PHP - How Can I Retrieve Different Rows Of Data From Mysql Database Table And Display Them In Multi-item Bootstrap Carousel?
i have 8 division (div), i want to display 4 rows in 4 division and the remain 4 rows in the next 4 division here is my code structure for carousel
<div class="nyie-outer"> second row third row
fourth row fifth row sixth row seven throw eighth row
</div><!--/.second four rows here-->
sql code
CREATE TABLE product( php code
<?php how can i echo that result in those rows
Similar TutorialsI've been working on developing a CMS blog and now I'm trying to create a slideshow wit Bootstrap Carousel on the homepage to present the dynamic content (images + text) using the data from table 'posts'. I tested this code, and it only presents one post. I mean, It's not possible to go to the next slide. I want to show all the posts on the slides. *The DB connection is already on the includes. The connection was written on a small file called DB.php Home.php <header> <div id="carouselExampleIndicators" class="carousel slide" data-ride="carousel"> <ol class="carousel-indicators"> <li data-target="#carouselExampleIndicators" data-slide-to="0" class="active"></li> <li data-target="#carouselExampleIndicators" data-slide-to="1"></li> <li data-target="#carouselExampleIndicators" data-slide-to="2"></li> </ol> <div class="carousel-inner" role="listbox"> <?php // The default SQL query $sql = "SELECT * FROM posts ORDER BY id desc"; $stmt = $ConnectingDB->query($sql); while ($DataRows = $stmt->fetch()) { $Id = $DataRows["id"]; $PostTitle = $DataRows["title"]; $Image = $DataRows["image"]; $PostText = $DataRows["post"]; ?> <!-- Slide --> <div class="carousel-item active" style="background-image: url('uploads/<?php echo $Image; ?>')"> <div class="carousel-caption"> <div class="card-body black"> <h3 class="large-mistral-white"><?php echo $PostTitle; ?></h3> <p class="small-times-white"><?php echo $PostText; ?></p> </div> </div> </div> <?php } ?> </div> <a class="carousel-control-prev" href="#carouselExampleIndicators" role="button" data-slide="prev"> <span class="carousel-control-prev-icon" aria-hidden="true"></span> <span class="sr-only">Previous</span> </a> <a class="carousel-control-next" href="#carouselExampleIndicators" role="button" data-slide="next"> <span class="carousel-control-next-icon" aria-hidden="true"></span> <span class="sr-only">Next</span> </a> </div> </header> DB.php <?php $DSN='mysql:host = localhost; dbname=everybody_blog'; $ConnectingDB = new PDO($DSN,'root',''); ?>
hi guys, im new to this forum I'm new also to php, I need help from you guys: I want to display personal information from a certain person (the data is on the mysql database) using his name as a link: example: (index.php) names 1. Bill Gates 2. Mr. nice Guy i want to click Bill Gates (output.php) Name: Bill Gates Country:xxxx Age: xx etc. How can i make this or how to learn this? As a complete newbie to php and webdesigning i have a following problem.I would like to retrieve the data from database and display it in a drop down menu.Then i should allow the user to select the values from drop down list along with other details,in other words i have to embed the drop down output as the form input for the user and store the form data in another table.I am running a xampp server and i am using php 5.4 version.Please help.My code is as follows.In this case project_name is displayed as the drop down output.but how do i use the same drop down output as a input in the form. <html> <head></head> <body> <?php error_reporting(E_ALL ^ E_DEPRECATED); include 'connect.php' ; $tbl_name="projects"; $sql="SELECT project_name FROM $tbl_name "; $result=mysql_query($sql); if($result === FALSE) { die(mysql_error()); } ?> <form name="resources" action="hourssubmit.php" method="post" > <?php echo "<select name='project_name'>"; while ($row = mysql_fetch_array($result)) { echo "<option value='" . $row['project_name'] ."'>" . $row['project_name'] ."</option>"; } echo "</select>"; ?> </form> </body> </html> I am not sure if the title is correct; I tried my best.
I'm a PHP/MySQL beginner and I really need some help.
I have a small script that I am using for sending SMS. I recently added a phonebook. The problem with the phonebook right now is that it's available to all users, i.e. they can all update and delete all rows. What I would like to do is make it so that each user can update and delete only their own contacts.
I have a table call contacts. Inside that table there is first name, last name, company and phonenumber.
How can I accomplish this with PHP & MySQL?
