PHP - Notice: Undefined Variable & Call Stack
Hi
I am buidling a Blog System using OO techniques (or at least attempting to).. I keep getting an error : Notice: Undefined variable: blog_categoryName in C:\wamp\www\atkinsonsCMS\admin170976\blog_categories.php on line 13 ...And then underneath all that is is displaying 'Call Stack'. I've never come across this notification before so I guess it is an OO term, and the a list of unexpected outputs: #, time, memory, function and location....each with an associated value. I attempted to resolve the variable issue in the usual way (as you can see in my code), but still the errors/warnings persist. The purpose of this part of the code is to simply retrieve SQL data (which is a list of blog categories), allowing the user to select one and then click through to be directed to the appropriate category page (although this last requirement of the code has not yet been programmed). Could those who have experience of this please take a look at my code and let me know where I am going wrong? Thanks blog_categories.php This file calls on the the blogFunctions.php Category Class, and the displays the results. session_start(); $pageTitle = "Blog Categories"; include("../includes/admin_header.php"); include("../classes/blogFunctions.php"); echo '<div class="admin_main_body"><br /><br />'; echo "<h2>Category List</h2><br />"; $content = new Category; $content -> process(); //print_r(debug_backtrace()); echo "<a href=blog.php>$blog_categoryName</a>"; echo '</div>'; echo '</div>'; include("../includes/admin_footer.php"); blogFunctions.php This class deals with the retreaval of the SQL data, and then passes it to blog_categories.php class Category { public $errors; public $blog_categoryName = NULL; public function __construct() { $this->errors = array(); $blog_categoryName = $this->blog_categoryName; } public function getCategories(){ if(!isset($blog_categoryName)) { $blog_categoryName = 'value'; } ($GLOBALS["___mysqli_ston"] = mysqli_connect("localhost", "atkinson", "XYZ111WA")) or die(((is_object($GLOBALS["___mysqli_ston"])) ? mysqli_error($GLOBALS["___mysqli_ston"]) : (($___mysqli_res = mysqli_connect_error()) ? $___mysqli_res : false))); ((bool)mysqli_query($GLOBALS["___mysqli_ston"], "USE atkinsonscms")) or die (((is_object($GLOBALS["___mysqli_ston"])) ? mysqli_error($GLOBALS["___mysqli_ston"]) : (($___mysqli_res = mysqli_connect_error()) ? $___mysqli_res : false))); mysqli_query($GLOBALS["___mysqli_ston"], "SELECT * FROM blog_category ORDER BY ASC"); $result = @mysqli_query($GLOBALS["___mysqli_ston"], $query); if ($result) { while ($row = $result->fetch_object()) { $blog_categoryName = $row->blog_categoryName; } //need to use mysqli query to retrieve results. if(mysqli_affected_rows($GLOBALS["___mysqli_ston"])< 1) $this->errors[] = 'Could not retrieve data'; } } public function show_errors(){ echo "<h3>Errors</h3>"; foreach($this->errors as $key=>$value) echo $value."<br>"; } public function process() { $this->getCategories(); return count($this->errors)? 0 : 1; } } //Closes Category Class. Similar Tutorialshi, I need help really badly for my PHP-Postcard Script. Basically it sends the card out but the URL does not work, I get the following error message: The URL is not valid and cannot be loaded It also states that Notice: Undefined index: www.voluntary.awardspace.co.uk in /home/www/voluntary.awardspace.co.uk/Postcard.php on line 25 Notice: Undefined index: Postcard.php in /home/www/voluntary.awardspace.co.uk/Postcard.php on line 25 See Code below: <?php session_start(); //check error log ini_set('display_errors', 1); ini_set('log_errors', 1); ini_set('error_log', dirname(__FILE__) . '/error_log.txt'); error_reporting(E_ALL); // CHANGE PARAMETERS HERE BEGIN $senderName = " Holidays From Home "; // Eg.: John's Postcards $senderEmail = "chris01@voluntary.awardspace.co.uk"; // Eg.: john@postcard.com // Change only if you have problems with urls $postcardURL = "http://".