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PHP - Implications Of Passing By Reference
If getValue is given a path which doesn't exist, I can use the isset check to return null. I can also use the uncommitted $tmp =&$tmp[$key];. Why does this prevent an undefined index warning?
public function getValue(string $path) {
$path=explode('.', $path);
$tmp=$this->config;
foreach($path as $key) {
//if(!isset($tmp[$key])) return null;
//$tmp =$tmp[$key];
$tmp =&$tmp[$key];
}
return $tmp;
}
Similar TutorialsHi all, I'm trying to understand passing by reference. Here is a copy of the code and the results: Code: [Select] <?php $a1 = 15; $b1 = 20; echo addone($a1, $b1); echo "<br/>"; function addone($n1, $n2){ $n1 = $n1 += 2; $n2 = $n2 += 2; return $n1 . " " . $n2; }; echo addonetwo($a1, $b1); function addonetwo($n1, $n2){ $n1 = $n1 += 2; $n2 = $n2 += 2; return $n1 . " " . $n2; } ?> The result output is: 17 22 17 22 If I change the code to add "&" before the "addone" function: Code: [Select] function addone(&$n1, &$n2){ $n1 = $n1 += 2; $n2 = $n2 += 2; return $n1 . " " . $n2; }; Then the output is: 17 22 19 24 I don't understand what's going on. Why is the "&" incrementing the changed variable and in the first example it's incrementing the variables as defined. Ok, starting around line 137 with the functions..... Commented well. Just not sure If im doing it right. Any help greatly appreciated. Basic stuff and still learning. Just trying to figure out if Im passing by reference correctly or if not how to do it. Thanks. php File is attached but heres a snippet. Thanks in advance. Peace, Adam // The grand total and the item total need to be passed BY REFERENCE. function show_table_contents($cart_items, $table, &$grand_total, &$item_total) Hi, I'm just trying out some basic code and playing around with passing variables by reference and i was reading this on the php manual at this page http://php.net/manual/en/language.references.pass.php : No other expressions should be passed by reference, as the result is undefined. For example, the following examples of passing by reference are invalid: <?php function foo(&$var) { $var++; } function bar() // Note the missing & { $a = 5; return $a; } foo(bar()); // Produces fatal error since PHP 5.0.5 foo($a = 5); // Expression, not variable foo(5); // Produces fatal error ?> So, i decided to try it out myself like i always do, and i noticed that i'm not getting an error when i do foo(bar()); i.e calling bar() without the & in the function declaration. Infact it works perfectly fine and returns an incremented $a after its passed to foo(). Likewise foo($a = 5); also works great and returns an incremented $a after being passed to foo(). Is this a mistake in the manual or am i missing something? Running PHP 5.3.2-1ubuntu4.5 I everyone, I'm developing a small MVC framework for my personal work, now, in order to have access from all the classes to certain variables I've created a registry class, for this to work I have 2 options: 1.- passing every time the registry object to the constructor class(controllers, models, etc) or 2.- create in the registry static set and get so I can reach the variables by Registry::set(name, value) and Registry::get(name) My question is, which one of this two options takes less resources(is faster)? I hope anyone can help me with this, thanks in advance hello how do i pass a foreach loop through "Passing by Reference" say i have a foreach loop in a function like this: Code: [Select] function findText(&$output){ $word = Text::find_all(); foreach ($word as $words){ $output = $words->text; } } then one the page i put Code: [Select] findText($output); echo $output; that will just give me the last word in the database. so how do i get it to echo out the array on the page ? thanks Doing some troubleshooting, and I see that the value of $_SERVER['REMOTE_PORT'] changes on every request.
Per http://php.net/manua...les.server.php:
'REMOTE_PORT'
The port being used on the user's machine to communicate with the web server.
