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PHP - Converting An Image Rotate.php To Making A Pic To Pic Link Structure
Is there a way to use php to incorporate a folder of pictures as a clickable slideshow.
For instance.... using a pic as a button... to go to the next pic.... except in quantities of 100... without having to manually write the code for each page...? In HTML: Code: [Select] <a href="index3.html"><img src="2.jpg" /></a> <a href="index4.html"><img src="3.jpg" /></a> <a href="index5.html"><img src="4.jpg" /></a> <a href="index6.html"><img src="5.jpg" /></a> <a href="index7.html"><img src="6.jpg" /></a> <a href="index8.html"><img src="7.jpg" /></a> <a href="index9.html"><img src="8.jpg" /></a> Something like using a basic rotating script activated on mouse click? How do i convert this into a button without making 100 pages? Code: [Select] <img src="/path/to/images/ rotate.php?img=my_static_image.jpg" /> I have come up with the rotate.php file as following: Code: [Select] <?php $folder = '/oprah/is/sofuckingfat.com/images/'; $extList = array(); $extList['gif'] = 'image/gif'; $extList['jpg'] = 'image/jpeg'; $extList['jpeg'] = 'image/jpeg'; $extList['png'] = 'image/png'; /* I believe that most of the following can be omitted once it hits the timer / countdown script */ $img = null; if (substr($folder,-1) != '/') { $folder = $folder.'/'; } if (isset($_GET['img'])) { $imageInfo = pathinfo($_GET['img']); if ( isset( $extList[ strtolower( $imageInfo['extension'] ) ] ) && file_exists( $folder.$imageInfo['basename'] ) ) { $img = $folder.$imageInfo['basename']; } } else { $fileList = array(); $handle = opendir($folder); while ( false !== ( $file = readdir($handle) ) ) { $file_info = pathinfo($file); if ( isset( $extList[ strtolower( $file_info['extension'] ) ] ) ) { $fileList[] = $file; } } closedir($handle); if (count($fileList) > 0) { $imageNumber = time() % count($fileList); $img = $folder.$fileList[$imageNumber]; } } if ($img!=null) { $imageInfo = pathinfo($img); $contentType = 'Content-type: '.$extList[ $imageInfo['extension'] ]; header ($contentType); readfile($img); } else { if ( function_exists('imagecreate') ) { header ("Content-type: image/png"); $im = @imagecreate (100, 100) or die ("Cannot initialize new GD image stream"); $background_color = imagecolorallocate ($im, 255, 255, 255); $text_color = imagecolorallocate ($im, 0,0,0); imagestring ($im, 2, 5, 5, "IMAGE ERROR", $text_color); imagepng ($im); imagedestroy($im); } } ?> Would be more or less converting the rotate.php script into the base for the link structure. I assume the timing element in this script would be omitted with a replacement or nothing. I can't figure out what will be the quickest way to go about making the href follow the folder contents. I just want a basic click on the pic to go to the next one until it ends. Thoughts anyone? Similar TutorialsI have the following code, works rotates the image. But it seems to lose its transparency and add color when rotated to say 45. How can I avoid this? // File and rotation $filename = 'placeholder.png'; $degrees = 45; // Content type header('Content-type: image/png'); // Load $source = imagecreatefrompng($filename); // Rotate $rotate = imagerotate($source, $degrees, 0); // Output imagepng($rotate); ?> Hi, I want to create a function that reads the exif orientation data of an image and rotates it as required - needs to run before before the resize function here, I'm using GD library if that is relevant:
function resize_gd($sourceFileName, $folder, $destinationFileName, $newWidth, $newHeight, $keepProportion)
{
$newWidth = (int)$newWidth;
$newHeight = (int)$newHeight;
if (!$this->gdInfo >= 1 || !$this->checkGdFileType($sourceFileName)) {
return false;
}
$img = &$this->getImg($sourceFileName);
if ($this->hasError()) {
return false;
}
$srcWidth = ImageSX($img);
$srcHeight = ImageSY($img);
if ( $keepProportion && ($newWidth != 0 && $srcWidth<$newWidth) && ($newHeight!=0 && $srcHeight<$newHeight) ) {
if ($sourceFileName != $folder . $destinationFileName) {
@copy($sourceFileName, $folder . $destinationFileName);
}
return true;
}
if ($keepProportion == true) {
if ($newWidth != 0 && $newHeight != 0) {
$ratioWidth = $srcWidth/$newWidth;
$ratioHeight = $srcHeight/$newHeight;
