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PHP - Get Variable Value To Another Php Page Using Ajax
My index.php,
$output .= '
<div class="col-sm-3 col-lg-4 col-md-3">
<div style="border:1px solid #ccc; border-radius:5px; padding:10px; margin-bottom:16px; height:300px;">
<audio controls controlsList="nodownload" style="padding: 10px 10px 10px 10px;margin-left: -21px;">
<source src="audio_sample/'. $row['voice_audio_file'] .'" alt="" class="img-responsive">
</audio>
<p align="center"><strong> '. $row['voice_name'] .'</strong></p>
<p style="font-size: 12px;">
Id : '. $row['voice_id'].' <br />
Name : '. $row['voice_name'].' <br />
Gender : '. $row['voice_gender'].' <br />
Genres : '. $row['voice_genres'].' <br />
Voice Modulation : '. $row['voice_voice_modulation'].' <br />
Languages : '. $row['voice_languages'].' <br />
Jingle Moods : '. $row['voice_jingle_moods'].' <br />
Ivr : '. $row['voice_ivr'].' <br /> </p>
<button type="button" class="btn btn-primary" type="submit" onclick="addCart('. "'".$row["voice_id"]."'".','."'". $row["voice_name"]."'".');" style="padding: 5px 83px 5px 83px;">Add to PlayList </button>
same page ajax :
<script>
function addCart(voice_id, voice_name)
{
$.ajax({
type: 'POST',
url: 'cart.php',
data: {
voice_id : voice_id,
voice_name : voice_name
},
dataType: 'text',
success: function(data) {
// alert(data);
}
});
}
$(document).ready(function(){
});
</script>
and get.php
<?php
$voice_id =" ";
$voice_name=" ";
if(isset($_POST['voice_id']) && isset($_POST['voice_name']))
{
$voice_id = $_POST['voice_id'];
$voice_name = $_POST['voice_name'];
}
echo "$voice_id, . "&". , $voice_name";
?>
if click button, the value send but the get.php not properly get the value and display on the php page. Edited June 12, 2019 by aveeva Similar TutorialsHello I'm trying to pass a php variable from produto.php to another file descProduto.php it ajax but without success. Please someone can tell me what I'm doing wrong? The ajax is working fine but I can't get the value/variable on descProduto.php
file index.php
<script type="text/javascript" src="jquery-1.11.min.js"></script> I have a PHP page that makes a checkbox appear after a certain textbox is exited. This part of the functionality is working - the user leaves the textbox, the AJAX call is made, and if certain criteria are met, the checkbox appears or it doesn't.
Here's where I need help. When the checkbox appears on the form and the form is submitted via POST, I can't get its value. Here's the code that's in the HEAD section:
<script type="text/javascript">
$(document).ready(function() {
$('#id2').blur(function(){
$.post("biz/add_official.php", {
id1: $('#id1').val(),
id2: $('#id2').val()
}, function(response){
$('#usernameResult').fadeOut();
setTimeout("finishAjax('usernameResult', '"+escape(response)+"')", 400);
});
return false;
});
});
function finishAjax(id, response) {
/* $('#usernameLoading').hide();*/
$('#'+id).html(unescape(response));
$('#'+id).fadeIn();
} //finishAjax
</script>
And here's the code that's in the FORM section:
<span id="usernameResult" style="color:green;"></span>
<script>
$('.container').find('.checkOfficial input[type="checkbox"]').val()
</script>
When the form is submitted via POST, how do I see if checkbox was checked or unchecked?
Both of these variables appear empty when the form is submitted: $_POST['checkOfficial'] $_POST['usernameResult']
This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=346932.0 This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=343073.0 Where is my "Progr" return value?
This is not my first day using php but I don't code in the language that often. I don't understand why my dynamic variable is not returned in AJAX GET? Essentially, I need to give the client a simple UI so that they can copy files to a printer and I wanted to provide a little unfiltered feedback so they knew whether operation was a success. My feedback was just going to be output of exec() function though cleaned up slightly (perhaps replace line breaks with html break tags). PHP version is 5.2.17.17 and cannot be upgraded. Web Server Apache.
