PHP - Favorite Sites Check Server Script

A beginner question..

I have tried "isset" but it aint working.. I wonder what PHP function to use to check if a user actually put a file to be uploaded on the server. A validation  just in case a user just click the submit button w/out even choosing a file first.


I have this code but it aint working...

Code: [Select]
<?php
if(isset($_POST['submit']))
{

if(isset($_FILES['uploaded_file']))
{
echo "<span class=\"error_validation\">You haven't choose a logo to upload!<br></span>";
echo "<span class=\"error_validation\">Upload Logo Again? <a href=\"edit_logo.php\">Click Here</a><br></span>";
}
else
{

if($_FILES['uploaded_file']["type"] == "image/gif")
{


$target_path = "logo/";

$target_path = $target_path. basename('matzhee_logo.gif');



if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $target_path))
{
echo "<span class=\"error_validation\">The Logo has been successfully changed! Refresh the page to see the changed!<br></span>";
echo "<span class=\"error_validation\">Upload Logo Again? <a href=\"edit_logo.php\">Click Here</a><br></span>";
}
else
{
echo "<span class=\"error_validation\">There was an error uploading the logo. Pls. try again.<br></span>";
echo "<span class=\"error_validation\">Upload Logo Again? <a href=\"edit_logo.php\">Click Here</a><br></span>";
}

}
else
{
echo "<span class=\"error_validation\">Invalid file format. We are only accepting image file. Pls. try again.<br></span>";
echo "<span class=\"error_validation\">Upload Logo Again? <a href=\"edit_logo.php\">Click Here</a><br></span>";
}
}

}
else
{
me_redirect_to("edit_logo.php");
}


?>

Anyone? thanks

Is there a way to run a check on the server to see how long it takes for the page to get built, then print it to the screen?   I tried searching for it online for a few minutes, but it wasn't able to be found.  All I'm finding  on there is how to optimize the pages, but I want a simple time check performed on the page loading

I need to check (from a Debian server to a Mac CLIENT (not server) machine) to see if a file exists on the file system...not an http server.

Here's what I've tried (based on reading at http://www.php.net/manual/en/function.ssh2-exec.php)

Code: [Select]
<?php
function check_remote_files($username, $hostname, $remote_file)
{
$connection = ssh2_connect($hostname, 22, array('hostkey'=>'ssh-rsa'));

if (ssh2_auth_pubkey_file($connection, $username,
                          '/root/.ssh/id_rsa.pub',
                          '/root/.ssh/id_rsa', '')) 
{
echo "Public Key Authentication On Server #2 Successful\n";
}

$url = "if ssh $hostname stat $remote_file \> /dev/null 2\>\&1";
$stream=ssh2_exec($connection,$url);
    stream_set_blocking( $stream, true );
    $cmd=fread($stream,4096);
fclose($stream);

$stream=ssh2_exec($connection,"then");
    stream_set_blocking( $stream, true );
    $cmd=fread($stream,4096);
fclose($stream);

$stream=ssh2_exec($connection,"echo File exists");
    stream_set_blocking( $stream, true );
    $cmd=fread($stream,4096);
fclose($stream);

$stream=ssh2_exec($connection,"else");
    stream_set_blocking( $stream, true );
    $cmd=fread($stream,4096);
fclose($stream);

$stream=ssh2_exec($connection,"echo Not found");
    stream_set_blocking( $stream, true );
    $cmd=fread($stream,4096);
fclose($stream);

$stream=ssh2_exec($connection,"fi");
    stream_set_blocking( $stream, true );
    $cmd=fread($stream,4096);
fclose($stream);

}
?>

NOTHING happens after the echo of Public Key Authentication On Server #2 Successful.

I'm running this script from a bash shell.

Any ideas what might be wrong?

Thanks.

Hey All,

I will be marketing a simple php script shortly and would like to Obfuscate my code and have it check to see if the person is running the script on the proper domain, much like other Purchased Scripts, you have to buy licenses and some are limited to a Per Domain basis.

Could I use cURL to run a script on another server (mine) that takes the URL it came from, and a variable "the auth key" and check if the person is using the script on the proper domain?  If the domain and auth key don't match in the DB i would return a message saying invalid key or something, else continue to execute the script.


