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PHP - Table Form Input To Output To 2nd Page Table
Hello everyone. I need help with the following PHP APP. I am running on (Version PHP 7.2.10) I am trying to have a page table form on table.php pass the input variable of “5-Numbers” to another page called table_results.php I want that variable string of “5-Numbers” to be compared against 4 arrays and output any duplicates found within each of those 4 lists. If nothing is found, I still want some visual output that reads “None found”.
Lets pretend I have the following example .. On table.php, I typed inside my table form the 5-Numbers .. INPUT: 2,15,37,13,28 On table_results.php, the 4 arrays to be compared against my input numbers “ 2,15,37,13,28” are ..
$array_A = array(2,6,8,11,14,18,24); $array_B = array(1,2,9,10,13,14,25,28,); $array_C = array(1,3,7,9,13,15,20,21,24); $array_D = array(4,5,12,22,23,27,28,29);
So my output should read as follows below .. OUTPUT:
TABLE COLUMN 1 COLUMN 2 ROW 1 Matches Found Results .. ROW 2 GROUP A: 2 ROW 3 GROUP B: 2,13,28 ROW 4 GROUP ? 13,15 ROW 5 GROUP ? 28 ROW 6 5#s Input: 2,15,37,13,28
Please let me know if anyone has any suggestions on how to go about it. Thanks. Edited January 1, 2019 by Jayfromsandiego Wanted to include image example Similar TutorialsWhat I'm trying to do here is generate a table based on a form in which the user selects two options. The first option tells the script which database entries to put in the table, the second option tells it how to arrange them. The first works perfectly, the second not at all - it doesn't produce an error, it just doesn't do anything. I've found a number of tutorials that seem to suggest that the problem is somewhere in my punctuation around ORDER BY '$POST[sort]' but I've been unable to find a solution that actually works. Any help would be much appreciated, my code is below. Thank you! mysql_select_db($database, $con); $result = mysql_query("SELECT * FROM main WHERE state='$_POST[state]' ORDER BY '$POST[sort]'"); if(mysql_num_rows($result)==0){ echo "<p align='left'>View Pantries by State</p><div id='stateform'> <form action='../admin/viewstate.php' method='post'> <select name='state' /> <option value='AL'>Alabama</option> <option value='AK'>Alaska</option> <option value='AZ'>Arizona</option> </select> <select name='sort' /> <option value='name'>Name</option> <option value='id'>Id</option> <option value='city'>City</option> <option value='zip'>Zip</option> <option value='timestamp'>Timestamp</option> </select> <input type='submit' value='Go'></input></form> </div>"; } else{ echo "<p align='left'>View Pantries by State</p> <div id='stateform'> <form action='../admin/viewstate.php' method='post'> <select name='state' /> <option value='AL'>Alabama</option> <option value='AK'>Alaska</option> <option value='AZ'>Arizona</option> </select> <select name='sort' /> <option value='name'>Name</option> <option value='id'>Id</option> <option value='city'>City</option> <option value='zip'>Zip</option> <option value='timestamp'>Timestamp</option> </select> <input type='submit' value='Go'></input></form> </div>"; echo "<div id='fptext'><span class='h1'>Food Pantries for " . $_POST['state'] . "</span><br><br></div>"; } echo "<table border='1' align='center' cellpadding='3' width='900px'> <tr> <th>ID</th> <th>Name</th> <th>Type</th> <th>Address</th> <th>State</th> <th>Phone</th> <th>E-mail</th> <th>Website</th> <th>Hours</th> <th>Requirements</th> <th>Additional Information</th> <th>Lat</th> <th>Lng</th> <th>Update</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['id'] . "</td>"; echo "<td>" . $row['name'] . "</td>"; echo "<td>" . $row['type'] . "</td>"; echo "<td>" . $row['address'] . "</td>"; echo "<td>" . $row['state'] . "</td>"; echo "<td>" . $row['phone'] . "</td>"; echo "<td>"; echo "<a href=mailto:".$row['email'].">".$row['email']."</a>"; echo "</td>"; echo "<td>"; echo "<a href=".$row['website']."\>".$row['website']."</a>"; echo "</td>"; echo "<td>" . $row['hours'] . "</td>"; echo "<td>" . $row['requirements'] . "</td>"; echo "<td>" . $row['additional'] . "</td>"; echo "<td>" . $row['lat'] . "</td>"; echo "<td>" . $row['lng'] . "</td>"; echo "<td><a href='../public/updatepage.php?id=".$row['id']."'