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PHP - Php And Querystring Problem

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Php And Querystring Problem	View Content

I've inherited some PHP code that is trying to save a querystring to a variable:

$from_url = '';

if ((isset($_GET['from'])) && ($_GET['from'] != '')) { $from_url = $_GET['from']; }

The sample URL is:

https://www.website.com/default.html?from=http://app.website.com/default.asp?utm_source=WelcomeEmail&utm_campaign=welcomeemail

What the code saves to $from_url is:

from=http://app.website.com/default.asp?utm_source=WelcomeEmail

It seems to stop at the "&" after the first querystring item and I understand why (because it parses the URL and runs into the next apostrophe "&" and assumes that it is not part of the "from" parameter).

How do I need to tweak the PHP code to have it save the entire querystring?

In other words, how do I take everything after ..."from=" (i.e. http://app.website.com/default.asp?utm_source=WelcomeEmail&utm_campaign=welcomeemail) and put it into a variable?

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Hyperlink/querystring Problem

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Need Help With Querystring ..

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Hi:

How can I build a querystring (or whatever I need to do to solve my issue) to pull in the month and year?

Meaning:

I have this link:
Code: [Select]
Entertainment.php

which goes to a dynamic calendar, which works fine except it does not show the events because I think it replies
on getting the current month and year.

When I click on a "Next Month" and the click back to the current month, the URL is:
Code: [Select]
Entertainment.php?month=4&year=2011

and the events then display properly in the calendar.

How do I properly build a URL for this?

The calendar code looks like this:
Code: [Select]
<?php
ob_start();
$today = date("M Y");
?>

...

<head>
<script>
function show_evt(m,y,day){
location.href = "<?=$_SERVER['PHP_SELF'];?>?month=" + m + "&year=" + y + "&day=" + day;
}

function goLastMonth(month, year)
{

if(month == 1)
{
--year;
month = 13;
}

document.location.href = '<?=basename($_SERVER['PHP_SELF']);?>?month='+(month-1)+'&year='+year;
}
function goNextMonth(month, year)
{

if(month == 12)
{
++year;
month = 0;
}

document.location.href = '<?=basename($_SERVER['PHP_SELF']);?>?month='+(month+1)+'&year='+year;
}
</script>
</head>

...

<p>

<?php

$date =time ();

$day = (isset($_GET['day'])) ? $_GET['day'] : date('d', $date);
$month = (isset($_GET['month'])) ? $_GET['month'] : date('m', $date);
$year = (isset($_GET['year'])) ? $_GET['year'] : date('Y', $date);

$first_day = mktime(0,0,0,$month, 1, $year);

$title = date('F', $first_day);

$day_of_week = date('D', $first_day);

switch($day_of_week){
     case "Sun": $blank = 0; break;
     case "Mon": $blank = 1; break;
     case "Tue": $blank = 2; break;
     case "Wed": $blank = 3; break;
     case "Thu": $blank = 4; break;
     case "Fri": $blank = 5; break;
     case "Sat": $blank = 6; break;
}

$days_in_month = cal_days_in_month(0, $month, $year);

?>
<table class="tableClass">
<tr class="field-bg-color">
<th class="eventLeftArrow"><a href="javascript: void(0);" onClick="goLastMonth(<?php echo $month . ", " . $year; ?>)"><<<</a></th>
<th colspan="5" class="eventHeader"><?=$title. " " . $year;?></th>
<th class="eventRightArrow"><a href="javascript: void(0);" onClick="goNextMonth(<?php echo $month . ", " . $year; ?>)">>>></a></th>
</tr>
<tr class="calDates">
<td>S</td>
<td>M</td>
<td>T</td>
<td>W</td>
<td>T</td>
<td>F</td>
<td class="lastOne">S</td>
</tr>
<?php

$day_count = 1;

?>
<tr>
<?php
while ( $blank > 0 ) {
?>
<td>      </td>
<?php
     $blank = $blank-1;
     $day_count++;
}

