PHP - Mysql Update And Fetch Not Working As Planned
Hello, I have this simple php form that updates the table, and also shows what the information in it is.
Here it is: <strong>Update multiple rows in mysql</strong><br> <?php $host="localhost"; // Host name $username=""; // Mysql username $password=""; // Mysql password $db_name="test"; // Database name $tbl_name="test_mysql"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); // Count table rows $count=mysql_num_rows($result); ?> <table width="500" border="0" cellspacing="1" cellpadding="0"> <form name="form1" method="post" action=""> <tr> <td> <table width="500" border="0" cellspacing="1" cellpadding="0"> <tr> <td align="center"><strong>Id</strong></td> <td align="center"><strong>Month</strong> <strong>Date</strong> </td> <td align="center"><strong>Lastname</strong></td> <td align="center"><strong>Email</strong></td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td align="center"><?php $id[]=$rows['id']; ?><?php echo $rows['id']; ?></td> <td align="center"><input name="month[]" MAXLENGTH="3" size="3" type="text" id="month" value="<?php echo $rows['month']; ?>">- <input name="date[]" MAXLENGTH="2" size="2" type="text" id="date" value="<?php echo $rows['date']; ?>"> </td> <td align="center"><input name="lastname[]" type="text" id="lastname" value="<?php echo $rows['lastname']; ?>"></td> <td align="center"><input name="email[]" type="text" id="email" value="<?php echo $rows['email']; ?>"></td> </tr> <?php } ?> <tr> <td colspan="4" align="center"><input type="submit" name="Submit" value="Submit"></td> </tr> </table> </td> </tr> </form> </table> <?php // Check if button name "Submit" is active, do this if (isset($_POST['Submit'])) { for($i=0;$i<$count;$i++){ $month = $_POST['month']; $date = $_POST['date']; $lastname = $_POST['lastname']; $email = $_POST['email']; $name = $month."<br>".$date; $sql1="UPDATE $tbl_name SET name='$name[$i]', month='$month[$i]', date='$date[$i]', lastname='$lastname[$i]', email='$email[$i]' WHERE id='$id[$i]'"; $result1=mysql_query($sql1); } } if($result1){ header("location:update2.php"); } ?> <?php $result = mysql_query("SELECT * FROM test_mysql") or die(mysql_error()); echo "<table border='1'>"; echo "<tr> <th>Name</th> <th>Age</th> </tr>"; // keeps getting the next row until there are no more to get while($row = mysql_fetch_array( $result )) { // Print out the contents of each row into a table echo "<tr><td>"; echo $row['name']; echo "</td><td>"; echo $row['lastname']; echo "</td></tr>"; } echo "</table>"; ?> What it does is this, it gets the row from the database, echos it and I am able to edit it and then save. The thing is, it works with the updating but im trying to combine 2 variables into 1 and update that one also. Im trying to combine month and date textboxes into one variable in the database that is name. It for some reason updates the column name to A instead of what I had in the 2 fields month and date. Here is where I combine both fields into one. $name = $month."<br>".$date; And here is where $month and $date is set. $month = $_POST['month']; $date = $_POST['date']; Here is a picture. Similar TutorialsWhen I echo the POST, it echoes the correct value. The MySQL portion seems to just ignore it all together. I've tried changing the dropdown option to just a text field, same thing occurred. I have text fields right above this particular one that update just fine with the SAME exactly scripting. if POST, update query, done. Works. This one for some reason will not. MySQL portion: if ($_POST['bUpdate']){ mysql_query("UPDATE `Patients` SET `b` = '$_POST[bUpdate]' WHERE `id` = '".