PHP - Function With Required File And Variables
I have a php file with a bunch of variables declared. I now need a function to put data on a separate page that pulls variables from the required page. <?php function getplayer($position) { // start function //$new_position = "$" . $position; $new_position = $position; $file = "their.php"; require "$file"; //echo $qb1; this displays the name John Doe...as $qb1 is declared in the required file $db_select_their = "bschultz_their"; $servername = "localhost"; $username = "user"; $password = "pass"; $dbname = "db_name"; // Create connection $conn = new mysqli($servername, $username, $password, $dbname); // Check connection if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } $sql = "SELECT * FROM (select number as position_number, name as position_name, pronunciation as position_pronunciation, pos as position_pos, height as position_height, weight as position_weight, year as position_year, city as position_city, state as position_state, notes as position_notes FROM $db_select_their WHERE name = '$new_position') as position"; //$sql = "SELECT * FROM bschultz_their WHERE name = $new_position"; echo $sql; //exit; /* this displays this text... SELECT * FROM (select number as position_number, name as position_name, pronunciation as position_pronunciation, pos as position_pos, height as position_height, weight as position_weight, year as position_year, city as position_city, state as position_state, notes as position_notes FROM bschultz_their WHERE name = '') as position The name is empty */ $result = $conn->query($sql); if ($result->num_rows > 0) { // output data of each row while($row = $result->fetch_assoc()) { echo "#: " . $position_number . " - Name: " . $position_name . ""; } } else { echo "0 results"; } } // end function getplayer("${$qb1}"); $conn->close(); ?>Edited September 8, 2019 by bschultz Similar TutorialsI am trying to pass a variable from inside of a function in a file that is included eg include.php Code: [Select] <? function noms(){ $foobar = "apples"; } ?> main.php Code: [Select] <? include("include.php"); noms(); echo "these ". $foobar. " are most delicious... OM NOM NOM"; ?> I am essentially using a include file for a mysql connection and based on the connection outcome i am either setting a value to true or false. It prints "Connected succesfully" and what not just fine, but, after that it wont pass on the variables data. I know its the function because, it passes the data if i put the variable before the function... i just dont get it.. any help would be great. Thanks. Ansel I have a file, test.php. It has a require statement to include line.php. Now on normal load, I can access the variables set in test.php in line.php. However, I also have an automated reload of line.php using AJAX, where I send a request to access the file and it outputs the same information. HOWEVER, in this case, the variables set in test.php can no longer be access :s .. why is that? I haven't set any data to be passed in the request, but I assume this doesn't have to be done. Hello All I currently have a function that takes in user input from form fields $email & $password. If all is well the function logs the user in, if not redirects back to the login form. What I require is two things. 1) Allow the user to login with either "email" or "username" (entered in the $email form field). 2) Allow the system to have a "master" password and if that is entered with a valid email or user from above then log that user in. Here is my current function, any help is greatly received. Regards function loginMember($email,$password,$returnURL){ if ($email != "" && $password != ""){ $result = mysql_query("SELECT mid,memberid,forename,surname FROM tbl001_member WHERE emailaddress='$email' AND password='".$password."' AND online=1"); if (mysql_num_rows($result) > 0) { $row = mysql_fetch_row($result); $_SESSION["logged_user"] = $row[2]." ".$row[3]; $_SESSION["logged_id"] = $row[0]; $_SESSION["logged_memid"] = $row[1]; session_unregister('wrong_email'); if (isset($_SESSION["logged_user"])) { header('Location:'.$returnURL); exit; } } else { session_register('wrong_email'); $_SESSION['wrong_email'] = $email; return "* There is no registered account with typed email & password."; } } else { session_register('wrong_email'); $_SESSION['wrong_email'] = $email; return "* Please input email and password correctly."; } } Hi, I need some help in saving the filename along with the extension in the database after i upload the file. Current Scenario: I am able to upload the file successfully and save the form details in the database. Problems: When file uploaded with same file name it overwrites the old file. How do i give the file a unique name when uploading the file and then saving the form details along with the new file name given? CODE USED TO SAVE THE FILE TO MYSQL AND UPLOAD THE FILE: <?php //This is the directory where images will be saved $target = "image/"; $target = $target . basename( $_FILES['photo']['name']); //This gets all the other information from the form $name=$_POST['name']; $email=$_POST['email']; $phone=$_POST['phone']; $pic=($_FILES['photo']['name']); // Connects to your Database mysql_connect("localhost", "data_admin2", "data25") or die(mysql_error()) ; mysql_select_db("Resumebank") or die(mysql_error()) ; //Writes the photo to the server move_uploaded_file($_FILES['photo']['tmp_name'], $target); //Writes the information to the database mysql_query("INSERT INTO `employee` VALUES ('$name', '$email', '$phone', '$pic')") ; echo "The file has been uploaded, and your information has been added to the directory"; ?