|
PHP - Include File.php Does Not Show On Server
my code look like this
Code: [Select] <ul id="navigation"> <li> <a href="index.php?page=profile.php">Profile</a></li> <li > <a href="index.php?page=product.php">Products</a></li> <li ><a href="index.php?page=service.php">Service</a></li> <li ><a href="index.php?page=promotion.php">Promotion</a></li> <li ><a href="index.php?page=contact.php">Contact us</a></li> </ul> . . . <div class="content"> <?php if(empty($page) or $page=="index"){ include ("profile.php"); } else { include ($_GET["page"]);} ?> </div> It works well on appserv, but when i uploaded to server ... it's not working.. what to do? Similar TutorialsI'm trying to make a simple website where people register to my website. When the user doesn't fill anything inside the boxes they get a message "Please fill all required fields" on the register.php page On my local host require_once works good. It shows up.
But when i upload the files to my sever the require_once does not show up on the register.php It just refreshes and i dont get the message "Please fill all required fields"
This is the code that works in local host but not in a live server <?php require_once 'messages.php'; ?>
Here is my full code
Register page: <html> <?php require_once 'messages.php'; ?> <br><br> <form action="register-clicked.php" method="POST"> Username:<br> <input type="text" name="usernamebox" placeholder="Enter Username Here"> <br><br> Email:<br> <input type="text" name="emailbox" placeholder="Enter email here"> <br><br> Password:<br> <input type="password" name="passwordbox" placeholder="Enter password here"> <br><br> Confirm Password:<br> <input type="password" name="passwordconfirmbox" placeholder="Re-enter password here"> <br><br> <input type="submit" name="submitbox" value="Press to submit"> <br><br> </form> </html>
Register clicked <?php
session_start();
$data = $_POST;
if( empty($data['usernamebox']) ||
empty($data['emailbox']) ||
empty($data['passwordbox']) ||
empty($data['passwordconfirmbox'])) {
$_SESSION['messages'][] = 'Please fill all required fields';
header('Location: register.php');
exit;
}
if ($data['passwordbox'] !== $data['passwordconfirmbox']) {
$_SESSION['messages'][] = 'Passwords do not match';
header('Location: register.php');
exit;
}
$dsn = 'mysql:dbname=mydatabase;host=localhost';
$dbUser='myuser';
$dbPassword= 'password';
try{
$connection = new PDO($dsn, $dbUser, $dbPassword);
} catch (PDOException $exception){
$_SESSION['messages'][] = 'Connection failed: ' . $exception->getMessage();
header('Location: register.php');
exit;
}
messages.php <?php
session_start();
if (empty($_SESSION['messages'])){
return;
}
$messages = $_SESSION['messages'];
unset($_SESSION['messages']);
?>
<ul>
<?php foreach ($messages as $message): ?>
<li><?php echo $message; ?></li>
<?php endforeach; ?>
</ul>
Edited Wednesday at 12:49 AM by bee65 I have a PHP web system that store in a windows server. In the system, there is a function for user to upload files to another server (Shared server in Unix). When i try to upload a file, it gives warning: Warning: move_uploaded_file(\\unixserver/sharedfolder/upload/test.txt) [function.move-uploaded-file]: failed to open stream: Permission denied in C:\wamp\www\upload\index.php on line 40 For your information, my username has been assigned in xxx's group that has access to read and write on that folder. Besides, i'm able to open,create and delete files on that folder's server manually (samba). The safe mode setting is off. Does anybody has any idea why this thing happen? Hey. I am wanting to move a couple of files from my current server to another. If i am uploading the file this is fine but if it is already on the server then im not sure how to move it. When uploading I can just use ftp_put($conn_id, $destination_file, $myFile, FTP_BINARY); What i need to do is figure out how to get a hold of the file and store it in $myFile then this would work fine. Is this possible? Cheers Anyone know how I can print a file (specifically a PDF) that is stored on the server to the clients computer with a button? I don't want them to be able to view it, just print it. I've done some research and understand that there is no way to print directly without popping up the Windows Print dialog. And that is fine. I just want them to print this file, but not no where it is or be able to type in a URL to access it. Thanks Mike I have a php file that generates a string that I need to use in a .js (javascript)file. Being that php developers sometimes using javascript with php, Im hoping someone can help me with this, cause i dont know any javascript. Code: [Select] //This is the varible inside the .js file var suggestionText = "I need to be able to include my string generated by the php file here..."; I want to include a php file after an succesfully login. Let's suposed that I have a login form on index.php. If the login was ok I want to include a php file with some content instead of the login form. Something like: Code: [Select] <? if($_POST['ok']){ require('content.php'); } else { //login form } ?> It's ok to include in the code the name of the file that you have on server ? From security point of view. Thanks www.desmond-otoole.co.uk/secure/securefunctions.php /bank/admin/index.php what should I do in the index.php file to access securefunctions.php