$_GET['id']."'"); } echo $_POST['bUpdate']; Form Portion: Code: [Select] <tr onmouseover="color(this, '#baecff');" onmouseout="uncolor(this);"> <td width="310" colspan="2" align="center"><span class="fontoptions">Postcard Status </span><br /> <? if ($data['b'] == 1){ echo '<select name="bUpdate"><option value="1" selected>Yes</option><option value="0">No</option></select>'; } else { echo '<select name="bUpdate"><option value="1">Yes</option><option value="0" selected>No</option></select>'; } ?> </td> </tr> hi - i'm trying to update mysql databse but not working... any ideas??? Code: [Select] [php] <?php ob_start(); require_once('../xconfig.php'); if(isset ($_GET['quote'])&& $_GET['quote']!=""){ $quote_id=$_GET['quote']; mysql_select_db($database, $makeconnection); $sql_find_quote = "SELECT * FROM tbl_quote WHERE quote_id = $quote_id"; $find_quote = mysql_query($sql_find_quote, $makeconnection) or die(mysql_error()); $row = mysql_fetch_assoc($find_quote); $totalRows = mysql_num_rows($find_quote); $quote_author = $_POST['quote_author']; $quote_desc = $_POST['quote_desc']; if (isset($_POST['submitted'])&&($_POST['submitted'] == "yes")) { $register_query = "SELECT quote_desc FROM tbl_quote WHERE quote_desc='$quote_desc'"; mysql_select_db($database, $makeconnection); $register_check=mysql_query($register_query, $makeconnection); $register_found_quote = mysql_num_rows($register_check); if($register_found_quote>1){ header ("Location: quote_modify.php?error=quoteexists"e=$quote_id"); }else{ $sql_modify = "UPDATE tbl_quote SET quote_desc = '$quote_desc' quote_author = '$quote_author' WHERE quote_id = '$quote_id'"; } mysql_select_db($database, $makeconnection); $Result1 = mysql_query($sql_modify, $makeconnection) or die(mysql_error()); header ("Location: quote.php"); } } ob_flush(); ?> [/php] here's my HTML form Code: [Select] <form action="" method="post" enctype="multipart/form-data" name="form1" id="form1"> <p> <input name="quote_author" type="text" class="active-field" id="quote_author" value="<? echo $row['quote_author'];?>"/> <br /> <input name="quote_desc" type="text" class="active-field" id="quote_desc" value="<? echo $row['quote_desc'];?>" /> <br /> <input name="submitted" type="hidden" id="submitted" value="yes" /> <input name="submit" type="submit" id="submit" class="submit-button" value="modiy"/> <br /> </p> </form> view_leader.php
Hi everyone, I have been trying to get this code working but no matter what I try it will not work, I am trying to allow a user to update their personal details when they login to my website. I have created a form and submit button, the code is shwn below: <?php echo $_SESSION['myusername']; ?> <br><br> <form action="updated.php" method="post"> Firstname: <input type="text" name="firstname" /><br><br> Surname : <input type="text" name="surname" /><br><br> Date Birth: <input type="text" name="dob" /><br><br> Total Wins: <input type="text" name="wins" /> Total Loses: <input type="text" name="loses" /><br><br> Email Add: <input type="text" name="email" /><br><br> Country : <input type="text" name="born" /><br><br> Other Info: <input type="text" name="other" /><br><br> <input type="submit" name="Submit" value="Update" align="right"></td> </form> The updated.php file <?php mysql_connect ("localhost","root","") or die("Cannot connect to Database"); mysql_select_db ("test"); $sql=mysql_query("UPDATE memberdetails SET firstname='{$_POST['firstname']}', surname='{$_POST['surname']}', dob='{$_POST['dob']}', totalwins='{$_POST['wins']}', totalloses='{$_POST['loses']}', email='{$_POST['email']}', country='{$_POST['born']}', info='{$_POST['other']} WHERE username=$_SESSION['myusername']); if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "Details Updated"; ?