> What should I do? Please help! This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=359179.0 I have a script that uses two functions and a simple switch statement. If I wanted to take the value of variables from function 1 and use them in function 2, would I have to declare them global in both functions, function 1, function 2, or outside the functions? For example Code: [Select] <?php function function_1() { //Here? global $variable_1; $variable_1 = hello world; return $variable_1 } function function_2() { //Or Here? global $variable_1; echo $variable_1 } //Or here? global $variable_1 //Or in all three places? I want the variable to be available everywhere in the script! ?> Hello I have a table with four variables. By choosing each of the variables we obtain a numerical value. I have a form with each of the variables to be selected and what I meant was that it appeared the value without having to place the table on page. step I (VAR 1) VAR2 VAR3 8h 10h 12h 14h 16h 18h(VAR4) A 0-30 4 2 1 1 2 4 A >30 1 3 2 4 5 3 B 0-30 7 6 4 6 4 3 B >30 4 5 3 6 3 5 C 0-30 2 2 2 2 1 8 C >30 8 8 5 6 2 2 D 0-30 6 9 8 2 8 8 D >30 5 5 6 8 6 8 step II (VAR1) VAR2 VAR3 8h 10h 12h 14h 16h 18h(VAR4) A >30 2 3 5 8 2 6 B >30 2 8 2 9 8 8 C >30 8 9 2 8 5 2 D >30 8 2 1 8 2 9 step I and step II is the first variable, then we have to see if it was A, B or C (second variable) and perhaps more complicated if the input value is between 0 - 30 or >30 (third variable) in stage I or greater than zero (third variable) in step II. The four variable was the hours. Have any suggestions on how I do this? Thanks Hello, I am trying to define some variables in a function, but the variable just returns null no matter what I do. Could someone please tell me what I'm doing wrong? Code: [Select] <?php function checkname() { global $t; if($_SESSION['name'] == '') { return false; $t = false; } elseif(isset($_POST['cont']) && $_SESSION['name'] != '') { return true; $t = true; } } var_dump($t); // returns NULL upon correct or incorrect submit. ?> I have a php script. I defined a variable outside of a function, but i cannot echo the variable inside the function. When I execute this: <?PHP $testvar = "test worked!"; testfunction(); function testfunction(){ echo $testvar; } ?> Nothing happens. what am i doing wrong. I did this on my local host. Apache running on Windows Vista Ultimate 32 bit Edition. Thanks in advance. Hello everyone, Can someone show me a way how to pass $_post variable from a form to a function? So, input username and input password to a function login($username, $password). Hello I've have read that global variables should not be used. so if i have 2 .php files: index.php - main content php file sitefunctions.php - php functions site file on my index.php page i have the following (an example of my problem): <?php displayError($errorID); ?> and in the sitefunctions.php file i have the following (an example of my problem): <?php function displayError($errorID) { if($errorID == 1) { echo "Password Failure"; } else { echo "Other Failure"; } } ?> now that works but since when first accesing that page the $errorID is not set then i get an error. How can i achieve this without first setting a blank $errorID global variable? Thanks Hi all I am having some issues basically Code: [Select] $sftp->put("server.properties", "allow-nether=".$nether." level-name=".$lname.""); is not printing the variables. $sftp is part of the phpseclib and the fuction is in the same format as fwrite(), I have tried and failed using fwrite as well! I can echo out the 1st variable correctly, but as soon as I add the second I just get Code: [Select] allow-nether= level-name= The variables $nether and $lname exist and I have echo'd them to check. I guess this is a formatting problem, just cant work it out! So say I have a file with the contents.. Code: [Select] ; this is a comment var2 : variable ; another comment var3 : file.txt how would I be able to do <?php echo $var2; ?> That would echo "variable" and <?php $file = file($var3); ?