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PHP - Creating A Gif From Images In A Directory..
So, We are trying to create a animation using the gifs in a directory by using the first 10 images. We just cannot figure out how to do the animation..
needs to have a 3 second delay between each frame Heres the code at the moment. Which creates the starting images and also sorts the images in the directory by time.. <?php $time = date("YmdHis"); $handle_data = file_get_contents('http://www.bungie.net/Stats/Halo3/Nightmap.ashx'); $img = new Imagick(); $img->readImageBlob($handle_data); $img->writeImage('nightmap/'.$time.'.gif'); foreach (glob('nightmap/*.gif') as $f) { # store the image name $list[] = $f; } sort($list);# sort is oldest to newest, $gif_0 = array_pop($list); $gif_1 = array_pop($list); $gif_2 = array_pop($list); $gif_3 = array_pop($list); $gif_4 = array_pop($list); $gif_5 = array_pop($list); $gif_6 = array_pop($list); $gif_7 = array_pop($list); $gif_8 = array_pop($list); $gif_9 = array_pop($list); ?> Similar TutorialsI am trying to create random no. of directories but its always giving this error Warning: mkdir() [function.mkdir]: Invalid argument in C:\xampp\htdocs\gl\movie_process.php on line 173 the code is for(i=0; i<5; i++) { mkdir("".$base."uploads/movies/$year/$month/$title/".$hosting[$i].""); } I have a script that will create a directory just fine but, I found a different script that I am trying to have it create a directory if necessary otherwise it will echo that the directory exists. As of right now I am just getting a 'Warning: mkdir() [function.mkdir]: File exists' My current code: Code: [Select] if (!file_exists($folder)) { mkdir ("../images/upload/upimg/$folder", 0777); mkdir ("../images/upload/thimg/$folder", 0777); }else { echo "Directory previously created, file uploaded successfully."; } Any help would be appreciated. Hi, I have a list of images from a directory that are in order by their "id". How could I display one at a time on a page--starting from the beginning, and have it so the user can click on the image and go to the next one in line. How can i display all the images in a certain directory and echo the image names. So if a new image is uploaded, it will still display without edited the gallery.php file. Cheers. Hi, i want to make an image gallery, this is the first step. uploading files. below is the code I am using , but don't i have to include info about the server? i dont know what to include since it is the server I am working with and not a database, any help greatly appreciated. thanks Code: [Select] <?php // Where the file is going to be placed $target_path = "uploads/"; /* Add the original filename to our target path. Result is "uploads/filename.extension" */ $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else{ echo "There was an error uploading the file, please try again!"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> </body> </html> ok I got the images to upload to the directory on the server. now I got some code to try to display the image on the same page after you submit it to the directory. so it's like, submit form-> images goes in server directory->echoes back out on same page but just above the upload form. please any help greatly appreciated. thanks. here is the code so far. Code: [Select] <?php // An Example about listing Images. $dir = "uploads/"; $odir = opendir($dir); while($file = readdir($odir)){ if(filetype($file) == "image/JPEG") { echo $file; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <p>UPLOAD YOUR PORTFOLIO AND PRICES</p> <p> </p> <p> <form enctype="multipart/form-data" action="uploader.php" method="POST"> <input type="hidden" name="MAX_FILE_SIZE" value="100000" /> Choose a file to upload: <input name="uploadedfile" type="file" /><br /> <input type="submit" value="Upload File" /> </form></p> </body> </html> Hi, I am trying to echo out images on my server's directory "uploads". The images are blank and not showing up. Please help if anyone can. Thank you. here is the page as it is. http://ealike.com/simple_uploader/uploader.php and here is the code. Code: [Select] <?php // Where the file is going to be placed $target_path = "uploads/"; /* Add the original filename to our target path. Result is "uploads/filename.extension" */ $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else{ echo "There was an error uploading the file, please try again!"; } //echo out all images $dir = "uploads/"; if (is_dir($dir)) { if ($dh = opendir($dir)) { while (($file = readdir($dh)) !