$_SERVER["www.voluntary.awardspace.co.uk"].$_SERVER["Postcard.php"]; // CHANGE PARAMETERS HERE END $result = 0; $msg = ""; $msg1 = ""; $pic = ""; function displayPhotos() { global $pic; $columns = 5; $act = 0; $act1 = 0; // Open the actual directory if($handle = opendir("thumbs")) { // Read all file from the actual directory while($file = readdir($handle)) { if(!is_dir($file)) { if(isset($pic[1])) { if($pic[1] == $act1){$sel = "checked";} else{$sel = "unchecked";} } if($act == 0){echo "<tr>";} echo "<td align='center'><img src='thumbs/$file' alt='postcard'/><br/><input type='radio' name='selimg' value='$file,$act1' $sel/></td>"; $act++; $act1++; if($act == $columns){$act = 0;echo "</tr>";} } } echo "</tr>"; } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "DTD/xhtml1-transitional.dtd"> <html> <head> <title>Micro Postcard</title> <link href= "style/style.css" rel="stylesheet" type="text/css" /> </head> <body> <div id="main"> <div class="style1" id="caption"> <div align="left" class="style1"></div> </div> <?php //makes sure form is correctly filled in if(!empty($_POST["submit"])) { if(empty($_POST["selimg"])){$msg = "Please select an image from above!";$result = 3;} else{$pic = explode(",",$_POST["selimg"]);} if(empty($_POST["email"]) && empty($result)){$msg1 = "You must enter an email address!";$result = 3;} $secCode = empty($_POST["secCode"]) ? "" : strtolower($_POST["secCode"]); if($secCode == $_SESSION["securityCode"] && $result != 3) { $filename = date("YmdGis"); $f = fopen("messages/".$filename.".txt","w+"); fwrite($f,$pic[0]."\n"); fwrite($f,$_POST['email']."\n"); fwrite($f,stripslashes($_POST["message"])."\n"); fclose($f); // Compose the mail $from = "From: $senderName <$senderEmail>\r\n"; $replay = "Reply-To: $senderEmail\r\n"; $params = "MIME-Version: 1.0\r\n"; $params .= "Content-type: text/plain; charset=iso-8859-1\r\n"; $mailtext = "You have just received a Virtual Postcard!\r\n\r\n You can pick up your postcard at the following web address:\r\n $postcardURL?show=$filename\r\n\r\n We hope you enjoy your postcard, and if you do, please take a moment to send a few yourself!\r\n\r\n Regards,\r\n Holidays From Home\r\n $postcardURL"; // Send email @mail($_POST["email"],"You've received a postcard",$mailtext,$from.$replay.$params); echo "<center> Your postcard was sent successfully!<br /><br /> <img src='images/$pic[0]' alt='postcard' /><br /><br /><br />".stripslashes($_POST["message"]). "</center>"; $result = 1; } else{if($result != 3){$result = 2;}} } if(!empty($_GET["show"])) { $file = $_GET["show"]; $content = file("messages/$file.txt"); $pic = $content[0]; unset($content[0]); unset($content[1]); foreach($content as $value){$main .= $value;} echo "<center> Your postcard!<br /><br /> <img src='images/$pic' alt='postcard' /><br /><br /><br />$main </center>"; } if((empty($result) || $result == 2 || $result == 3) && empty($_GET["show"])) { echo "<form action='#' method='post'> <table align='center'>"; displayPhotos(); echo "</table> <div style='color:#f00;font-size:16px;'>$msg</div> <h2>Fill in the Form and then click on Send Card!!</h2> <table width='100%'> <tr><td>Send to (email address):</td><td><div style='color:#f00;font-size:16px;'>$msg1</div><input type='text' name='email' size='30' value='".$_POST["email"]."' /></td></tr> <tr><td>Message:</td><td><textarea name='message' rows='10' cols='40'>".stripslashes($_POST["message"])."</textarea></td></tr> <tr><td colspan='2'>".($result == 2 ? "<p style='color:#f00;font-size:16px;'>Sorry the security code is invalid! Please try it again!</span></p>" : " ")."