CREATE TABLE IF NOT EXISTS `contacts` ( `contact_id` int(10) NOT NULL AUTO_INCREMENT, `firstname` varchar(255) NOT NULL, `lastname` varchar(255) NOT NULL, `company` varchar(255) NOT NULL, `cell_no` text NOT NULL, PRIMARY KEY (`contact_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; CREATE TABLE IF NOT EXISTS `users` ( `user_id` int(11) NOT NULL AUTO_INCREMENT, `users_name` varchar(30) NOT NULL, `uname` varchar(30) NOT NULL, `u_pass` varchar(60) NOT NULL, `utype` varchar(30) NOT NULL, `timezone` varchar(30) NOT NULL, `uapi_user` varchar(30) NOT NULL, `uapi_pass` varchar(60) NOT NULL, PRIMARY KEY (`user_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ; <?php if (isset($_POST['submit'])){ //form has been submitted1 $firstname = trim($_POST['firstname']); $lastname = trim($_POST['lastname']); $company = trim($_POST['company']); $cellno = trim($_POST['cell_no']); if($firstname == ''){ echo '<div class="alert alert-danger">First Name is not Valid!</div>'; exit; }elseif($lastname == ''){ echo '<div class="alert alert-danger">Last Name is not Valid!</div>'; exit; }elseif($company == ''){ echo '<div class="alert alert-danger">Company is not Valid!</div>'; exit; }elseif($cellno == ''){ echo '<div class="alert alert-danger">Cellphone Number is not Valid!</div>'; exit; }else{ $query = "Select cell_no from contacts where cell_no = '".$cellno."' "; $result = mysql_query($query); if (!mysql_num_rows($result)) { $sql = "INSERT INTO contacts(firstname, lastname, company, cell_no) values('{$firstname}','{$lastname}', '{$company}', '{$cellno}')"; $result = mysql_query($sql); confirm_query($result); //echo '<div class="alert alert-success">Successfully added.</div>'; //exit; ?> <script type="text/javascript"> window.location = "contact_list.php"; </script> <?php } else{ echo '<div class="alert alert-danger">Username. already exist!.</div>'; echo '<p><a href="new_contact.php" class="btn btn-success"> Back </a></p>'; exit; }} }else{ $firstname = ""; $lastname = ""; $company = ""; $cellno = ""; } ?> i'm trying to echo out the results from a query onto a page, but rather than having them echo out as rows in a table, i want them to be displayed in columns, i.e. first column would have the first 10 results and the second column would have the next to. Any ideas on how i could do this? at the moment i'm using this code to display my results $read=mysql_query("SELECT * FROM entry WHERE category_id=".$id." ORDER BY entry_title") or die("query failed".mysql_error()); $result=mysql_num_rows($read); for($j = 0; $j < $result; $j++) { $row = mysql_fetch_array($read); echo "<a href=article.php?id=".$row['entry_id']. ">".$row['entry_title']."</a><br />"; } but this just displays it as a list down the middle thanks I have a blog on my website and the blogs content is stored in a database. On my home page I have the two recent articles displayed on my home page but I have to change them manually so I add the recent article on the home page in the first column and the second most recent one in the next column so they are side by side. What I want to do is automatically display the blogs image and blog title from the database and display on the home page so I don't have to keep changing it manually My current code looks like the following <div class="block"> <div class="container"> <h3 class="text-center"><span class="color">Recent Blog Articles</span></h3> <div class="row"> <div class="col-md-6"> <div class="text-img animation" data-animation="fadeInLeft" data-animation-delay="0.5s"> <a href="https://www.it-doneright.co.uk/blog/one-year-to-go-until-end-of-support-for-windows-7"> <div class="image"> <img class="img-responsive" src="https://www.it-doneright.co.uk/images/blog/windows7-eos-new.jpg" alt="One year to go until end of support for Windows 7"> </div> <p>One year to go until end of support for Windows 7</p> </a> </div> </div> <div class="col-md-6"> <div class="text-img animation" data-animation="fadeInLeft" data-animation-delay="0.5s"> <a href="https://www.it-doneright.co.uk/blog/windows-10-is-going-to-require-7gb-of-storage-for-future-updates"> <div class="image"> <img class="img-responsive" src="https://www.it-doneright.co.uk/images/windows-ten-updates-needing-7gb-space-on-hard-drive.jpg" alt="Windows 10 is going to require 7gb of storage for future updates"> </div> <p>Windows 10 is going to require 7gb of storage for future updates</p> </a> </div> </div> </div> </div> </div> I did look on Google before posting but could not get my head around how to do it, could anyone point me in the right direction or start me off and will have a go Hi, I have a 'pre-release' sign up form, where people put in their email address and name, and it transmits to a MYSQL database. That's working fine. What I want to do is to have a piece of text that reads: (insert pre release amount of signer upperers here) have signed up. Will you? I'm guessing that the amount of rows on the table, would end up being the number. How do I do this? Thanks, Jack Hello to all, I have problem figuring out how to properly display data fetched from MySQL database in a HTML table. In the below example I am using two while loops, where the second one is nested inside first one, that check two different expressions fetching data from tables found in a MySQL database. The second expression compares the two tables IDs and after their match it displays the email of the account holder in each column in the HTML table. The main problem is that the 'email' row is displayed properly while its while expression is not nested and alone(meaning the other data is omitted or commented out), but either nested or neighbored to the first while loop, it is displayed horizontally and the other data ('validity', 'valid_from', 'valid_to') is not displayed.'