PHP dumbed down code:
exec("LoadZPL_PURL.bat", $output); Some code from my pages ,
Page1 ( Redirecting page )
<html> <title>login_redirect.</title> body> <form name="redirect" action="http://mysite/page2.php" method="post"> <input type="hidden" name="mac" value="$(mac)"> </form> <script language="JavaScript"> <!-- document.redirect.submit(); //--> </script> </body> </html>Page 2 ( select product )
<?php
session_start();
ini_set('display_errors',1);
error_reporting(E_ALL);
include '../lib/config.php';
include '../lib/opendb.php';
// get user mac adres from redirect post page1
$_SESSION['macid'] = $_POST['mac'];
// set $macid for other use ( maybe not needed, am learning )
$macid = $_SESSION['macid'];
// echo $macid does show mac adress, so variable is not empty here
if (!empty($_POST["submit"]))
{
$product_choice = $_POST['accounttype'];
$query= "SELECT AccountIndex, AccountCost, AccountName FROM AccountTypes WHERE AccountIndex='$product_choice'";
$result = mysql_query($query) or die('Query failed. ' . mysql_error());
while($row = mysql_fetch_array($result))
{
$_SESSION['AccountIndex'] = $row['AccountIndex'];
$_SESSION['AccountCost'] = $row['AccountCost'];
$_SESSION['AccountName'] = $row['AccountName'];
}
header('Location: page3.php');
}
// did leave out the other/html/form stuff here
Page 3 ( show Session variables )
<?php
ini_set('display_errors',1);
error_reporting(E_ALL);
session_start();
print_r($_SESSION);
?>
Now, on page 3 i do see the right session varables, only the "macid" is empty.
why ?
Hey guys, I'm making an Ajax call to my database and retrieving a newsletters HTML code as the result. I then prepend it into a div area called code_content. I use some php str_replace to add some links also. When the content loads into the div, the user can then add further content to it via Ajax calls, appending articles and that. What I'm trying to figure out is how can I then retrieve all the newly edited contents of this code_content div soni can send it to my Ajax function to write to te db? Hello, First of all ,I have been a regular reader of the forum and it has increased my knowledge in the PHP a lot. Till now i had just been a guest user and used to go through the queries and tips posted here. Today , for the first time i am posting on the forum Coming to a problem: I have to design a function for a client from travel domain. Where he wants the script/function to go and extract data from an airline website on the available fare for a specific date and destination. The problem is that only a part of fare(Base fare) is visible on the site and you have to select one of the given flight option(s) (after selecting the option through AJAX the full fare is displayed on the same page on the left hand site) to get the complete fare including fare and surcharges. Now i want my function/script to extract the full fare for all the available flight options. I have written the below piece of code. But its not efffective as it gets only the base fare part of the result page and not the complete fare.. The airline booking url is : http://book.spicejet.com/skylights/cgi-bin/skylights.cgi My code: //---- Spicejet start // ENGINE URL http://book.spicejet.com/skylights/cgi-bin/skylights.cgi?page=homecomp //Taking some sample search data - just to test the script $event="search" ; $module="SB" ; $page="SEARCH" ; $mode="empty" ; $travel="1" ; // ONE WAY OR 2 WAY $from1="HYD" ; $to1="DEL" ; $departDay1="13" ; $departDay2=""; $departMonth1="201010" ; $ADULT="1" ; $CHILD="0" ; $INFANT="0" ; $toCity1="DEL" ; $numberMarkets="1" ; // the page needs data in POST form $curlPost = 'event=' . urlencode($event) . '&module=' . urlencode($module) .'&page=' . urlencode($page) .'&mode=' . urlencode($mode) .'&travel=' . urlencode($travel) .'&from1=' . urlencode($from1) .'&to1=' . urlencode($to1) .'&departDay1=' . urlencode($departDay1) .'&departMonth1=' . urlencode($departMonth1) .'&ADULT=' . urlencode($ADULT) .'&CHILD=' . urlencode($CHILD) .'&INFANT=' . urlencode($INFANT) .'&toCity1=' . urlencode($toCity1) .'&numberMarkets=' . urlencode($numberMarkets).'&submitSearch=submitSearch'; $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, 'http://book.spicejet.com/skylights/cgi-bin/skylights.cgi'); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_USERAGENT, "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0; .NET CLR 2.0.50727; .NET CLR 1.1.4322)"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $curlPost); $data = curl_exec($ch); curl_close($ch); echo($data); Also one more query Is there something like beautiful soup (As in Python) to parse the data. I want to extract the flight timing and total price from the page and insert into a database. Thanxs in advance
I'm trying to login and scrape a page 4 pages deep. I can get to the fourth page...but that page only returns AJAX ERROR:0. I know NOTHING about AJAX calls via Curl. Can someone please help me with what to look for in the source code of the 4th page (when using a browser) to what I'm supposed to pass along via CURL? Hello, everyone. I have code that effectively calls a PHP page with AJAX (no JQuery). The PHP responds fine with an echo. Here is the javaScript that calls the PHP so refreshing the page doesn't need to be done.
function deleteCategory()
{
var e= document.getElementById("dropDown1");
var var1 = e.options[e.selectedIndex].text;
var xmlhttp = new XMLHttpRequest();
xmlhttp.onreadystatechange = alerta() {
if (this.readyState == 4 && this.status == 200) {
document.getElementById("insert").innerHTML = xmlhttp.responseText;
}
};
xmlhttp.open("GET", "deleteRow.php?q=" + var1 , true);
xmlhttp.send();
}
How do I call a PHP function on the same page while preserving the above AJAX.