</tr> <tr> <td>Security code: <input class='text' name='secCode' type='text' size='10' /> </td><td><img src='securityCode.php' alt='security code' border='1' /></td> </tr> <tr><td colspan='2'> </tr> <tr><td colspan='2' align='left'><input type='submit' value='Send card!' name='submit'/></td></tr> </table> </form>"; } ?> Absolutely any help would be much appreciated. I want ot know is there a way round this problem? Here is the http://voluntary.awardspace.co.uk/Postcard.php I am absolutely desperate to solve this burning issue I have just re-installed Xampp and suddenly my sites are now displaying lots of: Notice: Use of undefined constant name - assumed 'name' in ... Notice: Use of undefined constant price - assumed 'price' in ... this is an example of the line its refering too: $defineProducts[1001] = array(name=>'This is a product', price=>123); I don't know why I am getting an undefined variable when the url is define. look at the deleteid=6 it means it is defined and in the code it is written as below URL Quote http://www.ppp.com/storeprueba/storeadmin/inventory_list.php?deleteid=6 Code: [Select] <?php if(isset($_GET['deleteid'])){ //which is clearly active in the url then get it, /* line 27 ===> */ echo'Do you really want to delete pdoruct with ID of '. $GET ['deleteid'] . '? <a href="inventory_list.php?yesdelete=' . $GET ['deleteid'] . '">Yes</a> |<a href="inventory_list.php"> No</a>'; exit(); } if (isset($_GET['yesdelete'])) { // remove item from system and delete its picture // delete from database $id_to_delete = $_GET['yesdelete']; $sql = mysql_query("DELETE FROM products WHERE id='$id_to_delete' LIMIT 1") or die (mysql_error()); // unlink the image from server // Remove The Pic ------------------------------------------- $pictodelete = ("../inventory_images/$id_to_delete.jpg"); if (file_exists($pictodelete)) { unlink($pictodelete); } header("location:inventory_list.php"); exit(); } ?> the echo Code: [Select] <?php echo 'Do you really want to delete pdoruct with ID of '. $GET ['deleteid'] . '? <a href="inventory_list.php?yesdelete=' . $GET ['deleteid'] . '">Yes</a> |<a href="inventory_list.php"> No</a>'; ?> won't display the . $GET ['deleteid'] . after "Do you really want to delete product with ID of which is 6 but it won't display the number six with the actual configuration, instead it display it like Quote Notice: Undefined variable: GET in /home3/nyhungry/public_html/storeprueba/storeadmin/inventory_list.php on line 27 Notice: Undefined variable: GET in /home3/nyhungry/public_html/storeprueba/storeadmin/inventory_list.php on line 27 Do you really want to delete pdoruct with ID of ? Yes | No Notice not number in between 'ID of' and '?' Hello! Help me please!
My site nice work on php version 5.2.12, but now php version is changed to 5.2.17 and some code is not working.
It showing error:
"Notice: Undefined variable: newCode in ....../humancheck.php on line 29"
In file humancheck.php on line 29:
for($i=0; $i<$config_max_digits;$i++) $newCode = $newCode.rand(0,9);This variable, it seems, taken from another file - humancheck_showcode.php: session_start(); $newCode = $HTTP_SESSION_VARS["newCode"];And, in index.php file at the beginning of the file written: require ('human_check/humancheck.php');And, in index.php file below is written: <IMG src="humancheck_showcode.php">When I call the index.php file it shows error. So, I think, that variable "newCode" should be taken from file humancheck_showcode.php, but it don't do that. Hello all - am looking for help with dynamic links in PHP not returning data and coughing out "Notice: Undefined variable: row in /home/jj3wg2td/public_html/Uni More Info.php on line 200" The initial search is being fed from a mysql into table of results in another page ('ViewMore' being a column in my database and 'UniversityCourses' being the trigger to search that column): echo "<td class='result'><a href='Uni More