PHP - Problems Passing A Variable

The below script for some reason isn't passing along the product_id variable.
Code: [Select]
$product_id=$_GET['product'];
session_start();
$error=$_SESSION['error'];
$content.='<div class="product_information_text review_form">
<div class="review_header">Write a Review for '.$product_name.'</div>
<form action="./review_process.php?product='.$product_id.'">
<p class="form_item"><label>Name:</label> <input type="text" name="review_name" size="30" /></p>';
if(isset($error[0])){$content.='<p class="red">This field is required.</p>';}
$content.='
<p class="form_item"><label>E-Mail:</label> <input type="text" name="review_email" size="30" /></p>
<p class="form_item"><label>Location:</label> <input type="text" name="review_location" size="30" /></p>
<p class="form_item"><label>Describe Yourself:</label> <input type="text" name="review_describe" size="30" /></p>
<p class="form_item"><label>Review Title:</label> <input type="text" name="review_title" size="30" /></p>
<p class="form_item"><label>Best Use of Product:</label> <input type="text" name="review_best_use" size="30" /></p>
<p class="form_item"><label>Product Pros:</label> <input type="text" name="review_pros" size="30" /></p>
<p class="form_item"><label>Product Cons:</label> <input type="text" name="review_cons" size="30" /></p>
<p class="form_item"><label>Product Rating:</label><br />
<div class="rating_radio"><input type="radio" name="review_product_rating" value="1" /> <br />1</div>
<div class="rating_radio"><input type="radio" name="review_product_rating" value="2" /> <br />2</div>
<div class="rating_radio"><input type="radio" name="review_product_rating" value="3" checked /> <br />3</div>
<div class="rating_radio"><input type="radio" name="review_product_rating" value="4" /> <br />4</div>
<div class="rating_radio"><input type="radio" name="review_product_rating" value="5" /> <br />5</div>
<div class="worst">(Worst)</div><div class="best">(Best)</div>
</p>
<p>&nbsp;</p>
<p class="form_item"><label>Comments on Product:</label><br />
<textarea name="review_text" rows="10" cols="60"></textarea>
</p>
<p><input type="submit" value="Submit" name="Submit" /></p>
</form>
</div>
';
session_unset();
session_destroy();

That code shows the proper product=$product_id value in the form action tag.

Code: [Select]
$product_id=$_GET['product_id'];

$review_name=$_POST['review_name'];
$review_name = stripslashes($review_name);
$review_name = mysql_real_escape_string($review_name);
if($review_name==""){
$error0=1;
}
else{
$error0=0;
}

$review_title=$_POST['review_title'];
$review_title = stripslashes($review_title);
$review_title = mysql_real_escape_string($review_title);
if($review_title==""){
$error1=1;
}
else{
$error1=0;
}

$review_email=$_POST['review_email'];
$review_email = stripslashes($review_email);
$review_email = mysql_real_escape_string($review_email);
if($review_email==""){
$error2=1;
}
else{
$error2=0;
}

$review_location=$_POST['review_location'];
$review_location = stripslashes($review_location);
$review_location = mysql_real_escape_string($review_location);
if($review_location==""){
$error3=1;
}
else{
$error3=0;
}

$review_describe=$_POST['review_describe'];
$review_describe = stripslashes($review_describe);
$review_describe = mysql_real_escape_string($review_describe);
if($review_describe==""){
$error4=1;
}
else{
$error4=0;
}

$review_best_use=$_POST['review_best_use'];
$review_best_use = stripslashes($review_best_use);
$review_best_use = mysql_real_escape_string($review_best_use);
if($review_best_use==""){
$error5=1;
}
else{
$error5=0;
}

$review_pros=$_POST['review_pros'];
$review_pros = stripslashes($review_pros);
$review_pros = mysql_real_escape_string($review_pros);
if($review_pros==""){
$error6=1;
}
else{
$error6=0;
}

$review_cons=$_POST['review_cons'];
$review_cons = stripslashes($review_cons);
$review_cons = mysql_real_escape_string($review_cons);
if($review_cons==""){
$error7=1;
}
else{
$error7=0;
}

$review_product_rating=$_POST['review_product_rating'];
$review_product_rating = stripslashes($review_product_rating);
$review_product_rating = mysql_real_escape_string($review_product_rating);