Can someone help me on this, I guess the problem lies in the while loop? <thead> <tr> <th data-column-id="id" data-type="numeric">ID</th> <th data-column-id="email">Subscriber's Email</th> <th data-column-id="validity">Validity</th> <th data-column-id="valid_from">Valid From</th> <th data-column-id="valid_to">Valid To</th> </tr> </thead> Here is part of the PHP code:
<?php while($row = $stmt->fetch(PDO::FETCH_ASSOC)) { echo ' <tr> <td>'.$row["id"].'</td> '; while ($row1 = $stmt1->fetch(PDO::FETCH_ASSOC)) { echo ' <td>'.$row1["email"].'</td> '; } if($row["validity"] == 1) { echo '<td>'.$row["validity"].' month</td>'; }else{ echo '<td>'.$row["validity"].' months</td>'; } echo ' <td>'.$row["valid_from"].'</td> <td>'.$row["valid_to"].'</td> </tr>'; } ?>
Thank you. I have got connection to the the mysql database, how do I get the data from the database to display on the webpage im making a game and i need to show a users money but i dont know how help? how i want to display data from database to look like this : <table width="633" height="224" border="1"> <tr bgcolor="#999900"> <td width="45">Bil</td> <td width="121">Course_name</td> <td width="83">session</td> <td width="83">start_date</td> <td width="83">end_date</td> <td width="83">notes</td> <td width="89">pre-req</td> </tr> <tr bgcolor="#6A7AEA"> <td rowspan="2">1.</td> <td rowspan="2" bgcolor="#6A7AEA">Math</td> <td>1st session </td> <td>1 jan 11 </td> <td>6 jan 11 </td> <td rowspan="2"> </td> <td rowspan="2"><image icon that will link to the oter site> </td> </tr> <tr> <td bgcolor="#6A7AEA">2nd session </td> <td bgcolor="#6A7AEA">8 jan 11 </td> <td bgcolor="#6A7AEA">15 jan 11 </td> </tr> <tr> <td bgcolor="#0066CC">2.</td> <td bgcolor="#0066CC">English</td> <td bgcolor="#0066CC">1st session </td> <td bgcolor="#0066CC">1 feb 11 </td> <td bgcolor="#0066CC">6 feb 11 </td> <td bgcolor="#0066CC"> </td> <td bgcolor="#0066CC"><image icon that will link to the oter site></td> </tr> <tr> <td rowspan="2" bgcolor="#6A7AEA">3.</td> <td rowspan="2" bgcolor="#6A7AEA">Science</td> <td height="29" bgcolor="#6A7AEA">1st session </td> <td bgcolor="#6A7AEA">8 march 11 </td> <td bgcolor="#6A7AEA">15 march 11 </td> <td rowspan="2" bgcolor="#6A7AEA"> </td> <td rowspan="2" bgcolor="#6A7AEA"><image icon that will link to the oter site></td> </tr> <tr> <td bgcolor="#6A7AEA">2nd session</td> <td bgcolor="#6A7AEA">16 march 11 </td> <td bgcolor="#6A7AEA">21 march 11 </td> </tr> </table> ** all the view data is called from database including the icon image thanks... Hi, here's my problem: I am trying to make a simple online buying website and I want to display a table with all the fields for each item. So I got that part down which is to just use mysql_fetch_assoc("SELECT * FROM myTable") and use the html table tags stuff, but now I want to display my images in the table, so here's my code to display my mysql database table in html's table tag along w/ php: <html> <head> <title>My Online buying website project</title> </head> <body> <?php mysql_connect("localhost","root"); mysql_select_db("myTable"); $imagesArray=array("Apple_iPhone3GS.jpg","Apple_iPhone4.jpg","product3.jpg","product4.jpg","product5.jpg"); $result=mysql_query("SELECT Name, Manufacturer, Price, Description, SimSupport FROM myTable"); if(mysql_num_rows($result))//if there is at least one entry in bellProducts, make a table { print "<table border='border'>"; print "<tr> <th>Name</th> <th>Manufacturer</th> <th>Price</th> <th>Description</th> <th>SimSupport</th> </tr>"; //NB: now output each row of records while($row=mysql_fetch_assoc($result)) { extract($row); print "<tr> <td>$Name</td> <td>$Manufacturer</td> <td>$Price</td> <td>$Description</td><td>$SimSupport</td> </tr>"; }//END WHILE }//END IF ?