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PHP - How To Update Values Database Using Select Box
Hi guys,
Im developing a stock system and so far new stock and can be added with the quantity, however im trying to update the stock by using a select box and selecting the type of stock and inputting a new qty. the form and everything is set up and i can select files from the database, however i dont know how to update files from a select box The code i got so far is Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>stock manager</title> </head> <body> <?php $stockqty =&$_POST['stock_qty1']; ?> <center> <table> <td> <table> <td> <form action='stockview.php' method='POST'> Please Enter a Stock Name and Stock Value <table> <tr> <td> Stock Name: </td> <td> <input name="stock_name" type="text" /><BR /> </td> </tr> <tr> <td> Stock Qty: </td> <td> <input name="stock_qty" type="text" /> </td> </tr> </table> <input name="submit" type="submit" value="Add New Stock Items" /> </form> </td> </table> </td> <td> <table> <td> <form action='stockmanager.php' method='POST' enctype="multipart/form-data"> Please Select from the list the item you wish to update <table> <tr> <td> Stock Name: </td> <td> <?php $connect = mysql_connect("localhost","root", "") or die ("Couldn't Connect!"); mysql_select_db("stock", $connect) or die("Couldn't find db"); // select database $query=("SELECT id, stockname FROM stocks"); $result = mysql_query ($query); echo "<select name=stock value=''>Edit Stock QTY</option>"; while($nt=mysql_fetch_array($result)) { //Array or records stored in $nt echo "<option value=$nt[id]>$nt[stockname]</option>"; /* Option values are added by looping through the array */ } $queryreg = mysql_query("SELECT * FROM stocks WHERE stockqty='$stockqty'"); $numrows = mysql_num_rows($queryreg); $update = mysql_query("UPDATE stocks SET stockqty='$stockqty' WHERE stockname = '$stockname'"); echo("Its updated"); ?> </td> </tr> <tr> <td> Stock Qty: </td> <td> <input name="stock_qty1" type="text" /> </td> </tr> </table> <input name="submit" type="submit" value="Update stock items" /> </form> </td> </table> </td> </table> </center> </body> </html> Any help would be greatly appreciated. Thanks Lance Similar TutorialsHi guys, i have a select box which has been populated with values from the database however i would like to be able to select the value from the select box and change the qty. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>stock manager</title> </head> <body> <?php $stockqty =&$_POST['stock_qty1']; ?> <center> <table> <td> <table> <td> <form action='stockview.php' method='POST'> Please Enter a Stock Name and Stock Value <table> <tr> <td> Stock Name: </td> <td> <input name="stock_name" type="text" /><BR /> </td> </tr> <tr> <td> Stock Qty: </td> <td> <input name="stock_qty" type="text" /> </td> </tr> </table> <input name="submit" type="submit" value="Add New Stock Items" /> </form> </td> </table> </td> <td> <table> <td> <form action='stockmanager.php' method='POST' enctype="multipart/form-data"> Please Select from the list the item you wish to update <table> <tr> <td> Stock Name: </td> <td> <?php $connect = mysql_connect("localhost","root", "") or die ("Couldn't Connect!"); mysql_select_db("stock", $connect) or die("Couldn't find db"); // select database $query=("SELECT id, stockname FROM stocks"); $result = mysql_query ($query); echo "<select name=stock value=''>Edit Stock QTY</option>"; while($nt=mysql_fetch_array($result)) { //Array or records stored in $nt echo "<option value=$nt[id]>$nt[stockname]</option>"; /* Option values are added by looping through the array */ } $queryreg = mysql_query("SELECT * FROM stocks WHERE stockqty='$stockqty'"); $numrows = mysql_num_rows($queryreg); $update = mysql_query("UPDATE stocks SET stockqty='$stockqty' WHERE stockname = '$stockname'"); echo("Its updated"); ?> </td> </tr> <tr> <td> Stock Qty: </td> <td> <input name="stock_qty1" type="text" /> </td> </tr> </table> <input name="submit" type="submit" value="Update stock items" /> </form> </td> </table> </td> </table> </center> </body> </html> Any help would be greatly appreciated... ive been working on this for a while and cant seem to find the answer. Thanks Lance This has been bugging me for quite a while and I've tried so many different things and just run into all kinds of problems... What I'm doing or trying at least is pulling data from a table displaying it into a multiple select box allowing the user the oppertunity to remove one or more options. As the code stands now I'm getting no value at all in the post variable, by taking the [] brackets out of the inputs name i was able to get the first selected option but the php code was then unable to remove that value from the database. I hope I'm explaining this well enough but the code follows I'd really appreciate some help or direction on this one. The FORM Code: [Select] <FORM action='' method='post'> <select size='8' multiple name='remove_player[]'> <?php foreach ($members as $key => $mem) { if ($mem != "") { $mem = str_replace("-", " ", $mem); $mem = ucwords($mem); echo ("<option value='" . $mem . "'>" . $mem . "</option>"); } } ?