PHP - Not Showing A Tag If The Value Is Empty ??
Hello:
I have this bit of code in the works (which does not work): Code: [Select] <?php if ( $mySubHeader; != "" ) { echo " <h2> <?php echo $mySubHeader; ?> </h2> "; } What I am trying to do is to show the H2 tag only if it has a value from the database. Otherwise, I do not want to show it. What is the correct way to do this? Thanks. Similar TutorialsMan, I'm having a rough week with questions--if you're following at home. Basically matching a Coach's first and last name to another table, which if matched will yield information about that coach's team. Code: [Select] // or get user by username $current_user = wp_get_current_user(); $current_first = $current_user->user_firstname; $current_last = $current_user->user_lastname; $current_id = $current_user->ID; echo '<div class="contact_form">'; echo $current_first . ' ' . $current_last .' :: '; $query = "SELECT * FROM schools WHERE coachFirst='".$current_first."' AND coachLast='".$current_last."'"; $result = mysql_query ($query); if(!$result) { echo 'There is not a match for your name.'; } else { while($school= mysql_fetch_array($result)) { echo $school['school'] . ' ' . $school['id']; include(ABSPATH ."wp-content/plugins/my-team/form.php"); } echo '</div>'; echo '<div class="roster">'; include(ABSPATH ."wp-content/plugins/my-team/roster.php"); echo '</div>'; } What I am looking for is that if any field in a database is empty, the form comes back and puts in the word "empty" into the web page, but not the database. I got this right now, it shows the first part fine, but the second part it doesn't show the "Empty" comment... I don't understand why... as far as I can tell the code is fine... Code: [Select] <?php //Nonconformity, Disposition, Comments and Comments & Additional Details echo '<div id="box3">'; if (!empty($row['Nonconformity']) || !empty($row['Disposition']) || !empty($row['Comments']) || !empty($row['CommentsAdditional_Details'])) { echo '<div id="non"><span class="b">Nonconformity: </span><br />' . $row['Nonconformity'] . '</div>'; echo '<div id="dis"><span class="b">Disposition: </span><br />' . $row['Disposition'] . '</div>'; echo '<div id="comm"><span class="b">Comments: </span><br />' . $row['Comments'] . '</div>'; echo '<div id="comma"><span class="b">Comments and/or Additional Details: </span><br />' . $row['CommentsAdditional_Details'] . '</div>';} else if (empty($row['Nonconformity']) || empty($row['Disposition']) || empty($row['Comments']) || empty($row['CommentsAdditional_Details'])) { echo '<div id="non"><span class="b">Nonconformity: </span><br />Empty</div>'; echo '<div id="dis"><span class="b">Disposition: <br /></span>Empty</div>'; echo '<div id="comm"><span class="b">Comments: <br /></span>Empty</div>'; echo '<div id="comma"><span class="b">Comments and/or Additional Details: </span><br />Empty</div>';} echo '</div>'; ?> I am pretty new to PHP and am trying to create a simple (so I assumed) page to takes data from one html page(works fine) and updates a MYSQL Database. I am getting no error message, but the connect string down to the end of the body section is showing up as plain text in my browser window. I do not know how to correct this. I have tried using two different types of connect strings and have verified my names from the HTML page are the same as listed within the php page. Suggestions on what I need to look for to correct would be great. I have looked online, but so far all I am getting is how to connect, or how to create a comment, so I thought I would try here. Thank you for any assistance I may get!! - Amy - Code: [Select] <body><font color="006600"> <div style="background-color:#f9f9dd;"> <fieldset> <h1>Asset Entry Results</h1> <?php // create short variable names $tag=$_POST['tag']; $serial=$_POST['serial']; $category=$_POST['category']; $status=$_POST['status']; $branch=$_POST['branch']; $comments=$_POST['comments']; if (!$tag || !$serial || !$category || !$status || !$branch) { echo "You have not entered all the required details.<br />" ."Please go back and try again."; exit; } if (!get_magic_quotes_gpc()) { $tag = addslashes($tag); $serial = addslashes($serial); $category = addslashes($category); $status = addslashes($status); $branch = addslashes($branch); $comments = addslashes($comments); } //@ $db = new mysqli('localhost', 'id', 'pw', 'inventory'); $db = DBI->connect("dbi:mysql:inventory:localhost","id","pw") or die("couldnt connect to database"); $query = "insert into assets values ('".$serial."', '".$tag."', '".$branch."', '".$status."', '".$category."', '".