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PHP - Update Query Inserts Instead Of Update.
I created this code to upload a member's main picture on his member page on website. I'll only include the query part of the code since that's what is relevant to my problem. The idea is basically to upload a new picture onto the database if no picture already exists for that member and display the picture on the page. If a picture already exists, then the script replaces the old picture with the new one upon upload. But for whatever reason
I don't understand, when I try to replace the old pic, it gets inserted in a new row on the database instead of replacing the old row, and the new pic gets displayed on the web page alongside the old. Code: [Select] $query = "SELECT username FROM images WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'"; $result = @mysql_query($query); $num = @mysql_num_rows($result); if ($num> 0) { //Update the image $update = mysql_query("UPDATE images SET image = '" . $image['name'] . "' WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'"); $_SESSION['error'] = "File updated successfully."; //really should be session success message. header("Location: member.php"); exit; } else { // NOTE: This is where a lot of people make mistakes. // We are *not* putting the image into the database; we are putting a reference to the file's location on the server $sql = "insert into images (member_id, image_cartegory, image_date, image) values ('{$_SESSION['id']}', 'main', NOW(), '" . $image['name'] . "')"; $result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error()); $_SESSION['error'] = "File uploaded succussfully."; //really should be session success message. header("Location: member.php"); } So can anyone tell me what the problem is? Could the fact that my insert script actually uploads the image onto a folder on my server and only stores the path name in the database have anything to contribute to the mixup? Appreciate your responses in advance. Similar TutorialsI am trying to make a simple CMS, the table is created with this command(using php): Code: [Select] private function buildDB() { $sql = <<<MySQL_QUERY CREATE TABLE IF NOT EXISTS newcore ( id MEDIUMINT NOT NULL AUTO_INCREMENT, title VARCHAR(128), menutitle VARCHAR(128), bodytext TEXT, json VARCHAR(1024), children VARCHAR(128), template INTEGER, created VARCHAR(100), PRIMARY KEY (id) ) ENGINE=MyISAM; MySQL_QUERY; return mysql_query($sql); } everything works fine, insert, delete, select, etc. But when I update a row, the update is also done, but another row is created with the same values, but of course a new id. I do the update this way: Code: [Select] $created = time(); $sql = 'UPDATE newcore SET title="'.$title.'", menutitle="'.$menutitle.'", bodytext="'.$bodytext. '", json="'.$json.'", children="'.$children.'", template="'.$template.'", created="'.$created.'" WHERE id='.$req['id']; mysql_query($sql); All the values are entered by myself, so there is no possibility of problem in values to make it function like that. Please help me, It's driving me insane! Thanks in advance. Hello all,
Based on the suggestion of you wonderful folks here, I went away for a few days (to learn about PDO and Prepared Statements) in order to replace the MySQLi commands in my code. That's gone pretty well thus far...with me having learnt and successfully replaced most of my "bad" code with elegant, SQL-Injection-proof code (or so I hope).
The one-and-only problem I'm having (for now at least) is that I'm having trouble understanding how to execute an UPDATE query within the resultset of a SELECT query (using PDO and prepared statements, of course).
Let me explain (my scenario), and since a picture speaks a thousand words I've also inlcuded a screenshot to show you guys my setup:
In my table I have two columns (which are essentially flags i.e. Y/N), one for "items alreay purchased" and the other for "items to be purchased later". The first flag, if/when set ON (Y) will highlight row(s) in red...and the second flag will highlight row(s) in blue (when set ON).
I initially had four buttons, two each for setting the flags/columns to "Y", and another two to reverse the columns/flags to "N". That was when I had my delete functionality as a separate operation on a separate tab/list item, and that was fine.
Now that I've realized I can include both operations (update and delete) on just the one tab, I've also figured it would be better to pare down those four buttons (into just two), and set them up as a toggle feature i.e. if the value is currently "Y" then the button will set it to "N", and vice versa.
So, looking at my attached picture, if a person selects (using the checkboxes) the first four rows and clicks the first button (labeled "Toggle selected items as Purchased/Not Purchased") then the following must happen:
1. The purchased_flag for rows # 2 and 4 must be switched OFF (set to N)...so they will no longer be highlighted in red.
2. The purchased_flag for row # 3 must be switched ON (set to Y)...so that row will now be highlighted in red.
3. Nothing must be done to rows # 1 and 5 since: a) row 5 was not selected/checked to begin with, and b) row # 1 has its purchase_later_flag set ON (to Y), so it must be skipped over.
Looking at my code below, I'm guessing (and here's where I need the help) that there's something wrong in the code within the section that says "/*** loop through the results/collection of checked items ***/". I've probably made it more complex than it should be, and that's due to the fact that I have no idea what I'm doing (or rather, how I should be doing it), and this has driven me insane for the last 2 days...which prompted me to "throw in the towel" and seek the help of you very helpful and intellegent folks. BTW, I am a newbie at this, so if I could be provided the exact code, that would be most wonderful, and much highly appreciated.
Thanks to you folks, I'm feeling real good (with a great sense of achievement) after having come here and got the great advice to learn PDO and prepared statements.
Just this one nasty little hurdle is stopping me from getting to "end-of-job" on my very first WebApp. BTW, sorry about the long post...this is the best/only way I could clearly explaing my situation.