$day_num = 1;

while ( $day_num <= $days_in_month ) {
    $sql = "select count(calName) as evt_count from calTbl where calDate ='" . $month . '/' . $day_num . '/' . $year . "'";
    $result = mysql_query($sql);
    while($row = mysql_fetch_array($result)){
        if($row['evt_count'] >= 1){
    ?>
<td align="center" style="cursor:hand;cursor:pointer;background-color:#FF6A6A;text-align:center;" onclick="show_evt('<?=$month;?>','<?=$year;?>','<?=$day_num;?>');">
<div class="brown-bg-color cal-head-text white-text bold-text"><?=$day_num;?></div>      

<?php
        $sql = "select * from calTbl where calDate ='" . $month . '/' . $day_num . '/' . $year . "'";
        $result = mysql_query($sql);
            while($row = mysql_fetch_array($result)){
                ?>
<a href="<?=$_SERVER['PHP_SELF'];?>?month=<?=$month;?>&year=<?=$year;?>&day=<?=$day_num;?>"><?=$row['calName'];?></a></br>
<?
}
}else{
?>
<td>
<div class="brown-bg-color cal-head-text"><?=$day_num;?></div>      
<?php
        }
    }
?>
</td>
<?php
$day_num++;
$day_count++;

if ($day_count > 7){
?>
</tr><tr>
<?php
$day_count = 1;
}
}

while ( $day_count >1 && $day_count <=7 ) {
?>
<td> </td>
<?php
$day_count++;
}
?>
</tr></table>
<?php

if(isset($_GET['day'])){
         $sql = "select * from calTbl where calDate ='" . $month . '/' . $_GET['day'] . '/' . $year . "'";
         $result = mysql_query($sql);
         echo '<table class="data-table-class">';
         echo '<th>Event Name</th><th>Event Desc</th>';
        while($row = mysql_fetch_array($result)){
            echo '<tr><td>'. $row['calName'] . '</td><td>' . $row['calDesc'] . '</td></tr>';
        }
        echo '</table>';
}
?>

<div class="myClear"></div>

<?php
    ob_flush();
?>

</p>

Can anyone help me out? This is the last part and I am good to go!

Thanks!

Remove A Querystring From Url

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Anyone know how i can remove a querystring from url.

Example URL: http://www.mysite.com/?id=1

I am writing a script that needs to read in the ID from the URL. But once have got the information i would like to remove it from the URL and just display http://www.mysite.com but still be able to use the ID to query my database.

Any ideas???

Capture Value Via Querystring

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Greetings experts,

Please forgive me for this cheap question.

I have got a calendar of events and displays events for 7 departments.

For each department, we would like the calendar to display events specific to that department.

The way I am thinking about doing this is to grab the department from the url and compare it with the department on the db for which events is inserted into the db with.

If there is a match, then display the events for that department.

Something like:

$tquery = "select * from ".$EVENTS_TB." where ".$EVENTS_TB.".month='".$smmonth."' and ".$EVENTS_TB.".year='".$smyear."' and ".$EVENTS_TB.".deptid='deptFromQueryString' " ;

The problem that I have is that I don't in php, how to capture the querystring from url.

For instance, assume this is the url:

http://www.domain.com/departName.

DeparmentName represents the department value.

How do I capture the query above?

Thanks so much.

.htaccess Querystring

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I have the current rule in my htaccess

RewriteRule ^catalogue/([a-z0-9-]+)/([a-z0-9-]+).php$ catalogue/item.php?id1=$1&id2=$2 [L]

however whenever i type in the browser

/catalogue/computers/cases.php and then change the category to a category not in my database it still shows the item.php page but without any data - blank page.

How do you redirect this to a 404 or do I just write a script that if no records are found in the database redirect to the main catalogue page?

Passing Values Using Url Querystring

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Hi
I have a problem i need some help with, when passing values from my Results page to my Details page through a URL is the Querystring different because i have INNER JOINED 2 tables? This is my Querystring

<a href="DetailsPet.php?id=<?php echo $row_ResultsRS['id']; ?>">Details</a></td>

i have 2 tables (petdata and customerdata) and there INNER JOINED using the 'id'

But its not passing on the values, and just shows the 1st results in database all the time. Im only just learning Php, but would i be right in thinking it to do with the 'id' as this is what joins the 2 tables. Do i have to state which 'id' to use? if so how do i do it?

