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PHP - Import Csv In Mysql Db Using Ajax And Php
i was working on a mini project that imports csv file to the database through ajax and it's working fine
<?php
if(!empty($_FILES["marks_file"]["name"]))
{
$connect = mysqli_connect("localhost", "root", "", "dbname");
$output = '';
$allowed_ext = array("csv");
$extension = end(explode(".", $_FILES["marks_file"]["name"]));
if(in_array($extension, $allowed_ext))
{
$file_data = fopen($_FILES["marks_file"]["tmp_name"], 'r');
fgetcsv($file_data);
while($row = fgetcsv($file_data))
{
$name = mysqli_real_escape_string($connect, $row[0]);
$Physics = mysqli_real_escape_string($connect, $row[1]);
$Maths = mysqli_real_escape_string($connect, $row[2]);
$Chemistry = mysqli_real_escape_string($connect, $row[3]);
$Biology = mysqli_real_escape_string($connect, $row[4]);
$SST = mysqli_real_escape_string($connect, $row[5]);
$query = "
INSERT INTO csv
(name, Physics, Maths, Chemistry, Biology, SST)
VALUES ('$name', '$Physics', '$Maths', '$Chemistry', '$Biology' , '$SST')
";
mysqli_query($connect, $query);
}
$select = "SELECT * FROM csv ORDER BY id DESC";
$result = mysqli_query($connect, $select);
$output .= '
<table class="table table-bordered">
<tr>
<th width="25%" >name</th>
<th width="15%" >Physics</th>
<th width="15%" >Maths</th>
<th width="15%" >Chemistry</th>
<th width="15%" >Biology</th>
<th width="15%" >SST</th>
</tr>
';
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td>'.$row["name"].'</td>
<td>'.$row["Physics"].'</td>
<td>'.$row["Maths"].'</td>
<td>'.$row["Chemistry"].'</td>
<td>'.$row["Biology"].'</td>
<td>'.$row["SST"].'</td>
</tr>
';
}
$output .= '</table>';
echo $output;
}
else
{
echo 'errorx';
}
}
else
{
echo "errory";
}
?>
however the imported csv files inserts null values in the tables because the format of all csv files assigned to me are in the exact same format: ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,Fields,Physics~75,Maths~50,Chemistry~65,Bio~85,SST~100 ,,,Name1,10,25,35,42,62 ,,,Name2,80,45,45,45,25 ,,,Name3,63,25,63,36,36 ,,,Name4,82,36,75,48,42 ,,,Name5,45,45,78,25,24 ,,,Name6,36,36,15,75,36 ,,,Name7,99,45,24,24,45 ,,,Name8,45,85,85,85,96 i changed my code a bit modified the functions to espace blank spaces and not return null values in the data tables
while (($row = fgetcsv($file_data, 1000, ",")) !== FALSE)
{
if ((string) $row[0] != '0' and empty($row[0]))
{
continue;
}
$name = mysqli_real_escape_string($connect, $row[0]);
$Physics = mysqli_real_escape_string($connect, $row[1]);
$Maths = mysqli_real_escape_string($connect, $row[2]);
$Chemistry = mysqli_real_escape_string($connect, $row[3]);
$Biology = mysqli_real_escape_string($connect, $row[4]);
$SST = mysqli_real_escape_string($connect, $row[5]);
$query = "
INSERT INTO csv
(name, Physics, Maths, Chemistry, Biology, SST)
VALUES ('$name', '$Physics', '$Maths', '$Chemistry', '$Biology' , '$SST')
";
mysqli_query($connect, $query);
}
But it doesn't work with the specified csv files i think the ajax call breaks and that's why nothing happens.However it works fine with csv files without blank spaces Edited March 19, 2019 by zetastreak Similar TutorialsI have mysql exported in the following sql format: Code: [Select] - CREATE TABLE IF NOT EXISTS `pma_history` ( `id` bigint(20) unsigned NOT NULL AUTO_INCREMENT, `username` varchar(64) COLLATE utf8_bin NOT NULL DEFAULT '', `db` varchar(64) COLLATE utf8_bin NOT NULL DEFAULT '', `table` varchar(64) COLLATE utf8_bin NOT NULL DEFAULT '', `timevalue` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP, `sqlquery` text COLLATE utf8_bin NOT NULL, PRIMARY KEY (`id`), KEY `username` (`username`,`db`,`table`,`timevalue`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_bin