then upload.<br>Visit the help page to know how to reduce the file size.</p>\n";
   $invalidfiletype = "<p class='centeralign'>Your uploaded file must be of PNG, JPG or GIF. Other file types are not allowed.</p>\n";
   $successfullupload = "<p class='centeralign'>File uploaded successfully! :)</p>\n";   
   $failedupload = "<p class='centeralign'>File not uploaded successfully! :(</p>\n";   
   $notinstalled = "<p class='centeralign'>The requested function is not installed on this web server. :(</p>\n";
     
   //If the image is larger than 1Mb, do not upload.
   if ( $_FILES[ "file_up" ][ "size" ] > 1048576 )
   {
      $msg = $msg.$invalidfilesize;
      $file_upload="false";
   }
   
   //If the image is an invalid file type, do not upload.
   if ( ! ( $filetype == "image/x-png" || $filetype == "image/pjpeg"  || $filetype == "image/jpeg" || $filetype == "image/gif" ) )
   {
      $msg = $msg.$invalidfiletype;
      $file_upload = "false";
   }

   //Start the thumbnail generation.
   if( $file_upload == "true" )
   {
      $n_width = 160; // Fix the width of the thumbnail images
      $n_height = 120; // Fix the height of the thumbnail imaage
      
      switch ( $filetype )
      {
     case "image/x-png";
        $FromFormat = "ImageCreateFromPNG";
    $ToFormat = "ImagePNG";
break;
 case "image/jpeg";
        $FromFormat = "ImageCreateFromJPEG";
    $ToFormat = "ImageJPEG";
break;
 case "image/pjpeg";
        $FromFormat = "ImageCreateFromJPEG";
    $ToFormat = "ImageJPEG";
break;
         case "image/gif";
        $FromFormat = "ImageCreateFromGIF";
    $ToFormat = "ImageGIF";
break;
      }
  
      if ( function_exists( "$FromFormat" ) )// Generate the thumbnail.
      {            
         $im = $FromFormat( $startimage );
         $width = ImageSx( $im ); // Original picture width is stored
         $height = ImageSy( $im ); // Original picture height is stored
         $newimage = imagecreatetruecolor( $n_width, $n_height );
         imageCopyResized( $newimage, $im, 0, 0, 0, 0, $n_width, $n_height, $width, $height );
         Header( "Content-type: $filetype" );
         $ToFormat( $newimage, $thumbimage );
      }
  else { $msg = $msg.$notinstalled; }// Unable to generate the thumbnail. (GD library not installed on web server?)

      //Move the uploaded file to the correct place..
      if( move_uploaded_file ( $startimage, $largeimage ) ) { $msg = $msg.$successfullupload; }
      else { $msg = $msg.$failedupload; }//Unable to move uploaded file.
   }
   Print( "$msg" );   
   print( "      <script type=\"text/javascript\"><!--\n" );
   print( "         setTimeout('Redirect()',4000);\n" );
   print( "         function Redirect()\n" );
   print( "         {\n" );
   print( "            location.href = 'index.php';\n" );
   print( "         }// -->\n" );
   print( "      </script>\n" );   
   print( "   </body>\n" );
   print( "</html>\n" );
?>

I have a page that shows entries in a guestbook I'm making, and below the entries there is supposed to be a form to write an entry. Except, none of the HTML after the script to show the entries shows up on the page. I have no clue what's wrong. 

Here is the script to show the entries. $n is name, $d is date, $s is site (optional), and $m is message.
$file = fopen("posts.txt", 'rb');
flock($file, LOCK_SH);

while(!feof($file)){

$entry = fgetcsv($file, 0, '|');

if(empty($entry)){exit;}

$d = $entry[1]; $n = $entry[2]; $s = $entry[3]; $m = $entry[4];

echo '
<table style="border: #3399AA 1px solid;"><tr style="background: #3399AA; font: bold 10px verdana,sans-serif; color: #FFFFFF;">
<td width="170">'.$n.'</td>
<td align="right" width="170">'.$d.'</td>
</tr>
';

if($s != 'none'){
echo '
<tr><td colspan="2" style="font: 10px verdana,sans-serif; color: #3399AA;">
<b>Site: </b><a href="'.$s.'">'.$s.'</a>
<center><div style="width: 250; height: 1px; background: #3399AA; margin: 10px;"></div></center></td></tr>
';
}

echo '
<tr>
<td colspan="2" style="font: 10px verdana,sans-serif; color: #3399AA;">'.$m.'</td>
</tr></table><br>
';

}

flock($file, LOCK_UN);
fclose($file);

The file it is reading looks like this:
Code: [Select]
|11:51 am, 3rd Nov 2010|Memoria|none|Hello. :)
|11:51 am, 3rd Nov 2010|Memoria|http://sitehere|Hello again.
|11:51 am, 3rd Nov 2010|Memoria|none|How are you doing?
Thanks! 

