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PHP - Display Enum Values From Mysql Table
Hi, i don't understand how to show ENUM type data in php. Now i use:
<input type="text" name="type" style="width: 362px; height: 35px;" value="<?php echo $type; ?>"> But it print only the value that is set to topic i see. How to display all ENUM values in radio buttons and that checked button would be that one from the topic. For example: ENUM ('city','town','vilage') . I select town when writing a topic. And when i edit data i see 3 radio buttons and TOWN would be checked. Thank you for answer. p.s maybe someone know a good site where is a tutorial how to show enum in php Similar Tutorials
Table Issue - Multiple Location Values For User Pushes Values Out Of Row Instead Of Wrapping In Cell
Hello, I have some trouble to display result from my enum tab I did this : if ($level == "a"){ $level = "Level 1"; }else if ($level =="b"){ $level = "Level 2"; }else { $level = "Level 3"; } and on my html <?php echo $level; ?> it display Level 3 on all record... Any idea what I'm doing wrong? I have a database field `color` enum('red','blue','green','white') DEFAULT NULL, and php form <label for="color">Colors</label><br /> <input type="text" name="color" /> How do i display enum value on the php form from mysql database? Please help php mysql I am trying to display a single value on my page and i cant seem to display it for the life of me. can someone tell me if im doing something wrong? this is what i have so far: <?php require_once('inc/common.inc.php'); // Connect to the database db_connect(); // Check and update the authentication. check_auth(); db("select * from ${db_name}_users where login_id = '$login_id'"); echo "$login_id"; ?> obviously there is a field in the database that corresponds to turns and it is int(4), ..... Now, i am able to display $login_id, but when i try to display another field, named turns, it just displays a blank page. Any pointers would be appreciated thank you. Hello, I need some help. Say that I have a list in my MySQL database that contains elements "A", "S", "C", "D" etc... Now, I want to generate an html table where these elements should be distributed in a random and unique way while leaving some entries of the table empty, see the picture below. But, I have no clue how to do this... Any hints? Thanks in advance, Vero What gets put in for the values is my problem. I have tried every way I can think of but I get errors in the code or I don't get the row inserted. Can anyone give me a code sample using $ variables, preferably a multi-line list? I would have to fix up my code to show you what I am trying as it is in between tries now. I have to be doing something wrong and may have to put together a simple test script but a working example would be better. Everything I look at on the web shows "xxxxx xxxx" examples not $variables. Thanks in advance. Hello Guys, I am trying to insert a value in my table like this image.jpg,image2.jpg,image3.jpg Currently it just runs the image names together Here is my code.. I tried to use explode, but it just adds the word "array" in the table. Please advise $filename2 = $phstring; } $csv = $filename2; $fphoto = explode(',', $csv); // Insert ad details into mysql $query = "INSERT INTO ads (ad_type,ad_title,ad_body,ad_category,ad_photo,ad_member,ad_status,ad_city,ad_state,ad_zip)VALUES('".$ad_type."','".$ad_title."','".$ad_body."','".$catid."','".$fphoto."','".$vname."','".$ad_status."','".$city."','".$state."','".