COMMENT='SQL history for phpMyAdmin' AUTO_INCREMENT=3761 ; -- -- Dumping data for table `pma_history` -- INSERT INTO `pma_history` (`id`, `username`, `db`, `table`, `timevalue`, `sqlquery`) VALUES (2, 'root', 'information_schema', 'FILES', '2010-03-04 19:26:33', 'SELECT * FROM `FILES`') Just as an example anyway. What I need to be able to do, is import this using PHP. Does anyone know of a suitable class for doing this? I could make my own, but I cant quite work out the best way to seperate the queries out? Thanks I have a table I am trying to import to mySQL I am having trouble assigning the right variable which represents a column header to the correct column header in the mySQL table. <?php /********************************/ /* Code at http://legend.ws/blog/tips-tricks/csv-php-mysql-import/ /* Edit the entries below to reflect the appropriate values /********************************/ $databasehost = "xxx"; $databasename = "xxx"; $databasetable = "names"; $databaseusername ="xxx"; $databasepassword = "xxx"; $fieldseparator = "\t"; $lineseparator = "\n"; $csvfile = "AddEnt2.txt"; $con = @mysql_connect($databasehost,$databaseusername,$databasepassword) or die(mysql_error()); @mysql_select_db($databasename) or die(mysql_error()); $fcontents = file ('AddEnt2.txt'); # expects the csv file to be in the same dir as this script for($i=0; $i<sizeof($fcontents); $i++) { $line = trim($fcontents[$i],'\t'); // '\t' for tab delimeted $arr = explode('\t', $line); // '\t' for tab delimeted $name=implode("','",$arr); $PA=implode("','",$line); # if your data is comma separated # instead of tab separated # change the '\t' above to ',' $sql = "insert into $databasetable values ('$PA','$name')"; $sql = str_replace("''", mysql_escape_string("NULL"), $sql); $sql = str_replace("' '", mysql_escape_string("NULL"), $sql); mysql_query($sql); echo $sql ."<br>\n"; if(mysql_error()) { echo mysql_error() ."<br><b><font color=red>\n</b>"; } } ?> I have a problem with my project. i want to import Excel sheet directly into mysql database for PHP language without any conversion of Excel sheet into another format. i am very fed about this from last two weeks. So Please help me How I Do it. any expert please help me This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=358188.0 Hello I am trying to do a simple CSV import of a file and then upload to mysql. I am basing my code on an example I have found and I am getting the error message 'invalid file'. The example used includes a text box for the file import field and I am referencing the file from my computer in that box 'Users/James/name.csv' My code is as follows: HTML <form action="results.php?data=upload" method='post'> Import File : <input type='text' name='sel_file' size='20'> <input type='submit' name='submit' value='submit'> </form> PHP if ($b == 'upload') { $fname = $_FILES['sel_file']['name']; $chk_ext = explode(".",$fname); if(strtolower($chk_ext[1]) == "csv") { $filename = $_FILES['sel_file']['tmp_name']; $handle = fopen($filename, "r"); while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) { $sql = "INSERT into ".$db['name']."(field1,field2,field3,field4) values('$data[0]','$data[1]','$data[2]', '$data[3]')"; mysql_query($sql) or die(mysql_error()); } fclose($handle); echo "Successfully Imported"; } else { echo "Invalid File"; } } my file format is: 1,23,1,5 1,24,2,5 1,25,3,5 1,26,4,5 1,27,5,5 1,28,6,5 1,29,7,5 1,30,8,5 1,31,9,5 1,32,10,5 If anybody can help that would be good - or perhaps point out if I am going about this the wrong way - cheers Hey guys, I'm having a nightmare at the moment.
I am trying to import a CSV file into a MySQL table, some of the data is interested properly into the rows however some of the CSV row do not get imported.
