PHP - Image Creation

With the following code i can create an xml file.
Code: [Select]
<?php
$myXML = new SimpleXMLElement("<myroot></myroot>");
$title= $myXML->addChild('title');
$title->addAttribute('number','12');
$titleName= $title->addChild('titleName', 'title1');
$titleLink= $title->addChild('titleLink', 'link1');
Header('Content-type: text/xml');
echo $myXML->asXML();
?>

But when i check the validity of xml file
http://www.validome.org/xml/validate/
This error occurs:
Can not find declaration of element 'myroot'.

I suppose that the problem is missing of
!DOCTYPE and
!ELEMENT lines.

How can i create valid XML documents with PHP automatically??
Is it possible to make it without writing doctype and element types
for the whole element types of xml by hand
$title, $titleName and $titleLink

Thank you

Hi,

I am wanting to check to see if a folder exists, if not create it.  PHP on a windows machine so I would like to know how to handle the folder separators.  I am wanting to use a path which includes the drive letter, such as... $foldername ="C:\folder1\images\$checkfolder"

I was thinking about using something like this:
if(!is_dir($foldername)) mkdir ("$foldername",777);

What would be the best way of tackling this using windows paths?

I am not sure what to look for to even get started. If some one could help point me in the right direction that would be appreciated.   I created a customer system that tracks contracts and invoices ect. Where do I start if I would want a customer to be able to go to the website, sign up, and their own version of the system would be created.   Do I just write a script that creates a new database with the correct credentials? Do all of the users access the same files but just have different database. Do I have to copy the directory of files to a specific folder for each customer?   I know there must be tons of websites that once you sign up for example a calendar app that keeps your data seperate from everyone else.   Any help is appreciated.   Thanks   Jack    

This topic has been moved to mod_rewrite.

http://www.phpfreaks.com/forums/index.php?topic=321416.0

Hey, guys, in the following code, why i cannot see my ~/test.txt file? It seem he is not doing what i want, to create a .txt file with 'is just a test'. I'm using Debian.  

<?php
$f = fopen("~/test.txt","w+");
fwrite($f,'is just a test');
fclose($f);
?>

  Thank you!

Day

I'm using Codeigniter and inside the framework I create a file with PHP code
(Codeigniter doesn't provide means to create files) by copying from a template
file, set the permissions to 0775 and the ownership is ruled by sticky bits on the
directory hosting the file. The ownership is set to the Apache settings (http:http),
just to be 'sure'...

If I try to point to it, the web-server doesn't deliver due to permission issues.

All this is done in a 'register function' where I create some fields in a SQL
database to save user credentials. As of now the application should be
obvious.

If I put the user credentials into the database 'by hand' and likewise when I
create a file in the above mentioned directory (http:http) 'by hand' and point
the web-server on it, it gets delivered. Even if I keep the original ownership
conditions 'user:http'.

I'm pretty sure this issue has been existed before and I'd appreciate any help.
I'm also sure it has in some way to do with either file creation permissions
or/and the user running PHP. I was going far from that PHP (more precise
mod_php) is running as the same user as Apache?

 

Thanks for your help in forward.

Gee

Edited August 17, 2020 by bogus

I've been stuck on this for about a week so I was wondering if I can get some help from you guys!

Basically I'm exporting an array of values to a CSV file, within that array are two other arrays containing data I need. What I need to work out is how I can create a CSV with headers for these values, then with the nested arrays also print their values into the same rows as the first array. Example:

$List = array (
'Product ID' => '10',
'Customer Address' => '123 Fake Street',
array(
         array('Product Name'=>'Product1', 'Product Price'=>'10.00', 'Product Reference'=>'HGJEN'),
         array('Product Name'=>'Product2', 'Product Price'=>'5.00', 'Product Reference'=>'HGJTN'),
         array('Product Name'=>'Product3', 'Product Price'=>'10.00', 'Product Reference'=>'HGJNN'),
),
array(
         array('Product Customisation Name'=>'Additional Info', 'Customisation Value'=>'Things are great.'),
         array('Product Customisation Name'=>'Image Upload', 'Customisation Value'=>'Logo.jpg'),
   
),
'Telephone Number'=>'999',

);

To be exported to something looking like this:

Product ID Customer Address Product Name Product Price Product Reference Product Cus Name Cus Value Telephone Number 10 123 Fake Street Product2 5.00 HGJTN Additional Info Things are great 999 10 123 Fake Street Product1 10.00 HGJEN Image Upload Logo.jpg 999 10 123 Fake Street Product3 10.00 HGJNN 999
If anyone could help me out in anyway I would be so appreciative, I'm sure this ones going to end up killing me!

Hi All

I am trying to insert a feed on my site that automatically updates the football league etc

like this one

http://news.bbc.co.uk/sport1/hi/football/eng_div_1/table/default.stm

is there a way to do this please?

thanks

Hi all,

Weird one: I am re-working a site for a client. Their old site currently grabs text from a DB and somehow automatically puts it into a <ul>. The only thing to signify a <li> is a linebreak. So if I entered:

Item 1
Item 2
Item 3

into the database, they would come out looking like:

Item1 Item 2 Item 3
on the site. Anyone know of a way to recreate this?

An example of this in action is he http://www.postureperfection.com.au/Chairs/Amore_Chair/p/495/ (please remember - I am redesigning the site!)

Thanks heaps!

