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PHP - Paypal Friends And Family Link
Hi all
This part is integral to my site and im panicking as i cant seem to find an answer...
When someone clicks a link on my page with the below code it only does it as services... how can i create a paypal link to charge as friends and family PLEASE PLEASE PLEASE HELP
<form id="payid" name="_xclick" action="https://www.paypal.com/cgi-bin/webscr" method="post">
<input type="hidden" name="cmd" value="_xclick">
<input type="hidden" name="business" value="<?php echo $row1['EMAIL']; ?>">
<input type="hidden" name="currency_code" value="GBP">
<input type="hidden" name="item_name" value="BALL">
<input type="hidden" name="amount" value="<?php echo preg_replace( '/[^0-9,"."]/', '', $row['PRICE'] ); ?>">
<!--<input type="hidden" name="return" value="http://www.theeasypc.co.uk/lottery/heandal.php">-->
<input type="hidden" name="return" value="http://www.theeasypc.co.uk/lottery/heandal.php?success=1">
<input type="hidden" name="cancel_return" value="http://www.theeasypc.co.uk/lottery/heandal.php?error=1">
<!-- Where to send the PayPal IPN to. -->
<input type="hidden" name="notify_url" value="http://www.theeasypc.co.uk/lottery/heandal.php" />
<input type="image" src="http://www.paypal.com/en_US/i/btn/btn_buynow_LG.gif" border="0" name="submit" alt="Make payments with PayPal - it's fast, free and secure!">
</form>
I can see the its set to business in one flag but ive tried to change thie to f&f, personal, friends, family, nothing works also tried "_donations"
Similar TutorialsI have two button that load the next and previous pages of friends, I'm having trouble doing so, it sort of works, but it's got bugs so it's not right. Next: Code: [Select] $query = mysql_query("SELECT * FROM friends WHERE (friend_1='".$id."' OR friend_2='".$id."') AND id>$last_id ORDER BY id ASC LIMIT 16");previous: Code: [Select] $query = mysql_query("SELECT * FROM friends WHERE (friend_1='".$id."' OR friend_2='".$id."') AND id<$last_id ORDER BY id ASC LIMIT 16"); $id = id of the users profile. $last_id = the last loaded friend id (unique id to friends table , not the friends actual id) Hello and looking for some help please.. I have already read this : http://www.phpfreaks.com/forums/index.php?topic=120619.0 What I am after to do, is to after a successful Paypal payment from paypal, generate a link in a wordpress site (or external even) that will expire after 3 days to a video. I hope that makes sense please? Thanks in advance, Jim I was wondering if there was any way in which I could create a link which would direct to a paypal payment page and the amount to be paid could be specifed in the URL (GET method) as I have multiple products at differnt prices and would like to redirect the user to a page with a price I specify to be paid. Anyone have ideas? Hope someone can respond soon - thanks in advance for any help! Jake Hi i am making a website for my family and i would like them to be able to log in to it and create themselves a profile page, but i have no idea how to write code of any kind, any help would be great. hello ! I need a PHP script for my site ; I need a script like this for my family tree site ; Thank you! Table friends users Fred Tom Julie Henry Bill Wally Joe Joe friendwith Joe Joe Joe Joe Joe Joe Julie Wally Fred, Tom, Julie, Henry, Bill, and Wally have friended Joe. Code: [Select] <?php $username = 'Joe'; $query = "SELECT * FROM friends WHERE friendwith=' $username'"; $result = mysql_query($query); while($row = mysql_fetch_array($result)) { echo $row['users']."<br/>"; echo $row['friendwith']."<br/>"; } ?> Joe is friends with Julie and Wally. Code: [Select] <?php $username = 'Joe'; $query = "SELECT * FROM friends WHERE users='$username'"; $result = mysql_query($query); while($row = mysql_fetch_array($result)) { echo $row['users']."<br/>"; echo $row['friendwith']."<br/>"; } ?> Here's where I need your expert advice! I want to know who friended Joe except for those that Joe has friended. In other words, I want to show Fred, Tom, Henry, and Bill. Julie and Wally should not be included in the query because Joe has friended them as well. Hello Everyone, I am a noob at PHP so please forgive me if my code is wrong. I have a strong understanding of HTML and CSS just for the curious. Question: Write a program that formats a block of text (to be input by the user) based on preferences chosen by the user. Give your user options for color of text, font choice and size. Display output on a new page. I would greatly appreciate someone's help. The text is showing up but not according to the options selected. I know there is something wrong with the output page. Here is the Input Page (call it question4.php): <html> <head> <title> Please Enter Your Text</title> </head> <body> <form method="post" action="question4display.php"> <p>Enter the text you want formatted please: <input type="text" name="textformat" maxlength="30" size="30" /> <table> <tr> <td><label for="font">Select Font:</label></td> <td><select id="font" name="font"> <option value="Verdana">Verdana</option> <option value="Arial">Arial</option> <option value="Times New Roman">Times New Roman</option> </select> </td> </tr> <tr> <td><label for ="size">Select Size:</label></td> <td><select id="size" name="size"> <option value="10px">10px</option> <option value="12px">12px</option> <option value="14px">14px</option> <option value="20px">20px</option> </select> </td> </tr> <tr> <td><label for="color">Select Color:</label></td> <td><select id="color" name="color"> <option value="green">Green</option> <option value="blue">Blue</option> <option value="red">Red</option> </select> </td> </tr> </table> <input type="submit" name="submit" value="Submit" /> </form> </body> </html> Here is the OUTPUT page (called it:question4display.php): <?php session_start(); $_SESSION['textformat'] = $_POST['textformat']; $_SESSION['font'] = $_POST['font']; $_SESSION['size'] = $_POST['size']; $_SESSION['color'] = $_POST['color']; ?