$zip."')"; Apologies... I'm a noob trying to reverse engineer code. I have a script that can retrieve values from a MySQL database (based on a session login that recognizes which user you are) and places those values into the text fields of a form, pre-populating the form. Code: [Select] <?php mysql_connect('localhost', 'db', 'password'); mysql_select_db('users'); $id = mysql_real_escape_string($_SESSION['userid']); $select = "SELECT * FROM user_info WHERE md5(Member_No) = '$id';"; $query = mysql_query($select); if ($row = mysql_fetch_array($query)) { ?> <form> FIRST name: <input type="text" name="First" value="<?php echo stripslashes($row['First']); ?>" LAST name: <input type="text" name="Last" value="<?php echo stripslashes($row['Last']); ?>" > Birthday: <input type="text" name="Birthday" value="<?php echo stripslashes($row['Birthday']); ?>" <input type="submit" value="Submit"> </form> <?php } ?> I want to be able to connect to that same database and update ALL the values (3 in the example above) with the single click of the form button. I think I was told some time ago that it's not possible to update all the values at once? Thanks, ~Wayne Hi all, I have a table... id | Name | Downloads | 01 | tom | 5 02 | thomas | 2 03 | tommy | 15 I need a button in my page whcih on submit would resent the 'downloads' column so all values are set to 0, Is this possible and how if it is? Thanks for any advice Hello there, i'm not sure if this goes to mysql, or this section, but since it's PHP based, i would say here. So, here's the thing, i have full set up table that reads from mysql database and display it as table. Everything is working just fine, even "order" buttons that i made, now i would like to have below the table some counts, for example: My table name "canonkickoff" has column named "Prevoz" which contain only Yes and No answers, i would like to see below the table how much "Yes" answers are inside the column. Also i have other column called "VelicinaMajice", which contain 6 different answers ( XS, S, M, L, XL, XXL ), i would like to see (again, below the table) how much of every has been answered. Like: There a XS = 6 S = 1 M = 2 L = 3 And 32 answered with Yes. Could anyone help me out? Here's the full php table: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <title>CanonKickOff 2012 Tabela.</title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> <link rel="stylesheet" href="table.css" type="text/css"> </head> <body style="margin: 0 0 0 0;"> <? include("passwd.php"); @$start = $_GET["start"]; if($start =='') $start =0; include("lib.php"); $link = mysql_connect($host,$username,$password); if (!$link) { die('Could not connect: ' . mysql_error()); } $db_selected = mysql_select_db($db, $link); if (!$db_selected) { die ("Can't use $db : " . mysql_error()); } //total number of records in the table $orderBy = array('Kompanija', 'id', 'ImePrezime', 'Email', 'Prevoz', 'VelicinaMajice', 'SlazemSe'); $order = 'id'; if (isset($_GET['orderBy']) && in_array($_GET['orderBy'], $orderBy)) { $order = $_GET['orderBy']; } $res = mysql_query("SELECT * from `$table` ORDER BY '.$order"); $res2 = mysql_query("SELECT * from `$table` "); @$rows = mysql_num_rows ($res2); $result = mysql_query("SELECT * from `$table` ORDER BY $order limit $start,40"); if (!$result) { die('Invalid query: ' . mysql_error()); } echo 'Sortiraj Po: <br>'; echo '<a href="?orderBy=id">ID:</a> '; echo '<a href="?orderBy=ImePrezime">Ime i Prezime:</a> '; echo '<a href="?orderBy=Kompanija">Kompanija:</a> '; echo '<a href="?orderBy=email">Email adresi:</a> '; echo '<a href="?orderBy=Prevoz">Prevoz:</a> '; echo '<a href="?orderBy=VelicinaMajice">Velicina majice:</a> '; echo '<a href="?orderBy=SlazemSe">Slazu se:</a> '; echo "<p align=center class = 'menu'> Ocitana tabela: $table </p>"; $cols = mysql_num_fields($result); $records = mysql_num_rows ($result); echo "<table align='center' width='1200' >"; echo "<tr bgcolor='BBCCDD' class='menu'>"; for ($i = 0; $i < $cols;$i++) { echo "<td align='center'>".mysql_field_name($result,$i)."