Is this normal? I am using a curl library to upload images to Amazon S3 using a php wrapper (http://undesigned.org.za/2007/10/22/amazon-s3-php-class). However, becuse CURLOPT_FOLLOWLOCATION is set to true on my server and open_basedir is enabled, this throws an error: Code: [Select] CURLOPT_FOLLOWLOCATION cannot be activated when in safe_mode or an open_basedir is set I understand that I could disable open_basedir or use one of the workarounds at http://php.net/manual/en/function.curl-setopt.php. Instead, as a quick test I set CURLOPT_FOLLOWLOCATION = false. The image upload to S3 still seems to work, but I am concerned that something may break down the line. Are there any implications that I should be aware of? I am not quite if CURLOPT_FOLLOWLOCATION is it even relevant in this case? I can create a one-to-one relationship between two tables by placing a unique constraint on the foreign key and making it NOT NULL, and make it one-to-at-most-one by removing the NOT NULL constraint. My question is what criteria should one use to determine which table holds the foreign key? For instance, I have the Car and Motor entities as shown below where one Car has one Motor, and conversely one Motor is used by one Car.
AbstractPart
Car extends AbstractPart What reasoning should one use to determine whether the Car table contain the Motor ID or should the Motor table contain the Car ID? Here's my thought: A person buys data, they have a quota, I'm talking about cellular networks. In any area, a tower or provider is more prevalent / stronger than others. What if, a person could install an app that allowed them to broadcast / be as a hotspot while getting paid per kb "sold". Technically I am not breaking the law am I? I mean that person 'paid' for that data. What is the difference between selling it to someone for money on their behalf (and mine) as opposed to wasting it on useless activities like browsing social media sites... ?
It would be an app that has both parties, "searching" and "transmitting".
What is "illegal" about this?
Aside from obvious problems like security
What are the differences and implications of UTC time and Zulu time?
<?php
function getArr(string $time):array
{
$dateTime = new \DateTime($time);
return [
'time'=>$time,
'timestamp'=> $dateTime->getTimestamp(),
'dateTime' => $dateTime
];
}
$arr = getArr('2020-08-05');
$arr_z = getArr('2020-08-05T00:00:00Z');
print_r($arr);
print_r($arr_z);
echo('equal timestamps: '.($arr['timestamp'] === $arr['timestamp']?'true':'false'));
Array
(
[time] => 2020-08-05
[timestamp] => 1596585600
[dateTime] => DateTime Object
(
[date] => 2020-08-05 00:00:00.000000
[timezone_type] => 3
[timezone] => UTC
)
)
Array
(
[time] => 2020-08-05T00:00:00Z
[timestamp] => 1596585600
[dateTime] => DateTime Object
(
[date] => 2020-08-05 00:00:00.000000
[timezone_type] => 2
[timezone] => Z
)
)
equal timestamps: true
Hi, I just need someone to check that a couple of lines I've written do what I believe them to do... i.e. check my logic! I'm developing a booking form for booking on events. Each booking needs a unique reference, which needs to be meaningless to the customer, so I am BASE36 encloding it. As the booking is be saved to a MySql database, my approach is to use the auto-incremented ID for the record to make the reference unique. The increment starts at 10000, and I add a random number before coding to make the encoded reference longer. I then BASE36 encode it to make it appear random. Am I right in thinking the reference produced WILL be unique ... provided the auto-inc ID is unique? $ref = rand(100,999) . $auto_incremented_id; //e.g. 354 & 10012 = 35410001 $ref_encoded = strtoupper(base_convert($rand, 10, 36)); // e.g.UD4J8P Thanks hello. say i have list and i want the correct children under each