> </select> and then the handler code: Code: [Select] $to_remove = $_POST['remove_player']; $as_team = str_replace(" ", "-", $teamname); $as_team = strtolower($as_team); $for_remove = "SELECT * FROM teams WHERE name = '$as_team'"; $for_query = (mysql_query($for_remove)); foreach ($to_remove as $y => $z) { $z = str_replace(" ", "-", $z); $z = strtolower($z); } while($arr_remove = mysql_fetch_array($for_query)) { foreach ($arr_remove as $a => $b) { foreach ($to_remove as $c => $d) { if ($b == $d) { unset($arr_remove[$a]); } } } foreach ($arr_remove as $e => $f) { $add_replace = (mysql_result($for_query, 0, 'members')); $replace = ($add_replace . "\r\n" . $f . "\r\n"); $replace_mem = "UPDATE teams SET members = '$replace'"; $replace_q = (mysql_query($replace_mem)); } } echo "Member List successfully updated.<br>"; foreach ($to_remove as $h => $g) { echo ($g . " removed from the team.<br>"); } Also any time i try to print any part of the array/s I get no values but the database is being updated with 2 line breaks and a "3" at the end of the table which has me a bit confused as well. Thanks! Or something like that... I am not sure how to put this.. Anyway, I'll just get started with explaining my problem. I have an admin-page in which you can delete the comments given on blogs, using checkboxes and clicking on a button with the value 'verwijderenSubmit'. The deletion part works just fine, nothing wrong. However, I also want to be able to EDIT the comments with an other button called 'bewerkenSubmit', using the same checkboxes that I use for deletion. Selecting the right CID (CommentID) is no problem, because that works the same as the deletion-part, but selecting the right textarea to update into the database is the problem... I uploaded a file here with the whole code: http://dhost.info/ddfs/myproblem.html I escaped the textarea within with square brackets, because otherwise the whole textarea would screw up.. I also added <!-- RELEVANT CODE --> to select the parts that I need to change. Well, I hope you understand my problem and can help. Hello everyone I need code for this question
would you help me please..?
Hi i have this simple update form and scrip but somehow it doesnt seem to be update the field on the database can someone help out please. The html form is the second form bellow where the action send to status_update.php HTML FORM Code: [Select] <?php include("../header.html"); ?> <?php include("header_news.html"); extract($_REQUEST,EXTR_SKIP); ?><?php /* print("sfilm_refnum = $sfilm_refnum<BR>"); print("sfilm_addr01 = $sfilm_addr01<BR>"); print("sfilm_postcode = $sfilm_postcode<BR>"); print("Film Client = $fclient<BR>"); */ ?> <form id="search" action="list.php" method="post" name="search"> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#eeeeee"> <tr> <td align="right" width="140"></td> <td width="320"><span class="hofblack10"> </span> </td> <td align="center" width="100"><input type="hidden" name="lstart" value="<?php print("$lstart"); ?>" /><input type="hidden" name="lend" value="<?php print("$lend"); ?>" /><input type="hidden" name="lamount" value="<?php print("$lamount"); ?>" /></td> <td align="center" width="100"></td> <td align="right"></td> </tr> </table> </form> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#4050c4"> <tr> <td width="60" class="hofwhite10">action</td> <td width="140"><span class="hofwhite14">DATE</span></td> <td width="80"><span class="hofwhite14">ID</span></td> <td><span class="hofwhite14">News Titile</span></td> <td width="100"><span class="hofwhite14">Status</span></td> </tr> <tr height="0"> <td bgcolor="white" width="60"></td> <td bgcolor="white" width="140" height="0"></td> <td bgcolor="white" width="80" height="0"></td> <td bgcolor="white" height="0"></td> <td bgcolor="white" width="100" height="0"></td> </tr> </table><table width="780" border="0" cellspacing="0" cellpadding="4"><tr> <td width="60"></td> <td width="80"></td> <td><a class="blueullrg" href="add.php">Add News</a></td> <td align="right" width="120"></td> </tr> <tr height="0"> <td width="60" height="0"></td> <td width="80" height="0"></td> <td height="0"></td> <td align="right" width="120" height="0"></td> </tr> </table> <?php //get the DB connection variables include("../../../includes/config.php"); //connect to DB $connection = @mysql_connect($db_address,$db_username,$db_password) or die("Couldn't CONNECT."); $db = @mysql_select_db($db_name, $connection) or die("Couldn't select DATABASE."); $query2="SELECT * FROM news WHERE !