>Update Pantry</a></td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> I am trying to work on a code for php where you first have a form that asks the user to input a message then input a color. When they click the submit button it takes them to the output page. It should take their message and output it into boxes in a square. And the background should turn the color that they types in. Hi, I need a quick tip. I want this script to produce an output of "Table created" if it succesfully creates a table. <?php $con = mysql_connect("localhost","****","****"); if (!$con) { die('Could not connect: ' . mysql_error()); } // Create table mysql_select_db("my_db", $con); $sql = "CREATE TABLE People ( FirstName varchar(15), LastName varchar(15), Age int )"; // Execute query mysql_query($sql,$con); mysql_close($con); ?> I tried to do it on my own, but I guess I'm still completely new to php I tried: <?php $con = mysql_connect("localhost","****","****"); if (!$con) { die('Could not connect: ' . mysql_error()); } // Create table if (mysql_select_db("my_db", $con)) { echo "Table created"; } else { echo "Error creating Table: " . mysql_error(); } $sql = "CREATE TABLE People ( FirstName varchar(15), LastName varchar(15), Age int )" // Execute query mysql_query($sql,$con); mysql_close($con); ?> It gave me an error with the last two lines mysql_query($sql,$con); mysql_close($con); I removed them and it really did give the output "Table created" yet it didn't create the table in the database. I'm having a feeling that I need to add an "if" statement, something of the sort. if (sql(CREATE TABLE Persons)) But I'm also getting the feeling something there is wrong, I still haven't tried it. Help? Hi Guys, I have a query and a while loop output that I am sending to a webpage in a table format but I need some help in how best to do this so that the table columns line up with each other. Right now the column width seems to change depending on the data in the row. The code is quite simple: <?php include("lib/config.php"); $query = "SELECT * FROM staff_member"; $result = mysql_query($query); ?> <html> <style type="text/css"> <!-- @import url(style/style.css); --> </style> <head> </head> <body> <h2 align="center"> Full Staff list with Dependants</font></h2> <?php while($row = mysql_fetch_object($result)) { echo "<table id=sample> <th>Title</th> <th>First Name</th> <th>Initial</th> <th>Last</th> <th>Agency</th> <th>Street</th> <th>Address</th> <th>Parish</th> <th>Country</th> <th>Office Tel#</th> <th>Home Tel#</th> <th>Office Mobile#</th> <th>Personal Mobile#</th> <th>Zone</th> <th>Status</th> <th>Location</th> <th>Updated by</th> <tr> <td>" .$row->title ."</td> <td>" .$row->first ."</td> <td>" .$row->initial ."</td> <td>" .$row->last ."</td> <td>" .$row->agency ."</td> <td>" .$row->street ."</td> <td>" .$row->adress ."</td> <td>" .$row->parish ."</td> <td>" .$row->country ."</td> <td>" .$row->officetel ."</td> <td>" .$row->hometel ."</td> <td>" .$row->officemobile ."</td> <td>" .$row->personalmobile ."</td> <td>" .$row->zone ."</td> <td>" .$row->status ."</td> <td>" .$row->location ."</td> <td>" .$row->updater ."</td> </tr>"; echo "</table> </br>"; }//close $row while ?> </body> </html> Any help appreciated! Hi, Stuck again with the Joomla/K2 coding. Trying to output this field in a 2 column table but failing badly. Any help or ideas would be greatly appreciated. <?php if($this->item->params->get('catItemExtraFields') && count($this->item->extra_fields)): ?> <!-- Item extra fields --> <div class="catItemExtraFields"> <h4><?php echo JText::_('K2_ADDITIONAL_INFO'); ?></h4> <ul> <?php foreach ($this->item->extra_fields as $key=>$extraField): ?> <?php if($extraField->value): ?> <li class="<?php echo ($key%2) ? "odd" : "even"; ?> type<?php echo ucfirst($extraField->type); ?> group<?php echo $extraField->group; ?>"> <?php if ($extraField->name =='Closing date') : ?> <span class="catItemExtraFieldsLabel"><?php echo $extraField->name; ?></span> <span class="catItemDateCreated"><?php echo JHTML::_('date', $this->item->publish_down ); ?></span> <?php else :?> <span class="catItemExtraFieldsLabel"><?php echo $extraField->name; ?></span> <span class="catItemExtraFieldsValue"><?php echo $extraField->value; ?></span> <?php endif; ?> </li> <?php endif; ?> <?php endforeach; ?> </ul> <div class="clr"></div> </div> <?php endif; ?> Hello, I seem to have some problem with my script that has a goal of outputting data about the file size when a filename is queried.
