PHP - Create And Store Xls Files
Hi,
I have a database and I need to generate xls file selecting only few columns. The following should happen on click of a trigger like button/link: 1) 6 columns from mysql database table are selected. The first row of xls is the field name which is NOT the same as mysql table column name (xls columns are explicitly defined) 2) This file is generated and saved inside filesystem on remote server. 3) Link to this file is displayed which can be downloaded from server. Please help how to do this. I have the code for creating csv files but that doesnt save the file on server, just shoots it to browser to download. function createCSV() { include("dbconnect.php"); $query = "SELECT `EmailAddress` , `Name` , `FirstName` , `LastName` FROM directtable;"; $rsSearchResults = mysql_query($query) or die(mysql_error()); $out = ''; $fields = mysql_list_fields($dbDatabase,'directtable'); $columns = mysql_num_fields($fields); // Put the name of all fields for ($i = 0; $i < $columns; $i++) { $l=mysql_field_name($fields, $i); $out .= '"'.$l.'",'; } $out .="\n"; // Add all values in the table while ($l = mysql_fetch_array($rsSearchResults)) { for ($i = 0; $i < $columns; $i++) { $out .='"'.$l["$i"].'",'; } $out .="\n"; } // Output to browser with appropriate mime type, you choose ;) header("Content-type: text/x-csv"); //header("Content-type: text/csv"); //header("Content-type: application/csv"); $now=date("d-m-Y,H:i:s", time()); header("Content-Disposition: attachment; filename=emails_".$now.".csv"); echo $out; } Similar Tutorialshey i am using a MySql database and i need to create a dynamic HTML table with one of its columns as checkboxes.so i have to create multiple checkboxes.but these checkbox values are to be stored in a mysql table and then later retrieved when form reloads.and depending on previous state when form was submitted, the newly created checkboxes have to be checked in the same manner.so how do i store multiple checkbox values in my table and also how do i retrieve them? please help. hi i'm trying to create a php file from a script but i dont seem to be getting it right the file doesn't exist already am trying to create it. Code: [Select] <title>test</title> <?php include_once"includes/db_connect.php"; $sql=mysql_query("SELECT `urlName` FROM `products` WHERE `category`='1'"); while($fetch=mysql_fetch_object($sql)){ $File = "".$fetch->urlName.".php"; $handle = fopen($File, 'w'); fclose($handle); } ?> I am unsuccessfully able to do the following:
User creates an account
After login, checks server if user has their own folder created
If doesn't exist, create it
Copy files from source_code to this new folder
My code does create a folder, but no files appear inside it.
Been trying to find an example with google search for the past 3 days with no luck.
I am running LAMP on Linux Mint OS to run my PHP webpages.
Can anyone tell me if issues with this section of coding?
<?php function wait_time($seconds) { $seconds = abs($seconds); if ($seconds < 1): usleep($seconds*1000000); else: sleep($seconds); endif; } $file1 = "blank.html"; $file2 = "channel_video.php"; $file3 = "clear_playlist.php"; $file4 = "confirm.html"; $file5 = "index.html"; set_time_limit(0); //prevent script from timing out $account = $_POST["account_name"]; $src = "source_code/"; $dst = $account."/"; echo 'Setting up your account page ->.'; mkdir($account, 0777, true); echo '.'; //create folder with full write permissions wait_time(2000); //wait 2 seconds before copying files over copy($src.$file1, $dst.$file1); echo '.'; wait_time(2000); //wait 2 seconds before copying files over copy($src.$file2, $dst.$file2); echo '.'; wait_time(2000); //wait 2 seconds before copying files over copy($src.$file3, $dst.$file3); echo '.'; wait_time(2000); //wait 2 seconds before copying files over copy($src.$file4, $dst.$file4); echo '.'; wait_time(2000); //wait 2 seconds before copying files over copy($src.$file5, $dst.$file5); echo '.<- setup finished<br>'; ?