PHP - Quick Question On Creating Link For Php Search

Here is the function sources that calls the social communtiy re-route or re-direct.
 an you tell me how to re-write that line alone,pls
Code: [Select]
function getReturnURL()
    {
    $regType = XiptFactory::getSettings('user_reg');
       
        if($regType === 'community')
          // return XiPTRoute::_('index.php?option=com_community&view=register', false);
         return XiPTRoute::_('index.php?option=com_community&view=register&Itemid=436', false);

        //return XiPTRoute::_('index.php?option=com_user&view=register', false);
return XiPTRoute::_('index.php?option=com_community&view=register&Itemid=436', false);
    }


Quote from: danjapro

I need some quick help. I just need to write this redirect  out to where it only redirect the link I have.

Current State, NO GOOD producing two itemids.
Code: [Select]
return XiPTRoute::_('index.php?option=com_community&view=register&Itemid=436', false);

I just want the url I have listed to be in url, not any addtional itemids.

Thank you in advance.

Hello,

Does anyone know a tutorial I can follow to create my own search engine over the items I have in my SQL database?
I find a lot of tutorials but they are all 'one word searches' which means if you type two words you will get all results that contain either word (too many hits).

If the search engine tutorial displays result with AJAX even better.

Thanks for help.
df

Hello. I am working on a php script for searching a database table. I am really new to this, so I used the this tutorial http://www.phpfreaks.com/tutorial/simple-sql-search

I managed to get all the things working the way I wanted, except one important and crucial thing.
Let me explain.
My table consist of three columns, like this:

ID(bigint20)    title(text)        link (varchar255)
=============================
ID1                title1                link-1
ID2                title2                link-2
etc...

Like I said, I managed to make the script display results for a search query based on the title. Want I want it to do more, but I can't seem to find the right resource to learn how, is to place a "Download" button under each search result with its corresponding link from the table.

Here is the code I used.

<?php

$dbHost = 'localhost'; // localhost will be used in most cases
// set these to your mysql database username and password.
$dbUser = 'user'; 
$dbPass = 'pass';
$dbDatabase = 'db'; // the database you put the table into.
$con = mysql_connect($dbHost, $dbUser, $dbPass) or trigger_error("Failed to connect to MySQL Server. Error: " . mysql_error());

mysql_select_db($dbDatabase) or trigger_error("Failed to connect to database {$dbDatabase}. Error: " . mysql_error());
// Set up our error check and result check array
$error = array();
$results = array();
// First check if a form was submitted. 
// Since this is a search we will use $_GET
if (isset($_GET['search'])) {
   $searchTerms = trim($_GET['search']);
   $searchTerms = strip_tags($searchTerms); // remove any html/javascript.
   
   if (strlen($searchTerms) < 3) {
      $error[] = "Search terms must be longer than 3 characters.";
   }else {
      $searchTermDB = mysql_real_escape_string($searchTerms); // prevent sql injection.
   }
   
   // If there are no errors, lets get the search going.
   if (count($error) < 1) {
      $searchSQL = "SELECT title, link FROM db WHERE title LIKE '%{$searchTermDB}%'";

      $searchResult = mysql_query($searchSQL) or trigger_error("There was an error.<br/>" . mysql_error() . "<br />SQL Was: {$searchSQL}");
      
      if (mysql_num_rows($searchResult) < 1) {
         $error[] = "The search term provided {$searchTerms} yielded no results.";
      }else {
         $results = array(); // the result array
         $i = 1;
         while ($row = mysql_fetch_assoc($searchResult)) {
            $results[] = "{$row['title']}<br /> Download - this is the button I want to link to the title results - and maybe other links too - <br /> ";

    $i++;

       

   
         }
      
      }
   }
}

function removeEmpty($var) {
   return (!empty($var)); 


}
?>

      <?php echo (count($error) > 0)?"The following had errors:<br /><span id=\"error\">" . implode("<br />", $error) . "</span><br /><br />":""; ?>
      <form method="GET" action="search?" name="searchForm">
         Search for title: <input type="text" name="search" value="<?php echo isset($searchTerms)?htmlspecialchars($searchTerms):''; ?>" />
        
         <input type="submit" name="submit" value="Search" />
      </form>

    <?php echo (count($results) > 0)?"Rezultate lucrari de licenta sau disertatie pentru {$searchTerms} :<br /><br />" . implode("", $results):""; ?>




 $results = array(); // the result array
         $i = 1;
         while ($row = mysql_fetch_assoc($searchResult)) {
            $results[] = "{$row['title']}<br /> Download - this is the button I want to link to the title results - and maybe other links too - <br /> ";

    $i++;

 
I would like the results to be displayed like this

Results for SearchItem:

Result 1
Download | Other link
Result 2
Download | Other link
etc.... or something like this.

So, how do I add the data from the link row into a text(Dowload), within an <a href> tag (well, at least I guess it would go this way) ?
My first tries (fueled by my lack of knowledge) where things like

$results[] = "{$row['title']}<br /> <a href="{$row['link']}">Download</a> <br /> ";

but I keep getting lots of errors, and then I don't know much about arrays and stuff (except basic notions);
So there it is. I am really stuck and can't seem to find any workaround for this.
Any suggestions? (examples, documentation, anything would do, really)
Thanks,
Radu

$link	=	?><a href="post?id=<?php echo $id; ?>&title=<?php echo $slug_title; ?>"><?php echo $title; ?></a><?php

Basically what I am trying to do is get a url link of a current page that I'll be sending in an email. I have all the $_GET variables I need to duplicate the current url.  For some reason it's giving me an error.    Can you please fix what is shown above into something that'll work?   Thanks.
Edited by man5, 15 July 2014 - 07:09 PM.

hi.
when i get into some function manual and there is a note says.
Quote

This function has been DEPRECATED as of PHP 5.3.0. Relying on this feature is highly discouraged.

.
is that meaning that after 5.3.0 version this function will not be supported?
thanks , Mor.