parent so i have $id $parent_id $type $name in the db i have 4 parents each with 2 children id=1 - type=parent - parent_id=0 - name=p1 id=2 - type=parent - parent_id=0 - name=p2 id=3 - type=parent - parent_id=0 - name=p3 id=4 - type=parent - parent_id=0 - name=p4 id=5 - type=child - parent_id=1 - name=c1 id=6 - type=child - parent_id=1 - name=c2 id=7 - type=child - parent_id=2 - name=c3 id=8 - type=child - parent_id=2 - name=c4 id=9 - type=child - parent_id=3 - name=c5 id=10 - type=child - parent_id=3 - name=c6 id=11 - type=child - parent_id=4 - name=c7 id=12 - type=child - parent_id=4 - name=c8 so how would i do the code? i thought i could do it like this but its not working. Code: [Select] <?php $family = Family::find_all(); foreach($family as $familys){ $id = $familys->id; $type = $familys->type; $parent_id = $familys->parent_id; $name = $familys->name; echo' <ul>'; if($type == "parent"){ echo $name; } echo' </ul> <li>'; if($type == "child" && $parent_id == $id){ echo $name; } echo' </li>'; } ?> all i get back is p1 p2 p3 p4 no children ?? if i remove Quote $parent_id == $id from Quote if($type == "child" && $parent_id == $id){ i get this p1 p2 p3 p4 c1 c2 c3 c4 c5 c6 c7 c8 but they are not listed under the correct parent i also tried moving the </ul> to the bottom but i get the same Code: [Select] <?php $family = Family::find_all(); foreach($family as $familys){ $id = $familys->id; $type = $familys->type; $parent_id = $familys->parent_id; $name = $familys->name; echo' <ul>'; if($type == "parent"){ echo $name; } echo' <li>'; if($type == "child"){ echo $name; } echo' </li> </ul>'; } ?> any thoughts? thanks rick Hi all, I have been coding in PHP for a fair while now and I have come across variables by reference, but I don't really know: a) how they work; b) when to use them; c) why they are used; Can anyone here please clarify these issues please. Thanks in advance! Can someone explain this strange behavior: $aArray = array( 1 => null, 2 => null, 3 => null, ); foreach($aArray as $key => &$val) { $val = "Some Value"; foreach($aArray as $Xkey => $Xval){} // Second foreach } var_dump($aArray); Rsult is: array(3) { [1]=> string(10) "Some Value" [2]=> NULL [3]=> NULL } It looks like second foreach breaks reference, why? Hello, I've just started learning PHP, JavaScript and I've got a big problem on my website. I'm getting this ReferenceError. I know what's the problem, but I don't know how to solve it, and I know people can do it for money but I don't have money, I'm searching for someone who's willing to help newbie. As I said I'm begginer, and I know something. The main problem is because I want to use GKPlugin and Player(jwplayer). Plugin need to use object, example:
<object id="flashplayer" classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" width="600" height="400"> <param name="movie" value="player.swf" /> <param name="allowFullScreen" value="true" /> <param name="allowScriptAccess" value="always" /> <param name="FlashVars" value="plugins=plugins/proxy.swf&proxy.link=http://www.vidbull.com/53qx9uo10k5d" /> <embed name="flashplayer" src="player.swf" FlashVars="plugins=plugins/proxy.swf&proxy.link=http://www.vidbull.com/53qx9uo10k5d" type="application/x-shockwave-flash" allowfullscreen="true" allowScriptAccess="always" width="600" height="400" /> </object>Script is generetad just to embed with iframe, and the problem is when I replace it with object, then I'm getting this error. I know that JS can't "call" that iframe to show because I've replaced it with object. You guys probably know about what I'm talking. I'm just searching for some instructions, guidelines from you.
ReferenceError: embeds is not defined
if (embeds[embedid].indexOf("rapidplayer")== iframe_ad){
Here's the rest of code, I think it's used to show iframe.