Cheers guys!
case "update-delete":
if(isset($_POST['highlight-purchased']))
{
// ****** Setup customized query to obtain only items that are checked ******
$sql = "SELECT * FROM shoplist WHERE";
for($i=0; $i < count($_POST['checkboxes']); $i++)
{
$sql=$sql . " idnumber=" . $_POST['checkboxes'][$i] . " or";
}
$sql= rtrim($sql, "or");
$statement = $conn->prepare($sql);
$statement->execute();
// *** fetch results for all checked items (1st query) *** //
$result = $statement->fetchAll();
$statement->closeCursor();
// Setup query that will change the purchased flag to "N", if it's currently set to "Y"
$sqlSetToN = "UPDATE shoplist SET purchased = 'N' WHERE purchased = 'Y'";
// Setup query that will change the purchased flag to "Y", if it's currently set to "N", "", or NULL
$sqlSetToY = "UPDATE shoplist SET purchased = 'Y' WHERE purchased = 'N' OR purchased = '' OR purchased IS NULL";
$statementSetToN = $conn->prepare($sqlSetToN);
$statementSetToY = $conn->prepare($sqlSetToY);
/*** loop through the results/collection of checked items ***/
foreach($result as $row)
{
if ($row["purchased"] != "Y")
{
// *** fetch one row at a time pertaining to the 2nd query *** //
$resultSetToY = $statementSetToY->fetch();
foreach($resultSetToY as $row)
{
$statementSetToY->execute();
}
}
else
{
// *** fetch one row at a time pertaining to the 2nd query *** //
$resultSetToN = $statementSetToN->fetch();
foreach($resultSetToN as $row)
{
$statementSetToN->execute();
}
}
}
break;
}
CRUD Queston.png 20.68KB
0 downloads
Currently I show a list of users and their information. You can than click that specific user and it shows you their information to edit. My problem is it's not updating the query with the new input information.
Here is the page that displays the registration information:
<?php
$con=mysqli_connect('localhost', 'root', '');
/* check connection */
if (mysqli_connect_errno($con)) {
trigger_error('Database connection failed: ' . mysqli_connect_error(), E_USER_ERROR);
}
$query = "SELECT * FROM `bencobricks` . `users`";
$result = mysqli_query($con, $query) or trigger_error("Query Failed! SQL: $query - Error: ". mysqli_error($con), E_USER_ERROR);
?>
<table width="1000" border="0" cellspacing="1" cellpadding="0">
<tr>
<td>
<table width="1000" border="1" cellspacing="0" cellpadding="3">
<tr>
<td colspan="4"><strong>List data from mysql </strong> </td>
</tr>
<tr>
<td align="center"><strong>Username</strong></td>
<td align="center"><strong>Email</strong></td>
<td align="center"><strong>Membership</strong></td>
<td align="center"><strong>First Name</strong></td>
<td align="center"><strong>Last Name</strong></td>
<td align="center"><strong>Gender</strong></td>
<td align="center"><strong>Birthdate</strong></td>
<td align="center"><strong>Sets</strong></td>
<td align="center"><strong>Checkbox</strong></td>
<td align="center"><strong>Admin Flag</strong></td>
</tr>
<?php
while($rows=mysqli_fetch_array($result)){
?>
<tr>
<td><?php echo $rows['username']; ?></td>
<td><?php echo $rows['email']; ?></td>
<td><?php echo $rows['membership']; ?></td>
<td><?php echo $rows['firstName']; ?></td>
<td><?php echo $rows['lastName']; ?></td>
<td><?php echo $rows['gender']; ?></td>
<td><?php echo $rows['dateOfBirth']; ?></td>
<td><?php echo $rows['sets']; ?></td>
<td><?php echo $rows['checkbox']; ?></td>
<td><?php echo $rows['adminFlag']; ?></td>
<td align="center"><a href="update.php?userID=<?php echo $rows['userID']; ?>">update</a></td>
</tr>
<?php
}
?>
</table>
</td>
</tr>
</table>
<?php
mysqli_close($con);
?>
Page that displays specific user for updating:
<?php
$con=mysqli_connect('localhost', 'root', '');
/* check connection */
if (mysqli_connect_errno($con)) {
trigger_error('Database connection failed: ' . mysqli_connect_error(), E_USER_ERROR);
}
$id=$_GET['userID'];
$query = "SELECT * FROM `bencobricks` . `users` WHERE `userID` = '$id'";
$result = mysqli_query($con, $query) or trigger_error("Query Failed! SQL: $query - Error: ". mysqli_error($con), E_USER_ERROR);
$rows=mysqli_fetch_array($result);
?>
<table width="1000" border="0" cellspacing="1" cellpadding="0">
<tr>
<form name="form1" method="post" action="update_ac.php">
<td>
<table width="100%" border="0" cellspacing="1" cellpadding="0">
<tr>
<td> </td>
<td colspan="3"><strong>Update data in mysql</strong> </td>
</tr>
<tr>
<td align="center"> </td>
<td align="center"> </td>
<td align="center"> </td>
<td align="center"> </td>
</tr>
<tr>
<td align="center"><strong>Username</strong></td>
<td align="center"><strong>Email</strong></td>
<td align="center"><strong>Membership</strong></td>
<td align="center"><strong>First Name</strong></td>
<td align="center"><strong>Last Name</strong></td>
<td align="center"><strong>Gender</strong></td>
<td align="center"><strong>Birthdate</strong></td>
<td align="center"><strong>Sets</strong></td>
<td align="center"><strong>Checkbox</strong></td>
<td align="center"><strong>Admin Flag</strong></td>
</tr>
<tr>
<td align="center">
<input name="username" type="text" id="username" value="<?php echo $rows['username'] ;
echo (isset($_POST['username']) ? $_POST['username'] : ''); ?>">
</td>
<td align="center">
<input name="email" type="text" id="email" value="<?php echo $rows['email']; ?>" size="15">
</td>
<td>
<input name="membership" type="text" id="membership" value="<?php echo $rows['membership']; ?>" size="15">
