PHP - How To Find Image Height And Width Using Php Saved As Excel?
I have folder with 100's images, how to find Height and width as Excel sheet? Similar Tutorialsi am uploading image to s3 server and by php i am making a copy of that image on server , if i upload an image of 2.3 mb than the width of image is not coming but if i upload less size image like 26kb than it is showing the width of image so it is able to create the copy . here is my code of php : $s3 = new S3(awsAccessKey, awsSecretKey); $thumbId = uniqid(); $thumbId .= ".jpg"; $img = ''; if($imgType == "image/jpeg"){ $img = imagecreatefromjpeg($sourceUrl); }else if($imgType == "image/png"){ $img = imagecreatefrompng($sourceUrl); }else if($imgType == "image/gif"){ $img = imagecreatefromgif($sourceUrl); }else{ $img = imagejpeg($sourceUrl); } echo $width = imagesx( $img ); echo $height = imagesy( $img ); please tell me what is the problem with size of image.. regards rahul Hi Fellas, having a bit of a brain freeze here, i am trying to set a max width or height for a uploaded image, but my brain has frozen, maybe its the cold weather lol list($width,$height)=getimagesize($uploadedfile); $newwidth=250; $newheight=($height/$width)*$newwidth; $tmp=imagecreatetruecolor($newwidth,$newheight); basicly i want to find the biggest size of an image, beit width or height then set that size to 250... Any pointers here? Hey guys! I have the following php code that grabs variables (and the browsed image) from Flash. //FLASH VARIABLES $Name = $_POST['Name']; $itemNumber = $_POST['itemNumber']; $filename = $_FILES['Filedata']['name']; $filetmpname = $_FILES['Filedata']['tmp_name']; $fileType = $_FILES["Filedata"]["type"]; $fileSizeMB = ($_FILES["Filedata"]["size"] / 1024 / 1000); list($filename, $extension) = explode('.', basename($_FILES['Filedata']['name'])); $filename = $Name; $target = $filename . $itemNumber . "." . $extension; // Place file on server, into the images folder move_uploaded_file($_FILES['Filedata']['tmp_name'], "images/".$target); This works perfect, but what I want to change is the width and height of the uploaded image. Any ideas/suggestions on how this could be done? Thanks in advance!! Cheers! Hey guys I have a small issue, i have an upload that resizes the image into thumbnail by max width and ratios the width based on that. Here is my code
What I am wanting to do is instead upload the image with a max height and ratio the width proportionally. What variables do I have to reverse? Okay, so here is the deal. Have a table which stores image as blob files. Now i want to read the image width and height directly from the blob field. Is this possible and if yes, how? Things i tried so far; list($size[0],$size[1],$type, $attr) = getimagesize('image.php?i=26ddd45b02859e836d13d4b9fde34281'); print_r($size); $img = 'image.php?i=26ddd45b02859e836d13d4b9fde34281'; echo imagesy($img); image.php grabs the image from DB and show's it with header("Content-type: image/jpg"); It works for just showing the images with the <img> tag. Any ideas of help would be great! Hi there. How can i set up a maximum width and height of a picture? For example: the limit is 400x400. So if the photo is 200x200 then it stays that way, however if a photo is 550x550 then it gets resized to 400x400. Hi People. Thanks for all the help on here in the past, you have been brilliant. I run the airfield cards.com website and have a script in the output page that is as follows. Code: [Select] To Embed this Card into your website, cut and paste the following code: <input name="generate" value="<? echo "<iframe src='http://www.airfieldcards.com/php/courtesy_card.php?id=".$id. "' ></iframe>";?>"> Now the way it shows on the site is like this Code: [Select] <iframe src='http://www.airfieldcards.com/php/courtesy_card.php?id=165' ></iframe> So, I look at the iframe code from google that should be cut and pasted into a website (obviously it's working code from google) Code: [Select] <iframe width="700" height="1500" frameborder="0" scrolling="no" marginheight="0" marginwidth="0" src="http://maps.google.co.uk/maps/ms?msa=0&msid=203054009368331462137.0004aa731e7de2e86a0e0&ie=UTF8&t=h&vpsrc=0&ll=53.800651,-4.042969&spn=80.03397,61.435547&z=4&output=embed"></iframe><br /><small>View <a href="http://maps.google.co.uk/maps/ms?msa=0&msid=203054009368331462137.0004aa731e7de2e86a0e0&ie=UTF8&t=h&vpsrc=0&ll=53.800651,-4.042969&spn=80.03397,61.435547&z=4&source=embed" style="color:#0000FF;text-align:left">AirfieldCards.com</a> in a larger map</small> Now I have tried to take the code from the google iframe (width/height/scrolling/etc) and paste it into my source but it doesn't work. Here's how I have done it. Code: [Select] To Embed this Card into your website, cut and paste the following code: <input name="generate" value="<? echo "<iframe width="700" height="1500" frameborder="0" scrolling="no" marginheight="0" marginwidth="0" src='http://www.airfieldcards.com/php/courtesy_card.php?id=".$id. "' ></iframe>";?>"> Can someone please modify my fist lot of code so that I have the correct height and width settings (700 x 1500) Thanks in advance Regards Vince Gledhill Hello Everyone, I'm new to PHP and got a good big stuff. I would like to write an image in excel file. There will be almost 600+ rows and each row will have url and qrcode image. I would like to write an excel file which will write url and respective image into the next cell of the url. Is it possible to write an image in excel file? If yes, can anyone please guide me how? I have read so many post saying to use a pear package but again pear package is not allowing to write jpe/gif it only allows .bmp files. So, pear package is I don't think will work for me. I have also attached an example excel file which is showing the way I require to have an output. Please anyone if having any idea guide me and let me know. Thank you in advance for your help. Looking forward to hear from you soon! Hi folks, I'm using this code to display a picture that is uploaded in a