PHP - Running Script On Query With Conditional Update/insert Loop
I have a php script that I've been running that seems to have been working but now I'm wondering if some of my logic is potentially off. I select records from a db table within a date range which I put into an array called ```$validCount``` If that array is not empty, that means I have valid records to update with my values, and if it's empty I just insert. The trick with the insert is that if the ```STORES``` is less than the ```Quantity``` then it only inserts as many as the ```STORES``` otherwise it inserts as many as ```Quantity```. So if a record being inserted with had Stores: 14 Quantity:12
Then it would only insert 12 records but if it had It would only insert 1 record. In short, for each customer I should only ever have as many valid records (within a valid date range) as they have stores. If they have 20 stores, I can have 1 or 2 records but should never have 30. It seems like updating works fine but I'm not sure if it's updating the proper records, though it seems like in some instances it's just inserting too many and not accounting for past updated records. This is the logic I have been working with:
if(!empty($validCount)){ for($i=0; $i<$row2['QUANTITY']; $i++){ try{ $updateRslt = $update->execute($updateParams); }catch(PDOException $ex){ $out[] = $failedUpdate; } } }else{ if($row2["QUANTITY"] >= $row2["STORES"]){ for($i=0; $i<$row2["STORES"]; $i++){ try{ $insertRslt = $insert->execute($insertParams); }catch(PDOException $ex){ $out[] = $failedInsertStore; } } }elseif($row2["QUANTITY"] < $row2["STORES"]){ for($i=0; $i<$row2["QUANTITY"]; $i++){ try{ $insertRslt = $insert->execute($insertParams); }catch(PDOException $ex){ $out[] = $failedInsertQuantity; } } } }
Let's say customer 123 bought 4 of product A and they have 10 locations
customerNumber | product | category | startDate | expireDate | stores Because they purchased less than their store count, I insert 4 records. Now if my ```$validCheck``` query selects all 4 of those records (since they fall in a valid date range) and my loop sees that the array isn't empty, it knows it needs to update those or insert. Let's say they bought 15 this time. Then I would need to insert 6 records, and then update the expiration date of the other 9 records.
customerNumber | product | category | startDate | expireDate | stores There can only ever be a maximum of 10 (store count) records for that customer and product within the valid date range. As soon as the row count for that customer/product reaches the equivalent of stores, it needs to now go through and update equal to the quantity so now I'm running this but it's not running and no errors, but it just returns back to the command line $total = $row2['QUANTITY'] + $validCheck; if ($total < $row2['STORES']) { $insert_count = $row2['QUANTITY']; $update_count = 0; } else { $insert_count = $row2['STORES'] - $validCheck; // insert enough to fill all stores $update_count = ($total - $insert_count); // update remainder } for($i=0; $i<$row2['QUANTITY']; $i++){ try{ $updateRslt = $update->execute($updateParams); }catch(PDOException $ex){ $failedUpdate = "UPDATE_FAILED"; print_r($failedUpdate); $out[] = $failedUpdate; } } for($i=0; $i<$insert_count; $i++){ try{ $insertRslt = $insert->execute($insertParams); }catch(PDOException $ex){ $failedInsertStore = "INSERT_STORE_FAILED!!!: " . $ex->getMessage(); print_r($failedInsertStore); $out[] = $failedInsertStore; } }```
Similar TutorialsHi i have this upload script which works fine it uploads image to a specified folder and sends the the details to the database. but now i am trying to instead make a modify script which is Update set so i tried to change insert to update but didnt work can someone help me out please this my insert image script which works fine but want to change to modify instead Code: [Select] <?php mysql_connect("localhost", "root", "") or die(mysql_error()) ; mysql_select_db("upload") or die(mysql_error()) ; // my file the name of the input area on the form type is the extension of the file //echo $_FILES["myfile"]["type"]; //myfile is the name of the input area on the form $name = $_FILES["image"] ["name"]; // name of the file $type = $_FILES["image"]["type"]; //type of the file $size = $_FILES["image"]["size"]; //the size of the file $temp = $_FILES["image"]["tmp_name"];//temporary file location when click upload it temporary stores on the computer and gives it a temporary name $error =array(); // this an empty array where you can then call on all of the error messages $allowed_exts = array('jpg', 'jpeg', 'png', 'gif'); // array with the following extension name values $image_type = array('image/jpg', 'image/jpeg', 'image/png', 'image/gif'); // array with the following image type values $location = 'images/'; //location of the file or directory where the file will be stored $appendic_name = "news".