PHP - Git, Windows, Linux, And End Of Line

Is anyone running PHP storm on Windows and debugging their PHP code on a remote Linux box? I ask because I am contemplating buying PHPStorm.  What opinions I have read  on this configuration say it doesn't work well. 

Hi,

I have the following code:


Code: [Select]

<?
Header("content-type: application/x-javascript");
function returnimages($dirname="./windows/prezentare_jpg/") {
$files = array();
$curimage=0;
if($handle = opendir($dirname)) {
while(false !== ($file = readdir($handle))){
if(preg_match('/.jpg$/i', $file)){
echo 'galleryarray['.$curimage.']="'.$file .'";';
$curimage++;
}
}
closedir($handle);
}
return($files);
}
echo 'var galleryarray=new Array();';
returnimages();
?>


Ran on windows (xampp 1.7.7, PHP 5.3.8, Apache 2.2.21) it returns the correct alfabetical/numerical order:

Code: [Select]
var galleryarray=new Array();galleryarray[0]="01.jpg";galleryarray[1]="02.jpg";galleryarray[2]="03.jpg";galleryarray[3]="04.jpg";galleryarray[4]="05.jpg";galleryarray[5]="06.jpg";galleryarray[6]="07.jpg";galleryarray[7]="08.jpg";galleryarray[8]="09.jpg";galleryarray[9]="10.jpg";galleryarray[10]="11.jpg";galleryarray[11]="12.jpg";


Ran on linux (PHP 5.3.8, Apache 2.2.21) it returns an incorrect order:

Code: [Select]

var galleryarray=new Array();galleryarray[0]="06.jpg";galleryarray[1]="01.jpg";galleryarray[2]="08.jpg";galleryarray[3]="10.jpg";galleryarray[4]="04.jpg";galleryarray[5]="11.jpg";galleryarray[6]="05.jpg";galleryarray[7]="03.jpg";galleryarray[8]="07.jpg";galleryarray[9]="09.jpg";galleryarray[10]="02.jpg";galleryarray[11]="12.jpg";


I need the script to run correctly on the linux server.
What could be the problem? What can i try?

Hello,
The following is my situation where I seem to get a 500 error code from the linux server:

i have an 'index' file like this:
Code: [Select]
<?php
require("includes/config.php");

$a = $_REQUEST['a'];

switch ($a)
{
   case "home":
      include("frontpage/main.php");
   case "user-process":
      include("user-process.php");
}
?>
config.php is something like this:
Code: [Select]
<?php

require(includes/classes/session.class.php);
require(includes/classes/user.class.php);
require(includes/classes/db.class.php);
...
?>
Now if we fall into the case "home" it works fine. Instead, if we fall into user-process it writes to the logs file Fatal Error: Class User does not exist bla bla bla. Why doesn't it exist ? every class is included in the config.php file then index.php includes first config.php ( which has all the classes) and then includes the requested page.

I also have a .htaccess file which is as follows:
Code: [Select]
RewriteEngine On
RewriteRule ^([^/\.]+)?/?([^/\.]+)?/?([^/\.]+)?/?([^/\.]+)?/?([^/\.]+)?/?([^/\.]+)?/?([^/\.]+)?$ index.php?a=$1&b=$2&c=$3&d=$4&e=$5&f=$6&g=$7 [NC,L]
which is used to access in a SEO friendly way the pages that users request.

Hi,
I am trying to use php to pass some commands to my linux box.From my webpage I am using the shell_exec function which is working OK but for some administrative tasks in linux I must have root access. As I am sending the commands from the webpage the apache user is used and so I am not allowed to do several tasks. I have also tried to use a bash script to pass the commands but with no result. Any ideas ?

Hi guys,

I'm trying to run a php script from command line in linux.  I installed xampp for linux a.k.a lampp so typing

php /path/to/file.php

Just brings up a message saying I need to install php.

Whats the correct way to do this?

This topic has been moved to Installation on Linux.

http://www.phpfreaks.com/forums/index.php?topic=321601.0

Hello,

Can I set the priority on my scripts relating to swap? Something like set_swap(10); would mean that it will be first to go into swap and set_swap(1) means it will go as a last resort and set_swap(5) being the default ?

Kind of like the proc_nice() but for memory ?

Thanks,

David

Hi,    Please I keep seeing this on my wordpress website Linux+cfcd208495d565ef66e7dff9f98764da+01+[[]].  I've tried to clear it out but to no avail. Does anyone has a solution? I will appreciate.   Thanks

Hello, I'm working with Zend Framework on Linux, and I'm trying to generate a CAPTCHA using Zend_Form_Element_Captcha. Whenever the CAPTCHA page loads I get this error:


[12-Jan-2011 18:14:54] PHP Warning:  imagepng() [<a href='function.imagepng'>function.imagepng</a>]: Unable to open '/var/www/square/application/../public/captcha/ebf44d292149b3ebda05571c54c463a8.png' for writing: Permission denied in /usr/local/zend/share/ZendFramework/library/Zend/Captcha/Image.php on line 563


Here's my code for generating the CAPTCHA:

    // create captcha

    $captcha = new Zend_Form_Element_Captcha('captcha', array(

      'captcha' => array(

        'captcha' => 'Image',

        'wordLen' => 6,

        'timeout' => 300,

        'width'   => 300,

        'height'  => 100,

        'imgUrl'  => '/captcha',

        'imgDir'  => APPLICATION_PATH . '/../public/captcha',

        'font'    => APPLICATION_PATH . '/../public/fonts/LiberationSansRegular.ttf',

        )

    ));


I've checked permissions, and all directories mentioned above are accessible to root. Has anyone had a similar problem or have an idea how I can fix this?

