PHP - Section Search Error
I'm working on the following assignment and keep coming up with error messages.
"Warning: require(mysqli_connect_registrar.php): failed to open stream: No such file or directory in /home/students/r/b.richards/public_html/cis231/labs/sectionresults.php on line 3 I've included the code I have and any help would be appreciated. Thank you. Assignment Directions: Introduction This lab will demonstrate how to create a dynamic form that is created from database contents. And then that form will be used to pull results from the database, based on the user's selection.
STEP 1 - Create the Database Connection File In your labs directory, define a mysql_connect.php file for the registrar database (with the student | student credentials).
STEP 2 - Create the Form Define the form as sectionsearch.php. Create a dynamic form with a drop-down menu listing available courses by title. (Note: the courseID will be the value that is posted to the results page.)
Step 3 - Create the Results page Define the results page as sectionresults.php. Present the results of the query for sections (unless there are none—then show an appropriate message). If there are results, use an HTML table (dynamically-generated) to display available sections with the following information: Faculty last name Room number Class meeting day(s) Start time End time The information should be sorted by the faculty member's last name. Note: You will need to consult the structure of the database tables to determine which fields need to be drawn from which tables and how to join the appropriate tables needed for the query. Sectionsearch.php code:
<!doctype html>
<head> <body>
<form id="form1" name="form1" method="post" action="sectionresults.php">
<p>Courses
<p>
</form> mysql_connect.php code:
<!doctype html>
//Set database connection information
//Database connection
//Set the encoding sectionresults.php code:
<?php
$cat = "";
$q = "SELECT lastame, FROM faculty WHERE registrar = $cat ORDER BY lastname ASC"; Similar TutorialsOkay, I have no idea how this works out but this is really getting on my nerves. Here is my logic for the following code. I manually register a user, It goes into the database and dispatches an email notification explaining that a user must activate their account and change their user name (OPTIONAL) and password. In the email, There is an automatically generated password with the username, And a link to activate the account. This leads to stage 1 of the activation process, In this stage the user is accepted, Registered as a verified user and then is sent to another page to change the details like login and password. As far as I know this page works except through trial and error I found that this little snippet of code is causing browsers to show an error 500 page, If I remove this the page works: <?php if($messages){ displayErrors($messages); } else { echo("<p align=\"center\" class=\"standard\">Your account has been activated.</p><p align=\"center\" class=\"standard\">You now need to change your password. If you like you can also change your username, Remember that you only have 3 days to do so and this change will be permanent.</p>"); } ?> and this is the displayErrors function: <?php function displayErrors($messages) { print("<p align=\"center\" class=\"standard\">"."<b>There were problems with the previous action:</b>\n<ul>\n"); foreach($messages as $msg){ print("<li>$msg</li>\n"); } print("</ul>\n"."</p>"); } ?> The displayErrors function is in a file called functions.php, Which is included in config.php, Which is included in every page including this one. The entire "Change password and login page thingie" is he <?php include("config.php"); global $link, $messages; require_once('recaptchalib.php'); if($_GET['error']){ $id=$_GET['id']; $messages[]="There is more than one or no accounts with the verification code you are using. <a href=\"mailto:rentals@nivso.co.uk?subject=Two or no accounts with activation ID of $id\">Click here to email us about this and have the problem sorted.