if ($ratioWidth < $ratioHeight) {
$destWidth = $srcWidth/$ratioHeight;
$destHeight = $newHeight;
} else {
$destWidth = $newWidth;
$destHeight = $srcHeight/$ratioWidth;
}
} else {
if ($newWidth != 0) {
$ratioWidth = $srcWidth/$newWidth;
$destWidth = $newWidth;
$destHeight = $srcHeight/$ratioWidth;
} else if ($newHeight != 0) {
$ratioHeight = $srcHeight/$newHeight;
$destHeight = $newHeight;
$destWidth = $srcWidth/$ratioHeight;
} else {
$destWidth = $srcWidth;
$destHeight = $srcHeight;
}
}
} else {
$destWidth = $newWidth;
$destHeight = $newHeight;
}
$destWidth = round($destWidth);
$destHeight = round($destHeight);
if ($destWidth < 1) $destWidth = 1;
if ($destHeight < 1) $destHeight = 1;
$destImage = &$this->getImageCreate($destWidth, $destHeight);
Edited June 7, 2019 by mcfc4heatons
When having different levels of directories, using relative paths will not work anymore, for example: controller - authentication File 1: include('../../model/header.php') model File 2: header.php view File 3. style.css The header.php file includes the css file with a relative path, but the problem is it includes it as follows: ../view/style.css When now the header.php file gets included into File 1 in the folder "authentication", then the css file will not be accessible anymore, for it to be accessible you would have to go two directories up. In this sense my question is, what would be the proper path structure for a folder structure with multiple levels? Should I rather use absolute paths, I am not so prone of absolute path. What if the folders changes a bit, or the domain changes, or the location changes? This topic has been moved to Other. http://www.phpfreaks.com/forums/index.php?topic=316401.0 Hi guys! new to forum and to coding. I have poured over the forums and lots of places for an answer. I am not sure if this is due to my thus far limited understanding or, nto a specific enough question was asked. Basically it was suggested to me to make a link on a site from this: Search our Catalog: It was asked that I tie a link to that text and make it sort of a button so that when clicked, it takes someone to our catalog. The site is built with Drupal 6 and uses Danland theme and and a WYSIWYG. WHen I open the gear to edit this section I see: "<P align=right><a href="https://catalog.ncpl.lib.oh.us/polaris/logon.aspx"> Access Library Account</a> - <a href="https://catalog.ncpl.lib.oh.us/polaris/patronaccount/selfregister.aspx?"> Get a Card</a> - <a href="http://catalog.ncpl.lib.oh.us/polaris/search/default.aspx">Search Catalog</a></P> <!-- // Start of Search form --> <script language="javascript"> String.prototype.trim = function() { return this.replace(/^\s*|\s*$/g,''); } function ProcessInput(e) { if (window.event) // IE keyNum = e.keyCode; else if (e.which) // Netscape/Firefox/Opera keyNum = e.which; if (keyNum == 13) { e.returnValue = false; e.cancelBubble = true; DoKeywordSearch('KW'); return false; } return true; } function DoKeywordSearch() { if (document.getElementById('textboxTerm').value.trim() != '') { var strURL = 'http://catalog.ncpl.lib.oh.us/polaris/search/searchresults.aspx?ctx=1.1033.0.0.1'; var strWindex = document.getElementById('Windex').value; var strTerm = escape(document.getElementById('textboxTerm').value); window.location = strURL + "&type=Keyword&limit=TOM=*&sort=PD_TI&Page=0&by=" + strWindex + "&term=" + strTerm; } else { alert('Please enter a search term'); document.getElementById('textboxTerm').focus(); } } </script> <noscript>JavaScript must be enabled for catalog!</noscript> <table border="0"> <tr> <td> <label for="search">Search our Catalog:</label> <input class="search" type=text id=textboxTerm size=30 onkeypress="return ProcessInput(event)" /> <select class="search" id="Windex"> <option value="KW" selected="selected"> Anywhere </option> <option value="SU"> Subject </option> <option value="TI"> Title </option> <option value="AU"> Author </option> <option value="KW&fic=1"> Fiction </option> <option value="KW&fic=0"> Nonfiction </option> </select> <input type="submit" class="button" value="Go!" name="submit" onclick="DoKeywordSearch()" /> </td> </tr> </table> <!--// End of Search form -->" My question is where would the code for the link go and is there a good resource i can use to figure out how to write it? Any help is greatly appreciated, thank you. $link = ?