PHP - Detect Emails That Hard Bounce

I something like this to happen... A user has a text field and a button, he enters text in the field and clicks the button it will go to a URL. Once it goes to that URL it has a text field, this field would be automatically completed from what the user typed in at the start. On that URL there is also a button, that is automatically clicked once the text field has been automatically entered. BUT the user only sees the first page where he entered text in the field and clicked the button. Everything that happens after he clicked that button he cannot see.   Is there a particular phrase you would call this from what is happening? If so, what is it and how would I do it? This probably is hard to understand but I tried :/   Thanks

Get a hugh problem with a work in school!

We are suposed to optimize a website for moblie devices..

Just by using xhtml, css and php.

the problem is that I want the meny to just show at the front page for mobile devices..
I konw that I can choos pic with
< img >
< media="only screen and (min-width: 640px)" src="bild1.jpg" />
< media="only screen and (min-width: 800px)" src="bild2.jpg" />
</ img >

is it possible to do a if construct in any point with using media?

please help, Im lost.

Sorry this may sound insane.

Is there anyway to accomplish this,

using paypal you can creat buy it now buttons and whatnot. The problem with these is you set the price of the time when making the button.
Is there a way to set the price with php thus creating a dynamic price instead of a static one?

I know you can send paypal vars. but is there a way to edit the price?

Thanks I hope that makes sense at all

Please delete my other post as I realized it is not what I needed and I cannot delete it myself.

Here is exactly what I need.

I have X amount of text files (with random names) in each text file there is Y amount of lines with one word on each line.

I need to open all X amount of files and take the first line from each and save it in a new txt doc. then take the second line of each and save them to a new text doc. and so on.

so I have all the line 1's from all the txt files together
and all the line 2's together etc.


I hope that makes sense.

Hey guys,

this is what I'm trying to do.
I want to print on the member's profile page, a list of the products he has bought so far.

I've come with two solutions:

A) add a new field to the products' table, with the ID of every clients that bought that product;
B) add a new field to the members table, with the ID of every products he bought;

These are pretty similar approaches, but I've no idea on how can this be done.

It would look like:

Bought: 2, 3, 4, 5,

I dont know how to write this data or how to read it.

Any idea?
Thanks!

Ok all I need some help with this. I have been stuck for two days. Basically I have a form that asks a registrant their gender and age, then my script spits out a list of race categories they qualify for. The situation calls for the registrant to be able to register for any category YOUNGER than them, but not older.

Screen Shot #1 shows my database setup (this can be changed if you have any better ideas...) that holds the race category information.

Here is the sql statement I am using to pull a female racer information, where $race_age is their submitted age.

"SELECT * from counts where female=1 and $race_age < age_end and $race_age > age_start"

This works, but doesn't pull any categories YOUNGER Than their age.

I'm stumpped Thanks for any help in advance.

I get the following error:
Quote

Parse error: syntax error, unexpected ';' in /hermes/web06/b1946/moo.rghollenbeck/index.php on line 35


But here is the only php code on the whole page:


. . .more html code above
<?php 

// PHP version: 5.2.12
// MySQL Version: 5.0.77

$link = mysql_connect('path', 'username', 'pword'); 
if (!$link) { 
die('Could not connect: ' . mysql_error()); 
} 
mysql_select_db(guestlist); 

$Users_IP_address = $_SERVER["REMOTE_ADDR"] ;
echo "<input type='hidden' name='ip' value=";
echo $Users_IP_address;
echo ">";

$first_name=mysql_query("SELECT 'fname' FROM tblMain; WHERE 'ip'=" . $Users_IP_address);

// pseudocode section:
// If $first_name !null{
// echo "Hello " . $first_name;
// }
// end pseudocode section:
// something like that
?>
more html code below. . .

Thank you.

Hi guys,

Here's my problem.  My company wants to use SSRS to generate reports.  The backend, what stores the data for the report is MS SQL 2005 (and no, I can't upgrade it to 2008, we don't have the licenses for it).

When I used one of their examples to login, I got an error stating that the URL, username or password might not be correct.  But when I do this, I connect just fine:
Code: [Select]
$client = new SoapClient("http://sampleURL/reportserver/reportexecution2005.asmx?wsdl", array('login' => "lmaster\SVCWEBDOCS", 'password' => "pdfconverter"));
Now, honestly, I don't know much about this and I'm still doing some research, has anyone tried to make this SDK spit out a report?  I'd appreciate some guidance/direction as to what to do next.  Also, if you could tell me about some of your experiences in getting to work, I'd really appreciate it.

