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PHP - Php Longtext In Mysql - Cannot Get All Text
I have a MySQL Longtext field. When I query the data using PHP, I cannot get all of the text. If there are 1000 characters, I only get about half. Does this have anything to do with packet-size? Is this a configuration thing? Similar Tutorialsi have a with my script I made a basic messaging service for my website. I have a form with a textarea as an input variable. It inserts the textarea value to a database using a php script upon form submission. The SQL field is set as longtext so the user can insert a large text string. There's a few things i need to do to perfect it. I need to make it so the user can only insert text characters, so not to allow script manipulation; and I need to figure out why it's deleting my intro message when changing the `read` field from `unread` to `read`. The `messages` SQL table is separated into 6 fields: to, from, message, read, subject, and number. when the user reads a message, i have a php script that reads as follows: <?php include("include/session.php"); function curPageName() { return substr($_SERVER["SCRIPT_NAME"],strrpos($_SERVER["SCRIPT_NAME"],"/")+1); } $pagename = curPageName(); $replaced2 = eregi_replace("message", "", $pagename); $number = eregi_replace(".php", "", $replaced2); mysql_select_db("******_starcraft") or die(mysql_error()) ; $query = " SELECT * FROM `messages` WHERE number='$number' "; $result = mysql_query($query); $info = mysql_fetch_array ( $result ); $to = $info['to']; $from = $info['from']; $subject = $info['subject']; $message = $info['message']; $read = $info['read']; mysql_query("DELETE FROM `messages` WHERE `number`='$number'") ; mysql_query("INSERT INTO `messages` VALUES ('$to', '$from', '$message', 'read', '$subject', '$number')") ; ?> Now, after trouble shooting, i found that the problem is occuring when it tries to insert the $message string into the third field of the `messages` table. I find this strange because when you send the message to this user using the "compose message" script, the input variable is inserted into the database table without a stitch. Is there something i'm missing? i feel like it's on the tip of my tounge... thanks in advance, -dan
create table mimi (mimiId int(11) not null, mimiBody varchar(255) );
<?php
//connecting to database
include_once ('conn.php');
$sql ="SELECT mimiId, mimiBody FROM mimi";
$result = mysqli_query($conn, $sql );
$mimi = mysqli_fetch_assoc($result);
$mimiId ='<span>No: '.$mimi['mimiId'].'</span>';
$mimiBody ='<p class="leading text-justify">'.$mimi['mimiBody'].'</p>';
?>
//what is next?
i want to download pdf or text document after clicking button or link how to do that hello world! First post here! I'm a newbie trying to make my own cms, everything is working except the import of image into the post, this becomes text. Here is the code: Code: [Select] function connect() { $con = mysql_connect($this->host, $this->username, $this->password) or die (mysql_error()); mysql_select_db ($this->db, $con) or die (mysql_error()); } function get_content($id = '') { if($id != ""): $id = mysql_real_escape_string($id); $sql = "SELECT * FROM cms_content WHERE id = '$id'"; else: $sql = "SELECT * FROM cms_content ORDER BY id DESC"; endif; $return = '<a href="index.php">go back</a>'; $res = mysql_query($sql) or die(mysql_error()); if(mysql_num_rows($res) != 0): while($row = mysql_fetch_assoc($res)) { echo '<div class="title"><h1><a href="index.php?id=' . $row['id'] . '">' . $row['title'] . '</a></h1></div>'; echo '<div class="date"><p>' . $row['date'] . '</p></div>'; echo '<div class="photo"><p>' . $row['photo'] . '</p></div>'; echo '<div class="txt"><p>' . $row['body'] . '</p></div>'; } else: echo '<p class="results_">uH oh!