(news_status='deleted')"; $result2 = mysql_query($query2) or die("Couldn't execute QUERY - Select NEWS Qty"); $fqty = mysql_num_rows($result2); //SELECT or FIND the same USERNAME $query3="SELECT * FROM news WHERE !(news_status='deleted') ORDER BY news_id DESC"; $result3 = mysql_query($query3) or die("Couldn't execute QUERY - Select NEWS"); while ($row = mysql_fetch_array($result3)) { $news_id = $row['news_id']; $news_title = $row['news_title']; $news_story = $row['news_story']; $news_image = $row['news_image']; $news_image_caption = $row['news_image_caption']; $news_image_link = $row['news_image_link']; $news_date_day = $row['news_date_day']; $news_date_month = $row['news_date_month']; $news_date_year = $row['news_date_year']; $news_status = $row['news_status']; $news_website = $row['news_website']; $news_date_created = $row['news_date_created']; $news_date_modified = $row['news_date_modified']; ?> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#eeeeee"> <tr> <td width="60"><span class="hofblack10"> <?php if($news_status=="deleted"){ print("<a class='hifblack10'>deleted</span>"); }ELSE{ print("<a class='blueul' href='edit.php?id=$news_id'>edit</a>"); } ?> </span></td> <td width="140"><span class="titlegrey12"> <?php if(!$news_date_day) { echo "00"; } else{ echo $news_date_day; } echo "/"; if(!$news_date_month) { echo "00"; }else{ echo $news_date_month; } echo "/"; if(!$news_date_year) { echo "0000"; }else{ echo $news_date_year; } ?> </span></td> <td width="80"><span class="titlegrey12"><?php print("$news_id"); ?></span> </td> <td><?php if($news_status=="deleted") { print("<class='hofblack10'>$news_title</span>"); }ELSE{ print("<a class='blueul' href='edit.php?id=$news_id'>$news_title</a>"); } ?></td> <td width="100"> <form id="list_update" action="status_update.php" method="post" name="list_update"> <select name="newnstatus" size="1"> <option <?php if($row['news_status'] == "") { print("selected"); } ?> selected="selected" value="">Status...</option> <option <?php if($row['news_status'] == "on") { print("selected"); } ?> value="on">On</option> <option <?php if($row['news_status'] == "off") { print("selected"); } ?> value="off">Off</option> <option <?php if($row['news_status'] == "deleted") { print("selected"); } ?> value="deleted">Delete</option> </select> <input type="hidden" name="nstatus" value="<?php echo $row[news_status]; ?>" /> <input type="hidden" name="id" value="<?php echo $row[news_id]; ?>" /> <input type="submit" name="update" value="update" /> </form> </td> </tr> <tr height="0"> <td bgcolor="white" width="60"></td> <td bgcolor="white" width="140" height="0"></td> <td bgcolor="white" width="80" height="0"></td> <td bgcolor="white" height="0"></td> <td bgcolor="white" width="100" height="0"></td> </tr> </table> <?php } mysql_close($connection);//}?> <table width="780" border="0" cellspacing="0" cellpadding="4"> <tr> <td width="60"></td> <td width="80"></td> <td><a class="blueullrg" href="add.php">Add News</a></td> <td align="right" width="120"></td> </tr> </table><?php // include("list_navigation.html"); ?> <?php include("../footer.html"); ?> </div></body></html> The action script php Code: [Select] <?php /* echo "fstatus: ".$fstatus."<BR>"; echo "id: ".$id."<BR>"; echo "fclient: ".$fclient."<BR>"; echo "newfstatus: ".$newfstatus."<BR>";*/ //set the date of agreement $timestamp = date('l jS \of F Y h:i:s A'); //get the DB connection variables include("../../../includes/config.php"); //connect to DB $connection = @mysql_connect($db_address,$db_username,$db_password) or die("Couldn't CONNECT."); $db = @mysql_select_db($db_name, $connection) or die("Couldn't select FILMS DATABASE."); // All appears well, so enter into database $query= "UPDATE news SET news_status = '$newnstatus' WHERE news_id='$id'"; $result = mysql_query($query) or die("could not execute query - Update FILMS Record to DB"); //setup an email to the Admin @ hof, w/o attachment $emailto="xx@xxx.co.uk"; $emailfrom="no-reply@xxxx.co.uk"; $emailsubject="xx Record Updated"; $emailmessage="Hello Registrar\n\n"; $emailmessage.="News ID: ".$id."\n"; $emailmessage.="Updated on: ".$timestamp."\n\n"; $emailmessage.="Status was: ".$nstatus."\n"; $emailmessage.="Status now: ".$newfnstatus."\n"; $emailmessage.="Thank you,\n\n"; $emailmessage.="Web Site ROBOT\n"; $emailmessage.="(Administrator)\n"; $emailmessage.="xxx.co.uk | xxx.biz\n"; $emailmessage.="----------------------------------------------\n"; $emailmessage.="e. http://www.xxx.co.uk/contact.php\n"; $emailmessage.="w. http://www.xxx.co.uk\n"; $emailheader="From: xxx.co.uk<$emailfrom>"; $emailheader .= 'Cc: xxx@xxx.co.uk'."\r\n"; $emailheader .