> This is the error i recieve: Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in C:\wamp\www\website\updated.php on line 45 Line 45 is $sql=mysql_query line If anybody can help it will be very much appreciated! Hi guys need some help.I created a simple Update Customer Details page Where you Enter the Customer ID ,The Customer Details Get Displayed inside a Form and you make changes within the Form.But the update query I wrote is not working as it should be.It Executes the Query ,when I hardcode the Customer ID inside the Update query but fails when I need to Enter the Customer ID directly from the form using post.In This Code I tried to Update only the Customer's Firstname.Thanks Here Is The Code Code: [Select] <?php $db=mysql_connect("localhost","root","") or die('Unable to Connect To Database.Please check the Database Parameters'); mysql_select_db('ecommerce') or die(mysql_error()); if(isset($_POST['enterid'])) { $_POST['inputid']; } $query="SELECT * FROM customer WHERE Cid='$_POST[inputid]'"; $result=mysql_query($query) or die(mysql_error()); $row=mysql_fetch_array($result); $new_cid=$row['Cid']; $new_firstname=$row['Cfname']; $new_lastname=$row['Clname']; $new_email=$row['Email_id']; $new_address=$row['Address']; $new_pincode=$row['Pincode']; $new_payment=$row['Mode_of_payment']; $new_city=$row['City']; $new_state=$row['State']; $new_phone=$row['Phone']; $html1=<<<HTML1 <form action="updatecustomer.php" method="post"> <p class="inputidentifier">Please Enter The Customer's ID</p><input type="text" style="width:375px;height:40px;font-size:30px;" name="inputid" size="20"><br><br> <input type="submit" name="enterid" style="height:40px"> HTML1; print($new_cid); if(isset($_POST['update'])) { $query1="UPDATE customer SET Cfname='$_POST[firstname]' WHERE Cid='$_POST[inputid]'"; mysql_query($query1) or die(mysql_error()); if(mysql_affected_rows()==1) print("Query sucessful"); else print("Something went wrong"); } ?> <html> <head> <style type="text/css"> .inputtext {width:300px; height:40px;font-size:30px;} .inputidentifier{font-size:25px;font-family:"Arial"} .h1type{font-family:"Arial"} </style> <title>Test</title> </head> <body> <?php print($html1); ?> <h1 align="center" class="h1type">Update Customer Details</h1> <form action="updatecustomer.php" method="POST"> <table align="center" cellspacing="10" cellpadding="10" border="0" width="60%"> <tr> <td align="right" class="inputidentifier">First Name</td> <td align="left"><input type="text" class="inputtext" name="firstname" placeholder="eg:Kevin" value="<?php print($new_firstname) ?>"></td> </tr> <tr> <td align="right" class="inputidentifier">Last Name</td> <td><input type="text" class="inputtext" name="lastname" placeholder="eg:Aloysius" value="<?php print($new_lastname) ?>"></td> </tr> <tr> <td align="right" class="inputidentifier">E-mail</td> <td align="left"><input type="email" style="width:500" class="inputtext" name="email" placeholder="yourname@email.com" value="<?php print($new_email) ?>"> </tr> <tr> <td align="right" class="inputidentifier">Phone Number</td> <td align="left"><input type="text" class="inputtext" name="phone" placeholder="How Do We Call You?" value="<?php print($new_phone) ?>"></td> </tr> <tr> <td align="right" class="inputidentifier">Address</td> <td><textarea style="width:500;height:150" wrap="virtual" class="inputtext" name="address" placeholder="Where is your Crib?"><?php print($new_address) ?></textarea></td> </tr> <tr> <td align="right" class="inputidentifier">State</td> <td align="left"><input type="text" style="width:500" class="inputtext" name="state" placeholder="State" value="<?php print($new_state) ?