PHP - Php Script Request: Perform More Than One Action In Response To Single Form Submit Button Click

Hi,   I'm using an example below regarding a whole URL. I'm looking for some conditional PHP that will display certain content depending on if the URL contains the word 'liz' if not, display else.  

$host = $_SERVER['SERVER_NAME'] . $_SERVER['REQUEST_URI'];


if($host == 'liz-4.website.com') 
{
echo $this->__('The domain contains the word liz.');
}
else
{
echo $this->__('The domain does not contain the word liz.');
}

 

hi i need help on posting multiple inputs in a single button...while using mysql_fetch_array
here is my codes:

<?
$re6 = mysql_query('select username from users where course = "BSIT" and yearlevel = "FOURTH"');
?>
<br />
<h1>Post Grade</h1>
<h1>IT, Fourth Year</h1>
<br />Please fill the following form to send The Grade<br />
<?
$n = 0;
while($row = mysql_fetch_row($re6))
{
echo'<form action="grade_post.php" method="post">';
echo'Recipient<span class="small">(Username)</span><input type="text" value="'.$row['username'].'" readonly="readonly" id="recip" name="recip[' . $n . ']" />';
echo'Subject<input type="text" value="'.htmlentities($otitle, ENT_QUOTES, 'UTF-8').'" id="title" name="title[' . $n . ']" />';
echo'<input type="hidden" value="FOURTH" id="year" name="year[' . $n . ']" />';
echo'<input type="hidden" value="FIRST" id="sem" name="sem[' . $n . ']" />';
echo'Grade<input type="text" id="message" name="message[' . $n . ']" ><br />';
++$n;
}
?>


i get all my recipients in every input type, but when i tried to post it in my database not all of them are posted rather only one of them are posted in my database ...what i want to happen is that all of my recipients in every input type will be posted in my database with different ids'...help pls...

I want to loop through a MySQL table, and perform a calculation based on the current row the loop is on and the previous loop.

Say my table has 2 columns - Film_id and FilmRelease, how would I loop through and echo out a calculation of the current FilmRelease and the previous row's column value?

Thanks guys

I have got to this stage, but for some reason it's not printing out anything

Code: [Select]
<?php
 mysql_connect("localhost", "****", "*****") or die(mysql_error()); 
 mysql_select_db("*****") or die(mysql_error()); 

 $sql = mysql_query("SELECT FilmRelease FROM Films_Info") 
 or die(mysql_error()); 

 $last_value = null;

while ($row = mysql_fetch_assoc($sql)) {

  if (!is_null($last_value)) {

    print date_diff($row['FilmRelease'], $last_value) . "<BR>";
  }

  $last_value = $row['FilmRelease'];
}

Code: [Select]
<?php

$db = mysql_connect("localhost", "root") or die("Could not connect."); //username and password

if(!$db) 

die("no db");

if(!mysql_select_db("simple",$db)){
if(!mysql_select_db("regis",$db)){//database name

  die("No database selected.");}}
$message=$_POST['message'];


  print "<form action='registration.php' method='post'onsubmit='return msg();'>";

  print "Your message:<br>";

  print "<textarea name='message' cols='40' rows='2'></textarea><br>";

  print "<a onClick=\"addSmiley(':)')\"><img src='smile.gif'></a> ";

  print "<a onClick=\"addSmiley(':(')\"><img src='blush.gif'></a> ";

  print "<a onClick=\"addSmiley(';)')\"><img src='images/wink.gif'></a> ";

  print "<input type='submit' name='submit' value='Set Name'></form>";

  print "<script language=\"Java Script\" type=\"text/javascript\">\n";

  print "function addSmiley(a)\n";

  print "{\n";

  print "document.form.message.value += a;";

  print "document.form.message.focus();\n";

  print "}\n";

  print "</script>\n";

  print "<br><br>";
?>

 <script type="text/javascript">
 <?php
  function msg(){

if(isset($_POST['submit'])) //if submit button push has been detected

{



   if(strlen($message)<1)

   {    
    // print "You did not input a message";
      echo"<SCRIPT LANGUAGE='javascript'>alert('You did not input a message')</SCRIPT>";

   }

   else

   {

      $message=strip_tags($message);

      $IP=$_SERVER["REMOTE_ADDR"]; //grabs poster's IP

      $checkforbanned="SELECT IP from admin where IP='$IP'";

      $checkforbanned2=mysql_query($checkforbanned) or die("Could not check for banned IPS");

      if(mysql_num_rows($checkforbanned2)>0) //IP is in the banned list

      {

         print "You IP is banned from posting.";