Info.php?ID={$row['UniversityCourses']}'>{$row['ViewMore']}</a></td>"; This is working fine as I can see the various links changing when you hover over them in the table. clicking the links goes to "Uni More Info.php" where my PHP code is: <?php session_start(); ini_set('display_errors', 1); ini_set('display_startup_errors', 1); error_reporting(E_ALL); //Connect to the database $mysqli = new mysqli("localhost", "jj3wg2td_wix", "MYPASSWORD", "MYDATABASE"); if(isset($_GET['post'])){ $ID=mysqli_real_escape_string($mysqli, $_GET['ID']); $sql="SELECT * FROM uni2020 WHERE UniversityCourses='$ID'"; $result=mysqli_query($mysqli,$sql) or die ("Bad Query: $sql"); $row=mysqli_fetch_array($result); if(isset($_GET['post'])){ $Website=mysqli_real_escape_string($mysqli,$_GET['Website']); $UcasPointsRequired=mysqli_real_escape_string($mysqli,$_GET['UcasPointsRequired']); $OverallScore=mysqli_real_escape_string($mysqli,$_GET['OverallScore']); $sql= "INSERT INTO UniversityCourses (Website, UcasPointsRequired) VALUES ('$Website', $UcasPointsRequired');"; $result=mysqli_query($mysqli,$sql) or die ("Bad Query: $sql"); } } ?> <content> <?php echo $row['Website']?> <?php echo $row['UcasPointsRequired']?> <?php echo $row['OverallScore']?> </content> The error codes are showing:
Notice: Undefined variable: row in /home/jj3wg2td/public_html/Uni More Info.php on line 200 Which is the section in-between the <content></content> tags. Reading up into "Undefined Variable", it suggest that I havent "Declared the variables", but isn't that this section?: if(isset($_GET['post'])){ $Website=mysqli_real_escape_string($mysqli,$_GET['Website']); $UcasPointsRequired=mysqli_real_escape_string($mysqli,$_GET['UcasPointsRequired']); $OverallScore=mysqli_real_escape_string($mysqli,$_GET['OverallScore']); I am new to PHP and am learning as I go along....but yet again...I'm stumped! Any help is very much appreciated (again)!!!!
Steven I'm getting the following notice: Notice: Undefined variable: TotaalBerichten in C:\Users\Sander\Documents\**********************\index.php on line 60 Is it because it is in the IF? The code: //Aantal berichten totaal if (!$ResultTotaalBerichten = @mysql_query("SELECT COUNT(1) FROM " . $db_prefix . "berichten")) {$foutmelding .= $Taal['errorConfiguratieFromDB'];} else {$TotaalBerichten = mysql_result($ResultTotaalBerichten, 0); $TotaalPaginas = ceil($TotaalBerichten / $aantalBerichtenPerPagina);} @mysql_free_result($ResultTotaalBerichten); //Var eersteBericht is het eerste bericht if (isset($_GET['eersteBericht'])) {if (!is_numeric($_GET['eersteBericht'])) {$eersteBericht = '0';} else{$eersteBericht = $_GET['eersteBericht'];}} else{$eersteBericht = '0';} // Als er iets mis is met var eersteBericht, dan hem op 0 zetten if (($eersteBericht >= $TotaalBerichten) || ($eersteBericht < 0)) ///////////DIT IS LIJN 60 {$eersteBericht = 0;} EDIT: translated to english If i modify it to: $TotaalBerichten=0; /////////////ADDED //Aantal berichten totaal if (!$ResultTotaalBerichten = @mysql_query("SELECT COUNT(1) FROM " . $db_prefix . "berichten")) {$foutmelding .= $Taal['errorConfiguratieFromDB'];} else {$TotaalBerichten = mysql_result($ResultTotaalBerichten, 0); $TotaalPaginas = ceil($TotaalBerichten / $aantalBerichtenPerPagina);} @mysql_free_result($ResultTotaalBerichten); echo $TotaalBerichten; //////////////////////////////////////////////////////////////////////////ADDED //Var eersteBericht is het eerste bericht if (isset($_GET['eersteBericht'])) {if (!is_numeric($_GET['eersteBericht'])) {$eersteBericht = '0';} else{$eersteBericht = $_GET['eersteBericht'];}} else{$eersteBericht = '0';} // Als er iets mis is met var eersteBericht, dan hem op 0 zetten if (($eersteBericht >= $TotaalBerichten) || ($eersteBericht < 0)) ///////////DIT IS LIJN 60 {$eersteBericht = 0;} The $TotaalBerichten is '0' while there IS a message in the database??? code is Code: [Select] <?php $limit=12; if(isset( $_GET['page'])) $page=$_GET['page']; if($page<=0) $page = 1; else {$start=0;} $sql=mysql_query("select * from tbl_gallery where status=1 And category_name='0'"); $count=mysql_num_rows($sql); $totalcount=ceil($count/$limit);$start=($page-1)*$limit; $s=mysql_query("select * from tbl_gallery where status=1 And category_name='0' limit $start, $limit"); while($result=mysql_fetch_array($s)){ $start++; ?