>"> </tr> <tr> <td align="right" class="inputidentifier">City</td> <td align="left"><input type="text" class="inputtext" name="city" placeholder="City" value="<?php print($new_city) ?>"> </tr> <tr> <td align="right" class="inputidentifier">Pin Code</td> <td><input type="text" class="inputtext" name="pincode" placeholder="Mulund 400080" maxlength="6" value="<?php print($new_pincode) ?>"></td> </tr> <tr> <td align="right" class="inputidentifier">How do Pay for your Bling?</td> <td align="left"> <input type="text" class="inputtext" name="payment" value="<?php print($new_payment)?>"> </tr> <tr> <td></td> <td><input type="submit" name="update" value="Update!" style="width:100px;height:60px;"></td> </tr> </table> </form> </body> </html> Hi there, I'm having a problem with updating a record with an UPDATE mysql query and then following that query with a SELECT query to get those values just updated. This is what I'm trying to do...I'd like a member to be able to complete a recommended task and upon doing so, go to a page in their back office where they can check off that task as "Completed". This completed task would be recorded in their member record in our database so that when they return to this list, it will remain as "Completed". I'm providing the member with a submit button that will call the same page and then update depending on which task is clicked as complete. Here is my code: Code: [Select] $memberid = $_SESSION['member']; // Check if form has been submitted if(isset($_POST['task_done']) && $_POST['task_submit'] == 'submitted') { $taskvalue = $_POST['task_value']; $query = "UPDATE membertable SET $taskvalue = 'done' WHERE id = $memberid"; $result = mysqli_query($dbc, $query); } $query ="SELECT task1, task2, task3 FROM membertable WHERE id = $memberid"; $result = mysqli_query($dbc, $query); $row = mysqli_fetch_array($result, MYSQLI_ASSOC); $_SESSION['task1'] = $row['task1']; $_SESSION['task2'] = $row['task2']; $_SESSION['task3'] = $row['task3']; ?> <h4>Task List</h4> <table> <form action="" method="post"> <tr> <td>Task 1</td> <td><?php if($_SESSION['task1'] == 'done') {echo '<div>Completed</div>';} else{ echo '<input type="submit" name="task_done" value="Mark As Completed" />';} ?></td> </tr> <input type="hidden" name="task_value" value="task1" /> <input type="hidden" name="task_submit" value="submitted" /> </form> <form action="" method="post"> <tr> <td>Task 1</td> <td><?php if($_SESSION['task1'] == 'done') {echo '<div>Completed</div>';} else{ echo '<input type="submit" name="task_done" value="Mark As Completed" />';} ?></td> </tr> <input type="hidden" name="task_value" value="task2" /> <input type="hidden" name="task_submit" value="submitted" /> </form> <form action="" method="post"> <tr> <td>Task 1</td> <td><?php if($_SESSION['task1'] == 'done') {echo '<div>Completed</div>';} else{ echo '<input type="submit" name="task_done" value="Mark As Completed" />';} ?></td> </tr> <input type="hidden" name="task_value" value="task3" /> <input type="hidden" name="task_submit" value="submitted" /> </form> </table> The problem that I am having is that the database is not updated with the value "done" but after submission, the screen displays "Completed" instead of "Mark As Completed". So the value is being picked up as "done", but that is why I have the SELECT after the UPDATES, so that there is always a current value for whether a task is done or not. Then I refresh and the screen returns the button to Mark As Complete. Also, when I try marking all three tasks as, sometimes all three are updated, sometimes only one or two and again, I leave the page or refresh and the "Marked As Completed" buttons come back. Bizarre. If anyone can tell me where my logic is going wrong, I would appreciate it.