elseif (substr_count($link,"gorillavid")){
$video_id = explode("/",$link);
if (isset($video_id[count($video_id)-1])){
$video_id = $video_id[count($video_id)-1];
$embed = '<object id="flashplayer" classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" width="600" height="400">
<param name="movie" value="http://www.kiinc.com/videott/player.swf" />
<param name="allowFullScreen" value="true" />
<param name="allowScriptAccess" value="always" />
<param name="FlashVars" value="plugins=http://www.kiinc.com/videott/plugins/proxy.swf&proxy.link=http://gorillavid.in/'.$video_id.'" />
<embed name="flashplayer" src="player.swf" FlashVars="plugins=http://www.kiinc.com/videott/plugins/proxy.swf&proxy.link=http://gorillavid.in/'.$video_id.'" type="application/x-shockwave-flash" allowfullscreen="true" allowScriptAccess="always" width="600" height="400" />
</object>';
This is the original code. Don't look at providers(source as gorillavid) because I used gorillavid in previous an posted another example from another source (zalaa)
elseif (substr_count($link,"zalaa")){
$video_id = explode("/",$link);
if (isset($video_id[count($video_id)-1])){
$video_id = $video_id[count($video_id)-1];
$embed = '<IFRAME SRC="http://www.zalaa.com/embed-'.$video_id.'.html" FRAMEBORDER=0 MARGINWIDTH=0 MARGINHEIGHT=0 SCROLLING=NO WIDTH='.$width.' HEIGHT='.$height.'></IFRAME>';
Function which embed links and should embed GKPlugin/Player:
// general image link
if (!$embed){
$embed = "<div style='background-color:#000000; width: ".$width."px; height: ".$height."px;text-align:center;cursor:pointer;' onclick='window.open(\"$link\");'>";
$embed.= "<p style='text-align:center; padding-top: 70px;'>";
$embed.= "<a href='$link' target='_blank' style='font-size:24px; color: #ffffff !important'>Click here to play this video</a>";
$embed.= "</p>";
$embed.= "</div>";
}
return $embed;
}
JavaScript code:
function getEmbed(embedid){
if (embeds[embedid].indexOf("rapidplayer")== iframe_ad){
var html_content = "<div class='fake_embed' id='fake_embed"+embedid+"' onclick='closeFakeEmbed("+embedid+");'>" +
"<br /><br />" +
"<div class='fake_embed_ad_close'><a href='javascript:void(0);' onclick='closeFakeEmbed("+embedid+");'>Close Ad</a></div>" +
"<div class='fake_embed_ad' id='fake_embed_ad" + embedid +"'>" +
"<iframe src='"+baseurl+"/iframe_ad.php' width='300' height='300' frameborder='NO' border='0'></iframe>" +
"</div>" +
"<div class='fake_embed_bar'><span class='fake_embed_bar_right'></span></div>" +
"</div>" +
"<div id='real_embed"+embedid+"' style='display:none'>"+embeds[embedid]+"</div>";
jQuery('#videoBox'+embedid).html(html_content);
jQuery('#videoBox'+embedid).show();
} else {
jQuery('#videoBox'+embedid).html(embeds[embedid]);
jQuery('#videoBox'+embedid).show();
}
}
function countDown(embedid){
showCounter = showCounter-1;
jQuery('span#counter').html(showCounter);
if (showCounter>0){
showTimer = setTimeout('countDown('+embedid+');',1000);
} else {
showTimer = null;
showCounter = 20;
getEmbed(embedid);
}
}
function changeEmbed(embedid, counter){
if (counter == 0){
jQuery('.embedcontainer').html('');
jQuery('.embedcontainer').hide();
getEmbed(embedid);
} else {
if (showTimer){
clearTimeout(showTimer);
}
showTimer = null;
showCounter = counter;
jQuery('.embedcontainer').html('');
jQuery('.embedcontainer').hide();
jQuery('#videoBox'+embedid).html(js_lang.ticker);
jQuery('#videoBox'+embedid+' span#counter').html(showCounter);
jQuery('#videoBox'+embedid).slideDown("slow");
showTimer = setTimeout('countDown('+embedid+');',1000);
}
/*
jQuery('li.selected').removeClass('selected');
jQuery('#selector'+embedid).addClass('selected');
*/
}