</a>"; doIndex(); exit; } if(isset($_POST['submit'])){ if(!isset($_POST['activationid'])){ die("Doesn't exist -.- might as well quit this is *STUFF* -.-"); } $privatekey = "YOUR NOT HAVING THIS"; $resp = recaptcha_check_answer ($privatekey, $_SERVER["REMOTE_ADDR"], $_POST["recaptcha_challenge_field"], $_POST["recaptcha_response_field"]); if (!$resp->is_valid) { $messages[]="The code you entered is incorrect. Please go back and try again!"; doIndex(); exit; // exit or the below lines will be processed. } else { //This is where the fun starts! $login=$_POST['login']; $passw=$_POST['password']; $passc=$_POST['passwordc']; $id2=$_POST['activationid']; $changinglogin=false; $get1=excDB("SELECT * FROM `users` WHERE `activeID`='$id2'"); if($get1[0]){ $get1=$get1[1]; } else { die($get1[2]); } $pro1=mysql_fetch_array($get1); if($pro1['login']!=$login){ $changinglogin=true; field_validator("Login", $login, "alphanumeric", 4, 15); } field_validator("Password", $passw, "string", 6, 20); if($passw!=$passc){ $messages[]="The passwords do not match, Please make sure that the passwords are the same!"; } if($messages){ doIndex(); exit; } $passcl=mysql_escape_string($passw); $passen=md5($passcl); if($changinglogin){ $wri1=excDB("UPDATE `users` SET `login`='$login', `password`='$passen', `passchange`='1', `loginchange`='1' WHERE `activeID`='$id2';"); if($wri1[0]){ $wri1=$wri1[1]; } else { die($wri1[2]); } header("Location: login.php?created"); } else { $wri1=excDB("UPDATE `users` SET `password`='$passen', `passchange`='1', `loginchange`='0' WHERE `activeID`='$id2';"); if($wri1[0]){ $wri1=$wri1[1]; } else { die($wri1[2]); } header("Location: login.php?created2"); } } } else { doIndex(); } function doIndex(){ ?> <!DOCTYPE html> <head> <title>Family Rental System! - Rent your DVDs here - Design by Alex, Coding by Gergy008</title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <link type="text/css" href="css/main.css" rel="stylesheet"> <style type="text/css"> <!-- body { background-color: #333333; } --> </style></head> <body style="text-align:center;"> <div class="first"> <div class="backgrounder1"></div> <div class="headerbar1"></div> <div class="headerbar2"></div> </div> <div align="center"> <table border="0" cellpadding="0" cellspacing="0" width="900"> <tr> <td><img src="images/spacer.gif" width="52" height="1" border="0" alt="" /></td> <td><img src="images/spacer.gif" width="123" height="1" border="0" alt="" /></td> <td><img src="images/spacer.gif" width="352" height="1" border="0" alt="" /></td> <td><img src="images/spacer.gif" width="33" height="1" border="0" alt="" /></td> <td><img src="images/spacer.gif" width="55" height="1" border="0" alt="" /></td> <td><img src="images/spacer.gif" width="110" height="1" border="0" alt="" /></td> <td><img src="images/spacer.gif" width="110" height="1" border="0" alt="" /></td> <td><img src="images/spacer.gif" width="50" height="1" border="0" alt="" /></td> <td><img src="images/spacer.gif" width="15" height="1" border="0" alt="" /></td> <td><img src="images/spacer.gif" width="1" height="1" border="0" alt="" /></td> </tr> <tr> <td colspan="9" background="images/template.slice.1.png"> </td> <td><img src="images/spacer.gif" width="1" height="20" border="0" alt="" /></td> </tr> <tr> <td colspan="5" background="images/template.slice.2.png"> </td> <td colspan="2" rowspan="2" background="images/template.slice.3.png"><span class="login"><?php echo(loginHandler()); ?