$name;//this append the word [news] before the name so the image would be news[nameofimage].gif // substr counts the number of carachters and then you the specify how how many you letters you want to cut off from the beginning of the word example drivers.jpg it would cut off dri, and would display vers.jpg //echo $extension = substr($name, 3); //using both substr and strpos, strpos it will delete anything before the dot in this case it finds the dot on the $name file deletes and + 1 says read after the last letter you delete because you want to display the letters after the dot. if remove the +1 it will display .gif which what we want is just gif $extension = strtolower(substr($name, strpos ($name, '.') +1));//strlower turn the extension non capital in case extension is capital example JPG will strtolower will make jpg // another way of doing is with explode // $image_ext strtolower(end(explode('.',$name))); will explode from where you want in this case from the dot adn end will display from the end after the explode $myfile = $_POST["myfile"]; if (isset($image)) // if you choose a file name do the if bellow { // if extension is not equal to any of the variables in the array $allowed_exts error appears if(in_array($extension, $allowed_exts) === false ) { $error[] = 'Extension not allowed! gif, jpg, jpeg, png only<br />'; // if no errror read next if line } // if file type is not equal to any of the variables in array $image_type error appears if(in_array($type, $image_type) === false) { $error[] = 'Type of file not allowed! only images allowed<br />'; } // if file bigger than the number bellow error message if($size > 2097152) { $error[] = 'File size must be under 2MB!'; } // check if folder exist in the server if(!file_exists ($location)) { $error[] = 'No directory ' . $location. ' on the server Please create a folder ' .$location; } } // if no error found do the move upload function if (empty($error)){ if (move_uploaded_file($temp, $location .$appendic_name)) { // insert data into database first are the field name teh values are the variables you want to insert into those fields appendic is the new name of the image mysql_query("INSERT INTO image (myfile ,image) VALUES ('$myfile', '$appendic_name')") ; exit(); } } else { foreach ($error as $error) { echo $error; } } //echo $type; ?> Hi, Here is an extract of my while loop while ($personquery = mysql_fetch_array($personfetch, MYSQL_ASSOC)) { echo "$personfetch[first_name]"; } This will list each person now I want to do an INSERT to the database on every single member that is being listed I can only get it to INSERT for the one. Thanks I am really just a beginner in PHP but I've got a task to create a simple hotel booking system by using PHP and MySQL. It works in several steps, described in separate .php files. All of them seem to work fine, except the last one. In this last file I want to add all the data into a MySQL database table. I would like to do this by creating a record for each date, a guest is spending in a hotel (so that when booking, another loop checks whether the room is not occupied yet for that date). I decided to use a for-loop for that, but it doesn't seem to be working (the records just don't get inserted into the table). I checked all the variables by echo-ing them and they are all right. I also tried the query without the loop and it works as well. So I guess there is some other problem. This particular .php file looks as follow: <?php session_start(); include('db_config.php'); $name=($_POST['name']); $telephone=addslashes($_POST['telephone']); $email=addslashes($_POST['email']); $code=md5($email.time()); $checkout_date=$_SESSION['checkout']; $checkin_unix=$_SESSION['checkin_unix']; $checkout_unix=$_SESSION['checkout_unix']; $roomtype=$_SESSION['roomtype']; $checkin_date=$_SESSION['checkin']; for ($stay_date=$checkin_unix; ; $stay_date=$stay_date+24*60*60) { if ($stay_date=$checkout_unix){ break; } mysql_query("INSERT INTO reservations VALUES( '', '$roomtype', 'pending', 'date ('d/m/Y', $stay_date)', '$stay_date', '$checkout_date', '$name', '$telephone', '$email', '$code' )"); } ?