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PHP - Display Image Stream
I am trying to display an image stream from my pond cam... The stream generated by my ip video server is a jpeg stream without boundaries. Causeur of this the normal mime replace isn't working. I need php to read a picture from the stream, and display the picture in the browser while reading the next picture in the background.
I've got to the point that I am able to connect to the stream, read the first image, and display it in the browser as can be seen in the link below (cam is only on from 09:00 until 16:00) http://cam.xsiteit.nl/readstream_test.php From this point I need to read the second image and replace the image in the browser with the new one. This process has to continu until the browser is closed. Any help would be great! Regards, Peter Similar TutorialsHi I am really frustrated because I got my php code working fine and then I had to make some minor changes to my html form and now the php is not working. I am reciec=ving this message: Warning: move_uploaded_file(upload/carey.bmp) [function.move-uploaded-file]: failed to open stream: No such file or directory in /home/content/19/6550319/html/ipad/listing.php on line 35 Warning: move_uploaded_file() [function.move-uploaded-file]: Unable to move '/tmp/phpIEUQLo' to 'upload/carey.bmp' in /home/content/19/6550319/html/ipad/listing.php on line 35 Sorry, there was a problem uploading your file.03/10/11 : 20:50:08 I wrote it twice because it keeps coming out twice. I guess it means that it cant upload the image because there is no image but I really dont understand why. I havent changed the image part of the form. Does anyone have any ideas? It is much appreciated. Here is the code Code: [Select] <?php //This is the directory where images will be saved $target = "upload/"; $target = $target . basename( $_FILES['photo']['name']); //This gets all the other information from the form $price=$_POST['price']; $pic=($_FILES['photo']['name']); $pic2=($_FILES['phototwo']['name']); $pic3=($_FILES['photothree']['name']); $pic4=($_FILES['photofour']['name']); $description=$_POST['iPadDescription']; $condition=$_POST['condition']; $gig=$_POST['giga']; $yesg=$_POST['yesg']; $fname=$_POST['firstName']; $lname=$_POST['lastName']; $email=$_POST['email']; // Connects to your Database mysql_connect ("taken out for security", "taken out", "taken out") or die(mysql_error()) ; mysql_select_db("taken out") or die(mysql_error()) ; //Writes the information to the database mysql_query("INSERT INTO ipadlist (price,photo,phototwo,photothree,photofour,iPadDescription,condition,giga,yesg,firstName,lastName,email) VALUES ('$price', '$pic', '$pic2', '$pic3', '$pic4', '$description', '$condition', '$gig', '$yesg', '$fname', '$lname', '$email')") ; //Writes the photo to the server if(move_uploaded_file($_FILES['photo']['tmp_name'], $target)) { //Tells you if its all ok echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory"; } else { //Gives and error if its not echo "Sorry, there was a problem uploading your file."; } echo date("m/d/y : H:i:s", time()) ?> The Script:
<?php
if (isset($_POST['submit'])) {
$j = 0; //Variable for indexing uploaded image
$target_path = $_SERVER['DOCUMENT_ROOT'] . "/gallerysite/multiple_image_upload/uploads/"; //Declaring Path for uploaded images
for ($i = 0; $i < count($_FILES['file']['name']); $i++) {//loop to get individual element from the array
$validextensions = array("jpeg", "jpg", "png"); //Extensions which are allowed
$ext = explode('.', basename($_FILES['file']['name'][$i]));//explode file name from dot(.)
$file_extension = end($ext); //store extensions in the variable
$new_image_name = md5(uniqid()) . "." . $ext[count($ext) - 1];
$target_path = $target_path . $new_image_name;//set the target path with a new name of image
$j = $j + 1;//increment the number of uploaded images according to the files in array
if (($_FILES["file"]["size"][$i] < 100000) //Approx. 100kb files can be uploaded.