= 'Bcc: xxx@xxxxx.co.uk'."\r\n"; $ok=mail($emailto,$emailsubject,$emailmessage,$emailheader); mysql_close($connection); if ($ok) { header("Location: list.php"); /* Redirect browser */ exit; } else { $errmsg="There was a problem, please try later or telephone us direct."; $errsta="1"; include("edit_error.html"); //echo "<p>Mail could not be sent. Sorry!</p>"; exit; } ?> Thanks in advance what Im basically trying to do is just like a phpmyadmin function... you select rows you want to update with a checkbox and then it takes you to a page where the rows that are clicked are shown in forms so that you can view and edit info in them... and then have 1 submit button to update them all at once. after cloasing connection of database i still got the values form database. Code: [Select] <?php session_start(); /* * To change this template, choose Tools | Templates * and open the template in the editor. */ require_once '../database/db_connecting.php'; $dbname="sahansevena";//set database name $con= setConnections();//make connections use implemented methode in db_connectiong.php mysql_select_db($dbname, $con); //update the time and date of the admin table $update_time="update admin set last_logged_date =CURDATE(), last_log_time=CURTIME() where username='$uname'limit 3,4"; //my admin table contain 5 colums they are id, username,password, last_logged_date, last_log_time $link= mysql_query($update_time); // mysql_select_db($dbname, $link); //$con=mysql_connect('localhost', 'root','ijts'); $result="select * from admin where username='a'"; $result=mysql_query($result); mysql_close($con); //here i just check after closing data baseconnection whether i do get reselts but i do, why? echo "after the cnnection was closed"; if(!$result){ echo "cont fetch data"; }else{ $row= mysql_fetch_array($result); echo "id".$row[0]."usrname".$row[1]."passwped".$row[2]."date".$row[3]."time".$row[4]; } // echo "<html>"; //echo "<table border='1' cellspacing='1' cellpadding='2' align='center'>"; // echo "<thead>"; // echo"<tr>"; // echo "<th>"; // echo ID; // echo"</th>"; // echo" <th>";echo Username; echo"</th>"; // echo"<th>";echo Password; echo"</th>"; // echo"<th>";echo Last_logged_date; echo "</th>"; // echo "<th>";echo Last_logged_time; echo "</th>"; // echo" </tr>"; // echo" </thead>"; // echo" <tbody>"; //while($row= mysql_fetch_array($result,MYSQL_BOTH)){ // echo "<tr>"; // echo "<td>"; // echo $row[0]; // echo "</td>"; // echo "<td>"; // echo $row[1]; // echo "</td>"; // echo "<td>"; // echo $row[2]; // echo "</td>"; // echo "<td>"; // echo $row[3]; // echo "</td>"; // echo "<td>"; // echo $row[4]; // echo "</td>"; // echo "</tr>"; // } // echo" </tbody>"; // echo "</table>"; // echo "</html>"; session_destroy(); session_commit(); echo "session and database are closed but i still get values from doatabase session is destroyed".$_SESSION['admin']; ?> session is destroyed but database connection is not closed. thanks Guys, you are so going to be sick of me. But I really appreciate the help I am receiving here thus far. I have the code below sending the data from the form to the database. That's excellent. However, where I am stuck is doing the following two: 1. Updating currently inserted data 2. Displaying the data on the site. Here is settings.php: <?php include "../settings.php"; include "../lang/english.php"; include "../config/config.php"; $errors = array(); // condition and map inputs $fields = array('site_name'=>'sitename','site_email'=>'email','your_name'=>'name','meta_description'=>'meta-description','meta_keywords'=>'meta-keywords'); foreach($fields as $var => $field){ $$var = isset($_GET[$field]) ? trim($_GET[$field]) : ''; } // check if the form was submitted if(isset($_GET['submit'])){ // connect to/select database mysql_connect("$db_hostname", "$db_username", "$db_password") or die(mysql_error()); mysql_select_db("$db_database") or die(mysql_error()); // basic validation (not empty) and escape data foreach($fields as $var => $field){ if(empty($$var)){ $errors[] = "The form field: $field, is empty!"; } // escape the data $$var = mysql_real_escape_string($$var); } // if no validation errors, insert the data if(empty($errors)){ $insert = sprintf("INSERT INTO settings (site_name, description, keywords, email, name) VALUES ('%s','%s','%s','%s','%s')", $site_name, $meta_description, $meta_keywords, $site_email, $your_name ); if(!mysql_query($insert)){ // a query error occurred // check if due to duplicate data if(mysql_errno() == 1062){ // 1062 = duplicate primary key error (your error number might be different depending on your table definition) $errors[] = "The site name: $site_name, already exists and cannot be inserted!"; } else { // all other query errors - $errors[] = "A database error occurred and your query cannot be processed!"; trigger_error(mysql_error()); // use error_reporting/display_errors/log_errors to display/log the error condition } } else { echo "The data was successfully inserted!"; } } } //database_connect(); $sql = "UPDATE settings SET site_name='$site_name', description='$description', keywords='$keywords', email='$site_email', name='$your_name' WHERE id='$id'"; $query = mysql_query($sql)or die("There's a problem with the query: ". mysql_error()); if($query) echo "<br>The settings have been updated.