</p>'; endif; echo $return; } function add_content($p) { $title = mysql_real_escape_string($p['title']); $date = mysql_real_escape_string($p['date']); $photo = mysql_real_escape_string($p['photo']); $body = mysql_real_escape_string($p['body']); // if they write wrong if(!$title | | !$body): if(!$title): echo "<p>The Title is Required</p>"; endif; if(!$photo): echo "<p>No photo</p>"; endif; if(!$body): echo "<p>The body is Required</p>"; endif; echo '<p><a href="add-content.php">Try again</a></p>'; else: // add to db $sql = "INSERT INTO cms_content VALUES (null, '$title', '$date', '$photo', '$body')"; $res = mysql_query($sql) or die(mysql_error()); echo "<p class='results_'>Added with success!</p>"; // [END] add to db endif; // [END] if they write wrong } and in the html i got a form Code: [Select] <form enctype="multipart/form-data" method="post" action="index.php"> <input type="hidden" name="add" value="true"> <div> <label for="title"><p>Title:</p></label> <input type="text" name="title" id="title" /> </div> <div> <input type="file" name="photo"><br> </div> <div> <label for="body"><p>Body:</p></label> <textarea name="body" id="body" rows="8" cols="40"></textarea> </div> <input type="submit" name="submit" value="Add Content"> </form> I am trying to add a txt file to a mysql database. Is there any one that can help? Here are the details TEST.TXT contains the following A001200910019999999900000200000000000000000000000 00000000000000000000000000 A002200910019999999900000610000000000000000000000 00000000000000000000000000 A003200910019999999900000687500000000000000000000 00000000000000000000000000 A004200910019999999900000335000000000000000000000 00000000000000000000000000 A005200910019999999900000626500000000000000000000 00000000000000000000000000 A006200704019999999900000423500000000000000000000 00000000000000000000000000 A007200910019999999900000323500000000000000000000 00000000000000000000000000 A008200704019999999900000102500000000000000000000 00000000000000000000000000 And so on up to 200 rows long I need to split each row the same way and add them to a table I will use the first row as an example Character 1 to 4 (A001) entered into a field called name Character 5 to 12 (20091001) entered into a field called efdate Character 13 to 20 (99999999) entered into a field called exdate Character 21 to 31 (00000200000) entered into a field called prfee Character 32 to 42 (00000000000) entered into a field called assfee Character 43 to 53(00000000000) entered into a field called spfee Character 54 to 64 (00000000000) entered into a field called anfee Character 65 to 75 (00000000000) entered into a field called nanfee Thanks in advance for the help hello all, i am hoping someone would be kind enough to help me. the form and code works fine, until i add a ' for e.g. michael's and when i click the submit i get this error: Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 's','home')' at line 3. the mysql filed is set as text. the php code: Code: [Select] function content_add() { $sql="INSERT INTO content (title, body, page) VALUES ('$_POST[title]','$_POST[body]','$_POST[page]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "<script>window.location='index.php?option=content'</script>"; } just hoping someone can help me fix this issue, thanks all. I have just started updating my wordpress website using PDO. For some unknown reason, grabbing text from mysql and using 'echo' to display the data does not work. Here is my code:
global $wpdb;
$symbol = get_query_var('name');
$result = $wpdb->get_row("SELECT about FROM wp_data WHERE symbol = '{$symbol}'");
echo $result->about;
I used a foreach loop and echoed all data and everything shows up except for the "TEXT" field (I only have one TEXT column).
Please help! Thanks in advance.