&& in_array($file_extension, $validextensions)) {
if (move_uploaded_file($_FILES['file']['tmp_name'][$i], $target_path)) {//if file moved to uploads folder
echo $j. ').<span id="noerror">Image uploaded successfully!.</span><br/><br/>';
for ($i = 0; $i < count($_FILES['file']['name']); $i++) {
$tqs = "INSERT INTO images (`original_image_name`, `image_file`, `date_created`) VALUES ('" . $_FILES['file']['name'][$i] . "', '" . $new_image_name . "', now())";
$tqr = mysqli_query($dbc, $tqs);
}
// To create the thumbnails.
function make_thumb($src, $dest, $desired_width) {
/* read the source image */
$source_image = imagecreatefromjpeg($src);
$width = imagesx($source_image);
$height = imagesy($source_image);
/* find the "desired height" of this thumbnail, relative to the desired width */
$desired_height = floor($height * ($desired_width / $width));
/* create a new, "virtual" image */
$virtual_image = imagecreatetruecolor($desired_width, $desired_height);
/* copy source image at a resized size */
imagecopyresampled($virtual_image, $source_image, 0, 0, 0, 0, $desired_width, $desired_height, $width, $height);
/* create the physical thumbnail image to its destination */
imagejpeg($virtual_image, $dest);
}
$src = $target_path;
$dest = $_SERVER['DOCUMENT_ROOT'] . "/gallerysite/multiple_image_upload/thumbs/";
$desired_width = 100;
make_thumb($src, $dest, $desired_width);
} else {//if file was not moved.
echo $j. ').<span id="error">please try again!.</span><br/><br/>';
}
} else {//if file size and file type was incorrect.
echo $j. ').<span id="error">***Invalid file Size or Type***</span><br/><br/>';
}
}
}
?>
With this:
$dest = $_SERVER['DOCUMENT_ROOT'] . "/gallerysite/multiple_image_upload/thumbs/";I get this error message: Warning: imagejpeg(C:/xampp/htdocs/gallerysite/multiple_image_upload/thumbs/): failed to open stream: No such file or directory in C:\xampp\htdocs\gallerysite\multiple_image_upload\upload.php on line 49With this: $dest = "http://localhost/gallerysite/multiple_image_upload/thumbs/";I get this error message: Warning: imagejpeg(http://localhost/gallerysite/multiple_image_upload/thumbs/): failed to open stream: HTTP wrapper does not support writeable connections in C:\xampp\htdocs\gallerysite\multiple_image_upload\upload.php on line 49When I try deleting the "thumbs" folder and then try to upload an image, then I get this error message: Warning: imagejpeg(C:/xampp/htdocs/gallerysite/multiple_image_upload/thumbs/): failed to open stream: Invalid argument in C:\xampp\htdocs\gallerysite\multiple_image_upload\upload.php on line 49The spot of line 49 is this, at the spot where the script creates the thumbnails:
/* create the physical thumbnail image to its destination */
imagejpeg($virtual_image, $dest);
}
Also, with this part right here I am not getting an error message, which means that this part works fine in comparison:
$target_path = $_SERVER['DOCUMENT_ROOT'] . "/gallerysite/multiple_image_upload/uploads/"; //Declaring Path for uploaded imagesThe script itself works fine. The script also uses javascript for multiple image upload. I am using XAMPP. The folder "thumbs" is set to "read-only", when I try to uncheck the "read-only" option in the properties in Windows then it sets itself back again to "read-only". Then again, the script works fine when it comes to the "uploads" folder. This is mentioned in comparison to the "thumbs" folder. Any suggestions on how to solve this? EDIT: I am using XAMPP. The folder "thumbs" is set to "read-only", when I try to uncheck the "read-only" option in the properties in Windows then it sets itself back again to "read-only". I am wondering if I would have issue that the option sets itself back again with Linux? Edited by glassfish, 11 October 2014 - 05:35 PM. My images generator comprises
an array of image names extracted form an images table from a database using a select statement
a random number generator,
and a string that builds the correct pathname for the selected file.
