PHP - $row['index Here'] Outputs Null
<?php include('header.php'); require('dbcon/dbcon.php'); // if fields in form are set and submitted, check if user exists and is logged in or not if ($_SERVER['REQUEST_METHOD'] == 'POST') { $username = $_POST['username']; $password = $_POST['password']; $user_query = $pdo->query("SELECT * FROM profiles001 WHERE username = '$username'"); $row = $user_query->fetchAll(PDO::FETCH_ASSOC); // if username and password match, init session and redirect to another page. if ($row == 1 && password_verify($password, $row['password'])) { $_SESSION['logged_in_user'] = $username; // set to IDnum later on... $_SESSION['username'] = $username; // check if the user is logged in // if so, redirect to main page for logged-in users. if (isset($_SESSION['logged_in_user'])) { $_SESSION['logged_in_user'] = TRUE; header('Location: main.php'); } else { // not logged in, keep on same page... session_destroy(); exit(); } } else if ($username != $row['username'] || $password != $row['password']) { echo var_dump($row); echo var_dump($row['password']); echo var_dump($row['username']); echo var_dump($row['email']); echo "Incorrect username or password."; } } ?> This code is responsible for authenticating the user upon logging in. I went ahead and updated the mysqli portion to PDO. As you can see I var_dump some variables near the end. Variable $row prints out as array(1) { [0]=> array(9) { ["username"]=> string(4) "test" ["password"]=> string(60) "$2y$10$uQEUsIwm0usWyZjWk/vo8e90e867oPLBu3ThKCk1aUseMcQuuHrVq" ["avatar"]=> string(15) "assets/soap.jpg" ["doc"]=> NULL ["las"]=> NULL ["email"]=> string(13) "test@test.org" ["c_status"]=> string(1) "0" ["account_age"]=> NULL ["bio"]=> string(4) "test" } }. The other three print out as NULL. What exactly is going on here? Similar TutorialsI am just trying to use Associate array in another php file through session.
file1.php <?php $age = array(); $_SESSION["age"] = array("Peter"=>"35", "Ben"=>"37", "Joe"=>"43"); foreach($_SESSION["age"] as $x => $x_value) { echo "Key=" . $x . ", Value=" . $x_value; echo "<br>\n"; } ?> OUTPUT: Key=Peter, Value=35 Key=Ben, Value=37 Key=Joe, Value=43 file2.php <?php session_start(); foreach( $_SESSION["age"] as $x => $x_value) { echo "Key=" . $x . ", Value=" . $x_value; echo "<br>\n"; } ?> OUTPUT: PHP Notice: Undefined index: age in session.php on line 3 PHP Warning: Invalid argument supplied for foreach() in session.php on line 3 Why am I getting this error? Above is just example I tried to demonstrate for asking question for other issue, unfortunately I got new error in this example. But actual issue was, I was trying to plot graph using library which requires only Associate array, where the data is formed in file1.php. But I get only last index value displayed in file2.php even in graph or in echo. I don't understand why other values are not displayed in file2.php Please point me what is going wrong, Thanks. I am trying to update the database with isset to set the value of the variable to either null or the value entered by the user. Currently, if no value has been entered null is being set as a string causing the date field to populate with zeros. How do I code it so that it populates or sets the value as null and not as string null?