>Thanks for any input you can provide. I have looked around all overr, but cant find what im looking for. Everything I have found is about uploading multile files, what I need to do is upload one file and copy it so there is 3 files. Here is an example of what I need to accomplish. Upload file picture1.jpg From picture1.jpg create 3 files - smallimage_picture1.jpg, largeimage_picture1.jpg & smallimage_picture1_thumb.jpg Each file will need to be copied to a /products directory and also an entry for each file name placed in mysql database table. I don't think this is as simple as it sounds to do in PHP, but i am very willing to learn so if anyone knows of a good tutorial that get get me started that would be super. regards DB So far I have managed to create an upload process which uploads a picture, updates the database on file location and then tries to upload the db a 2nd time to update the Thumbnails file location (i tried updating the thumbnails location in one go and for some reason this causes failure) But the main problem is that it doesn't upload some files Here is my upload.php <?php include 'dbconnect.php'; $statusMsg = ''; $Title = $conn -> real_escape_string($_POST['Title']) ; $BodyText = $conn -> real_escape_string($_POST['ThreadBody']) ; // File upload path $targetDir = "upload/"; $fileName = basename($_FILES["file"]["name"]); $targetFilePath = $targetDir . $fileName; $fileType = pathinfo($targetFilePath,PATHINFO_EXTENSION); $Thumbnail = "upload/Thumbnails/'$fileName'"; if(isset($_POST["submit"]) && !empty($_FILES["file"]["name"])){ // Allow certain file formats $allowTypes = array('jpg','png','jpeg','gif','pdf', "webm", "mp4"); if(in_array($fileType, $allowTypes)){ // Upload file to server if(move_uploaded_file($_FILES["file"]["tmp_name"], $targetFilePath)){ // Insert image file name into database $insert = $conn->query("INSERT into Threads (Title, ThreadBody, filename) VALUES ('$Title', '$BodyText', '$fileName')"); if($insert){ $statusMsg = "The file ".$fileName. " has been uploaded successfully."; $targetFilePathArg = escapeshellarg($targetFilePath); $output=null; $retval=null; //exec("convert $targetFilePathArg -resize 300x200 ./upload/Thumbnails/'$fileName'", $output, $retval); exec("convert $targetFilePathArg -resize 200x200 $Thumbnail", $output, $retval); echo "REturned with status $retval and output:\n" ; if ($retval == null) { echo "Retval is null\n" ; echo "Thumbnail equals $Thumbnail\n" ; } }else{ $statusMsg = "File upload failed, please try again."; } }else{ $statusMsg = "Sorry, there was an error uploading your file."; } }else{ $statusMsg = 'Sorry, only JPG, JPEG, PNG, GIF, mp4, webm & PDF files are allowed to upload.'; } }else{ $statusMsg = 'Please select a file to upload.'; } //Update SQL db by setting the thumbnail column to equal $Thumbnail $update = $conn->query("update Threads set thumbnail = '$Thumbnail' where filename = '$fileName'"); if($update){ $statusMsg = "Updated the thumbnail to sql correctly."; echo $statusMsg ; } else { echo "\n Failed to update Thumbnail. Thumbnail equals $Thumbnail" ; } // Display status message echo $statusMsg; ?> And this does work on most files however it is not working on a 9.9mb png fileĀ which is named "test.png" I tested on another 3.3 mb gif file and that failed too? For some reason it returns the following Updated the thumbnail to sql correctly.Updated the thumbnail to sql correctly. Whereas on the files it works on it returns REturned with status 0 and output: Retval is null Thumbnail equals upload/Thumbnails/'rainbow-trh-stache.gif' Failed to update Thumbnail. Thumbnail equals upload/Thumbnails/'rainbow-trh-stache.gif'The file rainbow-trh-stache.gif has been uploaded successfully. Any idea on why this is? Hello I have a simple question about file handling... Is it possible to list all files in directories / subdirectories, and then read ALL files in those dirs, and put the content of their file into an array? Like this: array: [SomePath/test.php] = "All In this php file is being read by a new smart function!"; [SomePath/Weird/hello.txt = "Hello world. This is me and im just trying to get some help!";and so on, until no further files exists in that rootdir. All my attempts went totally crazy and none of them works... therefore i need to ask you for help. Do you have any ideas how to do this? If so, how can I be able to do it? Thanks in Advance, pros Hello, I have a variable called $Price, We are getting it through Mysql Database using While loop. We getting the data from database in ordered by ID. Now then i have requirement to store that data into Low to High form ... Like we are receiving $price lke unordered form .. 50 14 35 25 00 145 52 Here i just want to store it in Low to high form like 00, 14,25,35 ... and so on .. Please suggest me the appropriate code. While($myrow=mysql_fetch_array($result, MYSQL_ASSOC)) { some codes return value $price. // want to store in array } $array($price) // here want to store in Low to high with key value. I am using WPSQT plugin in my blog site .I code some files in PHP also.how to add that files in plugin files.