To select one of the images for display, i generate a random number between 1 and the length of the array.
Though the generator is working, I noticed one of the random numbers is throwing up this error:
Warning: getimagesize(images/): failed to open stream: No such file or directory in
An inspection of the array reveals 2 array elements (representing my number of images) but one array element is NULL ( the first entry in the banner table
image_generator.php
require_once('connection.inc.php');
$sql = 'SELECT `filename` FROM banner';
$result = $mysqli->query($sql, MYSQLI_STORE_RESULT) or die(mysqli_error());
$row = $result->fetch_array(MYSQLI_ASSOC);//an array of image names
$count = $result->num_rows;
for ($i = 1; $i <= $count; ++$i)
{
$row[$i] = $result->fetch_array(MYSQLI_ASSOC);
}
$i = rand(1, $count); //a random number generator,
//The random number is used in the final line to build the correct pathname for the selected file.
$selectedImage = "images/{$row[$i]['filename']}";
if (file_exists($selectedImage) && is_readable($selectedImage))
{
$imageSize = getimagesize($selectedImage);
}
var_dump($row)
array (size=1)
'filename' => string 'ginsomin2.jpg' (length=13)
null
RANDON IMAGE DISPLAY
require_once 'image_generator.php';
<div id="banner" class="wrapper clearfix">
<img src="<?php echo $selectedImage; ?>" alt="banner">
</div>
Kindly advice how i may proceed from here?
Thanks.
Hello, Five images will be displayed inside a division. There will be a previous and next button/link. If someone click the next button the next image will be added in that div and the first image will be gone from that div. The previous button/link will do the same thing. Is it possible with php? I am confused if it's a javascript or ajax question. Thanks. Would like to be able to click on a radio button that represents an image. Once selected and submitted, have that image display on another page. I have an idea, but need some guidance. BTW, is using php only doable? Is there a simpler or more elegant way to do this? Thanks all! I am creating a stream for my website similar to facebook's news feed where users can post to, add photos too ect. When a user uploads a photo it gets added to the photos table and a new row to the stream Code: [Select] mysql_query("INSERT INTO photos VALUES ('','$id','$username','$photo','$time')"); mysql_query("INSERT INTO stream VALUES ('','$id','$username','$time','No comment','$photo','')"); Which displays the image on the stream fine but what i am looking to do is if the user uploads more images one after another instead of adding a new post to the stream for every picture i want to show all of the new pictures in one post like what Facebook does. I can't figure out how i would do this. Hi ! I'm trying to understand how php://input works. I've read the manual ( http://php.net/manual/en/wrappers.php.php ) and I have an example of a file upload receiving the file with php://input instead of $_FILES. But I can't understand it, does somebody a good tutorial about php://input ? What is the data inside it? is always the same that $HTTP_RAW_POST_DATA ? How can we send a file to PHP and receive it with php://input ? I'm trying to see what's inside php://input with this code: Code: [Select] $in = fopen("php://input", "rb"); echo Debug::vars($in); if ($in) { while ($buff = fread($in, 4096)) { echo $buff . EOL; // fwrite($out, $buff); } } but I get always blank output (Debug is a Kohana class and it returns: Quote resource(stream) php://input Thanks !! The following will create a PHP stream. $response = $this->guzzleHttp->get($url); $stream = \GuzzleHttp\Psr7\StreamWrapper::getResource($response->getBody()); How can I return a stream using just PHP's native cURL library? Hi! I am having trouble reading a stream of data being sent to my PC via PHP5. It seems that my code stops when it gets to the read section and just sits there indefinately. I am somewhat new to PHP so a solution and explanation would be great! Code: [Select] <?php $host = "129.000.00.01"; // host IP address $port = 40000; // port to listen to // sets script execution limit set_time_limit(30); // 0 means unlimited execution time (constant running) // create UDP socket $socket = socket_create(AF_INET, SOCK_DGRAM, SOL_UDP) or die("Could not create UDP socket!\n"); // reset socket for binding if(!socket_set_option($socket, SOL_SOCKET, SO_REUSEADDR, 1)) { echo "Failed to reset socket!\n"; } else echo "Reset socket successfully!\n"; // bind socket socket_bind($socket, $host, $port); // connect if (!socket_connect($socket, $host, $port)) { echo "Failed to connect to port!\n"; } else echo "Connected to port successfully!\n"; while (1) { echo socket_read($socket, 1024, PHP_NORMAL_READ)."\n"; } // close sockets socket_close($socket); echo "\nDone"; How can I decode the following contents?
