PHP - Need Help With Tar Command

Is there anything in php that let's me SWAP  2 arrays?

like let's say I have

3,2,1  in a array,

is there a way I can swap the 2 and 1 if a statement is true?

I am having difficulty working out how to grab from a URL within a URL a link to an image and display this image on a webpage.
example:

http://domainA.com/page1.php?file_image=http://domainB.com/image.jpg

I know little of this the code below but this is not working:

<?php echo $_GET['file_image']; ?>

this just copies the url, whereas I want to display this image.jpg from domainB using image source by grabing it.
<img src=" ">

I hope you understand me.

Hi..

I have a php file where i have only one line which says header('Location: index.php');

How do i run this php file in the terminal on fedora 14?

Thanks,
Rohit

This topic has been moved to mod_rewrite.

http://www.phpfreaks.com/forums/index.php?topic=326238.0

It was suggested that I add a ‘report’ parameter to the code, after revising with the ‘scale2ref’ code which appears to prevent the video from uploading/proceeding:

$ffmpegCommand =''.$ffmpeg_b.' -y -i '.$video_file_full_path.' -i '.$watermark_image_full_path.' -filter_complex "[0]scale=426:-2[vid];[1][vid]scale2ref='oh*mdar':'ih/10'[wm][vid];[vid][wm]overlay=5:5:format=rgb,format=yuv420p" -vcodec libx264 -preset '.$pt->config->convert_speed.' -crf 26 -report'.$video_output_full_path_240.' 2>&1';
$shell = shell_exec($ffmpegCommand); 

I couldn’t see where the -report parameter was supposed to output (error.log has a filesize of 0). So I was asked to “run command from the shell and check”?

But, I’m not sure what command and where/how to do that.

I tried adding this to the php code, and attempted to upload again, same result

echo shell_exec("/usr/local/bin/ffmpeg -report log.txt 2>&1");

 

any additional help is appreciated

 

 

Any guidance with that is appreciated.

Edited June 4, 2019 by Chrisj

Hello people,

At the moment I am really desperate. I've done this script over 20 times now, always with the same script but all of a suddon, it doesn't work anymore. heres the problem:

I made a very simple "patient database" for a doctor. Where he can upload patients, alter and delete them. The script to add the patients works fine. now im trying to make a script where he can alter the variables agian, using the UPDATE command. but instead of updating the variables it cleares all the date in the row.

can someone help me? here s the entire code:


Code: [Select]
<?PHP
include'connect.php';
?>
            <?PHP
$SQL = mysql_query("SELECT * FROM leys_patienten WHERE patientid='".$_REQUEST['patientid']."'");
while ($row = mysql_fetch_array($SQL))
{
?>
        <?PHP
if ($_POST[submit]) {
if (!$_POST[volgnummer]) {
echo "<font size=\"2\" color=\"#990000\"><b>--> Vul een volgnummer in a.u.b. <--</b></font>";
}
elseif (!$_POST[naam])
{
echo "<font size=\"2\" color=\"#990000\"><b>--> Vul een naam in a.u.b. <--</b></font>";
}
elseif (!$_POST[voornaam])
{
echo "<font size=\"2\" color=\"#990000\"><b>--> Vul een voornaam in a.u.b.! <--</b></font>";
}
else {

mysql_query("UPDATE leys_patienten SET volgnummer='$volgnummer',naam='$naam',voornaam='$voornaam',adres='$adres',postcode='$postcode',plaats='$plaats',telefoon='$telefoon',email='$email',geboortedatum='$geboortedatum',geboorteplaats='$geboorteplaats',opmerkingen='$opmerkingen' WHERE patientid='".$_REQUEST['patientid']."'")
or die(mysql_error());

echo "Het patientendossier is succesvol gewijzigd, let op doorschakeling.";?>
        <meta http-equiv="Refresh" content="1; url=patient.php?patientid=<?PHP echo $row['patientid']?>" />
        <?
}
}
?></p>

