PHP - Values Wont Add To Db
hi guys hope some1 can help.
im creating a system that will allow stock to be added to a database and modifed. However on the add section, nothing adds it only inputs a new id row in the database and the other fields are blank. Can anyone have a look for me This sections is the form handler once the user has input a stockname and stock qty Code: [Select] <?php session_start(); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>stock</title> </head> <body> <?php $stockname = &$_POST['stockname']; $stockqty = &$_POST['stockqty']; $connect = mysql_connect("localhost","root", "") or die ("Couldn't Connect!"); mysql_select_db("stock", $connect) or die("Couldn't find db"); // select database $query = mysql_query("SELECT * FROM stocks WHERE stockname=$stockname, stockqty=$stockqty"); $numrows = mysql_num_rows($query); if ($numrows!=0) { echo("Item already exists! Try Updating the items instead!"); } else { $queryreg = mysql_query("INSERT INTO `stock` . `stocks` (`id`, `stockname`, `stockqty`) VALUES (NULL,'$stockname','$stockqty')"); echo("stock added!"); } ?> <center><table> <tr> <td> Stock_id </td> <td> Stock_name </td> <td> Stock_Qty </td> </tr> </table></center> </body> </html> Thanks Lance Similar Tutorials
Table Issue - Multiple Location Values For User Pushes Values Out Of Row Instead Of Wrapping In Cell
whats wrong in here for i get query failed everytime i submit the form? Code: [Select] //Create INSERT query $qry = "INSERT INTO class_members (user_name, passwrd, f_name, l_name, email, gender, date) VALUES('$user_name','".md5($_POST['password'])."','$f_name','$l_name','$email', '$gender','gmdate($date)',)"; $result = @mysql_query($qry); //Check whether the query was successful or not if($result) { header("location: register-success.php"); exit(); }else { die("Query failed"); } i need help trying to get this delete feature to work its not deleting from the database (by the way i took out my database names and passwords at the top of the file) is it possible someone could help me, ive been working on this for like a week and cant figure out the problem. thanks! you can email me at spr_spng@yahoo.com picture 2.png is showing what it looks like Code: [Select] <?php $host="localhost"; // Host name $username="username"; // Mysql username $password="password"; // Mysql password $db_name="database_name"; // Database name $tbl_name="table_name"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); $count=mysql_num_rows($result); ?> <style> /*table affects look of the whole table look */ table { margin-left: auto; margin-right: auto; border: 1px solid #330000; border-collapse:collapse; width:70%; border-width: 5px 5px 5px 5px; border-spacing: 1px; border-style: outset outset outset outset; border-color: #330000 #330000 #330000 #330000; border-collapse: separate; background-color: #330000; #800517 f535aa #330000 school color #9A0000 school color2 #991B1E school color3 #CCCC99 school color4 #9A0000 } /*th is table header */ th { text-align: left; height: 2.5em; background-color: #330000; color: #FC0; font-size:1.5em; } /*td is table data or the cells below the header*/ td { text-align: left; height:1.0em; font-size:1.0em; vertical-align:bottom; padding:10px; border-width: 5px 5px 5px 5px; padding: 8px 8px 8px 8px; border-style: outset outset outset outset; border-color: #9A0000 #9A0000 #9A0000 #9A0000; background-color: #CCCC99; -moz-border-radius: 0px 0px 0px 0px; } </style> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <td><form name="form1" method="post" action=""> <table width="400" border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td bgcolor="#FFFFFF"> </td> <td colspan="4" bgcolor="#FFFFFF"><strong>Pick Which Rows you want to delete, Then press delete.</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"><strong>Id</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Name</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Lastname</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Email</strong></td> <td align="center" bgcolor="#FFFFFF">delete</td></tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td bgcolor="#FFFFFF"><? echo $rows['id']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['name']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['lastname']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['email']; ?></td> <td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<? echo $rows['id']; ?>"></td> </tr> <?php } ?> <tr> <td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete" value="Delete"></td> </tr> <? // Check if delete button active, start this // edited if($delete){ for($i=0;$i<$count;$i++){ $del_id = $checkbox[$i]; $sql = "DELETE FROM $tbl_name WHERE id='$del_id'"; $result = mysql_query($sql); } // if successful redirect to delete_multiple.php if($result){ echo "<meta http-equiv=\"refresh\" content=\"0;URL=delete_multiple.php\">"; } } mysql_close(); ?> </table> </form> </td> </tr> </table> Dear All Members here is my table data.. (4 Columns/1row in mysql table)
id order_no order_date miles How to split(miles) single column into (state, miles) two columns and output like following 5 columns /4rows in mysql using php code.