></span></td> <td colspan="2" rowspan="3" background="images/template.slice.4.png"> </td> <td><img src="images/spacer.gif" width="1" height="30" border="0" alt="" /></td> </tr> <tr> <td rowspan="8" background="images/template.slice.5.png"> </td> <td colspan="2" background="images/template.slice.6.png"><form> <div align="center"> <input name="textfield" type="text" id="textfield" size="40" style="height:16px;"> <input type="submit" name="button" id="button" value="Search" style="height:20px;"> </div> </form></td> <td colspan="2" rowspan="2" background="images/template.slice.7.png"> </td> <td><img src="images/spacer.gif" width="1" height="30" border="0" alt="" /></td> </tr> <tr> <td colspan="2" rowspan="3" background="images/template.slice.8.png"><p> </p> <p> </p></td> <td colspan="2" background="images/template.slice.9.png"> </td> <td><img src="images/spacer.gif" width="1" height="70" border="0" alt="" /></td> </tr> <tr> <td rowspan="2" background="images/template.slice.10.png"> </td> <td colspan="4" background="images/template.slice.11.png"> </td> <td rowspan="6" background="images/template.slice.12.png"> </td> <td><img src="images/spacer.gif" width="1" height="30" border="0" alt="" /></td> </tr> <tr> <td colspan="4" background="images/template.slice.13.png"></td> <td><img src="images/spacer.gif" width="1" height="8" border="0" alt="" /></td> </tr> <tr> <td rowspan="4" background="images/template.slice.14.png"> </td> <td colspan="4" background="images/template.slice.15.png"> </td> <td colspan="2" rowspan="4" background="images/template.slice.16.png"> </td> <td><img src="images/spacer.gif" width="1" height="35" border="0" alt="" /></td> </tr> <tr> <td colspan="4" background="images/template.slice.17.png"> </td> <td><img src="images/spacer.gif" width="1" height="37" border="0" alt="" /></td> </tr> <tr> <td colspan="4" align="center" valign="top" background="images/template.slice.18.png" style="vertical-align:top;"><p class="standard"> </p> <table width="80%" border="0"> <tr> <td colspan="2"> <?php if($messages){ //displayErrors($messages); } else { //echo("<p align=\"center\" class=\"standard\">Your account has been activated.</p><p align=\"center\" class=\"standard\">You now need to change your password. If you like you can also change your username, Remember that you only have 3 days to do so and this change will be permanent.</p>"); ?></td> </tr> <form name="ChangeDetails" method="post" action="<?=$_SERVER['PHP_SELF']?>"> <input type="hidden" name="activationid" value="<?php if($_GET['id']){ $id=$_GET['id']; echo($id); } elseif($_POST['activationid']){ $id=$_POST['activationid']; echo($id); } else { die("No ID") } ?>" /> <tr> <td width="50%"><div align="right" class="standard">New Username: </div></td> <td width="50%"><input name="login" type="text" id="login" size="35" maxlength="30" /></td> </tr> <tr> <td><div align="right" class="standard">New Password:</div></td> <td><input name="password" type="password" id="password" size="35" maxlength="30" /></td> </tr> <tr> <td><div align="right" class="standard">Re-enter password:</div></td> <td><input name="passwordc" type="password" id="passwordc" size="35" maxlength="30" /></td> </tr> <tr> <td><div align="right" class="standard">Please enter the code: </div></td> <td> <?php require_once('recaptchalib.php'); $publickey = "6Le4fsESAAAAAKMOHb8aaiyDfGRJyr0y0EU7dXm-"; // you got this from the signup page echo recaptcha_get_html($publickey); ?> </td> </tr> <tr> <td> </td> <td><input type="submit" name="submit" id="submit" value="Change your details" /></td> </tr> </form> </table> </td> <td><img src="images/spacer.gif" width="1" height="450" border="0" alt="" /></td> </tr> <tr> <td colspan="4" background="images/template.slice.19.png"> </td> <td><img src="images/spacer.gif" width="1" height="50" border="0" alt="" /></td> </tr> <tr> <td colspan="9" background="images/template.slice.20.png"> </td> <td><img src="images/spacer.gif" width="1" height="40" border="0" alt="" /></td> </tr> </table> </div> </body> </html> <?php } ?> Thanks to all you kind people that take your time to read and help me with this problem. I'm sorry if it is a really simple problem I missed out that makes me look like a right idiot and wasted your time, but that's me I'm always missing stuff out like that, I do proof read though just sometimes not good enough. Thanks in advance! Hi folks, I am a complete n00b at php and mysql. I am teaching myself from books and the WWW, but alas I am stuck... the error I get is: Parse error: syntax error, unexpected T_STRING in X:\xampp\htdocs\search.php on line 7 here is the code: <?php mysql_connect ("localhost", "user", "password") or die (mysql_error()); mysql_select_db ("it_homehelp_test") or die (mysql_error()); $term = $_POST['term']; $sql = $mysql_query(select * from it_homehelp_test where ClientName1 like '%term%'); <<<------this is line 7 while ($row = mysql_fetch_array($sql)){ echo 'Client Name:' .