<br>"; $_SESSION['tekst']=""; ?> <!DOCTYPE html> <html> <head> <title><?php echo $site_name; ?> :: :: Powered by osPHPSite</title> <meta http-equiv="content-type" content="text/html; charset=iso-8859-1" /> <link href="css/admin.css" rel="stylesheet" type="text/css" /> </head> <body> <div id="main"> <div id="header"> <h1><?php echo $sitename; ?></h1> <ul id="top-navigation"> <li><a href="index.php"><?php echo $lang_button_index; ?></a></li> <li><a href="settings.php" class="active"><?php echo $lang_button_settings; ?></a></li> <li><a href="pages.php"><?php echo $lang_button_pages; ?></a></li> <li><a href="gallery.php"><?php echo $lang_button_gallery; ?></a></li> <li><a href="/"><?php echo $lang_button_viewsite; ?></a></li> <li><a href="logout.php"><?php echo $lang_button_logout; ?></a></li> </ul> </div> <div id="middle"> <div id="left-column"> <h3><?php echo $eng_navigation; ?></h3> <ul class="nav"> <li><a href="index.php"><?php echo $lang_button_index; ?></a></li> <li><a href="settings.php"><?php echo $lang_button_settings; ?></a></li> <li><a href="pages.php"><?php echo $lang_button_pages; ?></a></li> <li><a href="gallery.php"><?php echo $lang_button_gallery; ?></a></li> <li><a href="/"><?php echo $lang_button_viewsite; ?></a></li> <li><a href="logout.php"><?php echo $lang_button_logout; ?></a></li> </ul> <a href="http://www.osphpsite.com" target="_blank" class="link">osPHPSite</a> <a href="http://www.osphpsite.com/forums/" target="_blank" class="link">Support Forums</a> <a href="http://www.vichost.com" target="_blank" class="link">VicHost.Com</a> </div> <div id="center-column"> <div class="table"> <?php if(!empty($errors)){ echo 'The following errors occurred:<br />'; foreach($errors as $error){ echo "$error<br />"; } } ?> <form action="" id="settings" name="settings"> <table class="listing form" cellpadding="0" cellspacing="0"> <tr> <th class="full" colspan="2">Site Configuration</th> </tr> <tr> <th colspan="2">From the options below, define the default settings for your website.</th> </tr> <tr> <th colspan="2"></th> </tr> <tr> <td>Site name: </td> <td><input type="text" name="sitename" value="<?php echo $site_name; ?>" width="172" /> <em>Site name for logo</em></td> </tr> <tr> <td>Email: </td> <td><input type="text" name="email" value="<?php echo $site_email; ?>" width="172" /> <em>Your email address</em></td> </tr> <tr> <td>Name: </td> <td><input type="text" name="name" value="<?php echo $your_name; ?>" width="172" /> <em>Your own name</em></td> </tr> <tr> <td>Meta Description: </td> <td><input type="text" name="meta-description" value="<?php echo $meta_description; ?>" width="172" /> <em>SEO</em></td> </tr> <tr> <td>Meta Keywords: </td> <td><input type="text" name="meta-keywords" value="<?php echo $meta_keywords; ?>" width="172" /> <em>Separate with Commas</em></td> </tr> <tr> <td><input type="submit" class="button" name="submit" value="Submit"></td> </tr> </table> </form> </div> </div> </div> </div> </body> </html> This will be a huge hurdle if I can get passed this one, I am well and truly on my way. Any help, advice etc that you can give, and what needs to go where, I would really appreciate it and I promise not to annoy you guys unless absolutely necessary. Hi all, I'm trying to figure out how to update values I have in an array. I'm a bit stuck and hope someone can advise. I've read about all sorts of bits but I'm stuck, I dont really understand associative so thought I'd post an example of my code for someone to hopefully assist.. so, if I have a table $fees, which is filled from a select, for example.. select * from `cases_fees`. "contains fields for id, type, amount and others now I want to do is foreach through that table and update a field called `amount`. but I cant understand the foreach >= as key part. what is a key and what isn't ? (I know what the keys of the db table arem but that's not the same eh?) I'm fine with normal foreach, but I cant update back to the array so I need to find out how to be able to set valus back into $fees[`amount`] hope someone can point me in the right direction please... Ted I want to update a value by setting cookie. I use this code: Code: [Select] <?php if (isset($_POST['ChangeOrdering'])) { setcookie("Ordering", $_POST['ChangeOrdering'], time() + 31536000); } echo $_COOKIE["Ordering"]; ?