(5 Columns in mysql table) id order_no order_date state miles 310 001 02-15-2020 MI 108.53 310 001 02-15-2020 Oh 194.57 310 001 02-15-2020 PA 182.22
310 001 02-15-2020 WA 238.57 ------------------my php code -----------
<?php
if(isset($_POST["add"]))
$miles = explode("\r\n", $_POST["miles"]);
$query = $dbh->prepare($sql);
$lastInsertId = $dbh->lastInsertId(); if($query->execute()) {
$sql = "update tis_invoice set flag='1' where order_no=:order_no"; $query->execute();
} ----------------- my form code ------------------
<?php -- Can any one help how to correct my code..present nothing inserted on table
Thank You Edited February 8, 2020 by karthicbabuHi, My company has 240+ locations and as such some users (general managers) cover multiple sites. When I run a query to pull user information, when the user has multiple sites to his or her name, its adds the second / third sites to the next columns, rather than wrapping it inside the same table cell. It also works the opposite way, if a piece of data is missing in the database and is blank, its pull the following columns in. Both cases mess up the table and formatting. I'm extremely new to any kind of programming and maybe this isn't the forum for this question but figured I'd give it a chance since I'm stuck. The HTML/PHP code is below: <table id="datatables-column-search-select-inputs" class="table table-striped" style="width:100%"> <thead> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> <th>Actions</th> </tr> </thead> <tbody> <?php //QUERY TO SELECT ALL USERS FROM DATABASE $query = "SELECT * FROM users"; $select_users = mysqli_query($connection,$query);
// SET VARIABLE TO ARRAY FROM QUERY while($row = mysqli_fetch_assoc($select_users)) { $user_id = $row['user_id']; $user_firstname = $row['user_firstname']; $user_lastname = $row['user_lastname']; $username = $row['username']; $user_phone = $row['user_phone']; $user_image = $row['user_image']; $user_title_id = $row['user_title_id']; $user_role_id = $row['user_role_id'];
// POPULATES DATA INTO THE TABLE echo "<tr>"; echo "<td>{$user_id}</td>"; echo "<td>{$user_firstname}</td>"; echo "<td>{$user_lastname}</td>"; echo "<td>{$username}</td>"; echo "<td>{$user_phone}</td>";
//PULL SITE STATUS BASED ON SITE STATUS ID $query = "SELECT * FROM sites WHERE site_manager_id = {$user_id} "; $select_site = mysqli_query($connection, $query); while($row = mysqli_fetch_assoc($select_site)) { $site_name = $row['site_name']; echo "<td>{$site_name}</td>"; } echo "<td>{$user_title_id}</td>"; echo "<td>{$user_role_id}</td>"; echo "<td class='table-action'> <a href='#'><i class='align-middle' data-feather='edit-2'></i></a> <a href='#'><i class='align-middle' data-feather='trash'></i></a> </td>"; //echo "<td><a href='users.php?source=edit_user&p_id={$user_id}'>Edit</a></td>"; echo "</tr>"; } ?>
<tr> <td>ID</td> <td>FirstName</td> <td>LastName</td> <td>Username</td> <td>Phone #</td> <td>Location</td> <td>Title</td> <td>Role</td> <td class="table-action"> <a href="#"><i class="align-middle" data-feather="edit-2"></i></a> <a href="#"><i class="align-middle" data-feather="trash"></i></a> </td> </tr> </tbody> <tfoot> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> </tr> </tfoot> </table>
Hi all, Just curious why this works: Code: [Select] while (($data = fgetcsv($handle, 1000, ",")) !== FALSE){ $import="INSERT into $prodtblname ($csvheaders1) values('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]','$data[5]','$data[6]')"; } And this does not: $headdata_1 = "'$data[0]','$data[1]','$data[2]','$data[3]','$data[4]','$data[5]','$data[6]'"; while (($data = fgetcsv($handle, 1000, ",")) !== FALSE){ $import="INSERT into $prodtblname ($csvheaders1) values($headdata_1)"; }it puts $data[#'s] in the database fields instead of the actual data that '$data[0]','$data[1]'... relates to. I wrote a script to create the values in $headdata_1 based on the number of headers in $csvheaders1 but can't seem to get it working in the sql statement. Thanks Hi all, I'm a first time poster here and I would really appreciate some guidance with my latest php challenge! I've spent the entire day googling and reading and to be honest I think I'm really over my head and need the assistance of someone experienced to advise the best way to go! I have a multi dimensional array that looks like (see below); the array is created by CodeIgniter's database library (the rows returned from a select query) but I think this is a generic PHP question as opposed to having anything to do with CI because it related to working with arrays. I'm wondering how I might go about searching the array below for the key problem_id and a value