Hi, Wonder if someone could help with the problem below. Got a main page that includes a header, footer and a link to a database. I can get the two Includes to work but can't seem to display the database fields in the body of the page. What has me baffled is that it appears to be connecting to the database, (Opening the connection to the database server The connection worked. The link is: Resource id #3) but no text (see below for database text) is appearing on the screen. Yet I'm not getting a "page_not_found" message. I can go to the database in MYSQL console and query it successfully. Read and (hopefully) applied the section Debugging: A Beginner's Guide, but still can't see the problem. Any help greatly appreciated. Bren --------------------CODE FOR MAIN PAGE START------------------- <?php $page_name = $_REQUEST['name']; /*http://localhost/exemples/page.php?name=about_us*/ // Get the body of the page mysql_connect("localhost","root","") or die(mysql_error()); mysql_select_db("test") or die(mysql_error()); $sql = "SELECT * from pages WHERE name='$page_name'"; print "Opening the connection to the database server<br>"; $link = mysql_connect("localhost","root", ""); print "The connection worked. The link is: $link <br>"; /* --------------What is being selected from the database-------------- +----------+------------------------------------------------------------------------+ | name | body | +----------+------------------------------------------------------------------------+ | about_us | <h1>About Us</h1> ACME Toys has been established in 1850 to provide toys | to children all over the world +----------+------------------------------------------------------------------------+ 1 row in set (0.00 sec) ---------------------------------------------------------------------- */ $result = mysql_query($sql) or die(mysql_error() ); // If the page is not found, redirect to a static page if(mysql_num_rows($result) == 0 ) { header("Location: page_not_found.html"); } $row = mysql_fetch_assoc( $result ); $body = stripslashes( $row["body"] ); // Include the header include("c:/wamp/www/exemples/header.php"); // Print the body of the page echo $body; // Include the footer include("c:/wamp/www/exemples/footer.php"); ?> --------------------CODE FOR MAIN PAGE END------------------- This is my website http://www.rahulkadukar.info/ As you can see I have the blue navigation bar on top and on mouse hover you can see a drop down menu. The contents of the drop down menu can change and I wanted to write a script that would populate the contents of the drop down menus. Which of these is a better option 1. Use JavaScript along with a text file and use JavaScript to populate the drop down 2. Use a SELECT in PHP to populate the drop down menu I am expecting that the 10 main columns would have at the most 20 entries each. How can i use $query = "SELECT * FROM klanovi WHERE naziv = '{$trazi}' OR tag = '{$trazi}'"; but i need to search from base where that $trazi is contained in naziv or tag, i mean like wildacards? And how can i search that text but no matter of lowercase or uppercase ? Hi all, I have implemented a WYSIWYG in my admin panel, here i can write text and customize it how i want it and then convert it to a html code and save it in my mysql database. Now I want to let other people see the text in the homepage, but it is showing this text very wrong functions like this Code: [Select] <p> <b> <strong> <font> arent working. For example I make text Code: [Select] <b>title</b> <strong> blabla bla bla </strong> then the text becomes like this litterly Quote "<b>title<b> <strong> blabla bla bla </strong> " the codes have no effect and are seen as text in the homepage. My question is how is this possible and how can i fix this, thanks. The code on my homepage is like this Code: [Select] <?php $tekst="SELECT * from homepage where id='1'"; $tekst2=mysql_query($tekst) or die("unable to connect"); $tekst3=mysql_fetch_array($tekst2); print "$tekst3[tekst]"; ?