== false) { echo "<img src='$file' alt='$file' height='200' width='200' /> " ; } closedir($dh); } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> </body> </html> I currently have a file upload form that uploads images to a folder on my server called "attachments". This is the directory path: www.mysite.com/docs/attachments/ However, I want the images to upload to www.mysite.com/data/attachments/ instead. I have included the relevant part of the PHP below. I have tried changing this: $cur_dir = $cur_dir."/".$dir; to this: $cur_dir = $cur_dir."www.mysite.com/data/attachments/".$dir; and changing this: $dirs = explode("/","attachments//"); to this: $dirs = explode("www.mysite.com/data/","attachments//"); and also changing this: $_values[$file[0]."_real-name"] = "attachments/".date("YmdHis")."_".$_FILES[$file[0]]["name"]."_secure"; to this: $_values[$file[0]."_real-name"] = "www.mysite.com/data/attachments/".date("YmdHis")."_".$_FILES[$file[0]]["name"]."_secure"; But nothing has worked so far. Any suggestions would be appreciated. foreach($files[$form] as $file){ $str = $file[1]; if (eval("if($str){return true;}")) { $_values[$file[0]] = $_FILES[$file[0]]["name"]; $dirs = explode("/","attachments//"); $cur_dir ="."; foreach($dirs as $dir){ $cur_dir = $cur_dir."/".$dir; if (!@opendir($cur_dir)) { mkdir($cur_dir, 0777);}} $_values[$file[0]."_real-name"] = "attachments/".date("YmdHis")."_".$_FILES[$file[0]]["name"]."_secure"; copy($_FILES[$file[0]]["tmp_name"],$_values[$file[0]."_real-name"]); @unlink($_FILES[$file[0]]["tmp_name"]); }else{ $flag=true; if ($_isdisplay) { //$ExtFltr = $file[2]; //$FileSize = $file[4]; if (!eval("if($file[2]){return true;}")){echo $file[3];} if (!eval("if($file[4]){return true;}")){echo $file[5];} $_ErrorList[] = $file[0]; } } } I am trying to display images on a html page alphabetically in descending order by their filename. This script inserts all the images in a directory on the page. Just can't figure out how to maintain this with a sorting option <?php $dir = "./plate_cache"; $handle = opendir($dir); while (($file = readdir($handle))!==false) { if (strpos($file, '.png',1)) { echo "<img id=\"plates\" src=\"/tags/plate_cache/$file\"></a><br />;"; } } closedir($handle); } ?> I have a PHP script that uploads images to a folder on my server (attachments folder). Currently the folder sits within my webroot and is publicly accessible (I have to use chmod 777 due to permissions issue). So, I created the "attachments" folder outside of my webroot (so that it is not publicly accessible), but I do not know how to set the path in the PHP code to upload it to that "attachments" folder outside of the webroot. As you see in the snippet of PHP code below, the code currently uploads the the "attachments" folder within the www (webroot) directory. How do I make it upload to the "attachments" folder OUTSIDE of the www (webroot) directory? foreach($files[$form] as $file){ $str = $file[1]; if (eval("if($str){return true;}")) { $_values[$file[0]] = $_FILES[$file[0]]["name"]; $dirs = explode("/","attachments//"); $cur_dir ="."; foreach($dirs as $dir){ $cur_dir = $cur_dir."/".$dir; if (!@opendir($cur_dir)) { mkdir($cur_dir, 0777);}} $_values[$file[0]."_real-name"] = "attachments/".date("YmdHis")."_".$_FILES[$file[0]]["name"]."_secure"; copy($_FILES[$file[0]]["tmp_name"],$_values[$file[0]."_real-name"]); @unlink($_FILES[$file[0]]["tmp_name"]); }else{ $flag=true; if ($_isdisplay) { //$ExtFltr = $file[2]; //$FileSize = $file[4]; if (!eval("if($file[2]){return true;}")){echo $file[3];} if (!eval("if($file[4]){return true;}")){echo $file[5];} $_ErrorList[] = $file[0]; } } } Thanks Hi I'm trying to setup Pagination at the bottom of the page after showing 10 images in the following script but have no clue where to start and how to implement it into the script. I am trying to display images on a html page alphabetically in descending order by their filename. <?php $dir = "./plate_cache"; $handle = opendir($dir); while (($file = readdir($handle))!==false) { if (strpos($file, '.png',1)) { echo "<img id=\"plates\" src=\"/tags/plate_cache/$file\"></a><br />;"; } } closedir($handle); } ?> Any help is greatly appreciated! I want to create an image using pre-existing image files. I want to use more than one file, otherwise I would use the imagecreatefromjpg function. What function should I use to create an image using a for statement to determine how many of each image is being displayed in the new image? Hello all I have a requirement to create images mostly made up of rectangles circles and squares etc I have discovered imageline but is there anything a bit more exspansive? My images generator comprises
an array of image names extracted form an images table from a database using a select statement
a random number generator,
and a string that builds the correct pathname for the selected file.