The sql table name is file
The table columns are as followed: id | name | mime | size
The file name is stored in name. The script that i have that gets the file name is:
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="content-type" content="text/html;charset=utf-8" />
<meta name="generator" content="Adobe GoLive" />
<title>File Select</title>
<!--The following script tag downloads a font from the Adobe Edge Web Fonts server for use within the web page. We recommend that you do not modify it.--><script>var __adobewebfontsappname__="dreamweaver"</script><script src="http://use.edgefonts.net/aguafina-script:n4:default.js" type="text/javascript"></script>
</head>
<body>
<div id="title">
<h3 align="center">File Upload</h3>
</div>
<form action="result.php" method="post" name="fileID" target="_self" class="inp" AUTOCOMPLETE="ON">
<h1>
<!--Input file name-->
<label for="fileID">File Name: </label>
<input type="text" name='file1' id='sampleID' list="samp"> </input><br>
<datalist id="samp">
<?php
$connect = mysql_connect('localhost', 'root', '');
mysql_select_db("test_db");
$query = mysql_query("SELECT * FROM `file` ORDER BY `file`.`name` ASC LIMIT 0 , 30");
WHILE ($rows = mysql_fetch_array($query)):
$File_name = $rows['name'];
echo "<option value=$File_name>$File_name/option> <br>";
endwhile;
?>
</datalist>
<input type="submit" class="button" >
</form>
</body>
</html>
I'm having some trouble with displaying my white space between words. I have a table that holds records for resumes, and the administrator can access each record and edit them. I have the record displayed in text boxes for editing, but the white space between words is not showing up. Only the first word will show up. I have tried changing the field type in the table to text or blob instead of varchar, and I have tried using the nl2br function when displaying the records, but that isn't working either. What am I doing wrong? Here is my edit page: Code: [Select] <?php $applicant = "SELECT * FROM applicants WHERE id = '$_GET[id]'"; $applicant_res = mysql_query($applicant, $conn) or die(mysql_error()); $display_block = "<h3>Edit Entry</h3> <p>To edit the entry, change any relevant information below:</p> <form method=post action=update_U3IP.php><table>"; while ($applicants_list = mysql_fetch_array($applicant_res)){ $id = $applicants_list['id']; $firstname = $applicants_list['firstname']; $lastname = $applicants_list['lastname']; $address = $applicants_list['address']; $city = $applicants_list['city']; $state = $applicants_list['state']; $zip = $applicants_list['zip']; $phone = $applicants_list['phone']; $position = nl2br($applicants_list['position']); $file = $applicants_list['resume']; $display_block .= " <table> <tr> <td><label for=id><b>ID:</b></label></td> <td><input name=id type=text size=2 id=id value=$id /></td> </tr> <tr> <td><label for=firstname><b>First Name:</b></label></td> <td><input name=firstname type=text size=20 id=firstname value=$firstname /></td> </tr> <tr> <td><label for=lastname><b>Last Name:</b></label></td> <td><input name=lastname type=text size=20 id=lastname value=$lastname /></td> </tr> <tr> <td><label for=address><b>Address:</b></label></td> <td><input name=address type=text size=20 id=address value=$address /></td> </tr> <tr> <td><label for=city><b>City:</b></label></td> <td><input name=city type=text size=20 id=city value=$city /></td> </tr> <tr> <td><label for=state><b>State:</b></label></td> <td><input name=state type=text size=20 id=state value=$state /></td> </tr> <tr> <td><label for=zip><b>Zip:</b></label></td> <td><input name=zip type=text size=20 id=zip value=$zip /></td> </tr> <tr> <td><label for=phone><b>Phone:</b></label></td> <td><input name=phone type=text size=20 id=phone value=$phone /></td> </tr> <tr> <td><label for=position><b>Position:</b></label></td> <td><input name=position type=text size=20 id=position value=$position /></td> </tr> <tr> <td><b>Uploaded Resume:</b></td> <td><input type=text name=file id=file value=$file /></td> </tr> <tr> <td colspan=2> </td> </tr> <tr> <td colspan=2 align=center> <input type=hidden name=hidden_id id=hidden_id value=$id /> <input type=submit value=Submit /> <a href=admin_U3IP.php><input type=button name=back id=back value=Back /></a></td> </tr>"; } $display_block .