> So its reading the file to get the variable from the text file and if the line starts with ";" its disregarded.. Thanks Hi, I am trying to create a login system in PHP, but I am not the greatest at PHP so I am using a source code which I found online as I found it to be more secure as it uses things like salted passwords. Anyway I am trying to add more fields to the register system so it adds them to the mysql, the source has a way to do this with arrays, but it is quite complicated so I am just using variables from the original file. There are 2 files: register.php and class.loginsys.php which contains all the functions. At first the query syntax was incorrect so I decided to use the variables created in register.php in the class.loginsys, but now it's giving me an out of memory error: Fatal error: Allowed memory size of 134217728 bytes exhausted (tried to allocate 28672 bytes) in C:\xampp\htdocs\ls\class.loginsys.php on line 34 Which I am unsure of how to fix. I have tried using different variable names, checking the line, checking the whole register.php file for anything rogue. Here is the code: Top part of register.php <?php include "config.php"; ?>Config.php: <?php require "class.loginsys.php"; $LS=new LoginSystem(); ?>Then actual register part from register.php: <?php if( isset($_POST['submit']) ){ $firstname2 = $_POST['firstname']; $lastname2 = $_POST['lastname']; $user2 = $_POST['username']; $sex2 = $_POST['sex']; $country2 = $_POST['strCountryChoice']; $email2 = $_POST['email']; $pass2 = $_POST['pass']; $pass3 = $_POST['pass2']; $birthdate2 = $_POST['birthdate']; $created2 = date("Y-m-d H:i:s"); //need to add a lot more validation functions.. AKA Check if email exists and username. Password > 5 chars if( $user2=="" || $email2=="" || $pass2=='' || $pass3=='' || $firstname2=='' || $lastname2=='' || $sex2=='' || $country2=='' || $birthdate2=='' ){ echo "Fields Left Blank","Some Fields were left blank. Please fill up all fields."; exit; } if( !$LS->validEmail($email2) ){ echo "E-Mail Is Not Valid", "The E-Mail you gave is not valid"; exit; } if( !ctype_alnum($user2) ){ echo "Invalid Username", "The Username is not valid. Only ALPHANUMERIC characters are allowed and shouldn't exceed 10 characters."; exit; } if($pass2 != $pass3){ echo "Passwords Don't Match","The Passwords you entered didn't match"; exit; } $createAccount2 = $LS->register($user2, $pass2, array( "email" => $email2, "name" => $firstname2, "lastname" => $lastname2, "gender" => $sex2, "country" => $country2, "DOB" => $birthdate2, "created" => date("Y-m-d H:i:s") // Just for testing ) ); //$createAccount = $LS->register($firstname,$lastname,$user,$sex,$country,$email,$pass,$birthdate,$created); if($createAccount2 === "exists"){ echo "User Exists."; }elseif($createAccount2 === true){ echo "Success. Created account."; } } ?>And the function from the class: /* A function to register a user with passing the username, password and optionally any other additional fields. */ public function register( $id, $password, $other = array() ){ if( $this->userExists($id) && (isset($other['email']) && $this->userExists($other['email'])) ){ return "exists"; }else{ $randomSalt = $this->rand_string(20); $saltedPass = hash('sha256', "{$password}{$this->passwordSalt}{$randomSalt}"); if( count($other) == 0 ){ /* If there is no other fields mentioned, make the default query */ //old query: ("INSERT INTO `{$this->dbtable}` (`username`, `password`, `password_salt`) VALUES(:username, :password, :passwordSalt)"); //new query: ("INSERT INTO `{$this->dbtable}` (`username`, 'email' , `password`, `password_salt` , 'name' , 'lastname' , 'gender' , 'country' , 'DOB') VALUES(:username, :email, :pass, :passwordSalt, :firstname, :lastname, :gender, :country, :DOB)"); $sql = $this->dbh->prepare("INSERT INTO `{$this->dbtable}` (`username`, `password`, `password_salt`) VALUES(:username, :password, :passwordSalt)"); }else{ /* if there are other fields to add value to, make the query and bind values according to it */ //old query: ("INSERT INTO `{$this->dbtable}` (`username`, `password`, `password_salt`, $columns) VALUES(:username, :password, :passwordSalt, :$colVals)"); //new query: ("INSERT INTO `{$this->dbtable}` (`username`, 'email' , `password`, `password_salt` , 'name' , 'lastname' , 'gender' , 'country' , 'DOB') VALUES(:username, :email, :pass, :passwordSalt, :firstname, :lastname, :gender, :country, :DOB)"); $keys = array_keys($other); $columns = implode(",", $keys); $colVals = implode(",:", $keys); //l= $this->dbh->prepare("INSERT INTO `{$this->dbtable}` (`username`, `password`, `password_salt`, $columns) VALUES(:username, :password, :passwordSalt, :$colVals)"); //INSERT INTO MyGuests (firstname, lastname, email)cLUES ('John', 'Doe', 'john@example.com') $sql = $this->dbh->prepare("INSERT INTO `{$this->dbtable}` (username,email,password,password_salt,name,lastname,created,gender,country,DOB) VALUES ('$username2','$email2','$pass2','$saltedPass','$firstname2','$lastname2','$created2','$gender2','$country2','$birthdate2')"); print($sql); foreach($other as $key => $value){ $value = htmlspecialchars($value); $sql->bindValue(":$key", $value); } } /* Bind the default values */ $sql->bindValue(":username", $id); $sql->bindValue(":password", $saltedPass); $sql->bindValue(":passwordSalt", $randomSalt); $sql->execute(); return true; } }Thanks for your help. I am doing this because for a hobby I am trying to create a browser based game in which I use this login system to login the user to a main page then code all of the other pages myself. I have posted on stackoverflow