><a href="post?id=<?php echo $id; ?>&title=<?php echo $slug_title; ?>"><?php echo $title; ?></a><?phpBasically what I am trying to do is get a url link of a current page that I'll be sending in an email. I have all the $_GET variables I need to duplicate the current url. For some reason it's giving me an error. Can you please fix what is shown above into something that'll work? Thanks. Edited by man5, 15 July 2014 - 07:09 PM. Hi Everyone. I get the following data from a result from database search <?php echo $rsjobs['CompanyURL'];?> It prints out the url but when I try to turn it into a clickable link it does not work Here is the coding I have so far. <a href="<?php echo $rsjobs['CompanyURL'];?>"><?php echo $rsjobs['CompanyURL'];?></a> What am I doing wrong ? please help. I'm trying to convert a grayscale image to pure black and white in php using the GD library. The purpose would be to detect the cervical cells within the image. I'll leave the php code and a matlab one (i wrote this code in matlab and i'm trying to obtain the same result in php). Basically, im having troubles accessing each individual pixel's color and modifying it. MATLAB:
clear all, clc, close all;
I = imread('celule.jpg');
imshow(I)
title('original');
a=rgb2gray(I);
figure;
imshow(a)
title('grayscale');
s=size(a);
for i=1:s(1)
for j=1:s(2)
if a(i,j)>190
a(i,j)=0;
else a(i,j)=255;
end
end
end
figure;
imshow(a)
title('pure black and white');
PHP:
<?php
$im = imagecreatefromjpeg("celule.jpg");
function imagetograyscale($im)
{
if (imageistruecolor($im)) {
imagetruecolortopalette($im, false, 256);
}
for ($c = 0; $c < imagecolorstotal($im); $c++) {
$col = imagecolorsforindex($im, $c);
$gray = round(0.299 * $col['red'] + 0.587 * $col['green'] + 0.114 * $col['blue']);
imagecolorset($im, $c, $gray, $gray, $gray);
}
}
imagetograyscale($im);
//imagefilter($im, IMG_FILTER_CONTRAST, -255); //i'm not looking for this effect
header('Content-type: image/jpeg');
imagejpeg($im);
$C = imagesx($im); //width
$L = imagesy($im); //height
echo "Dimensiuni imagine: latime $C, inaltime $L <br>";
//scanning through the image
for($x = 0; $x < $L; $x++) { //each line
for($y = 0; $y < $C; $y++) { //each collumn
// pixel color at (x, y)
$color = imagecolorat($im, $y, $x);
$color = imagecolorsforindex($im, $color); //getting rgb values
$RED[$x][$y] = $color["red"]; //each rgb component
$GREEN[$x][$y] = $color["green"];
$BLUE[$x][$y] = $color["blue"];
}
}
?>
image "celule.jpg": https://i.ibb.co/6Ffj6sc/celule.jpg Basically I want to open up a png file with a transparent background which is 48x48 pixels And set the opacity of this to about 50% of the original. I have the following to do what I want but just returns an empty image On imagecolorallocatealpha i have tried setting the alpha value at different values between 0 and 127 with no success as 127 returns a black block imagecopy($menu,$image, #Positioning 0,0, 0,0, #Image size 48,48 ); #Create transparent block $new_img = imagecreatetruecolor(48, 48); imagealphablending($new_img, true); $transparent = imagecolorallocatealpha($new_img, 255, 255, 255, 0); imagefilledrectangle($new_img, 0, 0, 48, 48, $transparent); #Put block over original image imagecopy($menu,$new_img, #Positioning 0,0, 0,0, #Image size 48,48 ); The image below shows on top the original and on bottom what I am roughly trying to create Where am i going wrong? Hi I've got this database I created with fields ProductId ProductName Image I've managed to get it to list the ID,productname, and Image urls in a list. My next step is to have the image field actually display an image and make it clickable: heres what I've done so far: Code: [Select] <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("productfeed", $con); $result = mysql_query("SELECT * FROM productfeeds"); echo "<table border='0'> <tr> <th>Firstname</th> <th>Lastname</th> <th>Image</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['ProductID'] . "</td>"; echo "<td>" . $row['ProductName'] . "</td>"; echo "<td>" . $row['ImageURL'] . "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> Heres what I want to do: Code: [Select] while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['ProductID'] . "</td>"; echo "<td>" . $row['ProductName'] . "</td>"; // my changes beneath echo "<td>" . <a href="<?php echo $row['ImageURL'];?