require("../secure/SecureFunctions.php"); Nothing seems to work
I just get a stupid google chrome page saying Hello, Im trying to pass a variable to a newly created page using GET. Code: [Select] $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Restaurant' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title'>" . $nt[$i] . "</a>" . "<br/>"; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); header.php Code: [Select] <head> <?php $title = $_GET['Title']; ?> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <p>HEADER UPDATED!</p> <p>TESTING - the heading below should read (title goes here in capital letters)</p> <?php <h1>$title</h1> ?> //This is line 12 </body> </html> Im getting the error; Parse error: syntax error, unexpected '<' in D:\Hosting\3753557\html\1pw\mexican.php on line 12 I suspect that I have my syntax muddled in header.php? Is there a better way to pass variables to a newly created page? (fopen). Many thanks for any ideas. Can I include a class file in the same page that I use an instance of the same class with my action attribute with my form. Here's the code Code: [Select] <?php include 'Resources/User.php';?> <html> <head> <title></title> <link href="stylesheets/styles.css" rel="stylesheet" type="text/css"/> </head> <body> <form action = "Resources/testClass.php" method="post" enctype="multipart/form-data"> <label>First Name: </label> <input type="text" name="fname" id="fname" size="25" maxlength="25"/> <label>Last Name: </label> <input type="text" name="lname" id="lname" size="25" maxlength="25"/> <label>Email: </label> <input type="text" name="email" id="email" size="25" maxlength="40"/> <label>Username: </label> <input type="text" name="username" id="username" size="25" maxlength="32"/> <label>Password: </label> <input type="password" name="password" id="password" size="25" maxlength="32"/> <label>Re-enter Password: </label> <input type="password" name="conf_pass" id="conf_pass" size="25" maxlength="32"/> <br /><br /> <input type="submit" name="submit" id="submit" value="Register"/> <input type="reset" name="reset" id="reset" value="Reset"/> </form> </body> </html> Hi all, I'm at a dead-end here. I have a php file that I can query to return an array containing a bunch of data about a job listing. I include and query it by calling it like so within another file on my site. Quick Notes: The original file is in a different directory on my site than the page it's being included in. I have tried returning the array at the end of the script. I can print_r the array on the page I'm including the script on (so the URL path is correct). If I go to this URL directly and print_r on the array, I see the entire array as expected. Also, if I include the file on page 2 like I did above with print_r on the array in the original file, I see the array printed out on page 2. Code: [Select] include 'http://www.example.com/php/job-details.php?job=jobname&city=thecity'; However, if I do not print_r on the array in the original file and just include it on page 2, I cannot do anything with it and the array variable isn't found. Is this a case of variable scope? I'm so frustrated... Here is the code I have in my original file: Code: [Select] <? include('functions.php'); $jobtitlematch = $_GET["job"]; $jobcitymatch = $_GET["city"]; //echo $jobtitlematch; //echo $jobcitymatch; $url = 'http://somesite.com/something'; $xml = simplexml_load_file($url); foreach($xml->job as $job) { $jobtitle = makeURL((string)$job->title); $jobcity = makeURL((string)$job->region); if ($jobtitle == $jobtitlematch && $jobcity == $jobcitymatch) { $jobdata[] = array( Title => ((string)$job->title), URL_Title => makeURL((string)$job->title), Location => ((string)$job->region), URL_Location => makeURL((string)$job->region), Department => ((string)$job->department), URL_Department => makeURL((string)$job->department), Overview => ((string)$job->joboverview), Responsibilities => ((string)$job->responsibilities), Qualifications => ((string)$job->qualifications), Keywords => ((string)$job->metakeywords) ); } return $jobdata; //I have also tried return global $jobdata; } print_r($jobdata); ?> Thanks in advance for any help you can provide... hi php freaks, Is there a way to parse an include file through the php engine and then place the contents into a variable? Code: [Select] $x = include ($myfile); This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=308660.0 Here is a section of php file A include_once(dirname(__FILE__) . '/PhpfileB.php') $VALID_RATING_IDS = $Ratethese Here is all of php file B $Ratethese = "array("1", "2",);" I need the var $VALID_RATING_IDS to = $Ratethese from file B I am trying to include an array from php file B in php file A. Is this possible? How can i accomplish this?