</td>
<td>
<input name="firstName" type="text" id="firstName" value="<?php echo $rows['firstName']; ?>" size="15">
</td>
<td>
<input name="lastName" type="text" id="lastName" value="<?php echo $rows['lastName']; ?>" size="15">
</td>
<td>
<input name="gender" type="text" id="gender" value="<?php echo $rows['gender']; ?>" size="15">
</td>
<td>
<input name="dateOfBirth" type="text" id="dateOfBirth" value="<?php echo $rows['dateOfBirth']; ?>" size="15">
</td>
<td>
<input name="sets" type="text" id="sets" value="<?php echo $rows['sets']; ?>" size="15">
</td>
<td>
<input name="checkbox" type="text" id="checkbox" value="<?php echo $rows['checkbox']; ?>" size="15">
</td>
<td>
<input name="adminFlag" type="text" id="adminFlag" value="<?php echo $rows['adminFlag']; ?>" size="15">
</td>
</tr>
<tr>
<td> </td>
<td>
<input name="id" type="hidden" id="id" value="<?php echo $rows['userID']; ?>">
</td>
<td align="center">
<input type="submit" name="Submit" value="Submit">
</td>
<td> </td>
</tr>
</table>
</td>
</form>
</tr>
</table>
<?php
// close connection
mysqli_close($con);
?>
Finally the update query:
<?php
function test_input($data){
$data = trim($data);
$data = stripslashes($data);
$data = htmlspecialchars($data);
return $data;
}
$con=mysqli_connect('localhost', 'root', '');
/* check connection */
if (mysqli_connect_errno($con)) {
trigger_error('Database connection failed: ' . mysqli_connect_error(), E_USER_ERROR);
}
// update data in mysql database
if (empty($_POST["username"]))
{/* can never be empty due to design */}
else
{$username= test_input($_POST['username']);}
$id = 'id';
$query = "UPDATE `bencobricks`. `users` SET `username` = '$username', `password` = 'NULL', `email` = 'email', `membership` = 'membership', `firstName` = 'firstName', `lastName` = 'lastName',
`gender` = 'gender', `dateOfBirth` = 'dateOfBirth', `date` = 'NULL', `sets` = 'sets', `checkbox` = 'checkbox', `adminFlag` = 'adminFlag' WHERE `userID` = '$id'";
$result = mysqli_query($con, $query) or trigger_error("Query Failed! SQL: $query - Error: ". mysqli_error($con), E_USER_ERROR);
// if successfully updated.
if($result){
echo "Successful";
echo "<BR>";
echo "<a href='editUser.php'>View Users Page</a>";
}
else {
echo "ERROR";
}
?>
Attached Files
1.PNG 19.06KB
0 downloads
2.PNG 47.07KB
0 downloadsAfter a ton of trial and error and searching and searching for the answer, I have finally resorted to posting to ask for help. I am very new to php so please bear with me.
I have been building an employee training database at work. Basically to make sure that for example we have the current drivers liscense on file for those employees who drive and have gone through the required company training. I initially built an access database with a frontend that does everything needed. However, the company is very decentralized and we have several users who would regularly need access to the information when they are offsite. The database does work offsite however it is extremely slow. After purchasing a buffalo linkstation, I discovered it has the capability for a mysql server.
I have been able to migrate the data over to the mysql server and build a simple read only php form but cant get the changes you make to update back into the database.
I found a method of fetching the data using json that is based on a drop down selection, upon change, it goes and gets the correct data.
<script type="text/javascript">
function insertResults(json){
$("#Separated").val(json["Separated"]);
$("#id").val(json["id"]);
$("#Employee_ID").val(json["Employee_ID"]);
$("#Last_Name").val(json["Last_Name"]);
$("#First_Name").val(json["First_Name"]);
$("#Date_Of_Birth").val(json["Date_Of_Birth"]);
$("#Original_Hire_Date").val(json["Original_Hire_Date"]);
$("#Current_Hire_Date").val(json["Current_Hire_Date"]);
However, lets say you correct a mis-spelling in their name, I cant seem to write back to the db. I have a submit button that uses this code
<a href="InputFormSubmit.php?id=<?php echo $rows['id']; ?>"><input type="submit" name="submit2" value="Submit"></a>But I guess I cant seem to #1 completely grasp how to pass on the selected information using POST (correct?) to the next form "InputFormSubmit" and #2 correctly build the query for it? Code for it below:
<?php
include_once('db.php');
$Employee_ID = $_POST['Employee_ID'];
$Last_Name = $_POST['Last_Name'];
$First_Name = $_POST['First_Name'];
$id=$_POST['id'];
echo "$id";
echo "$Employee_ID";
// update data in mysql database
$con=mysql_connect("localhost","usernamegoeshere","passwordgoeshere","databasenamegoeshere");
// Check connection
mysql_query("UPDATE tbl_Employee_Master SET Last_Name='$Last_Name', First_Name='$First_Name' WHERE id='$id'");
mysql_close($con);
?>
The proper EmployeeID is passed from the previous form into this one, but the query dies I guess.
What I would like to do is pass the updated info into InputFormSubmit and then run the query and redirect back to the search page. Potentially passing back the employee ID and setting the drop down to that value so you would see the employees file you just updated again.
Super long post, thanks for any direction anyone can give me, Im sure my code looks awful from trying a thousand different things.
Thanks again.