Thanks willo

Losing Part Of Querystring

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I am working with a fellow who runs an eCommerce shop. The transaction resolution comes in on a querystring. I do not yet know what web server software is being used, nor if any security appliance/software is installed. One of the values in the querystring starts with the @ character. We know the web server gets this as there entries in the web server's access log that shows thing value is present. It is not available in PHP's $_GET array. We are trying to get an idea of where this value, and it's key, is getting discarded. Is there a known problem with (actual server software being used not yet known) web server software discarding a key/value if the value has the @ character in the querystring?

Php Read Url In Folder Form Instead Of Querystring

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Hi,

how to let php read the url in folder form instead of querystring?

e.g.

www.example.com/index.php?post=123
www.example.com/post/123/

both is actually directed to the same page - index.php, but how to make it read like a folder when the physical path doesn't really exist?

Request Variable/querystring Issue

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Hi:

I am trying to pass/request a Variable/QueryString from one page to another, but it isn't working.

Seems like it would be simple, so maybe I am overlooking the obvious.

I have the 1st page:
Code: [Select]
<a href="NewCity.php?abbr_state=<?php echo $abbr_state ?>">Insert New City</a>

Writes the URL properly - CityList.php?abbr_state=CT

The 2nd page:
Code: [Select]
<?php

$abbr_state = $_REQUEST['abbr_state'];

?>

<form>

State: <input type="text" name="abbr_state" value="<?php echo $abbr_state; ?>" readonly=""/><br />

</form>

But it does not get the variable/QueryString for "CT" and add it to the form field (it's not the "readonly" causing it).

Why?

What did I miss?

Simple Date Passing In Querystring

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the ultimate goal is to let the user select to date range (begin date in DD-MM and enddate in DD-MM), pass this through php file with ajax and query it against the registered date (stored as a datetime),

however i'm already running problems catching the values of minDate and maxDate. Can sombody tell me what's wrong please?

Code: [Select]
if (document.getElementById('brdat_dag').value != ''){
var minDag = document.getElementById('brdat_dag').value;}
if (document.getElementById('brdat_maand').value != ''){
var minMaand = document.getElementById('brdat_maand').value; }
var minDate = date ('Y-m-d H:i:s', mktime (0,0,0,minMaand,minDag.value,date('Y', time())));

var queryString = "?postcode=" + postcode + "&provincie=" + provincie + "&aland=" + aland + "&gland=" +gland +"&minAge=" + minAge +"&maxAge=" + maxAge + "&sex=" + sex; + [color=red]"&minDatum=" + minDatum;[/color]

Problem Fixed But Caused New Problem

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Guys thanks for helping me solve the problem i had but now i have another problem and i am lost. i have included the code below for you to have overview.

On the home page the url shows how it should be: http://localhost/board/italian.php?country=Italian
BUT
When you mouse over the NEXT link to go to next page you get this : http://localhost/board/?page=1&country=Italian and then an error 404 when you click on the link
page = 1 no matter if you are mousing over link for page 5 or 2

This is the code:

<table style="width:100%; margin-left:auto; margin-right:auto">
       <?php

           $items_per_page = 5;//how many records/rows to display per page

           $page_url = "http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI'];

           $cleaned_current_page_country = htmlspecialchars($_GET["country"]);

           $page_number = (isset($_GET['page']))? filter_var($_GET['page']) : 1;
           //$page_number = filter_var($_GET['page']);
           //$page_number = $_GET['page'];

           $selected_restaurant_type = $_GET['country'];

           // find number of rows in the db
               $query = "SELECT * FROM menu_update WHERE special_of_theday = 1 AND restaurant_type = '".$selected_restaurant_type."' ";
               $query_result = mysqli_query($connection, $query);
               $row_count = mysqli_fetch_array($query_result);
               $total_rows = mysqli_num_rows($query_result);

           $expected_number_of_pages = ceil($total_rows/$items_per_page); //expected number of pages