Hello everyone, I am working on a form that is similar to a shopping cart system and I am thinking of creating a button that submits the checked value and saves them to a $_SESSION variable. And also a link that links to a cart.html that takes the values of a $_SESSION variable. I am have trouble figuring what tag/attribute should I use in order to achieve that.
Right now my code attached below submits the checked values to cart.html directly. However I want my submit button to save the checked box to a $_SESSION variable and STAY on the same page. And then I will implement a <a> to link to the cart.php.
I researched a little bit about this subject and I know it's somewhat related to ajax/jquery. I just wanted to know more about it from you guys. I appreciate your attention for reading the post and Thanks!
Below is the form that I currently have:
<form name= "finalForm" method="POST" action="cart.php"> <input type="Submit" name="finalSelected"/> <?php foreach($FinalName as $key => $item) {?> <tr> <td><input type="checkbox" name="fSelected[]" value="<?php echo htmlspecialchars($FinalID[$key])?>" /> <?php echo "$FinalID[$key] & $item";?> </td> </tr> <?php } ;?>Below is the code for cart.php <?php require ('connect_db.php'); if(isset($_POST['finalSelected'])) { if(!empty($_POST['fSelected'])) { $chosen = $_POST['fSelected']; foreach ($chosen as $item) echo "aID selected: $item </br>"; $delimit = implode(", ", $chosen); print_r($delimit); } } if(isset($delimit)) { $cartSQL = "SELECT * from article where aID in ($delimit)"; $cartQuery = mysqli_query($dbc, $cartSQL) or die (mysqli_error($dbc)); while($row = mysqli_fetch_array($cartQuery, MYSQLI_BOTH)) { $aTitle[] = $row[ 'name' ]; } } ?> <table> <?php if(isset($delimit)) { $c=0; foreach($aTitle as $item) {?> <tr> <td> <?php echo $aTitle[$c]; $c++;?> </td> </tr> <?php }}?> </table> It seems that in the following script I am not able to make $page contain some values as it always acts as it contains 0. The script will give you more idea about what I wanna do with it. Code: [Select] <?php include('dbinfo.inc'); session_start(); $connect= mysql_connect($host,$dbuser,$password) or die("connect to database fails"); mysql_select_db($dbname, $connect); //This will set the number of messages we want to display on each page $rows_per_page = 5; function show_msg() { echo "<tr align='center'> <td>$row[message]</td> </tr> <tr><td><strong>Sent By: $_SESSION[username] ON Date: $row[date]</strong></td></tr> <tr><td></td></tr>"; } //This will set the necessay variables required to set the page layout function page_vars() { $sql = "select * from msgs"; $result = mysql_query($sql, $connect); $numrows = mysql_num_rows($result); $total_pages = ceil($numrows/$rows_per_page); //Check whether page is given or not if(isset($_GET["page"])) { $page = $_GET["page"]; } else { $page = 1; } if($page < 1): { $page = 1; } elseif($page > $total_pages): { $page = $total_pages; } endif; } if($_SESSION[loggedin] == TRUE && $_SESSION[actype] == lecturer) { echo "<form action='postmsg.php' method='POST'>"; echo "<table width='80%' border='1'><tr align='center'><td><strong>To send a new message type it in the below box and press SUBMIT</strong> </td></tr>"; echo "<tr align='center'> <td><textarea name='msgarea' cols='40' row='5'></textarea></td> </tr> <tr align='center'> <td><input type='submit' value='Send Message' /></td> </tr> </table>"; $limit .= 'LIMIT '.($page - 1)*$rows_per_page.', '.$rows_per_page; echo $limit; $sql = "select * from 'msgs' $limit"; $result = mysql_query($sql); echo "<table width='80%' border='1'>"; $row = mysql_fetch_assoc($result); while($row) { show_msg(); } } else { page_vars(); $limit .= 'LIMIT '.($page - 1)*$rows_per_page.', '.$rows_per_page; $sql = "select * from msgs $limit"; $result = mysql_query($sql,$connect); echo "<table width='80%' border='1'>"; while($row = mysql_fetch_assoc($result)) { show_msg(); } echo "<tr align='center'> <td> <a href='$_SERVER[php_self]?page=1'>First Page</a> <a href='$_SERVER[php_self]?page=($page - 1)'>$page</a> <a href='$_SERVER[php_self]?page=$page'>$page</a> <a href='$_SERVER[php_self]?page=($page + 1)'>$page</a> <a href='$_SERVER[php_self]?page=($total_pages)'>>>>Last Page</a> </td> </tr>"; echo "</table>"; } ?