> <form method="post" action="<?php echo $_SERVER["PHP_SELF"] ?>"> Reorder messages: <select name="ChangeOrdering"> <option value="DateAdded ASC">Oldest first</option> <option value="DateAdded DESC">Newest first</option> <option value="Title ASC">By Title, A-Z</option> <option value="Title DESC">By Title, Z-A</option> </select> <input type="submit" value=" Save Settings " /> </form> Problem is that echo will return the previous cookie set, not the last value. As a matter of fact, my problem is about updating the cookie. It seems that the browser load the cookie before it is updated by the POST value. I am trying to get info from a table, add rows in that table, and put the added value back into the table in another field...I want to add field1 and field2 of every row and put the total in the total row. Heres what the echo gives me Susan 14 Mary 18 Bob 13 Sam 21 heres the database mysql> SELECT total_val FROM table; +-----------+ | total_val | +-----------+ | 21 | | 21 | | 21 | | 21 | +-----------+ heres the code.... <?php require("connection.php"); mysql_select_db("database", $connection); echo "<br />"; $result = mysql_query("SELECT * FROM table"); while($row = mysql_fetch_array($result)) { $values = ($row['field1'] + $row['field2']); $sql=mysql_query("UPDATE table SET total = '$values'"); echo $row['user_name'] . " " . $values; echo "<br />"; } ?> also note that if I put a INT in place of $values - the echo changes to match...why?? PLEASE help...I have been working on this for 2 entire days.... Friends, I have the following table:
SELECT * FROM tbl1; +----+-------+-------+ | id | col_1 | col_2 | +----+-------+-------+ | 1 | 1 | NULL | | 2 | 2 | 2 | | 3 | NULL | 3 | | 4 | 4 | NULL | +----+-------+-------+ 4 ROWS IN SET (0.00 sec)So, if I wanna update only the null values of col_2 with these from col_1 or vice versa I'm running the following update statement with mysql ifnull() func. mysql> UPDATE test.tbl1 t1 SET t1.col_2 = ifnull(t1.col_2, t1.col_1), t1.col_1= ifnull(t1.col_1, t1.col_2); Query OK, 3 ROWS affected (0.06 sec) ROWS matched: 4 Changed: 3 Warnings: 0Is there a way to use LEFT JOIN to get all null values from every columns and rows, then to update the columns in the same way? I notice that the sub-query failed for me within an update statement. Hi there, I'm having a problem with updating a record with an UPDATE mysql query and then following that query with a SELECT query to get those values just updated. This is what I'm trying to do...I'd like a member to be able to complete a recommended task and upon doing so, go to a page in their back office where they can check off that task as "Completed". This completed task would be recorded in their member record in our database so that when they return to this list, it will remain as "Completed". I'm providing the member with a submit button that will call the same page and then update depending on which task is clicked as complete. Here is my code: Code: [Select] $memberid = $_SESSION['member']; // Check if form has been submitted if(isset($_POST['task_done']) && $_POST['task_submit'] == 'submitted') { $taskvalue = $_POST['task_value']; $query = "UPDATE membertable SET $taskvalue = 'done' WHERE id = $memberid"; $result = mysqli_query($dbc, $query); } $query ="SELECT task1, task2, task3 FROM membertable WHERE id = $memberid"; $result = mysqli_query($dbc, $query); $row = mysqli_fetch_array($result, MYSQLI_ASSOC); $_SESSION['task1'] = $row['task1']; $_SESSION['task2'] = $row['task2']; $_SESSION['task3'] = $row['task3']; ?> <h4>Task List</h4> <table> <form action="" method="post"> <tr> <td>Task 1</td> <td><?php if($_SESSION['task1'] == 'done') {echo '<div>Completed</div>';} else{ echo '<input type="submit" name="task_done" value="Mark As Completed" />';} ?></td> </tr> <input type="hidden" name="task_value" value="task1" /> <input type="hidden" name="task_submit" value="submitted" /> </form> <form action="" method="post"> <tr> <td>Task 1</td> <td><?php if($_SESSION['task1'] == 'done') {echo '<div>Completed</div>';} else{ echo '<input type="submit" name="task_done" value="Mark As Completed" />';} ?></td> </tr> <input type="hidden" name="task_value" value="task2" /> <input type="hidden" name="task_submit" value="submitted" /> </form> <form action="" method="post"> <tr> <td>Task 1</td> <td><?php if($_SESSION['task1'] == 'done') {echo '<div>Completed</div>';} else{ echo '<input type="submit" name="task_done" value="Mark As Completed" />';} ?