equal to a variable which I would provide. Then, when it finds an array with a the matching key and variable, it outputs the other values in that part of the array too. For example, using the sample data below. How would you recommend that I search the array for all the arrays that have the key problem_id and the value 3 and then have it output the value of the key problem_update_date and the value of the key problem_update_text. Then keep searching to find the next occurrence? Thanks in advance, as above, I've been searching really hard for the answer and believe i'm over my head! Output of print_r($updates); CI_DB_mysql_result Object ( [conn_id] => Resource id #30 [result_id] => Resource id #35 [result_array] => Array ( ) [result_object] => Array ( ) [current_row] => 0 [num_rows] => 5 [row_data] => ) Output of print_r($updates->result_array()); Array ( [0] => Array ( [problem_update_id] => 1 [problem_id] => 3 [problem_update_date] => 2010-10-01 [problem_update_text] => Some details about a paricular issue [problem_update_active] => 1 ) [1] => Array ( [problem_update_id] => 4 [problem_id] => 3 [problem_update_date] => 2010-10-01 [problem_update_text] => Another update about the problem with an ID of 3 [problem_update_active] => 1 ) [2] => Array ( [problem_update_id] => 5 [problem_id] => 4 [problem_update_date] => 2010-10-12 [problem_update_text] => An update about the problem with an ID of four [problem_update_active] => 1 ) [3] => Array ( [problem_update_id] => 6 [problem_id] => 4 [problem_update_date] => 2010-10-12 [problem_update_text] => An update about the problem with an ID of 6 [problem_update_active] => 1 ) [4] => Array ( [problem_update_id] => 7 [problem_id] => 3 [problem_update_date] => 2010-10-12 [problem_update_text] => Some new update about the problem with the ID of 3 [problem_update_active] => 1 ) ) Why isn't this working? elseif($db_password==md5($password)) Hey all, I have an odd problem that I hope someone here has had and knows how to fix. I recently installed Apache, PHP, and MySQL on a new server we have at work. Everything works fine, oddly enough, except for PHP parsing. You see the following code: Code: [Select] <? echo "test"; ?> Will display the PHP code, while Code: [Select] <?php echo "test"; ?> Will echo "test". The problem seems to be that PHP isnt parsing the <? directive as a start command. Does anyone have any idea why this might be? Thanks for any help. $last = mysql_query("SELECT MAX('id') FROM comments WHERE submittedby='$username'"); can any1 help me? For some reason i cannot for the life of me find, from the below code, <? echo $price ?> is returning nothing, could someone please take a look at this and explain to me where I'm going wrong, Would appreciate it tonnes, Thanks Freddy. Code: [Select] <?php //get item information $AttributeID = mysql_real_escape_string($_GET['AttributeID']); $sql = "SELECT * FROM attributes as a WHERE a.id = $AttributeID"; $query = mysql_query($sql) or die(mysql_error()); $attribute = mysql_fetch_array($query); $price = $attribute['SkillPoints']; //check for attribute $sql = "SELECT * FROM player_attributes WHERE player_id = $playerID AND attribute_id = $AttributeID"; $query = mysql_query($sql) or die(mysql_error()); $att = mysql_fetch_array($query); $quan = $att['quantity']; if ($quan == 0){ $quan = 0; }else{ $quan = ($quan); } if($quan == 0) { $price = ($price); }else{ } if ($quan >='1'){ $price = ($quan + $price); } ?> Ok, I am a complete noob when it comes to php. I am slowly learning it but I turned to youtube for a tutorial on a registration/login page. I found a good tutorial http://www.youtube.com/watch?v=ngqeWUIDlnk&feature=channel but for some reason my php is NOT working. I have it exactly the way he does but it wont echo anything or work at all. The login page worked great in his tutorial. What do I have wrong? I cant figure it out. Please help! echo "<h1>Register</h1>"; $submit = $_POST['submit']; $fullname = strip_tags($_POST['name']); $username = strip_tags($_POST['user']); $password = strip_tags($_POST['password']); $verifypassword = strip_tags($_POST['verifypassword']); $date = date("Y-m-d"); if ($submit) { if($fullname&&$username&&$password&&$verifypassword) { password = md5($password); verifypassword= = md5($verifypassword); } else echo "Please fill in all fields!"; } Code: [Select] <html> <form action='register.php' method='POST'> <table> <tr> <td>Full Name:</td> <td><input type='text' name='name'></td> </tr> <tr> <td>Username:</td> <td><input type='text' name='user'></td> </tr> <tr> <td>Password:</td> <td><input type='password' name='password'></td> </tr> <tr> <td>Verify Password:</td> <td><input