> <html> <head> </head> <body> <p <?php echo ' style="font-family: ' . $_POST['font'] . '; '; echo 'font-size: ' . $_POST['size'] . '; '; echo 'color: ' . $_POST['color'] . '; '; ?> > <?php echo $_POST['textformat']; ?> </p> </body> </html> Hi guys, im making a basic social networking site for a college project and I need to know how to make a system that will let logged in users add each other as friends but I carnt really find anything on google about how to start. Can anyone here help me or know a tutorial I can follow that will let me create something like this? Thanks Say i was going to store a "friends list" for a user. Would it be easier to store the names in a text string in the db instead of having to make a new field for each friend? In other words: 001 | Keith | Joe, Jane, Mike or 001 | Keith | Joe | Jane | Mike It seems like a pain to make a column for each but since i'm only 6 months into php i haven't really tapped into it's ability to deal with a string of data. My end game would to at some point take the user list and make a selectable table: Friends: Joe Jane Mike Preferably with an array pseudo coded as: Count how many users for each user echo username <a href username's page> Bottom line: Store as Columns or String? p.s. i've reviewed php.net etc. so it's not a matter of not knowing how but more which is preferable I have a website where users can add their friends. What I am trying to achieve is to show every user that who are their friends that are currently online. If any one knows a link to any script or tutorial that explains this, Please help. Thanks, Faisal Hi guys, I'm developing a website which allows people to connect and follow each other's activity (like Twitter, for example). To simplify everything, let's say I only have 2 tables: 1. Followers id | follower_id | id_to_follow ------------------------------------ 2. Activity id | member_id | message | time ----------------------------------------- Let's say John is following Jane and Bob. I want to create a "news" page and display the last 20 messages from Bob and Jane, chronologically. For small numbers, I'd do something like this: Select everything from the Activity table, check for every entry if the member is a friend of John's (in the Followers table) and, if so, display the message, ORDER BY `id` DESC. But, this is very inefficient, I guess, for larger numbers (I can't even think about how many queries would take to do this on a site like Twitter...). Any ideas of how to do the same thing more efficiently? Thank you. I have just a general question about a friends system here with regards to the database design....... lets say you have a website where users can rent books. The database design would be MEMBER BOOK LINk memberid isbn memberid name name isbn Or something to that extent Now with a friends system like facebook has that "LINK" table would be absolutley huge and I cant see it being good design practise. I mean how do you suppose facebook does this. Do they have ...... FRIENDS myID friendID and just millions upon millions of repeated data? The only way I can see would be in the member table have a field called friends and then the ID's of each friend like so Friends 001, 002, 003, 004, 005, 006, 007, Now is my logic correct here or am I thinking of this totally the wrong way? Would the other way be a better option or would it take the system too long to get to the 1000,000 th record in the database? I believe the first option would be correct but I cant see how the server would handle the request if say you had 1000,000 users. It just seems to me that you would create too many records. In my website people can sign up to mulitple events but if every user had 100 events the link table would just be massive!!!!!!!!!!!!!!!!!!!!!! Im just after peoples input really on the situation. Thank you I'm trying to make it so i can show the friends i added, or users that added a friend <table border=2 width="250" height="125"><tr> <?php $userfinal = get_username($_SESSION['user_id']); $Members = mysql_query("SELECT * FROM friends WHERE username='$userfinal' AND friendname"); $numRowsMembers = mysql_num_rows($Members); for($count = 1; $count <= $numRowsMembers; $count++) { $name = mysql_fetch_array($Members); ?> <td width="150" height="125"> <a href="view_profile.php?username=<? echo $name['friendname']?>"><img src="<? echo $name['main_P']?>" width="100" height="100"/> <? echo $name['friendname']?></a> <? if (isset($name['date']) && (time() - $name['date'] > 300)) { echo 'offline =['; } else { echo "<font color=green>[Online Now!]</font>"; } $name['date'] = time(); // update last activity time stamp ?> </td> <? } ?> </tr></table> database id friendname username 12 kristybellexo zhshero 13 demo zhshero 14 zhshero zhshero I have a database with all users.. Within that database all users have an id. How would I make it so users can "friend" other users? Would I need to make a new table for that? Im sorry for the dumb question.. I havent dealt with php or mysql in about two years because I was busy getting engaged and all.. But now that I have time again I think im gonna take up one of my old projects. Granted I probably could have answered this question myself back then but now im finding some trouble taking up programming again. :\ Here is the error code I am receiving;
Parse error: syntax error, unexpected $end (line 41)
The error message has consistently identified the statement in the else clause. Thanks for any help.