I found this site: http://www.wallpaperama.com/forums/how-to-save-html-output-code-from-php-script-t6898.html
it demonstrates how to save html output code from php script. here is an example: http://ads4agents.com/date.php

I cant get it to work on my site...where is the correct place ad these:
ob_start();

$HtmlCode= ob_get_contents();
ob_end_flush();


How can I get this to work in my php?

view_ad.php

<html>
<body>
<center>
<br/>
<h1>Apartment Reference #: <?php
echo $_POST["reference"]; ?><br /></h1>
<br/>
<?php echo $_POST["application"]; ?>, <?php echo $_POST["deposit"]; ?><br />
<?php echo $_POST["pets"]; ?><br />
<br/>
<?php echo $_POST["community"]; ?><br />
<?php echo $_POST["interior"]; ?><br />
<?php echo $_POST["amenities"]; ?><br />
<br/>
<?php echo $_POST["contact"]; ?><br />
<a href="<?php
echo $_POST['website'] ?>"><?php echo $_POST['website'];?></a><br/>
<br/>
<br/>
<br/>
</body>
</html>

I have a php string variable that is created by php code within an html form ($answer).
I need to pass this string variable along with all the html form input data to another php script specified with the form "action" (post method).

All the html form input data is coming thru fine but not the variable ($answer).

How do I do this?

Here is the php code for importing html form data at the script called in the form action:

 
$languages = $_POST['languages'];
$answergiven = $_POST['answergiven'];
$problemanswer = $_POST['$answer'];

'languages' and 'answergiven' are form inputs and come thru fine.
'$answer' does not get passed to the second script.


How do I do this?


Here is the php code within the first html form

<?php

// OPEN DATABASE

$username="servics3_sample";
$password="sample";
$database="servics3_sample";

mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");

// GENERATE RANDOM PROBLEM NUMBER

$probnum = (rand ( 1 , 9 ));

echo $probnum;

// RETRIEVE ANTI-SPAM PROBLEM

$query="SELECT * FROM liasantispam
WHERE `problem number` LIKE '%$probnum%'
";

$result=mysql_query($query) or die("Error: ". mysql_error(). " with query ". $query);

$firstnum=mysql_result($result,0,"first number");
$operator=mysql_result($result,0,"operator");
$secondnum=mysql_result($result,0,"second number");
$answer=mysql_result($result,0,"answer");

echo $firstnum," ",$operator," ",$secondnum," = ";

mysql_close();

?>

Hello,

I'm trying to take the value from an HTML form and insert it into a database on a button click. It inserts a null value into the database. The script is called submitColumnDetails.php.


This is where I create the text field that I want to take the information from. This is in a separate file.
Code: [Select]
echo <<<END
<form action = "submitColumnDetails.php" method = "POST">
<input type = "text" name = "columnField"/>
</form>
END;

This is the submitColumnDetails.php file

Code: [Select]

<?php
//Submit Column Data
//-----------------------------------------------------//
//Connect to localhost server
$connector = mysql_connect("localhost", "root", "root");
if(!$connector){ //If user can't connect to database
die('Could not connect: ' . mysql_error()); //Throw an error
}
//-----------------------------------------------------//

mysql_select_db("colin_db", $connector);

$newValue = $_POST["columnField"]; //Data from column field. THIS IS WHAT RETURNS NULL
$newColumnQuery = "INSERT INTO `colin_db`.`allColumnFields` (`DATA`) VALUES ('$newValue')";
mysql_query($newColumnQuery); //Query to add form to main table

$newColumnIntoMainTableQuery = "ALTER TABLE colin_table ADD ('$newValue' varchar(50))";
mysql_query($newColumnIntoMainTableQuery); //Query to add column to main table


mysql_close($connector); //Close database connection
echo "<script type = 'text/javascript'> window.location = 'index.php'</script>";
//Go back to original page
?>


Even when I print out the $newValue, it does not print anything. What am I doing incorrectly?

Hi,
I have made a basic html site and it has two forms on it. I have the forms linking to a file called process.php.
Basically i need to know what code to put in the php file in order for the forms to save whatever is entered in them to a txt file on my server or computer.
Or any other easier way to do the same thing, save the content of two forms on my site.
Hope i posted this in the right forum subject.
Thanks very much for anyone that helps.

Hi everyone!

