PHP - Display Pedigree Table Fron Mysql With Php By Levels
I am working on this page concept of pedigree. How can I foreach or create a loop that can get 6 levels of parents, for example name= 1 ; nfather=2; nmohter = 3 and the loop continue to get or consider nfather as a name = 2 and get his parents. this is my table any help plees
CREATE TABLE horsetest01 (
CREATE INDEX horsetest01_index02
Similar TutorialsHi everyone ! I am stuck on a task which I'm sure has been achieved by several others in the past. I need to create a category table with unlimited / infinite levels (depths) of categories, sub-categories, sub-sub-categories, sub-sub-sub-categories and so on. I need to know how to show the category tree through PHP. An example would be great or even a link to another page where someone has laid out a step-by-step tutorial. Please help! Thank you very much! Kind Regards, Xeirus. Hi, i don't understand how to show ENUM type data in php. Now i use: <input type="text" name="type" style="width: 362px; height: 35px;" value="<?php echo $type; ?>"> But it print only the value that is set to topic i see. How to display all ENUM values in radio buttons and that checked button would be that one from the topic. For example: ENUM ('city','town','vilage') . I select town when writing a topic. And when i edit data i see 3 radio buttons and TOWN would be checked. Thank you for answer. p.s maybe someone know a good site where is a tutorial how to show enum in php Hi, here's my problem: I am trying to make a simple online buying website and I want to display a table with all the fields for each item. So I got that part down which is to just use mysql_fetch_assoc("SELECT * FROM myTable") and use the html table tags stuff, but now I want to display my images in the table, so here's my code to display my mysql database table in html's table tag along w/ php: <html> <head> <title>My Online buying website project</title> </head> <body> <?php mysql_connect("localhost","root"); mysql_select_db("myTable"); $imagesArray=array("Apple_iPhone3GS.jpg","Apple_iPhone4.jpg","product3.jpg","product4.jpg","product5.jpg"); $result=mysql_query("SELECT Name, Manufacturer, Price, Description, SimSupport FROM myTable"); if(mysql_num_rows($result))//if there is at least one entry in bellProducts, make a table { print "<table border='border'>"; print "<tr> <th>Name</th> <th>Manufacturer</th> <th>Price</th> <th>Description</th> <th>SimSupport</th> </tr>"; //NB: now output each row of records while($row=mysql_fetch_assoc($result)) { extract($row); print "<tr> <td>$Name</td> <td>$Manufacturer</td> <td>$Price</td> <td>$Description</td><td>$SimSupport</td> </tr>"; }//END WHILE }//END IF ?> </table> </body> </html> *So how do I go about adding my images in this table? Hey Everyone, I'm creating a site that will show images uploaded for certain days working on a job site. Kind of a day-to-day photo journal for the customer. On the site, the user gets here, sees 3 large images, and a series of thumbnails if more than 3 images exist for that day (works fine). However, underneath that I want to display a 3-4 column setup of "Archived Dates" that provide a link to the images of the other dates. I have this working correctly, but the results are displayed as follows: Date 1: Date 2: Date 3: etc.... I want them to display like this; Day 1 Day 4 Day 2 Day 5 Day 3 Day 6 and so on..... in a 3 column format. Here is the code I have right now just looping through to display these link results, not the rest of the page. I am trying to do it tableless right now, but if that isn't the right way to go, please let me know. Thanks to anyone in advance, Nick $SQLRowe = "SELECT DISTINCT RoweImgDate from tblRowe WHERE RoweImgDate !