= "</table></form>"; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>KulaE_WDP4451_U3IP</title> </head> <body> <?php echo $display_block; ?> </body> </html> Hi guys I am new here I have had a search around and can't really find out how to do this. Its quite difficult for me to explain and I am really new to PHP / mySQL - just starting out really. I hope to learn from doing small projects like this and seeing how it gets done. So I have a mySQL DB with two different tables - one is called "notesnew" the other is called "users". I have modified a common tutorial on how to make a "to do list" for what I am doing here. Basically users can login and post messages on this list as them self. Each user's post appears as a list item, showing their username, the time they posted the message and the message content. The message content, time and owner of the message is stored in the "notesnew" table. The list of user's, their passwords and their "avatar/profile" image URL location is stored in the "users" table. Now I am having trouble getting each user's avatar image from being output next to each of their posts. The part that is confusing me is being able to match up the username's post with their content that is display - because I am posting the user's name along with their post, based on the logged in "session name" as their username. So basically, all the content being listed is being displayed from the "notesnew" table. I need to somehow figure out what each user's profile image is based on what is stored against their entry in the "users" table. Here is the code I have so far. It is not working properly - it displays all content etc, but displays the avatar / image of the last user that has registered. Can anyone help me out here with some code that works, or pointers to try follow? I know the $finduserprofile part is incorrect in the way it goes through all user's and finds their profileimg, and that the image displayed next to each post is therefore incorrect (as it displays the last member to have registered's avatar, but its just that I don't know how else to do what I am trying to do. Code: [Select] <?php //Connect to the database $connection = mysql_connect('localhost', 'zzzz' , 'zzzzzzz'); $selection = mysql_select_db('zzzzz', $connection); $username = $_COOKIE['ID_my_site']; //Was the form submitted? if($_POST['submit']){ //Map the content that was sent by the form a variable. Not necessary but it keeps things tidy. $content = $_POST['content']; //Insert the content into database $ins = mysql_query("INSERT INTO `notesnew` (content, owner, dp_time) VALUES ('$content', '$username', NOW())"); //Redirect the user back to the members or index page header("Location:index.php"); } /*Doesn't matter if the form has been posted or not, show the latest posts*/ //Find all the notes in the database and order them in a descending order (latest post first). $find = mysql_query("SELECT * FROM `notesnew` ORDER BY id DESC"); $finduserprofile = mysql_query("SELECT * FROM `users` ORDER BY id DESC"); //Setup the un-ordered list echo '<ul>'; while($row = mysql_fetch_array($finduserprofile)) { $imagelocation = $row['profileimg']; //Continue looping through all of them while($row = mysql_fetch_array($find)) { $owner = $row['owner']; //For each one, echo a list item giving a link to the delete page with it's id. echo '<li>' . '<img src ="' . $imagelocation . '">' . $row['owner'] . ' said at ' . $row['dp_time'] . ': ' . $row['content'] . ' <a id="' . $row['id'] . '" href="delete.php?id=' . $row['id'] . '"><img src="delete.png" alt="Delete?" /></a></li>'; } } //End the un-ordered list echo '</ul>'; ?> I have a function which finds a list of companies associated with a country from a custom taxonomy. It finds their logo and creates an output which is all logos associated with a country, and the logo has a href to link to a company page. The code for this is: function countryCompanies(){ global $post;
$echo = f_print(array(
The f_print function finds the logos, and their sizes. So the 'mainlogo' type is a pull down of the thumbnail at 200px size.