> please find the mistake Ik ben bezig met een gastenboek en snap de volgende foutmelding niet: Notice: Undefined variable: iCountFiles *************** regel 261 //Smilies toegestaan? if ($GetConfiguratie['smiley'] == 1) {$AfbeeldingenPerRegel = 12 ; if (!$rHandle = opendir('./images/smilies')) {$sP_Smilies = 'Geef de map "smilies" leesrechten!';} else {$sP_Smilies = ''; while (false !== ($sFile = readdir($rHandle))) {if (preg_match("/^([sa-zA-Z0-9]+){3}(:?\.gif|\.jpg)$/", $sFile)) { $sFileShort = preg_replace("/^([sa-zA-Z0-9]+)(:?\.gif|\.jpg)$/", "(\\1)",$sFile); $iCountFiles++ ; /////////////////////////////////////////////////////////////REGEL261 if ($iCountFiles % $AfbeeldingenPerRegel == 0) {$sP_Smilies .= '<img onClick="insertSmilie(\''.$sFileShort.'\')" src="images/smilies/'.$sFile.'" alt="code: '.$sFileShort.'" /><br />';} else {$sP_Smilies .= '<img onClick="insertSmilie(\''.$sFileShort.'\')" src="images/smilies/'.$sFile.'" alt="code: '.$sFileShort.'" /> ';} } } closedir($rHandle); } } hoe los ik dit het best op? Code: [Select] <form method="post" action=""> <input type="input" name="user_name" /> <input type="submit" name="user_name_submit" /> </form> <?php if(!empty($_POST['user_name'])) $user_name = $_POST['user_name']; if(isset($_POST['user_name_submit'])) { $user_name_submit = $_POST['user_name_submit']; } $user_name_preg_match = preg_match('/[a-zA-Z0-9]/', $user_name); if($user_name_preg_match) { echo 'true'; } else { echo 'false'; } ?> In this script I am getting the notice: Code: [Select] Notice: Undefined variable: user_name Any suggestions how to avoid the notice in this case? Hello i am new to this forum and coding. I am trying to fix a auto torrent downloading script which is php and curl. I have been stucked with Undefined offset error. Your help will be very appretiated, thanks. Starting download: Mp3-data1 Notice: Undefined variable: temp in /var/www/html/torrents/bgrahul2.php on line 338 Array ( => HTTP/1.1 200 OK Server: Transmission Content-Type: application/json; charset=UTF-8 Date: Wed, 21 Sep 2011 19:58:44 GMT Content-Length: 49 {"arguments":{"torrents":[]},"result":"success"} [1] => ) Marked those lines to bold Quote $result = callTransmission(array("filename" => "/var/www/html/donofwarez/xxx/torrents/$torrentfile", "download-dir" => "/home/Downloads/$title/"), "torrent-add", $arr[1]); callTransmission(array("seedRatioLimit" => 50, "seedRatioMode" => 1), "torrent-set", $arr[1]); /* echo "<pre>"; print_r($result); echo "</pre>"; */ if (preg_match('/"percentDone":[0-9.]+/i', $result[0], $matches)) $temp = str_replace('"id":', "", $matches[0]); // $temp="hlDr1wqu2ONtM3McVGHoVzfrkp2UgUcGwDt66IuxAe0LBkru"; $id[0] = $temp; //***OMG! We need the ids as integers! *** foreach ($id as $key => $value) { $id[$key] = (int) $value; } hello all, i have ran into another issue i get this message when i go onto my homepage Notice: Undefined variable: layout in i have the following includes on the main index page: Code: [Select] <?php // Include Main Core File. include '_class/core.php'; // Include Config File include 'config/config.php'; include 'config/db.php'; // Use Database $obj->connect(); // Include library include '_class/library.php'; // Include layout include 'layout/index.php'; ?> on the config file i have the varible it is refering too: Code: [Select] <?php $layout = $url . "layout/"; ?