Hi i have this simple update form and scrip but somehow it doesnt seem to be update the field on the database can someone help out please. The html form is the second form bellow where the action send to status_update.php HTML FORM Code: [Select] <?php include("../header.html"); ?> <?php include("header_news.html"); extract($_REQUEST,EXTR_SKIP); ?><?php /* print("sfilm_refnum = $sfilm_refnum<BR>"); print("sfilm_addr01 = $sfilm_addr01<BR>"); print("sfilm_postcode = $sfilm_postcode<BR>"); print("Film Client = $fclient<BR>"); */ ?> <form id="search" action="list.php" method="post" name="search"> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#eeeeee"> <tr> <td align="right" width="140"></td> <td width="320"><span class="hofblack10"> </span> </td> <td align="center" width="100"><input type="hidden" name="lstart" value="<?php print("$lstart"); ?>" /><input type="hidden" name="lend" value="<?php print("$lend"); ?>" /><input type="hidden" name="lamount" value="<?php print("$lamount"); ?>" /></td> <td align="center" width="100"></td> <td align="right"></td> </tr> </table> </form> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#4050c4"> <tr> <td width="60" class="hofwhite10">action</td> <td width="140"><span class="hofwhite14">DATE</span></td> <td width="80"><span class="hofwhite14">ID</span></td> <td><span class="hofwhite14">News Titile</span></td> <td width="100"><span class="hofwhite14">Status</span></td> </tr> <tr height="0"> <td bgcolor="white" width="60"></td> <td bgcolor="white" width="140" height="0"></td> <td bgcolor="white" width="80" height="0"></td> <td bgcolor="white" height="0"></td> <td bgcolor="white" width="100" height="0"></td> </tr> </table><table width="780" border="0" cellspacing="0" cellpadding="4"><tr> <td width="60"></td> <td width="80"></td> <td><a class="blueullrg" href="add.php">Add News</a></td> <td align="right" width="120"></td> </tr> <tr height="0"> <td width="60" height="0"></td> <td width="80" height="0"></td> <td height="0"></td> <td align="right" width="120" height="0"></td> </tr> </table> <?php //get the DB connection variables include("../../../includes/config.php"); //connect to DB $connection = @mysql_connect($db_address,$db_username,$db_password) or die("Couldn't CONNECT."); $db = @mysql_select_db($db_name, $connection) or die("Couldn't select DATABASE."); $query2="SELECT * FROM news WHERE !(news_status='deleted')"; $result2 = mysql_query($query2) or die("Couldn't execute QUERY - Select NEWS Qty"); $fqty = mysql_num_rows($result2); //SELECT or FIND the same USERNAME $query3="SELECT * FROM news WHERE !(news_status='deleted') ORDER BY news_id DESC"; $result3 = mysql_query($query3) or die("Couldn't execute QUERY - Select NEWS"); while ($row = mysql_fetch_array($result3)) { $news_id = $row['news_id']; $news_title = $row['news_title']; $news_story = $row['news_story']; $news_image = $row['news_image']; $news_image_caption = $row['news_image_caption']; $news_image_link = $row['news_image_link']; $news_date_day = $row['news_date_day']; $news_date_month = $row['news_date_month']; $news_date_year = $row['news_date_year']; $news_status = $row['news_status']; $news_website = $row['news_website']; $news_date_created = $row['news_date_created']; $news_date_modified = $row['news_date_modified']; ?> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#eeeeee"> <tr> <td width="60"><span class="hofblack10"> <?php if($news_status=="deleted"){ print("<a class='hifblack10'>deleted</span>"); }ELSE{ print("<a class='blueul' href='edit.php?id=$news_id'>edit</a>"); } ?> </span></td> <td width="140"><span class="titlegrey12"> <?php if(!$news_date_day) { echo "00"; } else{ echo $news_date_day; } echo "/"; if(!$news_date_month) { echo "00"; }else{ echo $news_date_month; } echo "/"; if(!$news_date_year) { echo "0000"; }else{ echo $news_date_year; } ?> </span></td> <td width="80"><span class="titlegrey12"><?php print("$news_id"); ?></span> </td> <td><?php if($news_status=="deleted") { print("<class='hofblack10'>$news_title</span>"); }ELSE{ print("<a class='blueul' href='edit.php?id=$news_id'>$news_title</a>"); } ?></td> <td width="100"> <form id="list_update" action="status_update.php" method="post" name="list_update"> <select name="newnstatus" size="1"> <option <?php if($row['news_status'] == "") { print("selected"); } ?> selected="selected" value="">Status...</option> <option <?php if($row['news_status'] == "on") { print("selected"); } ?> value="on">On</option> <option <?php if($row['news_status'] == "off") { print("selected"); } ?> value="off">Off</option> <option <?php if($row['news_status'] == "deleted") { print("selected"); } ?> value="deleted">Delete</option> </select> <input type="hidden" name="nstatus" value="<?php echo $row[news_status]; ?>" /> <input type="hidden" name="id" value="<?php echo $row[news_id]; ?>" /> <input type="submit" name="update" value="update" /> </form> </td> </tr> <tr height="0"> <td bgcolor="white" width="60"></td> <td bgcolor="white" width="140" height="0"></td> <td bgcolor="white" width="80" height="0"></td> <td bgcolor="white" height="0"></td> <td bgcolor="white" width="100" height="0"></td> </tr> </table> <?php } mysql_close($connection);//}?> <table width="780" border="0" cellspacing="0" cellpadding="4"> <tr> <td width="60"></td> <td width="80"></td> <td><a class="blueullrg" href="add.php">Add News</a></td> <td align="right" width="120"></td> </tr> </table><?php // include("list_navigation.html"); ?> <?php include("../footer.html"); ?> </div></body></html> The action script php Code: [Select] <?php /* echo "fstatus: ".$fstatus."<BR>"; echo "id: ".$id."<BR>"; echo "fclient: ".