>"> <img src="<?php echo $row['LinkURL']; ?>"> </a>. "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> Can you guys point me in the right direction? Many thanks i need help on this one. i am aiming to make my own smaller version of tineye.com or something similar i do have a function that will compare 2 images in GD. all i have to figure out now is how to spider the default image off of major networking sites like facebook,myspace etc. and list all the results found and the similarity of each picture. the function is something like compare_imgs($path,$source_pic,$comparison_pic) { } I have a line like this it prints text link but I prefer image link how should i edit it I would appreciate some feedback Code: [Select] $templates['etiket'] = array('name' => t('ETİKET'), 'module' => 'uc_invoice_pdf', 'path' => $templates_uc_invoice_pdf_path, 'pdf_settings' => $pdf_settings); Hi, I've read a lot of places that it's not recommended to store binary files in my db. So instead I'm supposed to upload the image to a directory, and store the link to that directory in database. First, how would I make a form that uploads the picture to the directory (And what kinda directories are we talking?). Secondly, how would I retrieve that link? And I guess I should rename the picture.. I'd appreciate any help, or a good tutorial (Haven't found any myself). I need help making the uploaded image file name, that's chosen to be uploaded, be displayed on the html page with the path /upload/ added to the beginning of the displayed file name like so: ../upload/test.png Any help/improvements will be appreciated.
<html>
<head>
<title>PHP Test</title>
</head>
<body>
<?php
if ($form_submitted == 'yes') {
$allowedExts = array("gif", "jpeg", "jpg", "png");
$temp = explode(".", $_FILES["file"]["name"]);
$extension = strtolower( end($temp) );
if ( $_FILES["file"]["size"] < 200000
&& in_array($extension, $allowedExts) )
{
if ($_FILES["file"]["error"]!= 0)
{
echo "Return Code: " . $_FILES["file"]["error"] . "<br>";
} else {
$length = 20;
move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $newfilename );
$file_location = '<a href="http://../upload/' . $newfilename . '">' . $newfilename . '</a>';
}
} else {
echo "Invalid upload file";
}
?>
<label for="file">Filename:</label>
<input type="file" name="file" id="file">
</body>
</html>
How to do that when you turn 360 degrees no longer come back? Only in this way was? Hey guy's i have a script i did a few months ago and now noticed that it is doing its job but keeps the old file ..so i got the image a few times but on a different angle...
how can i optimize this code to delete the old image when doing the rotation?
<?php
session_start();
include_once 'dbconnect.php';
if (!isset($_SESSION['userSession'])) {
header("Location: index.php");
}
$degrees = -270;
$path = $_GET['Folder'];
$file =$_GET['Pic'];
$fileid =$_GET['id'];
$image = $path.'/'.$file;
$imageN = $path.'/New_'.$file;
//load the image
$source = imagecreatefromjpeg($image);
//rotate the image
$rotate = imagerotate($source, $degrees, 0);
$NewImg='New_'.$file ;
//set the Content type
//header('Content-type: image/jpeg');
//display the rotated image on the browser
//imagejpeg($rotate);
imagejpeg($rotate,$imageN,100);
//free the memory
imagedestroy($source);
imagedestroy($rotate);
$sql = "UPDATE Coupon_list SET product_image_thumb = '$NewImg' WHERE id = '$fileid'";
if (mysqli_query($DBcon, $sql)) {
echo "Rotation ok";
echo('<script language="Javascript">opener.window.location.reload(false); window.close();</script>');
} else {
echo "Error Rotating: " . mysqli_error($DBcon);
}
mysqli_close($DBcon);
?>
<img src="gears.gif" alt="" />