> the actual file i get the error on (library.php) Code: [Select] <?php class library extends core { function advert() { /* * Name your images 1.jpg, 2.jpg etc. * * Add this line to your page where you want the images to * appear: <?php include "randomimage.php"; ?> */ // Change this to the total number of images in the folder $total = "2"; // Change to the type of files to use eg. .jpg or .gif $file_type = ".png"; // Change to the location of the folder containing the images $image_folder = $layout . "layout/images/adverts"; // You do not need to edit below this line $start = "1"; $random = mt_rand($start, $total); $image_name = $random . $file_type; echo "<img src=\"$image_folder/$image_name\" alt=\"$image_name\" />"; } } $obj = new library; ?> is there a way to make it so it $layout works on any page or file as long as its in the includes? thanks again. I have a php page that is trying to pass a variable like this: echo "<tr><td bgcolor='white'>" . $company_id . "</td><td bgcolor='white'><a href='companyusers.php?name=" . $company_name . "'>" . $company_name . "</a></td><td bgcolor='white'>" . $company_email . "</td><td bgcolor='white'>" . $company_status . "</td></tr>"; Then when some one clicks on that link they variable with it's value should go with the url and I'm trying to assign a variable like this: $company_name = $_POST['name']; It is not working!!! I get that "Notice: Undefined index: name in 'directory of page' on line 100" Can someone help please? Code: [Select] Notice: Undefined variable: page in C:\Program Files (x86)\EasyPHP5.2.10\www\admin.php on line 119 That line is: <?php session_start(); $_SESSION['prev_page'] = $_SERVER['REQUEST_URI']; if (!session_is_registered('username')) { header("location:login.php"); } ?> <hr> <style type="text/css"> table.gridtable { color:#333333; border-width: 1px; border-color: #666666; border-collapse: collapse; width: 100%; } table.gridtable th { border-width: 1px; padding: 1px; border-style: solid; border-color: #666666; background-color: #dedede; } table.gridtable td { border-width: 1px; padding: 1px; border-style: solid; border-color: #666666; } .valid { border-width: 1px; padding: 1px; border-style: solid; border-color: #666666; background-color: transparent; } </style> </div> <div class="newsJustify"> <script type="text/javascript"> function checkall(delchk) { for (i = 0; i < delchk.length; i++) delchk[i].checked = true; } </script> <script type="text/javascript"> function uncheckall(delchk) { for (i = 0; i < delchk.length; i++) delchk.checked = false; } </script> <script language="JavaScript"> function loadPage(list) { location.href=list.options[list.selectedIndex].value } </script> <?php mysql_connect("localhost", "root", "") or die(mysql_error()); mysql_select_db("chat") or die(mysql_error()); if (isset($_POST['del'])) { for ($count = 0; $count < count($_POST["delchk"]); $count++) { $delete = $_POST["delchk"][$count]; $query = "DELETE FROM members_shouts WHERE id = '$delete'"; $result = mysql_query($query); if (!$result) { die("Error deleting accounts! Query: $query<br />Error: " . mysql_error()); } } } $data = mysql_query("SELECT * FROM `members_shouts`") or die(mysql_error()); $rows = mysql_num_rows($data); if (isset($_GET['limit'])) { $page_rows = $_GET["limit"]; if ($page_rows == '') { $page_rows = 5; // no double quotes (int) } elseif ($page_rows == 'all') { $page_rows = $rows; } else { $page_rows = $_GET['limit']; /* validate this */ } if (!isset($_GET['pagenum'])) { $page = 1; } else { $page = (int) $_GET['pagenum']; } } else { $page_rows = 10; } ?> <?php $max_pages = ceil($rows / $page_rows); $last = ceil($rows / $page_rows); $pagenum = ($page && $page > 0 && $page <= $last) ? $page : 1; $max = 'limit ' . ($pagenum - 1) * $page_rows . ',' . $page_rows; $data_p = mysql_query("SELECT * FROM members_shouts $max") or die(mysql_error()); ?