           $page_position = (($page_number - 1) * $items_per_page); //get starting position to fetch record

           //fetch a group of records using sql LIMIT clause
               $query = "SELECT * FROM menu_update WHERE special_of_theDay = 1 AND restaurant_type = '".$selected_restaurant_type."' LIMIT " .$page_position. ',' .$items_per_page;
               $query_result = mysqli_query($connection, $query);
       ?>

           <table width="100%" border=0>
               <tr bgcolor = "#cccccc">
                   <td>Meal</td>
                   <td>Meal name</td>
                   <td>Meal Price</td>
                   <td>Order Now</td>
                   <td>Full Menu</td>
                   <td>Our Gallery</td>
                   <td>Find Us</td>
                   <td>Our Chef</td>
                   <td>Our Manager</td>
               </tr>
       <?php
               while($row_count = mysqli_fetch_array($query_result)){
                   echo "<tr>";
                       echo"
                           <td style ='width:200px; text-align:center; height:120px; background:#eaedf2'><a href='meal_fullPic.php'><img src= ".$row_count['img']." /></a></td>
                           <td style ='width:119px; text-align:center; height:120px; background:#eaedf2'> ".$row_count['meal_name']."</td>
                           <td style ='width:100px; text-align:center; height:120px; background:#eaedf2'>".$row_count['price']."</td>
                           <td style ='width:100px; text-align:center; height:120px; background:#eaedf2'><a href='order_processor.php'><img src= ".$row_count['order_now']." /></a></td>
                           <td style ='width:100px; text-align:center; height:120px; background:#eaedf2'><a href='full_menu.php'><img src= ".$row_count['full_menu_img']." /></a></td>

                           <td style ='width:170px; text-align:center; height:120px; background:#eaedf2'><a href='restaurant_gallery.php'><img src= ".$row_count['restaurant_pic']." /></a></td>
                           <td style ='width:100px; text-align:center; height:120px; background:#eaedf2'><a href='restaurant_location.php'><img src= ".$row_count['location_pic']." /></a></td>
                           <td style ='width:119px; height:120px; background:#eaedf2'> ".$row_count['chef_name']."</td>
                           <td style ='width:119px; height:120px; background:#eaedf2'> ".$row_count['admin']."</td>
                       ";
                   echo "</tr>";
               }
               mysqli_close($connection);
       ?>
           </table>
       <div class="board_pagination">
       <?php
           //display the links to the pages
           for($current_page = 1; $current_page <= $expected_number_of_pages; $current_page++){
    if ($page_number != $expected_number_of_pages){
                   $data = array(
                       'page' => $page_number,
                       'country' => $cleaned_current_page_country,
                   );
                   $the_query = http_build_query($data);
                   $page_url .= '?' . $the_query;
                   echo '<li><a href=" '.$the_query.' ">'.$current_page.'</a></li> ';
               }
           }
       ?>
       </div>
   </table>

Php Sql Problem

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Hi there,

I have a map of America made in flash, where you click on a state and the page should display the SQL database information for that state in the HTML table - but instead all it shows is the first entry of the database regardless of which state you click and it doesn't display the 2 radio buttons.

My code is as follows

Flash Actionscript 3 (just showing one state)
Code: [Select]
function waClick(event:MouseEvent):void {
var waURL:URLRequest = new URLRequest("restaurants.php?state=Washington");
navigateToURL(waURL, "_self");
}
wa_btn.addEventListener(MouseEvent.CLICK, waClick);
PHP code