$row['ClientName1']; echo 'Address:' .$row['Address1']; echo 'Phone:' .$row['Tel1']; } ?> Any help you can offer would be great. I can also post the ".html" file that creates the search bar if it is needed. Thanks This topic has been moved to mod_rewrite. http://www.phpfreaks.com/forums/index.php?topic=318858.0 Error: Warning: mysql_query() expects parameter 1 to be string, resource given in C:\Program Files\xampp\htdocs\NEW\search.php on line 35 Warning: mysql_num_rows() expects parameter 1 to be resource, null given in C:\Program Files\xampp\htdocs\NEW\search.php on line 36 Results Sorry, your search: "mod" returned zero results Click here to try the search on google You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Resource id #3 limit 0,10' at line 1 My PHP code <?php // Get the search variable from URL $var = @$_GET['q'] ; $trimmed = trim($var); //trim whitespace from the stored variable // rows to return $limit=10; // check for an empty string and display a message. if ($trimmed == "") { echo "<p>Please enter a search...</p>"; exit; } // check for a search parameter if (!isset($var)) { echo "<p>We dont seem to have a search parameter!</p>"; exit; } //connect to your database ** EDIT REQUIRED HERE ** mysql_connect("localhost","root",""); //(host, username, password) //specify database ** EDIT REQUIRED HERE ** mysql_select_db("school") or die("Unable to select database"); //select which database we're using // Build SQL Query $query = mysql_query("SELECT * FROM main WHERE username LIKE '%".$trimmed."%' ORDER BY username") or die(mysql_error()) ; // EDIT HERE and specify your table and field names for the SQL query $numresults=mysql_query($query); $numrows=mysql_num_rows($numresults); // If we have no results, offer a google search as an alternative if ($numrows == 0) { echo "<h4>Results</h4>"; echo "<p>Sorry, your search: "" . $trimmed . "" returned zero results</p>"; echo "<p><a href=\"http://www.google.com/search?q=" . $trimmed . "\" target=\"_blank\" title=\"Look up " . $trimmed . " on Google\">Click here</a> to try the search on google</p>"; } // next determine if s has been passed to script, if not use 0 if (empty($s)) { $s=0; } // get results $query .= " limit $s,$limit"; $result = mysql_query($query) or die(mysql_error()) ; // display what the person searched for echo "<p>You searched for: "" . $var . ""</p>"; // begin to show results set echo "Results"; $count = 1 + $s ; // now you can display the results returned while ($row= mysql_fetch_array($result)) { $title = $row["1st_field"]; echo "$count.) $title" ; $count++ ; } $currPage = (($s/$limit) + 1); //break before paging echo "<br />"; // next we need to do the links to other results if ($s>=1) { // bypass PREV link if s is 0 $prevs=($s-$limit); print " <a href=\"$PHP_SELF?s=$prevs&q=$var\"><< Prev 10</a>  "; } // calculate number of pages needing links $pages=intval($numrows/$limit); // $pages now contains int of pages needed unless there is a remainder from division if ($numrows%$limit) { // has remainder so add one page $pages++; } // check to see if last page if (!((($s+$limit)/$limit)==$pages) && $pages!=1) { // not last page so give NEXT link $news=$s+$limit; echo " <a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>"; } $a = $s + ($limit) ; if ($a > $numrows) { $a = $numrows ; } $b = $s + 1 ; echo "<p>Showing results $b to $a of $numrows</p>"; ?