I am using an inclue file on my layout.php page. Hello, I have a simply query that will if a simple two different things: Code: [Select] $cssyn = mysql_query("SELECT `12` FROM `12345` WHERE `abc` = '$_SESSION[number]'"); $cssy = mysql_fetch_row($cssyn); if($cssy[0] == "YES") { echo "Yes"; } else { echo "No"; } The YES or NO result is stipulated earlier on so thats not the problem. But basically before I added the if statement simply would have echoed a table with all the rows etc from another query. However I would like to give the user a choice between echoeing the results into one table or a neater two. I have separated the code for the table and the queries into two separate files but say if I use: file_get_contents then it just prints the HTML and doesnt actually populate it will the queried parts. Nor if I use something like include() then it wont echo anything, which it wouldnt unless called so what I am asking is: Is there a way to get EVERYTHING from the file if the answer is YES or the other file if NO. My catalog uses a template file to list product details. One part of it is responsible for putting these details into nifty little tabs: <?php $template = '{magictabs style=black_rounded, tabwidth=110px}'; $template .= 'Technical Specifications'; $template .= '::'; $template .= '<table colspan="3"><tr><td>'; $template .= $details; $template .= '</td></tr></table>'; $template .= '||||'; ?> I don't want it to output $details, I want it to output a separate script instead. How do I include this separate file as a variable? I want this: <?php include('specs.php'); ?> to replace the $details variable. Hi peeps iv been trying to figure out this but i cant see it....its probably obvious!!! in the $header variable the include files dont show... any ideas here the php code <? session_start(); ?> <link href="/styles/main.css" rel="stylesheet" type="text/css" /> <? //get data $button = $_GET['submit']; $search = $_GET['search']; $search = strtoupper($search); $header = ("<table width='100%' border='0' height='80' cellpadding='4' bgcolor='#000000' > <tr> <td width='39%' height='76' valign='top'><p><span class='stigrosheadfont'><strong>www.StigRos.com</strong></span><strong><span class='headnocrap'><br /> ( No Crap - Just Quality Movie & Music Downloads )</span></span><br /> <a href='http://mysite' class='headerlinkcolor'>Home</a> | <a href='register.php' class='headerlinkcolor'>Register</a> | <a href='#' class='headerlinkcolor'>Contact us</a></strong></td> <td width='47%' valign='bottom'><p class='normalblacktext'>You are currently logged in, <b>$_SESSION[username]</b></td> <td width='14%' valign='top'><div align='center'> <div align='center'><span class='headfont'><strong>Disclaimer</strong></span></div> <div align='center'> <? include_once 'countertest.php'; ?> <? date('F d, Y'); ?></div></td> </tr> </table>"); $s = $_GET['s']; if (!$s) $s = 0; $e = 10; // Just change to how many results you want per page $next = $s + $e; $prev = $s - $e; if (strlen($search)<=2) echo "Must be greater then 3 chars $user"; else { echo $header; echo " <form action='search.php' method='GET'> <center> <br> <input name='search' type='text' class='blacktext' size='50'> <input name='submit' type='submit' class='blacktext' value='Search Film'></font></p> </center> </form> "; //connect to db include('db.php'); //explode out search term $search_exploded = explode(" ",$search); foreach($search_exploded as $search_each) { //construct query $x++; if ($x==1) $construct .= "keyword LIKE '%$search_each%'"; else $construct .= " OR keyword LIKE '%$search_each%'"; } //echo outconstruct $constructx = "SELECT * FROM movies WHERE $construct"; $construct = "SELECT * FROM movies WHERE $construct LIMIT $s,$e"; $run = mysql_query($constructx); $foundnum = mysql_num_rows($run); $run_two = mysql_query("$construct"); if ($foundnum==0) echo "No results found for <b>$search</b>"; else { echo "<table bgcolor='#000000' width='80%' height='1px' align='center'><br /></table><table bgcolor='#000000' width='80%' height='10px' align='center'><tr><td><div align='right'><font color='#E6E6E6'>Showing 1-10 of <b>$foundnum</b> results found for <b>$search.</b></font></div></td></tr></table><p>"; echo "<br>"; while ($runrows = mysql_fetch_assoc($run_two)) { //get data $title = $runrows['film']; $desc = $runrows['description']; $url = $runrows['dl_link']; $imdb = $runrows['imdb']; $pic = $runrows['pic']; $film = $runrows['film']; echo "<table width='900' border='1' align='center'> <tr> <td width='229' align='center'><IMG SRC='$pic'></td> <td class='blacktext' width='655' align='center'><b>$film</b><br /><br />$desc<br /><br /><a href='$url' target='_blank'><b>Download Now</b></a> | <a href='$imdb' target='_blank'><b>IMDb</b></a></td> </tr> </table> "; } ?> <table width='100%'> <tr> <td> <div align="center"> <?php if (!$s<=0) echo "<a href='search.php?search=$search&s=$prev'>Prev</a>"; $i =1; for ($x=0;$x<$foundnum;$x=$x+$e) { echo " <a href='search.php?search=$search&s=$x'>$i</a> "; $i++; } if ($s<$foundnum-$e) echo "<a href='search.php?search=$search&s=$next'>Next</a>"; } } ?> </div> </td> </tr> </table> How do I include a file that is located two directories above the file that I want to include the file into? My absolute hosting path is /home/content/52/8840652/html if this would be of any use. I'm not quite sure about the PHP include functions. Any help would be greatly appreciated, Thanks! In my code include_once "http://myserver.com/someFile.php" does not work but include_once "/someFile.php" works I NEED to be able to full URL. Anyone know what PHP setting I need to change to get this working for me? Thanks |
|||||||