Hello. I activate the Payment Gateway Platform (by Redsys in Spain), and it works fine asking you for card number and it goes through correctly and says PAYMENT OK, but the notification.PHP FILE does not work. Could my server (SSL) configuration be the problem? or is it the CODE? Any help about this, please, would be highly appreciated. Thank you. Part of the Nofication.php code is: __________________________________________________________________________________
<?php $handle = fopen("_redsys.log", "a");
require_once("include/dbcommon.php"); $miObj = new RedsysAPI;
$version = postvalue("Ds_SignatureVersion");
// $version = "HMAC_SHA256_V1";
$claveModuloAdmin = 'sq7HjrUOBfKmC576ILgskD5srU870gJ7';
if ($signatureCalculada === $signatureRecibida && $res["Ds_AuthorisationCode"]!="++++++" && !isset($res["Ds_ErrorCode"]) {
$sql = "SELECT Espacio FROM Espacios WHERE Id_Espacio=" . $values["Id_Espacio"];
// echo '<img src="data:image/jpeg;base64,'.$imageData.'">';
_______________________________________________________________________________________________ I have been pulling my hair out for the lasy 3 hours i am trying to update a MySql table but i cant get it too work, i just keep getting MySql error #1064 - You have an error in your SQL syntax; if i just update 1 field it works fine but if i try to update more than 1 field it dosent work, Help Please! <?php $root = $_SERVER['DOCUMENT_ROOT']; require("$root/include/mysqldb.php"); require("$root/include/incpost.php"); $con = mysql_connect("$dbhost","$dbuser","$dbpass"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("$dbame", $con); mysql_query("UPDATE Reg_Profile_p SET build='$build' col='$col' size='$size' WHERE uin = '$uinco'"); ?> Hi, I'm wondering if theres a shortcut to a potential problem I have. I'm currently running a query on my website to pull all the fields from a table in my database, for the data to be used on various parts of the page. Usually I would do something as follows Code: [Select] $result = mysql_query("SELECT * FROM table WHERE page='1'"); while ($row=mysql_fetch_array($result)) { $title = $row["title"]; $data = $row["data"]; } And so on and so forth. I would then call the appropriate data by echoing $data for example. However, my table contains a lot more rows than i've mentioned (Around 25 or so). Rather than assigning each to a variable and having a large portion of variable assignments at the top of the page, is there any clever way of putting all of these values inside of an array. So for example, I could call $array_data["title"] or $array_data["data"]?? So it keeps the same key, but puts it inside of an array that I don't have to loop through each time? Hope that makes sense! Thanks, Edd Hi, I am trying to fetch all data from database. but any data show twice. like this: Ali Ali 30 30 Osman Osman 20 20 Omer Omer 40 40 Salim Salim 10 10 Suzan Suzan 25 25 $mem_qry = "SELECT * FROM tbl_name"; $res = mysql_query($mem_qry); function mysql_fetch_all($res) { $return = array(); while($row=mysql_fetch_array($res)) { $return[] = $row; } return $return; } $all = mysql_fetch_all($res); foreach($all as $k=>$v) { foreach($v as $k2=>$v2){ echo $v2.'<br />'; } } Im not sure where to post this but since it includes php il post it here instead of in the mysql forum. ok so, i have a table and i get the values using while($row = mysql_fetch_array($result)){ and then echo them in rows. that works fine but i need to add a class to the last row of my table. I would need somehow to fetch the last row of the array and make it echo something different. Any help is appreciated Thank you <?php require("connection.php"); $query = 'SELECT * FROM job_post WHERE id_jobpost= :Id'; $start = $bdd->prepare($query); $start->execute(array(':Id' => $_GET['id_jobpost'])); $result = $start->fetch(); foreach ($result as $results) { $jobtitle = $result['jobtitle']; $id_jobpost = $result['id_jobpost']; $description = $result['description']; } ?