Thanks a lot.
<html><head><meta http-equiv="Pragma" content="no-cache"/> <meta http-equiv="Expires" content="-1"/> The other day I noticed someone had post something like this, well this was actually the solution to the problem. But it got me thinking about a project of mine that I am working on and the need to pump out a downloadable file. We are storing most of the files in a database using base64 encoding the 2 key types of files we are storing are images and PDF's mostly pdf's anyway where I am wanting to go with this is, is there anyway to take the base64 encoded file and get it to download through this, or am I tackling the idea in the wrong way? <?php $filename = 'somename.txt'; //this would obviously be changed according to the file type we would output $data =<<<DATA I know my data would go here for the given file once decoded. DATA; header('Content-Description: File Transfer'); header('Content-Type: application/octet-stream'); header('Content-Disposition: attachment; filename=' . $filename); header('Content-Transfer-Encoding: binary'); header('Expires: 0'); header('Cache-Control: must-revalidate, post-check=0, pre-check=0'); header('Pragma: public'); header('Content-Length: ' . strlen($data)); echo $data; ?> I have my IP camera with the streaming URL :
http://x.x.x.x:81/li...user=admin&pwd=
Now i want to record the streaming using PHP . Now please anyone help how to do this ?
Any help would be appreciated .
Edited by ZohaibKhalid1, 17 October 2014 - 08:41 AM. Hi everybody, I'd like to protect a rtsp stream coming from a videoserver using a php page. Is this possible? The rtsp stream is a live h.264 stream with it's own local ip address. Currently i can access the stream by entering rtsp://192.168.1.3 in the browser and quicktime starts up. I have apache running on a different machine (192.168.1.2), which I want to use to pass on the stream. I'd like the rtsp stream to be accessed by entering rtsp://192.168.1.2/?password=changes-a-lot I've been using headers and readfile a lot to protect files. But the live stream seems to work differently. I've seen a lot of posts on how to access media using rtsp, but none of these work with a live stream. Does anybody have any ideas on how to get this to work? Here is my code, below. It is gathering the $url with the corret images. But poduces and error on line 50. Failed to open stream. No such file or directory. By this line: readfile($file_name); What Am I missing, beyond strong programmer mind set. Code: [Select] $merch_map = "http://spot_map"; $dir = "/opt/digistrive/tmp/media/current"; class merch_imgs { public function __construct() { $this->merch_imgs1(); } public function __call($method, $_) { $count = str_replace('merch_imgs', '', $method); echo "$count "; $this->{"merch_imgs" . ++$count}(); } } class thousand_printer extends merch_imgs { public function merch_imgs1000() {} } //03-2012. Location of merchant, if no image use place holder $thumbnails = implode(',', range(1, 10000)); $ext = ".png"; for($thumbnails = 0; $thumbnails < 10000; $thumbnails++) { $url = $merch_map.'/'.$thumbnails.''.$ext; echo $url . '<br>'; //echo '<img src='.