> </table> </body> </html> *So how do I go about adding my images in this table? Hi all, I have a data base with the following table: ---member_data--- id ^ mid ^fieldname^ fieldvalue 1 - 2 - applicant - Seth Smith 2 - 4 - firstname - Chris 3 - 4 - lastname - Cooper 4 - 7 - full_name - Joey Jones 5 - 7 - occupation - Programmer 6 - 7 - phone - 800-555-1212 And below is a snippet that I use to display the selected members data for editing ------------------------------- <table> <tr> <td>Name:</td> <td>Value:</td> </tr> <?php $query = "SELECT * FROM member_data WHERE mid='$mid'"; $result= mysql_query($query); while($row = mysql_fetch_array($result)) { $fieldname = $row["fieldname"]; $fieldvalue = $row["fieldvalue"]; ?> <tr> <td><input type="text" name="<?php echo $fieldname;?>" value="<?php echo $fieldname;?>"></td> <td><input type="text" name="<?php echo $fieldvalue;?>" value="<?php echo $fieldvalue;?>"></td> <?php } ?> </tr> </table> ------------------------------- My question is: - using the Db example above: - lets say Ive selected mid#7 (member id 7) to edit which is displayed using the snippet code from above. - once displayed how do I edit mid#7 given the fact that mid#7 is located on 3 seperate rows from the same table? Thank you, Dave *ALSO - I tried the snippet below which did Not work. foreach($_POST as $key => $val) { $sql = "UPDATE member_data SET fieldname='$key', fieldvalue='$val' WHERE mid='$mid'"; $result = mysql_query($sql); } i have a mysql table which contains name like mid mname 101 AAA 102 BBB 103 CCC now i have to print this name in a html table like AAA, BBB, CCC i am getting this by while loop in a variable but when loop changes then value also change so please tell me how i get this only in one variable & print I have code for displaying result from database:
foreach ($_SESSION["products"] as $cart_itm) { $product_code = $cart_itm["code"]; $results = $mysqli->query("SELECT * FROM products WHERE product_code='$product_code' LIMIT 1"); $obj = $results->fetch_object();Now, I display data with: $obj->product_name When I get the list, how to put inline numbers (1 2 3 4 ...)? 1 products1 2 products1 3 products1 4 products1.. Hi, Im trying to retrieve HTML from a mysql database but nothing i've tried seems to work. The HTML im trying to retrieve is an iframe with a link and styles (code from amazon associates). Im trying to display links to specific products on amazon from the product page on my site. All data about the product is retrieved from the database so i have code to select the amazon link row in my database table but i cant get it to display. It says the html isnt a string so i cant echo it, fair enough. I have tried using the following code: Code: [Select] $get_buylink_sql = "SELECT mobo_buylink FROM mobo WHERE mobo_id = $mobo_id"; $get_buylink_res = mysqli_query($mysqli, $get_buylink_sql) or die(mysqli_error($mysqli)); while ($buylink = mysqli_fetch_array($get_buylink_res)) { echo"<iframe src=\"".$buylink."\" style=\"width:120px;height:240px;\" scrolling=\"no\" marginwidth=\"0\" marginheight=\"0\" frameborder=\"0\"></iframe>"; } mysqli_free_result($get_buylink_res); mysqli_close($mysqli);I have also tried putting the whole iframe code in the database which didnt work either. The mobo_id variable works fine for retrieving the rest of the data and i need to get the amazon link from the same record. I hope i've put this in a way you can understand, but if not i'll try and explain better and give you a link to my site if needed. Thanks, Alex Hey everyone. I am creating a website so my family can select from the list of present my daugther has asked for. I have them logging in, and that works. I have the table data set and the search and table display works. But I would like to display the list (as in the code below) but with a checkbox in the first column (add a