PHP - How Tmp_name Generates?

What is $_FILES['userfile']['tmp_name']??

Is it a two-dimensional array?

Why can't I have a $_FILES['tmp_name']??


Debbie

Just a question concerning the $_FILES['tmp_name']  field. I'm uploading a file which is being moved into two different locations. I run an 'If' check to see if either process fails but as I am running them both at the same time, when a $_FILES['tmp_name'] is moved, can it be used again? Both my functions run fine independetly but when I try run them both it doesn't work  So my question is which may be seem fairly obvious: Once you move the $_FILES['tmp_name'] is it removed from the temp folder it's in? or is it copied?

Thanks!

I have another thread, but it's on a different question.

		// remake image
                if(create_image($fileExt, $_FILES["myfile"]["tmp_name"], $_FILES["myfile"]["tmp_name"], 80) !== FALSE){
		// generate thumbnail 
		if(generatethumbs2('.'.$fileExt, $_FILES["myfile"]["tmp_name"], 120, $_FILES["myfile"]["tmp_name"], 85) == TRUE){
			$aws = new s3;
			$aws = $aws->putObject($newFileName, $_FILES["myfile"]["tmp_name"]);
			image_string($username,$newFileName,$mysqli);
			}
		}

Is my code.   How do I access both the remade image AND the thumbnail? Currently, I can only access the thumbnail. I need to be able to access them concurrently for upload to Amazon s3.      

i have a php form where users can update db. but when the input has a <a href=""></a> input, it generates back slashes on the web.

below is the results after the input.
Code: [Select]
<a href=\'\\\"images/gallery/storyslideshow/ppic-5 (1).jpg\'\\\" rel=\'\\\"lyteshow[featgallery]\'\\\" title=\'\\\"\'\\\">View Slideshow</a><br><br>
i have a this on my updating code Code: [Select]
mysql_real_escape_string($_POST["fulldesc"]);

I have a function that get's a quick single item from a query:

function gimme($sql) { 
global $mysqli; 
global $mytable; 
global $sid; 
$query = "SELECT ".$sql." FROM ".$mytable." WHERE sid = ".$sid; $result = $mysqli->query($query); 
$value = $result->fetch_array(MYSQLI_NUM); 
$$sql = is_array($value) ? $value[0] : ""; 
return $$sql; // this is what I've tried so far 
$result->close(); 
}

It works great as:

echo(gimme("name"));

Then I realized that I could use that as a variable ('$name' in this case) elsewhere. However, I can't figure out how get that new, variable variable 'outside' of the function.  As such,

echo($name);

isn't working outside the function.  Is there a way to return a variable variable?  In other words, is there a way to make a function that creates a variable variable that will available outside of the function?

 

Thanks