$fclient."<BR>"; echo "newfstatus: ".$newfstatus."<BR>";*/ //set the date of agreement $timestamp = date('l jS \of F Y h:i:s A'); //get the DB connection variables include("../../../includes/config.php"); //connect to DB $connection = @mysql_connect($db_address,$db_username,$db_password) or die("Couldn't CONNECT."); $db = @mysql_select_db($db_name, $connection) or die("Couldn't select FILMS DATABASE."); // All appears well, so enter into database $query= "UPDATE news SET news_status = '$newnstatus' WHERE news_id='$id'"; $result = mysql_query($query) or die("could not execute query - Update FILMS Record to DB"); //setup an email to the Admin @ hof, w/o attachment $emailto="xx@xxx.co.uk"; $emailfrom="no-reply@xxxx.co.uk"; $emailsubject="xx Record Updated"; $emailmessage="Hello Registrar\n\n"; $emailmessage.="News ID: ".$id."\n"; $emailmessage.="Updated on: ".$timestamp."\n\n"; $emailmessage.="Status was: ".$nstatus."\n"; $emailmessage.="Status now: ".$newfnstatus."\n"; $emailmessage.="Thank you,\n\n"; $emailmessage.="Web Site ROBOT\n"; $emailmessage.="(Administrator)\n"; $emailmessage.="xxx.co.uk | xxx.biz\n"; $emailmessage.="----------------------------------------------\n"; $emailmessage.="e. http://www.xxx.co.uk/contact.php\n"; $emailmessage.="w. http://www.xxx.co.uk\n"; $emailheader="From: xxx.co.uk<$emailfrom>"; $emailheader .= 'Cc: xxx@xxx.co.uk'."\r\n"; $emailheader .= 'Bcc: xxx@xxxxx.co.uk'."\r\n"; $ok=mail($emailto,$emailsubject,$emailmessage,$emailheader); mysql_close($connection); if ($ok) { header("Location: list.php"); /* Redirect browser */ exit; } else { $errmsg="There was a problem, please try later or telephone us direct."; $errsta="1"; include("edit_error.html"); //echo "<p>Mail could not be sent. Sorry!</p>"; exit; } ?> Thanks in advance Can anyone post a generic update function to update mysql table. The manual approach: update $tablename set $column1='a', $column2='b' where $id=$value; Hi, i am currently designing a new website and am testing a few different compnents of it. One part gathers two variables of the url using the GET method and selects the relevant data from the database. It then performs an UPDATE of a field called balance before INSERTING a new record. Everything works and gets inserted except for the UPDATE. Here is the code Code: [Select] <?php include ("connect.php"); $id = ""; $offerid = ""; $id = $_GET['user_id']; $offerid = $_GET['offer_id']; $sql_user = mysql_query("SELECT * FROM user_info WHERE id = $id"); $sql_offer = mysql_query("SELECT * FROM offers WHERE offerid = $offerid"); $balance += $payout; mysql_query("UPDATE user_info SET balance = $balance WHERE id = $id"); mysql_query ("INSERT INTO offer_credited (id, offerid, date_credited, payout_to_user) VALUES ('$id', '$offerid', CURDATE(), '$payout')") or die(mysql_error()); echo "Your Offer has been recorded and Updated" ?> The balance field is a float that i want to increase by the amount of the payout variable which is from the offers table. However, the balance never gets updated and remains at 0. Any ideas what it could be, i am thinking it is something to do with, Code: [Select] $balance += $payout; But i can't think of what else to do. Hopefully this isn't too confusing. Thanks for the help I would like to edit a record that I already have in my database but my query is not working for some reason. Hope someone can help. The errors i get are Notice: Undefined variable: first_name in C:\chemicaluser\www\editinfo.php on line 40 Notice: Undefined variable: last_name in C:\chemicaluser\www\editinfo.php on line 40 Notice: Undefined variable: log_number in C:\chemicaluser\www\editinfo.php on line 40 .... line 40 = my query $query = "UPDATE table1 SET first_name = '$first_name', last_name = '$last_name' WHERE log_number = '$log_number' "; Very simple database, 1 table w/ 2 fields table name = table1 fields = first_name, last_name my php file Code: [Select] <?php require ('/menu.php'); require_once('sqlconnect.php'); if (isset($_GET['log_number']) && isset($_GET['first_name']) && isset($_GET['last_name']) ) { $log_number = $_GET['log_number']; $first_name = $_GET['first_name']; $last_name = $_GET['last_name']; } else if (isset($_POST['log_number']) && isset($_POST['first_name']) && isset($_POST['last_name']) ) { $log_number = $_POST['log_number']; $first_name = $_POST['first_name']; $last_name = $_POST['last_name']; } if (isset($_POST['submit'])) { $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); $query = "UPDATE table1 SET first_name = '$first_name', last_name = '$last_name' WHERE log_number = '$log_number' "; $result = mysqli_query($dbc, $query) or die ('Error querying database'); mysqli_close($dbc); } ?> my form Code: [Select] <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <label for="first_name">First name</label> <input type="text" id="first_name" name="first_name" value="<?php if (!empty($first_name)) echo $first_name; ?>"/> <label for="last_name">Last Name</label> <input type="text" id="last_name" name="last_name" value="<?php if (!empty($last_name)) echo $last_name; ?>" /> <input type="submit" value="Edit Information" name="submit" /> </form> Hi This does not make sense to me, I hope someone can tell me why this query don't work: Code: [Select] safe_query("UPDATE ".PREFIX."cup_challenges SET reply_date='$postdate', $select_map $select_date challenged_info='".$_POST['info']."', status='2' WHERE chalID='".$_GET['challID']."'");; and this query does work: Code: [Select] safe_query("UPDATE ".PREFIX."cup_challenges SET reply_date='$postdate', map1='".$_POST['map1']."', map2='".$_POST['map2']."', map3='".$_POST['map3']."', date1='".