Kind Regards,
Mike

I am new to Php and the linux environment.  I have written a php program which sames a file to folder using xampp in Windows but I am having a problem with the pathway using my Ubuntu server and LAMP.  My code I used in Windows was:

$fileName = "guessbook.txt";
$file = fopen ($fileName, "ab");
if(!$file)
{
    echo "ERROR! did not create the file! Exiting.<br />;
    exit();
}

This file was saved correctly using xampp into the htdoc folder and worked fine when I called it in my browser.  I tried to substitute a Linux pathway ie: /var/www/assignment2/guessbook.txt, where guessbook is in the code but still nothing.  Can someone explain how to write the correct pathway to save this file?

Thank you

Paul

What are your feelings regarding Linux desktop distros, and their ability to break through to mainstream usage? I started using Ubuntu about 6 or 7 years ago, and have fooled around with some other distros, but at least for me Ubuntu always seemed the best. I've got my 65 year old mom using it, and my 11 year old son playing with Kubuntu (and learning python!). I don't really consider us normal though; normal being almost too dumb to do more than check email and get on the internet.   I've managed to fully switch over to Ubuntu on all of my computers, with the exception of running Windows in a VM for Photoshop and Illustrator. Since I don't use those programs every day, there are a lot of days where I don't see Windows. I never really had a problem with Windows, except for Windows 3.1 was kind of a drag. Getting on the internet on a 56K modem on Windows 95 wasn't any fun either, but that wasn't Windows' fault. I never had the crashes and bad experiences people like to claim makes Windows suck. My main reason for abandoning Windows is just to be more involved with Linux, and hopefully reach Linux guru status someday.   I really never liked Macs. I bought one 3 or 4 years ago, and it just felt like I was paying a lot of money for a glorified (and over-hyped) linux distro. I really never liked the feel of the Finder. At the time there was no awesome text editor, and I bought a couple just to test out what I could find. Unlike Windows and Linux, it seemed like nothing is free in the Mac world. I eventually gave the Mac away. We couldn't be friends.   I'd really like to see Linux become the dominant OS. It's exciting to see how far Ubuntu has come in the years that I've used it, and I evangelize for Linux/Ubuntu quite a bit. Even still, it can sometimes seem that I am a stranger in a strange world. Do you think we can count on Linux being a bigger part of mainstream computing? One of the problems I see is that there are so many distros that a person investigating Linux may be a little overwhelmed. What do you think is keeping the masses from using Linux desktops?

Sorry for posting this here, but for some reason the "create new topic" in linux subforum doesnt exist.


anyways i made a small php script that enables me to retrieve data between two dates. now am stuck on how i should copy it  or u0pload it into linux.

system tells me i need to upload to /usr/bin/libexec , i am there now but i dont have the slightest idea on how to do that.


help is much appreciated.

Thanks

Hi Guys

I am struggling with a shell_exec command in the long run, but I am trying to work down the root cause.

The error I am getting with shell_exec is a file not found error, so I thought I would start with getting to the right folder.

I have this

Code: [Select]
$sym_dir = "/root/";
$cwd = getcwd();
  echo getcwd()."\n";
  chdir ($sym_dir);
  echo getcwd()."\n";

Which in theory should 1st display '/var/www' as it does and then display the contents of root, at least that is my understanding!

However my return is this /var/www /var/www

Why cannot I move outside the web root?

Cheers
Dave

I am using shared hosting at HostGator. I am trying to execute flare (a command line actionscript decompiler) via PHP.

According to phpinfo() my System is Linux gator1854.hostgator.com 3.2.13 #4 SMP Thu Mar 29 19:22:42 CDT 2012 x86_64

In my public_html, I have a folder named "zachafer" and inside that folder, I have a folder named "flare".

Inside the flare folder, I have the flare command line version, named "flare" and a file named movie.swf.

The flare website says that I need to run "./flare somepath/somename.swf"
Here is my code:
<?PHP

error_reporting(-1);

$swf = 'movie';

chdir("/home/infamous/public_html/zachafer/flare");
$cmd = "./flare $swf.swf";
shell_exec($cmd);

echo "Cmd: $cmd\n";
echo "File: ".file_get_contents("$swf.flr");

?>

Thank you.

what im trying to do is take a youtube embed code find the URL code for that video and remove all other parts of the code keeping only the URL of the video
after i get the URL by it self then replace the http://www.youtube.com/ part of the URL with http://i2.ytimg.com/vi/

to do this i know that i need something like this to get the URL of the video
http://www.youtube.com/((?:v|cp)/[A-Za-z0-9\-_=]+)
but how to only return just the URL is something idk how to do

then use str_replace http://www.youtube.com/(?:v|cp)/" with  http://i2.ytimg.com/vi/

so in the end im asking if anyone know how to remove all other codes i dont want  and only keep the URL


this may have to be done using "regex" im not sure as i dont know to much about regex and what it can do but does sound like it would help lol