Here is my PHP script:
<?php
$databasehost = "localhost";
$databasename = "name";
$databasetable = "import";
$databaseusername="username";
$databasepassword = "password";
$fieldseparator = ",";
$lineseparator = "\n";
$enclosedbyquote = '"';
$csvfile = "db-core/feed/csv/test.csv";
if(!file_exists($csvfile)) {
die("File not found. Make sure you specified the correct path.");
}
try {
$pdo = new PDO("mysql:host=$databasehost;dbname=$databasename",
$databaseusername, $databasepassword,
array(
PDO::MYSQL_ATTR_LOCAL_INFILE => true,
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION
)
);
} catch (PDOException $e) {
die("database connection failed: ".$e->getMessage());
}
$pdo->exec("TRUNCATE TABLE `$databasetable`");
$affectedRows = $pdo->exec("
LOAD DATA LOCAL INFILE ".$pdo->quote($csvfile)." REPLACE INTO TABLE `$databasetable`
FIELDS OPTIONALLY ENCLOSED BY ".$pdo->quote($enclosedbyquote)."
TERMINATED BY ".$pdo->quote($fieldseparator)."
LINES TERMINATED BY ".$pdo->quote($lineseparator)."
IGNORE 1 LINES");
echo "Loaded a total of $affectedRows records from this csv file.\n";
?>
As you can see the script is importing the CSV into the table however only 40 of the rows are added to the SQL table when there are actually 80 rows in the CSV. I am also telling the script to IGNORE 1 LINES if that has anything to do with the issue.
Here is one of the rows from the CSV file:
"AETA83919","AETV34458584","SD57VUP","BLACK","Diesel","2007","76778","Hatchback","3","VAUXHALL","CORSA","1.3 CDTi [90] SXi 3dr [AC]","1200","3989","","Manual","http://images.autoexposure.co.uk/AETA83919/AETV34458584_1b.jpg","0","3","","0","2007 57 reg VAUXHALL CORSA 1.3 CDTi [90] SXi 3dr [AC], Manual, Hatchback, Diesel, 76,778 miles. BLACK, Comprehensive Warranty Included In Price. HPI Checked! Pre Delivery Health Check!, 5 seats, LOVELY VAUXHALL CORSA SXI 1.3CDTI SXI WITH AIR CONDITIONING!! VERY WELL CARED FOR AND MAINTAINED AND JUST SERVICED BY DRIVEN CAR SALES LTD AT 76K!! GREAT COMBINATION OF PERFORMANCE AND ECONOMY!! VIEWING AND TEST DRIVING IS RECOMMENDED!! EACH CAR COMES WITH A MININIUM 9 MONTHS MOT. FULL MECHANICAL HEALTH CHECK GUARANTEES CAR IS PREPARED TO THE HIGHEST STANDARD. COMPREHENSIVE RAC WARRANTY INCLUDED. DRIVEN CAR SALES WELCOME ANY INSPECTION. BUY WITH CONFIDENCE AND REASSURANCE AS DRIVEN CAR SALES LTD ARE OFFICIAL MEMBERS OF RETAIL MOTOR INDUSTRY FEDERATION. VIEW OUR REVIEWS ON TRUSTPILOT. 3,989","","0","1","","UK","0","","0","0","","","",""As far as I can see everything looks fine with the row, all of the rows in the CSV end like this. One thing I have noticed is it looks like the rows that are missing are in fact being placed in the last column of every other row here is an example: So as you can see it looks like one row is being inserted into the last column of some rows and I am so confused to why this might be happening? Any ideas? <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Import a CSV File with PHP & MySQL</title> </head> <body> <form action="" method="post" enctype="multipart/form-data" name="csv" id="csv"> Choose your file: <br /> <input name="csv" type="file" id="csv" /> <input type="submit" name="Submit" value="Submit" /> </form> </body> I am working on a csv file import to mysql, which will include items in one table (irrelevant here), and a hierarchical table of categories (id | name | parent). I would think the simplest method to get each category name is too explode the categories from the csv into an array, for example: $array = "root/Business/Employment"; $categories = explode("/", $array); My problem though, is figuring out what the ID's are for each of the categories without knowing each name will be unique and not knowing for sure the full depth of each category hierarchy either. So (I think) I need to rely on the category structure to define the lowest level ID. So something like this: Code: [Select] SELECT t1.parent AS p1, t1.name AS lev1, t1.id AS cat1, t2.name AS lev2, t2.id AS cat2 FROM (categories AS t1) LEFT JOIN categories AS t2 ON t2.parent = t1.id WHERE t1.parent = '1' AND t2.name = "Employment"; This gives me the ID of Employment, but it's easily possible that the name will be duplicated somewhere else in another heirarchy (in fact I get 4 results from phpmyadmin). And since I don't know all these will be only 3 levels deep, it won't work all the time. Any ideas help would be greatly appeciated! Hi! I hope somebody can help me what im do wrong. i have checked that the data from the file is in $source_file but nothing imports to the database Code: [Select] <?php include('config.php'); include('opendb.php'); if(isset($_POST['upload'])) { $source_file = @$_POST['userfile']; //$source_file = fopen('http://localhost/test/upload/test.csv', 'r'); $target_table = 'foretag'; function csv_file_to_mysql_table($source_file, $target_table, $max_line_length=10000) { if (($handle = fopen("$source_file", "r")) !