$_POST['date1']."', date2='".$_POST['date2']."', date3='".$_POST['date3']."', date4='".$_POST['date4']."', challenged_info='".$_POST['info']."', status='2' WHERE chalID='".$_GET['challID']."'"); Variables in $select_map and $select_date makes the query fail but when I copy/paste this (bold) in query it works: $select_map = map1='".$_POST['map1']."', map2='".$_POST['map2']."', map3='".$_POST['map3']."', $select date = date1='".$_POST['date1']."', date2='".$_POST['date2']."', date3='".$_POST['date3']."', date4='".$_POST['date4']."', am I using the variable in query incorrectly? Hi Guys, I'm hoping someone can find what I clearly cant see, I have a page meant to update database records, the page will load and populate with the existing data and allow 5 out of the 7 fields to be edited, however when editing any of those 5, the remaining 2 blank out and can't be filled in again. Im at a bit of loss and have been staring at it for a bit too long i think, hoping a fresh set of eyes can help. Here's the page (the fields I'm having issues with are inv1/inv2: <?php $page_title = 'Edit a Cart'; include ('style.html'); // Check for a valid ID, through GET or POST. if ( (isset($_GET['id'])) ) { // Accessed through active_search.php $id = $_GET['id']; } elseif ( (isset($_POST['id'])) ) { // Form has been submitted. $id = $_POST['id']; } else { // No valid ID, kill the script. echo '<div id="title">Page Error</div> <p class="error">This page has been accessed in error.</p><p><br /><br /></p>'; exit(); } require_once ('mysql_connect.php'); // Connect to the db. // Check if the form has been submitted. if (isset($_POST['submitted'])) { $errors = array(); // Initialize error array. // Check for a PO. { $po = trim($_POST['po']); } // Check for a Master Serial. { $sr = trim($_POST['serial']); } // Check for a Charger Serial. { $ch = trim($_POST['charger']); } // Check for a Battery Serial. { $bt1 = trim($_POST['battery1']); } // Check for a Battery Serial. { $bt2 = trim($_POST['battery2']); } // Check for a Inverter Serial. { $in1 = trim($_POST['inv1']); } // Check for a 2nd Inverter Serial. { $in2 = trim($_POST['inv2']); } // Check for a Radio Serial. { $abc = trim($_POST['abc']); } if (empty($errors)) { // If everything's OK. // Test for unique master serial. $query = "SELECT serial FROM serials WHERE serial='$id'"; $result = mysql_query($query); if (mysql_num_rows($result) == 1) { // Make the query. $query = "UPDATE serials SET po='$po', serial='$sr', charger='$ch', batt1='$bt1', batt2='$bt2', inv1='$in1', inv2='$in2', abc='$abc' WHERE serial='$id'"; $result = @mysql_query ($query); // Run the query. if (mysql_affected_rows() == 1) { // If it ran OK. // Print a message. echo '<div id="title">Success!</div> <p>The node has been edited.<a href="javascript:window.close();">Close</a></p><p><br /><br /></p>'; } else { // If it did not run OK. echo '<div id="title">System Error</div> <p class="error">The node could not be edited due to a system error. We apologize for any inconvenience.</p>'; // Public message. echo '<p>' . mysql_error() . '<br /><br />Query: ' . $query . '</p>'; // Debugging message. exit(); } } else { // Already registered. echo '<div id="title">Error!</div> <p class="error">The Serial has already been registered.</p>'; } } else { // Report the errors. echo '<div id="title">Error!</div> <p class="error">The following error(s) occurred:<br />'; foreach ($errors as $msg) { // Print each error. echo " - $msg<br />\n"; } echo '</p><p>Please try again.</p><p><br /></p>'; } // End of if (empty($errors)) IF. } // End of submit conditional. // Always show the form. // Retrieve the user's information. $query = "SELECT * FROM serials WHERE serial='$id'"; $result = @mysql_query ($query); // Run the query. if (mysql_num_rows($result) == 1) { // Valid ID, show the form. // Get the user's information. $row = mysql_fetch_array ($result); // Create the form. echo '<div id="title">Edit a Cart</div> <form action="serial_edit.php" method="post"> <table width="100%" border="0" cellspacing="0" cellpadding="0"> <tr> <td>P.O #:</td><td><input type="text" name="po" size="15" maxlength="15" value="' . $row['po'] . '" /></td> </tr> <tr> <td>Cart Serial:</td><td><input type="text" name="serial" size="15" maxlength="30" value="' . $row['serial'] . '" /></td> </tr> <tr> <td>Charger:</td><td><input type="text" name="charger" size="20" maxlength="40" value="' . $row['charger'] . '" /> </td> </tr> <tr> <td>Battery 1:</td><td><input type="text" name="battery1" size="20" maxlength="40" value="' . $row['batt1'] . '" /> </td> </tr> <tr> <td>Battery 2:</td><td><input type="text" name="battery2" size="20" maxlength="40" value="' . $row['batt2'] . '" /> </td> </tr> <tr> <td>Inverter 1:</td><td><input type="text" name="inverter1" size="20" maxlength="40" value="' . $row['inv1'] . '" /> </td> </tr> <tr> <td>Inverter 2:</td><td><input type="text" name="inverter2" size="20" maxlength="40" value="' . $row['inv2'] . '" /> </td> </tr> <tr> <td>ABC:</td><td><input type="text" name="abc" size="20" maxlength="40" value="' . $row['abc'] . '" /> </td> </tr> <tr> <td><input type="submit" name="submit" value="Submit" /><input type="hidden" name="submitted" value="TRUE" /></td> <td><input type="hidden" name="id" value="' . $id . '" /></td></tr> </form>'; } else { // Not a valid ID. echo '<div id="title">Page Error</div> <p class="error">This page has been accessed in error.</p><p><br /><br /></p>'; } mysql_close(); // Close the database connection. ?