PHP - Show Who Is On The Current Page

show list of files uploaded by current session user to the database. I want to show different users when they log in to the website...they can see a list of old files that they have uploaded. can anyone tell me the code/script to this.....please, ty

Quesion: Show each movie in the database on its own page, and give the user links in a "page 1, Page 2, Page 3" - type navigation system. Hint: Use LIMIT to control which movie is on which page. I have provided 3 files: 1st: configure DB, 2nd: insert data, 3rd: my code for the question. I would appreciate the help. I am a noob by the way.

First set up everything for DB:

<?php
//connect to MySQL
$db = mysql_connect('localhost', 'root', '000') or
    die ('Unable to connect. Check your connection parameters.');

//create the main database if it doesn't already exist
$query = 'CREATE DATABASE IF NOT EXISTS moviesite';
mysql_query($query, $db) or die(mysql_error($db));

//make sure our recently created database is the active one
mysql_select_db('moviesite', $db) or die(mysql_error($db));

//create the movie table
$query = 'CREATE TABLE movie (
        movie_id        INTEGER UNSIGNED  NOT NULL AUTO_INCREMENT,
        movie_name      VARCHAR(255)      NOT NULL,
        movie_type      TINYINT           NOT NULL DEFAULT 0,
        movie_year      SMALLINT UNSIGNED NOT NULL DEFAULT 0,
        movie_leadactor INTEGER UNSIGNED  NOT NULL DEFAULT 0,
        movie_director  INTEGER UNSIGNED  NOT NULL DEFAULT 0,

        PRIMARY KEY (movie_id),
        KEY movie_type (movie_type, movie_year)
    )
    ENGINE=MyISAM';
mysql_query($query, $db) or die (mysql_error($db));

//create the movietype table
$query = 'CREATE TABLE movietype (
        movietype_id    TINYINT UNSIGNED NOT NULL AUTO_INCREMENT,
        movietype_label VARCHAR(100)     NOT NULL,
        PRIMARY KEY (movietype_id)
    )
    ENGINE=MyISAM';
mysql_query($query, $db) or die(mysql_error($db));

//create the people table
$query = 'CREATE TABLE people (
        people_id         INTEGER UNSIGNED    NOT NULL AUTO_INCREMENT,
        people_fullname   VARCHAR(255)        NOT NULL,
        people_isactor    TINYINT(1) UNSIGNED NOT NULL DEFAULT 0,
        people_isdirector TINYINT(1) UNSIGNED NOT NULL DEFAULT 0,

        PRIMARY KEY (people_id)
    )
    ENGINE=MyISAM';
mysql_query($query, $db) or die(mysql_error($db));

echo 'Movie database successfully created!';
?>



********************************************************************
***********************************************************************

second file to load info into DB:



<?php
// connect to MySQL
$db = mysql_connect('localhost', 'root', '000') or
    die ('Unable to connect. Check your connection parameters.');

//make sure you're using the correct database
mysql_select_db('moviesite', $db) or die(mysql_error($db));

// insert data into the movie table
$query = 'INSERT INTO movie
        (movie_id, movie_name, movie_type, movie_year, movie_leadactor,
        movie_director)
    VALUES
        (1, "Bruce Almighty", 5, 2003, 1, 2),
        (2, "Office Space", 5, 1999, 5, 6),
        (3, "Grand Canyon", 2, 1991, 4, 3)';
mysql_query($query, $db) or die(mysql_error($db));

// insert data into the movietype table
$query = 'INSERT INTO movietype
        (movietype_id, movietype_label)
    VALUES
        (1,"Sci Fi"),
        (2, "Drama"),
        (3, "Adventure"),
        (4, "War"),
        (5, "Comedy"),
        (6, "Horror"),
        (7, "Action"),
        (8, "Kids")';
mysql_query($query, $db) or die(mysql_error($db));

// insert data into the people table
$query  = 'INSERT INTO people
        (people_id, people_fullname, people_isactor, people_isdirector)
    VALUES
        (1, "Jim Carrey", 1, 0),
        (2, "Tom Shadyac", 0, 1),
        (3, "Lawrence Kasdan", 0, 1),
        (4, "Kevin Kline", 1, 0),
        (5, "Ron Livingston", 1, 0),
        (6, "Mike Judge", 0, 1)';
mysql_query($query, $db) or die(mysql_error($db));

echo 'Data inserted successfully!';
?>



**************************************************************
****************************************************************