Here's my code: (yes I know sql injections it's still in development )
<?php <?php $i = 2; $i = $i++; echo $i; ?>Output of above code is 2. <?php $i = 2; $p = $i++; echo $i; ?>Output of above code is 3. Why this difference? I mean how these codes are processed to give an output? Hi guys, I have a simple query he $sql="SELECT user_id FROM $tbl_name WHERE email='$loginuseremail' AND password='$loginpassword'"; $result=mysql_query($sql); $row = mysql_fetch_assoc($result); //START SESSION session_start(); $_SESSION['username']=$loginuseremail; $_SESSION['user_id']=$row; echo $_SESSION['user_id']; It should obviously output an ID number but instead I just get the word 'Array'. If I remove the mysql_fetch_assoc() I just get 'Resource ID #4'. Can anyone point me in the right direction? Thanks! Hey guys, I am having a bit of trouble, I am using the function time() to insert the time the form was submitted to the database. It inserts the data like this: 1301407145 I have a date column. I am then trying to echo the date the person submitted the form from the database using: <?php echo date('d-M-Y h:i A', $date); ?> the $date gets used with the mysql fetch array and for some reason it outputs it as: 01-Jan-1970 01:00 AM Can someone explain to me why? I am using this to insert into the db. $date = time(); and then the $date goes into the statement. mysql_query("INSERT INTO messages (reciever, sender, subject, message, date) VALUES ('$reciever', '$user', '$subject', '$message','$date')") or die (mysql_error()); Why isnt it working? I have a piece of code that outputs json as you can see from the example below it add \ / in front of urls & for ' it turns it into ' is there something i can do to correct this? Code: [Select] if (mysqli_num_rows($r) > 0) { // Available. while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) { $results[] = array( 'blog_id' => ($row['ID']), 'post_date' => ($row['pd']), 'post_title' => ($row['post_title']), 'article_img' => ('http://www.socialnewsoffice.com/uploads/'.$row['article_img']), 'post_content' => ($row['post_content']), 'tags' => ($row['tags']), 'views' => ($row['views']), 'categorie_id' => ($row['categorie_id']), 'post_url' => ($row['post_url'])); } echo $json = Pretty_JSON(json_encode($results)); it outputs Code: [Select] [{ "blog_id":"3", "post_date":"Thu, 1 March 2012", "post_title":"Facebook's New Fan Page Learn How To Use Features", "article_img":"http:\/\/www.socialnewsoffice.com\/uploads\/17963.jpg", "post_content":"<p>This week saw the release of Facebook's latest functionality changes (Timeline for Businesses) that will shape the future of how businesses will market their campaigns, through the social media giant Facebook. A number of marketers are wondering how they will incorporate the new features in an attempt to progress and move forward with their online social media presence.<\/p>\r\n<p>Taking all the key changes in to consideration we have managed to create a guide on how to smoothly move with the times and embrace the new Facebook layout.<\/p>\r\n<p>Please read on below for helpful tips and tricks on how to excel with 'Timeline for Brands'<\/p>\r\n<h2>New Features Announced at the Facebook Marketing Conference:<\/h2>\r\n<p><strong>View and Apps:<\/strong> What was once known as Application pages has changed to 'Tabs'. These can now have customizable images linked with them and the order of them can be changed too. Below you can see from the screenshot what a customized Facebook Timeline looks like.<\/p>\r\n<p><strong>Pinning Content:<\/strong> With this new feature you can 'pin' a post to the very top of your Facebook Timeline. This is Very effective when working on a new campaign and is a great way to entice increased traffic to your tab or application page.<\/p>\r\n<p><strong>Featured 'Starred' Content:<\/strong> This feature allows you to select key content or imagery and extend it so it fits across your entire page. Therefore giving you featured content on your Facebook Timeline and making it more visible.<\/p>\r\n<p><strong>Cover Photos:<\/strong> Cover Photos are another great new feature that allow you to announce your latest campaign, welcome your following community or just simply show visitors to your timeline what you can do. There are some slight flaws with this feature though and will be addressed below.<\/p>\r\n<p><strong>Page Dimensions:<\/strong> Dimensions of application pages has now changed with the release of Facebook Timeline. If you happen to be an SML user then you have all the tools necessary to update your page on your own. If your using Involvers App Suite then those applications will be updated soon.