To select one of the images for display, i generate a random number between 1 and the length of the array.
Though the generator is working, I noticed one of the random numbers is throwing up this error:
Warning: getimagesize(images/): failed to open stream: No such file or directory in
An inspection of the array reveals 2 array elements (representing my number of images) but one array element is NULL ( the first entry in the banner table
image_generator.php
require_once('connection.inc.php');
$sql = 'SELECT `filename` FROM banner';
$result = $mysqli->query($sql, MYSQLI_STORE_RESULT) or die(mysqli_error());
$row = $result->fetch_array(MYSQLI_ASSOC);//an array of image names
$count = $result->num_rows;
for ($i = 1; $i <= $count; ++$i)
{
$row[$i] = $result->fetch_array(MYSQLI_ASSOC);
}
$i = rand(1, $count); //a random number generator,
//The random number is used in the final line to build the correct pathname for the selected file.
$selectedImage = "images/{$row[$i]['filename']}";
if (file_exists($selectedImage) && is_readable($selectedImage))
{
$imageSize = getimagesize($selectedImage);
}
var_dump($row)
array (size=1)
'filename' => string 'ginsomin2.jpg' (length=13)
null
RANDON IMAGE DISPLAY
require_once 'image_generator.php';
<div id="banner" class="wrapper clearfix">
<img src="<?php echo $selectedImage; ?>" alt="banner">
</div>
Kindly advice how i may proceed from here?
Thanks.
Hello guys. I'm kinda new to PHP, I've been understanding everything so far. I have trouble with "imagestring" What I want is to query a row in MySQL. I want to display some of that info in the image. It's not working properly. Here's the code: <?php $imagepath="css/images/dog.jpg"; $image=imagecreatefromjpeg($imagepath); $imgheight=imagesy($image); $color=imagecolorallocate($image, 255, 255, 255); include("config.php"); $result = mysql_query("SELECT * FROM playerinfo WHERE Level > 0 ORDER BY Level DESC", $connect); while($myrow = mysql_fetch_row($result)) { // Not working properly. imagestring($image, 5, 50, $imgheight-50, $myrow[0], $color); } // This line works like it should: //imagestring($image, 5, 50, $imgheight-50, "Using it like this works!", $color); header('Content-Type: image/jpeg'); imagejpeg($image); ?> Any help will be GREATLY appreciated it. Thanks! This is so hard. :/ I have the following code: Code: [Select] <?php $signature = @imagecreate(350,60); $image_generate = imagecolorallocate($signature,84, 84, 84); $red = imagecolorallocate($signature,255,36,0); imagefilledrectangle($signature, 0, 1, 150, 30, $red); header("Content-type:image/png"); imagepng($signature); ?> How can I get the rectangle in the center? http://zchighscores.99k.org/image.php I don't really know what to change to get it in the right coordinates. :/ This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=342341.0 Hi all, Could someone help me add a thumbnail script to the below that works on scaling it down to 200px x 133px. I guess it is not that hard. <?php $destination='aircraft/'.$reg."1.jpg"; $temp_file = $_FILES['image']['tmp_name']; move_uploaded_file($temp_file,$destination); ?> Thanks Hey guys, I have a folder which has images. In this folder there are images that start with "refl_". I want to make sure those are not displayed. This is what I tried and it does not work. I want to show all images that don't start with "refl_". I am new to this as I am sure some can see. Thanks for the help if possible! <?php $dir = opendir("img/portfolio/"); while (false !== ($file = readdir($dir))) { $pos = strpos($file, "refl_"); if ($pos == false) { echo '<img src="img/portfolio/' . $file . '" longdesc="img/portfolio/' . $file . '" /></a>'; } } ?> |
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