      <form action="<?$PHP_SELF?>" method="post" name="post" id="post">
        <table width="805" border="0" align="center" cellpadding="0" cellspacing="0">
          <tr>
            <td class="table_forms">Volgnummer*</td>
            <td class="table_forms"><label><input name="volgnummer" type="text" id="volgnummer" value="<?PHP echo $row['volgnummer']?>" size="40" /></label></td>
          </tr>
          <tr>
            <td width="146" class="table_forms">Naam*</td>
            <td width="659" class="table_forms"><label><input name="naam" type="text" id="naam" value="<?PHP echo $row['naam']?>" size="40" /></label></td>
          </tr>
          <tr>
            <td class="table_forms">Voornaam*</td>
            <td class="table_forms"><font color="#FFFFFF" size="2">
              <label><input name="voornaam" type="text" id="voornaam" value="<?PHP echo $row['voornaam']?>" size="40" /></label>
            </font></td>
          </tr>
          <tr>
            <td class="table_forms">Adres </td>
            <td><font color="#FFFFFF" size="2">
              <label><input name="adres" type="text" id="adres" value="<?PHP echo $row['adres']?>" size="40" /></label>
            </font></td>
          </tr>
          <tr>
            <td class="table_forms">Postcode</td>
            <td><font color="#FFFFFF" size="2">
             <label><input name="postcode" type="text" id="postcode" value="<?PHP echo $row['postcode']?>" size="6" /></label>
            </font></td>
          </tr>
          <tr>
            <td class="table_forms">Plaats</td>
            <td><font color="#FFFFFF" size="2">
              <label><input name="plaats" type="text" id="plaats" value="<?PHP echo $row['plaats']?>" size="40" /></label>
            </font></td>
          </tr>
          <tr>
            <td class="table_forms">Telefoon</td>
            <td><font color="#FFFFFF" size="2">
              <label><input name="telefoon" type="text" id="telefoon" value="<?PHP echo $row['telefoon']?>" size="40" /></label>
            </font></td>
          </tr>
          <tr>
            <td class="table_forms">E-mail</td>
            <td><font color="#FFFFFF" size="2">
              <label><input name="email" type="text" id="email" value="<?PHP echo $row['email']?>" size="40" /></label>
            </font></td>
          </tr>
          <tr>
            <td class="table_forms">Geboortedatum</td>
            <td><font color="#FFFFFF" size="2">
              <label><input name="geboortedatum" type="text" id="geboortedatum" value="<?PHP echo $row['geboortedatum']?>" size="40" /></label>
            </font></td>
          </tr>
          <tr>
            <td class="table_forms">Geboorteplaats</td>
            <td><font color="#FFFFFF" size="2">
              <label><input name="geboorteplaats" type="text" id="geboorteplaats" value="<?PHP echo $row['geboorteplaats']?>" size="40" /></label>
            </font></td>
          </tr>
          <tr>
            <td valign="top" class="table_forms">Opmerkingen</td>
            <td><font color="#FFFFFF" size="2">
              <label><textarea name="opmerkingen" cols="40" rows="4" id="opmerkingen"><?PHP echo $row['opmerkingen']?></textarea></label>
            </font></td>
          </tr>
          <tr>
            <td valign="top" class="table_forms">&nbsp;</td>
            <td><span class="body_tekst">
              <input type="submit" id="submit" name="submit" value="verstuur" />
            </span></td>
          </tr>
        </table>
        <p class="body_tekst">&nbsp;</p>
      </form>
  <?
}
  ?>

is there a way to excute the system() command here but not wait for it and just let it go in the background? And something that wont boggle down the system too much? Thanks!

Code: [Select]
$this->db->insert('jukebox', $data);
echo '1';

system('ffmpeg -i ' . $id . '.mp3 -acodec libvorbis -aq 60 ' . $id . '.ogg');

hello,

I have this problem in running a specific command after using shell_exec or exec to execute a certain process.

The process I am running is unimrcpclient, after initialization, it expects some command to be entered in order to communicate with the mrcp server. however, passing the command as an attribute is not an option. Is there a way in PHP to execute a process, wait for initialization and then pass the command automatically?

thank you.

hey guys m using STDIN as input stream in php command line

my problem is that some time i get this error

Warning: fgets(): supplied argument is not a valid stream resource in D:\myquery
\test.php on line 16
$number=fgets(STDIN);
anyone knows solution

Sorry to be a newbie.

I am writing some code that is supposed to query a row in my database. If that row returns the value "yes" I want to display a text or image.  It is currently being written within a pop up box, hence within the <span> parameters. 