      }

     else
      
       if(strlen($message)>=1)
       {

         $message=strip_tags($message);
         echo("<SCRIPT LANGUAGE='JavaScript'>window.alert('$message')</SCRIPT>");
        // die("<meta http-equiv=\"refresh\" content=\"0; url=registration.php\">");
       }
        $message=$_POST['message'];
         $message=strip_tags($message);
     /*   if($_POST['username'] && $_POST['pass'])
       {

         $name = mysql_query("SELECT * FROM Persons");
         $thedate = date("U"); //grab date and time of the post

         $insertmessage="INSERT into mesej (name,IP,postime,message) values('$name','$IP','$thedate','$message')";

         mysql_query($insertmessage) or die("Could not insert message");

        }     */

   }
}
return false;
}
return true;
</script>
?>







This is my code in my submit2.php im clicked submit button but if it is empty it should return an javascript alert error but why it directs through registration.php without reading the rules?

Folks,

 

Look at this weird thing.

I load the page and get echoed as expected: Did Not REQUEST_METHOD!

Then, I click the SUBMIT button and to my astonishment I get echoed: Did Not POST->Submit!

Got 2 buttons. Same result whenever clicking any.

Why is that ?

Check it out:

	<?php
//include('error_reporting.php');
ini_set('error_reporting',E_ALL);//Same as: error_reporting(E_ALL);
ini_set('display_errors','1');
ini_set('display_startup_errors','1');
?>
	<form name = "submit" method = "POST" action="">
<label for="domain">Domain:</label>
<input type="text" name="domain" id="domain" placeholder="Input Domain">
<br>
<label for="domain_email">Domain Email:</label>
<input type="email" name="domain_email" id="domain_email" placeholder="Input Domain Email">
<br>
<label for="url">Url:</label>
<input type="url" name="url" id="url" placeholder="Input Url">
<br>
<label for="link_anchor_text">Link Anchor Text:</label>
<input type="text" name="link_anchor_text" id="link_anchor_text" placeholder="Input Link Anchor Text">
<br>
<textarea rows="10" cols="20">Page Description</textarea>
<br>
<label for="keywords">Keywords:</label>
<input type="text" name="keywords" id="keywords" placeholder="Input Keywords related to Page">
<br>
<input type="checkbox" name="alert_visitor_type" id="alert_visitor_type" value="Give Alert: Visitor Type">
</label for="alert_visitor_type">Give Alert: Visitor Type</lablel>
<input type="checkbox" name="alert_visitor_potential" id="alert_visitor_potential" value="Give Alert: Potential Visitor">
</label for="alert_visitor_potential">Give Alert: Potential Visitor</lablel>
<br>
<input type="radio" name="tos_agree" id="tos_agree_yes" value="yes">
<label for="tos_agree_yes">Yes:</label>
<input type="radio" name="tos_agree" id="tos_agree_no" value="no">
<label for="tos_agree_no">No:</label>
<br>
<label for="tos_agreement">Agree to TOS or not ?</label>
<select name="tos_agreement" id="tos_agreement">
<option value="yes">Yes</option>
<option value="no">No</option>
</select>
<br>
<button type="submit" value="submit">Submit</button><br>
<button type="submit">Submit</button>
<br>
<input type="reset">
<br>
</form>
	<?php
	if($_SERVER['REQUEST_METHOD'] === 'POST')
{
    if(isset($_POST['submit']))
    {
        mysqli_report(MYSQLI_REPORT_ALL|MYSQLI_REPORT_STRICT);
        mysqli_connect("localhost","root","","test");
        $conn->set_charset("utf8mb4");
        
        $query = "INSERT into links (domain,domain_email,url,link_anchor_text,page_description,keywords,alert_visitor_type,alert_visitor_potential) VALUES (?,?,?,?,?,?,?,?)";
	        $stmt = mysqli_stmt_init($conn);
	        if(mysqli_stmt_prepare($stmt,$query))
        {
            mysqli_stmt_bind_param($stmt,'ssssssss',$_POST['domain'],$_POST['domain_email'],$_POST['url'],$_POST['link_anchor_text'],$_POST['page_description'],$_POST['keywords'],$_POST['alert_visitor_type'],$_POST['alert_visitor_potential']);
            if(mysqli_stmt_execute($stmt) === FALSE)
            {
                die("Error\" . mysqli_stmt_error()");
            }
            
            mysqli_stmt_close($stmt);
            mysqli_close($conn);
        }
        else
        {
            die("Did not INSERT!");
        }
    }
    else
    {
        die("Did Not POST->Submit!");
    }
}
else
{
    die("Did Not REQUEST_METHOD!");
}
	?>
	

Hello

I am working in moodle and its code base is in PHP. I am a novice to moodle as well as PHP and not quite familiar with PHP syntax.