</td>"; } echo "</tr>"; while ($row = mysql_fetch_array($result, MYSQL_NUM)) { echo "<tr bgcolor='F6F6F6' class='normal'>"; foreach ($row as $value) { echo "<td align='center'>".$value ."</td>"; } echo "</tr>"; } $end = $start + $records; echo "<tr align = 'center' bgcolor = 'BBCCDD' class='menu'><td colspan=$cols> $start do $end od ukupno: $rows </td></tr>"; echo "<tr align = 'center' class='mylink'><td colspan=$cols> "; if($start != 0) { $prev = $start - 40; echo "<a href='tabela.php?start=$prev'> Prethodna </a> "; } if($start<$rows-10) { $next = $start + 40; echo "<a href = 'tabela.php?start=$next'>Sledeca</a> "; } echo "</td></tr>"; echo "</table>"; ?> </body> </html> I am pulling 5 addresses and I am wanting to store these 5 addresses in columns in a separate table. On the query string I put LIMIT 5. How can I store the results of each of the 5 loops into columns in a separate table? The columns are A1(for name), A2(for address), A3 (for city), A4 (for state), A5 (for zip), A6 (for phone), A7 (for miles), .... then I also have B1-B7, C1-C7, D1-D7, and E1-E7. I am basically wanting to store up to 5 addresses in an array and then update them into a mysql table. Code: [Select] foreach ($zips as $key => $value) { $result = mysql_query("SELECT State FROM extreme WHERE Zip = '$key' AND Type='store' AND `InStore` <> 'NO' LIMIT 5", $db); $num_rows = mysql_num_rows($result); while($myrow = mysql_fetch_array ($result)) { $Dealer=$myrow['Dealer']; $Address=$myrow['Address']; $City=$myrow['City']; $State=$myrow['State']; $Zip=$myrow['Zip']; $Phone=$myrow['Phone']; $Miles = $value; } } Hi, here's my problem: I am trying to make a simple online buying website and I want to display a table with all the fields for each item. So I got that part down which is to just use mysql_fetch_assoc("SELECT * FROM myTable") and use the html table tags stuff, but now I want to display my images in the table, so here's my code to display my mysql database table in html's table tag along w/ php: <html> <head> <title>My Online buying website project</title> </head> <body> <?php mysql_connect("localhost","root"); mysql_select_db("myTable"); $imagesArray=array("Apple_iPhone3GS.jpg","Apple_iPhone4.jpg","product3.jpg","product4.jpg","product5.jpg"); $result=mysql_query("SELECT Name, Manufacturer, Price, Description, SimSupport FROM myTable"); if(mysql_num_rows($result))//if there is at least one entry in bellProducts, make a table { print "<table border='border'>"; print "<tr> <th>Name</th> <th>Manufacturer</th> <th>Price</th> <th>Description</th> <th>SimSupport</th> </tr>"; //NB: now output each row of records while($row=mysql_fetch_assoc($result)) { extract($row); print "<tr> <td>$Name</td> <td>$Manufacturer</td> <td>$Price</td> <td>$Description</td><td>$SimSupport</td> </tr>"; }//END WHILE }//END IF ?> </table> </body> </html> *So how do I go about adding my images in this table? Hey Everyone, I'm creating a site that will show images uploaded for certain days working on a job site. Kind of a day-to-day photo journal for the customer. On the site, the user gets here, sees 3 large images, and a series of thumbnails if more than 3 images exist for that day (works fine). However, underneath that I want to display a 3-4 column setup of "Archived Dates" that provide a link to the images of the other dates. I have this working correctly, but the results are displayed as follows: Date 1: Date 2: Date 3: etc.... I want them to display like this; Day 1 Day 4 Day 2 Day 5 Day 3 Day 6 and so on..... in a 3 column format. Here is the code I have right now just looping through to display these link results, not the rest of the page. I am trying to do it tableless right now, but if that isn't the right way to go, please let me know. Thanks to anyone in advance, Nick $SQLRowe = "SELECT DISTINCT RoweImgDate from tblRowe WHERE RoweImgDate !