<?php session_start(); ?>
<!DOCTYPE html PUBLIC "-//W3C//DD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Blah</title>
<link rel="stylesheet" type="text/css" href="defaultcss.css" />
</head>
<body>
<div id ="wrapper">
<h2>Blah Forum Demo</h2>
<p>Creating basic login functionality</p>
<?php
if (!isset($_SESSION['uid']))
{
echo "<form action = 'login_parse.php' method ='post'>
Username: <input type ='text' name='username' />
Password: <input type ='password' name='password' />
Submit: <input type ='submit' name='submit' value='Log In' />
";
}
else
{
echo "<p>You are logged in as ".$_SESSION['username']." • <a href='logout_parse.php'>Logout</a>;
}
?>
</div>
</body>
</html>
Hi Guys http://www.phpfreaks.com/forums/Smileys/nrg_alpha/cool.gif Cool I have social networking application. I am trying to query a database to get the ids of all the users friends. With the ids of all the users friends I am then trying to query a second database with the status feed that contains all users status data. I would like to echo the users friends status data only from the second database code is below hope you can help. Thank you. <?Php session_start(); ?> <?Php //connect. include("connect.php"); //Time ago coverting code. include_once("classes/develop_php_library.php"); // Include the class library $id=$_SESSION['id']; /*find-out users friends*/ $findperson=mysql_query("SELECT * FROM friends WHERE sessid='$id'"); $timeAgoObject = new convertToAgo; // Create an object for the time conversion functions $findfriend=mysql_num_rows($findperson); //Count if the person has any friends. If they have friends get the ids of all their friends if($findfriend>0) { while($rati=mysql_fetch_assoc($findperson)) { $fried=$rati['friendid']; //query the status table to give the users friends status. $mediafeeds=mysql_query("SELECT * FROM status WHERE userid='$fried' LIMIT 0,8"); $media_num=mysql_num_rows($mediafeeds); } //count to see if their any status updates from users friends. if($media_num>0) { //display all the users friends status data. $datamedia="<TABLE BORDER='0' CELLPADDING=8 bgcolor='#FFFFFF' align='center' width='350px' height='30px'>"; while($mini=mysql_fetch_assoc($mediafeeds)) { $user_id=$mini['userid']; $viewer_nme=$mini['username']; $viewer_picture=$mini['viewerpics']; $media_pic=$mini['contentpic']; $desc_ption=$mini['description']; $date_time=$mini['date']; $convertedTime = ($timeAgoObject -> convert_datetime($datetime)); // Convert Date Time $datetime = ($timeAgoObject -> makeAgo($convertedTime)); // Then convert to ago time .. //This is just a table with the data of all the users friends data. $datamedia.="<tr><td valign='top' cellpadding='5' width='10%' bgcolor='#FFFFFF' align='center' >$viewer_nme<br/><a href='friendsprofile.php?uid=$uidd&&viewer=$id'><img src='".$mediapic."' width='80' height='80' align=left></td> <td valign='top' align='left' cellpadding='5' width='60%' bgcolor='#D3D3D3' cellpadding='0'>$introduction<br/>$titlenamed$titled<br/>$descd$desc_ ption<br/><br/>$datetime</td></tr>"; } $datamedia.="</TABLE>"; echo $datamedia; } else { echo "<font color='#333333' size='2' face='sans-serif' align=left><div align='center'> Your friends have not current activities.</div></font>"; } } else { } I am trying to make a filter to show posts from mutual friends between you and the persons profile you're on, I have somewhat of an idea on how to write the mysql query (it needs to be just one query, not two(which would be the easy way of doing it)). the "friends" table has: "friend_1" and "friend_2" and the "posts" table: "to_id" and "from_id" The PHP variables would be: "$session" and "$id" id would be the users Id of the profile you're on. Thanks, any help would be appreciated. I'm working on a Social Network from scratch. I'm stuck on how to store friend relationships between users? On one topic here, I found an idea. Have a table with 3 columns; id,user_1,user_2 each relationship would have a new row in the database. Would this be the best way to do this? I can imagine the table would get quite big. If each user has 100 friends and there's 10000 users that's 1000000 rows. etc Hi all I have a quick PayPal IPN question, is this the right group to post the message and does anyone know much about the PayPal IPN? Thanks Hey Guys, i have another problem, i am using paypal IPN, and i