Right now I have built a Web page in moodle, and its view.php file I need to implement a fuctionality on click of a button.

On click of submit button, I am trying to implement a functionality and I have written the code for that under if(isset($_POST['submit]))
{ ...my code...}

Also while creating the form I have set the attributes as follows:
echo "<form method='post' action='" . $_SERVER['PHP_SELF']."?inpopup=". $_GET['inpopup']."&amp;id=" . $_GET['id'] . "'>";

But irrespective of whether or not I click the button, whenevr the page loads for the first time, it perform the code written in IF loop as well.

So Am i going wrong in implementing a functionality on click of button in PHP or is it something related to moodle, if anyone knows?
Any help or suggestions would be appreciated. As I am stuck with this logic since last three days.

Regards

I am creating a user inbox system. I am retrieving all the unread messages. Each message row contains a "reply" form. So say I have 10 messages showing on a single page. That's 10 forms.

What I would like to know is how can I submit any one of the 10 forms and not have it affect the remaining 9 forms?

Here is the basic code.

if(isset($_POST['submit'])) {
  $post_message = trim($_POST['message']);

  $errors      =  array();
  $db->beginTransaction();

  if(empty($post_message)) {
    $errors[] = 'The message field can not be empty!';
  }

  if(empty($errors)) {
    $db->commit();
    
    echo 'success';

  } else {
    $db->rollBack();
  }
}
<form action="" method="post">
  <fieldset>
    <textarea name="message" maxlength="10000" placeholder="What would you like to say?"></textarea>
  </fieldset>
  <fieldset>
    <input type="submit" name="submit" value="Submit" />
  </fieldset>
</form>

 

i need to submit 1 article (3 input fields: title, category, description), to multiple sites. it must be done with 1 click.

one more thing... each site to which i have to submit has different input names, but are the same 3, also 1 is for title 1 for category and 1 for description.

I have an application which receives multiple requests at once and it advantageous to process them as a group.

I am thinking I should be doing something like the following, however, as I just came up with it on my own, would appreciate a critique.  Is this a common design pattern or should I be doing something differently?  Note that I have three questions asking specific questions in the below code (look for the comments with question marks).

Thanks
 

<?php
class Request
{
    private $response, $data;

    public function __construct(array $data)
    {
        $this->data=$data;
        return $this->response=new Response($this);
    }    

    public function getResponse():Response
    {
        return $this->response;
    }

    public function updateResponse($results):self
    {
        $this->response->setResults($results);
        return $this;
    }
}

<?php
class Response
{
    private $request, $results;

    public function __construct(Request $request)
    {
        //I don't really see the need for this.  Any need?
        $this->request=$request;
    }

    public function setResults($results):self
    {
        $this->results=$results;
        return $this;
    }

    public function getResults()
    {
        return $this->results;        
    }
}

 

<?php
class Container implements \Iterator
{
    private $position = 0;
    private $requests, $response;

    public function __construct(WorkerObject $worker, array $inputArray)
    {
        $this->requests=[];
        $this->responses=[];
        foreach($inputArray as $i =>$inputData) {
            $this->requests[$i]=new Request($inputData);
            $this->responses[]=$this->responses[$i]->getResponse();
        }

        //Should WorkerObject be responsible to execute Request::updateResponse() method? 
        $worker->process_requests(...$this->requests);

        //Or should I iterate over my requests upon completion and execute updateResponse() method? 
    }

    public function __construct() {
        $this->position = 0;
    }

    public function rewind() {
        $this->position = 0;
    }

    public function current() {
        return $this->responses[$this->position];
    }

    public function key() {
        //Will this work?
        return $this->requests[$this->position];
    }

    public function next() {
        ++$this->position;
    }

    public function valid() {
        return isset($this->responses[$this->position]);
    }
}

<?php
//...
$container=new Container(new WorkerObject, $inputArray);
foreach($container as $request => $response) {
    //...
}

 

Hello,

I am trying to do multiple curl requests and get the response for each one output to the screen.

I have wrote the following code, but only appear to be getting the last response when outputting $result.

What am i doing wrong? Is there a way to wait for each curl request to be completed before appending to $result so I can see them all?