Sincerely, Joshua Hi I have put together a options page for the script that I have been working on. I have 1 options page where there options are divided into 4 jQuery tabs with there own save button. The options in each tab are posted using Ajax to their own separate file like process.php, process1.php etc. My question is there a way to place all the processing code in one file and if so would this affect the load on the server? Would each form be better off having their own page for processing? For example: Code: [Select] <form id="options_1" action="process1.php" method="post" > <!-- this is form 1 that is processed with process1.php --> </form> <form id="options_2" action="process2.php" method="post" > <!-- this is form 2 Can this form be processed using process1.php instead of process2.php --> </form> <form id="options_3" action="process3.php" method="post" > <!-- this is form 3 Can this form be processed using process1.php instead of process3.php --> </form> I have a page that functions like this:
The user begins by loading ajaxtest.php, then using a drop-down menu, selects a user, after which a DIV on ajaxtest.php is populated with the user's selction to getuser.php?q=John%Doe
Here's a visual representation of what is currently happening, along with the part I don't understand.
getuser.php consists largely of a a large HTML table which interacts through PHP with my SQL database. Several of the fields in this table are editable, and after the user changes one of these fields, he can press an "update" button, which calls an AJAX script in update.js and runs update.php, which contains all my SQL queries to update the database, without the user being redirected to this update.php page. All of this is processing perfectly - the user makes some sort of edit, hits "update", and the database gets updated without any redirection or refresh.
Here's what I can't figure out though. Once the user makes a change, and hits "update," the database updates, but the end user doesn't see those changes that he made. I can't just do a simple page refresh, because the action is taking place on getuser.php, but getuser.php is loaded inside of a #DIV on ajaxtest.php. If I use something like window.location.reload(), this just refreshes ajaxtest.php and puts the user back to the starting point of having to select a user. This is not what I want. I don't want to refresh ajaxtest.php, I want to "refresh" ajaxtest.php with getuser.php?q=John%Doe insidethe DIV on ajaxtest.php.
It seems like this is very common - several forums have this capability, where a user has a page loaded, adds a comment, and sees that comment immediately without a full page refresh. I just don't know how to do it, and I've tried at lengths to search the web for an answer with no luck.
Can someone walk me through how to do this?
I am trying to implement lazy loading into a project with pagination already set up.
If I was to go to my website and after the .com, type in "api_courselist.php?page=1" I would receive the first 20 results of my query. If I was to change that to page=2, it would retrieve the next 20 and so on.
My issue is I have no idea how to implement that into my java script/ajax file. I have it set up so that when the user scrolls to the bottom of the page, a div will make its self visible with the new page populated inside of it and IT will keep on pulling pages in till There is no more content.
jQuery(function ($) {
jQuery(document).ready(function() {
var is_loaded = true;
jQuery(window).scroll(function() {
if(jQuery(window).scrollTop() == jQuery(document).height() - jQuery(window).height()) {
jQuery('div#loadMore').show();
if(is_loaded){
is_loaded = false;
jQuery.ajax({
url: "api_courselist.php?page=1",
success: function(html) {
is_loaded = true;
if(html){
jQuery("#infiscroll").append(html);
jQuery('div#loadMore').hide();
}else{
jQuery('div#loadMore').replaceWith("<center><h1 style='color:red'>End of Content !!!!!!!</h1></center>");
}
}
});
}
}
});
});
});
This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=326913.0 Right now I redirect to index page after I delete a record. However I am looking to make it so that I can delete a record without redirecting the page. I know this can be accomplised using Ajax. I have spent countless hours before trying to make it work, but it did not work.
So here is a basic setup I created. Can you please update it with ajax code so that I can see how it's done properly?