Code: [Select]
<?php
  include("mvfconnect.php");
  $theChoice = $_GET['state'];
  $query = "SELECT * FROM restaurants WHERE" .$theChoice;
  $result = @ mysql_query($query);
  if (!$result) {
   $message="Unfortunately we are having problems with this page, we promise to have it fixed as soon as possible";
    die($message);
  }
  $num = mysql_num_fields($result);
  $i=0;
  while ($row = mysql_fetch_array($result, MYSQL_ASSOC)){
   $show1=substr($row['state'],0,50)."...";
   $show2=substr($row['city'],0,50)."...";
   $show3=substr($row['rname'],0,50)."...";
   $show4=substr($row['address'],0,50)."...";
   $show5=substr($row['pnum'],0,50)."...";
   $show6=substr($row['web'],0,50)."...";
   $show7=substr($row['dishes'],0,50)."...";
   $show8=substr($row['dish_details'],0,50)."...";
   $show9=substr($row['challenges'],0,50)."...";
   $show10=substr($row['challenge_details'],0,50)."...";
   $show11=substr($row['youtube'],0,50)."...";
   $show12=substr($row['images'],0,50)."...";
   echo "<tr>".
          "<td>".$row['city']."</td>".
          "<td>".$row['rname']."</td>".
          "<td>".$row['address']."</td>".
          "<td>".$row['pnum']."</td>".
          "<td>".$row['web']."</td>".
          "<td>".$row['dishes']."</td>".
          "<td>".$row['challenges']."</td>".
              "<td id='state".$i."' style='display:none'>".$row['state']."</td>".
          "<td id='city".$i."' style='display:none'>".$row['city']."</td>".
          "<td id='rname".$i."' style='display:none'>".$row['rname']."</td>".
          "<td id='address".$i."' style='display:none'>".$row['address']."</td>".
          "<td id='pnum".$i."' style='display:none'>".$row['pnum']."</td>".
          "<td id='web".$i."' style='display:none'>".$row['web']."</td>".
          "<td id='dishes".$i."' style='display:none'>".$row['dishes']."</td>".
          "<td id='dish_details".$i."' style='display:none'>".$row['dish_details']."</td>".
          "<td id='challenges".$i."' style='display:none'>".$row['challenges']."</td>".
          "<td id='challenge_details".$i."' style='display:none'>".$row['challenge_details']."</td>".
          "<td id='youtube".$i."' style='display:none'>".$row['youtube']."</td>".
                  "<td id='images".$i."' style='display:none'>".$row['images']."</td>".
                  "<td><input type='radio' name='vid' id='vid".$i."' onclick='openVideo(".$i.")' /></td>".
          "<td><input type='radio' name='pic' id='pic".$i."' onclick='openImage(".$i.")' /></td>".
          "<td class='last'style='display:none'>".$show1." ".$show2." ".$show3." ".$show4." ".$show5." ".$show6."
                  ".$show7." ".$show8." ".$show9." ".$show10."</td>".
         "</tr>";
    $i++;
   }
?>

I have used this code before and it has worked fine, can someone please help me out!

Problem...

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I'm trying to run a process using shell_exec, however the program i'm trying to run must communicate with a process that is not a system process, and everytime i run it, it fails, does anyone know how to make a apache/php server run active windows not in the system process?

Big Problem

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Hi guys,

I'm working on a side-project whilst my work at Uni is at a low but I'm extremely rusty on PHP; I've not touched it since around '07. Before I get on to my project, which will lift information from external websites, I'm just trying to acquaint myself with cURL again. Before I get flamed, yes this code is largely lifted from a website, but I pretty much understand it.

My aim is to be able to get the title of a website, namely Facebook. Whilst this code is fine on seemingly any other website, it doesn't seem to be able to work for Facebook. I've checked the source code, and I really can't see the problem. Can anyone shed some light for me?

Code: [Select]
<?php
    $url = 'http://www.facebook.com/';
    $webinfo = get_data($url);

    $title = get_match('/<title>(.*)<\/title>',$webinfo);

    $content= '<h2>Title of webpage: </h2><p>'.$name.'</p>';

    echo $content;

    function get_match($regex,$content)
    {
      preg_match($regex,$content,$matches);
      return $matches[1];
    }

    //gets the data from a URL
    function get_data($url)
    {
      $ch = curl_init();
      $timeout = 5;
      curl_setopt($ch,CURLOPT_URL,$url);
      curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
      curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,$timeout);
      $data = curl_exec($ch);
      curl_close($ch);
      return $data;
    }
    ?>
Thanks!!!