<\/p>\r\n<p><strong>Removal of Default Landing Pages:<\/strong> The commonly used Facebook landing pages have been removed and replaced with various options to allow brands to drive content to application pages. These options allow you to use your cover photo and pinned content to attract users to your personal application pages. Despite the changes it is however still possible to link directly to application pages from ads, posts and outside of Facebook.<\/p>\r\n<h2>Getting Started with Timeline For Brand:<\/h2>\r\n<p>Firstly when accessing and logging in to your New Facebook Brand Page, you will see this admin message displayed below:<\/p>\r\n<p>When will my Page change to the latest design?<\/p>\r\n<p>To see a preview of what your new pages will look like, simply click on the green button at the top of your current pages. A second option is to wait until March 30th 2012 when all pages will be upgraded automatically.<\/p>\r\n<p>Where can I visit to learn more about how to use the new Pages?<\/p>\r\n<p><strong>There are a number of places you can visit to learn all you need to know about Pages:<\/strong><\/p>\r\n<ul>\r\n<li>To find out more about new features, download the Pages Overview guide by clicking here.<\/li>\r\n<li>If your wondering how to get started with Pages then download Facebook's full Pages Product Guide by clicking here.<\/li> \r\n<li>The Pages Learning video allows you to walk through the key features with Facebook's product experts.<\/li> \r\n<li>If you need answers to specific questions, visit Facebook's Help Centre. <\/li>\r\n<\/ul>\r\n<h2>How should I choose a cover photo for my Page?<\/h2>\r\n<p>Firstly select a unique image that represents your page. Facebook itself recommends using a photo of a popular menu item, album artwork or an image of your product being used by someone. You need to experiment with a number of different images that your audience responds positively to. \r\nFew key elements of Cover Images:\r\n<\/p>\r\n<p><strong>Each Cover image must be at least 399 pixels wide and must not contain the following:<\/strong><\/p>\r\n<ul>\r\n<li>Prices \/ Purchase information and displaying offers such as \"60% off this month\" are not permitted. Also 'Download this from our website' is not allowed.<\/li> \r\n<li>No email addresses, web addresses and any other contact information.<\/li>\r\n<li>References to clicking on or the use of Facebook interface elements such as Like or Share or any other Facebook Features.<\/li>\r\n<li>\"Tell your friends\" or \"Get it now\" or any other calls to action are not allowed in the latest version of Facebook Timeline.<\/li>\r\n<\/ul>\r\n<p>All Timeline cover imagery is public and therefore means anyone visiting your Page will be able to see exactly which image you have chosen. The photos you display must not be deceptive, false or misleading any way that infringes on third party intellectual property. You must also not encourage of incentivize other fellow users, friends or business associates to display the same cover image as yours on personal Timelines.<\/p>\r\n<p>To sum up we are extremely excited about the latest Facebook feature release this week. They constantly deliver new services that are amazing and incredibly innovative to the market place.<\/p>\r\n<p>Here at Northplanet we are commited to provide you with the latest information on the hottest online topics around, to keep you ahead in the game. We would love to hear some feedback from you on the brand new Facebook 'Timeline for Brands' release and invite you to visit our very own <a href=\"https:\/\/www.facebook.com\/northplanet\">Northplanet Facebook Timline page by clicking here.<\/a><\/p>", "tags":"facebook, new fan page", "views":"253", "categorie_id":"2", "post_url":"facebooks-new-fan-page-learn-how-to-use-features" } Sorry if this is a silly question lol. I want to know if there is an online tool I can use to check and see what PHP code will ouput server side. For example: <?php $tomorrow = mktime(0, 0, 0, date("m") , date("d")+1, date("Y")); ?> Hi, I've inherited a website with a problem! Basically the site runs pommo mailing list, which has worked fine for years. Recently though the website domain name changed. Since then - or at least at a similar time - pommo has just stopped working completely. It does nothing but outputs blank pages. I've never done any php development so I've no idea where to start in terms of debugging this. I've checked that the files etc all exist on the server: they do. I've uploaded a test html page which works. I've uploaded a test php page containing: <?php phpinfo( ); ?> and it works. But when I visit any page in the pommo application, the browser just renders a totally empty white page - no source HTML at all, just nothing! Can anyone suggest how to debug this? Even an error message would be somewhere to start. Thanks all! I really dont no what the problem is and im new here so i dont no if this is the right place to put this but im trying to make a registration page for my server and when i bring it up it says Undefined index: action in C:\xampp\htdocs\index.php on line 56 and idk what to do >.