MY CODE FOR THE QUESTION:


<?php
$db = mysql_connect('localhost', 'root', '000') or
die ('Unable to connect. Check your connection parameters.');

mysql_select_db('moviesite', $db) or die(mysql_error($db));

//get our starting point for the query from the URL
if (isset($_GET['offset'])) {
   $offset = $_GET['offset'];
} else {
   $offset = 0;
}

//get the movie
$query  = 'SELECT
   movie_name, movie_year
FROM
   movie
ORDER BY
   movie_name
LIMIT ' . $offset . ' , 1';
$result = mysql_query($query, $db) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
?>
<html>
<head>
<title><?php echo $row['movie_name']; ?></title>
</head>
<body>
<table border = "1">
<tr>
<th>Movie Name</th>
<th>Year</th>
</tr><tr>
<td><?php echo $row['movie_name']; ?></td>
<td><?php echo $row['movie_year']; ?></td>
</tr>
</table>
<p>
<a href="page.php?offset=0">Page 1</a>,
<a href="page.php?offset=1">Page 2</a>,
<a href="page.php?offset=2">Page 3</a>
</p>
</body>
</html>

I want to show a cookie of a referral's username on a sign up page. The link is like this, www.mysite.com/signup?ref=johnsmith.

The cookie doesn't show if I go to that url page. But it does show up once I reload the page.  So I'm wondering if it's possible to show the cookie the first time around, instead of reloading the page?

Here is my code.

// This is in the header
$url_ref_name = (!empty($_GET['ref']) ? $_GET['ref'] : null);

if(!empty($url_ref_name)) {

  $number_of_days = 365;
  $date_of_expiry = time() + 60 * 60 * 24 * $number_of_days;
  setcookie( "ref", $url_ref_name, $date_of_expiry,"/");

} else if(empty($url_ref_name)) {
  if(isset($_COOKIE['ref'])) {
    $user_cookie = $_COOKIE['ref'];
  }
} else {}

// This is for the sign up form
if(isset($_COOKIE['ref'])) {
  $user_cookie = $_COOKIE['ref'];
  ?>
  <fieldset>
    <label>Referred By</label>
    <div id="ref-one"><span><?php if(!empty($user_cookie)){echo $user_cookie;} ?></span></div>
    <input type="hidden" name="ref" value="<?php if(!empty($user_cookie)){echo $user_cookie;} ?>" maxlength="20" placeholder="Referrer's username" readonly onfocus="this.removeAttribute('readonly');" />
  </fieldset>
  <?php
}

 

is this possibe with php?

I am trying to create a script that alters the navigation div depending on the page the user is on.  How do I get the current page using PHP?

Hi guys, I'll try to explain this. I'm doing a quoting system for a building contractor and I have a dynamic purchase order created for every quote that's confirmed and it spits out all the materials they will need for each supplier. The layout of the page is exactly what I need emailed to the supplier so they can ship out the materials listed, it's your basic purchase order. I'm going to put a button on the page that sends the email to the supplier but I need to attach the purchase order displayed on the page. Preferably in PDF but it just needs to be an attached file. I know I can have the user use PRINT.... to save it as PDF and then use Outlook to email it but I'd like to automate it. Thanks.

Hi all,

I want to get the current page name as displayed in the URL, not neccesarily the name of the PHP script that is running.

E.g. I have a PHP file 'home.php' that contains iframes that contain other PHP files such as 'frame1.php'. What I want is a script that can be run from frame1.php but that will return 'home.php' as the current page (as displayed in the URL in the browser).

How do I do this?

Thanks!

Why this code dont work :S
<?php
    echo '
    <ul>
        <li'; if ($_SERVER['PHP_SELF'] == "kategorije.php") { echo ' id="current"'; } echo '><a href="kategorije.php"><span>Kategorije</span></a></li>
    </ul>';
?>


Checking if PHP_SELF is "kategorije.php" do not work, why, and what is solution ?

I have an html table that is being populated with links from a specific directory..

I would like the user to be able to click the link and if its a file they will download the file. If its a directory, I woudl like to reload the current page but this time show the contents of the directory.