> I would appreciate any kind of help, any idea. Hello, I am trying to pick up php again and just exercising my skills. So I have it so that it fills my form with the values of what I want to edit, and when I click the edit button, it doesn't edit any of the information. When I echo out $result, I get a MYSQL query string that has the same values as the table, so its not getting the new values that are edited. <?php @mysql_connect('localhost', 'root', '') or die("Could not connect to Mysql Server. " . mysql_error()); @mysql_select_db('tutorials') or die("Could not connect to Database. " . mysql_error()); if(isset($_GET['edit'])) { $id = $_GET['edit']; $query = "SELECT `username`, `password` FROM `users` WHERE `id` = '$id'"; $result = mysql_query($query); $row = mysql_fetch_array($result); $name = $row['username']; $password = $row['password']; } if(isset($_POST['edit'])) { $id = $_GET['edit']; $query = "UPDATE `users` SET `username` = '$name', `password` = '$password' WHERE `id` = '$id'"; $result = mysql_query($query); echo $query; if(!$result) { echo mysql_error(); }else{ echo 'updated post'; } } ?> <form method="POST" action="" > <input type="text" name="name" value="<?php echo $name; ?>" /> First name <br /> <input type="text" name="password" value="<?php echo $password; ?>" /> Last name <br /> <input type="submit" name="edit" value="edit" /> </form> I believe it has something to do with the values of $name and $password in the form conflicting with the first if isset and the second if isset. Thanks for any help possible Hi, I've been playing around with inserting the name of a file ($additional_upload_nameX) into the database only if it has been uploaded (it's not mandatory). When I submit the form, I'm told I have a problem with my WHERE clause. Any idea what I'm doing wrong here? Code: [Select] $query2 = "INSERT INTO uploads (date, upload_name, topic, year, status, keywords, description )" . "VALUES (NOW(), '$additional_upload_nameX', '$topic', '$year', '$status', '$keywords' , '$description') WHERE $additional_upload_nameX != ''"; //if($query){echo 'data has been placed'} mysql_query($query2) or die(mysql_error()); i have:
if( $stmt = $db_connect->prepare('UPDATE '.C_T_DRAGONS.' AS d, '.C_T_USERS.' AS u SET d.'.$prop.' = d.'.$prop.'+'.$val.', u.ap=u.ap-1 WHERE d.id = ? AND (SELECT u2.ap FROM '.C_T_USERS.' as u2 WHERE u2.id = ?) > 100') )which echoes out as: UPDATE dragons AS d, users AS u SET d.claws_dam = d.claws_dam+1, u.ap=u.ap-1 WHERE d.id = ? AND (SELECT u2.ap FROM users as u2 WHERE u2.id = ?) > 100and am getting the following response: Error : (1093) Table 'd' is specified twice, both as a target for 'UPDATE' and as a separate source for datawill this have to be done in 2 queries? did a little searching and im thinking maybe the subquery is being refused? Edited by BuildMyWeb, 04 December 2014 - 04:35 PM. So I've coded this to run the while loop once for every server within the the table, there is currently two rows within the table and the while loop wont stop running it just keeps on running until I restart Apache, its producing the same effect as what "while(1)" would do, could anybody tell me what the problem could be?, thanks for your time in advance. class bot_restart { function __construct( ) { while($CurrentServers = mysql_fetch_array(mysql_query("SELECT * FROM xhost_boxs"))) { echo $CurrentServers['box_id']; } } } Hi, I need to run a database insert when somebody clicks on an image. Should I use a php function ? or javascript ? or something else ? Many thanks in advance, Scott. Hey Guys, I have a DB with two tables, one is field names, the other is the data. So for example, I log in and I am user ID 1..... I need to query the DB to show all fields where user_id = 1 Field1 - Data1 Field2 - Data2 etc etc... This is what I have so far, but I dont get any output... $sql = "SELECT * FROM ".WPSC_TABLE_DATA." WHERE `user_id` == .$cu. ORDER BY id DESC"; $user= $wpdb->get_row($sql); while($user) { echo $user->name .' : '. $user->value .'<br />'; } Can you help please? Hi
I am having problems running a while loop twice. The first loop runs fine but the 2nd one does not run. Can anyone please advise why this is? My code is below
Thanks in advance.
