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PHP - Echo Download Link
Hi guys,
echo " Download <a href=".$file_path." download>Here</a>"; ?>
Didnt work, just took me to the path of the image. What i want is a link and when clicked the download window pops out.
Thanks Similar TutorialsCan php encrypt a link so that it's hidden or expires after a download or x number of days? An example of this use would be on music download sites. Hi, I have This Url After Click Link For Access and download file . Code: [Select] index.php?module=Files&action=show&id=default&download=yes&id=$_REQUEST[id] I set my mod_rewrite to : Code: [Select] RewriteRule ^files/(.*)/?$ index.php?module=Files&action=show&id=default&download=yes&id=$1in download page i have this for accept & download file : Code: [Select] if ($_REQUEST[download] == 'yes') { //check and create MYSQL Result echo " <meta http-equiv=\"refresh\" content=\"0; url=$cms[url]\">"; // $cms[url] = test.jpg } Now generate url (domain.com/files/test.jpg) but not refresh and not show file for download ( new Page)! what's problem ! thaks for any help I'm wanting to have users able to download a file, but I'm wanting it to be a file that only users who are logged in can download. Basically, I don't want a user to be able to enter the URL and download it while not being logged in. Does anyone know what I would use to do this? Thanks. Hi, Just looking how to create a link to download a file located on the server, it will be files like .doc etc. Cant seem to find anything on the net so i think i need php but may be html. Can anyone point me in the right direction? Thanks p.s. it will be used for more than one file so im looking for a small ish amount of code. Hi, I have one webhost (A) that supports no PHP and has unlimited bandwidth. I have a second webhost (B) that does support PHP, but has limited bandwidth. The website is on host A and contains a 5mb file that people can download and I'd like to count the downloads. But now I need to use host B to count the downloads. I'm using this small script on host B to count the downloads. <?php $hits=file("count.txt"); $hits[0]++;$fp=fopen("count.txt","w"); fputs($fp,$hits[0]); fclose($fp); header("Location: http://webhost-A.com/files/download.zip"); ?> The download link people see on my website is: http://webhost-B.com/download.php Generally this works fine, but I found out that people can still find the direct link with download managers and then put that direct link on their website, which prevents me from counting those downloads. A solution I found is to use ReadFile. But the problem is that when using ReadFile, host B first downloads the file from host A and then sends it to the user and that's exactly what I don't want. Is it possible to let people download the file directly from host A without showing the direct download link in any way and also count the downloads? So I am trying to download an image created with my php script. I use the following for the download: Code: [Select] <?php session_start(); $filename = $_SESSION['imgOut']; header('Content-type: application/octet-stream'); header('Content-Disposition: attachment; filename='.$filename ); ?> The file downloads however instead of downloading "example.jpg" from the /temp folder , it downloads "temp_example.jpg" which of course is an empty file. I am sure I am approaching this the wrong way, any suggestions? Hey guys, I'm going to start working on a simple php/mysql project, and wondering if you guys could point me in the right direction. Here is what I want to do: 1. User is presented with a simple form asking a series of questions (including email address) 2. Based on the answers, a specific download link is emailed to the user 3. store all inputted information in the database. I'm still not sure if I want the email process to be automated, or "held" until the information is reviewed, then download link sent. Does anyone know if a script already exist for this? I don't need to create user accounts, I just want to obtain user information every time they want to download something. Thanks for any help. How do I make this output a clickable link: <?php echo $_POST["website"]; ?><br /> I have created a database that echos out the result on a webpage, what i want to do is create one of the echo results into a link - the code is as follows: "Web Address: $web_address <br>" . Is there an easy way to make the result a link as the input will always be a web address? Thanks in advance! Hi all, I am having problems in forming this link: { echo "<a title='page $i' class='current' href='javascript:ajaxpage('view.php?catid=" . $catid ."