='" . $_GET['date'] . "' Order by RoweImgDate DESC Limit 0, 30"; //echo $SQLRowe; $rsSQLRowe = mysql_query($SQLRowe); <span class="rowe">Archived Photos:</span><br/> <div id="archive"> <?php while($row = mysql_fetch_array($rsSQLRowe)){ //echo "<a href='index.php?id="' . $row[RoweImgID] . '"' class='link'>$row[RoweImgDate]</a></br>"; echo "<div id='archivedates'>"; echo "<a href='index.php?date=" . $row[RoweImgDate] . "' class='link'>$row[RoweImgDate]</a>"; echo "</div>"; //echo "<img src='images/$row[RoweImage]'/><br/>"; //echo "<span class='FeatDesc'><p>$row[RoweImgDesc]</p></span><br/>"; } ?> </div> i have a mysql table which contains name like mid mname 101 AAA 102 BBB 103 CCC now i have to print this name in a html table like AAA, BBB, CCC i am getting this by while loop in a variable but when loop changes then value also change so please tell me how i get this only in one variable & print I have the following code that searches my database and displays results in a table: $fields = array("field1", "field2", "field3") $cols = implode (', ', $fields); $result= mysql_query (" SELECT $cols FROM tablename WHERE ................... "); if (!$result) {die('Could not search database: ' . mysql_error());} if($result) { if(mysql_num_rows($result) == 0) { return "Sorry. No records found in the database"; } else { $table = "<table border='1' cellpadding='5' cellspacing='5'>"; while($arr = mysql_fetch_array($result, MYSQL_ASSOC)) { $table .= "\t\t<tr>\n"; foreach ($arr as $val_col) { $table .= "\t\t\t".'<td>'.$val_col.'</td>'."\n"; } $table .= "\t\t</tr>\n"; } $table .= "</table>"; echo $table; } mysql_free_result($result); } As you can see each of the MySQL table fields specified by $fields is displayed in a new column in the html table. I want to change this so that e.g. "field3" is displayed in a new row instead. So, instead of the html table looking like: | "field1-result1" | "field2-result1" | "field3-result1" | | "field1-result2" | "field2-result2" | "field3-result2" | | "field1-result3" | "field2-result3" | "field3-result3" | I want it to look like: | "field1-result1" | "field2-result1" | | "field3-result1" | | | "field1-result2" | "field2-result2" | | "field3-result2" | | | "field1-result3" | "field2-result3" | | "field3-result3" | | I guess this is quite straightforward, but I can't work it out! Pls help! Thanks. Hi, I have a 'pre-release' sign up form, where people put in their email address and name, and it transmits to a MYSQL database. That's working fine. What I want to do is to have a piece of text that reads: (insert pre release amount of signer upperers here) have signed up. Will you? I'm guessing that the amount of rows on the table, would end up being the number. How do I do this? Thanks, Jack I am working on this page concept of pedigree. How can I foreach or create a loop that can get 6 levels of parents, for example name= 1 ; nfather=2; nmohter = 3 and the loop continue to get or consider nfather as a name = 2 and get his parents. this is my table any help plees
CREATE TABLE horsetest01 (
CREATE INDEX horsetest01_index02