Problem is it just doesnt work and was hoping someone could tell me why.  Have I got too many brackets? Should the values in the PHP admin table be set differently?  The bit I am having trouble is the 'IF commands".  Although the row 'moisture' has a yes value in the database it does not perform the echo.  The code is below:[/b][/b]






<a href="<?php echo $row_Recordset1['fabricpicture']; ?>" class="MagicZoomPlus" rel="caption-source:span;caption-position:right" title="<?php echo $row_Recordset1['fabricgroup']; ?> <?php echo $row_Recordset1['E']; ?>">

<img src="<?php echo $row_Recordset1['fabricpicture']; ?>" name="Grey" width="100" height="100" border="0" class="MagicZoomPlus" id="Grey"/>


<span><strong><?php echo $row_Recordset1['fabricgroup']; ?> <?php echo $row_Recordset1['E']; ?></strong> </p> <?php echo $row_Recordset1['fabricmaterial']?> </P> Max Width = <?php echo $row_Recordset1['width']?> </p> Max Drop = <?php echo $row_Recordset1['drop']?> </p> <?php if ($rowRecordset1['moisture']=="yes") {echo "moisture resistant";} ?> </p> <?php if ($rowRecordset1['flame'] == "yes") {echo "flame retardant";} ?></span>.
</a>

I want to do something like the following:

exec('open /Applications/Safari.app');



I can run exec on other commands like:


$output = exec('ls -ll);
echo $output;


And I can run the open command via Terminal, but I can't seem to run the open command via a PHP page using exec().

I've tried the permissions of the .app file at 777 and the open binary at 777.

Any suggestions?

I am trying to execute a command line tool, but am having a problem adding a variable to the line.
Here is the code
Code: [Select]
$filename = "devices.txt";
$handle = fopen($filename, 'r');

while (!feof($handle))
{
$devices = fgets($handle, 4096);
$query = 'ipmitool -I lanplus -H 192.168.1.1 -U admin -P adminpass sdr list';
passthru($query);
}
flcose($handle);

On this line I don't want to have the IP manually added like so.
Code: [Select]
$query = 'ipmitool -I lanplus -H 192.168.1.1 -U admin -P adminpass sdr list';

Instead I want to be able to insert the $devices variable which contains the values from the text file so it would look something like this:
Code: [Select]
$query = 'ipmitool -I lanplus -H $devices -U admin -P adminpass sdr list';
Problem is the command line tool does not run this way. How do I properly add the $devices variable so the command line tool ipmitool will run with its value?

Thanks,

Hello,

I am mounting google drive to my raspberry pi with this command from command line;

sudo gdfs -o allow_other /var/www/html/gdfs.creds /media/pi/gdrives

İt is working from command line, but it is not work when i execute it from web browser. Here php content;

shell_exec("sudo gdfs -o allow_other /var/www/html/gdfs.creds /media/pi/gdrives");

and i changed my sudoers file giving permission www-data. here is my sudoers file content

# This file MUST be edited with the 'visudo' command as root.
#
# Please consider adding local content in /etc/sudoers.d/ instead of
# directly modifying this file.
#
# See the man page for details on how to write a sudoers file.
#
Defaults        env_reset
Defaults        mail_badpass
Defaults        secure_path="/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin"

# Host alias specification

# User alias specification

# Cmnd alias specification

# User privilege specification
root    ALL=(ALL:ALL) ALL

# Allow members of group sudo to execute any command
%sudo   ALL=(ALL:ALL) ALL
www-data ALL=NOPASSWD: ALL

# See sudoers(5) for more information on "#include" directives:

#includedir /etc/sudoers.d

Can anyone tell me what i am doing wrong ?

Hi all,
I need to create a button my page that when clicked will update my mysql table.
I also need a command that will find 3 'x' values and update them accordingly,

It needs to update the theme column in my model pictures table, Would something similiar like this work?
Code: [Select]
UPDATE theme
SET name = '5'
WHERE name = '1 or 2 or 4';[code]

Does this make sense?

Hi, I have a strange problem using the exec command.
I have the following php code :
<?php
error_reporting(E_ALL);
ini_set('display_errors','On');

$accountBase = "HORAIREMOBILE";
$primaryUser = "DUM";
$secondaryUser = "DUM";
$result = exec(escapeshellcmd("/home/evidian/utils/getAccount ".escapeshellarg($accountBase)." ".escapeshellarg($primaryUser)." ".escapeshellarg($secondaryUser)),$output,$return_val);
echo $result;
?>

When I execute the command from the CLI, with any user, it just works fine, and shows my the result (basically a JSON formated output).
However, when I call the code frome the apache server, it simply returns nothing.

Could anybody help me with this issue ?