form. Code: [Select] print "<img src='http://www.coast2kosci.com/mylongrun/test/photo_uploads/$imgx' width='300' height='300' alt='Your photo' />"; At first I tried specifying only the width, without the height. But for tall photos, the display wasn't really what I was after. Then I specified both width and height, which results in a mis-scaled photo. Is there any way that I can specify the height and width atributes as a sort of maximum / or limiter. Ie: If the height is greater than the width, limit the height to 300, and if the width is greater than the height, limit the width to 300? Thanks for your time, Dave Hi Im working on a market place style website. the framework im using is called elgg. it uses an algoritm to find the right approximate width and height of an image thats being uploaded. but on my site, all heights and widths must be the same. this is difficult because some pictures have much greater width than height and some have much greater height. so whats the best algoritm to use to make an accurate thumbnail of all images uploaded? Thanks Hi.., My code is like: Code: [Select] <?php $filename ="excelreport.xls"; print "<table border=1>"; print "<tr ><td valign=bottom><img src=http://abc/images/big.png ></img></td> <td valign=bottom><img src=http://abc/images/small.png ></img></td> </tr>"; print "</table>"; header('Content-type: application/ms-excel'); header('Content-Disposition: attachment; filename='.$filename); ?>when I open the excel file, the images alignment is from top to bottom(equal from top of image). what i want is from bottom to top(equal from bottom of image). i did try using valign in td property, but still the images equal from top of image thanks for any reply/ help I need some help and hopefully will respond. I'm trying to put some information to the second row of the excel sheet once extracted. Can somebody help me with this script? I'm trying to move the address line to the second row. Thanks. Hello, i am currently getting an Microsoft Excel formatted text file whose save type is .Txt from a URL.I used to open it and will change the save type as excel file. Please suggest whether we can do this with php code. currently my code is like this, <? php copy("http://www.faa.gov/airports/airport_safety/airportdata_5010/menu/emergencyplanexport.cfm?Region=&District=&State=&County=&City=LAS%20VEGAS&Use=&Certification=","./contactsexport.xls"); ?> where as the contactsexport.xls type is .Txt which i need it in .xls Thanks in Advance. Hi, I was in the process of making thumnails for avatars It used to work before but now the files are being saved as resource ID and not in an image format. I can not point out what the issue is and also may I add when I try to echo nothing is happening. Code: [Select] $filename = $_FILES['myfile']['tmp_name']; if ($_POST['cpic']) { // Set a maximum height and width $width = 100; $height = 100; // Get new dimensions list($width_orig, $height_orig) = getimagesize($filename); $ratio_orig = $width_orig/$height_orig; $ratio_orig; if ($width/$height > $ratio_orig) { $width = $height*$ratio_orig; } else { $height = $width/$ratio_orig; } // Resample $image_p = imagecreatetruecolor($width, $height); $image = imagecreatefromjpeg($filename); imagecopyresampled($image_p, $image, 0, 0, 0, 0, $width, $height, $width_orig, $height_orig); $location = "cid/$myid/$filename"; imagejpeg($image_p, $location, 100); $query =mysql_query ("UPDATE clp SET avatar ='$location' WHERE cid='1'"); header ("LOCATION: editprofile.php"); } is there a way to get the $image width?... the $image is not on my server so i cant use getimagesize().. e.g. $image = http://www.example.com/picture.jpg how do i get the width? I'm building a website that uses session variables. My understanding of session variables is that they only exist as long as the browser is open -- meaning that once the browser closes, the session variables are lost. I have a function that creates a dropdown list in a form. The User saves their answer to the mysql table. How do I get their preselected answer back out of the table when they visit the form again? I know how to pull it from mysql and into a variable, but how to modify the below code to display the correct answer stumps me. Here is my dropdown function: Code: [Select] function dropdown($array, $id) { echo '<select name="'.$id.'" id="'.$id.'" class="select"><option value="">Select one...</option>'; foreach($array as $key => $value) { echo '<option value="'.$value.'">'.$value.'</option>'; } echo '</select>'; } Thanks for the help! hi all, I have an array(1,2,3,4) and i make a form and make checkboxes for this array and user selects 2,3 and 4 when user submit form then i save it in table by making selected check boxes and converting selected values into bitwise equivalent value like this foreach($data['meal_types'] as $v){ $mealTypeBits += pow(2,$v-1); } Now when i have to show user his selected data how will i compare table bitwise saved record with array(1,2,3,4) to get the values that he checked while saving. I have a code that will get the value of amount from $_GET, and it adds it to an image I have stored. My problem is the that image I use is 32x32, but I need to add more height to it to make it look correct. The image is transparent so I'd need to keep that also. The code I have now works, but the value of amount is on top of the image where I don't want it to be. Here's my code. <?php header("Content-type: image/png"); $image = $_GET['image'] .'.png'; $img_handler = imageCreateFromPNG("./item images/" . $image); imagesavealpha($img_handler, true); $color = ImageColorAllocate($img_handler, 204, 156, 12); ImageString($img_handler, 2, 0, 0, $_GET['amount'], $color); ImagePng($img_handler); ImageDestroy($img_handler); ?> I have a webpage where the candidates can attach their resumes and send to the admin.These attachments are saved in the mysql db as blob datatype.In another webpage the admin needs to download all this resumes and see the content. How will i code for that. |