My main issue is that I have a session variable called 'workingdirectory' that I need to update before I reload the page. I have tried setting it and then calling Location('page.php') but I get the 'cannot change header information' error. I realized I was getting this because I had begun to call HTML code before the PHP was finished. Is there a way to just simply update the session variable, and then make the page reload when the user clicks on a link?

I've looked at loads of other scripts that highlight the page but none of them work on mine . Here's part of my code:


$i =1; 
for ($x=0;$x<$foundnum;$x=$x+$e)
{

 echo " <a href='search.php?search=$search&s=$x'>$i</a> ";


$i++;

Hello, I got this basic code from a website and it is supposed to highlight the current page on the menu, which it does very well. The problem is that I cannot stylize the font, color or size of the type in the current page menu display. No matter what I do, it always stays as the default font. The other buttons on the menu can be stylized but not the current page. Is there a way to do this?

Code: [Select]
## SNIPPET 1 - THE PHP ## // To be saved in the 'includes' directory as "nav_include.php"

<?php
$menu=file_get_contents("includes/menu.html"); // get the navigation list of pages
$base=basename($_SERVER['PHP_SELF']); // get the current page
$menu=preg_replace("|<li><a href=\"".$base."\">(.*)</a></li>|U", "<li id=\"current\">$1</li>", $menu); // add an id of 'active' to the link and id of class to the list item for the current page 
echo $menu; // echo the HTML list with the current page highlighted
?>

## SNIPPET 2 - THE HTML LIST ##  To be saved as menu.html

<ul id="navlist">
  <li><a href="index.php">Home</a></li>
  <li><a href="products.php">Products</a></li>
  <li><a href="services.php">Services</a></li>
  <li><a href="about.php">About Us</a></li>
  <li><a href="contact.php">Contact Us</a></li>
</ul>

## CSS ## for the *.css file

#navlist { margin: 0; padding: 30px 0 20px 10px; float: right; width: 60%; }
#navlist ul, #navlist li { margin: 0; padding: 0; display: inline; list-style-type: none; }
#navlist a:link, #navlist a:visited { float: left; line-height: 14px; font-weight: bold; margin: 0 10px 4px; text-decoration: none; color: #4F4F4F; width: auto; } /* link and visited link styles - the visited state can be styled separately if you wish */
#navlist a:link#current, #navlist a:visited#current, #navlist a:hover { border-bottom: 4px solid #66733f; padding-bottom: 2px; background: transparent; color: #4F4F4F; } /* this line's the style for the current page link */
#navlist a:hover { border-bottom: 4px solid #4F4F4F; color: #4F4F4F; } /* hover state for all the links */

## TO DISPLAY ON THE PAGE ##

<?php include("includes/nav_include.php"); ?>

I have a few PHP files. Currently, if the URL contains page=var, index includes var.php, otherwise it includes home.php.

Apparently, this method makes the site easy to hack through Remote File Inclusion. Also, using PHP5 breaks this method entirely, as no matter what you set page to in the URL, it includes home.php.

What's the best way to do this without using the URL? Give example code if possible. I've used PHP for a while but haven't really gotten past the beginner level. I'd really appreciate any help.

Thanks.

Is there a function to check the name of the current page? Such as login.php or something like that? If not, does anyone have a custom function already created?

I'm doing a cURL post to a server and it returns "true No_Error Data was accepted 10356546 3770 false 0 "


Form --> Method=Post --> submit.php (this is the page that's doing the cURL post and the server returns data that appears on this page).


How do I take this and put it into a string?

I'm feeling a little overwhelmed/burned-out/confused...   

I have a page "article_index.php" that contains a summary of each article plus a link to it, e.g.

Code: [Select]
<a href="<?php echo WEB_ROOT; ?>articles/postage-meters-save-you-money">
When you click on a link, it goes to "article.php" and uses a mod_rewrite to transform the "pretty URL" to regular URL that "article.php" can use to query the correct article from my database.

-----

Here is what I need help with...

When a user is on a given article page, I want to sto

- ReturnToPath
- ArticleID

in the SESSION.

I am drawing a blank on how to get the "ArticleID" when a user is on a give page?!   

Hope you guys follow me?!


Debbie