$url.' border=0/>'; downloader($url, $dir); } function downloader($url){ $file_name = basename($url); $generated_files = geturl($url, $url); //file_put_contents($file_name); file_put_contents($url, $url = var_export($file_name,true)); $size=strlen($generated_files); if($size==0){exit(0);("<b>Error:</b>not found!");} //header('Content-type: application/force-download'); //header('Content-Disposition: attachment; filename=' . $file_name); //header('Content-Transfer-Encoding: binary'); //header('Expires: Sat, 26 Jul 1997 05:00:00 GMT'); //header('Cache-Control: must-revalidate, post-check=0, pre-check=0'); //header('Pragma: public'); //header('Content-Length: ' . $size); readfile($file_name); unlink($file_name); } function geturl($url, $referer) { $headers[] = 'Accept: image/png'; $headers[] = 'Connection: Keep-Alive'; $headers[] = 'Content-type: application/x-www-form-urlencoded;charset=UTF-8'; $user_agent = 'ONLY_MY_HOST'; //$useragent = $url; $process = curl_init($url); curl_setopt($process, CURLOPT_HTTPHEADER, $headers); curl_setopt($process, CURLOPT_HEADER, 0); curl_setopt($process, CURLOPT_USERAGENT, $user_agent); curl_setopt($process, CURLOPT_REFERER, $referer); curl_setopt($process, CURLOPT_TIMEOUT, 30); curl_setopt($process, CURLOPT_RETURNTRANSFER, 1); curl_setopt($process, CURLOPT_FOLLOWLOCATION, 1); $return = curl_exec($process); curl_close($process); return $return; } //downloader($dir, $url); //Merchant Images if($url && $user_agent){ file_get_contents($url); die(); } I am trying to use the google maps to geocode a location but I get this error: Warning: file_get_contents(http://maps.google.com/maps/api/geocode/json?address=New London,+Connecticut,+United States&sensor=false): failed to open stream: HTTP request failed! HTTP/1.0 400 Bad Request Code: [Select] $location_request = "http://maps.google.com/maps/api/geocode/json?address={$city},+{$real_state},+{$real_country}&sensor=false"; $geocode = file_get_contents($location_request); What am I doing wrong? I tried URL encoding the location request but that also didn't work. I can search for videos by keyword and can fetch videos list from youtube using its api in php. I can fetch video title, description, thumbnail etc. but how can i fetch video url not like this -> youtube.com/watch?id=xyz...
Example: ytpak[dot]com
Evening Everyone,
Been working on this problem for a couple of days and I am stumped. I have a single php file to handle download and streaming of files. It works great with music files, I can download and stream to an <audio> html 5 element just fine. When it comes to my movies, I can download fine but it fails on streaming to a <video> html 5 element. I have done some logging and it looks like after a very short time it just quits.
log when streaming music:
/path/to/music/124 - Mouth Techno -1.mp3 size: 1508731 ctype: audio/mpeg range: 0-1508730/1508731 write chunk: 8192-1508731 write chunk: 16384-1508731 .... write chunk: 1507328-1508731 write chunk: 1515520-1508731 completedlog when streaming movie - this is the complete output, it just stops: Log Started /path/to/movies/AVP_REQUIEM_UNRATED.Title1.DVDRip.mp4 size: 889628920 ctype: video/mp4 range: 0-889628919/889628920 write chunk: 8192-889628920 write chunk: 16384-889628920 write chunk: 24576-889628920 write chunk: 32768-889628920 write chunk: 40960-889628920 write chunk: 49152-889628920 write chunk: 57344-889628920 write chunk: 65536-889628920Here is how I am downloading and streaming the files. Music files work just fine with <audio>, movie files I can only download but want to stream with <video>. This is a hack from multiple sources on the net.