> Hi all, Firstly here is my code Code: [Select] <?php if (isset($_POST['update'])) { include('../config.php'); $name = $_POST['name']; $email = $_POST['email']; $id = $_POST['id']; $uquery=mysql_query("UPDATE customers SET name='$name' AND email='$email' WHERE id='$id'"); if($uquery) { echo mysql_error(); } else { echo mysql_error(); } } ?> <link href="../styles/clientbox.css" rel="stylesheet" type="text/css"> <link href="cancelform.css" rel="stylesheet" type="text/css" /> <link href="../styles/form_dark.css" rel="stylesheet" type="text/css" /> <body><br> <h3>My Details</h3> <div class="text"> Please keep your details updated below, for security reasons you cannot change your password.<br> <?php $id = $_GET['id']; include('../config.php'); $query=mysql_query("SELECT * FROM customers WHERE id='$id'"); while($row = mysql_fetch_assoc($query)) { $name = $row['name']; $email = $row['email']; } ?> <form class="dark" action="" method="post"> <ol> <li> <fieldset> <legend>My Details</legend> <ol> <li> <label for="name">Account Holder</label> <input type="text" id="name" name="name" value="<?php echo $name;?>" /> </li> <li> <label for="email">Contact/Login Email Address</label> <input type="text" id="email" name="email" value="<?php echo $email;?>" /> <input type="hidden" id="id" name="id" value="<?php echo $id;?>" /> </li> </ol> </fieldset> </li> </ol> <p style="text-align:right;"> <input type="reset" value="CANCEL" /> <input type="submit" value="UPDATE" name="update" /> </p> </form> Basically what is happening is that whatever you enter into the name box returns a 0 if its text or 1 if numbers are entered as opposed to storing the value inputed, if the email address is changed then nothing happens at all. Can someone see if I have made a noob mistake somewhere? The name and email fields are both varchar(256) in my database Thanks I have a value that in parts of my code i need to update. Its a number value, stored as TEXT. which i need to add numbers to it, at the moment I am using this to get the current value: Code: [Select] $sql2="SELECT * FROM weekly LIMIT 1"; $result2=mysql_query($sql2); $row2 = mysql_fetch_array( $result2 ); $rollingjackpot = $row2['rollingjackpot']; then i am adding the value to the varible, then using UPDATE to update it again, cant this be done in a simple query? something like: Code: [Select] $query = mysql_query("UPDATE weekly SET `rollingjackpot` + $amount WHERE `id` = '1'") or die(mysql_error()); okay, what i have is a page part of my ACP, and what i am trying to do is list all images from database, the list of images will have a "Checkbox" beside it. the checkbox is for setting where the image will be displayed. reason for the checkbox is cuz the images are only being displayed on 2 separate pages. basicly the whole list of images are in 1 form so when submit is activated its suppose to update the image list where checkboxs have been changed. hope i explained this clearly since im sick haha. but heres what i got for code Code: [Select] <form method="post"> <input type="submit" name="submit" value="Submit" /><br /> <?php $result = mysql_query("SELECT * FROM items") or die("Query Failed: ".mysql_error()); while($row = mysql_fetch_array($result)){ list($id, $item_info, $item_img, $price, $sale, $location) = $row; if($location == 'home'){ $set_checked = 'checked="checked"'; }else{ $set_checked = ''; } if(isset($_POST['location'])){ foreach($_POST['location'] as $value){ $id = $_POST['id']; $insert = mysql_query("UPDATE items SET location='$value' WHERE id='$id'") or die('Insert Error: '.mysql_error()); } } echo '<img src="../images/items/'.$item_img.'" width="100" /> Home Page Slide Show: <input type="checkbox" id='.$id.' value="home" name="location[]" '.$set_checked.' /><br />'; } ?> <input type="hidden" name="hdnLine" value="<? echo $count ?>" /> <input type="submit" name="submit" value="Submit" /> </form> i also added a pic of how it looks like lol Hi all, I'm trying to make a query that allows the user to edit the name of a entry in SQL. I believe I have the corect Syntax but I'm not sure if I have the code set up correctly. I am using 2 queries when I think it is possible with one. The first query is used to Pint out results for a certain year and the second to update the names. Code: [Select] $desiredYear = $_POST['year']; $nameEdit = $_POST['edit']; $origName = $_POST['orig']; echo ' The year you have chosen is '.$desiredYear; $describeQuery = "SELECT ID, Name, (SELECT SUM(SalesVolume) as SalesVolume FROM MonthlySales WHERE ProductCode=Products.ID AND Year = '$desiredYear') AS num_sales FROM Products"; $editQuery = "UPDATE Products SET Name = '$nameEdit' WHERE Name ='$origName'"; $results = sqlsrv_query($conn, $describeQuery); echo '<table border="1" BORDERCOLOR=Black>'; echo '<tr><th bgcolor = "LightBlue">Name</th><th bgcolor = "LightBlue" >ID</th> <th bgcolor = "LightBlue" >Sales</th></tr>'; while($row = sqlsrv_fetch_array($results, SQLSRV_FETCH_ASSOC)) { echo '<tr>'; echo '<td >' .$row['Name'].'</td>'; echo '<td>' .$row['ID'].'</td>'; echo '<td>' .$row['num_sales'].'