Little Url Problem Utf-8

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Sql Like Problem

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Code: [Select]
$sql = "SELECT softwareID,softwareName,softwareType,softwareDesc,softwarePath,ITOnly FROM software WHERE softwareName LIKE '%($searchSoftware)%' ORBER BY softwareName";
$result = mysqli_query($cxn,$sql) or die(mysqli_error());

There is something wrong with my LIKE statement because it's not pulling it since I'm either formatting it wrong or something.
Can anyone catch it?

The Problem With Vps

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Hi. I am from poland. I am 17 old age and like webmastering. I write my social network. I have new server 10 GB VPS and my script no runing In my server. in my server do can not login. No runing function
Code: [Select]
mb_strtolower();as delete function mb_strtolower() ; this login runing.
In my server haven`t installing liberary GD and no runing upload avatars.

my code upload is:
elseif ($_GET['act'] == "upload") {
echo <<< KONIEC
<hr>
<center>
        <p>
                <h2>Dodaj zdjęcie</h2>
                <ul class="gallery clearfix">
                        <li class="extra">
KONIEC;

error_reporting(E_ALL);

// we first include the upload class, as we will need it here to deal with the uploaded file
include('include/class.upload.php');

// retrieve eventual CLI parameters
$cli = (isset($argc) && $argc > 1);
if ($cli) {
    if (isset($argv[1])) $_GET['file'] = $argv[1];
    if (isset($argv[2])) $_GET['dir'] = $argv[2];
    if (isset($argv[3])) $_GET['pics'] = $argv[3];
}

// set variables
$dir_dest = (isset($_GET['dir']) ? $_GET['dir'] : 'test');
$dir_pics = (isset($_GET['pics']) ? $_GET['pics'] : $dir_dest);

if (!$cli) {

}

// we have three forms on the test page, so we redirect accordingly
if ((isset($_POST['action']) ? $_POST['action'] : (isset($_GET['action']) ? $_GET['action'] : '')) == 'simple') {

    // ---------- SIMPLE UPLOAD ----------

    // we create an instance of the class, giving as argument the PHP object
    // corresponding to the file field from the form
    // All the uploads are accessible from the PHP object $_FILES
    $handle = new Upload($_FILES['my_field']);

    // then we check if the file has been uploaded properly
    // in its *temporary* location in the server (often, it is /tmp)
    if ($handle->uploaded) {

        // yes, the file is on the server
        // now, we start the upload 'process'. That is, to copy the uploaded file
        // from its temporary location to the wanted location
        // It could be something like $handle->Process('/home/www/my_uploads/');
        $handle->Process($dir_dest);


         function TestProcess(&$handle, $title = 'test', $details='') {
            global $dir_pics, $dir_dest;
                        $unlink = 'test/'. $handle->file_dst_name;
$myid = $_SESSION['id'];
$opis = htmlspecialchars(stripslashes(strip_tags(trim($_POST["opis"]))), ENT_QUOTES);
            $handle->Process($dir_dest);

            if ($handle->processed) {
                                unlink("$unlink");
                                $link = ''.$dir_pics.'/' . $handle->file_dst_name .'';
                                $addphoto = mysql_query("INSERT INTO photo VALUES('', '$myid', '$link', '$opis')");
                                echo <<< KONIEC
                                <br>
                                <center>
                                <img src="$link" >
                                <br>
                                <br />
                                </center>
KONIEC;
            } else {
                echo '<fieldset class="classuploadphp">';
                echo '  <legend>' . $title . '</legend>';
                echo '  Error: ' . $handle->error . '';
                if ($details) echo '  <pre class="code php">' . htmlentities($details) . '</pre>';
                echo '</fieldset>';
            }
        }
        if (!file_exists($dir_dest)) mkdir($dir_dest);



        // -----------
                $handle->image_convert         = 'jpg';
                $handle->image_resize          = true;
        $handle->image_ratio_y         = true;
        $handle->image_x               = 500;
        $handle->image_precrop         = 15;
        $handle->image_watermark       = "watermark_large.png";
        $handle->image_watermark_x     = 20;
        $handle->image_watermark_y     = -20;
        TestProcess($handle, '15px pre-cropping (before resizing 800 wide), large watermark automatically reduced, position 20 -20', "\$foo->image_convert         = 'jpg';\n\$foo->image_resize          = true;\n\$foo->image_ratio_y         = true;\n\$foo->image_x               = 800;\n\$foo->image_precrop         = 15;\n\$foo->image_watermark       = 'watermark_large.png';\n\$foo->image_watermark_x     = 20;\n\$foo->image_watermark_y     = -20;");