></td> </tr> <input type="hidden" name="task_value" value="task3" /> <input type="hidden" name="task_submit" value="submitted" /> </form> </table> The problem that I am having is that the database is not updated with the value "done" but after submission, the screen displays "Completed" instead of "Mark As Completed". So the value is being picked up as "done", but that is why I have the SELECT after the UPDATES, so that there is always a current value for whether a task is done or not. Then I refresh and the screen returns the button to Mark As Complete. Also, when I try marking all three tasks as, sometimes all three are updated, sometimes only one or two and again, I leave the page or refresh and the "Marked As Completed" buttons come back. Bizarre. If anyone can tell me where my logic is going wrong, I would appreciate it. Well, I made this yesterday then realised, I need to check is it exists... I got this but when I go to accept the application and the member exists in the table it enters it anyway... Code: [Select] <?php $member=$_POST['memberid']; $status=$_POST['Status']; $con = mysql_connect("host","user","pass"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("a2186214_hbclan",$con); $sql="UPDATE application SET Status = '$status' WHERE ID = '$member'"; $sql1="INSERT INTO table_members(name) SELECT application.Name FROM application WHERE application.ID = '$member'"; if ($status == 'ACCEPTED') { if(mysql_num_rows(mysql_query("SELECT name FROM table_members WHERE name = '$member'"))) { if(mysql_query($sql, $con) or die(mysql_error())) { echo 'Status Changed.<br /><a href="../applications.php">Return To Members List</a>'; } else { die('Could not submit: ' . mysql_error()); } } else { if(mysql_query($sql, $con) or die(mysql_error())) { if(mysql_query($sql1, $con) or die(mysql_error())) { echo 'Status Changed.<br /><a href="../applications.php">Return To Members List</a>'; } } else { die('Could not submit: ' . mysql_error()); } } } else { if(mysql_query($sql, $con) or die(mysql_error())) { echo 'Status Changed.<br /><a href="../applications.php">Return To Members List</a>'; } else { die('Could not submit: ' . mysql_error()); } } mysql_close($con); ?> I am trying to update a mysql table called AvItems with the value 'Torso' in the Equip "section?" I have been through the forums and cannot see anything to match. I dont mind if the page looses the onsubmit() and has a button instead. Though I would like to update the database and link back to the same page: There is a display that shows the item that is currently equiped, I have put this in to show it works, or doesn't as the case may be. Hope I got the code /code right this time. many thanks in advance Andy Curtis Code: [Select] create table Items( ItemID integer unsigned auto_increment primary key, ItemName varchar(20) not null, Type varchar(10), UsedOn varchar(10), ); create table AvItems( AvItemID integer unsigned auto_increment primary key, AvID integer unsigned, ItemID integer unsigned, Equip varchar(8)); <?php $username="root"; $password="MyPassword"; $database="MyDataBase"; $AvName = "AndyJCurtis"; mysql_connect(localhost,$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $AvAccR = mysql_query( " SELECT AvID FROM AvAcc WHERE AvName = '$AvName' " ); $AvID = mysql_result($AvAccR, 0, 'AvID'); /////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// $Torso = mysql_query(" select ItemName from AvItems, Items where AvItems.itemID = Items.itemID AND AvItems.AvID = '$AvID' AND UsedON = 'Body' "); $TorsoE = mysql_query(" select ItemName from AvItems, Items where AvItems.itemID = Items.itemID AND AvItems.AvID = '$AvID' And UsedON = 'Body' AND Equip = 'Body' "); if(mysql_num_rows($TorsoE) != 0) { $TorsoItem = mysql_result($TorsoE ,0,"ItemName"); //mysql_close(); ?> <title></title> <head></head> <body> <form action="http://localhost/CI/Equip2.php" method="post"> <table border=1> <tbody> <tr> <td>Torso<BR> <?PHP echo "$TorsoItem <BR>"; ?> <select name="Torso" onchange="submit();" value =" Update"> <?PHP while($TorsoRow = mysql_fetch_array($Torso)) { echo "<option value=\"".$TorsoRow['ItemName']."\">".$TorsoRow['ItemName']."\n </option>"; } ?> </select> </td> </tr> //////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// <?php if($_POST['Torso'] == 'Update') { mysql_query("update AvItems set Equip = '' where Equip='Torso'") or die("cant update unequip"); mysql_query("update AvItems set Equip = 'Torso' where ItemID='{$_POST['ItemName']}'") or die("cant update equip"); } ?> /////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// </tbody> </table> </.form> </body> </html>
In the same $-POST , i wanted to perform update and delete. With the updated and deleted database, I need to select the updated data from the database. However, it tells me: Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in... .I am new to sql in php, is it true that i cannot perform sql in this way? Or is there any suggestion to perform select straight after deleting and updating?