> <?php $result = mysql_query("SELECT * FROM members_shouts"); if (mysql_num_rows($result) > 0) { ?> <span style="float: left;margin-left: 2px;"> <form> <select name="file" size="1" onchange="loadPage(this.form.elements[0])" target="_parent._top"> <option value="" <?php if ($page_rows == 0) { echo 'selected'; } ?>>Select Limit</option> <option value="?limit=9" <?php if ($page_rows == 9) { echo 'selected'; } ?>>9</option> <option value="?limit=15" <?php if ($page_rows == 15) { echo 'selected'; } ?>>15</option> <option value="?limit=30" <?php if ($page_rows == 30) { echo 'selected'; } ?>>30</option> <option value="?limit=all" <?php if ($page_rows == 'all') { echo 'selected'; } ?>>All</option> </select> </form> </span> <span style="float: right;margin-top: 2px;margin-right: 2px;"> <center> <?php if ($pagenum == 1) { } else { echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=1&limit={$page_rows}'>First</a> "; echo " | "; echo " "; $previous = $pagenum - 1; $current = $pagenum; echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$previous&limit={$page_rows}'>$previous</a> "; echo " | "; } echo "$pagenum"; if ($pagenum == $last || $last == 0) { } else { $next = $pagenum + 1; echo " | "; echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$next&limit={$page_rows}'>$next</a> "; echo " "; echo " | "; echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$last&limit={$page_rows}'>Last</a> "; } ?> </center> </span> <style type="text/css"> .clear2 { clear:both; height:0px; overflow:hidden; } </style> <div class="clear2"></div> <hr> <?php echo "<table class=\"gridtable\"> <thead> <tr> <th align=\"center\" scope=\"col\">user</th> <th align=\"center\" scope=\"col\">message</th> <th align=\"center\" scope=\"col\">when</th> <th align=\"center\" scope=\"col\">Delete?</th> </tr> </thead> <tbody>"; echo "<form name = 'myform' action='' method='post'>"; ?> <?php while ($info = mysql_fetch_array($data_p)) { echo "<tr align=\"center\">"; echo "<td class=\"valid\" >" . $info['user'] . "</td>"; echo "<td class=\"valid\" >" . $info['message'] . "</td>"; echo "<td>" . $info['when'] . "</td>"; echo '<td><input type="checkbox" id="delchk" name="delchk[]" value="' . $info['id'] . '" /></td>'; echo "</tr>"; } echo "</tbody>"; echo "</table>"; echo "<hr>"; echo "<input type='submit' name = 'del' value='Delete Selected'></form>"; echo "<input type='button' onclick='checkall(document.myform[\"delchk\"]);' value='Select All'>"; echo "<input type='button' onclick='uncheckall(document.myform[\"delchk\"]);' value='Deselect All'>"; echo "<hr>"; ?> <?php } else { // No rows were found ... echo '<center>No logged accounts.</center><hr>'; } ?> </hr> The line its refferring too is: $pagenum = ($page && $page > 0 && $page <= $last) ? $page : 1;[/QUOTE] in this block: $max_pages = ceil($rows / $page_rows); $last = ceil($rows / $page_rows); $pagenum = ($page && $page > 0 && $page <= $last) ? $page : 1; $max = 'limit ' . ($pagenum - 1) * $page_rows . ',' . $page_rows; $data_p = mysql_query("SELECT * FROM members_shouts $max") or die(mysql_error()); [/i] I am new to php and html, I am trying to make a search function where you can search by a persons firstname or lastname but I am getting an error. the error is Notice: Undefined variable: searchq in C:\wamp\www\search2.php on line 17. Can anyone help me please I just moved my code from Appserv to EasyPHP and it gave me this error, it was working fine on Appserv...what's with easyPHP ?? I have 2 issues happening, first one I need to get resolved is, line 60 is giving me a 'Notice: Undefined variable: delete'. This codes had multi issues but was able to resolve all but this one and my table not filling in with the data from my database. If you need any other info please let me know, Again I am new at this.