== FALSE) { $columns = fgetcsv($handle, $max_line_length, ","); foreach ($columns as $column) { $column = str_replace(".","",$column); } $insert_query_prefix = "INSERT INTO $target_table (".join(",",$columns).")\nVALUES"; while (($data = fgetcsv($handle, $max_line_length, ";")) !== FALSE) { while (count($data)<count($columns)) array_push($data, NULL); $query = "$insert_query_prefix (".join(",",quote_all_array($data)).");"; mysql_query($query); } fclose($handle); } } function quote_all_array($values) { foreach ($values as $key=>$value) if (is_array($value)) $values[$key] = quote_all_array($value); else $values[$key] = quote_all($value); return $values; } function quote_all($value) { if (is_null($value)) return "NULL"; $value = "'" . mysql_real_escape_string($value) . "'"; return $value; } } include('closedb.php'); echo "<br>done<br>"; ?> Hi, I am importing data from a csv file into mysql. Everything works fine except that the 'order_date' column in CSV is in the following format mm/dd/yy. Upon import I would like for that format to be changed to yyyy-mm-dd I am not sure how to modify the following code to be able to do so. Any help would be appreciated. <? include "connect.php"; if(isset($_POST['submit'])) { $filename=$_POST['filename']; $handle = fopen("$filename", "r"); while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) { $date = date("Y-m-d"); $import="INSERT into table (order_id, order_status, order_date, todays_date) values ('$data[0]', '$data[1]', '$data[2]', '$date')"; mysql_query($import) or die(mysql_error()); } fclose($handle); print "Import done"; } else { print "<form action='importnew.php' method='post'>"; print "Type file name to import:<br>"; print "<input type='text' name='filename' size='20'><br>"; print "<input type='submit' name='submit' value='submit'></form>"; } ?> I think this is the right section to post this is in..... Anyway.....I'm building a web site that requires i have functionality to upload a tab delimited file (or some file format that is easiest) via php and insert the data into MYSQL. I've searched for many third party scripts but none seem to work. So I've decided to move to the community to see if someone can give me insight on how i might accomplish this script. I have some third party scripts but I'm not sure if they'd be of any use. Thank you kindly This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=330652.0 Hello fellow programmers I recently bought a chat site without investigating (i know stupid me). this chat is made in Php / Mysql language and ajax, My question is, is there a possibility to convert the mysql to an IRC server. I dont know how to explane it 100% but is it possible to make the webchat thats coded in ajax & mysql work for a IRC server I have knowledge of mysql / php only is this above my level. My problem is that mysql is no option for chats, I need this webchat work with IRC but I have no idea where i should start. Maby someone can kick me in the right direction Thanks for your time & help Greets BTW this is the chatsite more people bought (this aint my site) but 100% the same : http://tinyurl.com/kk4gchd Edited by Remco, 26 November 2014 - 03:32 AM. This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=308756.0 Let's say I grab all the user's information from the users table. It's stored into a variable as an array: $pun_user. Now, to get access this user data, it selects all the data each refresh and sets it to $pun_user for extraction later. My idea: Create a $_SESSION['user_id'] = $pun_user['user_id'] And then when using updating stuff via ajax requests, I can just do SELECT blah from users where where user_id = $_SESSION['user_id'] instead of: calling the main query to enter all the data into $pun_user, then do that query AGAIN and do SELECT blah from users where user_id = $pun_user['user_id'] Is the $_SESSION way going to take a performance hit on the server? Or is the MYSQL way a more detrimental approach? Which way is faster, and less intrusive on the server? Edited by Monkuar, 22 January 2015 - 10:35 PM. Hi all,
I'm trying to code a dependable dropdownlist with php/mysql/ajax.
Goal is to select one thing in the first dropdown and depending on that option (and without reloading the page) enabling the second and add the options to the second, dependant on the first.