> Lines: Code: [Select] 35 == $numresults=mysql_query($query); 36 == $numrows=mysql_num_rows($numresults); 59 == $result = mysql_query($query) or die(mysql_error()) ; -- You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Resource id #3 limit 0,10' at line 1 Help Please.. Getting the following error message: Warning: mysql_fetch_array() expects parameter 1 to be resource, null given in This error occurs when I first navigate to the search page. When I put a search term in the box and click search it works fine and the error is gone. I've been trying to figure this out for days with no luck, any help you can offer would be greatly appreciated. Code: [Select] <?php require('config.php'); ?> <?php $conn = mysql_connect(SQL_HOST, SQL_USER, SQL_PASS) or die('Could not connect to MySQL database. ' . mysql_error()); mysql_select_db(SQL_DB, $conn); $result = NULL; if (isset($_GET['keywords'])) { $sql = "SELECT id, hostname, ip, clust_name, clust_ip, node_name, ". "node_ip, os, patch " . "FROM serv_main " . "WHERE MATCH (hostname,ip) " . "AGAINST ('" . $_GET['keywords'] . "' IN BOOLEAN MODE) " . "ORDER BY MATCH (hostname,ip) " . "AGAINST ('" . $_GET['keywords'] . "' IN BOOLEAN MODE) DESC"; $result = mysql_query($sql) or die('Could not perform search; ' . mysql_error()); } ?> <html> <body> <form method="get" action="search.php"> <p class="head">Type in the Server name below to search for an SLA</p> <p> <input id="searchkeywords" type="text" name="keywords" <?php if (isset($_GET['keywords'])) { echo ' value="' . htmlspecialchars($_GET['keywords']) . '" '; } ?> > <input id="searchbutton" class="submit" type="submit" value="Search"> </p> <?php echo "<h1>Search Results</h1>\n"; if ($result and !mysql_num_rows($result)) { if (isset($_GET['keywords'])) { $k = $_GET['keywords']; } echo "<p>No SLA for <b><font size=\"6\" color=#990000>" . $k . "</b></font> found.</p>\n"; } else { $bg = ''; //Error occurs right here********************* while ($row = mysql_fetch_array($result)) { //($row['id'], TRUE); $bg = ($bg=='F2F2FF'?'99CCCC':'F2F2FF'); $table = "<table border=\"0\" cellpadding=\"5\">"; $table .= "<tr bgcolor=\"#" . $bg . "\">" . "<td><a href=\"servedit.php?s=" . $row['id'] . "\">" . $row['hostname'] . "</a></td><td>" . $row['ip'] . "</td><td align=\"center\">" . $row['clust_name'] . "</td><td>" . $row['clust_ip'] . "</td><td>" . $row['node_name'] . "</td><td>" . $row['node_ip'] . "</td><td>" . $row['os'] . "</td><td>" . $row['patch'] . "</td></tr>"; } $table .= "</table>"; echo $table; } ?> </form> </body> </html> MOD EDIT: [code] . . . [/code] tags added. Hi I am finding that I get a random LDAP search fail the initial time i run a script against 2008R2 when I refresh all is ok ? PHP 5.2.5 get the same thing with the latest version of PHP. any ideas ? its as if the DC is sleeping until you give it a nudge, running on 2008R2 running on vmware. Hi, Im trying to do a search engine. However, im facing this errors.. Anyone can help.. Error : Notice: Undefined variable: searching in C:\wamp\www\i-document\s.php on line 17 Thankz in advance. Code: [Select] <h2>Search Form</h2> <form name="search" method="post" action="s.php"> Seach for: <input type="text" name="find" /> in <Select NAME="field"> <Option VALUE="file_name">File Name</option> <Option VALUE="year">Year</option> <Option VALUE="downer">Owner</option> < </Select> <input type="hidden" name="searching" value="yes" /> <input type="submit" name="search" value="Search" /> </form> <?php if ($searching =="yes"){ echo "<h3>Search Results</h3><p>"; if ($find == ""){ echo "<p>Please Enter a search term"; exit; } include "config.php"; $find = strtoupper($find); $find = strip_tags($find); $find = trim ($find); $query = mysql_query("SELECT * FROM document WHERE upper($field) LIKE'%$find%'"); while($result = mysql_fetch_array($query)){ echo $result['file_ref']; echo " "; echo $result['file_name']; echo "<br>"; echo $result['owner']; echo "<br>"; echo "<br>"; } $matches=mysql_num_rows($query); if ($matches == 0){ echo "Sorry, we can not find an entry to match your query<br><br>"; } echo "<b>Searched For:</b> " .$find; } ?