want the details of the order to be stored in my orders table of the databse as well as sending me an email. Im pretty sure the code is ok, but it is not working. Can some one please take a look? <?php include('db_fns.php'); // change these to your paypal settings $paypal_email = "benmunns@gmail.com"; $paypal_currency = 'USD'; $shipping = 10.00; /** * checks if paypal trans id is already in database * @param int $trans_id * @return bool */ function no_paypal_trans_id($trans_id) { $connection = db_connect(); $query = sprintf("SELECT id from orders WHERE paypal_trans_id = '%s'", mysql_real_escape_string($trans_id)); $result = mysql_query($query); $num_results = mysql_num_rows($result); if($num_results == 0) { return true; } return false; } /** * checks to make sure that paypal payment amount is correct * @param int $shipping * @param array $params * @return bool */ function payment_amount_correct($shipping, $params) { $amount = 0.00; for ($i=1; $i <= $params['num_cart_items']; $i++) { $query = sprintf("SELECT price from products where id='%s'", mysql_real_escape_string($params["item_number{$i}"])); $result = mysql_query($query); if($result) { $item_price = mysql_result($result, 0, 'price'); $amount += $item_price * $params["quantity{$i}"]; } } if(($amount+$shipping) == $params['mc_gross']) { return true; } else { return false; } } /** * creates order and adds items * @param array $params * @return bool */ function create_order($params) { db_connect(); $query = sprintf("INSERT INTO orders set orders.firstname = '%s', orders.lastname = '%s', orders.email = '%s', orders.country = '%s', orders.address = '%s', orders.city = '%s', orders.zip_code = '%s', orders.state = '%s', orders.status = '%s', orders.amount = '%s', orders.paypal_trans_id = '%s', created_at = NOW() ", mysql_real_escape_string($params['first_name']), mysql_real_escape_string($params['last_name']), mysql_real_escape_string($params['payer_email']), mysql_real_escape_string($params['address_country']), mysql_real_escape_string($params['address_street']), mysql_real_escape_string($params['address_city']), mysql_real_escape_string($params['address_zip']), mysql_real_escape_string($params['address_state']), mysql_real_escape_string($params['payment_status']), mysql_real_escape_string($params['mc_gross']), mysql_real_escape_string($params['txn_id']) ); $result = mysql_query($query); if(!$result) { return false; } $order_id = mysql_insert_id(); for ($i=1; $i <= $params['num_cart_items'] ; $i++) { $product = find_product($params["item_number{$i}"]); $query = sprintf("INSERT INTO items set order_id = '%s', product_id = '%s', title = '%s', price = '%s', qty = '%s' ", mysql_real_escape_string($order_id), mysql_real_escape_string($product['id']), mysql_real_escape_string($product['title']), mysql_real_escape_string($product['price']), mysql_real_escape_string($params["quantity{$i}"]) ); $result = mysql_query($query); if(!$result) { return false; } } return true; } // read the post from PayPal system and add 'cmd' $req = 'cmd=_notify-validate'; foreach ($_POST as $key => $value) { $value = urlencode(stripslashes($value)); $req .= "&$key=$value"; } // post back to PayPal system to validate $header .= "POST /cgi-bin/webscr HTTP/1.0\r\n"; $header .= "Content-Type: application/x-www-form-urlencoded\r\n"; $header .= "Content-Length: " . strlen($req) . "\r\n\r\n"; $fp = fsockopen ('www.paypal.com', 80, $errno, $errstr, 30); // assign posted variables to local variables $item_name = $_POST['item_name']; $item_number = $_POST['item_number']; $payment_status = $_POST['payment_status']; $payment_amount = $_POST['mc_gross']; $payment_currency = $_POST['mc_currency']; $txn_id = $_POST['txn_id']; $receiver_email = $_POST['receiver_email']; $payer_email = $_POST['payer_email']; if (!$fp) { // HTTP ERROR } else { fputs ($fp, $header . $req); while (!feof($fp)) { $res = fgets ($fp, 1024); if (strcmp ($res, "VERIFIED") == 0) { if ($_POST['payment_status'] == 'Completed' && no_paypal_trans_id($_POST['txn_id']) && $paypal_email == $_POST['receiver_email'] && $paypal_currency == $_POST['mc_currency'] && payment_amount_correct($shipping, $_POST) ) { // process payment create_order($_POST); } } else if (strcmp ($res, "INVALID") == 0) { // log for manual investigation } } fclose ($fp); } ?> |
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