$comments."')"; $result = $db->query($query); if ($result) { echo $db->affected_rows." asset inserted into Inventory."; } else { echo "An error has occurred. The item was not added."; } $db->close(); ?> </fieldset> </div> </body> Hi everyone! I'm new to PHP and needed from you. I have the following code that I can't figure out why it doesn't work on the last elseif. If I comment out the first elseif (line 19-39), it does go through the last elseif. Can someone here help? Thank you!!! The content of Instructors.txt as follow: ID#|fName lName|email_address|course1:course2:course3 ID#|fName lName|email_address|course1:course3 ID#|fName lName|email_address|course1:course2:course4 ID#|fName lName|email_address|course2:course3:course5:course6 <?php //If we submitted the form if(empty($_POST['Location'])) { $FH = fopen("Locations.txt", "rb"); print "<FORM name=\"myForm\" action=\"test4.php\" method=\"POST\">\n"; print "<P> Location:\n"; print "<select name=\"Location\">\n"; print "<option value=\"\">-- Select --\n"; while (!feof($FH)){ $line_of_text = fgets($FH); $line = explode('|', $line_of_text); print "<option value=$line[1]>$line[1]"; } fclose($FH); print "<input type=\"submit\" value=\" Next 1 \">\n"; exit(); } elseif(empty($_POST['Instructor'])) { $location = ($_POST['Location']); $FH = fopen("Instructors.txt", "rb"); print "<FORM name=\"myForm\" action=\"test4.php\" method=\"POST\">\n"; print "<P> Location: <input type=text value=$location>\n"; print "<P> Instructor: \n"; print "<select name=\"Instructor\">\n"; print "<option value=\"\">-- Select --\n"; while (!feof($FH)){ $line_of_text = fgets($FH); $line = explode('|', $line_of_text); if ($line[0] == "$location") { print "<option value=\"$line[1]\">$line[1]\n"; } } fclose($FH); print "<input type=\"submit\" value=\" Next 2 \">\n"; exit(); } elseif(empty($_POST['Course'])) { $location = ($_POST['Location']); $instructor = ($_POST['Instructor']); $FH = fopen("Instructors.txt", "rb"); print "<FORM name=\"myForm\" action=\"test4.php\" method=\"POST\">\n"; print "<P> Location: <input type=text value=$location>\n"; print "<P> Instructor: <input type=text value=\"$instructor\">\n"; print "<P> Course: \n"; print "<select name=\"Course\">\n"; print "<option value=\"\">-- Select --\n"; while (!feof($FH)){ $line_of_text = fgets($FH); $line = explode('|', $line_of_text); if ($line[1] == "Bert Vandenber") { $course = explode(':', $line[3]); for ($i=0; $i<count($course); $i++) { print "<option value=\"$course[$i]\">$course[$i]\n"; } } } fclose($FH); print "<input type=\"submit\" value=\" Next 3 \">\n"; exit(); } ?> I don't get the logic behind the construct. I can't ever see myself using this because it doesn't make sense when I code it. I understand isset($var) and why I should use it sometimes to avoid undefined messages. But with empty() it makes more sense to always test the variable directly because if the value is NULL, 0, '', or false then it evaluates as TRUE. Is there any situation where empty should be used always? i have made query and i want replace with no data N/A i have tryed with swich but no luck Code: [Select] if (($row['name']) = empty) { echo('n/a'); } I have search page in the form of search.php?q=query, as the php script calls for other files and a long process. When visiting search.php directly, the value of q is indeed null, and it makes a long loop and use lots of cpu. How to kill the script or redirect to the main page when visiting search.php?
This is a file called t12.php <?php include 'db.php'; error_reporting(E_ALL | E_WARNING | E_NOTICE); ini_set('display_errors', TRUE); if (session_status() == PHP_SESSION_NONE) { session_start(); } if(!isset($_SESSION['login'])) { echo (" <script>location.href='../clogin/'</script>"); die(); if(isset($_POST['transfer'])) { $username = $_SESSION['login']; $transAmount = $_POST['transAmount']; $totalTrans = $transAmount + 30; $sql = "SELECT * FROM customer WHERE username = ?"; $stmt = $connection->prepare($sql); $stmt->bind_param('s', $username); $stmt->execute(); $result = $stmt->get_result(); $count = $result->num_rows; if($count == 1) { while ($row = $result->fetch_assoc()) { if($totalTrans > $row['transLimit']) { echo 'you have exceeded limit'; exit(); } else { echo"limit passed"; } }//while loop }//count }//submit }//session ?>
<form action="t12.php" method="post"> <input type="number" name="transAmount" placeholder="Enter Amount"> </input><br> <button type="submit" name="transfer">Proceed</button></form>
Hi, please help me
for school i need to make an assignment and i need to make an script with regular expressions to get an image from a site named asaphshop.nl. but the only thing happens is that it's searching in the localhost what should be on the site.