<?php
//authkey would be defined in config file
$authkey = "769870afhljkzxf90436";

$curl_handle=curl_init();
curl_setopt($curl_handle,CURLOPT_URL,"http://example.com/page.php?authkey=$authkey");
curl_setopt($curl_handle,CURLOPT_CONNECTTIMEOUT,2);
curl_setopt($curl_handle,CURLOPT_RETURNTRANSFER,1);
$buffer = curl_exec($curl_handle);
curl_close($curl_handle);

if (empty($buffer))
{
    print "Sorry, AuthServ is performing maintenance.....<p>";
}
else
{
    print $buffer;
}
?>



Is there a smarter way to do this?  I don't have an extra 300 bucks to use something like ioncube,  just looking for a general proper direction on going about this as I am totally clueless.

thanks

Hi All - I'm trying to see if the below is possible using PHP.

is it possible for php to allow a user to check if a port is open/listening on a remote server/PC, from their local machine. I've seen scripts on the web that talk about opening cmd.exe - this won't work as not all of my users will be on windows. Also saw fsock.. but the remote server is not serving http page(s). Also saw telnet, but again, some of my users may not have that windows feature enabled.

Desired workflow:

1. user enters the server hostname/IP and a port

2. my php webapp will emulate checking if that hostname and port is open from the local user's computer.

 

thanks!

I have a server script with which i have allowed the user to mark any item as favorite, but i also want another script through which the user can unfavorite the same item if they want and that item should be deleted from their favorite list. I have kept the same table for both favorite and unfavorite code, therefore i have used update query to update the details. For this purpose i have a code, but its not working, as i am new in the programming field would appreciate if someone could provide the correct codes

 
<?php
require_once('config.php');

$favorite = $_REQUEST['favorite'];

    $unfavorite = $_REQUEST['unfavorite'];

    $id=$_REQUEST['id'];

    

$unfavoritedeal=mysql_query("SELECT * FROM favoritedeals where id='".$id."'"); //favoritedeals is the name of the table



if($row=mysql_fetch_array($unfavoritedeal))

     {

     $favorite=$row['favorite'];

     $unfavorite=$row['unfavorite'];

}



$myfavorite=(isset($_REQUEST['favorite'])?$_REQUEST['favorite']:$favorite);

         $myunfavorite=(isset($_REQUEST['unfavorite'])?$_REQUEST['unfavorite']:$unfavorite);

        

$update = mysql_query("update favoritedeals set favorite = '".$myfavorite."', unfavorite = 1 where id = '".$id."'");    



if(unfavorite="1" where id='".$id."')

{

"delete from favoritedeals WHERE id= '".$id."'";

}    





$posts[0]['message'] = 'favorite list updated';

    $selectt = mysql_query("select * from favoritedeals where id = '".$id."'");

    $results = mysql_fetch_assoc($selectt);

    $posts[0]['detail'] = $results;

    header('Content-type: application/json');

    echo json_encode($posts);

?>

Can someone propose a solution to resolve the following:

I have a PHP script that runs just fine when processing small amounts of data (opening and reading CSV file and performing afew validation checks before saving to db).

Issue: when attempting to process a large file, I have found the execution time exceeds the "timeout" value currently set on the server which is 60 seconds.
Note: I do not want to increase this time interval as that's a security risk so need to figure out a way to break up the data - being read from the CSV file - into chunks and some way create mini-processes (I guess) to execute chunks of that data at a time until the entire file is read.

Any suggestions?

I have been looking at this code most of the morning and do not have a clue what is wrong with the code. I am hoping its not a stupid mistake, can someone please help me out? thank you   

 
<title>Inputing Travel Detials</title>
 
<header>
  <h1 align="center"> Adding Travel Detials </h1>
  
 
  <body>
    <p>  <center><img  src="cyberwarfareimage1.png" alt="Squadron logo" style="width:200px;height:200px" style="middle"></center>
        <table border="1">
          <tr>
            <td><a href="index.php"> Home Page </a></td>
            <td><a href="administratorhomepage.html">Administrator Home Page </a></td>
            <td><a href="viewhomepage.html">View Home Page </a></td>
            <td><a href="Inputhomepage.html">Input Home Page </a></td>
            <td><a href="traveldetials.html">Enter More Travel Detials </a></td>
        </table>
    </p>
 
 
<?php
 
include "connection.php";
 
$Applicant_ID = $_POST["Applicant_ID"];
$Method_Of_Travel = $_POST["Method_Of_Travel"];
$Cost = $_POST["Cost"];
$ETA = $_POST["ETA"];
$Main_Gate_Advised = $_POST["Main_Gate_Advised"];
 