What I need to do is write CSS and PHP which will display these results in a grid, 4 colums across, and as many down as results from the array. At the moment all I can get is all the results in one column. What tutorials would I need to write appropriate CSS to create this, and then is it as simple as adding the div prior to the echo of the $echo variable? Thanks if I'm outputting from mysql with this: Code: [Select] // Connects to your Database mysql_connect("localhost", "root", "") or die(mysql_error()) ; mysql_select_db("test") or die(mysql_error()) ; //Retrieves data from MySQL $data = mysql_query("SELECT * FROM tickets") or die(mysql_error()); //Puts it into an array while($info = mysql_fetch_array( $data )) { //Outputs the image and other data Echo "<b>asset number:</b> ".$info['AssetNumber'] . "<br> "; Echo "<b>subject:</b> ".$info['subject'] . " <br>"; Echo "<b>notes:</b> ".$info['Notes'] . " <hr>"; } can I base the record it outputs somehow on this: Code: [Select] $value=""; $value = ProcessLargeText(GetData($data,"Asset Number", ""),"","",MODE_VIEW); if($mainTableOwnerID=="Asset Number") $ownerIdValue=$value; $xt->assign("Asset_Number_value",$value); if(!$pageObject->isAppearOnTabs("Asset Number")) $xt->assign("Asset_Number_fieldblock",true); else $xt->assign("Asset_Number_tabfieldblock",true); It's kind of like a job history so its getting records of job history from one table while the second piece of code is getting the asset details from a main table Hello All, Iam completely new (3days old) to sql, php, html, so could do with a little help. Ok so I just found out about this wonderfull world and thought i would give it a try and I like it. But as I have no real idea of what Iam doing Iam finding it abit tricky to change some of the code I found at. http://www.phpfreaks.com/tutorial/simple-sql-search By the way thanks for this. So far I have setup a wamp server and got it all working fine and tweeked the above details in the url. This works great (well chuffed). But I could do with changing two things for now. 1). I could do with beeing able to search multiple things in the one text box for example. If I inputed "hello world" or "hel wor" it would search through the 19,000 lines in my database and find all instances of "hello" and "world" or "hel" "wor" in the same line's, it dosent matter what column they are in and output those lines. The code has the option to search all feilds "matchall" but not multiple words or parts of words.(hope that made sense I dont know all the terminology) It could be like using wild cards I suppose??. Is this possible or would I need multiple search boxes and if so how would I do that? 2). I would like the results to be returned in a table with headings for each column. If any one can help this would be great and thanks in advance for checking the long post out. Nick. Sorry if this is out there already but not to sure what I need to search for!??!?!? Ill include what Iam using so far. <?php $dbHost = 'localhost'; // localhost will be used in most cases // set these to your mysql database username and password. $dbUser = 'root'; $dbPass = ''; $dbDatabase = 'Stk_search'; // the database you put the table into. $con = mysql_connect($dbHost, $dbUser, $dbPass) or trigger_error("Failed to connect to MySQL Server. Error: " . mysql_error()); mysql_select_db($dbDatabase) or trigger_error("Failed to connect to database {$dbDatabase}. Error: " . mysql_error()); // Set up our error check and result check array $error = array(); $results = array(); // First check if a form was submitted. // Since this is a search we will use $_GET if (isset($_GET['search'])) { $searchTerms = trim($_GET['search']); $searchTerms = strip_tags($searchTerms); // remove any html/javascript. if (strlen($searchTerms) < 3) { $error[] = "Search terms must be longer than 3 characters."; }else { $searchTermDB = mysql_real_escape_string($searchTerms); // prevent sql injection. } // If there are no errors, lets get the search going. if (count($error) < 1) { $searchSQL = "SELECT id, Stock_Code, SV_Part_Number, SV_Description, SV_Search_Key FROM stkdb1 WHERE "; // grab the search types. $types = array(); $types[] = isset($_GET['Stock_Code'])?"