> now when i echo $limit it always shows "-5, 5" , that's not what i want from this script. Instead I want limit to store "0, 1" with the same concept not direct because it will change according to what $_GET[page] holds. Hope I will get the solution here.... how do i get a drop down value and store it in a another table as of now i am getting the value from one table showing it on drop down now once that is selected i need to insert it into another table. <html> <?php mysql_connect('localhost','root','') or die('Could not connect to mysql ' . mysql_error()); mysql_select_db("dbtest") or die(mysql_error()); if(isset($_POST['submit'])) { //$name=$_POST['val']; $id = $_POST['select']; $id=$row['name']; ?> <input type="text" name="name2" value="<?php echo $row['name'] ?>"><br /> <?php $query = "INSERT INTO sub (`sub`) values('" . $id . "')"; $result = mysql_query($query); if($query) { echo "query executed"; } } ?> <form id="name" action="<?php $_POST['SERVER_SELF'] ?>" method="POST" > <input type="text" name="name1"><br /> <select name="select" id="select"> <?php $query = "SELECT name,id FROM main"; $result = mysql_query($query); if($query) { while($row = mysql_fetch_array($result)) { $options .= '<option value="' . $row['name'] . '">' . $row['name'] . '</option>'; // $out .= "<option value=\" . $row['name'] . \" >' . $row['name'] . '</option>"; } } echo $options; ?> </select> <input type="submit" name="submit1"> </form> </html> Thanks the above seem to work. Hi, I want to maintain users who log in a webpage and each time they leave, I want to record the current time, so this sounds silly but do I just set in my db table in a field that tracks a user's last log in with DEFAULT: CURRENT_TIMESTAMP? db structu user_id lastActivity lastSession (stores TIMESTAMP of last time user logged in) Any help much appreciated Hi,
I am building a website that will contain listings, there will be a categories page which will bring the user to the subcategories for that category then the user can see all listings linked to that subcategory. At the minute I am just linking each page using basic href tags to go to the page name.php and all my pages end up being homepage.com/clickedlink.php.
How do I change my URL's so that if i click on a certain category the url changes to page name.php?category=chosen category?
Thanks
Well, I am storing some of images on my server, but I have to type in the name myself which gets a bit boring and I may overwrite an old image by accident, so, I was thinking of having mysql auto increment the image names. But will this be suitable for images, or should it be text. Hi, I am writing a advertisement system, where i have two fields Ad_Start_date Ad_End_Date i was always confused, in doing this things regarding date whether to use datetime or timestamp in mysql Thanks, i'm trying to get all the results from a query search into an array and them have another query search the results from that array againts a different table to get the right results. Here is my code: Code: [Select] $name = $_GET['name']; //lets say $name = 'california' $get_state = mysql_query("SELECT * FROM locations WHERE state LIKE '$name'") or die(mysql_error()); $num_states = mysql_num_rows($get_state); $location_array = array(); $i = 0; while($state = mysql_fetch_assoc($get_state)){ $location_array[$i][] = $state['id']; $i++; } $get_buildings = mysql_query("SELECT * FROM points WHERE location_id='".implode(",", $location_array)."' ORDER BY name ASC") or die(mysql_error()); However i can't get any results. I tried outputing the array by imploding it and all i got was "array, array, array, array," I hope someone here can help me out. This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=327616.0 hello, um i got a form that stored an array of variables upon users clicks. it submits to another