='" . $_GET['date'] . "' Order by RoweImgDate DESC Limit 0, 30"; //echo $SQLRowe; $rsSQLRowe = mysql_query($SQLRowe); <span class="rowe">Archived Photos:</span><br/> <div id="archive"> <?php while($row = mysql_fetch_array($rsSQLRowe)){ //echo "<a href='index.php?id="' . $row[RoweImgID] . '"' class='link'>$row[RoweImgDate]</a></br>"; echo "<div id='archivedates'>"; echo "<a href='index.php?date=" . $row[RoweImgDate] . "' class='link'>$row[RoweImgDate]</a>"; echo "</div>"; //echo "<img src='images/$row[RoweImage]'/><br/>"; //echo "<span class='FeatDesc'><p>$row[RoweImgDesc]</p></span><br/>"; } ?> </div> I have the following code that searches my database and displays results in a table: $fields = array("field1", "field2", "field3") $cols = implode (', ', $fields); $result= mysql_query (" SELECT $cols FROM tablename WHERE ................... "); if (!$result) {die('Could not search database: ' . mysql_error());} if($result) { if(mysql_num_rows($result) == 0) { return "Sorry. No records found in the database"; } else { $table = "<table border='1' cellpadding='5' cellspacing='5'>"; while($arr = mysql_fetch_array($result, MYSQL_ASSOC)) { $table .= "\t\t<tr>\n"; foreach ($arr as $val_col) { $table .= "\t\t\t".'<td>'.$val_col.'</td>'."\n"; } $table .= "\t\t</tr>\n"; } $table .= "</table>"; echo $table; } mysql_free_result($result); } As you can see each of the MySQL table fields specified by $fields is displayed in a new column in the html table. I want to change this so that e.g. "field3" is displayed in a new row instead. So, instead of the html table looking like: | "field1-result1" | "field2-result1" | "field3-result1" | | "field1-result2" | "field2-result2" | "field3-result2" | | "field1-result3" | "field2-result3" | "field3-result3" | I want it to look like: | "field1-result1" | "field2-result1" | | "field3-result1" | | | "field1-result2" | "field2-result2" | | "field3-result2" | | | "field1-result3" | "field2-result3" | | "field3-result3" | | I guess this is quite straightforward, but I can't work it out! Pls help! Thanks. Hi, I have a 'pre-release' sign up form, where people put in their email address and name, and it transmits to a MYSQL database. That's working fine. What I want to do is to have a piece of text that reads: (insert pre release amount of signer upperers here) have signed up. Will you? I'm guessing that the amount of rows on the table, would end up being the number. How do I do this? Thanks, Jack hi, i'm new to php. i've got a problem. I've 3 tables and table has following content table 1 id name email address phone execution_date executor_name web_address table 2 id name email address phone execution_date executor_name project_title table 3 id name email address phone execution_date executor_name reviewer I want to export these table to and spreadsheet (.xls) with some criteria a form will assign which data will published at the spreadsheet with these criteria #all data can be exported from three tables #some column can be selected from three tables #some or all data can be selected from individual table i've implement a script for this but it didn't meet my requirements. Can anyone help? here is my script <?php $DB_Server = "localhost"; //your MySQL Server $DB_Username = "root"; //your MySQL User Name $DB_Password = "pass"; //your MySQL Password $DB_DBName = "mydb"; //your MySQL Database Name $search_from_date = $_POST['start_date']; $search_to_date = $_POST['end_date']; $Connect = @mysql_connect($DB_Server, $DB_Username, $DB_Password) or die("Couldn't connect to MySQL:<br>" . mysql_error() . "<br>" . mysql_errno()); $Db = @mysql_select_db($DB_DBName, $Connect) or die("Couldn't select database:<br>" . mysql_error(). "<br>" . mysql_errno()); $now_date = date('m-d-Y H:i'); if(($_POST['typer_of_report'] == 'rrc_report') || ($_POST['typer_of_report'] == 'all_report')) { $DB_TBLName = 'rrc_record'; } if(($_POST['typer_of_report'] == 'erc_report') || ($_POST['typer_of_report'] == 'all_report')) { $DB_TBLName2 = 'erc_record'; } if(($_POST['typer_of_report'] == 'aeec_report') || ($_POST['typer_of_report'] == 'all_report')) { $DB_TBLName3 = 'aeec_record'; } $file_type = "vnd.ms-excel"; $file_ending = "xls"; //} header("Content-Type: application/$file_type"); header("Content-Disposition: attachment; filename=protocol_report.