this is my code:
<?php header('Content-Type: text/html; charset=utf-8'); $url = "http://www.asaphshop.nl/epages/asaphnl.sf/nl_NL/?ObjectPath=/Shops/asaphnl/Products/80203122"; $htmlcode = file_get_contents($url); $pattern = '#class="noscript">.*(<img.*>).*</div>#isU'; preg_match_all($pattern, $htmlcode, $matches); //print_r ($matches); $image = ($matches[0]); print_r ($image); ?>in the attached file is the thing i get Attached Files Naamloos.png 21.8KB 0 downloads Hi all I have a pice of code that I want to only show the image if it's empty: Code: [Select] <?php if(!empty($node->field_img['und'][0]['filename'])); { ?> <li><img src="http://mysite.co.uk/sites/default/files/brand-images/<?php print $node->field_img['und'][0]['filename']; ?>" style="max-width:270px; text-align:center;" /></li> <?php } ?> However, it shows an image placeholder (Red cross) even when it's empty? Many thanks for your help Pete Im trying to echo certain code if the array returned is empty. I know for certain the array is empty and it works when its not empty. here is my code <?php while ($club = mysql_fetch_assoc($qclubs)) { if (empty($club)) {echo "<option value='None'>None</option>";} else{ echo" <option value='{$club['groupID']}'>{$club['group']}</option>"; }}?> Can someone please point out the error of my ways? I am using a script to take postcodes and give distances between them and list all postcodes within a radius. Where it should list all the postcodes in the radius it provides and empty array - any clues?? the table is 'geodb' relevant fields are postcode place latitude longitude and the code is Code: [Select] if(isset($_GET['Search'])) { $postcode = strtoupper($_GET['postcode']); $radius = $_GET['radius']; echo $postcode . '<br>'; echo $radius . '<br>'; $conn = mysql_connect(/*credentials removed*/) or die('db connect error: ' . mysql_error()); mysql_select_db('db379121', $conn) or die('could not select database'); $sqlstring = "SELECT * FROM geodb WHERE postcode = '".$postcode."'"; $result = mysql_query($sqlstring); $row = mysql_fetch_assoc($result); ++++++++++++++++++++++++++++++++++++++++++ var_dump($row); // seeing whqat is in the array - returns one result (array(9) { ["id"]=> string(1) "1" ["countrycode"]=> string(2) "GB" ["postcode"]=> string(4) "AB10" ["place"]=> string(8) "Aberdeen" ["postaltown"]=> string(8) "Aberdeen" ["region1"]=> string(8) "Scotland" ["region2"]=> string(13) "Aberdeen City" ["latitude"]=> string(12) "57.135813090" ["longitude"]=> string(12) "-2.121224030" })// ++++++++++++++++++++++++++++++++++++++++++ $lng = $row["longitude"] / 180 * M_PI; $lat = $row["latitude"] / 180 * M_PI; echo $lat . '<br>'; echo $lng . '<br>'; ++++++++++++++++++++++++++++++++++++++++++ echo to check that there is a value here - i get lat 0.99720805922458 lng -0.037022343495923 ++++++++++++++++++++++++++++++++++++++++++ mysql_free_result($result);} $sqlstring2 = "SELECT DISTINCT geodb.postcode,geodb.place,(6367.41*SQRT(2*(1-cos(RADIANS(geodb.latitude))*cos(".$lat.")*(sin(RADIANS(geodb.longitude))*sin(".$lng.")+cos(RADIANS(geodb.longitude))*cos(".$lng."))-sin(RADIANS(geodb.latitude))* sin(".$lat.")))) AS Distance FROM geodb AS geodb WHERE (6367.41*SQRT(2*(1-cos(RADIANS(geodb.latitude))*cos(".$lat.")*(sin(RADIANS(geodb.longitude))*sin(".$lng.")+cos(RADIANS(geodb.longitude))*cos(".$lng."))-sin(RADIANS(geodb.latitude))*sin(".$lat."))) <= '".$distance."') ORDER BY Distance"; $result = mysql_query($sqlstring2) or die('query failed: ' . mysql_error()); $str = "<table width=\"300\" border=\"0\" cellspacing=\"0\" cellpadding=\"0\">"; $str .= "<tr>"; $str .= "<th>postcode</th>"; $str .= "<th>city</th>"; $str .= "<th>distance</th>"; $str .= "</tr>"; while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $str .= "<tr><td>".$row["postcode"]."</td><td>".$row["place"]."</td><td>".round($row['Distance'])."km</td></tr>"; } $str .