$review_text=$_POST['review_text'];
$review_text = stripslashes($review_text);
$review_text = mysql_real_escape_string($review_text);
if($review_text==""){
$error8=1;
}
else{
$error8=0;
}

$review_show="n";

date_default_timezone_set('US/Eastern');
$review_date = date("F j, Y, g:i a T");

$error="".$error0."".$error1."".$error2."".$error3."".$error4."".$error5."".$error6."".$error7."".$error8."";

if($error!=="000000000"){
session_start();
$_SESSION['error']=$error;
header("Location: ./store.php?product=".$product_id."#review");
}
else{
$sql="INSERT INTO $tbl_name3 (product_id, review_show, review_title, review_email, review_name, review_location, review_date, review_describe, review_best_use, review_pros, review_cons, review_product_rating, review_text) VALUES ('$product_id', '$review_show', '$review_title', '$review_email', '$review_name', '$review_location', '$review_date', '$review_describe', '$review_best_use', '$review_pros', '$review_cons', '$review_product_rating', '$review_text')";
mysql_query($sql);
echo "Thank You for submitting your review. It should appear on the site
within 48 hours.";
}

The above redirects to store.php?product=#review with no product id. Ideas on why?

Hi,
I am trying to pass a variable when posting a form.
This is my form with the select:
Code: [Select]
<form id="form1" name="form1" method="post"  action="products_2.php?id_subcategoria= WHAT SOULD I PUT HERE?">
<select name="subcats" class="subcatsSelectMenu" id="subcats" onchange="this.form.submit()">
<option value="">Ver placas por tipos</option>
<?php
do {  
?>
<option value="<?php echo $row_subcats_RS['id_subcategoria']?>"><?php echo $row_subcats_RS['subcategoria_esp']?></option>
<?php
} while ($row_subcats_RS = mysql_fetch_assoc($subcats_RS));$rows = mysql_num_rows($subcats_RS);
  if($rows > 0) {
      mysql_data_seek($subcats_RS, 0);
  $row_subcats_RS = mysql_fetch_assoc($subcats_RS);
  }
?>
</select>
</form>How can I pass the variable in the URL?
Thanks

hello all,

I'm new here and I'm learning mysql/php.  Currently I have a dynamic table on one of my webpages, and the loop code looks like this:while ($i < $numRows) {
$fname = mysql_result($result, $i, "fname");
$fcode = mysql_result($result, $i, "fcode");
$ftype = mysql_result($result, $i, "ftype");
$fdesc = mysql_result($result, $i, "fdesc"); ?>
  <tr>
<td><a href="showfunction.php?fname=<?php echo "$fname"; ?>" target="_self"> <?php echo "$fname"; ?></a></td>
<td> <?php echo "$fdesc"; ?> </td>
<td><div align="center"> <?php echo "$ftype"; ?> </div></td>
  </tr>
<?php $i++; 
  } ?>
what I would like to do is pass the ''fname'' variable to the "showfunction" page so it can printed from the database.  Here is the relevant portion of the page:<body><div class="codeblock"> 
<div class="title">Code:<br /> 
</div><code><pre>

<?php echo $fcode; ?>

</pre></code></div>
<br /><pre><hr />
</pre>
I know that doesn't work, and I didn't expect it to because there is no way to 'get' the 'fname' variable from the preceeding script.  I do not want to use the GET method with this because from what I understand, you can only use it with Forms.  I really don't want to put controls in all of my table fields just to be able to pass the function name to the next page.  Does that make sense?

If I could get a jumpstart on this one last hurdle, I would appreciate it.  thank you so much!

Cheers.

I'm an hour worth of searches into this. It's 2:30. I just want some nice person to give me the answer.

I'm trying to pass a variable using href to another page. It works great if the variable is only one word. But it only passes the first word. There are multiple posts on this topic, but I can't seem to get any of those fixes to work for me.

Here the code.
Code: [Select]
<?php
$query = "select DISTINCT city from daily where open_bid>0 order by city ASC";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
$details='';
$details.='<li class="menu"><span class="name"><a href=list.php?city='.$row['city'].'>'.$row['city'].'</a>';
$details.='</li>';
echo($details);
}
?>

As you can imagine, some cities names are made up of two words. This is only passing the first word.