$query = ("UPDATE `int_board_applicant` SET `Method_Of_Travel`=`$Method_Of_Travel', `Cost`=`$Cost', `ETA`='$ETA', `Main_Gate_Advised`='$Main_Gate_Advised' WHERE `Applicant_ID`='$Applicant_ID'");
   
 
$result = mysqli_query($dbhandle, $query) 
    or die(mysqli_error($dbhandle));
 
if($result){ echo "Success!"; }
 
  else{ echo "Error."; }
 
 
// successfully insert data into database, displays message "Successful".
 if($query){
  echo "Successful";
}
 
  else {
  echo "Data not Submitted";
}
 
 
//closing the connection
   mysqli_close($dbhandle)
   
 
 
 
 
?>

Is there any php function I can test how fast my server is performing, like how fast its carrying out a certain action so I can see its resource usage.

I'm trying to show the progress of executing a python script in PHP with a progress bar. I found a link (https://www.htmlgoodies.com/beyond/php/show-progress-report-for-long-running-php-scripts.html) that uses SSE to send progress updates to the client. In the original code, a loop is used to simulate a long script but in my case I'm trying to execute a python script that takes roughly 50 seconds.

index.php

<!DOCTYPE html>
   <html>
      <head>
         <meta charset="utf-8" />
      </head>
      <body>
         <br />
         <input type="button" onClick="startTask()"  value="Start Long Task" />
         <input type="button" onClick="stopTask();"  value="Stop Task" />
         <br />
         <br />
         <p>Results</p>
         <br />
         <div id="results" style="border:1px solid #000; padding:10px; width:300px; height:250px; overflow:auto; background:#eee;"></div>
         <br />
         <progress id='progressor' value="0" max='100' style=""></progress>
         <span id="percentage" style="text-align:right; display:block; margin-top:5px;">0</span>
      </body>
   </html>

process.php

<?php
header('Content-Type: text/event-stream');
// recommended to prevent caching of event data.
header('Cache-Control: no-cache');

function send_message($id, $message, $progress) {
    $d = array('message' => $message , 'progress' => $progress);

    echo "id: $id" . PHP_EOL;
    echo "data: " . json_encode($d) . PHP_EOL;
    echo PHP_EOL;

    ob_flush();
    flush();
}

//LONG RUNNING TASK
// for($i = 1; $i <= 10; $i++) {
//     send_message($i, 'on iteration ' . $i . ' of 10' , $i*10);
//     sleep(1);
$path="test.py";
$test= shell_exec("python " . $path . ""); {
    echo "data: " . json_encode($test) . "\n\n";
    sleep(1)
}

send_message('CLOSE', 'Process complete');
 

Problem: As you can see in process.php I commented the original code and placed a simple python execution in php. I just want to diplay the progress of the script but it is not doing so. What do I have to do to show the progress of the script? Note: I don't think is relavent but the python script just opens up a batch file.

Are there other methods to display the progress bar of a script in php?

This is mind bender. I recently upgraded from a VPS to a Dedicated server. The script is a data mining tool that primarily uses cURL. It worked flawlessy on the the VPS. Because it was the same hosting company everything was migrated and done so smoothly to the new dedicated.

Now, the program hangs for no reason at all. The times vary but I'll usually get about an hour of the script before it hangs. It used to run for hours at a time on the VPS.

While I do see some 'notices' and cURL timeouts - there are no error messages echoed out when the program hangs and there is nothing within the error log on the server to indicate anything in terms of why. The program simply 'freezes'.

I think I've spent the last three days modifying the php.ini file. Here are some settings which may be of interest?

post_max_size = 16M
log_errors = On
max_execution_time = 0; (From what I understand is unlimited).
max_input_time = 0   ;
memory_limit = 128M;

At the top of every page within my script:

set_time_limit(0);
error_reporting(E_ALL);

The dedicated is an 8 gig Linux box running Apache. Speaking of which, here are some settings within WHM for Apache:

Max Clients 500
Max Requests Per Child - 0 (unlimited)
Keep-Alive - On
Keep-Alive Timeout - 50
Max Keep-Alive Requests - Unlimited
Timeout - 1000

Because the script works on another VPS that I have within the same hosting company can someone direct me with what I should be looking for and/or comparing between both servers?

What are the most common reasons for a PHP script to freeze from a server setting standpoint?