<?php
// sanitize the file request, keep just the name and extension
$filename = $filefix = str_replace('%20', ' ', $_GET["name"]);
$file_path = $filename;
$path_parts = pathinfo($file_path);
$file_dir = $path_parts['dirname'];
$file_name = $path_parts['basename'];
$file_ext = $path_parts['extension'];
$path_default = "/path/to/music/";
$path_types = array(
"mp3" => "/path/to/music/",
"mpg" => "/path/to/movies/",
"avi" => "/path/to/movies/",
"mp4" => "/path/to/movies/",
);
$path = isset($path_types[$file_ext]) ? $path_types[$file_ext] : $path_default;
$file_path = "$path"."$filename";
clearLog();
startLog();
writeLog("$file_path\n");
// allow a file to be streamed instead of sent as an attachment
$is_attachment = isset($_GET["play"]) ? false : true;
// make sure the file exists
if (is_file("$file_path")){
$file_size = filesize($file_path);
$file = @fopen($file_path,"rb");
writeLog("size: $file_size\n");
if ($file){
header("Expires: -1");
header("Cache-Control: public, must-revalidate, post-check=0, pre-check=0");
// set appropriate headers for attachment or streamed file
if ($is_attachment){
header("Content-Disposition: attachment; filename=\"$file_name\"");
}else{
header('Content-Disposition: inline;');
}
// set the mime type based on extension.
$ctype_default = "application/octet-stream";
$content_types = array(
"exe" => "application/octet-stream",
"zip" => "application/zip",
"mp3" => "audio/mpeg",
"mpg" => "video/mpeg",
"avi" => "video/x-msvideo",
"mp4" => "video/mp4",
);
$ctype = isset($content_types[$file_ext]) ? $content_types[$file_ext] : $ctype_default;
header("Content-Type: " . $ctype);
writeLog("ctype: $ctype\n");
$end = ($file_size - 1);
$start = 0;
header("Content-Length: $file_size");
header('Accept-Ranges: bytes');
header("Content-Range: bytes $start-$end/$file_size");
writeLog("range: $start-$end/$file_size\n");
$a=0;
while(!feof($file)) {
$chunk = (1024*8);
echo fread($file, $chunk);
//ob_flush();
flush();
$a=$a+$chunk;
writeLog("write chunk: $a-$file_size\n");
if (connection_status()!=0){
writeLog("failed\n");
fclose($file);
exit;
}
}
// file save was a success
writeLog("completed\n");
fclose($file);
exit;
}else{
// file couldn't be opened
header("HTTP/1.0 500 Internal Server Error");
exit;
}
}else{
// file does not exist
header("HTTP/1.0 404 Not Found");
exit;
}
function startLog(){
$myfile = fopen("newfile.txt", "w");
fwrite($myfile, "Log Started\n");
fclose($myfile);
}
function writeLog($pstr) {
$myfile = fopen("newfile.txt", "a");
fwrite($myfile, $pstr);
fclose($myfile);
}
function clearLog() {
//fclose("newfile.txt");
unlink("newfile.txt");
}
?>
incase it helps, code calling download.php
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<link rel="stylesheet" type="text/css" href="movies.css">
</head>
<body>
<a href="javascript:history.back()"><img src="pics/back.png" style=\"height:50px; width=50px;\"/></a>
<a href="index.html"><img src="pics/home.png" style="height:50px; width=50px;display: in-line;"/></a>
<div id="searchContainer" style="height: 40px; width = 700px; display: block; padding: 10px;">
<input type="text" id="SearchString" placeholder="Enter Search Address" style="vertical-align: top;padding: 10px;" class="valid">
<button name="btnSearch" id="btnSearch" type="button"></button>
</div>
<div id="Mainbox" >
<div id="ItemList">
<ol id="List">
<?php
$dir = '/path/to/movies/';
$dirlist = array_diff(scandir($dir), array('..', '.','Thumbs.db'));
asort($dirlist);
$a=0;
foreach ($dirlist as $file) {
$size = round(filesize('/path/to/movies/'.$file)/1048576);
$filefix = str_replace(' ', '%20', $file);
echo "<li><div class=\"item\" id=\"$a\">";
//title
echo "<div id=\"title\">$file</div>";
echo "<div id=\"mb\">$size MB</div>";
echo "<div id=\"dl\"><a href=\"download.php?name=$filefix\"><img src=\"pics/download.png\" style=\"height:25px; width=25px;\"/></a></div>";
if ($size < 1500){
$url = 'download.php?name='.$filefix.'&play=true';
echo "<div id=\"play\" data-value=\"$url\"><a href=\"javascript:void(0)\" onClick=\"updateSource(this);\"><img src=\"pics/play.png\" style=\"height:25px; width=25px;\"/></a></div>";
}
echo "</div></li>";
$a++;
}
?>
</ol>
</div>
</div>
<div id="videocontainer">
<video id="video" controls>
<source id="mp4movie" type="video/mp4">
<source src="movie.ogg" type="video/ogg" codecs="avc1.64001E, mp4a.40.2">
Your browser does not support the video tag.