Thanks very much

if (isset($_POST['submit'])) {
	$result = array();
	foreach ($textAr as $line) {
		$ch = curl_init();
		curl_setopt($ch, CURLOPT_URL, $url);
		curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
		curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
		curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true );
		curl_setopt($ch, CURLOPT_ENCODING, "gzip,deflate");
		$result[] = curl_exec ($ch);
	}
	curl_close ($ch);

	echo "<pre>";
	print_r($result);
	echo "</pre>";

}

 

I need to make my client's site distinguish among different tabs in the same browser. (See http://www.phpfreaks.com/forums/index.php?topic=357772.0 for background.)

I create a tab ID when the user first visits the site in a particular tab, and I'm passing it from page to page as a parameter. This seems to be the only way to do what I need.

The tab ID is always passed through POST so that the user won't see it. If it were visible, users could make trouble (or more likely get in trouble) by adding or removing the ID themselves.

This is not simple where a page is loaded by a hyperlink. The anchor tag passes parameters via GET, period.

The solution I found is to link to a script named post.php, which takes the real link target and the tab ID as parameters, sends the browser a form that passes the tab ID to the real link target via POST, and auto-submits the form via JavaScript.

This works, but it requires two round trips to the browser to load a page. It's also a pain to code.

Is there a more efficient way to do this... perhaps a way to make the server send the browser a POST response, even though it made a GET request?

If it matters, the server is Apache 2.x.

I'm having problems creating a working submit button for a php script. 

The script is sitting on index.php and if I browse to that page it will send the email as required... great. 

So I though happy days I'll make a simple button for it... 6 hours later no joking. 

Firstly this is working php

<?php

require 'includes/PHPMailer.php';
require 'includes/SMTP.php';
require 'includes/Exception.php';

use PHPMailer\PHPMailer\PHPMailer;
use PHPMailer\PHPMailer\SMTP;
use PHPMailer\PHPMailer\Exception;

$mail = new PHPMailer();

$mail->isSMTP();

$mail->Host = "smtp.gmail.com";

$mail->SMTPAuth = "true";

$mail->SMTPSecure = "tls";

$mail->Port = "587";

$mail->Username = "Myemail@gmail.com";

$mail->Password = "Pass";

$mail->Subject = "Test email using PhPmailer";

$mail->setFrom("Myemail@gmail.com");

$mail->isHTML(true);

$mail->addAttachment('img/LifesaverFootage.mp4');

$mail->Body = "<h1>This is a HTML heading</h1></br><p>Title</p>";

$mail->addAddress("myemail@gmail.com");


if ($mail->Send() ) {
	echo "Email sent..!";	
}
else{
	echo "Error..!";
}

$mail->smtpClose();

?>

Now I've been at this with everything but a blow torch these are some attempts below. I've also tried to just href to the page. All that happens is it creates another copy of the index.php file as if it were a download. The last thing I wanted to do was wrap this up as a function and I wanted to try something to do with Isset. But it won't even load the page if I define it as a function and then call it. I know I'm defining and calling the function correctly as I can do an echo function. Surely it couldn't be this hard. I mean all the thing has to do is dang trigger the page for goodness sake. Lol sighhhhhhh...Please help 

<!--
<!DOCTYPE html>
<html>
<head>
  <meta charset="UTF-8">
  <title>Email Button</title>
</head>
<body>
  <form action="index.php" method="get">
    <input type="hidden" name="act" value="run">
    <input type="submit" value="Run me now!">
</form>

</body>
</html>

I have a problem that is particular to the FF and Safari browsers.  I do not see the problem in IE.

Again, I am very new to php programming - no formal training - just a hacker.

I have a web page that presents a form with a results table and a SUBMIT button.  Each time the button is selected I want to present one of two different tables of results. 

Everything works fine the first time I hit the SUBMIT button.  The page updates and shows the second table.

But on the next SUBMIT the script that swaps things around is executed twice in FF and Safari vs. one time like in EI.

This results in the same result table being displayed over and over vs. the two switching back and forth.

Any idea what could be going wrong in these two browsers?

Here's my swap script:

Code: [Select]
<?php
session_start();
// This script reverses the coin flip to see what would happen the other way
if ($_SESSION['Coin_Flip'] == "heads") { //switch to tails
  $_SESSION['Coin_Flip'] = "tails";
  include ('tails_algo.php');
} elseif ($_SESSION['Coin_Flip'] == "tails") {
  $_SESSION['Coin_Flip'] = "heads";
  include ('heads_algo.php');
}
include ('kind-comp_result.php');
?>

Hello all , here is another problem of my project.