In ubuntu 18.10 ,  i created a folder name db in the external usb hard dirve changed the ownership to the www-data the apache2 server and set the permissions to 777 , i run this php code and get the permission error:

<php
 chdir('/media/user/e46cafba-2656-4e42-b1c9-6417f28839df/db/');
 system('./rs');
?>    

but the php code cannot change to the dir and get the error:

[21-Feb-2019 10:43:26 UTC] PHP Warning:  chdir(): Permission denied (errno 13) in /home/user/www/html/rse4db.php on line 5

 

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=328677.0

hey guys

so I have this code:
$result = mysql_query("SELECT * FROM pec_mssgs  ORDER BY (y / m) DESC, d ASC");

while($row = mysql_fetch_array($result))
  {
  
  
echo "&bull;<a style='text-decoration: underline; font-weight: bold;' href='../index?id=".$row['id']."'>". $row['m']."/".$row['d']."/".$row['y'] . "  -  ".$row['title']."</a>";
echo "<br /><br />";


  }

in my database instead of doing date I have 3 rows d, m, y, which correlate to day, month, year.

now currently its echo out a list and sorting by year then month then day this way the events which are happening soonest will be at top.

the problem is it shows events that has already passed.

what do I do?

It will be way to much work to to back and recode the application to just use date.

is there a way I can create a var. using my d/m/y then compare that var. to the current date or something?

thanks for the help.

Hi all,

I have created a successful registration and login page for what will eventually be a squash league website.

I am struggling with the following issue.

When a player logs in using their email address and password I want to populate some drop down boxes which are relevant to the person who has just logged in.

These drop downs should show all the leagues the logged in user belongs to and the other drop down should show all the players the currently logged in player has ever played against so that they could view a head to head.

So my code works but currently I have the id of the player who has logged in hard coded in my sql statements.

I'm wondering if anyone can help me so that I can pass in the id of the player who is logged in as obviously the whole site is not going to work with hard coded values.

The code is as follows:

Code: [Select]
<?php

include_once $_SERVER['DOCUMENT_ROOT'] . '/includes/magicquotes.inc.php';

require_once $_SERVER['DOCUMENT_ROOT'] . '/includes/access.inc.php';

if (!userIsLoggedIn())
{
 include 'login.html.php';
 exit();
}

if (!userHasRole('Squash Administrator'))
{
 $error = 'This page is only for Squash Administrators.';
 include 'accessdenied.html.php';
 exit();
}

if(isset($_REQUEST['email']))
{
 include $_SERVER['DOCUMENT_ROOT'] . '/includes/db.inc.php';
 
 $email = mysqli_real_escape_string($link, $_REQUEST['email']);
 $sql = "SELECT id, firstname, lastname, email FROM player WHERE email = '$email'";
 $result = mysqli_query($link, $sql);
 if(!$result)
 {
  $error = 'Unable to select players firstname from the database.' . mysqli_error($link);
  include 'error.html.php';
  exit();
 }
 
 while($row = mysqli_fetch_array($result))
 {
  $players[] = array('id' => $row['id'], 'firstname' => $row['firstname'], 'lastname' => $row['lastname'], 'email' => $row['email']);
 }

 //
 //POPULATE THE OPPONENTS DROP DOWN BOX TO SHOW ALL PREVIOUS OPPONENTS
 //

 $sqlid = "SELECT id FROM player WHERE email = '$email'";
 $playerid = mysqli_query($link, $sqlid);
 $sql = "SELECT DISTINCT player.firstname, game.player2_id AS opponent_id
 
FROM player INNER JOIN game
                
                ON player.id = game.player2_id

WHERE player1_id = '$row['id']'

UNION

SELECT DISTINCT player.firstname, game.player1_id AS opponent_id

FROM player INNER JOIN game
                
                ON player.id = game.player1_id

WHERE player2_id = '$row['id']'";

 $result = mysqli_query($link, $sql);
 if(!$result)
 {
  $error = 'Unable to populate the players dropdown from the database.' . mysqli_error($link);
  include 'error.html.php';
  exit();
 }
 
 while($row = mysqli_fetch_array($result))
 {
  $opponents[] = array('id' => $row['opponent_id'], 'firstname' => $row['firstname']);
 }

include 'squash.html.php';

}

?>
Thanks for your help and time in advance.

hello dear php-experts


how to testrun a drive with command-line?

note: i had several blank screens during the last week

does this somewhat have to  do with the hard-drive?

which tests can be done?

hello,

if i have

$big=3410

how can i take the last 2 digits of that to make it so that i only get the 10?

hope this makes sence.

 hello, i seem to be stuck again and this bug is difficult for me to solve.

if(isset($_POST['boards']))
	$boards[] = $_POST['boards'];
$allboards = implode("",$boards[0]);
echo $allboards;

outputs (browser source)...
hello
world

I have a combobox with the "multiple" property.  when two items are selected, the combobox "name" property has an array that passes to the $_POST variable. what i would like is those two words to be displayed on the same line.
I have tried rtrim($var, "\r\n") but that does nothing.

the reason i need them on the same line is because i would change then to "hello, world" and then add them as a mysql query, for example... $query = "SELECT hello, world FROM table...