= "</table>"; ++++++++++++++++++++++++++++++++++++++++++ var_dump($row["place"]); // this produces null ++++++++++++++++++++++++++++++++++++++++++ mysql_free_result($result); mysql_close($conn); echo $str; how would I make it so that the option 'Remove (make blank)' would post an empty value? Quote <form action="/new/newrotastaffprocess.php" Method="POST"> <select name="username"> <?php $result = mysql_query("SELECT * FROM members") or die(mysql_error()); while($row = mysql_fetch_array( $result )) { echo "<option value=\"" . htmlentities($row["username"]) . "\">" . htmlentities($row["username"]) . "</option>"; } echo "<option value='empty'>Remove (make blank)</option>"; ?> </select> </div> <div style="position:absolute; top:397px; left:570px;"> <form action="/new/newrotastaffprocess.php" METHOD="POST"> <input type = "hidden" value="<?php echo $wkbeg;?>" name="wkbeg"> <input type = "hidden" value="<?php echo $staffno;?>" name="staffno"> <input type = "submit" value="New!"> </form> Hello everybody,
I am new to php, I have a question for you guys.
why I've got an empty page.
<?php I'm not sure what i have done wrong here... all it says is "Query was empty" <?php SESSION_START(); ?> //some html <?php if($_SESSION['email']){ $mysql = "SELECT id,firstname FROM users WHERE 'id'='".$_SESSION['email']."'"; $res = mysql_query($sql) or die(mysql_error()); if(mysql_num_rows($res) == 0){ session_destroy(); echo"Please <a href=\"/index.html\">Login</a> or <a href=\"/register.php\">Join Us.</a>"; }else{ $row = mysql_fetch_assoc($res); echo "welcome back, <a href=\"./index.php?act=profile&id=".$row['id']."\">".$row['firstname']."</a>\n"; } }else { echo"Please <a href=\"/index.html\">Login</a> or <a href=\"/register.php\">Join Us.</a>"; } ?> I have this line in my code $result2 = mysqli_query($link, 'Select * from categories where cat_loc ='.$nav['id']); how do I say "if $result2 is empty or false"? (basically if it didn't find any cat_loc = to $nav['id']) to echo '</li>'; Hi all, I have this: Code: [Select] <?php session_start(); include('login/functions.php'); $username = $_SESSION['username']; $check = mysql_query("SELECT email FROM user_profile WHERE username = '$username'"); $a = mysql_fetch_field($check); if(empty($a)) { header('Location: complete.php'); } ?> However if the field is empty, ie no email address for user then nothing happens? Am going about this the right way? Cheers I have a number of fields to display on a page, from a mysql query, some fields are empty, some not. depends on what they choose on the original form. I am trying to display on the form results on a page formatted using the below: If the mysql field is empty, display an unchecked check box next to the result. If there is data in the field display a check box ticked. What can i do to achieve this, can you point me in the right direction? Results page using echo: </TD><TD>Options: <input type='checkbox' CHECKED>". $row[17]. " </TD> = is not empty field </TD><TD>Options: <input type='checkbox' UNCHECKED>". $row[17]. " </TD> = emtpy ,mysql field </TD><TD>Options: <input type='checkbox' CHECKED>". $row[18]. " </TD> = not empty mysql field from query </TD><TD>Options: <input type='checkbox' UNCHECKED>". $row[18]. " </TD> = Empty field in mysql I am trying to show Rows 1 to 16 to display normally, rows 17 to 30 use the above logic. There are about 30 fields to display like this, the others are required fields and are displayed no matter what. I introduce if condition when a string is empty as Code: [Select] if (empty($string)) { How I can add the condition for a certain value too. If empty or equal to "word1". I was just wondering what the best way to identify an empty set is. At the moment I have this but this doesn't seem to work so I was wondering what the best way is. Thanks. $article_rs = mysql_query($article_sql, $mysql_conn); if (!$article_rs) { $_SESSION['no_articles'] = "<p>Sorry but there are no articles that match your search.</p>"; } |