Jonathan
$sql = "SELECT id, url, time FROM fyi_links"; $res = odbc_exec($con, $sql); while ($row = odbc_fetch_array($res)) { print($row['id'].",".$row['url'].",".$row['time']."\n"); } //Run loop again after some other code while ($row = odbc_fetch_array($res)) { print($row['id'].",".$row['url'].",".$row['time']."\n"); } Hello all,
Based on the suggestion of you wonderful folks here, I went away for a few days (to learn about PDO and Prepared Statements) in order to replace the MySQLi commands in my code. That's gone pretty well thus far...with me having learnt and successfully replaced most of my "bad" code with elegant, SQL-Injection-proof code (or so I hope).
The one-and-only problem I'm having (for now at least) is that I'm having trouble understanding how to execute an UPDATE query within the resultset of a SELECT query (using PDO and prepared statements, of course).
Let me explain (my scenario), and since a picture speaks a thousand words I've also inlcuded a screenshot to show you guys my setup:
In my table I have two columns (which are essentially flags i.e. Y/N), one for "items alreay purchased" and the other for "items to be purchased later". The first flag, if/when set ON (Y) will highlight row(s) in red...and the second flag will highlight row(s) in blue (when set ON).
I initially had four buttons, two each for setting the flags/columns to "Y", and another two to reverse the columns/flags to "N". That was when I had my delete functionality as a separate operation on a separate tab/list item, and that was fine.
Now that I've realized I can include both operations (update and delete) on just the one tab, I've also figured it would be better to pare down those four buttons (into just two), and set them up as a toggle feature i.e. if the value is currently "Y" then the button will set it to "N", and vice versa.
So, looking at my attached picture, if a person selects (using the checkboxes) the first four rows and clicks the first button (labeled "Toggle selected items as Purchased/Not Purchased") then the following must happen:
1. The purchased_flag for rows # 2 and 4 must be switched OFF (set to N)...so they will no longer be highlighted in red.
2. The purchased_flag for row # 3 must be switched ON (set to Y)...so that row will now be highlighted in red.
3. Nothing must be done to rows # 1 and 5 since: a) row 5 was not selected/checked to begin with, and b) row # 1 has its purchase_later_flag set ON (to Y), so it must be skipped over.
Looking at my code below, I'm guessing (and here's where I need the help) that there's something wrong in the code within the section that says "/*** loop through the results/collection of checked items ***/". I've probably made it more complex than it should be, and that's due to the fact that I have no idea what I'm doing (or rather, how I should be doing it), and this has driven me insane for the last 2 days...which prompted me to "throw in the towel" and seek the help of you very helpful and intellegent folks. BTW, I am a newbie at this, so if I could be provided the exact code, that would be most wonderful, and much highly appreciated.
Thanks to you folks, I'm feeling real good (with a great sense of achievement) after having come here and got the great advice to learn PDO and prepared statements.
Just this one nasty little hurdle is stopping me from getting to "end-of-job" on my very first WebApp. BTW, sorry about the long post...this is the best/only way I could clearly explaing my situation.