> Just take a look at the code.. idk whats wrong. <?php // Get the search variable from URL $var = @$_GET['q'] ; $trimmed = trim($var); //trim whitespace from the stored variable // rows to return $limit=10; // check for an empty string and display a message. if ($trimmed == "") { echo "<p>Please enter a search...</p>"; exit; } // check for a search parameter if (!isset($var)) { echo "<p>We dont seem to have a search parameter!</p>"; exit; } //connect to your database ** EDIT REQUIRED HERE ** mysql_connect("localhost","root",""); //(host, username, password) //specify database ** EDIT REQUIRED HERE ** mysql_select_db("school") or die("Unable to select database"); //select which database we're using // Build SQL Query $query = "select * from the_table where 1st_field like \"%$trimmed%\" order by 1st_field"; // EDIT HERE and specify your table and field names for the SQL query $numresults=mysql_query($query); $numrows=mysql_num_rows($numresults); // If we have no results, offer a google search as an alternative if ($numrows == 0) { echo "<h4>Results</h4>"; echo "<p>Sorry, your search: "" . $trimmed . "" returned zero results</p>"; echo "<p><a href=\"http://www.google.com/search?q=" . $trimmed . "\" target=\"_blank\" title=\"Look up " . $trimmed . " on Google\">Click here</a> to try the search on google</p>"; } // next determine if s has been passed to script, if not use 0 if (empty($s)) { $s=0; } // get results $query .= " limit $s,$limit"; $result = mysql_query($query) or die("Couldn't execute query"); // display what the person searched for echo "<p>You searched for: "" . $var . ""</p>"; // begin to show results set echo "Results"; $count = 1 + $s ; // now you can display the results returned while ($row= mysql_fetch_array($result)) { $title = $row["1st_field"]; echo "$count.) $title" ; $count++ ; } $currPage = (($s/$limit) + 1); //break before paging echo "<br />"; // next we need to do the links to other results if ($s>=1) { // bypass PREV link if s is 0 $prevs=($s-$limit); print " <a href=\"$PHP_SELF?s=$prevs&q=$var\"><< Prev 10</a>  "; } // calculate number of pages needing links $pages=intval($numrows/$limit); // $pages now contains int of pages needed unless there is a remainder from division if ($numrows%$limit) { // has remainder so add one page $pages++; } // check to see if last page if (!((($s+$limit)/$limit)==$pages) && $pages!=1) { // not last page so give NEXT link $news=$s+$limit; echo " <a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>"; } $a = $s + ($limit) ; if ($a > $numrows) { $a = $numrows ; } $b = $s + 1 ; echo "<p>Showing results $b to $a of $numrows</p>"; ?> its supposed to search my databases i guess.. i need a site searcher if anyone wanna make me post it please.. or post a tut I made a search engine to search my database for specific users ( well I used a tutorial ). I'm not getting any errors atleast when loading the page which is a first for me. However, now I am tackled by something new. When entering the keywords and submitting the search I get: Access forbidden! You don't have permission to access the requested object. It is either read-protected or not readable by the server. If you think this is a server error, please contact the webmaster. Error 403 127.0.0.1 04/30/07 11:09:21 Apache/2.2.16 (Win32) PHP/5.3.3 Which is odd for me because I am using the same config.php with connection code to connect to the db which I used with all my other pages. And in those pages I have been able to add/delete/edit and display records from the database tables. Does this have something to do with it being a search engine? Here is my code: Code: [Select] <html> <head> </head> <body> <h2>Search</h2> <form name="search" method="post" action="<?=$PHP_SELF?