<tr> <td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete value="delete"></td> </tr> <?php // Check if delete button active, start this *line 60* -----> if ($delete){ for($i=0;$i<$count;$i++){ $del_id = $checkbox[$i]; $sql = "DELETE FROM $tbl_name WHERE id='$del_id'"; $result = mysqli_query($sql); } // if successful redirect to delete_multiple.php if($result){ echo "<meta http-equiv=\"refresh\" content=\"0;URL=delete_multiple.php\">"; } } mysqli_close($con); ?> Hello, I have the situation shown below in the code: if(//condition is met) { $val = new Val(); $valon = $val->check($_POST, array(.........)); } if($valon->passes()) { $use = new Use(); ........ } //check() and passes() both belong to class Val public function check($source, $items = array()) { ...................... return $this; }I get the following warning and error: Notice: Undefined variable: valon and Fatal error: Call to a member function passes() on a non-object I can't see anything wrong with the code. check() returns an object of class Val which is assigned to $valon, $valon then calls a member function of class Val. Could you please help. Please let me know whether to include further code.
First let me explain my code. This is later included in project_status.php] . In project_status.php] , I have included another file project_status_app.php which contains a HTML form.
<?php include 'inc_fn_header_and_menu.php'; function includeFile($file,$variable) { $var = $variable; include($file); } if (isset($_GET['id']) && $_GET['id']!="") { $pid = $_GET['id']; $_SESSION['pidForApproval'] = $_GET['id']; $query = 'SELECT * FROM `profile` WHERE pid ='.'\''.$pid.'\''; $result=mysqli_query($db,$queryToRetrievePP) or die("There are no records to display ... \n" . mysqli_error()); foreach ($result as $row) { $status = $row['status']; } } ...........some PHP and HTML code....... <div id="customerPurchaseApprovalForm"> <?php echo '<p>APPROVAL FOR CUSTOMER PURCHASE</p>'; $discountApprovalStatus = "Granted"; if ($discountApprovalStatus == "Granted") { includeFile("project_status_app.php",$highestannualvalue); } else { //......... } In project_status_app.php I am attempting to retrieve pidForApproval from the $_SESSION array. <?php // put your code here UPDATE `pp` SET `customer_purchase_remarks` = 'hahaha' WHERE `pp`.`id` = 207; if ($_SERVER['REQUEST_METHOD'] == 'POST') { include '../../inc/fastlogin.php'; $sql = "UPDATE pp SET customer_purchase_remarks ='{$_POST['remarkstxt']}' WHERE pp.pid='{$_SESSION['pidForApproval']}'"; $result = mysqli_query ( $fastdb, $sql ) ; if (mysqli_affected_rows($fastdb) != 1) { $_SESSION['err_cpa_rmks'] = "<p>Error while updating WHERE id='{$_SESSION['pidForApproval']}'</p>"; //echo "<p>Error while updating WHERE id='{$_POST['pidForApproval']}'</p>".mysqli_error($fastdb); } else { $_SESSION['suc_cpa_rmks'] = "<p>Records was updated successfully.</p>"; //echo "Records was updated successfully."; } header ("location: project_status.php?id="$_SESSION['pidForApproval']); exit(); } ?> When I load project_status.php, project_status_app.php is supposed to display the form. Once the user fills in the form the and the submit button has been pressed, the UPDATE statement is supposed to run and then it is supposed to navigate back to project_status.php?id=FA142. But the update is failing and the when the project_status.php is loaded back, the url looks like this http://localhost/fast/project_status.php?id= . The id is empty. It is supposed to be something like this http://localhost/fast/project_status.php?id=FA142. With the id being populated at the header ("location: project_status.php?id=".$_SESSION['pidForApproval']);
Missing some information. Hi. I installed xampp to practice php scripting. Until today, it has worked fine, but now it says: Notice: Undefined variable: text in E:\xampp\htdocs\Experiments\Tutorial\HelloWorld.php on line 6 What can I do to fix this? I'm told that variable don't need to be defined before being initialized, but that doesn't really mean much to me! Please help I have a form and a validation both on the same page, however I'm getting notices since I have undefined variables. How do I get around this? Notice: Undefined index: submit in C:\xampp\htdocs\5dollar\register.php on line 10 Notice: Undefined index: password in C:\xampp\htdocs\5dollar\register.php on line 12 Notice: Undefined index: repeatpassword in C:\xampp\htdocs\5dollar\register.php on line 13 Notice: Undefined index: paypalemail in C:\xampp\htdocs\5dollar\register.php on line 14 $submit = $_POST['submit']; $password = strip_tags($_POST['password']); $repeatpassword = strip_tags($_POST['repeatpassword']); $paypalemail = strip_tags($_POST['paypalemail']); |