Cheers guys!
case "update-delete": if(isset($_POST['highlight-purchased'])) { // ****** Setup customized query to obtain only items that are checked ****** $sql = "SELECT * FROM shoplist WHERE"; for($i=0; $i < count($_POST['checkboxes']); $i++) { $sql=$sql . " idnumber=" . $_POST['checkboxes'][$i] . " or"; } $sql= rtrim($sql, "or"); $statement = $conn->prepare($sql); $statement->execute(); // *** fetch results for all checked items (1st query) *** // $result = $statement->fetchAll(); $statement->closeCursor(); // Setup query that will change the purchased flag to "N", if it's currently set to "Y" $sqlSetToN = "UPDATE shoplist SET purchased = 'N' WHERE purchased = 'Y'"; // Setup query that will change the purchased flag to "Y", if it's currently set to "N", "", or NULL $sqlSetToY = "UPDATE shoplist SET purchased = 'Y' WHERE purchased = 'N' OR purchased = '' OR purchased IS NULL"; $statementSetToN = $conn->prepare($sqlSetToN); $statementSetToY = $conn->prepare($sqlSetToY); /*** loop through the results/collection of checked items ***/ foreach($result as $row) { if ($row["purchased"] != "Y") { // *** fetch one row at a time pertaining to the 2nd query *** // $resultSetToY = $statementSetToY->fetch(); foreach($resultSetToY as $row) { $statementSetToY->execute(); } } else { // *** fetch one row at a time pertaining to the 2nd query *** // $resultSetToN = $statementSetToN->fetch(); foreach($resultSetToN as $row) { $statementSetToN->execute(); } } } break; }CRUD Queston.png 20.68KB 0 downloads Hi, I have written some code however when I echo the query it runs it twice... Quote SELECT `description`, `fulldescription` FROM `productdbase` WHERE `keywords` LIKE '%table%'something found.SELECT `description`, `fulldescription` FROM `productdbase` WHERE `keywords` LIKE '%table%'something found. I only have the query once in my code. Any suggesions? Code: [Select] <?php if (isset($_POST['keywords'])){ $keywords = mysql_real_escape_string (htmlentities(trim($_POST['keywords']))); } $errors = array(); if (empty($keywords)) { $errors[] = 'Please enter a search term'; } else if (strlen($keywords)<3) { $errors[] = 'Your search must be three or more characters'; } else if (search_results($keywords) === false) { $errors[] = 'Your search for '.$keywords.' returned no results'; } if (empty($errors)) { search_results ($keywords); } else{ foreach($errors as $error) { echo $error, '</br>'; } } ?> <?php function search_results ($keywords) { $returned_results = array(); $where = ""; $keywords = preg_split('/[\s]+/', $keywords); $total_keywords = count($keywords); foreach($keywords as $key=>$keyword) { $where .= "`keywords` LIKE '%$keyword%'"; if ($key != ($total_keywords - 1)) { $where .= " AND "; } } $query_string = "SELECT `description`, `fulldescription` FROM `productdbase` WHERE $where"; echo $query_string; $query = mysql_query($query_string); if ($results_num === 0) { return false; }else{ echo 'something found.'; } } ?> Its the Code: [Select] $query = "INSERT INTO hitlist hit_id = ($addIDs_str), player_id = '$playerID'"; Thats the issue, my codes below i cannot figure out how to insert the results, any help would be appreciated Thanks Code: [Select] if (isset($_POST["submit"]) && $_POST["submit"] == "Recall Selected Informants") { //Force POST values to be INTs $addIDs_ary = array_map('intval', $_POST['chkInv']); //Remove any 'false' value $addIDs_ary = array_filter($addIDs_ary); //Check that there was at least one valid value if(count($addIDs_ary)) { //Create comma separated string of the IDs $addIDs_str = implode(',', $addIDs_ary); //Create and run one query to perform all the adds (of the user) $query = "INSERT INTO hitlist hit_id = ($addIDs_str), player_id = '$playerID'"; $sql = "UPDATE players SET Informants = Informants - 1 WHERE id = '$playerID'"; mysql_query($sql) or die(mysql_error()); if(mysql_query($query)) { $selectedCount = count($addIDs_ary); $adddCount = mysql_affected_rows(); echo "{$adddCount} of {$selectedCount} Investigated player(s) were successfully Removed."; if($adddCount != $selectedCount) { echo " You do not have rights to the others."; } }else{ echo "There was a problem running the query.