>"> Seach for: <input type="text" name="find" /> in <Select NAME="field"> <Option VALUE="fname">First Name</option> <Option VALUE="sname">Last Name</option> <Option VALUE="sno">Profile</option> </Select> <input type="hidden" name="searching" value="yes" /> <input type="submit" name="search" value="Search" /> </form> </body> </html> <?php //This is only displayed if they have submitted the form $searching ='searching'; if ($searching =="yes") { echo "<h2>Results</h2><p>"; //If they did not enter data then they receive an error if ($find == "") { echo "<p>You forgot to enter a search term"; exit; } // Otherwise connect to database include 'includes/config.php'; include 'includes/functions.php'; connect(); // filtering $find = strtoupper($find); $find = strip_tags($find); $find = trim ($find); // search for term in specified field $data = mysql_query("SELECT * FROM student WHERE upper($field) LIKE'%$find%'"); // display results while($result = mysql_fetch_array( $data )) { echo $result['fname']; echo " "; echo $result['sname']; echo "<br>"; echo $result['sno']; echo "<br>"; echo "<br>"; } //Counts number or results and display message if there we're non $anymatches=mysql_num_rows($data); if ($anymatches == 0) { echo "Sorry, but we can not find an entry to match your query<br><br>"; } //And we remind them what they searched for echo "<b>Searched For:</b> " .$find; } ?> Any ideas? Thanks in advance Hey All, I'm trying to add multiple word search to my site and I'm getting the following error: "mysql_num_rows(): supplied argument is not a valid MySQL result resource " I know, my search is posting because I'm getting my search terms back with the "nothing found" message I have set up. Here's what I have: Code: [Select] $search = $_POST["search"]; $arraySearch = explode(" ", $search); $arrayFields = array(0 => "title", 1 => "content"); $countSearch = count($arraySearch); $a = 0; $b = 0; $query = "SELECT * FROM table1 WHERE desc LIKE '$arraySearch'"; $countFields = count($arrayFields); while ($a < $countFields) { while ($b < $countSearch) { $query = $query."$arrayFields[$a] LIKE '%$arraySearch[$b]%'"; $b++; if ($b < $countSearch) { $query = $query." AND "; } } $b = 0; $a++; if ($a < $countFields) { $query = $query.") OR ("; } } $query = $query.")"; $query_result = mysql_query($query); if(mysql_num_rows($query_result) < 1) { echo '<p>No matches found for "'.$search.'"</p>'; } else { Print "<table border cellpadding=3>"; while($row = mysql_fetch_assoc($query_result)) { Print "<th>Description:</th> <td>".$row['desc']. "</td> "; } Print "</table> "; } You guys are the best, thanks so much. //get the search variable from the FORM$function_keywords = mysql_real_escape_string($_POST['function_keywords']);//trim whitespace from the stored variable$trimmed = trim($function_keywords);//separate key-phrases into keywords$trimmed_keywords = explode(" ",$trimmed);// Build SQL Query for each keyword enteredforeach ($trimmed_keywords as $trimm){// MySQL "MATCH" is used for full-text searching.//this code is ebv weird , should check out soon!$query = "SELECT * , MATCH (function_description) AGAINST ('".$trimm."') AS score FROM table_name WHERE MATCH (function_description) AGAINST ('+".$trimm."') ORDER BY score DESC "; // Execute the query to get number of rows that contain search kewords $results=mysql_query ($query,$connection); $row=""; $row =$row . mysql_fetch_array($results, MYSQL_BOTH);} $row_num=mysql_num_rows ($row); if($row_num < 1){ redirect("welcome.php?search=fail"); } else if ($row_num > 1){ ?> <html> <head> <title>Search results</title> </head> <body> <?php foreach($row as $row_result){ echo "function name : {$row_result['function_name']} --- function Description : {$row_result['function_description']}<br/><br/>"; }?