> Hi I have the following for an input form, I was under the impression that ucwords would format the text into Initial Characters, but this does not do that? What have I done wrong? $ven_name = trim(ucwords(mysql_prep($_POST['ven_name']))); Anyone? Ive parced before but this maybe too complex?? Code: [Select] {"page_number":1,"total_rows":3,"date":"April, 19 2012 00:44:42","stats":[ {"rnk":1,"top":4,"ref":1000007,"3Per":1.0,"sts":4,"w":2,"p":2,"sF":00112,"es":8.0020,"reg":"X","hN":"Defence","s":0,"winP":0.98}, {"rnk":3,"top":2,"ref":1000001,"3Per":1.0,"sts":4,"w":2,"p":2,"sF":00112,"es":8.0020,"reg":"X","hN":"Defence","s":0,"winP":0.98}, {"rnk":2,"top":4,"ref":1000000,"3Per":1.0,"sts":4,"w":2,"p":2,"sF":00111,"es":7.0002,"reg":"X","hN":"Forward","s":9,"winP":0.12}]} fields.. rnk, top, ref, 3Per, sts, w, p, sF, es, reg, hN, s winP... all after the : is the data I want. Ive done csv before its simple with , ' but this.. need a little help if possible. exclude {"page_number":1,"total_rows":2,"date":"April, 19 2012 00:44:42","stats": and start from [ to ] its orignally a text file.. to mysql is the plan. I have problem that only last text field is updated, how should I fix this? Here's the code <?php if(isset($_POST["update"])){ mysql_query("UPDATE categories SET name_category = '".$_POST['category']."' WHERE ID= ".$_POST['currentCat']." ") or die(mysql_error()); mysql_query("UPDATE podkategorije SET name_subcategory = '".$_POST['subcategory']."' WHERE id_subCat= ".$_POST['currentSubCat']." ") or die(mysql_error()); } ?> <form action="" method="post" > <?php //creating texfields from db $query = "SELECT k.ID, k.name_category, pk.name_subcategory, pk.id_subCat FROM `categories` AS k JOIN `subcategories` AS pk ON pk.id_mainCat = k.ID"; $result = mysql_query($query) or die(mysql_error()); $currentCat = false; while($row = mysql_fetch_array($result)) { //so it doesn't repeat itself if($currentCat != $row['ID']) { //display of main Categories ?> <ul> <li> <br/><input name="categories" type="text" value="<?php echo $row['name_category']; ?>" /> </li> </ul> <? $currentCat = $row['ID']; } //display subcategories ?> <input name="subcategories" type="text" value="<?php echo $row['name_category']; ?>" /><br/> <input type="hidden" name="currentCat" value="<?php echo $row['ID']; ?>" /> <input type="hidden" name="currentSubCat" value="<?php echo $row['id_subCat']; ?>" /> <? } ?> <br /> <input type="button" value="Back" onClick="history.go(-1);return true;"> <input type="submit" value="Update" name="update"/> </form> Hi My problem is that text that is in my database are showing up next to each other in a line rather than on seperate lines, normally I would have just used <br> but as it's generated from my sql I don't know how to do it. Code: [Select] <ul id="headlines"> <?php foreach ( $results['articles'] as $article ) { ?> <a href=".?action=viewArticle&articleId=<?php echo $article->id?>"><?php echo htmlspecialchars( $article->title )?></a> <?php } ?> </ul> Anyone have any idea? Thanks Hey guys... since im new enough to php, i was wondering if someone could talk me through this one. i have three radio buttons.. allowing the user to search by age, area and skill level.. age and area have a text box and skill level has a drop down box. If the user was to select one of the radio buttons and enter/select a value.. how would the if statement work to search the db? I know how to open a connection, but not exactly sure how to structure this one. hi, i made my own page, but when i do an insert using mysql, jquery and php, the arabic text does not show properly it is a comments page. here is the DB structure Code: [Select] CREATE TABLE IF NOT EXISTS `app_comments` ( `comment_id` int(20) NOT NULL auto_increment, `comment` text NOT NULL, `user_id` int(20) NOT NULL, `comment_date` date NOT NULL, `app_id` int(20) NOT NULL, PRIMARY KEY (`comment_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=35 ; here is the jquery piece that transfers to php code. Code: [Select] function submit_comment(){ $(".post_comments_button").click(function() { var post_comments = $('.post_comments').val(); var app_id = $('#app_id').val(); //alert (app_id); if(confirm('Add Comment?')) { var string = "task=add_comment&app_id=" + app_id + "&comment="+post_comments; $.ajax({ url : "appajax.php", type : "POST", data : string, success : function(data) { alert(data); window.location.reload(true); } }); } /**/ }); }and here is the acutal insert code in php $new_appquery = 'INSERT INTO app_comments (comment, user_id, app_id,comment_date) VALUES ("' . $comment . '",' . $user_id . ', ' . $app_id . ',NOW());'; and the actual problem is, the arabic text shows like this in my application: Quote بالتوفيق للريال how can i solve this issue? hello dear php-experts,
well i want to do some data-saving in the next few days. i have some data amount to store in a mysql-db.