hi, i'm new to php. i've got a problem. I've 3 tables and table has following content table 1 id name email address phone execution_date executor_name web_address table 2 id name email address phone execution_date executor_name project_title table 3 id name email address phone execution_date executor_name reviewer I want to export these table to and spreadsheet (.xls) with some criteria a form will assign which data will published at the spreadsheet with these criteria #all data can be exported from three tables #some column can be selected from three tables #some or all data can be selected from individual table i've implement a script for this but it didn't meet my requirements. Can anyone help? here is my script <?php $DB_Server = "localhost"; //your MySQL Server $DB_Username = "root"; //your MySQL User Name $DB_Password = "pass"; //your MySQL Password $DB_DBName = "mydb"; //your MySQL Database Name $search_from_date = $_POST['start_date']; $search_to_date = $_POST['end_date']; $Connect = @mysql_connect($DB_Server, $DB_Username, $DB_Password) or die("Couldn't connect to MySQL:<br>" . mysql_error() . "<br>" . mysql_errno()); $Db = @mysql_select_db($DB_DBName, $Connect) or die("Couldn't select database:<br>" . mysql_error(). "<br>" . mysql_errno()); $now_date = date('m-d-Y H:i'); if(($_POST['typer_of_report'] == 'rrc_report') || ($_POST['typer_of_report'] == 'all_report')) { $DB_TBLName = 'rrc_record'; } if(($_POST['typer_of_report'] == 'erc_report') || ($_POST['typer_of_report'] == 'all_report')) { $DB_TBLName2 = 'erc_record'; } if(($_POST['typer_of_report'] == 'aeec_report') || ($_POST['typer_of_report'] == 'all_report')) { $DB_TBLName3 = 'aeec_record'; } $file_type = "vnd.ms-excel"; $file_ending = "xls"; //} header("Content-Type: application/$file_type"); header("Content-Disposition: attachment; filename=protocol_report.$file_ending"); header("Pragma: no-cache"); header("Expires: 0"); if($DB_TBLName) { $sql = "Select * from ".$DB_TBLName." where execution_date >= '".$search_from_date."' and execution_date <= '".$search_to_date."' order by execution_date desc"; $Use_Title = 1; $title = "Report for $DB_TBLName on $now_date"; $result = @mysql_query($sql,$Connect) or die("Couldn't execute query:<br>" . mysql_error(). "<br>" . mysql_errno()); if ($Use_Title == 1) { echo("$title\n"); } $sep = "\t"; //tabbed character for ($i = 0; $i < mysql_num_fields($result); $i++) { echo mysql_field_name($result,$i) . "\t"; } print("\n"); while($row = mysql_fetch_row($result)) { $schema_insert = ""; for($j=0; $j<mysql_num_fields($result);$j++) { if(!isset($row[$j])) $schema_insert .= "NULL".$sep; elseif ($row[$j] != "") $schema_insert .= "$row[$j]".$sep; else $schema_insert .= "".$sep; } $schema_insert = str_replace($sep."$", "", $schema_insert); $schema_insert = preg_replace("/\r\n|\n\r|\n|\r/", " ", $schema_insert); $schema_insert .= "\t"; print(trim($schema_insert)); print "\n"; } //} echo "\n...\n"; } if($DB_TBLName2) { $sql = "Select * from ".$DB_TBLName2." where execution_date >= '".$search_from_date."' and execution_date <= '".$search_to_date."' order by execution_date desc"; $result = @mysql_query($sql,$Connect) or die("Couldn't execute query:<br>" . mysql_error(). "<br>" . mysql_errno()); $Use_Title = 1; $title = "Report for $DB_TBLName2 on $now_date"; if ($Use_Title == 1) { echo("$title\n"); } $sep = "\t"; //tabbed character for ($i = 0; $i < mysql_num_fields($result); $i++) { echo mysql_field_name($result,$i) . "\t"; } print("\n"); while($row = mysql_fetch_row($result)) { $schema_insert = ""; for($j=0; $j<mysql_num_fields($result);$j++) { if(!isset($row[$j])) $schema_insert .= "NULL".$sep; elseif ($row[$j] != "") $schema_insert .= "$row[$j]".$sep; else $schema_insert .= "".$sep; } $schema_insert = str_replace($sep."$", "", $schema_insert); $schema_insert = preg_replace("/\r\n|\n\r|\n|\r/", " ", $schema_insert); $schema_insert .= "\t"; print(trim($schema_insert)); print "\n"; } echo "\n...\n"; } if($DB_TBLName3) { $sql = "Select * from ".$DB_TBLName3." where execution_date >= '".$search_from_date."' and execution_date <= '".