Hi everyone, This is driving me crazy. I need to reference different files located in different folder structure. For example, I have the following file structure. /my_project/ /my_project/database/database_script.php /my_project/index.php 1. If I want to reference /my_project/index.php from /my_project/database/database_script.php, how can I reference it ? 2. From /my_project/index.php to /my_project/database/database_script.php , it's obvious all I gotta do it include("/database/database_script.php"). I use $_SERVER('DOCUMENT_ROOT"), to solve the 1. problem. It works on my XAMPP local machine but when I uplode it onto the server, there's a problem. The path becomes '/my_project/my_project/database/database_script.php". Is there a universal way (more like a standard way) to reference files in php so that I won't need to change every file path once I upload those onto the server ? Regards, I am writting a php function that uses mysql to get user data - pretty common, right Well, my issue is that I need to run a check in my file system. Users profile pictures are stored in my image directory as .png's. I need to have my function check that directory and if an image matches their id, then return their information. I only want the user data if they have an image uploaded. Here is my current function: Code: [Select] function fetch_users_login($limit) { $limit = $limit(int); $sql = "SELECT `users`.`id`, `users`.`firstname`, `users`.`lastname`, `users`.`username`, `user_privacy`.`avatar` FROM `users` LEFT JOIN `user_privacy` ON `users`.`id` = `user_privacy`.`uid` WHERE `users`.`status` > 2 AND `user_privacy`.`avatar` = 1 ORDER BY `users`.`id` DESC LIMIT 0, {$limit}"; $result = mysql_query($sql) or die(mysql_error()); $users = array(); $i = 0; while(($row = mysql_fetch_assoc($result)) !== false) { $users[$i] = array( 'id' => $row['id'], 'firstname' => $row['firstname'], 'lastname' => $row['lastname'], ); $users[$i]['avatar'] = getUserAvatar($row['username']); $i++; } return $users; } Dear All, Am new to PHP. now i want to online cargo tracking system in php. in that i create the reference id for each user to track the shipments. in that user must login and track the shipments. now i need the code for the specific user only view they shipments only. the other user can't be check the other shipments. so i need how to link the user and reference id. kindly advice me. OK, so I have the following file that has database functions: <?php function dbDelete($param){ $conDelete = mysql_connect($url,'username','password',true); mysql_select_db('my_db',$conDelete); mysql_query($param,$conDelete); mysql_close(); if(isset($conDelete)){ mysql_close($conDelete); } } ?> I include the above file in a session handling file. But for some reason the new file can't call the above function as follows: <?php include_once 'the above stated file'; function timeOut(){ dbDelete("DELETE FROM acctussessi WHERE acctussessi_usid = '$sessius[0]'"); $_SESSION = array(); setcookie(session_name(),'',time()-4200); session_destroy(); } //CHECK FOR TIMEOUT REQUEST switch($_GET['xyz']){ case 'timeout': timeOut(); header("Location: /?xyz=timedout"); break; case 'logout': timeOut(); header("Location: /?xyz=loggedout"); break; case 'refresh': dbUpdate("UPDATE acctussessi SET acctussessi_time = ".time()." WHERE acctussessi_unid ='".$token."'"); break; } ?> dbDelete isn't being called inside of the TimeOut() function. The only way it works is by doing the following: <?php function timeOut(){ $_SESSION = array(); setcookie(session_name(),'',time()-4200); session_destroy(); } //CHECK FOR TIMEOUT REQUEST switch($_GET['xyz']){ case 'timeout': dbDelete("DELETE FROM acctussessi WHERE acctussessi_usid = '$sessius[0]'"); timeOut(); header("Location: /?xyz=timedout"); break; case 'logout': dbDelete("DELETE FROM acctussessi WHERE acctussessi_usid = '$sessius[0]'"); timeOut(); header("Location: /?xyz=loggedout"); break; case 'refresh': dbUpdate("UPDATE acctussessi SET acctussessi_time = ".time()." WHERE acctussessi_unid ='".$token."'"); break; } ?> But this is annoying and repetitive. What is going on? Thanks in advance. Is it possible to get something as a reference in the script if it is such a http://site.com/home#p1 tried in different ways but #p1 my script does not see |
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