type='password' name='verifypassword'></td> </tr> </table> <p><input type='submit' name='submit' value='Submit'></p> </form> </html> I use mysql and this code that I will show says that the info was sucessfully updated, but it wasnt. please help. By the way, I am designing a website for a boy scout troop that has asked me to help. any help appreciated: Code: [Select] <?php session_start(); // Must start session first thing /* Created By Adam Khoury @ [URL=http://'http://www.flashbuilding.com/']www.flashbuilding.com[/URL] -----------------------June 20, 2008----------------------- */ // Here we run a login check if (!isset($_SESSION['id'])) { echo 'Please <a href="login.php">log in</a> to access your account'; exit(); } //Connect to the database through our include include_once "connect_to_mysql.php"; // Place Session variable 'id' into local variable $id = $_SESSION['id']; // Query member data from the database and ready it for display $sql = mysql_query("SELECT * FROM members WHERE id='$id' LIMIT 1"); while($row = mysql_fetch_array($sql)){ $rank = $row['rank']; } // Process the form if it is submitted if ($_POST['rank']) { $rank = $_POST['rank']; $sql = mysql_query("UPDATE members SET rank='$rank' where id='$id'"); echo 'Your account info has been updated, visitors to your profile will now see the new info.<br /><br /> <meta HTTP-EQUIV="REFRESH" content="3; url=http://final.net46.net/myprofile.php">'; exit(); } // close if post ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Untitled Document</title> </head> <body> <form id="form1" name="form1" method="post" action="scout.php" onsubmit="return validate_form ( );"> <label for="rank"></label> <select name="rank" id="rank"> <option value="Scout">Scout</option> <option value="Tenderfoot">Tenderfoot</option> <option value="Second Class Scout">Second Class Scout</option> <option value="First Class Scout">First Class Scout</option> <option value="Star Scout">Star Scout</option> <option value="Life Scout">Life Scout</option> <option value="Eagle Scout">Eagle Scout</option> <option value="<?php echo $rank; ?>" selected="selected"></option> </select> <input type="submit" name="submit" id="submit" value="Save" /> </form> </body> </html> Any idea why I cant get the order by to work? $res = mysql_query ("SELECT COUNT(*), LEFT(`comment`, 3) AS truncated from comments where navn='$rows[navn]' AND adresse='$rows[adresse]' ORDER BY time desc" ) or die(mysql_error()); HI im having a problem displaying an image in an iframe or img tag on my php page if i set the source to google it displays fine in the iframe! but if i set the source to a page on my server it doesnt display. It displays in both fire fox and chrome!???? Any help would be greatly appreciated Thanks Sean Ive got some like code like this (this is a part of my source, it'll be enough to solve my problem). I've got 4 functions here trying to run them using switch statement, but only the default one is running, why ? Code: [Select] <?php //******PETLJA ZA MENI*******// switch(@$HTTP_GET_VARS["method"]) { case "ShowAdd": GetNewPollDetails(); break; case "AddFinal": AddPoll(); break; case "ShowDelete": GetPollToDelete(); break; case "DeleteFinal": DeletePoll(); break; default: GetChoice(); } function GetChoice(){ ?> <ul> <li><h2><a href="managepoll.php?method=ShowAdd">Dodaj anketu</a></h2></li> <li><h2><a href="managepoll.php?method=ShowDelete">Izbrisi anketu</a></h2></li> <li><h2><a href="managepoll.php?method=DeleteFinal">Pregledaj ankete</a></h2></li> </ul> <?php } ?> <?php function GetNewPollDetails(){ ?> <h1>Nova anketa</h1> <form name="DodajAnketu" action="managepoll.php?method=AddFinal"> <br /> Pitanje Ankete:<input name="text" type="text" width="150"/> <br /> Odogovor 1:<input name="text2" type="text" width="150"/> <br /> Odogovor 2:<input type="text" width="150"/> <br /> Odogovor 3:<input type="text" width="150"/> <br /> Odogovor 4:<input type="text" width="150"/> <br /> Odogovor 5:<input type="text" width="150"/> <br /> <input type="submit" value="Napravi" name="napravi" /> </form> <?php } ?> Hey everyone,
Calling all web devs, so here is my problem from the gecko. I am currently using a free flux theme. The problem is that it has a rss feed news box. I have phpbb forums and i used the link and it wont show. I'm not sure why i did alot of research and it seems it happens because my forums use a php based feed. I do not know how to merge it with the default rsslib.php file that is already there or how to even begin to edit it so it displays correctly on the page. Below is the theme I'm currently using along with a screenshot of the coding for the rsslib.php.