I've been working on a php script to replace links that contain a query with direct links to the files they would redirect to.

I'm having trouble echoing $year in my script. Listed below is the script, just below ,$result = mysql_query("SELECT * FROM $dbname WHERE class LIKE '%$search%'") or die(mysql_error());, in the script I try to echo $year. It doesn't show up in the table on the webpage. Everything else works fine. Any help wold be appreciated greatly. Thanks in advance.



<?php
include 'config2.php';

$search=$_GET["search"];

// Connect to server and select database.
mysql_connect($dbhost, $dbuser, $dbpass)or die("cannot connect");
mysql_select_db("vetman")or die("cannot select DB");


$result = mysql_query("SELECT * FROM $dbname WHERE class LIKE '%$search%'") or die(mysql_error());
// store the record of the "" table into $row
//$current = '';
echo "<table align=center border=1>";
echo "<br>";
echo "<tr>";
echo "<td align=center>";
?>
<div style="float: center;"><a><h1><?php echo $year; ?></h1></a></div>


<?php
echo "</td>";
echo "</tr>";
echo "</table>";


// keeps getting the next row until there are no more to get
if($result && mysql_num_rows($result) > 0)

{
    $i = 0;
    $max_columns = 2;
    echo "<table align=center>";
echo "<br>";
    while($row = mysql_fetch_array($result))
   {
       // make the variables easy to deal with
       extract($row);

       // open row if counter is zero
       if($i == 0)

          echo "<tr>";

          echo "<td align=center>";
          ?>
          <div style="float: left;">
          <div><img src="<?php echo $image1; ?>"></div>

  </div>


          <?php
          echo "</td>";

       // increment counter - if counter = max columns, reset counter and close row
       if(++$i == $max_columns)
       {
           echo "</tr>";
           $i=0;
       }  // end if
   } // end while
} // end if results

// clean up table - makes your code valid!
if($i > 0)
{
    for($j=$i; $j<$max_columns;$j++)
        echo "<td>&nbsp;</td>";
   echo '</tr>';
}
mysql_close();
 ?>
</table>

Hi i have this upload script which works fine it uploads image to a specified folder and sends the the details to the database.
but now i am trying to instead make a modify script which is Update set so i tried to change insert to update but didnt work can someone help me out please
this my insert image script which works fine but want to change to modify instead
Code: [Select]
<?php
mysql_connect("localhost", "root", "") or die(mysql_error()) ;
mysql_select_db("upload") or die(mysql_error()) ;

// my file the name of the input area on the form type is the extension of the file
//echo $_FILES["myfile"]["type"];

//myfile is the name of the input area on the form 
$name = $_FILES["image"] ["name"]; // name of the file
$type = $_FILES["image"]["type"]; //type of the file
$size = $_FILES["image"]["size"]; //the size of the file
$temp = $_FILES["image"]["tmp_name"];//temporary file location when click upload it temporary stores on the computer and gives it a temporary name
$error =array(); // this an empty array where you can then call on all of the error messages
$allowed_exts = array('jpg', 'jpeg', 'png', 'gif'); // array with the following extension name values
$image_type = array('image/jpg', 'image/jpeg', 'image/png', 'image/gif'); // array with the following image type values
$location = 'images/'; //location of the file or directory where the file will be stored
$appendic_name = "news".$name;//this append the word [news] before the name so the image would be news[nameofimage].gif

// substr counts the number of carachters and then you the specify how how many you letters you want to cut off from the beginning of the word example drivers.jpg it would cut off dri, and would display vers.jpg
//echo $extension = substr($name, 3);

//using both substr and strpos, strpos it will delete anything before the dot in this case it finds the dot on the $name file deletes and + 1 says read after the last letter you delete because you want to display the letters after the dot. if remove the +1 it will display .gif which what we want is just gif
$extension = strtolower(substr($name, strpos ($name, '.') +1));//strlower turn the extension non capital in case extension is capital example JPG will strtolower will make jpg
// another way of doing is with explode
// $image_ext strtolower(end(explode('.',$name))); will explode from where you want in this case from the dot adn end will display from the end after the explode

$myfile = $_POST["myfile"];

     if (isset($image)) // if you choose a file name do the if bellow
       {
       
       // if extension is not equal to any of the variables in the array $allowed_exts error appears
        if(in_array($extension, $allowed_exts) === false )
       {
         $error[] = 'Extension not allowed! gif, jpg, jpeg, png only<br />'; // if no errror read next if line
       }
        // if file type is not equal to any of the variables in array $image_type error appears
        if(in_array($type, $image_type) === false)
       {
          $error[] = 'Type of file not allowed! only images allowed<br />';     
       }
       