$file_ending"); header("Pragma: no-cache"); header("Expires: 0"); if($DB_TBLName) { $sql = "Select * from ".$DB_TBLName." where execution_date >= '".$search_from_date."' and execution_date <= '".$search_to_date."' order by execution_date desc"; $Use_Title = 1; $title = "Report for $DB_TBLName on $now_date"; $result = @mysql_query($sql,$Connect) or die("Couldn't execute query:<br>" . mysql_error(). "<br>" . mysql_errno()); if ($Use_Title == 1) { echo("$title\n"); } $sep = "\t"; //tabbed character for ($i = 0; $i < mysql_num_fields($result); $i++) { echo mysql_field_name($result,$i) . "\t"; } print("\n"); while($row = mysql_fetch_row($result)) { $schema_insert = ""; for($j=0; $j<mysql_num_fields($result);$j++) { if(!isset($row[$j])) $schema_insert .= "NULL".$sep; elseif ($row[$j] != "") $schema_insert .= "$row[$j]".$sep; else $schema_insert .= "".$sep; } $schema_insert = str_replace($sep."$", "", $schema_insert); $schema_insert = preg_replace("/\r\n|\n\r|\n|\r/", " ", $schema_insert); $schema_insert .= "\t"; print(trim($schema_insert)); print "\n"; } //} echo "\n...\n"; } if($DB_TBLName2) { $sql = "Select * from ".$DB_TBLName2." where execution_date >= '".$search_from_date."' and execution_date <= '".$search_to_date."' order by execution_date desc"; $result = @mysql_query($sql,$Connect) or die("Couldn't execute query:<br>" . mysql_error(). "<br>" . mysql_errno()); $Use_Title = 1; $title = "Report for $DB_TBLName2 on $now_date"; if ($Use_Title == 1) { echo("$title\n"); } $sep = "\t"; //tabbed character for ($i = 0; $i < mysql_num_fields($result); $i++) { echo mysql_field_name($result,$i) . "\t"; } print("\n"); while($row = mysql_fetch_row($result)) { $schema_insert = ""; for($j=0; $j<mysql_num_fields($result);$j++) { if(!isset($row[$j])) $schema_insert .= "NULL".$sep; elseif ($row[$j] != "") $schema_insert .= "$row[$j]".$sep; else $schema_insert .= "".$sep; } $schema_insert = str_replace($sep."$", "", $schema_insert); $schema_insert = preg_replace("/\r\n|\n\r|\n|\r/", " ", $schema_insert); $schema_insert .= "\t"; print(trim($schema_insert)); print "\n"; } echo "\n...\n"; } if($DB_TBLName3) { $sql = "Select * from ".$DB_TBLName3." where execution_date >= '".$search_from_date."' and execution_date <= '".$search_to_date."' order by execution_date desc"; $result = @mysql_query($sql,$Connect) or die("Couldn't execute query:<br>" . mysql_error(). "<br>" . mysql_errno()); $Use_Title = 1; $title = "Report for $DB_TBLName3 on $now_date"; if ($Use_Title == 1) { echo("$title\n"); } $sep = "\t"; //tabbed character for ($i = 0; $i < mysql_num_fields($result); $i++) { echo mysql_field_name($result,$i) . "\t"; } print("\n"); while($row = mysql_fetch_row($result)) { $schema_insert = ""; for($j=0; $j<mysql_num_fields($result);$j++) { if(!isset($row[$j])) $schema_insert .= "NULL".$sep; elseif ($row[$j] != "") $schema_insert .= "$row[$j]".$sep; else $schema_insert .= "".$sep; } $schema_insert = str_replace($sep."$", "", $schema_insert); $schema_insert = preg_replace("/\r\n|\n\r|\n|\r/", " ", $schema_insert); $schema_insert .= "\t"; print(trim($schema_insert)); print "\n"; } } ?> have anyone any idea? i have a mysql table which contains name like mid mname 101 AAA 102 BBB 103 CCC now i have to print this name in a html table like AAA, BBB, CCC i am getting this by while loop in a variable but when loop changes then value also change so please tell me how i get this only in one variable & print I am in the process of trying to create a pedigree website (php/mysql)...
I want to be able to calculate a dog's inbreeding coefficient on 10 generations.
I am so not sure where to even begin.
I have a database table:
dogs:
Fields: id name sireid damid
equation:
FX = å [ (½) n1+n2+1 (1 + FA)]
http://www.highflyer...coefficient.htm
Can someone give me a starting point?