page fine as an array and i can print them using if(!empty($_POST['langSpoken'])) { echo "\n<p><strong>You selected the following LangSpoken:</strong></p>\n<ul>"; foreach($langSpoken as $lang) { // exclude any items with chars we don't want, just in case someone is playing if(!preg_match('/^[-A-Z0-9\., ]+$/iD', $lang)) continue; // print the lang echo "\n\t<li>" . htmlspecialchars($lang) . "</li>"; } echo "\n</ul>"; } else { echo "\n<p>No items selected</p>"; } it prints a list a of array like english spanish but i need to store each one in one variable so i can store in a database is there a way? thanks Hey I created a drop box and got a form for that. Now when I click on submit I want the data to be compaired with the data inside the mysql. For example: Subject name = Subject id the drop down list contains subject names. And this should be compaired with the subject id and store the id into a new table called test. <Html> <?php session_start(); include '../Database/connection.php'; ?> <body> <form action="try1.php" method="post"> <?PHP include '../Database/subject_sql.php'; $result=mysql_query($query) or die ("Unable to Make the Query:" . mysql_error() ); echo "<select name=myselect>"; while($row=mysql_fetch_array($result)){ echo "<OPTION VALUE=".$row['Sub_ID'].">".$row['Sub_Name']."</OPTION>"; } echo "</select>"; ?> <input type="submit" value="submit"/> </form> </body> </html> Anyone could help or giude how to secure this script by storing session into database?
login.php
<?php //Start session session_start(); //Include database connection details require_once('config.php'); //Get ip function get_client_ip() { $ipaddress = ''; if ($_SERVER['HTTP_CLIENT_IP']) $ipaddress = $_SERVER['HTTP_CLIENT_IP']; else if($_SERVER['HTTP_X_FORWARDED_FOR']) $ipaddress = $_SERVER['HTTP_X_FORWARDED_FOR']; else if($_SERVER['HTTP_X_FORWARDED']) $ipaddress = $_SERVER['HTTP_X_FORWARDED']; else if($_SERVER['HTTP_FORWARDED_FOR']) $ipaddress = $_SERVER['HTTP_FORWARDED_FOR']; else if($_SERVER['HTTP_FORWARDED']) $ipaddress = $_SERVER['HTTP_FORWARDED']; else if($_SERVER['REMOTE_ADDR']) $ipaddress = $_SERVER['REMOTE_ADDR']; else $ipaddress = 'UNKNOWN'; return $ipaddress; } //Array to store validation errors $errmsg_arr = array(); //Validation error flag $errflag = false; //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $login = clean($_POST['login']); $password = clean($_POST['password']); $ip = get_client_ip(); //Input Validations if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } /* if($login != '' || $password != '') { if($login !='admin' && $ip !=''.$log_ip.''){ $errmsg_arr[] = 'Your IP <b>'.$ip.'</b> is not recognized...'; $errflag = true; } } */ //If there are input validations, redirect back to the login form if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); //header("location: index.php"); echo ('<meta http-equiv="refresh" content="0;url=index.php">'); exit(); } //Create query $qry="SELECT * FROM members WHERE login='$login' AND passwd='".$_POST['password']."'"; $result=mysql_query($qry); //Check whether the query was successful or not if($result) { if(mysql_num_rows($result) == 1) { //Login Successful session_regenerate_id(); $member = mysql_fetch_assoc($result); $_SESSION['SESS_MEMBER_ID'] = $member['member_id']; $_SESSION['SESS_LOGIN_NAME'] = $member['login']; $_SESSION['SESS_PASS'] = $member['passwd']; session_write_close(); //header("location: member-index.php"); echo ('<meta http-equiv="refresh" content="0;url=member-index.php">'); exit(); }else { //Login failed //header("location: login-failed.php"); echo ('<meta http-equiv="refresh" content="0;url=login-failed.php">'); exit(); } }else { die("Query failed"); } ?>auth.php (included on top of all php pages <?php //Start session session_start(); //Check whether the session variable SESS_MEMBER_ID is present or not if(!isset($_SESSION['SESS_MEMBER_ID']) || (trim($_SESSION['SESS_MEMBER_ID']) == '')) { //header("location: access-denied.php"); echo ('<meta http-equiv="refresh" content="0;url=access-denied.php">'); exit(); } ?> |