well i am pretty sure this is a easy question for php-freaks
the question is: from plain-text to mysql-db: how to store a triple / array? how to store this data into a mysql-db have a dataset of 10 000 lines: {'data_1': 'data_2', 'data_3': 'data_4', 'data_5': 'data_6', 'data_7': 'data_8'}
how to store this dataset into the mysql db ? love to hear from you greetings Hi there, I got some good advice from Harristweed the other day about how to export from Mysql to excel, so that each field appears in a different column in excel. I expanded the code Harristweed gave me to cover all fields in my database, and all went well until the 2nd last field, when I hit a brick wall. Unlike previous fields, which were based on info inputted via radio buttons, dropdown lists, or text boxes, the field causing problems was based on data that came from a text area on the web form. A few tests revealed that the problem was related to when a user pressed the "Enter" key while filling in that field, to begin a new paragraph. When this happens, it would go into the database fine. However, when I used the code to export it to excel, anything after the "Enter" key had been pressed would appear in a new cell on a new row, thereby putting the table out of alignment. I could get around this by rewording the question into a few questions which each use a text box rather than a text area box. However, if there is a way to get around this by tweaking the php code, I'd love to know. The field with which I'm having the problem is the one called "experience". Thanks for your time, Dave <?PHP $db = mysql_connect("localhost", "MYUSERNAME", "MYPASSWORD"); mysql_select_db("MYDATABASE",$db); $query="SELECT * FROM applications2010"; $result=mysql_query($query); $header=" date\t firstname\t lastname\t sex\t dobday\t dobmonth\t dobyear\t streetaddress\t suburb\t state\t postcode\t country\t preferredphone\t secondphone\t thirdphone\t emailaddress\t emconname\t emconphone\t experience\t "; while($row = mysql_fetch_assoc($result)) { if(empty($row[date]))$row[date]=" "; if(empty($row[firstname]))$row[firstname]=" "; if(empty($row[lastname]))$row[lastname]=" "; if(empty($row[sex]))$row[sex]=" "; if(empty($row[dobday]))$row[dobday]=" "; if(empty($row[dobmonth]))$row[dobmonth]=" "; if(empty($row[dobyear]))$row[dobyear]=" "; if(empty($row[streetaddress]))$row[streetaddress]=" "; if(empty($row[suburb]))$row[suburb]=" "; if(empty($row[state]))$row[state]=" "; if(empty($row[postcode]))$row[postcode]=" "; if(empty($row[country]))$row[country]=" "; if(empty($row[preferredphone]))$row[preferredphone]=" "; if(empty($row[secondphone]))$row[secondphone]=" "; if(empty($row[thirdphone]))$row[thirdphone]=" "; if(empty($row[emailaddress]))$row[emailaddress]=" "; if(empty($row[emconname]))$row[emconname]=" "; if(empty($row[emconphone]))$row[emconphone]=" "; if(empty($row[experience]))$row[experience]=" "; $line = ''; $line .= "$row[date]\t $row[firstname]\t $row[lastname]\t $row[sex]\t $row[dobday]\t $row[dobmonth]\t $row[dobyear]\t $row[streetaddress]\t $row[suburb]\t $row[state]\t $row[postcode]\t $row[country]\t $row[preferredphone]\t $row[secondphone]\t $row[thirdphone]\t $row[emailaddress]\t $row[emconname]\t $row[emconphone]\t $row[experience]\t "; $data .= trim($line)."\n"; } $data = str_replace("\r","",$data); if ($data == "") { $data = "\n(0) Records Found!\n"; } header("Content-type: application/x-msdownload"); header("Content-Disposition: attachment; filename=filename=".date("d-m-Y")."-export.xls"); header("Pragma: no-cache"); header("Expires: 0"); print "$header\n$data";exit; ?> I am not very advanced in web programming I need help..
I am using an API and my sql database. I would to implement live/ dynamic updates in the text field where user will input their text, and the web should first check the database then the api live. I would also like to retrieve the user input without refreshing the page, so the retrieved information regarding the inputted text should be automatically loaded without refreshing the page.
please help .
Hi Guys
I'm just getting back into coding after taking a break from it. I want to have a text field that can take up to 1000 characters. What is the best field type for the MySQL field for this? I can't remember if there are any particular special types.
Thanks
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