> https://prnt.sc/uk3913 Whats wrong with this code Hi guys, Im having problem on how to achieved this one.. I would like to get the all event of this month (April ) Starting todays date.. Code: (php) [Select] $now = gmdate("Y-m-d", mktime(gmdate("H")+8, gmdate("i"), gmdate("s"), gmdate("m"), gmdate("d")+8, gmdate("Y"))); $week = gmdate("Y-m-d", mktime(gmdate("H")+8, gmdate("i"), gmdate("s"), gmdate("m"), gmdate("d")+30, gmdate("Y"))); if ($result = mysql_query("SELECT * FROM fiesta WHERE sta_date BETWEEN '$now' AND '$week' ORDER BY sta_date LIMIT 10")){ if (mysql_num_rows($result)) { $return = ''; while ($row = mysql_fetch_array( $result )) { $date = date("D",strtotime($row["sta_date"])); $return .= "<a href='sta.php' style='font-size:11px;' title='" . $row['fiesta_brgy'] . " " . $row['fiesta_town'] . "'>" . $row['fiesta_brgy'] . " " . $row['fiesta_town'] . "</a> ($date), "; } echo rtrim($return, ', '); } } The result of this query will include the events on May.. How can i display only the event on this month(April)? starting todays date. Thank you Hello i want to fetch the content from my MySQL db for one table and show it on a page, i'm using this code: Code: [Select] <?php include("inc/connect.php"); ?> <?php $result = $_REQUEST['result']; ?> Code: [Select] <?php $query = mysql_query("select * from listtest order by id asc"); while($result = mysql_fetch_array($query)) { ?> <tr> <td><?php echo $result['id']; ?></td> <td><?php echo $result['code']; ?></td> <td align="center"><a href="edit.php?id=<?php echo $result['id']; ?>">View</a></td> <td align="center"> </td> </tr> <?php } ?> it's throwing me this error: Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in 32qgtf.php on line 30 What am i doing wrong ? /Edit: line 29/30 is the mysql query / fetch. Can anyone post a generic update function to update mysql table. The manual approach: update $tablename set $column1='a', $column2='b' where $id=$value; I am trying to create a simple calendar where a user can add/remove their availability date. This part works so far. Now what I am having trouble with is highlighting the already selected dates that are fetched from a MySQL database.
Here's my code. // HTML <div id="datetimepicker1"></div> // Jquery/Ajax <script> $(document).ready(function () { $('#datetimepicker1').datepicker({ dateFormat: "yy-mm-dd", multidate: true, onSelect: function () { var getDate = $("#datetimepicker1").val(); $.ajax({ type: "POST", //or GET. Whichever floats your boat. url: "snippets/adapter-set.php", data: { date: getDate }, success: function(data) { // alert(data); }, error: function() { alert("Error."); } }); } }); }); </script> // PHP // adapter-set.php $post_date = $_POST['date']; $find_query = $db->prepare("SELECT user_id FROM user_dates WHERE date_available = :date_available"); $find_query->bindParam(':date_available', $post_date); $find_query->execute(); $result_find = $find_query->fetchAll(PDO::FETCH_ASSOC); if(count($result_find) > 0) { foreach($result_find as $row) { $user_id = $row['user_id']; } $delete_query = $db->prepare("DELETE FROM user_dates WHERE user_id = :user_id"); $delete_query->bindParam(':user_id', $user_id); $delete_query->execute(); $result_delete = $delete_query->execute(); if($result_delete == false) { echo 'delete false'; } else { echo 'delete success'; } } else { $insert_query = $db->prepare("INSERT INTO user_dates(date_available) VALUES(:date_available)"); $insert_query->bindParam(':date_available', $post_date); $result_insert = $insert_query->execute(); if($result_insert == false) { echo 'insert false'; } else { echo 'insert success'; } }
The above code works fine. It inserts and deletes a date row in MySQL database table based on a click. Now what I would like to do is to highlight all the "available" dates that are already inserted into the database; so that the user knows which dates he has already selected. This is my code for that. But it doesn't seem to be working. No errors. It's just not highlighting the inserted dates. Can you tell me what I'm doing wrong? // JQUERY <script> $(document).ready(function() { $.post('snippets/adapter-fetch.php', {}, function(data){ $("#datetimepicker1").datepicker({ datesEnabled : data.datesEnabled }); }, 'json'); }); </script> // PHP // adapter-fetch.php $global_user_id = 5; $find_query = $db->prepare("SELECT date_available FROM user_dates WHERE user_id = :user_id"); $find_query->bindParam(':user_id', $global_user_id); $find_query->execute(); $result_find = $find_query->fetchAll(PDO::FETCH_ASSOC); if(count($result_find) > 0) { foreach($result_find as $row) { $date_available = $row['date_available']; echo $date_available; } } else { echo 'not dates available'; }