Thanks for your help.

I had an iframe working for the last few months on a site at hostgator.  Yesterday, it quit working (403 permissions error).  After a long bout of trouble-shooting, I found out that it has something to do with mod_security that they have suddenly enabled (have no idea as I'm not a Linux guy). 

They told me they fixed the problem on my domain by whitelisting it as an exception, but strangely, even though the permissions error went away, the actual src= box of the iframe, which was the url variable I was passing in the url, no longer loads. 

So.. I'm trying to break this down into the simplest form to figure it out.  I just understand php basics so needing some verification that I'm doing this right/wrong. 

Here's my code.. 

page1.php
Code: [Select]
<? $testurl = "http://google.com"; ?>
<a href="http://mysite.blah/page2.php?url=<? echo $testurl; ?>">page2.php</a>
page2.php
Code: [Select]
if (isset($_GET['testurl'])) echo $testurl;
else echo "sorry dude";
I am only able to print "sorry dude". 
Am I doing something wrong or shouldn't this send the url? 

Thanks for the help!

I'm starting to fear that this is impossible.. I will severely appreciate any kind of advice!

On site A, I have a link (an affiliate type link) that redirects to site B. When clicking the link on site A, I use this code to redirect..

header('HTTP/1.1 301 Moved Permanently');
header('Location: ' .  $url);
exit;

the $url var is just site's A URL. What I can't figure out is how to pass a variable from the redirection script onto site B without using a query string in the URL itself ( for example, http://www.siteB.com/?var_to_pass=something)

Can passing a variable between two sites be achieved with js.. or XML? I'm willing to use anything as long as I don;t have to add the variable in the URL.

i need to pass the id called id from the maim page to an iframe, but it failes to send. i'm wondering if anyone knows why it fails.

Code: [Select]
<iframe src="details.php?ID=<?php echo $ID; ?>" width="700px" height="150px">
 </iframe>

Hi Guys,

I'm working on an image resizer, to create thumbnails for my page. The resizer works on principle of include a DIRECT link to the image. But what I want to do is put in the PHP Variable in the URL string, so that it points to that file and resizes it accordingly.

My code is as follows :
Code: [Select]
<img src="thumbnail.php?image=<?php echo $row_select_property['image_url']; ?>

Image Resize :
Code: [Select]
<?php 
// Resize Image To A Thumbnail

// The file you are resizing 

 $image = '$_GET[image_url]'; 
 
 //This will set our output to 45% of the original size 
 $size = 0.45; 
 
 // This sets it to a .jpg, but you can change this to png or gif 
 header('Content-type: image/jpeg'); 
 
 // Setting the resize parameters
 list($width, $height) = getimagesize($image); 
 $modwidth = $width * $size; 
 $modheight = $height * $size; 
 
 // Creating the Canvas 
 $tn= imagecreatetruecolor($modwidth, $modheight); 
 $source = imagecreatefromjpeg($image); 
 
 // Resizing our image to fit the canvas 
 imagecopyresized($tn, $source, 0, 0, 0, 0, $modwidth, $modheight, $width, $height); 
 
 // Outputs a jpg image, you could change this to gif or png if needed 
 imagejpeg($tn); 
?>

What I am trying to do is pass on the variable "image=<?php echo $row_select_property['image_url']; ?>" to the Thumbnail script. At the moment I am passing it through the URL string, but it doesnt  seem to load the graphic.

I'll try expand on this more, should you have questions as I am finding it a little difficult to explain.

Thanks in advance.

Help I am trying to pass a php variable into a javasript function. Here is my code.

<a href="<?php echo $row['track']; ?>" download="<?php echo $row['track']; ?>" onclick="myhit(<?php echo $row['track']; ?>)">Download</a>

<script>
function myhit(top){
alert(top);

}
</script>

the javascript function is never called

<head>
<script language="javascript" type="text/javascript" src="datetimepicker.js">
</script>
</head>
<form action="main.php?id=test.php" method="post">
  <p>Start Date:
  <input name="start" id="start" type="text" size="10">
  <a href="javascript:NewCal('start','ddmmyyyy')"><img src="cal.gif" width="16" height="16" border="0" alt="Pick a date"></a>
    End Date: <input name="end" id="end" type="text" size="10">
  <a href="javascript:NewCal('end','ddmmyyyy')"><img src="cal.gif" width="16" height="16" border="0" alt="Pick a date"></a>
  <input name="submit" type="submit" value="Look Up">
</form>
<?php
if(isset($_POST['submit']))
{
$start = $_POST['start'];
$end = $_POST['end'];
$sql = "SELECT * FROM `corps` WHERE `notedate` BETWEEN '$start' AND '$end'";