I need to create a textarea , drop down list and submit button .

At first , I can type whatever I want in the textarea , but for certain part I can just choose the word I want from drop down list and click submit , then the word will appear in the textarea as my next word .

But I have no idea how to make this works , is there any simple example for this function ?
Thanks for any help provided .

Hey guys! I've looked through this code over and over today, and I still haven;t found where my error is. Here is my entire code:

Code: [Select]
<?php
session_start();
include("config536.php");
?>
<html>
<head>
<link rel="stylesheet" type="text/css" href="style.css" />
</head>

<?php
if(!isset($_SESSION['username'])) {
echo "<banner></banner><nav>$shownavbar</nav><ubar><a href=login.php>Login</a> or <a href=register.php>Register</a></ubar><content><center><font size=6>Error!</font><br><br>You are not Logged In! Please <a href=login.php>Login</a> or <a href=register.php>Register</a> to Continue!</center></content>";
}

if(isset($_SESSION['username'])) {
echo "<nav>$shownavbar</nav><ubar>$ubear</ubar><content><center><font size=6>Quest Agency</font><br><br>";

$startjob = $_POST['submit'];
$jobq = "SELECT * FROM jobs WHERE username='$showusername'";
$job = mysql_query($jobq);
$jobnr = mysql_num_rows($job);

if($jobnr == "0") {
?>
<form action="<?php echo "$PHP_SELF"; ?>" method="POST">
<input type="submit" name="submit" value="Start Job"></form>
<?php
}
if(isset($startjob)) {
$initemidq = "SELECT * FROM items ORDER BY RAND() LIMIT 1";
$initemid = mysql_query($initemidq);
while($ir = mysql_fetch_array($initemid)) {
$ids = $ir['itemid'];
}
mysql_query("INSERT INTO jobs (username, item, time, completed) VALUES ('$showusername', '$ids', 'None', 'No')");
$wegq = "SELECT * FROM items WHERE itemid='$ids'";
$weg = mysql_query($wegq);
while($wg = mysql_fetch_array($weg)) {
$im = $wg['image'];
$nm = $wg['name'];
$id = $wg['itemid'];
}
$_SESSION['theid'] = $id;
$yeshere = $_SESSION['theid'];

echo "<font color=green>Success! You have started this Job!</font><br><br>Please bring me this item: <b>$nm</b><br><br><img src=/images/items/$im><br><br><br>";
}

if($jobnr == "1") {
$yeshere = $_SESSION['theid'];
$finish = $_POST['finish'];
$quit = $_POST['quit'];
$okgq = "SELECT * FROM items WHERE itemid='$yeshere'";
$ok = mysql_query($okgq);
while($ya = mysql_fetch_array($ok)) {
$okname = $ya['name'];
$okid = $ya['itemid'];
$okimage = $ya['image'];
}
$yeshere = $_SESSION['theid'];
echo "Where is my <b>$okname</b>?<br><br><img src=/images/items/$okimage><br><br><br>";
?>
<form action="<?php echo "$PHP_SELF"; ?>" method="POST">
<input type="submit" name="finish" value="I have the Item"><br><br>
<input type="submit" name="quit" value="Quit"></form>
<?php
}
}

if(isset($finish)) {
$yeshere = $_SESSION['theid'];
$cinq = "SELECT * FROM uitems WHERE theitemid='$_SESSION[theid]'";
$cin = mysql_query($cinq);
$connr = mysql_num_rows($cin);
if($connr != "0") {
mysql_query("DELETE FROM uitems WHERE username='$showusername' AND theitemid='$yeshere' LIMIT 1");
mysql_query("UPDATE users SET jobs=jobs+1 WHERE username='$showusername'");
mysql_query("UPDATE users SET credits=credits+320 WHERE username='$showusername'");
mysql_query("DELETE FROM jobs WHERE username='$showusername'");
echo "<font color=green>Success! You have completed this job! You have been given <b>320</b> credits as an award. Thank You!</font>";
} else {
echo "<font color=red>Error! You do not have my item!</font>";
}
if(isset($quit)) {
mysql_query("DELETE FROM jobs WHERE username='$showusername'");
echo "<font color=green>Success! You have quit this quest.</font>";
}
$yeshere = $_SESSION['theid'];

}
?>

The variable for the button is: $quit = $_post and I want the quit button to work. Does anybody know why it will not work? Thank you in advance!