This is the index :
<?php
require_once($_SERVER['DOCUMENT_ROOT'].'/dbconnect.php');
?>
<script type="text/javascript" src="http://ajax.googleapis.com/
ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function()
{
$(".country").change(function()
{
var id=$(this).val();
var dataString = 'id='+id;
$.ajax
({
type: "POST",
url: "edit_form.php",
data: dataString,
cache: false,
success: function(html)
{
$(".city").html(html);
}
});
});
});
</script>
<?php
$id_test=$_POST['selector'];
$N = count($id_test);
for($i=0; $i < $N; $i++)
{
$result = mysqli_query($conn, "SELECT * FROM cloud where id='$id_test[$i]'");
while($row = mysqli_fetch_array($result))
{
$id_bird = $row['id'];
?>
<div style="margin:80px">
<label>Country :</label> <select name="country" class="country">
<option selected="selected">--Select Country--</option>
<?php
$sql=mysqli_query($conn, "SELECT category.id AS cat_id, category.name, category.type, cloud.id
FROM cloud,category,link_category_cloud
WHERE link_category_cloud.cloud_id = cloud.id
AND link_category_cloud.category_id = category.id
AND cloud.id='$id_test[$i]'");
while($row=mysqli_fetch_array($sql))
{
$id_test=$row['cat_id'];
$data=$row['name'];
echo '<option value="'.$id_test.'">'.$data.'</option>';
} ?>
</select>
<br/>
<br/>
<label>City :</label> <select name="city" class="city">
<option selected="selected">--Select City--</option>
</select>
</div>
<?php
}
}
?>
And this is the edit_form.php part :
<?php
require_once($_SERVER['DOCUMENT_ROOT'].'/dbconnect.php');
$cat_id = $_GET['cat_id'];
$cloud_id = $_GET['id'];
if($_POST['id_test'])
{
$id_test=$_POST['id_test'];
$data=$_POST['data'];
$sql=mysqli_query($conn, "SELECT * FROM link_category_cloud WHERE category_id={$cat_id}");
$data=$row['cloud_id'];
$id_test=$_POST['id_test'];
echo '<option value="'.$id_test.'">'.$id_test.' '.$data.'</option>';
//}
}
?>
Now, it does not work. I'm not only tring to pass through ID to 'edit_form.php', but also $data and $id_test[i]. Any idea how I can do this?
Thank you very much, all help is so appreciated!!
This topic has been moved to Beta Test Your Stuff!. http://www.phpfreaks.com/forums/index.php?topic=342258.0 I wonder whether someone can help me please. I've found http://www.plus2net.com/php_tutorial/ajax-listbox.php tutorial to create a drop down menu using mySQL table data, which, in turn returns a list of results on the page. Following this tutorial I've put together the tables in my database and the required scripts as shown in the tutorial with the one exception, the "z_db.php" file, which I've assumed to be: Code: [Select] <?php mysql_connect("host", "user", "password")or die(mysql_error()); mysql_select_db("database"); ?> The problem I have, is that when I try and run this, I receive the following error: Quote Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /homepages/2/d333603417/htdocs/development/catsearch.php on line 91 which is this line in the search form: echo "</head><body onload="ajaxFunction()";>";. I must admit I've guessed as to the structure of the 'z_db.php' file should look like because this is not shown so perhaps this is the problem. I just wondered wether someone could perhaps take a look at this please and let me know where I've gone wrong. Many thanks and kind regards
//my controller
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use DB;
class homeController extends Controller
{
public function index() {
$employee = DB::table('employee')->orderBy('id','desc')->get();
$department = DB::table('department')->orderBy('id','desc')->get();
return view('index', ['employee' => $employee , 'department' => $department]);
}
}
//my routes
Route::get('index','homeController@index');
//my view using blade temmplating engine
@foreach($employee as $emp)
<div class="employee">
<b>{{ $emp->name }} </b>
<a href="employee/{{ $emp->id }}">
<p class="intro">{{ substr($emp->intro ,0, 50) }}...</p>
</a>
</div>
@endforeach
@foreach($department as $dep)
<div class="department">
<b>{{ $dep->name }} </b>
<a href="department/{{ $dep->id }}">
<p class="desc">{{ substr($dep->description ,0, 100) }}...</p>
</a>
</div>
@endforeach
I want to fetch using ajax, how can i do it, teach/help me This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=347691.0 |
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