Theme used - Free Flux Green Theme
Screenshots The index.php importing the rsslib.php coding Spoiler Hi Guys I have created a registration page where when users login they can pay to become premium, however everything looks fine but paypal wont update the field. The field is 0 and needs to be 1 once payment has been made. Below is my code, <?php //connect to database $error = "Problem connecting"; mysql_connect('localhost','_prince','getmeout') or die($error); mysql_select_db('hmt_cms') or die($error); // read the post from PayPal system and add 'cmd' $req = 'cmd=_notify-validate'; foreach ($_POST as $key => $value) { $value = urlencode(stripslashes($value)); $req .= "&$key=$value"; } // post back to PayPal system to validate $header .= "POST /cgi-bin/webscr HTTP/1.0\r\n"; $header .= "Content-Type: application/x-www-form-urlencoded\r\n"; $header .= "Content-Length: " . strlen($req) . "\r\n\r\n"; $fp = fsockopen ('ssl://www.sandbox.paypal.com', 443, $errno, $errstr, 30); // assign posted variables to local variables $item_name = $_POST['item_name']; $item_number = $_POST['item_number']; $payment_status = $_POST['payment_status']; $payment_amount = $_POST['mc_gross']; $payment_currency = $_POST['mc_currency']; $txn_id = $_POST['txn_id']; $receiver_email = $_POST['receiver_email']; $payer_email = $_POST['payer_email']; if (!$fp) { // HTTP ERROR } else { fputs ($fp, $header . $req); while (!feof($fp)) { $res = fgets ($fp, 1024); if (strcmp ($res, "VERIFIED") == 0) { if ($payment_status=="completed") { if ($payment_amount==1.00&&$payment_currency=="GBP") { $update = mysql_query("UPDATE cms SET premium='1' WHERE email='$payer_email'"); } } // check the payment_status is Completed // check that txn_id has not been previously processed // check that receiver_email is your Primary PayPal email // check that payment_amount/payment_currency are correct // process payment } else if (strcmp ($res, "INVALID") == 0) { // log for manual investigation } } fclose ($fp); } ?> im testing it from sanbox and these are my settings. IPN handler URL is correct Transaction type : cart checkout payment_status : completed payment type: instant email is the same email registered mc_fee = 1 the rest of mcs are set to 0 currency is GBP any help would be appreciated, thanks in advance For some reason this wont work.. Index is jsut returned blank ... Hmm Index.php : <?php include("http://www.website.com/cookie.php"); ?> Cookie.php: <?php if (isset($_COOKIE["background"])) $background = $_COOKIE['background']; else $background = " bgcolor='#FFFFFF'"; ?> It works perfectly if I just enter the code without using a include ... I have a php page which is ran after a form is posted from the previous page. I am having trouble getting the SQL strings to work. When the page is ran online there is no WSOD or error message but the tables in my database are not being updated. Any help with this would be greatly appreciated.
Attached Files
payment.php 1.79KB
4 downloads I've Basically got this script and everything works. Except for the part that it doesen't insert "$_FILES['file']['name']" into the image_url. Any Ideas guys? Code: [Select] <? include "includes/config.php"; if (isset($_POST['add'])) { if ((($_FILES["file"]["type"] == "image/gif") || ($_FILES["file"]["type"] == "image/jpeg") || ($_FILES["file"]["type"] == "image/png")) && ($_FILES["file"]["size"] < 20000)) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { if (file_exists("images/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; echo $_FILES['file']['name']; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "images/" . $_FILES["file"]["name"]); } } } else { echo "Sorry, but only PNG, JPG, and GIF files are allowed."; } mysql_connect ($mysql_host, $mysql_user, $mysql_pass); mysql_select_db ($mysql_db); $image_url = "http://localhost/admin/images/". $_FILES['file']['name'] .""; $sql = "INSERT INTO test (title, link, description, image_url) VALUES ('$_POST[title]', '$_POST[link]', '$_POST[description]', '$image_url')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } header( 'Location: portfolio.php' ); mysql_close(); } ?> Code: [Select] <form enctype="multipart/form-data" method="post"> <p> <strong>TITLE</strong><br/> <input type="text" name="title" class="box"/> </p> <p> <strong>LINK</strong><br/> <input type="text" name="link" class="box"/> </p> <p> <strong>IMAGE</strong><br/> <input type="file" class="box" name="file"/> </p> <p> <strong>DESCRIPTION</strong><br/> <input type="textarea" name="description" class="box"/> </p> <p> <input name="add" type="submit" id="submit" tabindex="5" class="com_btn" value="ADD WORK"/> </p> </form> |