<br>" . mysql_error(); } }else{ echo "Invalid ID data passed."; } } Hi i was wondering what im doing wrong, im trying to insert a query for submit button, it works if i run it straight in mysql, but not working when linked through php. Im just doing it for testing purpose right now only, so when i see that it works i will use another query. here it is Code: [Select] <?php include('config.php'); if($_SESSION['username']){ if(isset($_POST['ASubmit'])){ $query3=("update country set Status='test1' where Uname='Mclovin'");} echo '<td><form name="test" method="post" form id="form1"><label for="test">Status</label> <select name="Status"> <option value="">-----</option> <option value="In process" '.(($row['Status']=='In process')?'selected="selected"':'').'>In process</option> <option value="Approved" '.(($row['Status']=='Approved')?'selected="selected"':'').'>Approved</option> <option value="Denied" '.(($row['Status']=='Denied')?'selected="selected"':'').'>Denied</option> </select><input name="ASubmit" type="submit" value="Update">'; echo $row{'Status'}.'</td></form>'; } ?> If you also have any feedback on my code, please do tell me. I wish to improve my coding base. Basically when you fill out the register form, it will check for data, then execute the insert query. But for some reason, the query will NOT insert into the database. In the following code below, I left out the field ID. Doesn't work with it anyways, and I'm not sure it makes a difference. Code: Code: [Select] mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); Full code: Code: [Select] <?php include_once("includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title><? $title; ?></title> <meta http-equiv="Content-Language" content="English" /> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <link rel="stylesheet" type="text/css" href="style.css" media="screen" /> </head> <body> <div id="wrap"> <div id="header"> <h1><? $title; ?></h1> <h2><? $description; ?></h2> </div> <? include_once("includes/navigation.php"); ?> <div id="content"> <div id="right"> <h2>Create</h2> <div id="artlicles"> <?php if(!$_SESSION['user']) { $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $name = mysql_real_escape_string($_POST['name']); $server_type = mysql_real_escape_string($_POST['type']); $description = mysql_real_escape_string($_POST['description']); if(!$username || !$password || !$server_type || !$description || !$name) { echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings!<br/>All forms are required to be filled out.<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>"; echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'> <option value='Any'>Any</option> <option value='PvP'>PvP</option> <option value='Creative'>Creative</option> <option value='Survival'>Survival</option> <option value='Roleplay'>RolePlay</option> </select></td></tr> <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40' name='description'></textarea></td></tr>"; echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>"; } elseif(strlen($password) < 8) { echo "Password needs to be higher than 8 characters!"; } elseif(strlen($username) > 13) { echo "Username can't be greater than 13 characters!"; } else { $check1 = mysql_query("SELECT username,name FROM servers WHERE username = '$username' OR name = '$name' LIMIT 1"); if(mysql_num_rows($check1) < 0) { echo "Sorry, there is already an account with this username and/or server name!"; } else { $ip = $_SERVER['REMOTE_ADDR']; mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); echo "Server has been succesfully created!"; } } } else { echo "You are currently logged in!"; } ?> </div> </div> <div style="clear: both;"> </div> </div> <div id="footer"> <a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop </div> </div> </body> </html> I created this code to upload a member's main picture on his member page on website. I'll only include the query part of the code since that's what is relevant to my problem. The idea is basically to upload a new picture onto the database if no picture already exists for that member and display the picture on the page. If a picture already exists, then the script replaces the old picture with the new one upon upload. But for whatever reason I don't understand, when I try to replace the old pic, it gets inserted in a new row on the database instead of replacing the old row, and the new pic gets displayed on the web page alongside the old. Code: [Select] $query = "SELECT username FROM images WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'"; $result = @mysql_query($query); $num = @mysql_num_rows($result); if ($num> 0) { //Update the