Hi, There are 10 images in a folder called "Images". All images are named like 1.jpg, 2.jpg, 3.gif, 4.png, and so on... I am using these images on my website with this link: MyDomain.com/Images/1.jpg Now what i want to do is change the image every minute. from 1... to ...10 all images one by one, every minute... Link should remain same, but it should give different image every time. and if someone copies my link of image, it still gets changed every minute. i hope to get some help, better with some example code... Thanks! Maybe somebody knows a good way to do this... I have a simple query that seasonal categories - plus one special events header. then for each header I pull all the classes in that category. Right now it just pulls and orders by id. So, regardless of year, they come out in the same order: spring, winter, fall, special events. I'm trying to see if there's a way to make them show in order of relevance to the current time. right now, the "cat" table just has two fields: cat_id, cat_name. In other words, in autumn, I want them to order: Autumn, winter, summer, spring - then special events. In summer, I want them to order: Summer, spring, autumn, winter - then special events. any thoughts on how to do this? step one, order by relevence to current date. step two, special events is always last. Code: [Select] $query1 = "select * from tbl_cat ORDER by cat_id"; $result_cats = mysql_query($query1) or die(mysql_error()); while ($row = mysql_fetch_array($result_cats)) { $query_selectall = "select *,workshop_date AS tester from tbl_workshops WHERE category={$row['cat_id']} and active_inactive = '1' ORDER by workshop_date"; $result_all = mysql_query($query_selectall) or die(mysql_error()); $catid = $row['cat_id']; $catname = $row['cat_name']; echo "<font face='georgia' size=5><b>".$catname." </b></font><br><div style='color:#fff;'>"; while ($c_row = mysql_fetch_array($result_all)){ // rest of code pulls items that match that specific category id. } So whether I am uploading an image through my iphone or sending that image to my computer and uploading it from the computer, it has the same effect. If I upload that image, it'll orient the image in landscape mode. Having said that, I found a function that can fix the orient issue. The problem is I don't know the proper way to integrate it into the image upload script. I have tried several different ways but they all give me errors. Can you show me where exactly I should use this function?
// IMAGE ORIENTATION
function getOrientedImage($imagePath) {
$image = imagecreatefromstring(file_get_contents($imagePath));
$exif = exif_read_data($imagePath);
if(!empty($exif['Orientation'])) {
switch($exif['Orientation']) {
case 8:
$image = imagerotate($image,90,0);
swapHW();
break;
case 3:
$image = imagerotate($image,180,0);
break;
case 6:
$image = imagerotate($image,-90,0);
swapHW();
break;
}
}
return $image;
}
// IMAGE UPLOAD SCRIPT
if(isset($_FILES['fileToUpload']) AND !empty($_FILES['fileToUpload']["name"])) {
if(is_uploaded_file($_FILES['fileToUpload']["tmp_name"])) {
$target_dir = '../members/images/'.$global_user_id.'/projects/'.$url_project_id.'/';
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
$source_file = $_FILES["fileToUpload"]["tmp_name"];
$random_name = generateRandomString(10);
$new_image = $random_name . '.' . $imageFileType;
$resized_image = compressImage($source_file, $new_image, 50);
$new_file_path = $target_dir . $resized_image;
if(!is_dir($target_dir)){
mkdir($target_dir, 0775, true);
}
$uploadOk = 1;
// Check if image file is a actual image or fake image
$check = getimagesize($source_file);
if($check !== false) {
// echo "File is an image - " . $check["mime"] . ".";
$uploadOk = 1;
} else {
$errors[] = 'File is not an image!';
$uploadOk = 0;
}
// Check if file already exists
if (file_exists($target_file)) {
$errors[] = 'Sorry, file already exists!';
$uploadOk = 0;
}
// Check file size
if ($_FILES["fileToUpload"]["size"] > 5000000) {
$errors[] = 'Sorry, your file size is bigger than 5mb!';
$uploadOk = 0;
}
// Allow certain file formats
if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg" && $imageFileType != "gif" && $imageFileType != "JPG" && $imageFileType != "PNG" && $imageFileType != "JPEG" && $imageFileType != "GIF") {
$errors[] = 'Sorry, only JPG, JPEG, PNG & GIF files are allowed!';
$uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if($uploadOk == 0) {
$errors[] = 'Sorry, your file was not uploaded!';
// if everything is ok, try to upload file
} else {
if(rename($new_image, $new_file_path)) {
echo 'success';
} else {
$errors[] = 'Sorry, there was an error uploading your file!';
}
}
} else {
$errors[] = 'You must upload an image!';
}
}
Edited December 23, 2019 by imgrooot |
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