        } else {
            // one error occured
            echo '<fieldset>';
            echo '  <legend>file not uploaded to the wanted location</legend>';
            echo '  Error: ' . $handle->error . '';
            echo '</fieldset>';
        }

        // we copy the file a second time


        // we delete the temporary files
        $handle-> Clean();

    } else {
        // if we are here, the local file failed for some reasons
        echo '<fieldset>';
        echo '  <legend>local file error</legend>';
        echo '  Error: ' . $handle->error . '';
        echo '</fieldset>';
    }

echo <<< KONIEC
<li>
                </ul>

        </p>
</center>
KONIEC;

is it the only problem that isn`t installing GD as i have something off in php.ini ? Plise Help me

I Think I Have A Problem.... Can You Help Me? :)

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i'm getting this erro
"Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 3 in /***/***/*****.php on line 278
not an active session, starts new"

this is the code:
if ($phase = mysql_result(mysql_query("SELECT `phase` FROM `as_support` WHERE `mission` = '$var2'"),0,0))
{
   if ($phase=='5') {
//      mysql_query("DELETE FROM `as_support` WHERE `mission` = '$var2'");
//      header("Location: https://www.**********/*******/*******.php");
   }
   else {
      echo date('h:i:s') . ": PHASE is $phase<br />";
      echo "\$var1=$var1,\$var2=$var2<br />";
   }
}
else {
   echo "not an active session, starts new<br />";
   echo "\$var1=$var1,\$var2=$var2<br />";
   mysql_query("INSERT INTO `as_support` (`mission`, `phase`) VALUES ('$var2', '0')") OR DIE(mysql_error());

the first line is line no. 278

can someone please tell me what to do?

tnx

shirley

If Then Problem

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Not exactly sure how to do this.

What I need is when a person clicks on the link ie: page.php?nid=1 then it loads what needs to be loaded but if a user clicks and there is no nid ie: page.php?nid= Then it loads something else.

if (nid==$nid){
echo "This is the data to show";
}else{
Show this data instead
}

Both if and else both show different mysql data.

Hopefully I explained myself well.

Problem With If -

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Hi Guys, I am having an issue with an if statement, I cant get it to go true, even though it clearly is!

Please excuse the messy code, im pulling my hair out here!

$itemprice[0] = 8.99;
$itemprice[1] = 19.95;
$itemprice[2] = 8.99;
print_r($itemprice);
echo "<BR>";
$x=0;
foreach($itemprice AS $val) {
echo gettype($val) .$val. "<br>";
if($val == 8.99) {
$x++;
$freecount++;
}
}
echo $x;

outputs correctly:
Array ( => 8.99 [1] => 19.95 [2] => 8.99 )
double8.99
double19.95
double8.99
x = 2

replacing:
$newtotal = add_to_price($id, $non_disc);
$itemprice[] = $newtotal - $non_disc;
print_r($itemprice);
echo "<BR>";
$x=0;
foreach($itemprice AS $val) {
echo gettype($val) .$val. "<br>";
if($val == 8.99) {
$x++;
$freecount++;
}
}
echo $x;

The add to price function returns a running total, the take away gives me the current item price in a for loop to build the array.

Output:

Array ( => 8.99 [1] => 19.95 [2] => 8.99 )
double8.99
double19.95
double8.99
x = 1

The problem? Well when I build the array up automatically it still prints the same, has the same datatype, yet the if statement does not catch the second 8.99 value?

Please accept my apologies for this post, it is my first ever and i've been doing this for 10 years now, i have never been this stumped on something so simple, I can only think it is a datatype error but i have tried apostrophes in the if, make no difference.

All help massively gratefully received.

Please email me if you want to see it in action...