> </body> </html>() IS there an error on the SQL syntax ? or its about ? : Code: [Select] $results=mysql_query ($query,$connection); $row=""; $row =$row . mysql_fetch_array($results, MYSQL_BOTH); } $row_num=mysql_num_rows ($row); The dreadful apostrophie problem... This search form returns an error whenever searching with an apostrophie (') Here's the code on the form (html) <td align="center" width="135"><form method="post" action="srch_advert.php"><input type=text name='search' size=15 maxlength=255><br><input type=submit></form></td> <td align="center" width="135"><form method="post" action="srch_details.php"><input type=text name='search' size=15 maxlength=255><br><input type=submit></form></td> <td align="center" width="135"><form method="post" action="srch_artist.php"><input type=text name='search' size=15 maxlength=255><br><input type=submit></form></td> <td align="center" width="135"><form method="post" action="srch_track.php"><input type=text name='search' size=15 maxlength=255><br><input type=submit></form></td> and heres the code on srch_advert.php if ($search) // perform search only if a string was entered. { mysql_connect($host, $user, $pass) or die ("Problem connecting to Database"); $srch="%".$search."%"; $query = "select * from tvads WHERE advert LIKE '$srch' ORDER BY advert, year DESC, details ASC LIMIT 0,30"; $result = mysql_db_query("cookuk_pn", $query); if(mysql_num_rows($result)==0) { print "<h2>Your search returned 0 Results</h2>"; } else if ($result) { The result pages is supposed to have pagination like google help me please
Hey guys so I am making an App website and somehow need to make a developer section. So like developers can come and setup their app name,description etc. Then be able to program there own app and use like an API service to get the user username etc. So what would I need to let developers do a such thing like let them make an API key and all that is there some tutorial to make such service. (This will be an important feature to my website so please help, thanks)
Hi php freaks I've been learning php, but what confuses me are the arrays. I have ini file, i want to get the data from file and add it to the database. Every section makes a new table and all they keys are added with their values. I figured out how to get the keys and how to see the values, but how can i get the name of the sections. Furthermore, how do i know what keys belong to what section. I am really grateful for person who helps me to realize how to be a good friend with those complicated arrays. Can i open a pdf within a page? e.g. within <td> or <table> of htmls so that it appears on a section of a page where someone can just read through and still able to browse the web page. I dont want the PDF downloading or taking the whole page or even opening a new window and filling it. Thanks in advance. Hello. Well I haven't any code for this, but its only a question. Do you think it would be possible for PHP, to make and image or draw one from just a blank JPG. Then placing text on the image. That is possible and quite simple. But do you think it is possible to say. Say if you have 3 different set of texts on the image. Click here for 1 Click here for 2 Click here for 3 And also for the script to link those text to different web addresses. But all still workable with a dynamic signature EG [ img ] [ / img ] Basically its a dynamic signature with links on it is what i am trying to say. Do you think its possible? Or am I thinking to big. I think it would be interesting and useful to many to make a do and don't section or pinned post for most sections.
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Like the phpfreaks bible of coding, best practices.
A lot of members post some valuable information that gets lost old posts or too hard to search for.
Everyone repeating themselves on bad practices or deprecated code, turning on error reporting and such.
I would love to add a comment section to my music blogging site. Does anyone have some simple code that they would not mind sending me? or at least helping me with this situation? Hi! I'd like to echo a text section from pageB.php to pageA.php Is it possible to mark it up somehow and tell the browser to echo the variable? I'm thinking something like this should work after some alteration: pageA: <?php echo pageb.php/variable; ?> pageB: <?php $variable = ***the content section I want to be displayed on pageA*** "; ?> I'd be very grateful if someone could help me out. (: |