Hi

So I have successfully set up a website and database where a user can create a listing and view listings on a listing details page. The viewing can only be done, however, only from either from either running a search query from the search form or from clicking one of the listings from the listing table. The listings are not being indexed from the search engines from the direct page, instead from the listing table which is about 3,000 listings, not very user friendly to land on this page and have to go through the table or use the table filter.  Here's what I am trying to accomplish:

A web page that has a dynamic presence / URL like a Wordpress page: http://www.mysite.com/listing_title/ The title of the page has the listing information in it: This page is about a $listing_title $listing_item listing number $listing_number that is online! Each individual Listing / page is indexed on the search engines and has a direct link to it
I am familiar with PHP and have created this site but I am far from an expert! Please give me a code example or link to one because if you just say "do this to this and that" you will totally loose me.
Thank you so much for any help.

Hi All,    I've been interested in writing a PHP pdo configuration file so that I can include connections in various files on my site. While I was looking up some possible solutions I stumbled across an interesting post on stack overflow http://stackoverflow...-pdo-connection   The first responder suggested the code below. However, I don't understand how to access the connection and make query calls. I'm confused by how it's possible to return a variable name as an object { return new $name( $this->connection ) }.   Also, If someone could explain what the author means by  { $something = $factory->create('Something');}. Wouldn't the "Something" need to be a class? And how would that class get the db connection?    All the best,    Karma 

$provider = function()
{
    $instance = new PDO('mysql:......;charset=utf8', 'username', 'password');
    $instance->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    $instance->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
    return $instance;
};

class StructureFactory
{
    protected $provider = null;
    protected $connection = null;

    public function __construct( callable $provider )
    {
        $this->provider = $provider;
    }

    public function create( $name)
    {
        if ( $this->connection === null )
        {
            $this->connection = call_user_func( $this->provider );
        }
        return new $name( $this->connection );
    }
}

$factory = new StructureFactory( $provider );
$something = $factory->create('Something');
$foobar = $factory->create('Foobar');

Hi -
I know this is a #101 question but here goes!

I simply want to select  a single  row from a table and use the columns fields as variables that can then be posted in a form.

$result = mysql_query("SELECT * from tblquestions WHERE qid='1'");


if (!$result) {
    echo 'Could not run query: ' . mysql_error();
    exit;
}
$row = mysql_fetch_row($result);

$oid=$result['oid'];
$qid=$result['qid'];
$question=$result['question'];


The code above isn't working - as when I try to echo each variable <?php echo $question;?> nothing is being shown on screen.

I'm obviously barking up the wrong tree in the way I'm trying to create the variable - but don't really have any idea where to look next.

*Mods* PLEASE don't move this to the OOP section again. I've had no luck there, and it's not specifically an OOP question.

Hi everyone,
I just want to know if there's a shorthand way to create objects, as there is for arrays:

Code: [Select]
// shorthand array creation

$foo = array(
'bar' => 0,
'baz' => array
(
'name' => 'Dave',
'gender' => 'male'
)
)
Code: [Select]
// is there a way to do this with objects?
// not that I know so far...

$foo = object(
bar->0,
'baz' -> object
(
name -> 'Dave',
gender -> 'male'
)
)
I find object-access syntax is often quicker and easier to write than array-access syntax. Have I missed something obvious that I can't just write it out this way?

Cheers,
Dave

Given the below 3 database tables I am trying to construct a SQL query that will give me the following result:

customer_favourites.cust_id
customer_favourites.prod_id OR product.id
product.code
product.product_name
product.hidden
product_ section.section_id (MUST BE ONLY THE ROW WITH THE LOWEST SECTION ID, I.E. ROW ID #44108)
product_ section.catpage (MUST BE ONLY THE ROW WITH THE LOWEST SECTION ID, I.E. ROW ID #44108)
product_ section.relative_order (MUST BE ONLY THE ROW WITH THE LOWEST SECTION ID, I.E. ROW ID #44108)

I currently have....

SELECT customer_favourites.cust_id, customer_favourites.prod_id, product.code, product.product_name, product.hidden, product_section.section_id, product_section.relative_order, product_section.catpage  
FROM customer _favourites  
INNER JOIN product ON customer_favourites.prod_id = product.id  
INNER JOIN product_section ON product_section.product_code = product.code  
WHERE `cust_id` = '17' AND `hidden` = '0' GROUP BY `code`  
ORDER BY `section_id` ASC, `relative_order` ASC, `catpage` ASC LIMIT 0,30

This gives me what I want but only sometimes, at other times it randomly selects any row from the product_section table.

I was hoping that by having the row I want as the last row (most recent added) in the product_section table then it would select that row by default but it is not consistent.

Somehow, I need to be able to specify which row to return in the product_section table, it needs to be the row with the lowest section_id value or it should by the last row (most recent).

Pulling my hair out so any help is gratefully received.  
customer_favourites

id     cust_id   prod_id
70    4            469
product

id        code           product_name    hidden
469    ABC123     My Product        0
product_section

id                  section_id      catpage    product_code    relative_order     recommended
44105         19                   232            ABC123             260                    1
44106          3                     125            ABC123              87                      1
44107          2                     98              ABC123             128                     1
44108          1                    156             ABC123             58                        0

 

I havent included the whole title as it wouldnt let me but I was wondering if someone could help me on this?

I know this is possible as torrentflux caters for this but unsure of where to start.

I dont want to allow file or directory uploads or creation in my /etc/php.ini file (this is turned off).

Yet then torrentflux allows me to link a torrent from an external source (using legal downloads of course  ) but then it uploads it on my server and creates folders on a per user basis.

How is this possible can someone give me some pointers please?

I look forward to any replies,
Jeremy.