$search_to_date."' order by execution_date desc"; $result = @mysql_query($sql,$Connect) or die("Couldn't execute query:<br>" . mysql_error(). "<br>" . mysql_errno()); $Use_Title = 1; $title = "Report for $DB_TBLName3 on $now_date"; if ($Use_Title == 1) { echo("$title\n"); } $sep = "\t"; //tabbed character for ($i = 0; $i < mysql_num_fields($result); $i++) { echo mysql_field_name($result,$i) . "\t"; } print("\n"); while($row = mysql_fetch_row($result)) { $schema_insert = ""; for($j=0; $j<mysql_num_fields($result);$j++) { if(!isset($row[$j])) $schema_insert .= "NULL".$sep; elseif ($row[$j] != "") $schema_insert .= "$row[$j]".$sep; else $schema_insert .= "".$sep; } $schema_insert = str_replace($sep."$", "", $schema_insert); $schema_insert = preg_replace("/\r\n|\n\r|\n|\r/", " ", $schema_insert); $schema_insert .= "\t"; print(trim($schema_insert)); print "\n"; } } ?> have anyone any idea? i have 8 division (div), i want to display 4 rows in 4 division and the remain 4 rows in the next 4 division here is my code structure for carousel
<div class="nyie-outer"> second row third row
fourth row fifth row sixth row seven throw eighth row
</div><!--/.second four rows here-->
sql code
CREATE TABLE product( php code
<?php how can i echo that result in those rows
Hi, My company has 240+ locations and as such some users (general managers) cover multiple sites. When I run a query to pull user information, when the user has multiple sites to his or her name, its adds the second / third sites to the next columns, rather than wrapping it inside the same table cell. It also works the opposite way, if a piece of data is missing in the database and is blank, its pull the following columns in. Both cases mess up the table and formatting. I'm extremely new to any kind of programming and maybe this isn't the forum for this question but figured I'd give it a chance since I'm stuck. The HTML/PHP code is below: <table id="datatables-column-search-select-inputs" class="table table-striped" style="width:100%"> <thead> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> <th>Actions</th> </tr> </thead> <tbody> <?php //QUERY TO SELECT ALL USERS FROM DATABASE $query = "SELECT * FROM users"; $select_users = mysqli_query($connection,$query);
// SET VARIABLE TO ARRAY FROM QUERY while($row = mysqli_fetch_assoc($select_users)) { $user_id = $row['user_id']; $user_firstname = $row['user_firstname']; $user_lastname = $row['user_lastname']; $username = $row['username']; $user_phone = $row['user_phone']; $user_image = $row['user_image']; $user_title_id = $row['user_title_id']; $user_role_id = $row['user_role_id'];
// POPULATES DATA INTO THE TABLE echo "<tr>"; echo "<td>{$user_id}</td>"; echo "<td>{$user_firstname}</td>"; echo "<td>{$user_lastname}</td>"; echo "<td>{$username}</td>"; echo "<td>{$user_phone}</td>";
//PULL SITE STATUS BASED ON SITE STATUS ID $query = "SELECT * FROM sites WHERE site_manager_id = {$user_id} "; $select_site = mysqli_query($connection, $query); while($row = mysqli_fetch_assoc($select_site)) { $site_name = $row['site_name']; echo "<td>{$site_name}</td>"; } echo "<td>{$user_title_id}</td>"; echo "<td>{$user_role_id}</td>"; echo "<td class='table-action'> <a href='#'><i class='align-middle' data-feather='edit-2'></i></a> <a href='#'><i class='align-middle' data-feather='trash'></i></a> </td>"; //echo "<td><a href='users.php?source=edit_user&p_id={$user_id}'>Edit</a></td>"; echo "</tr>"; } ?>
<tr> <td>ID</td> <td>FirstName</td> <td>LastName</td> <td>Username</td> <td>Phone #</td> <td>Location</td> <td>Title</td> <td>Role</td> <td class="table-action"> <a href="#"><i class="align-middle" data-feather="edit-2"></i></a> <a href="#"><i class="align-middle" data-feather="trash"></i></a> </td> </tr> </tbody> <tfoot> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> </tr> </tfoot> </table>
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