< this is the line that has the problem if($_POST['action']!="signup") so hopefully u guys could help me :/ Im using xampp btw Hi there, I was wondering if there is a way to display content on only my index.php page? I believe there is a way and I have done it before, but some of my pages use index.php?category etc. Is there a way to show content just on index.php and not on any dynamic pages? Thanks Hello All, I tried searching here and google, but couldn't figure it out on my own... still Bellow is my code, I need some help figuring out how to tell PHP that "If picture is NULL, don't try to display it." Basically I have a dynamic news system set up. Some stories have pictures, some do not. I need PHP to not display the code for showing the picture if the picture value = NULL. Any help would be appreciated! <?php include ("../../includes/connections/newsconnection.php"); $id=$_GET['id']; //declare the SQL statement that will query the database $query = " SELECT * FROM news WHERE id='$id' "; //execute the SQL query and return records $result = mssql_query($query); //display the results //id, school, date, link, title, story, picture while($row = mssql_fetch_array($result)) { echo "<span class='bodyb'>"; echo $row["title"]; echo "</span>"; echo "<br /><i>"; echo date('l, F j, Y', strtotime($row['date'])); echo "</i>"; echo "<br /><br />"; //heres where I need to stop if picture is null echo "<img src='../../images/news/"; echo $row["picture"]; echo "' align='left' class='imgspacer-left'>"; echo fixQuotes($row["story"]); } //close the connection mssql_close($dbhandle); ?> I'm trying to display the null values only, where am I going wrong?
SELECT IFNULL(trans, 0) AS 'Transactions', customer.cID AS 'Customer ID', customer.surname AS 'Surname' FROM customer LEFT JOIN account ON (account.cID = customer.cID) WHERE IFNULL(trans, 0); I have a for loop that I am looping through. When I use var_dump() I get 10 results (which is what I should be getting). However, when I loop through it using a for() loop I am getting an extra 11th value that is blank. What would be causing this? My code is below: Code: [Select] $legacy = new Legacy(); // Loop through each film in the shopping cart for ($i = 0; $i < $myShoppingCartInfo['row_count']; $i++) { // Determine if the film is of a legacy series if ($legacy->isLegacyCheckout($myShoppingCartInfo['data']['PRODUCTSKUID'][$i])) { // Declare array to hold all legacy film entity_id values $legacyEntityIds = array(); $legacyEntityIds = $legacy->getLegacyEntityIds($myShoppingCartInfo['data']['PRODUCTSKUID'][$i]); var_dump($legacyEntityIds); // Loop through all legacy video entity_id's for ($i = 0; $i < $legacyEntityIds['data']['ENTITY_ID']; $i++) { // Grant streaming access to each entity id echo $legacyEntityIds['data']['ENTITY_ID'][$i] . '<br />'; // Insert the product into the order items table /*$query = "INSERT INTO tblOrderItems (OrderItemID, ProductSKUID, RentalDate, OrderID) VALUES (##newID##, '".$myShoppingCartInfo['data']['PRODUCTSKUID'][$i]."', ".($myShoppingCartInfo['data']['RENTALDATE'][$i] === NULL ? 'NULL' : "'".$myShoppingCartInfo['data']['RENTALDATE'][$i]."'").", ".$newOrderID.")"; $cartItemInserted = counter_id_insert($query,'OrderItemID'); $curr_user->addNewEntityLicense($legacyEntityIds['data']['ENTITY_ID'][$i]);*/ } } When I view the source code of the output page in a browser, this is what I see: array(5) { ["row_count"]=> int(10) ["col_count"]=> int(1) ["col_names"]=> array(1) { => string(9) "entity_id" } ["col_types"]=> array(1) { => string(3) "int" } ["data"]=> array(1) { ["ENTITY_ID"]=> array(10) { => string(7) "1681799" [1]=> string(7) "1681872" [2]=> string(7) "1681871" [3]=> string(7) "1681870" [4]=> string(7) "1681869" [5]=> string(7) "1681868" [6]=> string(7) "1681867" [7]=> string(7) "1681866" [8]=> string(7) "1681865" [9]=> string(7) "1681864" } } } 1681799<br />1681872<br />1681871<br />1681870<br />1681869<br />1681868<br />1681867<br />1681866<br />1681865<br />1681864<br /><br /> How can I change Yes to No for the NULL field in the mysql db structure. E.g. (Table name: address and Column name : state) <?php $link = mysql_connect("localhost","db","pw"); mysql_select_db("db"); mysql_query("alter table address modify state null NO); $result = mysql_query($query); $sent = "Edit Successful."; echo ($sent); ?> I have an array which can be empty; in this case, I get error. I want to skip when the array is empty. When calling the array from file, I use the following code if (file_exists($array_file)) { "the doing code" } else { echo "File does not exist"; } How I should use this If Else condition when array comes from a string like $test_array = explode(', ', $examplestring, -1); 2 PART QUESTION (so I don't have to ask two questions 😀 )
1.)