column). From that the authenticated user can click on the item they have purchased and that selection will be moved to another table (called purchased). I have that code. The only thing I cannot figure out is to present the data in list form with a checkbox (like you would see on an order form). Here is the display code (there is no error checking at this point): <head><LINK REL="SHORTCUT ICON" HREF="cmwschl.ico"></head> <body bgcolor="#C0C0C0"> <font face="Arial" color="#000080">Books from the Selected Series</font> </h1> <hr font color="Navy" font size="3"> <center> <table border="1" cellpadding="5" cellspacing="0" bordercolor="#000000"> <tr> <td width="170" bgcolor="#FFCC66"><center><b><font color="navy" size="2" face="Trebuchet MS"><b><center>Book Number</center></font></b></center></td> <td width="140" bgcolor="#FFCC66"><center><b><font color="navy" size="2" face="Trebuchet MS"><b><center>Book Group</center></font></b></center></td> <td width="100" bgcolor="#FFCC66"><center><b><font color="navy" size="2" face="Trebuchet MS"><b><center>Book Title</center></font></b></center></td> </tr> <?php $con = mysql_connect("localhost","twilson","R00tb33r!") or die('Connection: ' . mysql_error());; mysql_select_db("CMWWeb", $con) or die('Database: ' . mysql_error()); ?> <? $group = $_POST['bookgrp']; //if ($Prod <> 0) { $sql = "SELECT * FROM `OpenBooks` WHERE `bookgrp`= '$group'"; $results = mysql_query($sql); if ($results) { //this will check if the query failed or not if (mysql_num_rows($results) > 0) { //this will check if results were returned while($copy = mysql_fetch_array($results)) { $variable1=$copy['booknum']; $variable2=$copy['bookgrp']; $variable3=$copy['booktitle']; //table layout for results print ("<tr>"); print ("<td><center>$variable1</center></td>"); print ("<td><center>$variable2</center></td>"); print ("<td><left>$variable3</left></td>"); print ("</tr>"); } } else { echo "No results returned"; } } else { echo "Query error: ".mysql_error(); } mysql_close($con); ?> </table> </center> I insert multiple id from my checkbox to mysql database using php post form. in e.x i insert id (checkbox value table test) to mysql. no i need to any function for retrieve data from mysql and print to my page with my e.x output.(print horizontal list name of table test where data = userid) my checkbox value ( name table is test ) : Code: [Select] 01 ---id----- name ---- 02 ---1 ----- test1 ---- 03 ---2 ----- test2 ---- 04 ---3 ----- test3 ---- 05 ---4 ----- test4 ---- 06 ---5 ----- test5 ---- 07 ---6 ----- test6 ---- 08 ---7 ----- test7 ---- 09 ---8 ----- test8 ---- 10 ---9 ----- test9 ---- mysql data Insert ( name of table usertest ): Code: [Select] 1 ---id----- data ---- userid ----- 2 ---1 ----- 1:4:6:9 ---- 2 ----- 3 ---2 ----- 1:2:3:4 ---- 5 ----- 4 ---3 ----- 1:2 ---- 7 ----- example outout : ( print horizontal list name of table test where data = userid ) print? Code: [Select] 1 user id 2 choise : test1 - test4 - test6 - test9 Thanks Hi folks, Complete No0b here when it comes to PHP and MySQL. I am in the middle of creating a PHP website. What I want to do is have the contents of a page in a MySQL table and have PHP gather the page content and display it on the page. Here is what I have in my home.tpl file: Code: [Select] <?php $query = "SELECT home, FROM $database_name"; $result = mysql_query($query); ?> And, in my index.php I simply call that home.tpl to display the data by using: Code: [Select] <?php include 'templates/default/home.tpl'; ?> Now, all I get is a blank page on index.php. Is there something else I should be doing? Remember, I am a complete No0b! Thanks folks. I want to use session to do a query and will I be able to do this? I have a session that was gathered from login and now i was to use this session to do a query If Yes, How? |