</video>
</div>
<script type="text/javascript">
function updateSource(element) {
var dvalue = element.parentElement.getAttribute('data-value');
var video = document.getElementById('video');
var source = document.getElementById('mp4movie');
source.src=dvalue;
video.load(); //call this to just preload the audio without playing
video.play(); //call this to play the song right away
}
</script>
</body>
</html>
Thanks for any help!
Edited by AdrianHoffman, 27 September 2014 - 11:51 PM. I am trying to install a wordpress plugin called CiviCRM. I am using the GoDaddy wordpress dashboard to do this. I am getting this error (which is just the first error in a list of several that are appearing): Warning: require(/home/NAME/public_html/wordpress.SITE.com/wp-content/plugins/civicrm/civicrm/vendor/composer/../symfony/polyfill-ctype/bootstrap.php): failed to open stream: No such file or directory in /home/NAME/public_html/wordpress.SITE.com/wp-content/plugins/civicrm/civicrm/vendor/composer/autoload_real.php on line 70 I am looking at the code in file "autoload_real.php" and line 70 reads: require $file; nowhere else in this file is $file defined. the directory "/home/NAME/public_html/wordpress.SITE.com/wp-content/plugins/civicrm/civicrm/vendor/composer/" DOES exist, but the rest of the line "../symfony/polyfill-ctype/bootstrap.php" does not. there are also 3 other errors in eclipse that are indicated and all of those errors are "syntax error: unexpected 'Autoload()'. The 3 different lines of code that throw this error a 1) self::$loader = $loader = new \Composer\Autoload\ClassLoader(); 2) call_user_func(\Composer\Autoload\ComposerStaticInitdb2000479593e65ef23454e56d74a73f::getInitializer($loader)); 3) $includeFiles = Composer\Autoload\ComposerStaticInitdb2000479593e65ef23454e56d74a73f::$files; I'm not really sure what the issue is, as I'm not experienced enough. Any help from the experts here? GoDaddy claims the problem is with the plugin file's coding. Edited October 24, 2019 by ajetrumpetHello there. I used this code so many times long ago, but I still don't remeber and don't know what I'm doing wrong. http://circus.ka-blooey.net/ If I try to click on any link below the post, I got the error: Code: [Select] Warning: include(.php) [function.include]: failed to open stream: No such file or directory in /home/kablooey/public_html/circus/index.php on line 5 Warning: include(.php) [function.include]: failed to open stream: No such file or directory in /home/kablooey/public_html/circus/index.php on line 5 Warning: include() [function.include]: Failed opening '.php' for inclusion (include_path='.:/usr/lib/php:/usr/local/lib/php') in /home/kablooey/public_html/circus/index.php on line 5 -----------------------x My index is: Code: [Select] <?php include("header.php"); ?> <? if (empty($_GET["boo"])) {$boo="news/show_news";} include "$boo.php"; ?> <?php include("footer.php"); ?> and the footer, where the links are is: Code: [Select] <br /> <div id="menu"><center><a href="http://circus.ka-blooey.net">clear</a> ---x--- <a href="?boo=out">links out</a> ---x--- <a href="?boo=credits">credits</a></center></div><br /> <br /> <br /> <div id="footer"><img src="http://circus.ka-blooey.net/layout/circus_footer.jpg" /></div> </div> </div> </div> </body> </html> Help please? =/ |
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