`Stock_Code` LIKE '%{$searchTermDB}%'":''; $types[] = isset($_GET['SV_Part_Number'])?"`SV_Part_Number` LIKE '%{$searchTermDB}%'":''; $types[] = isset($_GET['SV_Description'])?"`SV_Description` LIKE '%{$searchTermDB}%'":''; $types[] = isset($_GET['SV_Search_Key'])?"`SV_Search_Key` LIKE '%{$searchTermDB}%'":''; $types = array_filter($types, "removeEmpty"); // removes any item that was empty (not checked) if (count($types) < 1) $types[] = "`Stock_Code` LIKE '%{$searchTermDB}%'"; // use the body as a default search if none are checked $andOr = isset($_GET['matchall'])?'AND':'OR'; $searchSQL .= implode(" {$andOr} ", $types) . " ORDER BY `Stock_Code`"; // order by title. $searchResult = mysql_query($searchSQL) or trigger_error("There was an error.<br/>" . mysql_error() . "<br />SQL Was: {$searchSQL}"); if (mysql_num_rows($searchResult) < 1) { $error[] = "The search term provided {$searchTerms} yielded no results."; }else { $results = array(); // the result array $i = 1; while ($row = mysql_fetch_assoc($searchResult)) { $results[] = "{$i}: {$row['Stock_Code']}<br />{$row['SV_Part_Number']}<br />{$row['SV_Description']}<br />{$row['SV_Search_Key']}<br /><br />"; $i++; } } } } function removeEmpty($var) { return (!empty($var)); } ?> <html> <title>My Simple Search Form</title> <style type="text/css"> #error { color: red; } </style> <body> <?php echo (count($error) > 0)?"The following had errors:<br /><span id=\"error\">" . implode("<br />", $error) . "</span><br /><br />":""; ?> <form method="GET" action="<?php echo $_SERVER['PHP_SELF'];?>" name="searchForm"> Search For: <input type="text" name="search" value="<?php echo isset($searchTerms)?htmlspecialchars($searchTerms):''; ?>" /><br /> Search In:<br /> Stock_Code: <input type="checkbox" name="Stock_Code" value="on" <?php echo isset($_GET['Stock_Code'])?"checked":''; ?> /> | SV_Part_Number: <input type="checkbox" name="SV_Part_Number" value="on" <?php echo isset($_GET['SV_Part_Number'])?"checked":''; ?> /> | SV_Description: <input type="checkbox" name="SV_Description" value="on" <?php echo isset($_GET['SV_Description'])?"checked":''; ?> /> | SV_Search_Key: <input type="checkbox" name="SV_Search_Key" value="on" <?php echo isset($_GET['SV_Search_Key'])?"checked":''; ?> /><br /> Match All Selected Fields? <input type="checkbox" name="matchall" value="on" <?php echo isset($_GET['matchall'])?"checked":''; ?><br /><br /> <input type="submit" name="submit" value="Search!" /> </form> <?php echo (count($results) > 0)?"Your search term: {$searchTerms} returned:<br /><br />" . implode("", $results):""; ?> </body> </html> In this output table, I would like to be able to click on any number in the ama row, add .html to that value and then execute the link. Example: If the ama number in row 3 is 890543, add .html to the number = 890543.html, then click on it to link to that web page. <?php // Connect to database ========================================= include("connect_db.php"); $table1='passwords'; $table2='airplanes'; // send query =================================================== $result = mysql_query("SELECT * FROM $table2") or die(mysql_error()); if (!