        // if file bigger than the number bellow error message
        if($size > 2097152)
       {
          $error[] = 'File size must be under 2MB!';     
       }
       
       // check if  folder exist in the server
        if(!file_exists ($location))
       {
          $error[] = 'No directory ' . $location. ' on the server Please create a folder ' .$location;     
       }
            
     }
     // if no error found do the move upload function
       if (empty($error)){
           if (move_uploaded_file($temp, $location .$appendic_name))
           {
             // insert data into database first are the field name teh values are the variables you want to insert into those fields appendic is the new name of the image
mysql_query("INSERT INTO image (myfile ,image)
 VALUES ('$myfile', '$appendic_name')") ;
           exit();
           }
         }
       else
          {
        foreach ($error as $error)
           {
               echo $error;
           }
        }
      
     
  
//echo $type;
?>

I'm trying to use this script known as SimpleImage.php that can be found here <a href="http://www.white-hat-web-design.co.uk/articles/php-image-resizing.php">link</a> I'm trying to include what is on the bottom of the page to my existing script can anyone help me I've tried several ways but its not working.
Code: [Select]
<?php 
session_start();
error_reporting(E_ALL);
ini_set('display_errors','On');

//error_reporting(E_ALL); 


// image upload folder
    $image_folder = 'images/classified/'; 
// fieldnames in form
$all_file_fields = array('image1', 'image2' ,'image3', 'image4');
// allowed filetypes
$file_types = array('jpg','gif','png');
// max filesize 5mb
$max_size = 5000000;
//echo'<pre>';print_r($_FILES);exit;

$time = time();
$count = 1;

foreach($all_file_fields as $fieldname){ 
if($_FILES[$fieldname]['name'] != ''){

$type = substr($_FILES[$fieldname]['name'], -3, 3);

// check filetype
if(in_array(strtolower($type), $file_types)){

//check filesize
if($_FILES[$fieldname]['size']>$max_size){
$error = "File too big. Max filesize is ".$max_size." MB";

}else{

// new filename
$filename = str_replace(' ','',$myusername).'_'.$time.'_'.$count.'.'.$type;

// move/upload file
$target_path = $image_folder.basename($filename);
move_uploaded_file($_FILES[$fieldname]['tmp_name'], $target_path);

//save array with filenames
$images[$count] = $image_folder.$filename;
$count = $count+1;

}//end if

}else{ $error = "Please use jpg, gif, png files";

}//end if
}//end if
}//end foreach



if($error != ''){ echo $error;
}else{


/* --------------------------------------------------------------------------------------------------
SAVE TO DATABASE ------------------------------------------------------------------------------------
-------------------------------------------------------------------------------------------------- */
?>

hey guys im really just after a bit of help/information on 2 things (hope its in the right forum).   1. basically I'm wanting to make payments from one account to another online...like paypal does...im wondering what I would need to do to be able to do this if anyone can shine some light please?   2.as seen on google you type in a query in the search bar and it generates sentences/keywords from a database   example:   so if product "chair" was in the database whilst typing "ch" it would show "chair" for a possible match   I know it would in tale sql & json but im after a good tutorial/script of some sort.   if anyone can help with some information/sites it would be much appreciated.   Thank you

Hello,

I stored a fsockopen function in a separate "called.php" file, in order to run it as another thread when it needs.
The called script should return results to the "master.php" script.
I'm able to run the script to get the socket working, and I'm able to get results from the called script. I tried for hours but I can't do the twice both 

My master.php script (with socket working):

Code: [Select]
<?php
$command = "(/mnt/opt/www/called.php $_SERVER[REMOTE_ADDR] &) > /dev/null";
$result = exec($command);
echo ("result = $result\r\n");
?>

and my called.php script
Code: [Select]
#!/mnt/opt/usr/bin/php-cli -q
<?php
$device = $_SERVER['argv'][1];
$port = "8080";
$fp = fsockopen($device, $port, $errno, $errstr, 5);
fwrite($fp, "test");
fclose($fp);
echo ("normal end of the called.php script");
?>

In the master script, if I use
Code: [Select]
$command = "(/mnt/opt/www/called.php $_SERVER[REMOTE_ADDR] &) > /dev/null";
the socket works, but I have nothing in $result
(note also that I don't anderstand why the ( ... &) are needed!?)

and if I use
Code: [Select]
$command = "/mnt/opt/www/called.php $_SERVER[REMOTE_ADDR]";
I have the correct text "normal end of the called.php script" in $result but the socket connection is not performed (no errors in php logs)

Could you help me to find a way to let's work the two features correctly together?
Thank you.