PHP - Date() If Statements

Hi,

I have a job listing website which displays the closing date of applications using:

$expired_date

(This displays a date such as 31st December 2019)

I am trying to show a countdown/number of days left until the closing date.

I have put this together, but I can't get it to show the number of days.

                    <?php 
                    $expired_date = get_post_meta( $post->ID, '_job_expires', true );
                    $hide_expiration = get_post_meta( $post->ID, '_hide_expiration', true );
                    if(empty($hide_expiration )) {
                        if(!empty($expired_date)) { ?>
                                <span><?php echo date_i18n( get_option( 'date_format' ), strtotime( get_post_meta( $post->ID, '_job_expires', true ) ) ) ?></span>
                    
                    <?php
                                        $datetime1 = new DateTime($expired_date);
                                        $datetime2 = date('d');
                                        $interval = $datetime1->diff($datetime2);
                                        echo $interval->d;

                     ?>
                        <?php }
                    } 
                    ?>

Can anyone help me with what I have wrong?

Many thanks

Hi,

I am trying to convert a String date into numeric date using PHP function's, but haven't found such function.
Had a look at date(), strtotime(), getdate();

e.g. Apr 1 2011  ->    04-01-2011

Could someone please shed some light on this?

Regards,
Abhishek

Hi Guys..

How can I change a date on the fly ?
Everything is UTC on my server.

How can I change a date to something else on the fly?

Ie:

$timezone = "cet";
$datetime = "2011-09-04 19:53:00";

echo $datetime($timezone);

So I can give it a datetime and have it echo the datetime as if it were in the other timezone?

Thanks
Graham

Hi there,

I have a string '12/04/1990', that's in the format dd/mm/yyyy.

I'm attempting to convert that string to a Date, and then insert that date into a MySQL DATE field.

The problem is, every time I try to do so, I keep getting values like this in the database: 1970-01-01.


Any ideas?


Much appreciated.

Hi guys, I'm putting together a small event system where I want the user to add his own date and time into a textfield (I'll probably make this a series of drop-downs/a date picker later).
This is then stored as a timestamp - "0000-00-00 00:00:00" which displays fine until I try to echo it out as a UK date in this format - jS F Y, which just gives today's date but not the inputted date.



Here's the code I have right now:

Code: [Select]
$result = mysql_query("SELECT * FROM stuff.events ORDER BY eventdate ASC");

echo "<br />";
echo mysql_result($result, $i, 'eventvenue');
echo ", ";

$dt = new DateTime($eventdate);

echo $dt->format("jS F Y");


In my mysql table eventdate is set up as follows:
 
field - eventdate
type - timestamp
length/values - blank
default - current_timestamp
collation - blank
attributes - on update CURRENT_TIMESTAMP
null - blank
auto_increment - blank


Any help as to why this could be happening would be much appreciated, thanks.

Hi, Currently I am making a module for joomla. every article has an publish date, if the article was published in 7 days ago, it will displayed as "article in last week", My idea is to use today's date - publish date, if the result is greater than 7 and smaller than 14, the article will be displayed as "article in last week.
Any one know how to write this code?
Here is what I have got, but not working.

<?php
$todays_date = date("Y-m-d"); 

$result = mysql_query("select * from jos_content where $test between $todays_date-14 and $todays_date-7");  
while($row = mysql_fetch_array($result))
  {
echo "$todays_date - $row[title]";
}
?>

i have a table that shows payments made but  want to the payments only showing from a set date(06/12/14) and before this date i dont want to show   this is my sql that doesnt seem to work and is showing dates before the specified date. .

"SELECT * FROM payments2014, signup2014, editprop2014 WHERE signup2014.userid = payments2014.payment_userid AND editprop2014.prop_id = signup2014.prop_id AND signup2014.userid !='page1' AND signup2014.userid !='page6' AND signup2014.userid !='page4' AND payments2014.payment_transaction_status !='none' AND payments2014.payment_transaction_status !='CANCELLEDa' AND payments2014.payment_type !='deposit' AND payments2014.payment_paid_timestamp NOT LIKE '%2012%' AND payments2014.payment_paid_timestamp NOT LIKE '%2011%' AND payments2014.payment_paid_timestamp >= '06/12/14' ORDER BY payments2014.payment_id DESC"

i have some other parts in the statment but this one that should be filtering is 

host_payments2014.payment_paid_timestamp >= '06/12/14' 

thanks in advance

I'm getting this Time Zone error.
Perhaps it's a compatibility issue with PHP 5.3. Looked all over for an answer without finding one.
Here is the error message


Warning: date() [function.date]: It is not safe to rely on the system's timezone settings.
You are *required* to use the date.timezone setting or the date_default_timezone_set() function.
In case you used any of those methods and you are still getting this warning,
you most likely misspelled the timezone identifier. We selected 'America/New_York' for 'EST/-5.0/no DST'
instead in /blocked.php on line 41
12/02/12

Here is the code. Line 41 is near the bottom, the one with the d,m,y.  Perhaps the echo date (d/m/y") needs to be changed. Appreciate any help!