Hi all! 
Yet again I have a problem. I really couldn't find what the heck's wrong with this thing. It's extremely simple and still...
I'm trying to put a php script in my website to monitor the status of my FTP and HFS servers. Help?

<TITLE>Server Status</TITLE>
<?php 
$data .= " 
    </div>
    <center> 
     <div style=\"border-bottom:1px #999999 solid;width:480;\"><b> 
       <font size='1' color='#3896CC'>Server Status</font></b> 
     </div>  
   </center> 
<br>"; 

//configure script 
$timeout = "1"; 

//set service checks
$port[1] = "80";            $service[1] = "Apache";            $ip[1] = "localhost";    $icon[1] = "habbo.jpg";        $alt[1] = "Apache";
$port[2] = "8080";            $service[2] = "HFS Server";        $ip[2] = "localhost";    $icon[2] = "web.png";        $alt[2] = "HFS Server";  
$port[3] = "21";            $service[3] = "FTP Server";        $ip[3] = "localhost";  $icon[3] = "web.png";        $alt[3] = "FTP Server";

// 
// NO NEED TO EDIT BEYOND HERE  
// UNLESS YOU WISH TO CHANGE STYLE OF RESULTS 
// 

//count arrays 
$ports = count($port); 
$ports = $ports + 1; 
$count = 1;

//beggin table for status 
$data .= "<table width='480' border='1' cellspacing='0' cellpadding='3' style='border-collapse:none' bordercolor='#CCCCCC' align='center'>"; 

while($count < $ports){ 

     if($ip[$count]==""){ 
       $ip[$count] = "localhost"; 
     } 
        $fp = @fsockopen("$ip[$count]", $port[$count], $errno, $errstr, $timeout); 
        if (!$fp) { 
            $data .= "<tr><td width='18' align='center'><img src='http://127.0.0.1/stat/$icon[$count]' title='$alt[$count]' alt='$alt[$count]'></td><td>$service[$count]</td><td width='18' align='center'><img src='http://127.0.0.1/stat/off.png'></td></tr>"; 
        } else { 
            $data .= "<tr><td width='18' align='center'><img src='http://127.0.0.1/stat/$icon[$count]' title='$alt[$count]' alt='$alt[$count]'></td><td>$service[$count]</td><td width='18' align='center'><img src='http://127.0.0.1/stat/on.png'></td></tr>"; 
            fclose($fp); 
        } 
    $count++; 

}  

//close table 
$data .= "</table><div>"; 

echo $data; 

?>

The output of this is...

Quote

Parse error: syntax error, unexpected T_VARIABLE in D:\Program Files\xampp\xampp\htdocs\stat\server.php on line 18


Also, does somebody have a link or something to a tutorial/pre-made script (although I'd like to follow instructions about it) about server statistics? I want to have data on how much a certain partition on the server has free or full. Thank you in advance.

 

Ok this is puzzleing. I am geting "Could not delete data: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1". but its is deleting the entry that needs to be removed. The "1" is the entry. Just not sure what is causing the error. I do have another delete php but I have put that on the back burning for the time being.     <?php

         $con = mysqli_connect("localhost","user","password","part_inventory");
    // Check connection
if (mysqli_connect_errno()) {
  printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
} else {
    
    $result = mysqli_query($con, "SELECT * FROM amp20 ");
    
    $amp20ptid = $_POST['amp20ptid'];                // escape variables for security
    $amp20ptid = mysqli_real_escape_string($con, $_POST['amp20ptid']);
    
    mysqli_query($con, "DELETE FROM amp20 WHERE amp20ptid = '$amp20ptid'");
      
    
if (!mysqli_query($con, $amp20ptid));

{
 die('Could not delete data: ' . mysqli_error($con));    
}
 echo "Part has been deleted to the database!!!\n";
    mysqli_close($con);
}
?>