2.) On my particular coding, I can use either the NULL/isset style, or, the ""/== style, with no errors or ill effects.... but something tells me the expert PHP coders prefer one over the other... Thank you!! Edited July 10 by ChenXiuHi... i have table EMP_NO LOGIN - DATETIME, NULL LOGOUT - DATETIME, NULL I have this query: Code: [Select] <?php include 'config.php'; $currentEmpID = $_SESSION['empID']; if(!isset($_POST['submit_'])){ $DATE1 = $_POST['firstinput']; $DATE2 = $_POST['secondinput']; $sql = "SELECT EMP_NO, LOGIN, LOGOUT FROM employee_attendance WHERE DATE(LOGIN) BETWEEN '$DATE1' AND '$DATE2'"; $attendance = $conn3->GetAll($sql); $smarty->assign('attendance', $attendance); } $smarty->display('header_att.tpl'); $smarty->display('empAttendance.tpl'); $smarty->display('footer.tpl'); ?> My problem is I have data EMP_NO 00000223 LOGIN NULL LGOUT NULL this data was not displayed because it has a null value.. i want it to displayed also and highlight it because it has a value null.. Thank you My code; $sql = "SELECT SUM(IF(`submitdate` IS NULL , 1 , 0 )) as 'Survey Started But Not Completed' FROM `survey_$surveyid`"; $statement = $dbh->prepare($sql); $statement->execute(); $result = $statement->fetch(PDO::FETCH_OBJ); //pass that data to an objectIs returning; stdClass Object ( [Survey Started But Not Completed] => ) I need to set this to a vaule that I can actually print out on the screen... Like a "0" for example. At the moment it is just a NULL. How do I do this?? These don't work; $result = 0; $result = array(['Survey Started But Not Completed'] => "0"); Can someone help me to get this code working... Code: [Select] public function getBowlContents(){ if is_null($this->contents) { return "The bowl is empty!"; } else { return "The bowl contains " . $this->contents . " soup!"; } TomTees hi all, i have a script in where the user enters there post code and it will provide a price for delivery, how would i echo "please contact us for price" if the db record for the price is (null) or empty?? <?php mysql_connect ("localhost", "root","password") or die (mysql_error()); mysql_select_db ("postcode"); $term = $_POST['term']; $sql = mysql_query("SELECT * FROM uk_postcodes, zones WHERE postcode LIKE '%$term%' AND zone_id = zone_large "); while ($row = mysql_fetch_array($sql)){ echo '<br/> Postcode: '.$row['postcode']; echo '<br/> Town: '.$row['town']; echo '<br/> County: '.$row['county']; echo '<br/> Small: £'.$row['price_s']; echo '<br/> Medium: £'.$row['price_m']; echo '<br/> Large: £'.$row['price_l']; echo '<br/><br/>'; } ?> |