$results = mysql_query($sql) OR DIE(mysql_error());
$numrow = mysql_num_rows($results) ;
$i = 0;
While ($i < $numrow)
$shownotes = mysql_result($results,$i,'notes');
echo $shownotes."<br>";
{
Echo "Records found ".$i."<br>";
$i++;
}
}

The $start, and $end don't seem to be getting any values

I  have a menu that i want to be added to every page of  my coding using a hidden variable, but i cannot get it to work. I using this with a few if conditions. the index page should navigate every page. can anyone help?


I have attached the files to illustrate the coding i have done so far.

[attachment deleted by admin]

i have this code in a form, i need to pass a variable $time to next page, how can i do that ?


      if( $sErr ) print "<script language='javascript' type='text/javascript'>location.href='#error';</script>";;;

else:

     print "<script language='javascript' type='text/javascript'>location.href='paypal.php';</script>";;;

Hello,

I'm trying to build a small project; and as part of it - I want users to search and when presented with relevant enteries in the SQL database - they should be able to click and retrieve a page dedicated to that entity.

The problem I am having is in passing the 'id' of the search result onto the next (description) page.

Code: [Select]
$SQL = "SELECT * FROM loads";
$result = mysql_query($SQL);


while ($db_field = mysql_fetch_assoc($result)) {
$clickid = $_GET['id'];
print $db_field['id'] ."<a href=\"load_info.php?id=$id"
  . $id . "\" target=\"_self\" title=\"\">More Info</a>;";
print $db_field['depart:'] . "<BR>";
print $db_field['dest'] . "<BR>";

}

I thought it was easy enough to pass the variable like above ("load_info.php?id=$id) and then grab it on the next page like so:

$val = $_GET['clickid'];

Unfortunately, it doesn't retrieve the info from the page before. If I insert a number in there, it does work correctly, but I really need the ID of the database entry to pass on so as to provide the user with further information.

If anyone could help it would be appreciated.

L.

I'm new to php and was wondering how I would be able to do the following:

-I have a search page that allows someone to search for a particular user in the database
-In the results, I want to have a <a href> link to another page which will run a sql query based on which user's link was clicked and list their posts.


So right now I have been trying this code to build that href link:

Code: [Select]
  echo '<td><a href="viewuser.php?username='.urlencode($row['username']).'>View user</a></td>';
However on the following page it is unable to retrieve the 'username' field.

I want to build an image with text variables.
I can get the image OK but not the text, which I need to pass in an img tag from a form.
I have not posted the form  here as I know the post field is populated.
The static string shows overlayed on the image but not the variable string passed in the query string.
Any help appreciated.
My code is as follows:-
input form

<?php

if (isset($_POST['submitted'])) {

if(isset($_POST['AuthorName'])){

$str=($_POST['AuthorName']);

?><img src="http://localhost:8888/test_upload/text-create2.php?str=' . $str . '"/><?php

}

}
?>



The recieving script


<?php
$str2=$_GET['$str'];
$image = ImageCreateFromPNG("http://localhost:8888/wordpress_3/wp-content/plugins/Authors2/jackets/GDL.png");
$color = imagecolorallocate($image, 0xFF, 0xFF, 0xFF);
$colorShadow = imagecolorallocate($image, 0x66, 0x66, 0x66);
$font = 'Tahoma.ttf';
$fontSize = "10";
$fontRotation = "0";
$str= "Successful Home Catering";


/* Shadow */
ImageTTFText($image, $fontSize, $fontRotation, 27, 22, $colorShadow, $font, $str );

/* Top Level */
ImageTTFText($image, $fontSize, $fontRotation, 25, 20, $color, $font, $str);

ImageTTFText($image, $fontSize, $fontRotation, 25, 100, $color, $font, $str2);

header("Content-Type: image/PNG");
ImagePng ($image);
imagedestroy($image);
?>