Code: [Select]
   <table border="3" width="16%" align="center" cellspacing="0" bgcolor="#FF6600" bordercolor="red" bordercolordark="red" bordercolorlight="red">
                            <tr>
                                    <td width="176">

                                            <p align="center"><?php // shows IP Number on Page
            echo $ip; ?> </p>

                                    </td>
                            </tr>
                    </table>
                    <p align="center"><?php // Show the user agent
        echo 'Your user agent is: <b>'.$_SERVER['HTTP_USER_AGENT'].'</b><br />';?></p>
                    [b]<h1 align="center"><?php echo date("d/m/y");?></h1>[/b]
            </td>
    </tr>
</table
[,code]

How to write 2 "if" statements together?

if($userResult==$myResult) and ($userResult<0)
{

Hey Guys,

I am creating an array and I have a need to put a if statement inside it. Is this even possible?

Here is where I am at so far, its just not working.


 function load_permissions($gid)
    {
     $data = array();
     $this->db->select('`groups`.`name` AS `permission_name`, `permissions`.``');
$query = $this->db->get('`groups`,`permissions`');
if ($query->num_rows() > 0){
foreach ($query->result_array() as $row){
  $data[] = array(
  "name" => $row['permission_name'],
  "read" => if($row['level'] >= 1)
   { 
    img("img/true.gif")
   } else { 
    img("img/false.gif")
   },
 
  );
  }
 }
 
 $query->free_result();
return $data;



Thanks,
Peter

Anything wrong with this because I got a parse error ONLY after adding to create this.

<?php
                            $visible = array('Yes', 'No');
                            foreach($visible as $visible):
                            $visible2 = array('yes', 'no');
                            foreach($visible2 as $visible2):
                        ?>      

Hello, I am learning PDO SQL statements, I have mananged to connect using PDO:


Code: [Select]
try
{
$this->link = $dbh = new PDO('mysql:host='.$this->dbhost.';dbname='.$this->dbname.'', $this->dbuser, $this->dbpass);
}
catch (PDOException $e)
{
echo 'Connection failed: ' . $e->getMessage();
}


I am not getting any error, so I guess that is a good start. I then tried the PDO SQL statement out. My old mySQL query is commented out in the


Code: [Select]
if (isset($_SESSION['id']) && isset($_SESSION['password']))
{
$_SESSION['id'] = ( isset( $_SESSION['id'] ) ) ? $_SESSION['id'] : FALSE;
$_SESSION['password'] = ( isset( $_SESSION['password'] ) ) ? $_SESSION['password'] : FALSE;


//$logged = mysql_query("SELECT * FROM `db_members` WHERE `id`='".$_SESSION['id']."' AND `password` = '".$_SESSION['password']."'");
//$logged = mysql_fetch_array( $logged );

// the new pdo statement
$ff = $dbh->prepare('SELECT * FROM db_members WHERE id = '.$_SESSION['id'].' AND password = '.$_SESSION['password'].'');

$ff->execute();
$logged = $ff->fetchAll();

echo $logged['username'];
}

I am trying to assign the session to logged variable. So all I am asking is go into db_members and check the id and password that is the same as session id and password and collect the rows data such as username.

My login script and everything works perfectly, even session id and password is valid when echo'd but I cannot assign it to the logged variable like my old sql statements.


Code: [Select]
$logged = mysql_query("SELECT * FROM `db_members` WHERE `id`='".$_SESSION['id']."' AND `password` = '".$_SESSION['password']."'");
$logged = mysql_fetch_array( $logged );

I used other PDO statements and it works perfectly but I just don't understand why this is not working.... can I please get some help if you have any solution to this?

Hi Guys,
Newbie trying to understand PHP conditionals.
In the below Code: [Select]
[[*id]] is a global variable which equates to my current page id so it could have the value of 1 for example. I tested it using echo and the correct values pass to it in the cms I'm using. What I cant achieve is for the conditionals below to work correctly so perhaps you can see a syntax error or show me away of doing the same using an array or something perhaps? THANKS

Code: [Select]
<?php
$id='[[*id]]'

if ($id=="1" || $id=="2")
  echo "we are in 1 or 2";
elseif ($id=="3" || $id=="4")
  echo "we are in 3 or 4";
else
  echo "not in 1 to 4";
?>

The below is constantly loading the password page no matter what is enter in the password input on the form (on another page). I have checked the $login variable by echoing it and it is carrying the value from the field.


<?php
$off="yes";
$login=$_POST['login'];
if($off=="yes" && (!isset($_SESSION['login']) || $_SESSION['login']!="pass")){
    if($login=="" || $_SESSION['login']!="pass"){
    header('Location: ./index2.html');
    exit();
    }
    elseif(!isset($_SESSION['login'])){
    session_start();
    $_SESSION['login']=$login;
    header('Location: ./index.php');
    exit();
    }
}
elseif($off=="no" || $_SESSION['login']=="pass"){
content goes here.
}
?>