PHP - Image Display Script Problem??

I had posted a similar post  a few days back, about an display script which is supposed to retrieve a stored image from my database and displays it on an html page, but fails to do so.  Someone suggested that I  upload my image onto a folder on the server and then save the image path name in my database.  I found this script(below)  which does just that.  It uploads the image into a folder on the server called images and stores the image path into a table in my database called images and I know this script works because i saw the file saved in the images folder and the path name inserted into the images table.
Code: [Select]


<?php

//This file inserts the main image into the images table.

//address error handling

ini_set ('display_errors', 1);
error_reporting (E_ALL & ~E_NOTICE);





//authenticate user
//Start session
session_start();

       
        //Connect to database
require ('config.php');

//Check whether the session variable id is present or not. If not, deny access.
if(!isset($_SESSION['id']) || (trim($_SESSION['id']) == '')) {
header("location: access_denied.php");
exit();
}

        else{ 







// Check to see if the type of file uploaded is a valid image type

function is_valid_type($file)

{

     // This is an array that holds all the valid image MIME types

     $valid_types = array("image/jpg", "image/jpeg", "image/bmp", "image/gif");

 

     if (in_array($file['type'], $valid_types))

         return 1;

     return 0;

}

 

// Just a short function that prints out the contents of an array in a manner that's easy to read

// I used this function during debugging but it serves no purpose at run time for this example

function showContents($array)

{

     echo "<pre>";

     print_r($array);

     echo "</pre>";

}

 

// Set some constants

 

// This variable is the path to the image folder where all the images are going to be stored

// Note that there is a trailing forward slash

$TARGET_PATH = "images/";

 

// Get our POSTed variable

$image = $_FILES['image'];

 

// Sanitize our input

$image['name'] = mysql_real_escape_string($image['name']);

 

// Build our target path full string.  This is where the file will be moved to

// i.e.  images/picture.jpg

$TARGET_PATH .= $image['name'];

 

// Make sure all the fields from the form have inputs

if ( $image['name'] == "" )

{

     $_SESSION['error'] = "All fields are required";

     header("Location: member.php");

     exit;

}

 

// Check to make sure that our file is actually an image

// You check the file type instead of the extension because the extension can easily be faked

if (!is_valid_type($image))

{

     $_SESSION['error'] = "You must upload a jpeg, gif, or bmp";

     header("Location: member.php");

     exit;

}

 

// Here we check to see if a file with that name already exists

// You could get past filename problems by appending a timestamp to the filename and then continuing

if (file_exists($TARGET_PATH))

{

     $_SESSION['error'] = "A file with that name already exists";

     header("Location: member.php");

     exit;

}

 

// Lets attempt to move the file from its temporary directory to its new home

if (move_uploaded_file($image['tmp_name'], $TARGET_PATH))

{

     // NOTE: This is where a lot of people make mistakes.

     // We are *not* putting the image into the database; we are putting a reference to the file's location on the server

     $sql = "insert into images (member_id, image_cartegory, image_date, image) values ('{$_SESSION['id']}', 'main', NOW(), '" . $image['name'] . "')";

     $result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error());

     header("Location: images.php");

echo "File uploaded";

     exit;

}

else

{

     // A common cause of file moving failures is because of bad permissions on the directory attempting to be written to

     // Make sure you chmod the directory to be writeable

     $_SESSION['error'] = "Could not upload file.  Check read/write persmissions on the directory";

     header("Location: member.php");

     exit;

}







        } //End of if session variable id is not present.
 


?> 











Now the display image script accompanying this insert image script is shown below. Code: [Select]
<?php

// Get our database connector

require("config.php");

?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"

      "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">

 

<html xmlns="http://www.w3.org/1999/xhtml">

    <head>

        <title>Dream in code tutorial - List of Images</title>

    </head>

 

    <body>

     

        <div>

 

            <?php   

                // Grab the data from our people table

                $sql = "SELECT * from images  WHERE  image_cartegory = 'main'";

                $result = mysql_query($sql) or die ("Could not access DB: " . mysql_error());

 

                while ($row = mysql_fetch_assoc($result))

                {

                    echo "<div class=\"picture\">";

                    echo "<p>";

 

                    // Note that we are building our src string using the filename from the database

                     echo "<img src=\"images/ " . $row['filename'] . " \" alt=\"\" />";

                   

                    echo "</p>";

                    echo "</div>";

                }



            ?>

         

        </div>

    </body>

</html>



Well, needless mentioning, the picture isn't displayed.  Just a tiny jpeg icon is displayed at the top left hand corner of the page.  Figuring out that the problem might be the lack of a header that declares the image type, I add this line
header("Content-type: image/jpeg");
but all it does is display a blank white page, without the tiny icon this time.  What am I missing? Any clues??