Hi,
Does anyone have a clue how I might solve this little issue:
I have a MySQL query, for example:
<?php // Make a MySQL Connection $query = "SELECT * FROM staff"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result)){ if($row['clock'] < time()) { echo "<b>"$row['name']. " - ". $row['age']"</b>"; echo "<br />"; } else { echo $row['name']. " - ". $row['age']; echo "<br />"; } } ?>Taking data from the following table setup: name - age - clock Timmy Mellowman - 23 - 09:00:00 Sandy Smith - 21 - 12:00:00 Bobby Wallace - 15 - 14:00:00 What im trying to achieve is compare the current time to the time in the clock column and depending if it's earlier or later, change the styling of the results. The above code does appear to work somewhat however it seems to change the styling of all results in one go, rather than individually when it passes the time in the cell, which is what im looking for. Thanks //my controller <?php namespace App\Http\Controllers; use Illuminate\Http\Request; use DB; class homeController extends Controller { public function index() { $employee = DB::table('employee')->orderBy('id','desc')->get(); $department = DB::table('department')->orderBy('id','desc')->get(); return view('index', ['employee' => $employee , 'department' => $department]); } } //my routes Route::get('index','homeController@index'); //my view using blade temmplating engine @foreach($employee as $emp) <div class="employee"> <b>{{ $emp->name }} </b> <a href="employee/{{ $emp->id }}"> <p class="intro">{{ substr($emp->intro ,0, 50) }}...</p> </a> </div> @endforeach @foreach($department as $dep) <div class="department"> <b>{{ $dep->name }} </b> <a href="department/{{ $dep->id }}"> <p class="desc">{{ substr($dep->description ,0, 100) }}...</p> </a> </div> @endforeach I want to fetch using ajax, how can i do it, teach/help me Hello, So I have a weird error where if I fetch more than a certain number of rows from a mysql table, it triggers a 500 Internal Server Error. I am using Apache Web Server (through GoDaddy) and the offending code is below: Code: [Select] set_time_limit(0); $this->Connect(); $Output = array(); $search = "SELECT * FROM <table> WHERE user_id = ?"; if($Statement = $this->MySQLi->prepare($search)){ $Statement->bind_param("i", $UserId); $Statement->execute(); $Statement->bind_result(<result variables>); $count = 0; while($Statement->fetch() && $count++ < 70){ ChromePhp::log(<result variables>); } $Statement->close(); } $this->Disconnect(); ChromePhp::log is a way of dumping things to the Javascript Console in your browser from within a PHP script just as a heads-up. So when I set the stop number as 70, everything is fine. If I try to fetch more than that it triggers a 500 internal server error on Apache Server port 443. I have looked through the error logs and can't figure out the cause but this is almost certainly a server configuration issue? I'd appreciate any feedback, especially anyone familiar with GoDaddy's hosting services Thanks Warning: mysql_fetch_array() expects parameter 1 to be resource, string given... im tryin to put class inside code if $dayNumber and $dan are equal i tried few ways but all are complicated since i have to call some functions this end up as "simple" solution but i dont know where did i get wrong PS that should be possible? Code: [Select] else { echo "<td width='40'"; $moj_id = $_SESSION['id']; $query_event = mysql_query("SELECT * FROM events WHERE id_user='$moj_id' GROUP BY 'event_date'") ; $test = mysql_fetch_array('$query_event'); $date_event = $test['event_date']; sscanf($date_event, "%d-%d-%d", $godina, $mjesec, $dan); if ($dan==$dayNumber && $mjesec==$month && godina==$year) { echo " class='radni'"; } echo"><a href='day_info.php?dan=",$dayNumber,"&mj=",$month,"&gd=",$year,"'>" . $dayNumber . " </a></td>\n"; $dayNumber++; } |