<!DOCTYPE HTML> <html lang="en"> <head> <meta charset="UTF-8"> <title>Home Page</title> </head> <body> <div class="record" > <a href="record.php?id=<?php echo $record_id ?>"><?php echo $record_name; ?></a> <div class="delete-record"> <a href="delete.php">Delete Record</a> </div> </div> </body> </html> Edited by man5, 18 August 2014 - 08:55 PM. Code: [Select] SOLVED I want to use a variable I defined on another page, but I don't know how. Here's the original page with the variable: cart.php Code: [Select] $total += $qty*$row['price']; Here's the new page new page without the variable: checkout.php Code: [Select] //I want the value $total onto this page Thanks In my registration form there are many form elements to give users' details for registration in my web site. among those elements there are two select boxes for user to select their district and city. I have created these two select box using ajax. Therefor a user select a district then automatically ajax creating second select box for cities is populating. I used separate php page called findcity.php to create city select box. I called this findcity.php page from my original register.php page through onChange attribute. and there I passed the district id with the url to findcity.php page. like wise, Now I need to bring city id to my original register.php page when user select a city from city select box in findcity.php page. my problem is that. I tried to get city Id to register.php page but still I couldn't get it. city id is needed me to send to the database with other form elements' values. can anybody help me to fix my problem? here is my coding for your reference. This code is, from my register.php page Code: [Select] <div> <label for="district">District <img src="../images/required_star.png" alt="required" /> : </label> <?php require_once ('../includes/config.inc.php'); require_once( MYSQL2 ); $query="select * from district order by district_id"; $result = mysqli_query( $dbc, $query); echo '<select name="district" class="text" onChange="getCity(' . "'" . 'findcity.php?district=' . "'" . '+this.value)">'; echo '<option value="">-- Select District --</option>'; while( $row = mysqli_fetch_array($result, MYSQLI_NUM)) { echo '<option value="' . $row[0] . '"'; // Check for stickyness: if ( isset( $_POST['district']) && ( $_POST['district'] == $row[0] )) echo ' selected="selected"'; echo " >$row[1]</option>"; } echo '</select>'; ?> </div> <div> <label for="city">City <img src="../images/required_star.png" alt="required" /> : </label> <input type="hidden" name="reg_locationid" id="reg_locationid" value="56" /> <div id="citydiv" style="position: relative; top: -14px; left: 130px; margin-bottom: -26px;"> <select name="city" class="text"> <option>-- Select City --</option> </select> </div> </div> this is, from my findcity.php page Code: [Select] <?php $districtId=$_GET['district']; require_once ('../includes/configaration.inc.php'); require_once( MYSQLCONNECTION ); $query="select city_id, city_name from city2 where district_id=$districtId"; $result=mysqli_query( $dbc, $query); echo '<select name="city" class="text"> <option>-- Select City --</option>'; while($row=mysqli_fetch_array($result, MYSQLI_NUM)) { echo '<option value="' . $row[0] . '"'; // Check for stickyness: if ( isset( $_POST['city']) && ( $_POST['city'] == $row[0] )) { echo ' selected="selected"'; //echo '<input type="hidden" name="city" value="' . $row[0] . '"'; } echo " >$row[1]</option>"; } echo '</select>'; ?> I want to include a variable (for example an object $user) in each PHP page. Previously I declared $var in an include file then included that file in every page, however it generates an error in Zend Studio and it's also not very good programming style. I want to know how I can do it any other way. I was thinking of using constants but I don't know if constants should be used for this purpose and also I do not think constants can be defined as objects. Thank you very much for your help. Im not sure that it is possible, but I thought I would post and ask anyway. I want to use a page redirect such as: Code: [Select] <?php header("Location: http://www.redirect-to-home.com/"); exit; ?> However, due to the nature of the redirect and the header having to be sent first, Im not sure how I could use a variable or probably better, something like HTTP_HOST. In a post I made elsewhere on here, someone posted this code: Code: [Select] if($_SERVER['HTTP_HOST'] == "localhost"){ // For local development define('SITEURL', 'http://' . $_SERVER['HTTP_HOST'] . '/template'); define('SITEPATH', $_SERVER['DOCUMENT_ROOT'] . 'template'); } else{ // For production web define('SITEURL', "http://" . $_SERVER['HTTP_HOST']); define('SITEPATH', $_SERVER['DOCUMENT_ROOT']); I began thinking then, I wonder is something like that could be used as a page redirect as a very basic and simple prevention to direct access to a specific folder on the site? But Im not sure how to make it work, Im just not that experienced in PHP yet. I dont know if using an index.html file would be better over an index.php file either. Im still experimenting a little trying to figure things out. So is there a way to use a php variable to redirect someone back to the home page? I know you can use .htaccess and things like that as well, but I wanted to see if this could be done also. Thanks in advance for any help. Hello, I'm trying to build a small project; and as part of it - I want users to search and when presented with relevant enteries in the SQL database - they should be able to click and retrieve a page dedicated to that entity. The problem I am having is in passing the 'id' of the search result onto the next (description) page. Code: [Select] $SQL = "SELECT * FROM loads"; $result = mysql_query($SQL); while ($db_field = mysql_fetch_assoc($result)) { $clickid = $_GET['id']; print $db_field['id'] ."<a href=\"load_info.php?id=$id" . $id . "\" target=\"_self\" title=\"\">More Info</a>;"; print $db_field['depart:'] . "<BR>"; print $db_field['dest'] . "<BR>"; } I thought it was easy enough to pass the variable like above ("load_info.php?id=$id) and then grab it on the next page like so: $val = $_GET['clickid']; Unfortunately, it doesn't retrieve the info from the page before. If I insert a number in there, it does work correctly, but I really need the ID of the database entry to pass on so as to provide the user with further information. If anyone could help it would be appreciated. L. |
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