</td>'; echo '</tr>'; } echo '</table>'; sqlsrv_close($conn); Can somebody help me with this? Thank you what Im basically trying to do is just like a phpmyadmin function... you select rows you want to update with a checkbox and then it takes you to a page where the rows that are clicked are shown in forms so that you can view and edit info in them... and then have 1 submit button to update them all at once. Hi guys need some help.I created a simple Update Customer Details page Where you Enter the Customer ID ,The Customer Details Get Displayed inside a Form and you make changes within the Form.But the update query I wrote is not working as it should be.It Executes the Query ,when I hardcode the Customer ID inside the Update query but fails when I need to Enter the Customer ID directly from the form using post.In This Code I tried to Update only the Customer's Firstname.Thanks Here Is The Code Code: [Select] <?php $db=mysql_connect("localhost","root","") or die('Unable to Connect To Database.Please check the Database Parameters'); mysql_select_db('ecommerce') or die(mysql_error()); if(isset($_POST['enterid'])) { $_POST['inputid']; } $query="SELECT * FROM customer WHERE Cid='$_POST[inputid]'"; $result=mysql_query($query) or die(mysql_error()); $row=mysql_fetch_array($result); $new_cid=$row['Cid']; $new_firstname=$row['Cfname']; $new_lastname=$row['Clname']; $new_email=$row['Email_id']; $new_address=$row['Address']; $new_pincode=$row['Pincode']; $new_payment=$row['Mode_of_payment']; $new_city=$row['City']; $new_state=$row['State']; $new_phone=$row['Phone']; $html1=<<<HTML1 <form action="updatecustomer.php" method="post"> <p class="inputidentifier">Please Enter The Customer's ID</p><input type="text" style="width:375px;height:40px;font-size:30px;" name="inputid" size="20"><br><br> <input type="submit" name="enterid" style="height:40px"> HTML1; print($new_cid); if(isset($_POST['update'])) { $query1="UPDATE customer SET Cfname='$_POST[firstname]' WHERE Cid='$_POST[inputid]'"; mysql_query($query1) or die(mysql_error()); if(mysql_affected_rows()==1) print("Query sucessful"); else print("Something went wrong"); } ?> <html> <head> <style type="text/css"> .inputtext {width:300px; height:40px;font-size:30px;} .inputidentifier{font-size:25px;font-family:"Arial"} .h1type{font-family:"Arial"} </style> <title>Test</title> </head> <body> <?php print($html1); ?> <h1 align="center" class="h1type">Update Customer Details</h1> <form action="updatecustomer.php" method="POST"> <table align="center" cellspacing="10" cellpadding="10" border="0" width="60%"> <tr> <td align="right" class="inputidentifier">First Name</td> <td align="left"><input type="text" class="inputtext" name="firstname" placeholder="eg:Kevin" value="<?php print($new_firstname) ?>"></td> </tr> <tr> <td align="right" class="inputidentifier">Last Name</td> <td><input type="text" class="inputtext" name="lastname" placeholder="eg:Aloysius" value="<?php print($new_lastname) ?>"></td> </tr> <tr> <td align="right" class="inputidentifier">E-mail</td> <td align="left"><input type="email" style="width:500" class="inputtext" name="email" placeholder="yourname@email.com" value="<?php print($new_email) ?>"> </tr> <tr> <td align="right" class="inputidentifier">Phone Number</td> <td align="left"><input type="text" class="inputtext" name="phone" placeholder="How Do We Call You?" value="<?php print($new_phone) ?>"></td> </tr> <tr> <td align="right" class="inputidentifier">Address</td> <td><textarea style="width:500;height:150" wrap="virtual" class="inputtext" name="address" placeholder="Where is your Crib?"><?php print($new_address) ?></textarea></td> </tr> <tr> <td align="right" class="inputidentifier">State</td> <td align="left"><input type="text" style="width:500" class="inputtext" name="state" placeholder="State" value="<?php print($new_state) ?>"> </tr> <tr> <td align="right" class="inputidentifier">City</td> <td align="left"><input type="text" class="inputtext" name="city" placeholder="City" value="<?php print($new_city) ?>"> </tr> <tr> <td align="right" class="inputidentifier">Pin Code</td> <td><input type="text" class="inputtext" name="pincode" placeholder="Mulund 400080" maxlength="6" value="<?php print($new_pincode) ?>"></td> </tr> <tr> <td align="right" class="inputidentifier">How do Pay for your Bling?</td> <td align="left"> <input type="text" class="inputtext" name="payment" value="<?php print($new_payment)?>"> </tr> <tr> <td></td> <td><input type="submit" name="update" value="Update!" style="width:100px;height:60px;"></td> </tr> </table> </form> </body> </html> This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=325938.0 So I filled out my edit form and I had it echo the query and it said exactly what it was supposed to but it didn't update it. Here's what the echo query looked like. UPDATE `efed_list_menu_items` SET `content_id`='0', `newscat`='0', `application_id`='1', `itemname`='Testing 3', `itemurl`='testing3.php', `sortorder`='3' WHERE `id` = '3' So im not really sure if this is possible but this is what I am trying to do.. I have a table that has a list of products...There is a spot for an image for each of these products. What I want to do is give a user the option to add an image to an existing product. I have one spot for image_name, ie: this_picture.jpg and and BLOB field for the image file called: image this is my code.. Code: [Select] mysql_connect("locahost","root","") or die(mysql_error()); mysql_select_db("my_db") or die(mysql_error()); $picture = $_FILES['image']['tmp_name']; if(!isset($picture)) echo ""; else { $image = addslashes(file_get_contents($_FILES['image']['tmp_name'])); $image_name = addslashes($_FILES['image']['name']); $image_size = getimagesize($_FILES['image']['tmp_name']); if($image_size==FALSE) echo "This is not an Image"; else{ if(!$insert = mysql_query ("UPDATE `Sheet1` SET `image_name` = '".$image_name."', `image`='".$image."' WHERE pro_id ='".$id."';")) echo "Problem Uploading Image."; else{ $lastid = mysql_insert_id(); echo "Image Uploaded!<p />".$text."<p /><p /> Your Image:<p /><img src=get.php?id=$lastid>"; } } } The get.php page basically just displays the image and works fine but if you would need to see it for some reason I can provide it. |
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