Hi guys   I have this code below and all works fine when submitting this online application apart from when someone types either ' # & into one of the comment fields in which it throws up the error. Have tried various fixes from across the internet but no joy. Can anyone offer suggestions?   <?php $con = mysql_connect("localhost:3306","root","password"); if (!$con)   {   die('Could not connect: ' . mysql_error());   } mysql_select_db('sfapp', $con); $sql="INSERT INTO 'sfapp' ('surname_add','forename_add','dob_add','hometele_add','mobiletele_add','homeadd_add','siblings_add','schoolname_add','headname_add','schooladd_add','schooltele_add','schoolem_add','alevel_add','personstate_add','nameprovided_add','pe_add','se_add','PredGrade_Art','PredGrade_AScience','PredGrade_BusStudies','PredGrade_Electronics','PredGrade_EnglishLang','PredGrade_EnglishLit','PredGrade_French','PredGrade_German','PredGrade_Geog','PredGrade_Graphics','PredGrade_History','PredGrade_Maths','PredGrade_SepScience','PredGrade_ProductDesign','PredGrade_Spanish','PredGrade_Other','Gender_Male','Gender_Female','Sub_EnglishLit','Sub_Maths','Sub_FurtherMaths','Sub_Biology','Sub_Chemistry','Sub_Physics','Sub_French','Sub_German','Sub_Spanish','Sub_Geography','Sub_History','Sub_RE','Sub_FineArt','Sub_Business','Sub_Computing','Sub_GlobPersp','Sub_DramaAndTheatre','Sub_PE','Sub_Dance','Sub_Politics','Sub_Psychology','Sub_Sociology','readprospect_chk','Sib_Yes','Sib_No','Current_Student_Yes','Current_Student_No','I_Understand_chk','Current_Education_chk','Local_Care_chk','Staff_Cwhls_chk','Sub_Film')   VALUES ('$_POST[surname_add]','$_POST[forename_add]','$_POST[dob_add]','$_POST[hometele_add]','$_POST[mobiletele_add]','$_POST[homeadd_add]','$_POST[siblings_add]','$_POST[schoolname_add]','$_POST[headname_add]','$_POST[schooladd_add]','$_POST[schooltele_add]','$_POST[schoolem_add]','$_POST[alevel_add]','$_POST[personstate_add]','$_POST[nameprovided_add]','$_POST[pe_add]','$_POST[se_add]','$_POST[PredGrade_Art]','$_POST[PredGrade_AScience]','$_POST[PredGrade_BusStudies]','$_POST[PredGrade_Electronics]','$_POST[PredGrade_EnglishLang]','$_POST[PredGrade_EnglishLit]','$_POST[PredGrade_French]','$_POST[PredGrade_German]','$_POST[PredGrade_Geog]','$_POST[PredGrade_Graphics]','$_POST[PredGrade_History]','$_POST[PredGrade_Maths]','$_POST[PredGrade_SepScience]','$_POST[PredGrade_ProductDesign]','$_POST[PredGrade_Spanish]','$_POST[PredGrade_Other]','$_POST[Gender_Male]','$_POST[Gender_Female]','$_POST[Sub_EnglishLit]','$_POST[Sub_Maths]','$_POST[Sub_FurtherMaths]','$_POST[Sub_Biology]','$_POST[Sub_Chemistry]','$_POST[Sub_Physics]','$_POST[Sub_French]','$_POST[Sub_German]','$_POST[Sub_Spanish]','$_POST[Sub_Geography]','$_POST[Sub_History]','$_POST[Sub_RE]','$_POST[Sub_FineArt]','$_POST[Sub_Business]','$_POST[Sub_Computing]','$_POST[Sub_GlobPersp]','$_POST[Sub_DramaAndTheatre]','$_POST[Sub_PE]','$_POST[Sub_Dance]','$_POST[Sub_Politics]','$_POST[Sub_Psychology]','$_POST[Sub_Sociology]','$_POST[readprospect_chk]','$_POST[Sib_Yes]','$_POST[Sib_No]','$_POST[Current_Student_Yes]','$_POST[Current_Student_No]','$_POST[I_Understand_chk]','$_POST[Current_Education_chk]','$_POST[Local_Care_chk]','$_POST[Staff_Cwhls_chk]','$_POST[Sub_Film]')"; if (!mysql_query($sql,$con))   {   die('Error: ' . mysql_error());   }   ?> <?php //if "email" variable is filled out, send email   if (isset($_REQUEST['pe_add']))  {     //Email information     $admin_email = $_REQUEST['pe_add'];   $forename = $_REQUEST['forename_add'];   $email = "autoreply@testing.com";   $subject = "Application";   $desc =   "Dear $forename   Thank you for submitting your online application, we will be in touch shortly. " ;       //send email   mail($admin_email, "$subject", "$desc", "From:" . $email);     //Email response   echo "Thank you for contacting us!";   }     //if "email" variable is not filled out, display the form   else  { ?> If you are seeing this, you need to go back and fill out the Personal Email section! <?php   }   header("location:complete.php"); mysql_close($con) ?>     Thanks in advance.