&" ; if($subid > 0) { echo "subid="; echo $subid . "&"; } echo "p=$i', 'content';'>$i</a> "; } Which currently points to javascript:ajaxpage( and then ends! I have to put a link that can be clicked around the first name and last name variables in the echo statement below. I also need to add a variable from the Select query to the link such as: 'www.phpfreaks.com/admin/customers.php?page=1&cID="VARIABLE HERE" &action=edit' I've tried a bunch of things and none seem to work. while($row = mysql_fetch_array($result)){ echo '<tr><td>' . $row['customers_firstname'] . " " . $row['customers_lastname'] . '</td><td>' . date("M. d, Y", strtotime($row['date'])) . '</td><td>' . $row['plan_id'] . '</td></tr>'; David hello, im trying to add a hyperlink that launches in a new window to the following (in the last column) any ideas? Code: [Select] echo "<tr>"; echo "<td align='center'>" . $row["ID"] . "</td>"; echo "<td align='center'>" . $row["Name"] . "</td>"; echo "<td align='center'>" . $row["jobNO"] . "</td>"; echo "<td align='center'>" . $epn . "</td>"; echo "<td align='center'>" . $cname . "</td>"; echo "<td align='center'>" . $cadd . "</td>"; //want to add a hyperlink here echo "</tr>"; } echo "</table>"; } Trying to figure out how to make it so name is a link to the profile when its echo anyone know how to do this? im at a huge stand still Code: [Select] <?php $sql = "SELECT name FROM users WHERE DATE_SUB(NOW(),INTERVAL 5 MINUTE) <= lastactive ORDER BY id ASC"; $query = mysql_query($sql) or die(mysql_error()); $count = mysql_num_rows($query); $i = 1; while($row = mysql_fetch_object($query)) { $online_name = htmlspecialchars($row->name); echo '<a href="Inbox.php">"'[$goauld]'</a>"'; ?> <html> <?php include connect.inc; $id = $_GET['id']; mysql_query("UPDATE count SET clicks=clicks+1 WHERE id='$id'"); $sql = mysql_query("SELECT link FROM count WHERE id='$id'"); $fetch = mysql_fetch_row($sql); $result = mysql_query($sql); while($row = mysql_fetch_array($result)) { echo "Name :{$row['id']} <br>" . "Subject : {$row['link']} <br>" . "Message : {$row['count']} <br><br>"; } mysql_close(); ?> <a href='/index.php?id=1'>link1</a> <a href='/index.php?id=2'>link2</a> </html>
Basically I would like to place a link on my website and have the user download a file, but rather than just right clicking and choosing save target as, the link must be clicked, on the next page the file is fetched and then the client can download the file. How would I go about setting this up please? OK, have no idea what's going on... I've done this a million times... why wont this output!?? I must have a major brain meltdown and dont know it yet!!! Code: [Select] <?php // this echoes just fine: echo $_POST['testfield']; // but this wont echo: echo if (isset($_POST['testfield'])) { $_POST['testfield'] = $test; } echo $test; /// or even this DOESNT echo either!: $_POST['testfield'] = $test; echo $test; ?> I have made a Php program that downloads an Inno setup installation file for installing a program. However, if I for one or another reason want to make a new download of the same Inno setup installation file, the previous file will still be found in the Download folder. Each of the downloads get a number in parenthesis, setup(1), setup(2), setup(3) etc. However, I wondered if it is posible to erase the previous file in the same process as I download a new one, so that however many downloads I do, there will all the time only be one occurence of this file in the Download folder. The download code is as follows:
$exe = "Inno script/Test_setup.exe";
header("Content-Type: application/octet-stream");
header("Content-Disposition: attachment; filename=\"Test_setup.exe\"");
header("Content-Length: " . filesize($exe));
readfile($exe);
Thanks in advance. Sincerely
Hi All, I'm trying to echo the response from an SLA query, the query works and returns the data when I test it on an SQL application.. but when I run it on my webpage it won't echo the result. Please help? <?php $mysqli = mysqli_connect("removed", "removed", "removed", "removed"); $sql = "SELECT posts.message FROM posts INNER JOIN threads ON posts.pid=threads.firstpost WHERE threads.firstpost='1'"; $result = mysqli_query($mysqli, $sql); echo {$result['message']}; ?> I have a log system that allows 10 logs on each side(Left and right). I am trying to make it so that the left side has the 10 most recent logs, then the right as the next 10. Any ideas? So I need to echo a row from my database with php, but where i need to echo is already inside an echo. This is my part of my code: $con = mysql_connect("$host","$username","$password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("main", $con); $result = mysql_query("SELECT * FROM Vendor"); while($row = mysql_fetch_array($result)) { //I need to echo right here .................. but I get a blank page when I try this. Please Help. echo '<option value=$row['vendor_id']>'; echo $row['vendor_id']; echo '</option>'; } mysql_close($con); Result: A Blank page. Thanks in advance! |
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