CANCEL BOOK RESERVATION
if(isset($_POST['cancelres']))
{
$query = "DELETE FROM reserved_books WHERE id='$resid';"; //delete reservation
$query .="UPDATE reserved_books SET queue = queue - 1 WHERE bookid = '$bookid' AND queue > '$bookqueue';";//update queue number where reservation that queue behind/after/ the current reservation
$query_run = mysqli_multi_query($connection, $query);
if($query_run)
{
$_SESSION['success'] = "Reservation Cancelled";
}
else
{
$_SESSION['status'] = " Reservation Not Cancelled";
}
$query= "SELECT title FROM books WHERE id = '$bookid';"; //get book title from db
$query_run = mysqli_query($connection,$query);
if(mysqli_num_rows($query_run)>0)
{
foreach ($query_run as $row) {
$title = $row['title'];
}
}
$bookres = "SELECT * FROM reserved_books WHERE bookid = '$bookid' AND queue = 1";
$bookres_run = mysqli_query($connection,$bookres);
foreach($bookres_run as $row)
{
$res_username = $row['username'];
$res_id = $row['id'];
}
$query= "SELECT option_value FROM settings WHERE option_name = 'email_temp_rescollect'"; //get email template from db
$query_run = mysqli_query($connection,$query);
if(mysqli_num_rows($query_run)>0)
{
$row = mysqli_fetch_array($query_run);
$rescollect_template = $row[0];
}}
There are about 400 records in a database with a field zabp_package = T_SIMT. They were uploaded in an order where specific category lists were uploaded together. For example, first 100 dining, then 75 insurance, then 150 health, then 75 cars. So from an auto increment standpoint they were inserted in that order. I want to select at random 100 of these 400 and update two fields. My update statement is: update `usersOld` SET `m_org` = 'ZABP.org Corporate HQ' , `m_orgID` = 'PFL2a96bW' WHERE `zabp_package` = 'T_SIMT' This works for all, I just need to limit a random selection to 100. Any Help on this, thanks in advance. I have a Prepared Statement that runs a SELECT statement and returns 2 records, and I would like to store the Field Value for each Record into an Array. Here is the code I usually use for queries that return just a single value... // ****************** // Populate Form. * // ****************** // Build query. $q2 = "SELECT response FROM bio_answer WHERE member_id=?"; // Prepare statement. $stmt2 = mysqli_prepare($dbc, $q2); // Bind variable to query. mysqli_stmt_bind_param($stmt2, 'i', $memberID); // Execute query. mysqli_stmt_execute($stmt2); // Store results. mysqli_stmt_store_result($stmt2); // Check # of Records Returned. if (mysqli_stmt_num_rows($stmt2)>0){ // Details Found. // Bind result-set to variable. mysqli_stmt_bind_result($stmt2, $response); // Fetch record. mysqli_stmt_fetch($stmt2); // Close prepared statement. mysqli_stmt_close($stmt2); }else{ // Details Not Found. $_SESSION['resultsCode'] = 'DETAILS_NOT_FOUND_2133'; // Close prepared statement. mysqli_stmt_close($stmt2); // Set Error Source. $_SESSION['errorPage'] = $_SERVER['SCRIPT_NAME']; // Redirect to Display Outcome. header("Location: " . BASE_URL . "/members/results.php"); // End script. exit(); }//End of POPULATE FORM Can someone help me out with the syntax so that I get an end result like this... $answerArray[0] = 'I want to be my own boss!!' $answerArray[1] = 'Don't waste your time trying to do your own Taxes!' Thanks, Debbie Hi all i have 2 small questions and maybe someone could help me out. Say I have a database with a table 'users'. This table has fields: email, name and year. What I want to do is show at the front-end all users, by selecting them from the table, and arrange them by year in column 1 and show them as individuals in column 2. But here is the thing; if someone selects for instance year 1970 and also someone from 1970 individually, someone will be selected twice. (edit:As a side note the selecting is aimed and emailing the users, that's why selecting someone twice is not good First question is: does anyone know how to remove doubles (maybe even triples if there is a select all button, maybe turn this around and say select only 1 instance of a user). Second question: is this a wise way to let someone select. Right now all users are fetched, and if the table users grows this could be tricky because of the large number of users. If someone could point me in the right direction of thinking I would be very happy, been thinking about this and scalability for quite a while now Hi, all... have a basic question here as a newbie that I am... Many times, in some scripts I see (I think, if not mistaken), places where within a echo sentence I see variables echoed like this with no quotes: echo "First Name: $firstName and Last Name: $lastName"; as opposed to like one would expect: echo "First Name: " . $firstName . " and Last Name: " . $lastName"; Sometimes I see that also when variables are used in select/update statements I think.. like this: $query = mysql_query("SELECT FROM table WHERE column = $columnname"); Instead of like this within quotes: $query = mysql_query("SELECT FROM table WHERE column = '$columnname'"); Is it because some of these values may be numbers (numeric) as opposed to "strings"?? Not sure if I make sense... appreciate teh feedback, Thanks! |
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