and someone on their suggested that I should use a framework. If this is the case, can someone point me in the right direction? Thanks again, if you need any info ask. So here is what I have going. #1 - My weather station software processes a file and enters variables and then uploads it as a php file. #2 - Currently the station also just uploads every file to the site and enters the data in the html, but I would rather have it only upload this one file and the other pages grab data from it and print it out. I have a few php scrips in there to preform certain functions (if temp <= 32 it echos that data in blue and so on) but would rather make most of it php so I have less files being uploaded every 5 minutes. This is what the station sends to the web, but I have no idea how to get the other pages to read it and input the variables from it. Right, so I've made a very simple web app that allows.... 1.) People to register (adding them to the MySQL database) 2.) Login (providing they're in the database) I've gotten it all working, but I'm stuck at the last hurdle. If someone logs in using the correct username and password, it takes them to login_success.php. Here I query the database and use "SELECT * FROM Users WHERE Username = '$name'" I would have thought, that it would have returned that user's entry in the database. But instead I just get a blank page. Am I right in thinking that's because the contents of the $name variable aren't passed from log.php to login_success.php If so, how do I fix it? ---------------------------------------------------------------------------------------------------- LOGIN.PHP Code: [Select] <?php include_once "Common/header.php"; session_name("MyLogin"); $page = (isset($_GET['login']) ? strtolower($_GET['login']) : NULL); if($page == "failed"){ print $_GET['cause']; } ?> <div id="main"> <br />   <br />  <br /> <h2>Sign In</h2>   <form name="form1" method="post" action="log.php?action=login"> <b>Username:</b>  <input type="text" name="uname"/><br />  <br /> <b>Password:</b>                 <input type="password" name="pword" /><br />  <br /> <input type="submit" value="submit" /> </form> <?php include_once "Common/footer.php"; ?> LOG.PHP Code: [Select] <?php session_name("MyLogin"); session_start(); if($_GET['action'] == "login") { $conn = mysql_connect("localhost", "root", ""); $db = mysql_select_db("test"); $name = ($_POST['uname']); $word = ($_POST['pword']); $sql = "SELECT * FROM Users WHERE Username='$name' and Password='$word'"; $q_user = mysql_query($sql) or die(mysql_error() . ' <br /> in ' . $sql); if(mysql_num_rows($q_user) == 1){ $_SESSION['uname'] = $_POST['uname']; header("Location: login_success.php"); exit; } else{ header("Location: login.php?login=failed&cause=".urlencode('Invalid Username or Password')); exit; } } else{ header("Location: login.php?login=failed&cause=".urlencode('Invalid User')); exit; } if(session_is_registered("name") == false) { header("Location: login.php"); } ?> LOGIN_SUCCESS.PHP Code: [Select] <?php include_once "Common/header.php"; $connect=mysql_connect("localhost", "root", "")or die ("Could not connect to database"); $data = mysql_query("SELECT * FROM Users WHERE Username ='$name'") or die(mysql_error()); Print "<table border cellpadding=3>"; while($info = mysql_fetch_array( $data )) { Print "<tr>"; Print "<th>First Name:</th> <td>".$info['First_Name'] . "</td> "; Print "<th>Last:</th> <td>".$info['Last_Name'] . " </td></tr>"; } Print "</table>"; ?> Login Successful <?php include_once "Common/footer.php"; ?> Okay I have a function that stores data into an Array. The function takes about 7 seconds to run and through a number of different loops it creates one final array with about 15,000 keys. I want to recall this data a number of times in different functions, however how can I have this data easily accessible without running the function each time. EX: Code: [Select] function theFunction() { for($x=0;$x,=15000;$x++) { //Run the loop and store data. $string[$x] = //output from other loops and calculations } return $string } //Then later on if I want to recall the data the only way I know how is to do the follow: $newstring = theFunction() The only problem I have with this is that it has to re-run the function every time in order to get to the data it spits out. How can I store this data into another array outside of the function without having to re-run it? I hope this makes sense. Thanks. Hey guys, I want to pass the unique id of a node to a function when that image is clicked. Actually i am a newbee in php so don't know what to search about or where to look for it,but find this place and you all guys so helpful so i am asking for a guide here Hey ive been wanting to know how to make a function call another function which will then create a variable which i can send back to first function where i can use it. I tried somthing like this Code: [Select] <?php a(); function a($wall) { b(); echo $wall; } function b() { $wall = "test"; #a($wall); } ?> Thats what i tried but ofcourse didnt work, how would i go about doing this? Thanks. |