Do I need to learn bianary trees? could I do this with an array?
Thanks
Edited by Triple_Deuce, 20 November 2014 - 01:27 PM. i have 8 division (div), i want to display 4 rows in 4 division and the remain 4 rows in the next 4 division here is my code structure for carousel
<div class="nyie-outer"> second row third row
fourth row fifth row sixth row seven throw eighth row
</div><!--/.second four rows here-->
sql code
CREATE TABLE product( php code
<?php how can i echo that result in those rows
ok im trying to create a admin panel but i want to be able to set what level of power they have how would i start i know that i have to use a enum I just added a user log on for a site I am building using PHP. I used a simple session based system for this. I can log on just fine. What I am looking for is a way to pass on in ht session what rank a user is so some links/pages will only show for the admin or the super user but not the normal user. I rank the users as Admin 1, superuser 2, and user 3. This is what I have for the session in my header that allows you to be logged in. Code: [Select] <? session_start(); if(!session_is_registered(myusername)){ header("location:login.php"); } ?> Here is what I have that starts the session Code: [Select] //Connection stuff $query="SELECT * FROM user WHERE username='$myusername' and password='$mypassword'"; $result=mysql_query($query); $count=mysql_num_rows($result); if($count==1){ session_register("myusername"); session_register("mypassword"); header("location:index.php"); } else { echo "Wrong Username or Password"; } ob_end_flush(); ?> Happy Monday All! I am writing some code to try to pull in some XML from the TVA on lake levels. This file is updated about every 3 to 4 hours. I have the startings to pull the data in, but running into some problems. Here is a break down of the problems. I am fairly new to PHP, but trying to learn as I go. Any help would be greatly appreciated. The code I have will not pull in the data and display One I am able to display the code, I need to review the upsteam elevation and compare to the previous levels and show the lake rising, falling, or stable. Here is my code: Code: [Select] <?php $html = file_get_contents('http://www.tva.gov/lakes/xml/OHH_R.xml'); $xml = simplexml_load_file('$html'); echo $html->getName() . "<br />"; foreach($xml->children() as $child) { echo $child->getName() . ": " . $child . "<br />"; } ?> I am fairly new to PHP, but trying to learn as I go. Any help would be greatly appreciated. i know how to get my current directory, and the root path, but what i'm needing to do is find the levels of the current dir, for instance, if i'm in: domain.com/folder1 or if i'm in domain.com/folder1/folder2 or if i'm in domain.com/folder1/folder2/folder3 can someone help? thanks much GN good evening folks, i have a question regarding the foreach syntax when needing to access something say 3 levels deep into the json architecture here's the example I'm trying to accomplish but when echoing it's not returning the value i need from 3 levels deep. I believe i just don't understand the correct syntax so here's the example any help would he sincerely appreciated.
https://pastebin.com/mEBiMUW5 create table mimi (mimiId int(11) not null, mimiBody varchar(255) ); <?php //connecting to database include_once ('conn.php'); $sql ="SELECT mimiId, mimiBody FROM mimi"; $result = mysqli_query($conn, $sql ); $mimi = mysqli_fetch_assoc($result); $mimiId ='<span>No: '.$mimi['mimiId'].'</span>'; $mimiBody ='<p class="leading text-justify">'.$mimi['mimiBody'].'</p>'; ?> //what is next? i want to download pdf or text document after clicking button or link how to do that Hello, I need some help. Say that I have a list in my MySQL database that contains elements "A", "S", "C", "D" etc... Now, I want to generate an html table where these elements should be distributed in a random and unique way while leaving some entries of the table empty, see the picture below. But, I have no clue how to do this... Any hints? Thanks in advance, Vero Hello everyone, Sorry if this has been answered but if it has I can't find it anywhere. So, from the begining then. Lets say I had a member table and in it I wanted to store what their top 3 interests are. Their$ row has all the usual things to identify them userID and password etc.. and I had a further 3 columns which were labled top3_1 top3_2 & top3_3 to put each of their interests in from a