$result) { die("Query to show fields from table failed"); } echo "<table border='10' cellpadding='3' cellspacing='2'>"; echo "<p>View All Airplanes</p>"; echo "<tr> <th>ID</th> <th>AMA #</th> <th>Model Name</th> <th>Model MFG</th><th>Wingspan</th><th>Engine</th><th>Decibels</th></tr>"; // keeps getting the next row until there are no more to get ================ while($row = mysql_fetch_array( $result )) { // Print out the contents of each row into a table ========================== echo "<tr><td>"; echo $row['id']; echo "</td><td>"; echo $row['ama']; // Append .html to this number echo "</td><td>"; echo $row['model_name']; echo "</td><td>"; echo $row['model_mfg']; echo "</td><td>"; echo $row['wingspan']; echo "</td><td>"; echo $row['engine']; echo "</td><td>"; echo $row['decibels']; echo "</td></tr>"; } echo "</table>"; ?> Hi guys, is there anyway to process this $result from a mysql query inside PHP so that the data below will be formatted to a pivot-like table? The number of rows and columns of the output 'table' will be indefinite. Thanks so much! Data: ID Row Col Name 1 1 A A1 2 2 A A2 3 3 A A3 4 1 B B1 5 2 B B2 6 3 B B3 7 1 C C1 8 2 C C2 9 3 C C3 Results: A1(1) A2(2) A3(3) B1(4) B2(5) B3(6) C1(7) C2( C3(9) Hello people. I am very new to PHP and have a website for microlight pilots where you can add an airfield. It is a Joomla based site and the input form can be seen here. http://microlight.co/index.php/New-Airfield I am quite prepared to re-write the whole input form again if I have to. Now here's my question. I would like the output of the form to be in an HTML table like it is on this page http://microlight.co/index.php/billaricay This is because at the moment people fill out the form, I get an e-mail with the info, and then have to put it into the airfield card manually myself. Sorry, If my explanation isn't very clear. But basically want users input into a table. Hi, I need some help here, the one which I have highlighted in red, 'dob' and 'gender', are not inputting any values into my database table. I'm just wondering did I miss out something important, or should I change the 'type' in my database table? Thanks <?php $dob = $_POST['dob']; $gender = $_POST['gender']; /**INSERT into tutor_profile table**/ $query2 = "INSERT INTO tutor_profile (name, nric, dob, gender, race) VALUES ('$name', '$nric', '$dob', '$gender', '$race')"; $results2 = mysqli_query($dbc, $query2) or die(mysqli_error()); ?> <html> <div> <label for="dob" class="label">Date Of Birth</label> <input name="dob" type="text" id="dob"/> </div> </html> <!--Race--> <div> <label for="race" class="label">Race</label> <?php echo '<select name="race" id="race"> <option value="">--Please select one--</option>'; $dbc = mysqli_connect('localhost', '111', '111', '111') or die(mysqli_error()); $query = ("SELECT * FROM race ORDER BY race_id ASC"); $sql = mysqli_query($dbc, $query) or die(mysqli_error()); while($data = mysqli_fetch_array($sql)) { echo'<option value="'.$data['race_id'].'">'.$data['race_name'].'</option>'; } echo '</select><br/>'; mysqli_close($dbc); ?> </div> Hi All,
I have a form with a jquery autocomplete input field. Once the user has entered 2 characters, there is a list of values (people names) containing this string that appears. This works good.
The values come from a database table with two fields (names and ids). The query that extracts the names also retreives the values in the id field.
What would be the syntax to set the "value" attribut of the input tag to the id of a name when the user clicks on that name in the list?
The PHP part that builds the json is :
$data[] = array( 'label' => $row['name'], 'value' => $row['name'], 'id' => $row['id'] ); echo json_encode($data);The JS begins as follows :
jQuery(document).ready(function(){
$('#input_id').autocomplete({source:'my_jquery_suggest.php', select: function(event, ui) {
$(event.target).val(ui.item.value);
$('#form_id').submit();
return false;
},
minLength:2,delay: 1000}).focus(function () {
window.pageIndex = 0;
$(this).autocomplete("search");
});
...
Thanks for your help.
This topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=323045.0 Hello. I have a basic form and I want to check for errors by making sure the user inputs everything, if not an error explaining to the user what needs to be fixed. (very common on all forms) When I use echo in my script, it displays at the top of my browser. How do I put the error codes right beside my form elements? I currently don't have all the error checking included but I want to get a few sorted out before anything else. Form Page: http://www.fusionfashionhair.com/registration.php My PHP Code all above DOCTYPE in the php file. Code: [Select] <?php $submit = $_POST['submit']; // Form Data // Check all form inputs using check_input function $name = strip_tags($_POST['name']); $address = strip_tags($_POST['address']); $email = strip_tags($_POST['email']); $repeatemail = strip_tags($_POST['repeatemail']); $phone = strip_tags($_POST['phone'], "Enter your Phone Number"); $salonname = strip_tags($_POST['salonname']); $salonaddress = strip_tags($_POST['salonaddress']); $salonprov = strip_tags($_POST['salonprov']); $salonpostal = strip_tags($_POST['salonpostal']); $salonconfirm = strip_tags($_POST['salonconfirm']); $enewsletter = strip_tags($_POST['enewsletter']); $saloncountry = strip_tags($_POST['saloncountry']); $password = strip_tags($_POST['password']); $repeatpassword = strip_tags($_POST['repeatpassword']); $date = date("Y-m-d"); // Set e-mail recipient $myemail = "info@fusionfashionhair.com"; if ($submit) { //check for existance if ($name&&$password&&$repeatpassword&&$email) { if ($password==$repeatpassword) { if ($email==$repeatemail) { //check password length if (strlen($password)>32||strlen($password)<6) { echo '<p class="formecho">Password must be between 6 and 32 characters</p>'; } else { // Thank you Page $insertGoTo = "thankyou.php"; header(sprintf("Location: %s", $insertGoTo)); // encrypt password $temppass = $password; $password = md5($password); $repeatpassword = md5($repeatpassword); // dBase file include "dbConfig.php"; //open database //generate random number for activation process $random = md5(rand(23456789,987654321)); // register the user! // Set default username $username = $email; // INSERT INTO user... replace user with table name // make sure you have the same number and order of values as the database has $queryreg = mysql_query(" INSERT INTO user VALUES ('','$name','$username','$password','$date','$email','$phone','$address','$salonname','$salonaddress','$salonprov','$salonpostal','$saloncountry','$salonconfirm','$enewsletter','$random','0')"); //Insert ID based on last ID in database $lastid = mysql_insert_id(); //send activation email $to = $email; $subject = "Activate Salon Member Acctount at Fusion Fashion Hair"; $headers = "From: webmaster@fusionfashionhair.com"; $server = "mail.fusionfashionhair.com"; //change php.ini and set SMTP to $server ini_set("SMTP",$server); $body = " $name from $salonname is wanting a membership, \n\n Please click on the link provided below to activate the account with Fusion Fashion Hair http://www.fusionfashionhair.com/activate.php?id=$lastid&code=$random \n\n Username = $username \n Password = $temppass \n Thank you, Customer Service "; //function to send email mail($to, $subject, $body, $headers); } } else echo '<p class="formecho">Your passwords do not match!</p>'; } else echo '<p class="formecho">Your Emails do not match!</p>'; }//End check Existance else echo '<p class="formecho">Please fill in <b>ALL</b> fields!</p>'; }// End if Sumbit ?> Hi All,
I want to copy into a table values from another table that partially match a given value, case-insensitively. So far I do as follows but I wonder whether there is a quicker way.
$input_table=array('1'=>'toto','2'=>'tota','3'=>'hello','4'=>'TOTO','5'=>'toto');
$input_table_2 = array_map('strtolower', $input_table);
$value_to_look_for='Tot';
$value_to_look_for_2=strtolower($value_to_look_for);
$output_table=array();
foreach ($input_table_2 as $k=>$v)
{
if(false !== strpos($v, $value_to_look_for_2))
{
$output_table[]=$input_table[$k];
}
}
One drawback is that $input_table_2 is 'foreached' whereas there might be no occurrences, which would lead to a loss of time/resources for big arrays.
Thanks.
Hello, I need some help. Say that I have a list in my MySQL database that contains elements "A", "S", "C", "D" etc... Now, I want to generate an html table where these elements should be distributed in a random and unique way while leaving some entries of the table empty, see the picture below. But, I have no clue how to do this... Any hints? Thanks in advance, Vero |
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