image $update = mysql_query("UPDATE images SET image = '" . $image['name'] . "' WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'"); $_SESSION['error'] = "File updated successfully."; //really should be session success message. header("Location: member.php"); exit; } else { // NOTE: This is where a lot of people make mistakes. // We are *not* putting the image into the database; we are putting a reference to the file's location on the server $sql = "insert into images (member_id, image_cartegory, image_date, image) values ('{$_SESSION['id']}', 'main', NOW(), '" . $image['name'] . "')"; $result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error()); $_SESSION['error'] = "File uploaded succussfully."; //really should be session success message. header("Location: member.php"); } So can anyone tell me what the problem is? Could the fact that my insert script actually uploads the image onto a folder on my server and only stores the path name in the database have anything to contribute to the mixup? Appreciate your responses in advance. Hi, I have a PHP script which I want to run from a different IP on my server. Example of what I want to do: My main ip: 4.5.6.7 Have several IP's on server. I want my PHP script (running from CLI) to use cURL with another IP, ay 4.5.6.9 Is this possible to do? Help would be greatly appreciated! Hi All, I have a form that enables the user to know events that occur in a specific city. Most of the time they get the results in a few seconds, despite the fact that many rows in various tables might be searched for detailed infos about the events in that city. However, this form partly relies on a table against which a MySQL event regularly does some operations. If the user uses the form while the event is being executed, they have to wait up to 30 seconds before getting the results, and sometimes only part of the html page is generated. Is there a way to avoid this lengthy waiting time ? I am wondering whether or not the best would be putting the site on maintenance while the event is being executed, with a "please come back in a few minutes" message. Thanks in advance for your help. hi
I am having problems trying to either include php file or execute a php script within <div with a class> which I use for a drop down menu, every bit of help much appreciated, thanks..singhy
<h2 class="hidenextdiv"><a href="#">dropdown menu1</a></h2> <div class="another dropmenuclass"> <h3>Test</h3> want to add my php working code here, have tried includes but no joy, it either breaks the dropdown menu or I am not getting the results back from the database, my script works ok, have tested it separately. <h3> </h3> <div style="clear: both;"> </div> </div> So I have a php script in public_html on my apache server, and it runs a global economy code for my browser game. If I open firefox and go to: http://localhost/Economy.php it runs the code, and it changes all the values in the database properly. How do I get that to run automatically, say every 6 minutes? I have windows so no cron jobs. I went to task scheduler and created a task which I thought would work, and it lists the task as running. But it gives me an error. Event Views: Code: [Select] Log Name: Microsoft-Windows-TaskScheduler/Operational Source: Microsoft-Windows-TaskScheduler Date: 9/28/2011 5:02:37 PM Event ID: 101 Task Category: Task Start Failed Level: Error Keywords: (1) User: SYSTEM Computer: Matt-PC Description: Task Scheduler failed to start "\Economy" task for user "Matt-PC\Matt". Additional Data: Error Value: 2147750687.Event Xml: Code: [Select] <Event xmlns="http://schemas.microsoft.com/win/2004/08/events/event"> <System> <Provider Name="Microsoft-Windows-TaskScheduler" Guid="{DE7B24EA-73C8-4A09-985D-5BDADCFA9017}" /> <EventID>101</EventID> <Version>0</Version> <Level>2</Level> <Task>101</Task> <Opcode>101</Opcode> <Keywords>0x8000000000000001</Keywords> <TimeCreated SystemTime="2011-09-28T22:02:37.967669800Z" /> <EventRecordID>18</EventRecordID> <Correlation /> <Execution ProcessID="1012" ThreadID="1484" /> <Channel>Microsoft-Windows-TaskScheduler/Operational</Channel> <Computer>Matt-PC</Computer> <Security UserID="S-1-5-18" /> </System> <EventData Name="TaskStartFailedEvent"> <Data Name="TaskName">\Economy</Data> <Data Name="UserContext">Matt-PC\Matt</Data> <Data Name="ResultCode">2147750687</Data> </EventData> </Event> EDITed for code tags |