post form. If instead I wanted to store this data as a PHP Array instead (using 1 column instead of 3) is there a way to store it as readable data when you open the PHPmyadmin? At the moment all it says is array and when I call it back to the browser (say on a page where they could review and update their interests) it displays 'a' as top3_01 'r' as top3_02 and 'r' as top3_03 (in each putting what would be 'array' as it appears in the table if there were 5 results. Does anyone know what I mean? For example - If we had a form which collected the top 3 interests to put in a table called users, Code: [Select] <form action="back_to_same_page_for_processing.php" method="post" enctype="multipart/form-data"> <input name="top3_01" type="text" value="enter interest number 1 here" /> <input name="top3_02" type="text" value="enter interest number 2 here" /> <input name="top3_03" type="text" value="enter interest number 3 here" /> <input type="submit" name="update_button" value=" Save and Update! " /> </form> // If my quick code example for this form is not correct dont worry its not the point im getting at :) And they put 'bowling' in top3_01, 'running' in top3_02 and 'diving' in top3_03 and we catch that on the same page with some PHP at the top --> Code: [Select] if (isset($_POST)['update_button']) { $top3_01 = $_POST['top3_01']; // i.e, 'bowling' changing POST vars to local vars $top3_02 = $_POST['top3_02']; // i.e, 'running' $top3_03 = $_POST['top3_03']; // i.e, 'diving' With me so far? If I had a table which had 3 columns (1 for each interest) I could put something like - Code: [Select] include('connect_msql.php'); mysql_query("Select * FROM users WHERE id='$id' AND blah blah blah"); mysql_query("UPDATE users SET top3_01='$top3_01', top3_02='$top3_02', top3_03='$top3_03' WHERE id='$id'"); And hopefully if ive got it right, it will put them each in their own little column. Easy enough huh? But heres the thing, I want to put all these into an array to be stored in the 1 column (say called 'top3') and whats more have them clearly readable in PHPmyadmin and editable from there yet still be able to be called back an rendered on page when requested. Continuing the example then, assuming ive changed the table for the 'top3' column instead of individual colums, I could put something like this - Code: [Select] if (isset($_POST)['update_button']) { $top3_01 = $_POST['top3_01']; // i.e, 'bowling' changing POST vars to local vars $top3_02 = $_POST['top3_02']; // i.e, 'running' $top3_03 = $_POST['top3_03']; // i.e, 'diving' $top3_array = array($top3_01,$top3_02,$top3_03); include('connect_msql.php'); mysql_query("UPDATE members SET top3='$top3_array' WHERE id='$id' AND blah blah blah"); But it will appear in the column as 'Array' and when its called for using a query it will render the literal string. a r r in each field instead. Now I know you can use the 'serialize()' & 'unserialize()' funtcions but it makes the entry in the database practically unreadable. Is there a way to make it readable and editable without having to create a content management system? If so please let me know and I'll be your friend forever, lol, ok maybe not but I'd really appreciate the help anyways. The other thing is, If you can do this or something like it, how am I to add entries to that array to go back into the data base? I hope ive explained myself enough here, but if not say so and I'll have another go. Thanks very much people, L-PLate (P.s if I sort this out on my own ill post it all here) I know I'm doing it something right, but can someone tell me why only one table is showing up? Can you help me fix the issue? Heres my code: function showcoords() { echo"J3st3r's CoordVision"; $result=dbquery("SELECT alliance, region, coordx, coordy FROM ".DB_COORDFUSION.""); dbarray($result); $fields_num = mysql_num_fields($result); echo "<table border='1'>"; // printing table headers echo "<td>Alliance</td>"; echo "<td>Region</td>"; echo "<td>Coord</td>"; // printing table rows while($row = mysql_fetch_array($result)) { // $row is array... foreach( .. ) puts every element // of $row to $cell variable foreach($row AS $Cell) echo "<tr>"; echo "<td>".$row['alliance']."</td>\n"; echo "<td>".$row['region']."</td>\n"; echo "<td>".$row['coordx'].",".$row['coordy']."</td>\n"; echo "</tr>\n"; } echo "</table>"; mysql_free_result($result); } I have 2 rows inserted into my coords table. Just frustrated and ignorant to php. |